how do i graph x+4y=8​

Answers

Answer 1

Answer:

x = 8  y = 2

(8,2)

Step-by-step explanation:

You have to find the value of both x and y

x + 4y = 8

to find x you have to cancel out y so,

x + 4(0) = 8

x = 8

to find y you have to cancel out x

0 + 4y = 8

4y = 8

divide both sides by 4

y = 2

Hope this Helps!!!

Answer 2

By changing the equation to slope intercept form we draw the graph and graph is given in attachment.

What is Graph?

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

Let us convert the equation of line  x+4y=8​ to slope intercept form.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

x+4y=8

4y=8-x

Divide both sides by 4

y=-x+2

Now let us find few point to draw the graph.

If x=0

y=2

If x=1

y=1

If x=2

then y=0

if x=3

then y=-1

Now plot (0, 2), (1, 1) and (3, -1) and draw the graph

Hence, by plotting the points (0, 2), (1, 1) and (3, -1) we draw the graph and the graph is in attachment.

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How Do I Graph X+4y=8

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4mn+2m+2n+1

Step-by-step explanation:

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Answer: 4mn+2n+1

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Step-by-step explanation:

Shape p is translated to shape Q using vector (a b).
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Answer:

the answer is:

a=-2

b=-4

Step-by-step explanation:

Shape P is translated to shape Q using vector [tex]\left[\begin{array}{ccc}2\\4\end{array}\right][/tex].

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"A translation in math moves a shape left or right and/or up or down. The translated shapes look exactly the same size as the original shape, and hence the shapes are congruent to each other."

Given, the shape P is mentioned on the graph.

Now, shape P is translated to shape Q.

Therefore, in order to reach Q from P, the shape needs to shift to the left 2.

After that the shape needs to shift downwards 4 places.

Therefore, the required vector is [tex]\left[\begin{array}{ccc}2\\4\end{array}\right][/tex].

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The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the past 20 months. The phone company decides to use the upper fence as the cutoff point for the number of minutes at which the customer should be contacted. what is the cutoff point?321 474 461 548406 464 517 311534 425 377 505322 435 410 513499 354 307 363The cutoff point is ____minutes( round to the nearest minute)

Answers

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

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[tex]\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5[/tex]  position orders

[tex]10^{th} \ and \ 11^{th}[/tex] place an average of observations so, the

[tex]Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430[/tex]

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

[tex]Q_1[/tex] often falls throughout the ordered BELOW average is [tex]= \frac{(n+1)}{2}[/tex] place.

[tex]\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}[/tex]ordered position

Average [tex]5^{th} \ and \ 6^{th}[/tex]  location findings

[tex]Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5[/tex]

In  [tex]= \frac{(n+1)}{2}[/tex] the ordered place, Q3 always falls ABOVE the median.

[tex]\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}[/tex] ordered At median ABOVE 

Consequently [tex]Q_3[/tex] falls between [tex]5^{th} \ and \ 6^{th}[/tex] ABOVE the median position

[tex]15^{th}\ and \ 16^{th}[/tex]place average of observations

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[tex]\to IQR = Q_3 - Q_1= 502-358.5= 143.5[/tex]  

[tex]\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25[/tex]

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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542.5 x 3 (the amount of weeks in a month) = $1627.5

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Answer:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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What is trigonometry?

Trigonometry is mainly concerned with specific functions of angles and their application to calculations. Trigonometry deals with the study of the relationship between the sides of a triangle (right-angled triangle) and its angles.

For the given situation,

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Hence we can conclude that the possible trigonometric function is option (C) [tex]sec \theta = \frac{3}{\sqrt{5} }[/tex] and [tex]tan \theta = \frac{-2}{\sqrt{5} }[/tex] is the correct answer.

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Answers

Answer:

360°

Step-by-step explanation:

Based on what I know that the total of degrees has to be 360°. So, two sides of the rhombus have to have two acute angles and two obtuse angles. So, the  Image shows that the 63° is an acute angle. So, multiply 63 by 2 which is 126. Then subtract 126 from 360 which is 234. Then, divide 234 by 2 which is 117. Lastly, add 63 with 63 and 117 with 117 which is 360.

Hopefully, you understand.

y= 1/2x+ 2 to make the x the subject.

Answers

Answer:

[tex]x=2y-4[/tex]

Step-by-step explanation:

[tex]y=\frac{1}{2} x+2[/tex]

"To make x the subject" means to have the equation with all the terms in x on one side. As of now, y is the subject of the equation.

You start by subtracting 2 from both sides, you should get the following.

[tex]y-2=\frac{1}{2} x[/tex]

Then you multiply by 2 from both sides, you should end up with the following.

[tex]2(y-2)=x[/tex]

Therefore, you get the following.

[tex]x=2(y-2)[/tex]

Finally, you distribute and get the answer.

[tex]x=2y-4[/tex]

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