Answer:
When objects fall to the ground, gravity causes them to accelerate.
Explanation:
Gravity causes an object to fall toward the ground at a faster and faster velocity the longer the object falls.
The primary coil of a transformer has 200 turns and the secondary coil has 800 turns. The power supplied to the primary coil is 400 watts. What is the power generated in the secondary coil if it is terminated by a 20-ohm resistor? The primary coil of a transformer has 200 turns and the secondary coil has 800 turns. The power supplied to the primary coil is 400 watts. What is the power generated in the secondary coil if it is terminated by a 20-ohm resistor? 20W 200W 400W 800W 8000W 16000W 32000W\
Answer:
400 W
Explanation:
Ignoring the efficiency rating for the transformer we have to assume 100% .. Also, the power input to primary is equal to the power output in secondary.
This means that power input = 400 W = power output
Why do astronauts' weights differ in space?
There is a less gravitational force in space.
Their mass changes in space.
Space is colder than Earth.
There is less oxygen in space.
Answer:
There is less gravitational force in space.
Explanation:
Gravity doesn't exist as it does on Earth. Earth's gravity is as 6 times stronger as it is on the moon.
How dose the Sum Of Forces help you
Answer:
The purpose of adding force vectors is to determine the net force acting upon an object. In the above case, the net force (vector sum of all the forces) is 0 Newton. ... We would say that the object is at equilibrium. Any object upon which all the forces are balanced (Fnet = 0 N) is said to be at equilibrium.
Explanation:
hope that helps you
A proton starts from rest, and moves 1 meter through a constant electric field. The potential difference between its starting and ending points is 500 V. How fast is the proton moving at the end? How large is the electric field? How long does it take the proton to complete its journey? [Late clarification: since the field is accelerating the particle from rest, you can assume that the direction of the particle's motion is parallel to the field.]
Answer:
E = - 500 V / m, v = 30.95 10⁴ m / s and t = 6.46 10⁻⁶ s
Explanation:
For this problem we use the relation
ΔU = - E s
E = -ΔU / s
E = - 500/1
E = - 500 V / m
Now we can look for the proton approach
F = q E
let's use Newton's second law
F = m a
a = F / m
a = q E / m
Now let's use kinematics relations, where the proton starts from the rest
v₀ = 0
v² = v₀² + 2 a x
v = √2 q E / m x
v = √ (2 1.6 10⁻¹⁹ 500 / 1.67 10⁻²⁷ 1)
v = √ (958.08 108)
v = 30.95 10⁴ m / s
for time let's use the equation
x = v₀ t + ½ to t2
t = √2x / a
t = √ (2x m / qE)
t = √ (2 1 1.67 10⁻²⁷ / (1.6 10⁻¹⁹ 500))
t = √ (0.004175 10⁻⁸)
t = 0.0646 10⁻⁴ s
t = 6.46 10⁻⁶ s
A block is given an initial speed of 3m/s up a 25° incline coefficient of friction= 0.12
A) how far up the plane will it go?
B) how much time elapses before it returns to it's starting point?.
Answer:
a) y = 0.459 m , b) t = 13 s
Explanation:
a) For this exercise we use Newton's second law to find the acceleration of the block
we fix a reference system with the x axis parallel to the plane and the y axis perpendicular to it
X axis
-Wₓ - fr = m a (1)
Axis y
N - [tex]W_{y}[/tex] = 0
N = W_{y}
the friction force has the formula
fr = μ N
let's use trigonometry to find the components of the weight
sin 25 = Wₓ / W
Wₓ = W sin 25
cos 25 = W_{y} / W
W_{y} = W cos 25
we substitute in 1
- W sin 25 - μ W cos 25 = m a
- g (sin 25 - μ cos 25) = a
let's calculate
a = - 9.8 (sin 25 - 0.12 cos 25)
a - 0.25 m / s
this is the acceleration on the plane, so we can use the kinematic relations in one dimension
the highest point where the block rises the speed is zero (va = 0)
v² = v₀² - 2 a y
y = v₀² / 2g
y = 3 2 / (2 9.8)
y = 0.459 m
this is the distance the cantes block travels to stop
b) the time of the entire journey is
y = v₀ t - ½ a t²
the point where the body recesses is y = 0
0 = (vo - ½ a t) t
whose solutions are
t = 0
0 = vo - ½ a t
t = 2vo / a
t = 2 3 / 0.459
t = 13 s
A 385-g tile hangs from one end of a string that goes over a pulley with a moment of inertia of 0.0125 kg ⋅ m2 and a radius of 15.0 cm. A mass of 710 g hangs from the other end of the string. When the tiles are released, the larger one accelerates downward while the lighter one accelerates upward. The pulley has no friction in its axle and turns without the string slipping. What is the tension in the string on the side of the 710-g tile?
