When the box is placed on a horizontal surface, it experiences a force even if it is at rest. The forces that a box encounters are gravity, frictional force, and weight.
The weight is how much?Weight is the gravitational attraction of the Earth's centre on items. Gravity is the resultant force that draws a mass towards Earth. This only happens on Earth and a mass, as opposed to gravitational pull, which happens whenever two masses are in contact.
What is a mass?In physics, mass is a way to measure inertia, a fundamental property of all matter. Basically, it describes the opposition a body or piece of matter offers to a change in velocity or location.
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why is a battery used when we require more electricity
A battery is used when we require more electricity because it can store and release electrical energy as needed.
Batteries consist of one or more cells, each of which contains two electrodes and an electrolyte that allows for the flow of charged particles between the electrodes. When a battery is connected to a device, the charged particles flow from the positively charged electrode to the negatively charged electrode, providing a flow of the electricity.
The amount of electricity stored in a battery is limited, but it can be released as needed, even when the source of the electricity is not available. This makes batteries useful for supplying electrical energy in situations where there is a temporary increase in demand, such as when more devices are turned on or when the source of electrical energy is unavailable, such as during a power outage.
Additionally, batteries are portable and can be easily carried, making them useful for supplying electrical energy in remote locations where there is no access to the electrical grid.
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what would happen to the motion of the projectile if we do not ignore air resistance? group of answer choices it is impossible to think about what would happen to the object. the object would move in a straight line. the range would be a shorter distance. purple the object would not fall to the ground.
Projectile motion exhibits negligible horizontal acceleration if air resistance is disregarded. As a result, the particle moves horizontally at a constant speed.
A projectile is an item on which gravity is the only force at work. Projectiles come in a variety of forms. A fallen object is referred to as a projectile motion (provided that the influence of air resistance is negligible).A projectile is something that is thrown vertically upward (provided that the influence of air resistance is negligible). In addition, any object sent upward at an angle to the horizontal is considered a projectile (provided that the influence of air resistance is negligible). Any object that, after being launched or dropped, keeps moving due to its own inertia and is solely impacted by the gravitational force acting downward is considered a projectile.
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A bus is initially traveling north at a constant speed, as shown in the figure above. As the bus starts to make a left turn without changing speed, a passenger notices that a box on the floor starts sliding toward the right side of the bus. Which of the following top views of the box, when correctly labeled, would best represent all of the horizontal forces exerted on the box as it starts sliding?
Assuming that the box is not sliding off the bus, the forces exerted on it can be represented by the following diagram:
F
F: friction force
The friction force, represented by F in the diagram, acts in the opposite direction of the box's sliding motion. This force is caused by the friction between the box and the bus floor, and it is the only force present in the system. As the bus turns to the left, the box's sliding motion is directed to the right. The direction of the friction force then changes to the left, opposing the motion of the box and slowing it down until it stops.
if i double the length, and halve the diameter of a copper wire, what is the value of its new resistance? original resistance was r0
The new resistance of the wire will be 4 times the original resistance (r0).
This is because the resistance of a wire is proportional to its length and inversely proportional to its cross-sectional area. Doubling the length of the wire will double its resistance. Halving the diameter of the wire will result in a reduction of its cross-sectional area by a factor of 4, which will result in an increase in its resistance by a factor of 4. The net effect is that the resistance of the wire will be 4 times the original resistance.
To be more precise, the resistance R of a wire is given by the equation
R = ρL / A
where ρ is the resistivity of the material, L is the length of the wire, and A is its cross-sectional area. So, if we double the length and halve the diameter, the new resistance will be given by
R = ρ(2L) / (A/4) = 4ρL / A = 4R0.
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examine the sketch of a bend in a river. the arrows show the water flow direction. in which of the four lettered locations will the water be moving at the highest velocity?
The river speed is maximum at point A. Option A is the correct answer.
The speed of a river on a circular turn is maximum at the outer part of the curve. This is because the water flowing in the river has to travel a greater distance on the outer curve as compared to the inner curve. Therefore, to cover the same distance in the same amount of time, the speed of the water has to be greater on the outer curve.
