Due to the fact that it is an electron acceptor that is blue when oxidized and colorless when reduced, DPIP is a redox dye that is frequently employed as a monitor of the light processes in photosynthesis.
NADP+ is frequently replaced with DPIP. Due to the chemical makeup of the dye, it changes hue when it is reduced. In order to track tPMET, DPIP is also used as an extracellular electron acceptor. In our DCPIP reduction experiment, electrons transfer to DCPIP rather than cytochrome b6f from the intramembrane plastoquinone pool. The colourless, reduced form of DCPIP is created as the oxidised, blue form receives the electrons. Chloroplasts oxidise water and send the resultant electrons to the synthetic electron acceptor, dichlorophenol, via the photosynthetic electron transport chains in their thylakoid membranes.
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for f = 52 lb, compute the combined moment of the two forces about (a) point o, (b) point c, (c) point d. the moments are positive if counterclockwise, negative if clockwise.
The combined moment of the two forces about ;Moment about point O = 0
,Moment about point C = 52 lb · 8 ft = 416 lb · ft,Moment about point D = 52 lb · 4 ft = 208 lb · ft.
What is the forces ?Force is an influence that causes an object to move, stop, or change its direction. It can be a push or pull, and can result from interaction with another object, person, or object of nature. Force can also be caused by non-contact interactions such as electric fields, magnetic fields, and gravitational forces. Force can be measured in Newtons, which is the amount of force required to accelerate a one-kilogram mass by one meter per second squared.
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A particle undergoes three consecutive displacements, given by the following vectors: D1 = (3.8 mm)i + (-3.4 mm)j + (-2.2 mm)k, D2 = (2.9 mm)i + (-7.7 mm)j + (2.8 mm)k, and D3 = (-7.7 mm)i + (2.8 mm)j + (2.9 mm)k. A. What is the magnitude of the net displacement, in mm? B. What would have been the magnitude of the net displacement, in mm, if the three displacements (having the same magnitudes as D1, D2, and D3) were in the same direction?
A. magnitude of the net displacement is 10.4 mm.
B. The magnitude of the net displacement would have been 11.7 mm.
A. The magnitude of the resulting vector, which is created by summing the vectors D1, D2, and D3, provides the size of the net displacement, in mm. The Pythagorean Theorem may be used to calculate the following:
[tex]|D1+D2+D3| = \sqrt((3.8)^2 + (-3.4)^2 + (-2.2)^2 + (2.9)^2 + (-7.7)^2 + (2.8)^2 + (-7.7)^2 + (2.8)^2 + (2.9)^2) \\\\ =10.4 mm[/tex]
Therefore,the magnitude of the net displacement is 10.4 mm.
B.The magnitude of the net displacement would be determined by the magnitude of the total of the vectors, which would be equal to the sum of the magnitudes of the individual vectors, if all three displacements (with the same magnitudes as D1, D2, and D3) were in the same direction.
if the three displacements were in the same direction. This can be calculated as follows:
[tex]|3D1| = 3\sqrt((3.8)^2 + (-3.4)^2 + (-2.2)^2) \\ \\ = 11.7 mm[/tex]
Therefore, the magnitude of the net displacement would have been 11.7 mm.
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determine the rate of heat loss from that person by radiation in a large room having walls at a temperature of 300 k. you must provide an answer before moving to the next part.
The rate of heat loss by radiation from a person in a room with walls at 300 K is approximately 325 W.
The rate of heat loss by radiation from a person in a room with walls at a temperature of 300 K can be calculated using the equation for Stefan-Boltzmann law. This law states that the rate of heat loss by radiation from an object is proportional to the fourth power of its temperature and the surface area of the object.