Answer:
the tension in the string is 5.59 N
Explanation:
Here ,
m_1 = 0.385 Kg
m_2 = 0.710 Kg
Using second law of motion ,
a = F_net / effective mass
a = (0.710- 0.385)×9.8/(0.710 + 0.385 + 0.0125/0.15^2)
a = 1.93 m/s^2
Now , let tension be T ,
then,
mg-T=ma
0.710×g - T = 0.710×1.93
T = 5.59 N
the tension in the string is 5.59 N
A ball is thro.d hit the grouvelocity)?
Answer:
The velocity of the ball is 3.52 m/s.
Explanation:
A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.
Given that the ball was thrown vertically upward on the top of a skyscraper of height 61.9 m. So that the velocity can be determined by;
u = [tex]\sqrt{\frac{2H}{g} }[/tex]
Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/[tex]s^{2}[/tex], then;
u = [tex]\sqrt{\frac{2*61.9}{10} }[/tex]
= [tex]\sqrt{\frac{123.8}{10} }[/tex]
u = 3.5185
The velocity of the ball is 3.52 m/s.
Which item stores the most electrical potential energy within its capacitors?
A) Cell phone
B) Tablet
C) Television
D) Heating and Cooling system
Answer:
C. Television
Explanation:
Mostly in cathode ray television, a TV has many of different types of capacitors, used as connections between circuits, as timing components and as electronic filters. TV capacitors perform many functions.
capacitor acts as a reservoir for electric charge, storing and releasing electricity in precise amounts.
What is a Capacitor ?
A capacitor is a simple device consisting of a pair of metal foils separated by a thin insulator, such as plastic, used basically for storing charge
Answer:
D) Heating and Cooling system
Explanation:
just took the test and got it right :)
A rigid uniform rod of length 90.0 cm and mass 35.0 kg laying on a horizontal frictionless surface is free to rotate on that surface about an axle through its center. A small puck slides into it at an angle of 90 degrees to its surface at a distance of 30.0 cm from the pivot point at a speed of 20.0 m/s. It rebounds with a speed of 16.0 m/s along the same line. If the angular speed of the rod immediately after the collision is 1.14 rad/s, what was the mass of the puck
Answer:
m = 0.217 kg
Explanation:
We can solve this exercise using the conservation of angular momentum. For this the system is formed by the bar and the disk, so that the forces during the crash have been internal and the angular momentum is preserved
initial angular mount. Before impact
L₀ = L_bar + L_ disk
L₀ = I_bar w₀ + m r v₀
final angular momentum. Right after the crash
[tex]L_{f}[/tex] = I_bar wf = m r v_{f}
The moment of inertia of a bar that rotates at its ends is
I_bar = 1/12 M L
how the angular momentum is conserved
L₀ = L_{f}
I_barr w₀ + mr v₀ = I_barr w_{f} + m r v_{f}
I_bar (w₀- w_{f}) = m r (v₀- v_{f})) r
m = I_bar (w₀ - w_{f}) / r (v₀ -v_{f})
m = 1/12 M L (w₀ -w_{f} ) / r (v₀ -v_{f})
in the exercise it indicates that the initial speed of the disc is v₀ = 20 m / s and its final speed is v_{f} = -16 m / s, the negative sign is because the disc recoils
we calculate
m = 1/12 35 0.90 (0 + 1.14) / [0.30 (30- (-16))]
m = 0.217 kg
Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much torque must Ned produce to turn the bolt?