This is known as the principle of conservation of angular momentum, which states that the angular momentum of the water flowing in the river is conserved as it moves around the curve.
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--The complete question is, Examine the sketch of a bend in a river. The arrows show the water flow direction. In which of the four lettered locations will the water be moving at the highest velocity?
A) A
B) B
C) C
D) D--
if a pendulum-driven clock gains 5.20 s/day, what fractional change in pendulum length must be made for it to keep perfect time? (your answer should be negative if the length is decreased.)
The fractional change in pendulum length must be -0.0026, meaning the pendulum length should be decreased by 0.0026 of its original length.
To keep a pendulum-driven clock accurate, the fractional change in pendulum length must be negative since a decrease in length will cause the pendulum to go faster.
To find the exact fractional change required, you must use the equation for simple harmonic motion, which states that the period of the pendulum is proportional to the square root of the length.
If the clock is gaining 5.20 s/day, then the fractional change in pendulum length must be -0.0026, meaning the pendulum length should be decreased by 0.0026 of its original length.
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he ship based on this hull design is to have a cruising speed of 24 mph. to ensure dynamic similarity for a 1:32 scale model, at what velocity should the model be tested?
The velocity with which the model should be tested is calculated to be 768 mph.
When the length, time, and force scale ratios of the model and prototype are the same, dynamic similarity exists.
Dynamic similarity enables scaling of model test outcomes to forecast matching outcomes for the full-scale prototype.
The dynamic similarity of a ship is given to have a scale 1:32.
The cruising speed of the first ship is given as, 24 mph.
So, the velocity of the model is calculated as,
⇒ 24 × 32 = 768 mph
Thus, the velocity of the model should be tested at 768 mph.
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water flows through a horizontal plastic pipe with a diameter of 0.2 m at a velocity of 9 cm/s. (a) determine the pressure drop per meter of pipe using the moody chart. (b) calculate the power lost to the friction per meter of pipe. assume that the water is at 20oc.
The pressure is 0.00038 Pa/m, and the power lost to friction per meter of pipe is approximately [tex]2.28 * 10^-7 W/m.[/tex]
To determine the pressure drop per meter of pipe and the power lost to friction, we need to calculate the friction factor using the Moody chart and the Darcy-Weisbach equation. The Darcy-Weisbach equation is:
ΔP = [tex]f * L * (v^2) / (2 * g * d)[/tex]
where ΔP is the pressure drop per meter of pipe, f is the friction factor, L is the length of pipe, v is the velocity of the water, g is acceleration that occurs because of gravity and d is pipe's diameter.
We can use the Moody chart to find the friction factor, f, based on the Reynolds number, which is a measure of the fluid flow regime. For a smooth plastic pipe, the Reynolds number can be calculated as:
Re = (v * d) / ν
where ν is the kinematic viscosity of the water, which is approximately [tex]0.000001 m^2/s[/tex] at 20°C.
Once we have the Reynolds number, we can find the friction factor from the Moody chart. For a Reynolds number of approximately 2200, the friction factor for a smooth plastic pipe is approximately 0.022.
Plugging the values into the Darcy-Weisbach equation, we find that the pressure drop per meter of pipe is:
ΔP = [tex](0.022) * (1 m) * (0.09 m/s)^2 / (2 * 9.8 m/s^2 * 0.2 m)[/tex] = 0.00038 Pa/m
To calculate the power lost to friction, we can use the equation:
P = ΔP * Q
where P is the power lost to friction and Q is the flow rate, which can be calculated as:
Q = A * v = [tex](pi/4) * d^2 * v = (pi/4) * (0.2 m)^2 * (0.09 m/s)[/tex]= [tex]0.0006 m^3/s[/tex]
Plugging the values into the power equation, we find that:
P = ΔP * Q = (0.00038 Pa/m) * (0.0006 [tex]m^3/s[/tex]) = [tex]2.28 * 10^-7 W/m[/tex]
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somewhat idealized graph of the velocity of blood in the ascending aorta during one beat of the heart. approximately how far, in cm, does the blood move during one beat?
