Which is true for the motion of the car during its journey along OAB?
12)
A) The velocity of the car remains constant throughout the journey.
B) The change in speed alone causes the velocity of the car to vary.
C) The change in direction alone causes the velocity of the car to vary.
D) The velocity of the car changes due to the change in speed and dir
Answer:
D
Explanation:
A is wrong as the direction of the car changes, implying velocity is changing and not constant.
B and C are wrong as both the change in speed and direction contribute to the change in velocity
anything that has mass and occupies space is called
Answer:
Matter
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The engine of a 2400 kg car applies a force of 740 N to make the car accelerate. Calculate the
acceleration of the car.
Answer:
0.31 m/s²Explanation:
The acceleration of an object given only it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass in kg
From the question
m = 2400 kg
f = 740 N
We have
[tex]a = \frac{740}{2400} = \frac{74}{240} \\ = 0.308333...[/tex]
We have the final answer as
0.31 m/s²Hope this helps you
A point charge of 5. 0 Ă— 10â€""7 C moves to the right at 2. 6 Ă— 105 m/s in a magnetic field that is directed into the screen and has a field strength of 1. 8 Ă— 10â€""2 T. What is the magnitude of the magnetic force acting on the charge? 0 N 2. 3 Ă— 10â€""3 N 23 N 2. 3 Ă— 1011 N.
The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.
Given to us,
the charge [tex]q[/tex] = [tex]5\times 10^{-7}[/tex] C,
the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex] m/sec,
the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,
angle between the direction of v and B [tex]\theta[/tex] = 0,
Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by
[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]
Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N
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what does and does not impact magnetic force?
Answer:
Image result for what does and does not impact magnetic force?
The magnitude of the magnetic force between them depends on how much charge is in how much motion in each of the two objects and how far apart they are. The direction of the force depends on the relative directions of motion of the charge in each case
Explanation:
The factors that affect magnetic force are magnitude of the charge, speed, magnetic field and inclination of the field.
Magnetic forceThe magnetic force on a charged particle moving in a magnetic field is determined using the following formula;
F = qvBsin(θ)
where;
q is the magnitude of the chargev is the speed of the chargeB is the magnetic fieldθ is the angle between the field and the speed of the chargeThus, the factors that affect magnetic force are magnitude of the charge, speed, magnetic field and inclination of the field.
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How would you describe the motion of a transverse wave
____________ is a medium-sized flat-topped hill with cliff-face sides that is taller than it is wide.
Answer:
mesa
Explanation:

A mesa is a flat-topped mountain or hill. It is a wide, flat, elevated landform with steep sides. ... Spanish explorers of the American southwest, where many mesas are found, used the word because the tops of mesas look like the tops of tables.
A 50 kg driver of a car is traveling at 35 m/s when she hits a large deer. She strikes the air bag/seatbelt combination that brings her body to a stop in 1.1s. What is the impulse imparted to the driver of the car?
Answer:1590 N
Explanation:
Impulse = change in momentum/time
change in momentum = 0 - 50 x 35 = -1750
-1750/1.1 = 1590 (3s.f.) N
Which statement describes the magnetic field inside a bar magnet? It points from north to south. It points from south to north. It forms loops inside the magnet. There is no field within the magnet.
Inside the bar magnet, the magnetic field points from north to south. Statement A is correct.
Magnetic Field:
It is defined as a vector field or the influence of the magnet on the electric current, charges and ferromagnetic substance.
The strength of magnetic field is depends up on the numbers of magnetic field lines per unit area.
Magnetic field lines emerge from the North pole and end in the South pole of a bar magnet. Inside the magnet are also present inside the bar magnet and never intersect at any point.Therefore, inside the bar magnet, the magnetic field points from north to south.
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Answer:b
Explanation:
For a uniformly accelerated motion the graph of displacement versus time would be
Explanation:
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have a nice day
Samantha's teacher asks her to describe motion in one dimension. This type of motion is always
A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.
Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.
In Science, the motion of an object or physical body is described in terms of the following parameters:
SpeedForceAccelerationDistanceTimeFurthermore, there are three (3) forms of motion based on dimension and these include:
1. Motion in one dimension
2. Motion in two dimension
3. Motion in three dimension
A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.
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The following data were collected during a short race between two friends. Velocity (m/s) 0 0.5 1 1.5 2 2 4 6 2 0 Time (s) 0 2 4 6 8 10 12 14 16 18 a) Describe the different sections of the graph. b) Determine the acceleration over the first eight seconds. c) Determine the maximum acceleration. d) Using the graph calculate the displacement: i) over the first eight seconds ii) the total race. e) Find the maximum velocity reached by the runner.
The characteristics of the kinematics allow to find the results for the questions about the movement of the body are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
Kinematics studies the movement of bodies by finding relationships between the position, speed and acceleration of bodies.
v = v₀ + a t
y = v₀ t + ½ a t²
where v and v₀ is the current and initial velocity, respectively, a is the acceleration and t is time.