The equation for heat loss by radiation is given by:
Q = σ * A * (T^4 - T_0^4)
where:
Q is the rate of heat loss (in W)
σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2 K^4)
A is the surface area of the person (in m^2)
T is the temperature of the person (in K)
T_0 is the temperature of the walls (300 K)
The surface area of an average person is about 1.7 m^2, and the average body temperature is about 310 K. Plugging these values into the equation, we can estimate the rate of heat loss by radiation:
Q = σ * A * (310^4 - 300^4)
Q = 5.67 x 10^-8 W/m^2 K^4 * 1.7 m^2 * (93,901,000 - 81,000,000)
Q = approximately 325 W
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it turns out that there is an electric field that points inward toward the center of the earth that has magnitude of about 100 n/c near the earth's surface. estimate the total charge of the earth needed to support such a field. where do you think all this charge comes from?
The total charge of the earth needed to support such a field is −4.56 × 10⁵ C.
What is electric charge ?
The physical quality of matter—its electric charge—is what causes it to feel a force when exposed to an electromagnetic field. Protons and electrons, the two types of charge carriers, typically carry positive and negative electric charges. Charges moving through a system produce energy.
What is electric field ?
According to mathematics, the electric field is described as a vector field that may be connected to each point in space and represents the force per unit charge that is applied to a positive test charge that is at rest at that location. Either the electric charge or time-varying magnetic fields can produce an electric field.
Given
E = 100 N/C inward
Flux =[tex]\dfrac{ q_{enclosed}}{\epsilon}[/tex]
−E(4πr2) =[tex]\dfrac{ q_{enclosed}}{\epsilon}[/tex] as field is inward so flux is negative
⇒ [tex]q_{enclosed}[/tex] = −εE (4πr²)
⇒ [tex]q_{enclosed}[/tex] = −εE (4πr2)
= −8.85 × 10⁻¹² × 100 × 4π × (6400×1000 m)²
= −4.56 × 10⁵ C
this charge may be coming because earth core is ionised and positively charged so on surface maybe negative charge induced.
Thus, The total charge of the earth needed to support such a field is −4.56 × 10⁵ C.
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Complete question:
It turns out that there is an electric field that points inward toward the center of the Earth that has a magnitude of about 100 N/C near the Earth's surface. Estimate the total charge of the Earth needed to support such a field. Where do you think all this charge comes from?
an electron (m= 9.1 x10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbit in the H atom).
The centripetal force on the electron in the first orbit of the hydrogen atom would be 81.75 x 10⁻⁹.
What is Bohr model of atom?The main points of Bohr's model of atom are -
Electrons orbit the nucleus in orbits that have a set size and energy.The energy of the orbit is related to its size. The lowest energy is found in the smallest orbit.Radiation is absorbed or emitted when an electron moves from one orbit to another.Given is that an electron (e⁻) (m = 9.1 x 10⁻³¹ kg) moving at 2.18 x 10⁶ m/s (in a Bohr orbit in the H atom).
The radius of first Bohr orbit of hydrogen atom is -
{r} = 0.529 A˚ = 0.529 x 10⁻¹⁰ m.
The centripetal force on the electron in the first orbit of the hydrogen atom would be -
F = mv²/r
F = (9.1 x 10⁻³¹)(2.18 x 10⁶)²/0.529 x 10⁻¹⁰
F = 81.75 x 10 ⁻³¹ ⁺ ¹² ⁺ ¹⁰
F = 81.75 x 10⁻⁹
Therefore, the centripetal force on the electron in the first orbit of the hydrogen atom would be 81.75 x 10⁻⁹.
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Answer:its 1.9 10^26
Explanation:
new planets formed in a cloud of dust and debris surrounding our young sun through a process known as .
Accretion is the process when new planets formed in a cloud of dust and debris surrounding our young sun.
The solar nebula is a whirling disk generated by the remaining portion of the cloud. Scientists think that dust and ice particles buried in the gas migrated inside the solar nebula, occasionally clashing and clumping together.
These tiny particles created larger things through a process known as "accretion," which eventually led to the formation of planetesimals with sizes up to a few kilometers across.
Planetesimals in the hotter, inner region of the solar nebula were primarily made of silicates and metals. Water ice predominated in the outer, colder region of the nebula.
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Complete question is
What is the process when new planets are formed in a cloud of dust and debris surrounding our young sun known as ?