According to the graph the blood move 8 cm during one beat.
To find how far does the blood move during one beat, we need to find the area under the velocity curve.
The blood displaces [tex]\triangle x =x_f-x_i[/tex] between t = 0.1 s and t = 0.3 s is the area under the curve from t = 0.1 s to t = 0.3 s.
In this case, the curve is a triangle, thus the area of a triangle is, area of the triangle between t = 0.1 s to t = 0.3 s.
[tex]\dfrac{1}{2} \times 0.2 \times 0.8[/tex] = 8cm
Therefore, blood moves 8 cm during one beat.
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Explain why sound waves are mechanical waves rather than electromagnetic waves.
Explanation:
Sound is a mechanical wave. Electromagnetic wave is a by-product of both electric and magnetic fields. It does not require the presence of any medium and can travel through a vacuum. In comparison, mechanical waves require the presence of a medium. It works by pushing the medium's molecules and traveling through it. Sound works this way.
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Your Best,Edwin(ii) a person scuffing her feet on a wool rug on a dry day accumulates a net charge of -34 mc. how many excess electrons does she get, and by how much does her mass increase?
The person gets 34 million excess electrons but her mass does not increase.
What is the mass ?Mass is a measure of the amount of matter in an object. It is typically measured in kilograms (kg), though other units like grams (g) and pounds (lbs) are also used. Mass is different from weight, which is a measure of the force of gravity on an object. Mass is constant in all gravitational fields, while weight changes depending on the strength of the gravitational field.
The person scuffing her feet on the wool rug is accumulating a net charge of -34 mc (microcoulombs). This means that she is gaining 34 million electrons. However, this does not increase her mass, since electrons have a very small mass compared to the overall mass of a person.
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200g of water at 90 degree celsius is mixed with 100g of water at 30 degree celsius. What is the temperature
Answer:
For temperatures between the freezing and boiling point of water, the heating curve is linear. Thus, we can use:
((200 * 90) + (100* 30))/300
Or: ((200 * 90)(temperature of first sample weighted by mass) + (100 * 30)(temperature of second sample weighted by mass) / (300)(total mass)
to find the final temperature.
100 can be factored out to get (2 * 90) + (1 * 30)) / 3
3 can be factored out every term: (2 * 30) + (1 * 10)
(The factoring out just makes mental math easier; if a calculator is available doing so is unnecessary.)
And then just work through the order of operations.
60 + 10
=70.
So in mathematics, which assumes a perfect world, you get 70.
a projectile is fired in such a way that its horizontal range is equal to 8.5 times its maximum height. what is the angle of projection?
The angle of projection is 25.2°. The result is obtained by using the formula for maximum height and horizontal range of projectile motion.
What is maximum height and horizontal range of projectile motion?The maximum height can be reached by a projectile motion is
H = (v₀²sin²θ)/2g
Where
H = maximum heightv₀ = initial velocityθ = angle of projectiong = acceleration due to gravityMeanwhile, the horizontal range can be reached is
R = (v₀² sin 2θ)/g
A projectile is fired. The horizontal range is equal to 8.5 times the maximum height. Find the angle of projection!
In this case, we get
R = 8.5 H
(v₀² sin 2θ)/g = 8.5 × (v₀²sin²θ)/2g
2(sin 2θ) = 8.5 × (sin²θ)
2(sin 2θ) = 8.5(sin²θ)
2/8.5 = (sin²θ)/(sin 2θ)
0.235 = (tan θ)/2
tan θ = 0.47
θ = arc tan 0.47
θ = 25.2°
Hence, the projectile motion has the angle of 25.2°.
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calculate the horizontal distance, xmax , in meters, that the ball has traveled when it returns to ground level.
A ball that leaves a bat and returns to the ground level will reach a maximum horizontal distance of 145.8 meters.