Answer:
[tex]T = 6.75\,N\cdot m[/tex]
Explanation:
Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:
[tex]T = F\cdot r \cdot \sin \theta[/tex]
[tex]T = F_{\bot} \cdot r[/tex]
Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:
[tex]T = (15\,N)\cdot (0.45\,m)[/tex]
[tex]T = 6.75\,N\cdot m[/tex]
Which of the choices is not a statement or direct application of the second law of thermodynamics? There are no 100% efficient heat engines. Heat energy naturally transfers from a high temperature substance to a low temperature substance. The change in internal energy of a system can be found by combining the heat energy added to a system minus the work done by the system. All natural processes tend toward states of increased entropy.
Answer:
Explanation:
Heat energy naturally transfers from a high temperature substance to a low temperature substance.
It is not a statement or direct application of the second law of thermodynamics.
The change in internal energy of a system can be found by combining the heat energy added to a system minus the work done by the system.
It is not a statement or direct application of the second law of thermodynamics. This statement is in accordance with first law of thermodynamics.
All the other two statements are in accordance with second law of thermodynamics.
The statement B is not a statement or direct application of the second law of thermodynamics.
Statements given to us:
(a.) There are no 100% efficient heat engines.
(b.) Heat energy naturally transfers from a high temperature substance to a low temperature substance.
(c.) The change in internal energy of a system can be found by combining the heat energy added to a system minus the work done by the system.
(d.) All natural processes tend toward states of increased entropy.
According to the Second Law of Thermodynamics:
heat transfer occurs spontaneously only from higher to lower temperature bodies.Entropy of the entire universe, as an isolated system, will always increase over time. The changes in the entropy in the universe can never be negative.So, according to the above points statement B is not a statement or direct application of the second law of thermodynamics.
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Which of the following statement(s) is
true about clipper circuits
Select one:
O a. It converts a.c to d.c always
O b. The output is clipped of some
portion of input signal
O c. It converts d.c to a.c
O d. None of these
Answer:
Explanation:
A rectifier is an electrical device that converts alternating current (AC) to direct current (DC), a process known as rectification. Rectifiers have many uses including as components of power supplies and as amplitude modulation detectors (envelope detectors) of radio signals. Rectifiers are most commonly made using solid state diodes but other type of components can be used when very high voltages or currents are involved. When only a single diode is used to rectify AC (by blocking the negative or positive portion of the waveform), the difference between the term diode and the term rectifier is simply one of usage. The term rectifier describes a diode that is being used to convert AC to DC. Most rectifier circuits contain a number of diodes in a specific arrangement to more efficiently convert AC power to DC power than is possible with only a single diode.
b. A force 100N makes an angle of Ø with the x axis and has a y component of 30 N. Find both the x and y component of the force and the angle Ø.
Answer:
Explanation:
The y component of the force is 100 sinØ . But given that y component is 30N
so 100 sinØ = 30
sinØ = 0.3
Ø = 17.5°.
X component of force = 100 cosØ
= 100 cos17.5
= 95.35 N .
Y component of force = 30 N .
Angle Ø = 17.5°.
What kind of lens is found in both a magnifying glass and a microscope
Answer:
convex lens
Explanation:
If you run the simulation a few times, you should see that for this particular pair of block and disc the block's position has the same numerical value as the disc's angular position, and the block's velocity has the same numerical value as the disc's angular velocity. Which of the following pairs of quantities must also have the same numerical values for the block and disc (assuming we use standard meter-kilogram-second units)? Select all that apply.
a. The work done by the force on the block and the work done by the torque on the disc.
b. The acceleration of the block and the angular acceleration of the disc.
c. The mass of the block and the mass of the disc.
d. The translational kinetic energy of the block and the rotational kinetic energy of the disc.
e. The momentum of the block and the angular momentum of the disc
Explanation:
C) is incorrect. The mass is equivalent to the moment of inertia in an angular formula.
The others appear all correct.
T * theta = F * r * theta = F * (r theta) = fx = work
This is the only one that needed explanation. The others should be obvious.