Starting at the origin, an object has a velocity of 3m/s and an acceleration of -2 m/s2. What is the final velocity after 3 seconds?
The final velocity, when initial velocity, acceleration are given, is calculated to be -3 m/s. Minus sign represents opposite direction.
From the equations of motion, we should select a correct equation which relates initial velocity, final velocity, acceleration and time.
It is said that the object starts at the origin.
The initial velocity of the object is given as 3 m/s
The acceleration of the object is given as -2 m/s²
The final velocity after 3 sec is to be calculated.
So, the suitable equation of motion is, v = u + a t
where, v is final velocity
u is initial velocity
a is acceleration
t is time
Let us put in the values into the above equation.
v = u + a t
v = 3 + (-2) (3) = 3 - 6 = -3 m/s
3 m/s in the opposite direction from that of the initial velocity.
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how far would the sun be from alpha centauri on this scale?
Answer: On this scale,Alpha centauri would be 1.48×10∧6
metres or about 890 miles away.
Explanation: If the sun were scaled to a 1 foot radius , then alpha centauri would be about 10,000 miles away.
a long thin rod of length l has a linear density λ(x)=ax where x is the distance from the left end of the rod. (a) how far is the center of mass of the rod from the left end of the rod?
The rod's center of mass is measured from the left end of the rod is X=(2/3)l.
As we know that the linear density of a rod is as λ(x)= dM/dx.
So, dM = λ(x)dx
Integrate the above equation with the interval [0, l], and we get:
[tex]M=\int\limits^l_0 {\lambda(x)} \, dx \\M=\int\limits^l_0 {A(x)} \, dx \\M = A(\dfrac{x^2}{2} )\limits^l_0[/tex]
M = Al²/2 .....(1)
The rod's center of mass is measured from the left end of the rod expressed as follows:
[tex]X=\frac{1}{M} \int\limits^l_0 {x \lambda(x)} \, dx\\X = \frac{1}{M} \int\limits^l_0 {x (Ax)} \, dx\\X=\frac{1}{M}A(\frac{x^3}{3} )_0^l[/tex]
X = (1/M)Al³/3
Substitute the value of M = Al²/2 in the above equation,
X = [1/(Al²/2)]Al³/3
X = (2/3)l
Therefore, the rod's center of mass is measured from the left end of the rod is X=(2/3)l.
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what will happen if high temperature gas enters compressor
If high temperature gas enters compressor, than although the compressor's capacity declines with increasing superheat, its current consumption reduces because less vapour is drawn in during the suction stroke.
A compressor is a mechanical device that lowers a gas's volume while raising its pressure. An air compressor is one distinct case of gas compressor. Two very different pumps and compressors can convey a fluid through a pipe while increasing the fluid's pressure.
The molecules in a hot gas move more quickly than those in a cold gas; while the mass of the gas doesn't change, the kinetic energy does, which raises the temperature.
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for a spacecraft going directly from the earth to the moon, beyond what point will lunar gravity begin to dominate? that is, where will the lunar gravitational force be equal in magnitude to the earth's gravitational force?
The point where the lunar gravitational force becomes equal in magnitude to the Earth's gravitational force is called the "Lagrange point," and it is located approximately 1.5 million kilometers from the Moon in the direction of Earth.
At this point, the gravitational forces of the Earth and the Moon balance each other out, and a spacecraft can remain in a stable position without using any fuel. This makes the Lagrange point an ideal location for a spacecraft to rest or make observations, as it requires minimal effort to maintain position.
It is important to note that beyond this point, the Moon's gravitational force begins to dominate, and the spacecraft would be pulled towards the Moon. However, by using the right combination of velocity and trajectory, a spacecraft can be sent directly from the Earth to the Moon and land on the lunar surface.
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Small rockets are used to make tiny adjustments in the speed of satellites. One such rocket has a thrust of 50. 0 n. If it is fired to change the velocity of a 75,000-kg spacecraft by 45 cm/s, how long should it be fired?.
The time taken by the rocket to move with the velocity of 45 cm/s is 675 seconds.