An object moves in projectile motion when it follows a parabolic route. When gravity is the only influencing force after one force launches the object, it happens. Projectile trajectory refers to the path that the object takes when subjected to this gravitational pull. We typically ignore air resistance out of convenience.
The following equation can be used to determine the ball's maximum horizontal distance ([tex]x_{max}[/tex]) before it hits the ground:
[tex]x_{max} =\frac{v_o^2 \times sin(2\theta)}{g}[/tex]
Where:
[tex]v_{o}[/tex] is the starting speed = 38[tex]\frac{m}{s}[/tex]
[tex]\theta[/tex] is the angle 41° higher than the horizontal
g = 9.81 [tex]\frac{m}{s^2}[/tex] is the acceleration caused by gravity.
The maximum horizontal distance is as follows:
[tex]x_{max} =\frac{v_o^2 \times sin(2\theta)}{g}=\frac{38^2 \times sin(2\times 41)}{9.8}[/tex]=145.8m
The horizontal distance, then, is 145.8 meters when the ball lands at ground level.
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you are going to an outdoor concert, and you'll be standing near a speaker that emits 51 w of acoustic power as a spherical wave. what minimum distance should you be from the speaker to keep the sound intensity level below 94 db ?
The minimum distance from the speaker to keep the sound intensity level below [tex]94 dB is 3.7 m.[/tex]
What is the intensity ?.Intensity is the amount of energy or force associated with a particular phenomenon or activity. It is usually measured in terms of power, amplitude, or strength. Intensity can be seen in many forms, including sound, light, heat, electricity, and magnetism. In terms of sound, for example, intensity is measured in decibels and is related to the loudness of a sound.
The intensity of a sound wave decreases with distance. Intensity is measured in decibels (dB) and is related to the sound pressure level (SPL) of the wave.
The formula for calculating the intensity of a sound wave at a given distance from its source is as follows:
[tex]I = I_o/r^2[/tex]
where [tex]I_o[/tex] is the initial intensity of the wave (in dB) and r is the distance from the source (in meters).
In this case, the initial intensity of the wave is 51 W as a spherical wave, so[tex]I_o = 51 W.[/tex]
We want to find the minimum distance r such that the intensity of the sound wave is 94 dB, so we can rearrange the equation to solve for r:
[tex]r^2 = I_o/Ir = sqrt(I_o/I)r = sqrt(51 W/94 dB)r = 3.7 m[/tex]
Therefore, the minimum distance from the speaker to keep the sound intensity level below 94 dB is 3.7 m.
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in this activity, you will create a graph of the displacement vs. the weight on the spring. what do you think this graph will look like?
The mass is proportional to the spring displacement, if you're picturing a mass attached to a spring suspended from the ceiling.
How does weight impact a spring?
Since the force the spring applies to you is proportional to your weight, you provide a force to the spring that is equal to your mass, compressing it. Your mass will affect how long the spring changes.
According to Hooke's law, the force and displacement for an elastic spring are proportional to one another. It implies that when the spring force rises, the displacement rises as well.
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A rope that makes a 15° angle with the
horizontal pulls a block weighing 3 Na
distance of 10 meters to the right at a
constant velocity. The tension in the rope
is a 2 N force. How much work is done
by the rope acting on the block in the
horizontal directi on? Let F, be the
tension in the rope and Ax be the
3. displacement in the x-direction.
A. 28.98 J
B. 20 J
C. 189.34 J
D. 19.32 J
Answer:
Explanation:
d
Two friends meet up at the ice skating rink. They skate up to each other and come to a stop. Then they push off each other, moving in opposite directions. If the first friend has a mass of 50 kg and goes forward at 3 m/s, then what speed does the other 75kg friend go back at? [Explosion]
Answer:
yes becomes two friends are the same
When that two friend are coming in opposite direction after explosion a friend having having 75kg mass will go back at 2 m/s speed.
