How do you think rocks form?

Answer:

See explanation.

Explanation:

Hello,

In this case, the chemical structure of the given compound, which is an alcohol, based on the suffix "ol", the bromo radical at the first carbon and the isobutyl radical at the 3rd carbon is shown on the attached picture wherein the hydroxyl is drawn at the 4th carbon. Remember that IUPAC rules for nomenclature help us to easily name or draw organic molecules by indicating the radicals and their positions and the main chain at the en of the name.

Best regards.

The diagrammatic structure for the compound 1-Bromo-3-isobutyl-4-heptanol  can be seen in the image below.

When naming an organic compound, we will first consider the longest chain of the carbon atom and attach the substituents in such a way that we will have the lowest number when adding them.

In the compound 1-Bromo-3-isobutyl-4-heptanol, we first draw the seven carbon chain with -OH substituent on the fourth carbon. This was followed by adding the substituent of isobutyl to carbon atom 3 and bromine to carbon atom 1.

Learn more about naming organic compounds here:

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Answer:

The reduction potential of   [tex]Cu^2+/Cu[/tex] is  [tex]E_c^o = 0.34 \ V[/tex]

Explanation:

From the question we are told that

      The potential of the cell is  [tex]M_{cell} = E^o _{cell} = 1.100 \ V[/tex]

       The range is  [tex]R = 0.005 \ V[/tex]

        The temperature is  [tex]T = 25 ^oC[/tex]

Note the reason why Zn is oxized and  Cu is reduced is because Zn is higher than Cu on the electrochemical series

    The reaction at the anode is  

              [tex]Zn ^{2-} _{(aq)} + 2e \to Zn_{(s)} \ \ \ \ \ E^o_a = -0.76 \ V[/tex]    

The [tex]E^o\ is \ the \ standard\ oxidation \ potential\ value\ for\ Zn\ oxidation[/tex]

    The reaction at the anode is  

             [tex]Cu^{2+} _{(aq)} + 2e^{-} \to Cu_{(s)} \ \ \ \ \ \ \ \ E^o_c = c \ V[/tex]  

Now

          [tex]E^o _{cell} = E_c^o - E_a^o[/tex]  

substituting values

           [tex]1.100 = E_c^o -(- 0.76)[/tex]

           [tex]E_c^o = 1.100 - 0.76[/tex]

           [tex]E_c^o = 0.34 \ V[/tex]

Hence the reduction potential of   [tex]Cu^2+/Cu[/tex] is  [tex]E_c^o = 0.34 \ V[/tex]

Answer:

a. 1.23 V

b. No maximum

Explanation:

Required:

a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?

b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

If E°cell must be at least 1.10 V (E°cell > 1.10 V),

E°red, cat - E°red, an > 1.10 V

E°red, cat - 0.13V > 1.10 V

E°red, cat > 1.23 V

The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.

Answer:

Now length of body diagonal of this cube = √3×√2×r =2.45r

Explanation:

a) length of body diagonal of this cube = √3×√2×r = 2.45 r

it can solved as following

length of body diagonal = √3a   (where a is edge length of cube)

length of face diagonal = √2a

But length of face diagonal = 2r

Therefore a = 2r /√2  = √2×r

Now length of body diagonal of this cube = √3×√2×r

Answer:

The molecular formula for A is C2H4(NO3)2

The molecular formula for B is C2H6O2

Explanation:

I linked an image that will show the work.

Answer:

Earth's crust

Explanation:

The lithosphere is the rigid outer part of the earth, consisting of the crust and upper mantle. It is the, rigid, rocky outer layer of the Earth, consisting of the crust and the solid outermost layer of the upper mantle. It extends to a depth of about 60 miles (100 km). It is the outer part of the solid earth composed of rock essentially like that exposed at the surface, consisting of the crust and outermost layer of the mantle.

We can also look at it as the solid part of the earth on which plants grow and animals survive. It contains all the rock formations that bear the various minerals found on earth.

The lithosphere is composed of both the crust and the portion of the upper mantle that behaves as a brittle, rigid solid.

Answer:

nuclear

Explanation:

This is because when the protons and neutrons split the energy being released is heat, also known as nuclear fission.