The force applied by the rocket = 50 N
The mass of the spacecraft = 75,000 kg
The velocity of the rocket = 45 x 10⁻² m/s
The time taken by the rocket can be found using the formula,
F = mv/t
where F is the force applied
m is the mass of the spacecraft
v is the velocity of the rocket
t is the time taken by the rocket
Let us rearrange the above equation, we get
t = mv/F
Let us substitute the known values in the above equation, we get
t = 75,000 x 45 x 10⁻² / 50
= 33750 / 50
= 675 seconds
Therefore, the time taken by the rocket is 675 seconds
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place one of the positive charges in the center of the screen. notice the electric field? move the charge around and note what the field does.
Placing a positive charge in the center of a screen will produce an electric field, which can be observed as lines of force that radiate away from the charge. Moving the charge around will cause the electric field to change direction and magnitude.
An electric field is a field of force that exists around a charged object and affects other charged objects within the field. The electric field can be visualized as lines of force that radiate away from the charge, and the direction of the lines of force indicates the direction of the force that the electric field will exert on another charged object.
When a positive charge is placed in the center of a screen, the electric field will radiate away from the charge in all directions. The strength of the electric field will be greatest close to the charge and will decrease as you move further away from the charge. You can observe the electric field by drawing the lines of force, or by using a simulation to visualize the electric field.
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An ATV professional can race around the track in record time. If the pro raced down 19
meters of track in 30 seconds, what speed was he going? Please help
The ATV professional was going at a speed of approximately 2.3 km/h.
To determine the speed of the ATV professional who is racing around the track we can use the distance formula.
Distance = speed × time
Rearranging the equation we get the equation for speed as
Speed = Distance ÷ Time
Given that the ATV professional raced down 19 meters in 30 seconds time, we can calculate his speed as follows
distance = 19 meters
time = 30 seconds
Speed = 19 meters ÷ 30 seconds
Which is equal to 0.633 meters/second
This speed is expressed in meters per second (m/s). To convert this to kilometers per hour (km/h), you can multiply by 3.6 hence the final result can be formulated as
0.633 m/s x 3.6 = 2.3 km/h
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If the force of a golf club on a golf ball is 200 n forward, what will the force of the ball on the club be?.
The force of a golf club on a golf ball is 200 N forward, according to Newtons third law of motion, every action has an equal and opposite reaction. Thus, the force of the ball on the club will be the same as 200 N but will act in the opposite direction, i.e., backward.
However, one source stated that the force of a golf club on a golf ball is 22.5 N but it was later found to be incorrect due to an error in calculation
The force of the ball on the club will be 200 N backward as a result of the equal and opposite reaction according to Newton's third law of motion.
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2 The man who set up the first psychology laboratory was answer : Wilhelm Wundt and John Watson and Abraham Maslow and Edward Tichener ?
The man who set up the first psychology laboratory was Wilhelm Wundt
What is a Psychology Laboratory?The psychology laboratories are specially designed spaces where psychology students can gather data from human subjects using the same tools as licensed psychologists.
It can be noted that in 1879, Wundt founded the first psychological laboratory of the world in Leipzig, Germany, where he mainly studied sensations and feelings by employing experimental methods.
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What gravitational force does the moon produce on the Earth if their centers are 3.88x108 m apart? The moon has a mass of 7.34x1022 kg and the earth has a mass of 5.97x1024 kg.
Explanation:
The gravitational force between two masses, m1 and m2, separated by a distance, r, can be calculated using the formula:
F = G * (m1 * m2) / r^2
where
F is the gravitational force,
G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2),
m1 is the mass of the first object,
m2 is the mass of the second object,
r is the distance between the centers of the two objects.
Plugging in the values:
F = G * (7.34 x 10^22 kg * 5.97 x 10^24 kg) / (3.88 x 10^8 m)^2
= (6.67 x 10^-11 Nm^2/kg^2) * (4.36 x 10^47 kg^2) / (15.0244 x 10^16 m^2)
= 2.80 x 10^22 N
So, the moon produces a gravitational force of 2.80 x 10^22 N on the Earth when their centers are 3.88 x 10^8 meters apart.
A 50-kg meteorite moving at 1000 m/s strikes earth. Assume the velocity is along the line joining earth's center of mass and the meteor's center of mass.
The internal energy of the meteor is 25000 kJ.
What is the internal energy?We to note that from the law of the conservation of energy that energy can not be created nor destroyed but that energy can be converted from one form to the other and that is the basis of the discussion that we are going to have in this problem.
We know that the internal energy of the meteor was converted to the kinetic energy of the meteor so we can now write that;
E = 1/2 mv^2
E = 0.5 * 50 * (1000)^2
= 25000 kJ
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Missing parts;
A 50-kg meteorite moving at 1000 m/s strikes earth. Assume the velocity is along the line joining earth's center of mass and the meteor's center of mass.
Calculate the internal energy.
A car moves along a straight line whose equation of motion is given by s = 12t + 3t^2 − 2t^3, where s is in meters and t in seconds. The velocity of car at start will be
a. 7m/s
b. 9m/s
c. 12 m/s
d. 16m/s
A car moves along a straight line . The velocity of car at start will be 12m/s.
Option C is correct.
Calculating the problem:s = 12t + 3t² - 2t³
[tex]\frac{ds}{dt}[/tex] = 12 + 6t - 6t
so t = 0 then
[tex]\frac{ds}{dt}[/tex] = 12 m/s
What does velocity mean?
A vector representation of the time-dependent displacement experienced by an object or particle is velocity. The meter per second (m/s) is the standard unit of velocity magnitude, which is also known as speed. Alternately, the magnitude of a velocity can be expressed in centimeters per second (cm/s).
Why is velocity a unit of the vector?Because velocity has magnitude as well as direction, it is a vector quantity. Speed, on the other hand, is a scalar quantity because it only has a magnitude and no direction.
What kinds of speeds exist?Uniform velocity, variable velocity, average velocity, and instantaneous velocity are the various velocities
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Find the value of 10 joule on a system which has 10 cm, 100 g and 30 s as the
fundamental units.
10 Joule hav an equal value of 90,000 gr.cm².s² in a system with 10 cm, 100 gram, and 30s as the fundamental units.
Joule is a standard units consisted of kg, m², and s² units. We can breakdown the value of 1 Joule into:
1 Joule = 1 kg.m²/s²
Hence, the value of 10 Joule equals to:
10 Joule = 10 kg.m²/s²
Next, we need to assume N as the converted value under the given fundamental units. The value of 10 Joule in the fundamental units will be:
10 Joule = N (100gr) (100cm) (30s)
10 kg. m²/s² = N (100gr) (100cm) (30s)
10 kg. m² s⁻² = N (100gr) (100cm) (30s)
N = 10 (kg/10gr) (m/100cm)² (s/30s)⁻²
N = 10 (1000gr/100gr) (100cm/100cm)² (1s/30s)⁻²
N = 10 (10gr) (1cm)² (1/30 s)⁻²
N = 10 (10gr) (1cm²) (30s)²
N = 90,000 gr.cm².s²
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A car travels on the entrance ramp to a freeway as it accelerates from 30 mph to the freeway speed of 70 mph for 4. 0 s. Suppose that the car moves with the constant acceleration.
Assuming that the car moves with a constant acceleration, the average acceleration over the 4 second period can be calculated as follows:
Average acceleration = (70 mph - 30 mph) / (4 s) = 15 mph / s
This means that the car accelerates from 30 mph to 70 mph in 4 seconds, with an average acceleration of 15 mph per second.
Furthermore, the acceleration can be used to calculate the velocity of the car at any given point in the 4 second period. The equation for this is:
Velocity = Initial Velocity + Acceleration * Time
Therefore, the velocity of the car at 1 second is 30 mph + 15 mph/s * 1s = 45 mph, and the velocity of the car at 2 seconds is 30 mph + 15 mph/s * 2s = 60 mph. This can be extended for the entire 4 second period.