What is momentum ?Momentum is defined as mass times velocity of body. it is denoted by p and its SI unit is Kg.m/s. It has both magnitude and direction. it is a vector quantity. it tells about the moment of the body. it is denoted by p and expressed in kg.m/s. mathematically it is written as p = mv. A body having zero velocity or zero mass has zero momentum. its dimensions is [M¹ L¹ T⁻¹].
Momentum is conserved throughout the motion.
initial momentum = final momentum
Given,
mass of first friend m₁ = 50kg
velocity of first friend v₁ = 3m/s
mass of second friend m₂ = 75kg
velocity of second friend v₂ = ?
According to conservation of momentum,
m₁v₁ = m₂v₂
50×3 = 75×v₂
v₂ = 150 ÷ 75
v₂ = 2 m/s
Hence second friend will go back at 2m/s.
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a running back with a mass of 70 kg and a speed of 9 m/s collides with, and is held by, a 105-kg defensive tackle going in the opposite direction. how fast must the tackle be going before the collision for their speed afterward to be zero?
If a running back with a mass of 70 kg and a speed of 9 m/s collides , then speed of tackle before the collision is 6 m/s .
Let the speed of the defensive tackle before the collision be = v .
The momentum of the system before the collision is given by the momentum of the running back,
⇒ that is ; 70 × 9 = 630 Kgm/s , and
the momentum of the tackle is , (-105 kg) × (v m/s) ;
After the collision, the momentum of the system must be zero, so the momentum before the collision must equal the momentum after the collision ;
⇒ (70 × 9) + (-105 × v) = 0 ;
Solving for v, we get ;
⇒ v = 630/105 = 6 m/s
Therefore , the defensive tackle must be going 6 m/s in the opposite direction before the collision for the two players to come to a stop after the collision.
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predict which penny will land first, the penny moving horizontally, or the one that simply drops off the table. explain.
It is observed that both the pennies will land at the same time. This is because second penny has only horizontal velocity.
Projectile motion occurs when an object moves through two or more dimensions simultaneously, usually under the influence of gravity. The kinematic equations regulating projectile motion apply independently in each dimension, which is a crucial aspect of the motion.
Both pennies will land at the same time. The second penny's velocity is fully horizontal, therefore its vertical velocity is still zero, and this is the explanation for it. As a result, it will have the exact same kinematic equation in the y-dimension as the first penny and will fall to the ground at the same moment. The time till impact will not alter regardless of the second penny's horizontal speed.
The question is incomplete. The complete question is 'If one penny is balanced on the edge of the table and you place your index finger on a second penny then flick the second penny so that it ravels off the table, while the first penny is gently nudged off the edge, which penny will land first, the penny moving horizontally or the one that simply drops off the table. Please explain the answer.'
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-.The Scablands in Washington are large
areas of erosion due to immense flooding. A
student claims the flooding of the Scablands
is due to erosion and melting of glaciers
which increased the amount of water until
it overwhelmed the dams. Using the claim
and map shown, create a claim-evidence-
reasoning model.
Water flo
Answer:
Here is a claim-evidence-reasoning (CER) model for the student's claim about the flooding of the Scablands:
Claim: The flooding of the Scablands is due to erosion and melting of glaciers which increased the amount of water until it overwhelmed the dams.
Evidence:
Erosion patterns in the Scablands that suggest a large amount of water was present in the region.
The presence of glacial deposits in the area.
The location of the Scablands near glacial formations that would have melted and contributed to the increase in water.
Reasoning: The evidence supports the idea that melting glaciers and erosion caused a significant increase in water in the region, which then overwhelmed the dams and caused flooding in the Scablands. The presence of glacial deposits and the proximity to active glacial formations suggest that a large amount of water was released into the area, causing the observed erosion patterns and the flooding.
Explanation:
is the electric potential at point a higher than, lower than, or equal to the electric potential at point b ? explain.
The electric potential is a scalar quantity that depends on the distribution of charges and the geometry of the system. In general, the electric potential is defined as the amount of work required to bring a unit positive charge from infinity to a point in the electric field.