Answer:

The answer is Nuclear

Answer:

D & E

Explanation:

I think this is dealing with latent heat and D & E would be the range where you will find solid and liquid phases in equilibrium, cuz it starts as gas at from A to B, B to C is gas and liquid equilibrium, C to D is liquid, D to E solid and liquid, and then E to F is solid.

Answer:

2.42x10^5 L

Explanation:

10.0ft x 11.0 ft x 8.00 ft = 880. ft^3 (1 cubic foot = 28316.8 cubic cm)

880. ft^3 * (28316.8 cubic cm/ 1 cubic foot) = 24,918,784 cm^3

(1L=103 cm^3)

24,918,784 cm^3 (1L/103 cm^3) = 2.42x10^5 L

[tex]2.42*10^5[/tex]  liters of air are in a room.

It helps to show another person the exact amount you have. Assist in solving a mathematical problem, especially in chemistry, where you can follow the units to get to the answer. Show which measurement system the person is using.

1 in. = 2.54 cm

1 L = 10³ cm³

Given: 10.0 ft × 11.0 ft 8.00 ft ceiling

Now, converting into given quantities:

[tex]10.0ft * 11.0 ft * 8.00 ft = 880. ft^3 ( = 28316.8 \text{ cubic cm})\\\\880. ft^3 * (\frac{28316.8 \text{ cubic cm}} {\text{1 cubic foot}} }) = 24,918,784 cm^3\\\\24,918,784 cm^3 (\frac{1L}{10^3 cm^3})= 2.42*10^5 L[/tex]

→  Thus,[tex]2.42*10^5[/tex] liters of air are in a room that measures 10.0 ft × 11.0 ft and has an 8.00 ft ceiling.

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Answer:

there are approximately 52 moles in 15 grams of lithium.

Answer:

1.32 mole

Explanation:

The following data were obtained from the question:

Volume of solution = 2.2L

Molarity of solution = 0.60M

Mole of Li3PO4 =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:

Molarity = mole /Volume

With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:

Molarity =mole /Volume

0.6 = mole of Li3PO4 /2.2

Cross multiply

Mole of Li3PO4 = 0.6 x 2.2

Mole of Li3PO4 = 1.32 mole

Therefore, 1.32 mole of Li3PO4 is contained in the solution.

Answer:

  0.690 g/mL

Explanation:

Density is the ratio of mass to volume:

  gasoline mass = (flask+gas mass) - (flask mass) = 145.028 g -110.525 g

  gasoline mass = 34.503 g

Density = (gas mass)/(gas volume) = (34.503 g)/(50.0 mL)

Density = 0.690 g/mL

_____

The least-precise number in this calculation is the sample volume, which has 3 significant figures. Thus, the answer is good only to 3 significant figures.

Answer:

Concentration of hydronium ion, H3O+ is 1x10^-2 M

Explanation:

The following data were obtained from the question:

Concentration of Hydroxide ion, [OH-] = 1.0x10^-12 M

Concentration of hydronium ion, [H3O+] =?

Next, we shall determine the pOH of the solution. This is illustrated below below:

pOH = - Log [OH-]

pOH = - Log 1.0x10^-12

pOH = 12

Next, we shall determine the pH of the solution.

pH + pOH = 14

pOH = 12

pH + 12 = 14

Collect like terms

pH = 14 - 12

pH = 2

Finally, we shall determine the Concentration of hydronium ion, [H3O+] as follow:

pH = - log [H3O+]

pH = 2

2 = - log [H3O+]

- 2 = log [H3O+]

[H3O+] = Antilog (-2)

[H3O+] = 0.01M = 1x10^-2 M

Answer:

1.heat a pan of water with just a little bit of water,have a boil

2.chosse ure salt

3.stir in has much salt has u can than take the pan off the heat

4.pour the mix into a glass jar

5.tie a string to an objeet that can lay accross the top and put just the string in ure mix

Explanation oh and look at it everyday       hope that helps

Answer:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Explanation:

H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)

A careful observation of the equation above, shows that the equation is already balanced.

To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Answer:

B. She can ask people about their backgrounds .

Explanation:

A, C, and D, aren't good answers.

