how does the tilt of earth affect the hours of daylight north of the tropical of cancer at the time of year shown?​

Answer:

The object gains or loses electrons to become charged. Both are a movement of electrons from the negative to the positive charge. A circuit has a continuous current provided by a voltage source.

Explanation:

Answer:

car d

Explanation:

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Answer:

D

Explanation:

transparent_objects that allows light to pass through and can you see through them

Answer:

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Explanation:

I need points sorry

Answer:

honestly this was so long ago can i get brainliest i need 2 more until i am at expert level

Explanation:

Complete Question:

A finch rides on the back of a Galapagos tortoise, which walks

at the stately pace of 0.060 m/s. After 1.5 minutes the finch tires of

the tortoise’s slow pace, and takes flight in the same direction for

another 1.5 minutes at 11 m/s.

What was the average speed of the  finch for this 3.0-minute interval?

Answer:

[tex]Speed = 5.53 m/s[/tex]

Explanation:

Distance is calculated as:

[tex]Distance = Speed * Time[/tex]

First, we calculate the distance for the first 1.5 minutes

For the first 1.5 minutes, we have:

[tex]Speed = 0.060m/s[/tex]

[tex]Time = 1.5\ mins[/tex]

[tex]D_2= 0.060m/s * 1.5\ mins[/tex]

Convert 1.5 mins to seconds

[tex]D_2= 0.060m/s * 1.5 * 60s[/tex]

[tex]D_2= 5.4m[/tex]

Next, we calculate the distance for the next 1.5 minutes

[tex]Speed = 11m/s[/tex]

[tex]Time = 1.5\ mins[/tex]

[tex]D_2= 11m/s * 1.5\ mins[/tex]

Convert 1.5 mins to seconds

[tex]D_2 = 11m/s * 1.5 * 60s[/tex]

[tex]D_2= 990m[/tex]

Total distance is:

[tex]Distance = 990m + 5.4m[/tex]

[tex]Distance = 995.4m[/tex]

The average speed for the 3.0 minute interval is:

[tex]Speed = \frac{Distance}{Time}[/tex]

[tex]Speed = \frac{995.4\ m}{3.0\ mins}[/tex]

Convert 3.0 minutes to seconds

[tex]Speed = \frac{995.4\ m}{3.0 * 60 secs}[/tex]

[tex]Speed = \frac{995.4\ m}{180 secs}[/tex]

[tex]Speed = 5.53 m/s[/tex]

Answer:

1. 65 N.

2. 160 N.

3. 0 N.

4. 210 N.

5. 90 N.

Explanation:

1. Determination of the net force.

Force applied to the right (Fᵣ) = 80 N

Force applied to the left (Fₗ) = 145 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 145 – 80

Fₙ = 65 N

Thus, the net force is 65 N

2. Determination of the net force.

Force 1 applied to the left (F₁) = 35 N

Force 2 applied to the left (F₂) = 125 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 35 + 125

Fₙ = 160 N

Thus, the net force is 160 N.

3. Determination of the net force.

Force applied to the right (Fᵣ) = 75 N

Force applied to the left (Fₗ) = 75 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 75 – 75

Fₙ = 0

Thus, the net force is 0 N

4. Determination of the net force.

Force 1 applied to the right (F₁) = 150 N

Force 2 applied to the right (F₂) = 60 N

Net force (Fₙ) =?

Fₙ = F₁ + F₂

Fₙ = 150 + 60

Fₙ = 210 N

Thus, the net force is 210 N.

5. Determination of the net force.

Force applied to the right (Fᵣ) = 115 N

Force applied to the left (Fₗ) = 25 N

Net force (Fₙ) =?

Fₙ = Fᵣ – Fₗ

Fₙ = 115 – 25

Fₙ = 90 N

Thus, the net force is 90 N

Answer: Yes indeed it does.

Explanation: Newton's Three Laws of Motion explain how forces create motion in sport. These laws are usually referred to as the Laws of Inertia, Acceleration, and Reaction. maybe brainliest to level up.

Answer:

The force will be [tex]F_{c}=2.47 N[/tex]

Explanation:

Let's use the centripetal force equation.