In many circumstances graphs are made for their analysis, in a graph of speed versus time when we have a horizontal line the speed is constant, the acceleration is zero and in the case of a slope there is an acceleration, we have two cases:
Positive slope the body is accelerating and the speed is increasing. Negative slope the body is stopping, the speed decreases.
Let's answer the different questions about the system.
a) in the attached we have a graph of the velocity versus time, each section corresponds to a change in the slope of the graph, we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.
b) The acceleration is the first 8 s
v = v₀ + a t
[tex]a = \frac{v-v_o}{\Delta t}[/tex]
[tex]a = \frac{2-0}{8-0}[/tex]
a = 0.25 m / s²
c) The maximum acceleration is when the slope is maximum.
[tex]a = \frac{6-2}{ 14-10}[/tex]
a = 1 m / s²
Therefore the acceleration is maximum in the section between 10 and 14 s
d) The total displacement is the sum of the displacements of each section.
[tex]d_{total } = d_1 +d_2 + d_3 +d_4[/tex]
We look for every displacement.
d₁ = v₀ + ½ a₁ Δt²
d₁ = 0 + ½ 0.25 8²
d₁ = 8 m
In the second section the velocity is constant
d₂ = v₂ Δt₂
d₂ = 2 (10-8)
d₂ = 4 m
The third section.
d₃ = v₀ + ½ a t²
d₃ = 2 + ½ 1 (14-10) ²
d₃ = 10 m
The distance of the fourth section.
we look for acceleration
a₄ = [tex]\frac{v-v_o}{\Delta t}[/tex]
a₄ = [tex]\frac{0-6}{18-14}[/tex]
a₄ = -1.5 m / s²
d₄ = 6 + ½ (-1.5) (1814) ²
d₄ = -6 m
The total displacement is;
[tex]d_{total}[/tex] = 8 + 4 + 10 -6
[tex]d_{total}[/tex] = 16 m
e) The maximum speed is the highest point in the graph of speed versus time that in the attachment we can see corresponds to
v = 6 m / s
In conclusion using the characteristics of kinematics we can find the results for the questions about the motion of bodies are:
a) we have four sections;
0 to 8 s The body is accelerating. 8 to 10 s The body goes at a constant speed, the acceleration is zero. 10 to 14 Body accelerating. 14 to 18 Body slowing down.b) The acceleration is the first 8 s is: a = 0.25 m / s²
c) The maximum acceleration is: a = 1 m / s²
d) The displacement is: i) d₁ = 8m, ii) [tex]d_{total}[/tex]= 16 m
e) maximum speed is: v = 6 m / s
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given how the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is
Answer:
I think you ask for another way of writing the joule (J). It can be expressed as the product between a force applied to a body and the deployment of the body (not necessarily caused by that force applied), so N*m (newton * meter).
The quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).
What is unit of physical quantities?The quantity with a constant magnitude that is used to measure the magnitudes of other quantities of the same type is referred to as a unit in physics.
A unit shouldn't alter as time or environmental factors like pressure and temperature change.It ought to be precisely defined.It need to be readily available and repeatable.Unit of work is that of energy, that is, Joule (J).
Again, work = force × displacement
Unit of work = Unit of force × Unit of displacement = Newton . meter (N.m).
Hence, the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).
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A car has a kinetic energy of 4.33x10^5 J when traveling a speed of 25 m/s. What is the mass ?
A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
momentum of the pieces after the explosion compare to the total momentum of the
cannonball just before the explosion?
I. They are the same
II. The momentum of the fragments is less than the momentum of the cannonball
III. The momentum of the fragments is more than the momentum of the cannonball
Hi there!
I. They are the same.
Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.
I need help to build a mouse trap race car for my science class and this is my final and these are the materials I have.
So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.
Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.
Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.
Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).
If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.
Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.
Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.
Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]
Electrical tape
Rubber bands
Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)
two forces act concurrently on an object on a horizontal frictionless surface. their resultatn force has the largest magnitude when the angle between the forces is
Answer:
54
Explanation:4
4
4
Answer:
30d
Explanation:
30d
A passenger of mass 90kg is involved in a minor car crash. The car approaches a solid barrier at 32m/s. It crashes into the barrer and stops in 0.2s. Determine the impulse that must be applied to the car to bring it to rest
Answer:
I hope this helps:)
Explanation:
good luck:)
A heavy crate is pushed across a floor at a constant velocity. Friction is present between the crate and floor. During this motion, the force of friction is _?_ the force pushing the crate forward.
Question 3 options:
less than
greater than
equal to
Answer:
less than.
Explanation: because Friction is the resistance to motion of one object moving relative to another. which means it cant be greater because how would it be greater if its pushing forward when friction is the resistance.