(A. She can tell people what she knows about their backgrounds.) Telling is far different from listening.

(C. She can say she already knows everything about different backgrounds.) Saying you know everything about a background wouldn't be a good answer.

(D. She can write songs about people's backgrounds.) This could be an answer but I believe that B. is the answer.

Hope this helped :)

Answer:  A degenerate pressure will generate a large force to repel further  compression.

Explanation: In the production of new stars from the core of old dying white dwarf stars, the inner parts of the star will experience contraction with the release of  heat , as they contract, their atoms will be  squeezed such that their electrons start to overlap, and because of the Pauli's exclusive principle which states that no two electrons can occupy same space, the electrons will begin to repel each other and an opposing pressure called degenerate pressure will create a force so that the electrons  cannot continually be crushed or overlap. With the limit of contraction, the outer parts of the star will expand and be repelled releasing the old stars called nebula  and creating space for the inner new stars to form.

Explanation:

Na

Na (gas) -> Na+ (g) + e-

Answer:

Rb

Explanation:

Answer:

B

Explanation:

Answer:

Because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface

Explanation:

Hello,

In this case, meteorology is the branch of science studying the atmosphere in its weather processes and forecasting and it had a late development because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface. We cannot forget that even nowadays, it is very difficult to predict upcoming weathers with the 100 % assurance and with many days in advance.

Best regards.

Meteorology is developed lately as compared to other branches of science due to far away from the reach of humans.

Meteorology is a late developer compared to other branches of science because the measuring the climatic conditions in the atmosphere is difficult and even impossible without the presence of advance technologies.

To find out the weather as well as climatic conditions can't be measured due to it is not reachable to the human like other materials present on the earth surface so we can conclude that meteorology is developed lately as compared to other branches of science due to far away from the reach of humans.

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Answer:

I sent u on insta

Explanation:

Found it

Answer:

hi idk the answer

Explanation:

Answer:

1. Molality.

2. Concentration.

3. Percent by mass.

4.  Mole fraction.

Explanation:

Molarity is the measurement by which the number of moles is measured by a solute. The solution here is one liter respectively.

Concentration is the product which is emerged when the amount of the solute is divided by the amount o the solvent or solution.

Mole fraction refers to the number of component moles divided by the number of the solution moles.

Answer:

Rb

Explanation:

Ionization energy is defined required energy to eliminate or remove an electron from an ion or atom.

From the given elements Rb or Rubidium has the lowest ionization energy as it has lowest shielding effect, so it easy to remove electron from it's shell.

The ionization energy generally decreases from top to bottom in groups due to lower shielding effect and outer electrons are loosely packed so easy to remove and increases from left to right across a period because of valence shell stability.

Rubidium has atomic number 37 and lies below than other given elements and also placed in the left side in the periodic table.

Hence, the correct option is Rb

Answer:

Order is MgBr₂ > KBr > (CH₃COOH) > (C₆H₁₂O₆)

Explanation:

Find the given attachment

Answer:

[tex]M_{A}[/tex] : [tex]M_{B}[/tex]  = 4 : 1

Explanation:

Given that:

Volume of a cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h

For cylinder A, [tex]l_{A}[/tex] = [tex]h_{A}[/tex] = [tex]\frac{1}{4} l_{B}[/tex] and [tex]r_{A}[/tex] = 4[tex]r_{B}[/tex].

Volume of cylinder A = [tex]\pi[/tex][tex](4r_{B}) ^{2}[/tex] × [tex]\frac{1}{4} l_{B}[/tex]

                                   = 4[tex]\pi[/tex][tex]r_{B} ^{2}[/tex] [tex]l_{B}[/tex]

Volume of cylinder B =  [tex]\pi[/tex][tex](r_{B}) ^{2}[/tex] [tex]l_{B}[/tex]

                                  =  [tex]\pi[/tex][tex]r_{B} ^{2}[/tex][tex]l_{B}[/tex]

To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).

i.e    ρ = [tex]\frac{M}{V}[/tex]

Thus, since the cylinders are made from the same material, they have the same density  (ρ). So that;

density of A = density of B

density of A = [tex]\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }[/tex]

density of B = [tex]\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }[/tex]