According to recent typical test data, a Ford Focus travels 0.240 mi in 19.3 s, starting from rest. The same car, when braking from 62.5 mph on dry pavement, stops in 150 ft. Assume constant acceleration in each part of its motion, but not necessarily the same acceleration when slowing down as when speeding up.(a) Find the magnitude of this car's acceleration while braking.(b) Find the magnitude of this car's acceleration while speeding up.(c) If its acceleration is constant while speeding up, how fast (in mph) will the car be traveling after 0.250 mi of acceleration?(d) How long does it take the car to stop while braking from 59.0 mph?
Answer:
Explanation:
a )
While breaking initial velocity u = 62.5 mph
= 62.5 x 1760 x 3 / (60 x 60 ) ft /s
= 91.66 ft / s
distance trvelled s = 150 ft
v² = u² - 2as
0 = 91.66² - 2 a x 150
a = - 28 ft / s²
b ) While accelerating initial velocity u = 0
distance travelled s = .24 mi
time = 19.3 s
s = ut + 1/2 at²
s is distance travelled in time t with acceleration a ,
.24 = 0 + 1/2 a x 19.3²
a = .001288 mi/s²
= 2.06 m /s²
c )
If distance travelled s = .25 mi
final velocity v = ? a = .001288 mi / s²
v² = u² + 2as
= 0 + 2 x .001288 x .25
= .000644
v = .025 mi / s
= .0025 x 60 x 60 mi / h
= 91.35 mph .
d ) initial velocity u = 59 mph
= 86.53 ft / s
final velocity = 0
acceleration = - 28 ft /s²
v = u - at
0 = 86.53 - 28 t
t = 3 sec approx .
what property of an electromagnetic wave changes when the wave is encoded with analog information?
Answer:
Amplitude and Frequency
Explanation:
Analog signals are composed of continuous waves that can have any values for frequency and amplitude. These waves are smooth and curved.
Radio transmissions are a combination of two kinds of waves: audio frequency waves that represent the sounds being transmitted and radio frequency waves that "carry" the audio information. All waves have a wavelength, an amplitude and a frequency as shown in the figure. These properties of the wave allow it to be modified to carry sound information.
The two most common types of modulation used in radio are amplitude modulation (AM) and frequency modulation (FM). Frequency modulation minimizes noise and provides greater fidelity than amplitude modulation, which is the older method of broadcasting . Both AM and FM are analog transmission systems, that is, they process sounds into continuously varying patterns of electrical signals which resemble sound waves.
who is the first person created light bulb
Answer:
Thomas Alva EdisonExplanation:
he created the bulb first. He was an American. He was an inventor and also a businessman. Moreover he invented the phonograph, and the motion picture camera, as well as improving the telegraph and telephone.
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A mass weighting 48 lbs stretches a spring 6 inches. The mass is in a medium that exerts a viscous resistance of 27 lbs when the mass has a velocity of 6 ft/sec. Suppose the object is displaced an additional 6 inches and released.
Required:
a. Find an equation for the object's displacement, u(t), in feet after t seconds.
b. What is the mass of the object?
c. What is the damping coefficient?
d. What is the spring constant?
Answer:
a)
[tex]u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)[/tex]
b)
m = 48lb
c)
b = 144.76lb
Explanation:
The general equation of a damping oscillate motion is given by:
[tex]u(t)=u_oe^{-\frac{b}{2m}t}cos(\omega t-\alpha)[/tex] (1)
uo: initial position
m: mass of the block
b: damping coefficient
w: angular frequency
α: initial phase
a. With the information given in the statement you replace the values of the parameters in (1). But first, you calculate the constant b by using the information about the viscous resistance force:
[tex]|F_{vis}|=bv\\\\b=\frac{|F_{vis}|}{v}\\\\|F_{vis}|=27lbs=27*32.17ft.lb/s^2=868.59ft.lb/s^2\\\\b=\frac{868.59}{6}lb/s=144.76lb/s[/tex]
Then, you obtain by replacing in (1):
6in = 0.499 ft
[tex]u(t)=0.499ft.e^{-\frac{144.76lb/s}{2(48lb)}t}cos(\omega t)\\\\u(t)=0.499ft.e^{-1.5t}cos(\omega t)[/tex]
b.