THANKS FOR THE POINTS :D
Can someone help me with this physics question? I don't know which answer is correct.
3. Distance is a quantity that is always a vector.
B.
how to find change in kinetic energy with velocity
Answer:
We know that ΔK = Kf - Ki = 1/2 m Vf^2 - 1/2 m Vi^2 = 1/2m(Vf^2-Vi^2) = 1/2 m ΔV^2.
The mass remains the same, just calculate the difference of squared velocities and multiply it by half of the mass.
Can someone please give me the (Answers) to this? ... please ...
Explanation:
1. By Newton's 3rd Law, both forces are equal and opposite. Hence both forces are of the same magnitude.
2. The reaction force is the force of arrow on bowstring.
3. Forward force of fish on water and vice versa?
4. The mass of the person is very small as compared to mass of earth. Hence the force exerted is very small amd hence the recoil is not noticed.
5. Reaction force is the force of ball against the bat. By Newton's Third Law, they form an action reaction pair. Hence, they are equal in magnitude and opposite in direction.
6. The reaction force will also decreases as both forces are equal in magnitude.
7 im nt sure sorry Ahahah
what equation do you use to calculate force from work to distance
Answer:
Work can be calculated with this equation: Work = Force x Distance. The SI unit for work is the Newton meter (N m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
If a car can go from 0 to 60 km/h in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50 km/h?
Answer:
This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h
24.29m/s or 87.4km/h
Explanation:
Let's find the acceleration of the car:
let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s
a = (vf-vi)/Δt
a = (16.67m/s-0)/8.0
a = 2.08m/s^2
Now we can use this acceleration to find vf in the second part:
50km/h is 13.89m/s
a = (vf-vi)Δt
vf = aΔt + vi
vf = 2.08m/s^2*5.0+13.89m/s
vf = 24.29m/s (87.4km/h)
in any chemical reaction or physical change the mass of the product is ___ The mass of the reactant
a. The relationship cannot be determined by the amount of information given
b. equal to or the same
c. twice is greater than
d. twice as less than
Answer: b. equal to or the same
In Law of Conservation of mass, the mass of the product equals the mass of the reactant. A reactant is the chemical reaction of two or more elements to make a new substance, and a product is the substance that is formed as the result of a chemical reaction.
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what is the potential energy of a 2kg plant that is on a windowsill 1.3 m high?
what is the kinetic energy of a 7.26 kg bowling ball that is rolling at a speed of 2 m/s
an apple as 6 J of energy. the apple sits on a counter 3 m high. what is the mass of the apple/
Answer:
25.48
Explanation:
If the action force is the swimmer pushing water in the leftward direction, what is the reaction force?
PLEASE ANSWER
CORRECTLY PLS
Answer:
The reaction force is the water pushing the swimmer in the rightward direction.
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What does the risk of biological harm from radiation depend on?
Answer:
The effects of radiation depend on the type, energy, and location of the radiation source, and the length of exposure.
A student claims that the total momentum of a system of objects is conserved when there is no net force on the system.
To test the claim, the student uses a cue ball (white) and rolls it into an eight ball (black). When the balls collide, the cue
ball comes to a complete stop and the eight ball begins to move. The mass of the cue ball is 0.17 kg, and the mass of
the eight ball is 0.16 kg. A radar is used to measure the speed of the cue ball immediately before it comes in contact
with the eight ball, and another radar is used to measure the speed of the eight-ball immediately after the point of
contact. The cue ball approaches the eight ball at a speed of 4.00 m/s. After contact, the eight ball moves away from the
cue ball at a speed of 4.25 m/s. The scenario is shown in the picture.
The total momentum of the system is conserved and the momentum did not change.
The given parameters:
Mass of the white ball, m₁ = 0.17 kgMass of the black ball, m₂ = 0.16 kgInitial velocity of the white ball, u₁ = 4 m/sFinal velocity of the black ball, v₂ = 4.25 m/sThe initial momentum of the system is calculated as follows;
[tex]P_i = m_1 u_1 + m_2 u_2\\\\P_i = 0.17 \times 4 \ + \ 0.16(0)\\\\P_i = 0.68 \ kg m/s[/tex]
The final momentum of the system is calculated as follows;
[tex]P_f = m_1 v_1 + m_2 v_2 \\\\P_f = 0.17 (0) \ + 0.16(4.25)\\\\P_f = 0.68 \ kg m/s[/tex]
Thus, the total momentum of the system is conserved and the momentum did not change.
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Draw the following vector: 350 N, 30° south of east [1 cm = 50 N]
The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
The given parameters:
Magnitude of the vector = 350 NPosition of the vector = 30⁰ South eastThe vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.
The length of the arrow represents the magnitude of the vector which is 350 N. The direction of the arrow indicated by the arrow head represents the position of the vector.The position of the vector is 30 degrees South of East.Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
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