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which one of the following statements is true concerning the strength of the electric field between two oppositely charged parallel plates? group of answer choices it is a maximum near the negatively charged plate. it is zero midway between the plates. it is a maximum midway between the plates. it is a maximum near the positively charged plate. it is constant between the plates except near the edges.
The electric field is constant between the plates except near the edges.
Electric field can be considered as an electric property associated with each point in the space where a charge is present in any form. An electric field is also described as the electric force per unit charge.Electric fields are usually caused by varying magnetic fields or electric charges. Electric field strength is measured in the SI unit volt per meter (V/m).The direction of the field is taken as the direction of the force which is exerted on the positive charge. The electric field is radially outwards from positive charge and radially in towards negative point charge.The electric field is generated by the electric charge or by time-varying magnetic fields. In the case of atomic scale, the electric field is responsible for the attractive forces between the atomic nucleus and electrons which hold them together.To know more about electric field visit:
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what is the component of your displacement in the x-direction, in meters?
The component of displacement in the x-direction is -20.8272 m. displacement in x direction = -20.8272 m
initial walk = 10.5 m
Toward 20 degree west of north, then 22.5 m toward 40 degree south of west;
Total distance in x direction = -20.8272 m;
Sum of x components = -10.5 * sin(20) + (-22.5 * cos(40));
The x-axis component of the displacement vector from P1 to P2 is (x2 - x1), and the y-axis component is (y2 - y1). It is possible to write d = (x2 - x1)i + (y2 - y1)j to represent the displacement vector d from P1 to P2. (x2 - x1) units in the x-direction plus (y2 - y1) units in the y-direction make up the displacement d. The x-component and y-component are typically thought of as the components of a vector in a two-dimensional coordinate system. V = (vx, vy), where V is the vector, can be used to express it. They are the components of the vectors produced along the axes.
Question
Suppose you first walk 10.5 m in a direction 20 degree west of north and then 22.5 m in a direction 40 degree south Of west.
what is the component of your displacement in the x-direction, in meters?
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A horizontal force of 8. 0 n acts on an object mass 6. 0 kg over a distance of 10 m along a horizontal, frictionless surface. What is the change in its kinetic energy over this 10 m distance?.
Change in kinetic energy is 80J.
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.Kinetic energy of an object is the measure of the work an object can do by virtue of its motion.Changes in potential and kinetic energy go hand in hand. If there is a negative change in potential energy, there will be a positive change in kinetic energy and vice versa.We know that change in kinetic energy is total work done by the object.
i.e. Change in KE = Force * Displacement
Given, Force = 8N
Displacement = 10m
Putting these values in above equation we get: KE = 8*10 = 80 N.
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Acid rain is precipitation that has become acidic over time. It is caused by pollution from human activities. Acid rain is harmful to aquatic environments and forests. Which of these could be used to determine the amount of acid rain that might occur in the hydrologic cycle of an area?.
Answer:
A device that measures the amount of chemicals released into the air by a factory.
Three Identical Metallic Conducting Spheres Carry The Following Charges: Q1 = +7.8 ΜC, Q2 = −1.4 ΜC, And Q3 = −4.0 ΜC. The Spheres That Carry The Charges?
Charge on third sphere is 5.1MC after making a contact with the other two metallic conducting spheres.
Specifically, in the event that a metal sphere is charged, since charge can stream unreservedly through a metal, the self-shock of charges will bring about all the charge living on the outer layer of the sphere, which then, at that point, acts as an empty circular accuse dispersion of zero electric field inside.
From the given data, Q1 and Q2 are brought into contact as they are both conductors, as such there will be evenly distribution of charges.
Firstly,charge on each sphere(Q) = Q1 + Q2 / 2
= +7.8 MC + (- 1.4 MC) / 2
=>+7.8 MC + (-0.7)MC = 7.1MC
Now, one of those two spheres is brought into contact with the third sphere ; Q is brought into contact with Q4 = Q + Q3 / 2
= 7.1MC - 4 MC /2
=7.1MC -2MC
= 5.1 MC
Hence,5.1MC is the final charge on the third sphere.
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(Complete question) is:
Three identical metallic conducting spheres carry the following charges: Q1 = +7.8 MC, Q2 = −1.4 MC, and Q3 = −4,0 MC. The spheres that carry the charges Q1 and Q2 are brought into contact. Then they are separated. After that, one of those two spheres is brought into contact with the third sphere that carries the charge Q3. What is the final charge on the third sphere?
the designated length of a ladder is:
The designated length of a ladder refers to the maximum length that a ladder can safely be used for. This length is determined by the manufacturer and is based on various factors.
Designated Length depends on factors like:
The materials usedThe weight capacity of the ladderThe design of the ladderThe designated length is typically marked on the ladder itself and is usually the distance from the ground to the highest rung that can be safely reached. It is important to note that the designated length does not refer to the overall length of the ladder, but rather the distance it can be safely extended.
Exceeding the designated length of a ladder can be extremely dangerous and can result in the ladder collapsing or becoming unstable. This can lead to serious injury or even death. It is therefore essential to always use a ladder within its designated length, and to follow all safety instructions provided by the manufacturer.
In addition to following the designated length, it is also important to use a ladder on a stable surface and to ensure that it is properly secured. This will help to prevent accidents and ensure that the ladder is used safely and effectively.
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To navigate, a porpoise emits a sound wave that has a wavelength of 4.2 cm. The speed at which the wave travels in seawater is 1522 m/s. Find the period of the wave
The time required to complete one vibration in the density of the medium is referred to as the sound wave's time period.
It is denoted by the letter T. Its SI unit comes in second (s).
Given: [tex]C = 1522m/s[/tex]
λ = [tex]4.2*10^{-2} m[/tex]
Frequency of soundwave can be determine by
f = c/λ
[tex]f = \frac{1522}{4.2*10^{-2} }[/tex]
f = 3.623
Period of sound wave is given by:
[tex]T = \frac{1}{T}[/tex]
[tex]T = \frac{1}{3.623}[/tex]
[tex]T = 0.27601[/tex]
Therefore, the period of sound wave is 0.27601 s.
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The speed of sound in a particular fluid is 1480 m/s. What is the wavelength of sound waves of frequency 23 kHz that travel through the fluid?
6. 4 cm
5. 5 cm
2. 1 m
3. 2 cm
The wavelength of sound waves of frequency 23 kHz that travel through the fluid is 0.064 metres.
V = 1480 m/s
f = 23 kHz
We know the relation
V = f λ
V= velocity in a particular medium
f = frequency
λ = wavelength of sound wave
λ= [tex]\frac{1480}{23000}[/tex]
λ = 0.064 metre
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nasa's ames research center in mountain view, california, houses a 20g centrifuge used to conduct research and training to solve real world problems related to the effects of acceleration on systems. it consists of a horizontal rail system with a 58-foot diameter mounted on a central axis, as shown in the figure below. an astronaut is using the centrifuge for training on high accelerations during spaceflight. the astronaut is seated 29.0 ft from the axis of rotation. at what rotation rate, in revolutions per second, will the astronaut experience a centripetal acceleration of 15.9g?
Rotating objects are subject to centripetal and centrifugal forces. An object is kept moving in a circle by the centripetal force, which is always directed toward the center of the circle.
What is Centripetal force?As an illustration, the centripetal force of the sun's gravitational field maintains the Earth rotating around it. The centrifugal force, meanwhile, is an apparent outward force acting on a rotating object.
The sensation you get while riding a merry-go-round that makes you want to fly outwards is an illustration of centrifugal force.
Centrifugal force is felt by passengers when they turn a corner in an automobile or when an aircraft banks into a turn. When kids ride on a merry-go-round or during a washing machine spin cycle, it happens.
Therefore, Rotating objects are subject to centripetal and centrifugal forces. An object is kept moving in a circle by the centripetal force, which is always directed toward the center of the circle.
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