⇒            [tex]\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }[/tex]  =  [tex]\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }[/tex]

The ratio of mass of cylinder A to that of B is given as;

                       [tex]\frac{M_{A} }{M_{B} }[/tex]  =  [tex]\frac{4\pi r_{B} ^{2} l_{B} }{\pi r_{B} ^{2} l_{B} }[/tex]

⇒                        [tex]\frac{M_{A} }{M_{B} }[/tex] = [tex]\frac{4}{1}[/tex]

Therefore, [tex]M_{A}[/tex] : [tex]M_{B}[/tex]  = 4 : 1

Answer:

4.

Explanation:

Hello,

In this case, since we are talking about the same material, their densities are the same:

[tex]\rho _A=\rho _B[/tex]

And each density is defined by:

[tex]\rho _A=\frac{m_A}{V_A} \\\\\rho _B=\frac{m_B}{V_B}[/tex]

Thus, we also define the volume of a cylinder:

[tex]V_{cylinder}=\pi r^2h[/tex]

Therefore, we obtain:

[tex]\rho _A=\frac{m_A}{\pi r_A^2h_A}[/tex]

[tex]\rho _B=\frac{m_B}{ \pi r_B^2h_B}[/tex]

Now, the given information regarding the the length and the radius is written mathematically:

[tex]h_A=\frac{1}{4} h_B\\\\r_A=4 r_B[/tex]

So we introduce such additional equations in:

[tex]\frac{m_A}{\pi r_A^2h_A}=\frac{m_B}{\pi r_B^2h_B}\\\\\frac{m_A}{\pi (4r_B)^2(\frac{1}{4}h_B)}=\frac{m_B}{\pi r_B^2h_B}\\\\\frac{m_A}{m_B} =\frac{\pi (4r_B)^2(\frac{1}{4}h_B)}{\pi r_B^2h_B}[/tex]

So we simplify for the radius and lengths:

[tex]\frac{m_A}{m_B} =\frac{\pi (4r_B)^2(\frac{1}{4}h_B)}{\pi r_B^2h_B}\\\\\frac{m_A}{m_B} =16 *\frac{1}{4}\\ \\\frac{m_A}{m_B} =4[/tex]

So the ratio of the mass of cylinder A to the mass of cylinder B is 4.

Best regards.

Answer:

The answer to your question is given below

Explanation:

1. 2,4-dimethylhexane can be drawn as follow:

a. The parent name: Hexane i.e it contains 6 carbon atom.

b. The substitute group attached: Methyl i.e CH3 and it is at carbon 2 and 4.

c. Draw 6 carbon atom in a straight line and put CH3 at carbon 2 and 4. As shown in attach photo.

2. 4-methyl-2-pentene can be drawn as follow:

a. The parent name: pentene i.e it contains 5 carbon atom and the double bond is at carbon 2.

b. The substitute group attached: Methyl i.e CH3 and it is at carbon 4.

c. Draw 5 carbon atom in a straight line and put a double bond at carbon 2 and CH3 at carbon 4 as shown in attach photo.

3. 4-chloro-7-methyl-2-nonyne can be drawn as follow:

a. The parent name: nonyne i.e it contains 9 carbon atom and the triple bond is at carbon 2.

b. The substitute group attached:

i. Chlorine (Chloro) i.e Cl and it is at carbon 4.

ii. Methyl i.e CH3 and it is at carbon 7.

c. Draw 9 carbon atom in a straight line and put a triple bond at carbon 2, Cl at carbon 4 and CH3 at carbon and 7 as shown in attach photo.

Answer:

Double displacement chemical reaction.

Explanation:

Hello,

In this case, for the given reaction we firstly balance it:

[tex]LiBr_2 +K_2CO3 \rightarrow LiCO3 +2KBr[/tex]

Then, since the lithium and potassium cations are being exchanged to each other from bromide and carbonate, we are talking about a double displacement chemical reaction.

Best regards.

Answer:

thermal energy

Explanation:

Answer:

B- Thermal Energy

Explanation:

Thermal energy is produced due to all of the movement of particles inside the material.