mass, m = 48lb
c.
b = 144.76 lb/s
A Ferris wheel has a 40-foot radius and the center of the Ferris wheel is 48 feet above the ground. The Ferris wheel rotates in the CCW direction at a constant angular speed of 2 radians per minute. Enrique boards the Ferris wheel at the 3-o'clock position and rides the Ferris wheel for many rotations. Let t represent the number of minutes since the ride started.
Write an expression (in terms of t ) to represent the number of radians Enrique has swept out from the 3-o'clock position since the ride started.
Answer:
[tex]\theta=\frac{\pi}{4}+2\frac{rad}{s}t[/tex]
Explanation:
To find the expression in terms of time t you take into account the following equation for the angular distance traveled by an object with angular acceleration w and initial angular position θo:
[tex]\theta=\theta_o+\omega t+\frac{1}{2}\alpha t^2[/tex] ( 1 )
α is the angular acceleration, but in this case you have a circular motion with constant angular speed, then α = 0 rad/s^2. θo is the initial angular position, the information of the question establishes that Enrique is at 3-o'clock. This position can be taken, in radian, as π/4 (for 12-o'clock = 0 rads).
The angular speed is:
[tex]\omega=2\frac{rad}{min}[/tex]
You replace the values of θo, α and w in the equation ( 1 ):
[tex]\theta=\frac{\pi}{4}+2\frac{rad}{s}t[/tex]
Furthermore, the arc length is:
[tex]s=r\theta=(40ft)[\frac{\pi}{4}+2\frac{rad}{s}t][/tex]
A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 15 m/s at an angle θ = 31 ° below horizontal. The stone moves without air resistance; use a Cartesian coordinate system with the origin at the stone's initial position.
Required:
With what speed, vf in meters per second, does the stone strike the ground?
Answer:
The stone strikes the ground in 14.72m/sExplanation:
The initial vertical velocity of the stone is given by:
Vyo= VSin theta
Given: V = 15m/s , theta = 31°
Vyo = 15 Sin 31
Vyo = 7.73m/s
Final vertical velocity, Vf can be determined by using kinematic equation
Vf^2 - U^2 = 2as
Vf^2 -( 7.73)^2 = 2(9.8×(-8))
Vf^2 = 59.75 + 156.8
Vf^2 = 216.6
Vf = sqrt(216.46)
Vf = 14.72m/s
Therefore,The stone strikes the ground in 14.72m/s
2. Water at the Antarctica usually exits as ice, making it very difficult to use the water or conduct experiment requiring the water to be in liquid state. A coffee addicted physicist stationed at a research base requires about 0.8 kg of ice for his coffee on the hour.
a. How much heat is required to convert 0.8 kg of ice at —35 °C into steam at 100°C?
Answer:
662480 J
Explanation:
The heat required to convert 0.8Kg of ice at -35°c to steam at 100°c is the sum of the heat required to raise the temperature of the ice from -35°c to 0°C, the latent heat of fusion of ice and the heat required to raise the temperature of the ice from 0°c to 100°c.
Latent heat of fusion for ice= 3.36× 10^5 J Kg-1
Specific heat capacity of ice= 2060 J kg−1K−1
Specific heat capacity of water= 4200 JKg-1K-1
Heat required to raise the temperature of the ice to fusion point
H= 0.8 × 2060 × [0-(-35)]
H= 57680 J
Latent heat of fusion of ice;
H= mL
H= 0.8 ×3.36× 10^5
H= 2.688×10^5 J
Heat required to raise the temperature of the water to 100°C
Since mass is conserved, the mass of ice that has melted has been turned into an equivalent mass of water.
Therefore mass of water formed= 0.8Kg
H= 0.8× 4200 × 100
H= 336000J
Therefore total heat required;
H= 57680 + 2.688×10^5 + 336000
H= 662480 J
Answer:
2468,080j
Explanation:
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An elevator with a person inside weighs a total of 24,450 Newtons. an elevator that rises 12 meters in 30 seconds. How much power is needed for the elevator trip?