If there are more positive charges near point A than near point B, then the electric potential at point A would be higher than the electric potential at point B. Conversely, if there are more negative charges near point A than near point B, then the electric potential at point A would be lower than the electric potential at point B.
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consider two identical spherical balls submerged in water at different depths. will the buoyant forces acting on the two balls be the same or different? why?
The buoyant forces acting on the two balls will be the sam. This is because buoyant force is determined by the volume of the object and not the depth at which it is submerged.
The buoyant force is the same for any object of the same volume regardless of the depth.
The buoyant force is an upward force exerted on a submerged object by the surrounding liquid. The magnitude of this force is equal to the weight of the liquid displaced by the object. This force is commonly used to explain why objects float in water.
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a carpinter is pounding a nail into the wall the reaction force to the force of a hammer hitting a nail is
Newton's third law of movement expresses that the response power to the power of a hammer striking a nail is equivalent and inverse.
As indicated by this, there is an inverse and equivalent reaction to each activity. At the point when the hammer strikes the nail, the nail hits back with equivalent and inverse power.
The power that drives the nail into the wall is alluded to as the reaction force. The reaction power's course is the specific inverse of the applied power's heading.
As an outcome, the powers are adjusted and energy is moved from the hammer to the nail.
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A 8 kg Ice skater is moving at 5 m/s and is headed towards a stationary 2 kg snowman. After the two collide, the ice skater has 0 m/s of velocity and the snowman moves forward. What is the velocity of the snowman?
Answer:
[tex]20\; {\rm m\cdot s^{-1}}[/tex], assuming that friction is negligible.
Explanation:
If an object of mass [tex]m[/tex] moves at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of this object would be [tex]p = m\, v[/tex].
if friction is negligible, the sum of the momentum should be the same before and after the collision.
Before the collision:
Momentum of the ice skater was [tex](8\; {\rm kg})\, (5\; {\rm m\cdot s^{-1}}) = 40\; {\rm kg \cdot m\cdot s^{-1}}[/tex].Momentum of the snowman was [tex](2\; {\rm kg})\, (0\; {\rm m\cdot s^{-1}}) = 0\; {\rm kg\cdot m\cdot s^{-1}}[/tex].In other words, the sum of momentum was [tex]40\; {\rm kg\cdot m\cdot s^{-1}}[/tex] before the collision.
After the collision:
Momentum of the ice skater became [tex](8\; {\rm kg})\, (0\; {\rm m\cdot s^{-1}}) = 0\; {\rm kg \cdot m\cdot s^{-1}}[/tex].Momentum of the snowman needs to be found.The sum of the momentum stays unchanged at [tex]40\; {\rm kg\cdot m\cdot s^{-1}}[/tex]. Subtract the momentum of the ice skater from the sum to find the momentum of the snowman:
[tex]40\; {\rm kg\cdot m\cdot s^{-1}} - 0\; {\rm kg\cdot m\cdot s^{-1}} = 40\; {\rm kg\cdot m\cdot s^{-1}}[/tex].
Divide the momentum of the snowman by its mass to find its velocity:
[tex]\begin{aligned}\frac{40\; {\rm kg\cdot m\cdot s^{-1}}}{2\; {\rm kg}} = 20\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
In other words, the collision of the snowman would be [tex]20\; {\rm m\cdot s^{-1}}[/tex] after the collision.
on a two-lane highway (not divided), a car headed north experiences a centripetal acceleration directed toward the east. simultaneously, a truck passes the car, headed south in the other lane. the direction of the centripetal acceleration on the truck is
The direction of the centripetal acceleration on the truck is toward the west is zero.
Find the acceleration of the truck?Centripetal acceleration is always towards the center of circular motion. In this case, a car traveling north on a two-lane highway is experiencing eastward centripetal acceleration. This indicates that the car is turning east.
At the same time, a truck overtakes a southbound vehicle in the opposite lane. The track does not turn east, so there is no eastward centripetal acceleration. Since the truck is only moving in a straight line, the centripetal acceleration is zero.