[tex]F_{c}=m\omega ^{2}R[/tex]

Where:

m is the mass of the bunch of bananas

ω is the angular speed

R is the radius

Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.

[tex]\omega =0.25\frac{rev}{s}=0.25*2\pi \frac{rad}{s}=1.57 \frac{rad}{s}[/tex]

FInally, the force will be:

[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]

[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]

[tex]F_{c}=2.47 N[/tex]

I hope it helps you!

Answer:

the mass of the box is 51.98 kg.

Explanation:

Given;

applied horizontal force, F = 450 N

coefficient of friction, μ = 0.795

constant velocity, v = 1.2 m/s

At constant velocity, the acceleration of the object is zero and the net force will be zero.

[tex]F_{Net} = F - F_k\\\\0 = F - F_k\\\\F_k = F\\\\\mu \ N = F\\\\\mu (mg) = F\\\\m = \frac{F}{\mu g} \\\\m = \frac{405}{0.795 \ \times \ 9.8} \\\\m = 51.98 \ kg[/tex]

Therefore, the mass of the box is 51.98 kg.

This question is incomplete, the complete question is;

Styrofoam has a density of 32kg/m³.

What is the maximum mass that can hang without sinking from a 50-cm diameter Styrofoam sphere in water

Answer: the required maximum mass is 63.3459 kg

Explanation:

Given that;

diameter d = 50 cm = 0.5 m

radius r = 0.5 / 2 = 0.25 m

Styrofoam density = 32kg/m³

Volume of sphere V = 4/3 πr³.

we substitute

V = 4/3 π(0.25)³

V = 0.06544 m³

Mass of sphere M = Volume × Density

we substitute

Mass of sphere M = 0.06544 m³ × 32kg/m³

Mass of Sphere M = 2.09408 kg

Mass of the water it displace will be;

volume × density

we know that density of water = 1000 kg/m³

so

Mass of the water it displace = 0.06544 m³ × 1000kg/m³

= 65.44 kg

Now the difference between mass of water and mass of the Styrofoam will be the amount of mass that the sphere can support

so

65.44 kg - 2.09408 kg = 63.3459 kg

Therefore, the required maximum mass is 63.3459 kg

The object takes 0.5 seconds to complete one rotation, so its rotational speed is 1/0.5 rot/s = 2 rot/s.

Convert this to linear speed; for each rotation, the object travels a distance equal to the circumference of its path, or 2π (1.2 m) = 2.4π m ≈ 7.5 m, so that

2 rot/s = (2 rot/s) • (2.4π m/rot) = 4.8π m/s ≈ 15 m/s

thus giving it a centripetal acceleration of

a = (4.8π m/s)² / (1.2 m) ≈ 190 m/s².

Then the tension in the rope is

T = (50 kg) a ≈ 9500 N.

Answer:

true

Explanation:

the dog hasn't moved, displacement has direction, and there is no movement or direction involved, his final position and initial are the same

Answer:

4.3 * 10^28 kg

Explanation:

Given:

Period, T = 84s

Radius of satellite orbit, r = 8*10^6

Using the relation :

M = 4π²r³ / GT²

Where G = Gravitational constant, 6.67 * 10^-11

M = 4*π^2*(8*10^6)^3 / 6.67 * 10^-11 * 84^2

M = (20218.191872 * 10^18) / 47063.52 * 10^-11

M = 0.4295937 * 10^18 - (-11)

M = 0.4295937 * 10^29

M = 4.295937 * 10^28 kg

M = 4.3 * 10^28 kg

Mass of planet Nutron = 4.3 * 10^28 kg

Answer:

I guess C

Explanation:

cause you can just try with hot water and ice cubes you know.

and we all know that ice will melt and the hot tea will get cold.

Answer:

D option

Explanation:

heat move from hot source to cold sink untill equilibrium reached

Answer:

Jupiter's gravitational acceleration is 24.8 m/s^2

Explanation:

Recall that the weight under the influence of a gravitational acceleration G is defined as:

Weight = m * G

Then, in our case we have

372 N = 15 kg * G

G = 372/15  m/s^2

G = 24.8 m/s^2

The total mechanical energy of the particle of mass m at the surface of the planet of mass M when the distance is R (planet's radius) is [tex] E = \frac{GmM}{R}  + \frac{1}{2}mv_{e}^{2} [/tex].            