Answer:
9780 W
Explanation:
Power: This can be defined as the rate at which work is done. The S.I unit of power is Watt (W).
From the question,
P = W/t....................... Equation 1
Where P = power, W = work, t = time.
But,
W = F×d.............. Equation 2
Where F = force, d = distance.
Substitute equation 2 into equation 1
P = (F×d)/t................. Equation 3
Given: F = 24450 N, d = 12 m, t = 30 s.
Substitute these vales into equation 3
P = (24450×12)/30
P = 9780 W.
Hence the power needed for the elevator trip = 9780 W
Answer:
9,780WattsExplanation:
Power is defined as the rate of workdone with respect to time.
The formula for calculating power P needed by the eleveator is expressed as;
Power = [tex]\frac{workdone}{time}[/tex]
Since Workdone = Force*distance then;
[tex]Power = \frac{force * distance}{time}[/tex]
Given the weight of elevator = 24,450Newtons
distance moved by the elevator = 12m
time taken = 12seconds.
Substituting this values in the formula given will give;
[tex]Power = \frac{24,450*12}{30} \\Power = \frac{293,400}{30} \\Power = 9,780Watts\ or\ 9.78kW[/tex]
The amount of power needed for the elevator trip is 9,780Watts
A person is trying to tighten a bolt of mass 1 kg using a wrench of mass 6 kg and length
15 cm by applying a force of 12 N as shown in the diagram below. What is the torque
applied?
Answer:
0.18 Nm
Explanation:
Note: Torque is independent of the mass of a body.
From the question,
T = F×d.......................Equation 1
Where T = Torque, F = force applied to the wrench, d = length of the wrench.
Given: F = 12 N, d = 15 cm = 0.015 m
Substitute into equation 1
T = 12(0.015)
T = 0.18 Nm.
Hence the torque applied is 0.18 Nm
An insulating plastic rod is charged by rubbing it with a wool cloth, and then brought to an initially neutral conducting metallic sphere sitting on an insulating stand. The rod touches the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod:_____
A) is repelled by the sphere.
B) is attracted to the sphere.
C) feels no force due to the sphere.
Answer:
A) is repelled by the sphere.
Explanation:
When a charged insulated rod is touched with an insulated conducting sphere , some charge on the rod gets transferred to the sphere . So they become similarly charged . We all know that there is repulsion when two similarly charged object are brought near to each other . Hence here too there will be repulsion between the rod and the sphere when the rod is brought near the sphere.
Is it true or wrong that if anyone say that, can something that is “speeding up” it means it is also have a negative acceleration? Either true or wrong justify your answer with solid reason.
Answer:
wrong
Explanation:
it depends your perspective on it
D’andre expends 120W of power in moving a couch 15 meters in 5 seconds. How much force does he exert?
Answer:
40N
Explanation:
Jamal has a fan that plugs into the wall. When Jamal plugs in the fan and turns it on, the blades spin and make the air around them move.
Jamal's fan uses _______ energy to cause motion.
A.
electrical
B.
light
C.
sound
D.
heat
Which medium (1 or 2) is more dense?
Answer:
The answer is 1
Explanation:
It's fr 1
Sinec the light rays bends away from the normal when it enters into medium 2, the denser medium is medium 1.
What is refraction?Refraction is the bending of light waves at the boundary of media of different densities.
During refraction, if light travels from less dense to a denser medium, the light rays is bent towards the normal.
However when light travels from denser to less dense medium, the light rays bends away from the normal.
Therefore, since the light rays bends away from the normal when it enters into medium 2, the denser medium is medium 1.
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A team of landscapers pull an unplanted tree across the lawn. What forces are used?
Answer:
Explanation:
When an unplanted tree is pulled across the lawn then a variety of forces will be acting on the tree i.e.
1.There will be gravity force
2.Friction force to oppose the motion
3.Applied force which is pulling the tree
4. Normal force in response to the gravity force.