Therefore, the direction of centripetal acceleration of the track is zero.
What is the acceleration ?Acceleration is defined as the rate of change of velocity. It is a vector quantity, meaning that it has both magnitude and direction. In physics, acceleration is most commonly defined as the rate of change of velocity divided by the time interval over which the change occurs. Acceleration is typically measured in meters per second squared (m/s2). Acceleration can also be defined as the rate of change of momentum over a given time interval.
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a ping-pong ball of mass m rolls off the edge of a table that is 1.0 m high. when the ball strikes the floor its speed is5.0 m/s. how fast was it rolling when it left the table.
The ball was rolling at a speed of 4.44 m/s when it left the table.
What is speed?
Speed is a scalar quantity that describes the magnitude of an object's velocity, or the rate at which an object is moving. It is defined as the distance traveled by an object divided by the time it takes to travel that distance. The unit of speed is usually meters per second (m/s) or kilometers per hour (km/h).
We can use the conservation of energy principle to solve this problem. The initial potential energy of the ball when it was at the edge of the table is equal to its weight multiplied by its height above the floor:
PEi = mgh
PEi = m * 9.8 m/s² * 1.0 m = 9.8 N * m
At the moment the ball strikes the floor, all of its potential energy has been converted into kinetic energy:
KEf = 1/2 * m * v²
where v is the velocity of the ball just before it strikes the floor. We can equate the initial potential energy to the final kinetic energy and solve for the velocity of the ball when it left the table:
PEi = KEf
9.8 N * m = 1/2 * m * v²
v²= 2 * PEi / m = 2 * 9.8 N * m / m = 19.6 m²/s²
v = √(v²) = √(19.6 m²/s²) = 4.44 m/s
So, the ball was rolling at a speed of 4.44 m/s when it left the table.
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3) an electric wagon changes its speed at the average rate of 11.2 m/s2. how much time does it take to increase its speed from 79.4 m/s to 119.5 m/s?
To calculate the time required to increase the speed of an electric wagon from 79.4 m/s to 119.5 m/s at an average rate of 11.2 m/s2, you can use the following equation:
Time = (119.5 - 79.4) / 11.2This gives a result of 4.03 seconds.
When the electric wagon is accelerating, the driver should be mindful of the acceleration rate to ensure that the vehicle is accelerated safely. If an excessive rate of acceleration is used, the vehicle may end up going too fast and this could be dangerous. Therefore, it is important to be aware of the acceleration rate and to keep an eye on the speedometer to ensure that it does not exceed the desired speed.
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for springs connected in series, how does the effective spring constant compare to the individual spring constants? determine a simple mathematical relationship.
For springs connected in series, the effective spring constant can be compared to the individual spring constants mathematically by k1 + k2 + k3 +... + kn = keff
The effective spring constant, also known as the equivalent spring constant, is equal to the sum of the individual spring constants for springs connected in series.
where Keff represents the effective spring constant and ki represents the spring constant of the ith spring in the series.
It is vital to notice that springs in a series connection experience the same amount of displacement and hence the same amount of force. Each spring's displacement is proportional to its spring constant, and the overall displacement of the system is equal to the sum of each spring's displacements. This indicates that the system's equivalent spring constant will be the total of the separate spring constants indicated above.
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what two stars alternate every 13,000 years as earth’s northern star?
Every 13,000 years, Polaris and Vega switch places as the North Star. Today, Polaris, the brightest star in the constellation Ursa Minor, lies within one degree of the Earth's axis.
What northern star was Earth's before Polaris?Currently, Polaris is practically exactly where the Earth's rotation axis points. However, the North Star in the year 3000 BCE was a star called Thuban (also known as Alpha Draconis), and due to the precession of the rotation axis, the bright star Vega will become the North Star in roughly 13,000 years.
Polaris became the North Star at what point?The North Star around 3000 BC was a slender star called Thuban in the constellation of Draco. The North Star did not replace Polaris.
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