When the particle is at rest at a distance "r" from the planet's center, it only has gravitational potential energy. As the particle falls to the planet's surface, some initial gravitational potential energy converts to kinetic energy.      

The total mechanical energy of the particle at the planet's surface is equal to the sum of the gravitational potential energy and kinetic energy, so:

[tex] E = P + K [/tex]    

[tex] E = maR + \frac{1}{2}mv_{e}^{2} [/tex]  (1)

Where:

m: is the mass of the object

a: is the acceleration due to gravity on the surface of the planet

R: is the radius of the planet

[tex]v_{e}[/tex]: is the escape velocity                            

The acceleration due to gravity is given by:

[tex] a = \frac{GM}{R^{2}} [/tex]  (2)  

By entering equation (2) into (1), we have:

[tex] E =mR\frac{GM}{R^{2}}  + \frac{1}{2}mv_{e}^{2} [/tex]  

[tex] E = \frac{GmM}{R}  + \frac{1}{2}mv_{e}^{2} [/tex]

Therefore, the total mechanical energy of the particle is [tex] E = \frac{GmM}{R}  + \frac{1}{2}mv_{e}^{2} [/tex]

Learn more here:

I hope it helps you!  

Answer:

t = 0.196 s

Explanation:

The speed of a pulse is determined by the characteristics of the medium, its density and its resistance to stress, as long as these remain the speed will be constant for which we can use the kinetic expressions of the uniform movement

          v = x / t

          t = x / v

calculate

          t = 2/102

          t = 0.196 s

Answer:

Psychophysics is the subfield of psychology devoted to the study of physical stimuli and their interaction with sensory systems.

Explanation:

Hope this helps <3

Answer:

6g/cm³

Explanation:

Density is the mass per unit volume of any substance. To solve this problem:

   Density  = [tex]\frac{mass}{volume}[/tex]  

 Since mass = 600g

Let us find the volume;

    Volume  = length x width x height

   Volume  = 25cm x 2cm x 2cm  = 100cm³  

Therefore;

         Density  = [tex]\frac{600}{100}[/tex]    = 6g/cm³

Answer:

bruuuuuuuuh

Explanation:

id                  

Answer:

Ekin = 250000 [J]

Explanation:

The kinetic energy of a body or object can be calculated based on the mass and the speed with which it moves. This energy can be easily calculated by means of the following equation.

[tex]E_{kin}=\frac{1}{2} *m*v^{2}[/tex]

where:

m = mass = 200 [kg]

v = velocity = 50 [m/s]

Now replacing:

[tex]E_{kin}=\frac{1}{2} *200*(50)^{2}\\E_{kin}=250000[J][/tex]

Answer:

true true true true true

Answer:

d)infrared waves

Explanation:

A remote control uses light waves just beyond the visible spectrum of light—infrared light waves—to change channels on your TV. This region of the spectrum is divided into near-, mid-, and far-infrared.

Answer:

The time at maximum height is 2.49 s.

Explanation:

The time (t) at the maximum height can be found using the following equation:

[tex] v_{f} = v_{0} - gt [/tex]

Where:

[tex]v_{f}[/tex]: is the final velocity = 0 (at the maximum height)

[tex]v_{0}[/tex]: is the initial velocity = 80 ft/s

g: is the gravity = 9.81 m/s²

Hence, the time is:

[tex]t = \frac{v_{0}}{g} = \frac{80 \frac{ft}{s}*\frac{1 m}{3.281 ft}}{9.81 m/s^{2}} = 2.49 s[/tex]

Therefore, the time at maximum height is 2.49 s.

I hope it helps you!                        

Answer:

The slope intercept form is probably the most frequently used way to express equation of a line. To be able to use slope intercept form, all that you need to be able to do is 1) find the slope of a line and 2) find the y-intercept of a line.

Explanation:

Answer:You plot the numbers and divide

Explanation: