Answer:
For a deeper material truss, increase in distance between the top chord and bottom chord will cause the truss to bear more load with increase in Span
For Cantilever Truss ; increase in span will result in decrease in load bearing capacity of the truss
When a truss fails the areas that are affected are the supports of the truss and its corresponding spam. i.e. 4 crossbars at quarter of the span
Explanation:
The load-carrying capacity of a truss on the span is basically based on the type of truss ,
For a deeper material truss, increase in distance between the top chord and bottom chord will cause the truss to bear more load with increase in Span
For Cantilever Truss ; increase in span will result in decrease in load bearing capacity of the truss
When a truss fails the areas that are affected are the supports of the truss and its corresponding spam. i.e. 4 crossbars at quarter of the span
What does an environmental science and protection technician have in common with a microbiologist
Answer:
Environmental science and protection technicians both use laboratory equipment, such as microscopes, to analyze samples collected in the field. Environmental science and protection technicians also monitor the environment and investigate sources of pollution and contamination, including those affecting public health.
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Tank has an average bearing pressure of 105 kPa. Ground water is deep. Calculate the total, pore and effective stress before tank loading and with tank
Answer:
Hello your question is incomplete attached below is the complete question
answer :
A) At 8 meters below center
Total stress = 228.827 KN/m^2
pore water pressure = 0 KN/m^2
effective stress = 228.827 - 0 = 228.827 KN/m^2
B) At 8 meters below tank edge
Total stress = 186.289 KN/m^2
pore water stress = 0 Kn/m^2
effective stress = 186.289 - 0 = 186.289 KN/m^2
Explanation:
Given data :
Diameter = 21 m
radius = 21 / 2 = 10.5 m
soil moist = 18.4 KN/cubic meter
Average bearing pressure = 105 kPa
i) Before Loading Tank
Total stress = 8 * 18.4 = 147.2 KN/m^2
Pore pressure = 0 KN/m^2
Effective stress = 147.2 - 0 = 147.2 KN/m^2
ii) After loading Tank
No change occurs
A) At 8 meters below center
Total stress = 228.827 KN/m^2
pore water pressure = 0 KN/m^2
effective stress = 228.827 - 0 = 228.827 KN/m^2
B) At 8 meters below tank edge
Total stress = 186.289 KN/m^2
pore water stress = 0 Kn/m^2
effective stress = 186.289 - 0 = 186.289 KN/m^2
attached below is the detailed solution
What simple changes would you make to a basic PID controller if you expected the sensors to be very noisy and the target to change by large steps?
Answer:
tuning the value of Ki termincreasing/changing the Kp termExplanation:
The simple change that would be made to a basic PID controller to prevent it from been noisy is tuning the value of Ki term while
The simple change that would be made to a PID controller if you want to change the target by large steps is increasing/changing the Kp term associated with the PID controller