How could weathering by release of pressure affect the amount of weathering by freezing and thawing?

Explanation:

Na

Na (gas) -> Na+ (g) + e-

Answer:

Rb

Explanation:

Answer:

there are approximately 52 moles in 15 grams of lithium.

Answer:

Because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface

Explanation:

Hello,

In this case, meteorology is the branch of science studying the atmosphere in its weather processes and forecasting and it had a late development because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface. We cannot forget that even nowadays, it is very difficult to predict upcoming weathers with the 100 % assurance and with many days in advance.

Best regards.

Meteorology is developed lately as compared to other branches of science due to far away from the reach of humans.

Meteorology is a late developer compared to other branches of science because the measuring the climatic conditions in the atmosphere is difficult and even impossible without the presence of advance technologies.

To find out the weather as well as climatic conditions can't be measured due to it is not reachable to the human like other materials present on the earth surface so we can conclude that meteorology is developed lately as compared to other branches of science due to far away from the reach of humans.

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Answer:

Explanation:

HF acid

F ⁻ conjugate base , name is fluoride ion .

H₂O acid

OH⁻ conjugate base , name hydroxide ion

H₂CO₃ acid ,

HCO₃⁻ conjugate base , name bicarbonate ion .

HSO₄⁻ acid bisulphate ion

SO₄⁻² ion , conjugate base ,name sulphate ion .

Answer:

D & E

Explanation:

I think this is dealing with latent heat and D & E would be the range where you will find solid and liquid phases in equilibrium, cuz it starts as gas at from A to B, B to C is gas and liquid equilibrium, C to D is liquid, D to E solid and liquid, and then E to F is solid.

Answer:

1.32 mole

Explanation:

The following data were obtained from the question:

Volume of solution = 2.2L

Molarity of solution = 0.60M

Mole of Li3PO4 =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:

Molarity = mole /Volume

With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:

Molarity =mole /Volume

0.6 = mole of Li3PO4 /2.2

Cross multiply

Mole of Li3PO4 = 0.6 x 2.2

Mole of Li3PO4 = 1.32 mole

Therefore, 1.32 mole of Li3PO4 is contained in the solution.

Answer:

I think the insect would be the one in the second photo reading from left to right

Explanation:

the other insects:

the first of the first photo is a change of what would be the external surface of the insect, it is not the insect itself.

In the third photo, the insect has short legs with little grip, which indicates that it does not climb large areas on top, and finally, the 4 image is of an insect that lives in desert areas and is poorly coordinated in areas of high heat. and sand.

These are the reasons why I chose photo number two reading from left to right

Answer:

I would say that your answer would be the second one.( the red one)

Explanation:

because the legs it has seem like it would grip onto trees fairly well.

Answer:

[tex]3H_2S+2Ga(ClO_3)_3\rightarrow Ga_2S_3+6HClO_3[/tex]

Explanation:

Hello,

In this case, the described chemical reaction is:

[tex]H_2S+Ga(ClO_3)_3\rightarrow Ga_2S_3+HClO_3[/tex]

After balancing, we must assure the same quantity of atoms of all the elements at both reactants and products:

[tex]3H_2S+2Ga(ClO_3)_3\rightarrow Ga_2S_3+6HClO_3[/tex]

Thus, we find two galliums, three sulfurs, six chlorines, six hydrogens and eighteen oxygens at both reactants and products.

Best regards.

Answer:

A) It indicates the direction in which the reaction occurs.

Explanation:

The reason we don't use equals signs (=) in chemical reactions is because of the Identity Property of Equality (if a = b then b = a), which would allow us to reverse reactions. Reactions can't just be reversed (since some don't even occur); we need to know what is reacting to make what. Thus, we use the arrow, or yields symbol to denote this.

The substances to the left of the sign are the reactants, the ones that are reacting, and the ones on the right are the products, the ones that are being produced from the reactants. The arrow is an excellent way to represent the direction the reaction occurs in as the way it's written clearly demonstrates direction.

Hope this helps!

Answer:

See explanation.

Explanation:

Hello,

In this case, the chemical structure of the given compound, which is an alcohol, based on the suffix "ol", the bromo radical at the first carbon and the isobutyl radical at the 3rd carbon is shown on the attached picture wherein the hydroxyl is drawn at the 4th carbon. Remember that IUPAC rules for nomenclature help us to easily name or draw organic molecules by indicating the radicals and their positions and the main chain at the en of the name.

Best regards.

The diagrammatic structure for the compound 1-Bromo-3-isobutyl-4-heptanol  can be seen in the image below.

When naming an organic compound, we will first consider the longest chain of the carbon atom and attach the substituents in such a way that we will have the lowest number when adding them.

In the compound 1-Bromo-3-isobutyl-4-heptanol, we first draw the seven carbon chain with -OH substituent on the fourth carbon. This was followed by adding the substituent of isobutyl to carbon atom 3 and bromine to carbon atom 1.

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Answer:

2.42x10^5 L

Explanation:

10.0ft x 11.0 ft x 8.00 ft = 880. ft^3 (1 cubic foot = 28316.8 cubic cm)

880. ft^3 * (28316.8 cubic cm/ 1 cubic foot) = 24,918,784 cm^3

(1L=103 cm^3)

24,918,784 cm^3 (1L/103 cm^3) = 2.42x10^5 L

[tex]2.42*10^5[/tex]  liters of air are in a room.

It helps to show another person the exact amount you have. Assist in solving a mathematical problem, especially in chemistry, where you can follow the units to get to the answer. Show which measurement system the person is using.

1 in. = 2.54 cm

1 L = 10³ cm³

Given: 10.0 ft × 11.0 ft 8.00 ft ceiling

Now, converting into given quantities:

[tex]10.0ft * 11.0 ft * 8.00 ft = 880. ft^3 ( = 28316.8 \text{ cubic cm})\\\\880. ft^3 * (\frac{28316.8 \text{ cubic cm}} {\text{1 cubic foot}} }) = 24,918,784 cm^3\\\\24,918,784 cm^3 (\frac{1L}{10^3 cm^3})= 2.42*10^5 L[/tex]

→  Thus,[tex]2.42*10^5[/tex] liters of air are in a room that measures 10.0 ft × 11.0 ft and has an 8.00 ft ceiling.

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Answer:

Concentration of hydronium ion, H3O+ is 1x10^-2 M

Explanation:

The following data were obtained from the question:

Concentration of Hydroxide ion, [OH-] = 1.0x10^-12 M

Concentration of hydronium ion, [H3O+] =?

Next, we shall determine the pOH of the solution. This is illustrated below below:

pOH = - Log [OH-]

pOH = - Log 1.0x10^-12

pOH = 12

Next, we shall determine the pH of the solution.

pH + pOH = 14

pOH = 12

pH + 12 = 14

Collect like terms

pH = 14 - 12

pH = 2

Finally, we shall determine the Concentration of hydronium ion, [H3O+] as follow:

pH = - log [H3O+]

pH = 2

2 = - log [H3O+]

- 2 = log [H3O+]

[H3O+] = Antilog (-2)

[H3O+] = 0.01M = 1x10^-2 M

Answer:

Earth's crust

Explanation:

The lithosphere is the rigid outer part of the earth, consisting of the crust and upper mantle. It is the, rigid, rocky outer layer of the Earth, consisting of the crust and the solid outermost layer of the upper mantle. It extends to a depth of about 60 miles (100 km). It is the outer part of the solid earth composed of rock essentially like that exposed at the surface, consisting of the crust and outermost layer of the mantle.

We can also look at it as the solid part of the earth on which plants grow and animals survive. It contains all the rock formations that bear the various minerals found on earth.

The lithosphere is composed of both the crust and the portion of the upper mantle that behaves as a brittle, rigid solid.

Answer:

The answer is "16"

Explanation:

In the question given, it asks about the partial carbon dioxide ([tex]CO_2[/tex]) pressure, which is directly related to the oxygen ([tex]O_2[/tex]) to carbon dioxide ([tex]CO_2[/tex]) mole ratio, which is 1 to 4.

Answer:

19.7 L

Explanation:

Answer:

The answer is 19.7

Explanation:

Answer:

1.heat a pan of water with just a little bit of water,have a boil

2.chosse ure salt

3.stir in has much salt has u can than take the pan off the heat

4.pour the mix into a glass jar

5.tie a string to an objeet that can lay accross the top and put just the string in ure mix

Explanation oh and look at it everyday       hope that helps

Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

[tex]C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)[/tex]

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion)  and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = [tex]156.31 g/mol.[/tex]

[tex]\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.[/tex]

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

[tex]V = \frac{nRT}{P} \\[/tex]

[tex]V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\[/tex]

[tex]V = 428.23 \ L[/tex]

Answer:

thermal energy

Explanation:

Answer:

B- Thermal Energy

Explanation:

Thermal energy is produced due to all of the movement of particles inside the material.

Answer:

B

Explanation:

Answer:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Explanation:

H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)

A careful observation of the equation above, shows that the equation is already balanced.

To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Answer:  A degenerate pressure will generate a large force to repel further  compression.

Explanation: In the production of new stars from the core of old dying white dwarf stars, the inner parts of the star will experience contraction with the release of  heat , as they contract, their atoms will be  squeezed such that their electrons start to overlap, and because of the Pauli's exclusive principle which states that no two electrons can occupy same space, the electrons will begin to repel each other and an opposing pressure called degenerate pressure will create a force so that the electrons  cannot continually be crushed or overlap. With the limit of contraction, the outer parts of the star will expand and be repelled releasing the old stars called nebula  and creating space for the inner new stars to form.

Answer:

Order is MgBr₂ > KBr > (CH₃COOH) > (C₆H₁₂O₆)

Explanation:

Find the given attachment

Answer:

The answer to your question is given below

Explanation:

1. 2,4-dimethylhexane can be drawn as follow:

a. The parent name: Hexane i.e it contains 6 carbon atom.

b. The substitute group attached: Methyl i.e CH3 and it is at carbon 2 and 4.

c. Draw 6 carbon atom in a straight line and put CH3 at carbon 2 and 4. As shown in attach photo.

2. 4-methyl-2-pentene can be drawn as follow:

a. The parent name: pentene i.e it contains 5 carbon atom and the double bond is at carbon 2.

b. The substitute group attached: Methyl i.e CH3 and it is at carbon 4.

c. Draw 5 carbon atom in a straight line and put a double bond at carbon 2 and CH3 at carbon 4 as shown in attach photo.

3. 4-chloro-7-methyl-2-nonyne can be drawn as follow:

a. The parent name: nonyne i.e it contains 9 carbon atom and the triple bond is at carbon 2.

b. The substitute group attached:

i. Chlorine (Chloro) i.e Cl and it is at carbon 4.

ii. Methyl i.e CH3 and it is at carbon 7.

c. Draw 9 carbon atom in a straight line and put a triple bond at carbon 2, Cl at carbon 4 and CH3 at carbon and 7 as shown in attach photo.

Answer:

[tex]M_{A}[/tex] : [tex]M_{B}[/tex]  = 4 : 1

Explanation:

Given that:

Volume of a cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h

For cylinder A, [tex]l_{A}[/tex] = [tex]h_{A}[/tex] = [tex]\frac{1}{4} l_{B}[/tex] and [tex]r_{A}[/tex] = 4[tex]r_{B}[/tex].

Volume of cylinder A = [tex]\pi[/tex][tex](4r_{B}) ^{2}[/tex] × [tex]\frac{1}{4} l_{B}[/tex]

                                   = 4[tex]\pi[/tex][tex]r_{B} ^{2}[/tex] [tex]l_{B}[/tex]

Volume of cylinder B =  [tex]\pi[/tex][tex](r_{B}) ^{2}[/tex] [tex]l_{B}[/tex]

                                  =  [tex]\pi[/tex][tex]r_{B} ^{2}[/tex][tex]l_{B}[/tex]

To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).

i.e    ρ = [tex]\frac{M}{V}[/tex]

Thus, since the cylinders are made from the same material, they have the same density  (ρ). So that;

density of A = density of B

density of A = [tex]\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }[/tex]

density of B = [tex]\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }[/tex]

⇒            [tex]\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }[/tex]  =  [tex]\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }[/tex]

The ratio of mass of cylinder A to that of B is given as;

                       [tex]\frac{M_{A} }{M_{B} }[/tex]  =  [tex]\frac{4\pi r_{B} ^{2} l_{B} }{\pi r_{B} ^{2} l_{B} }[/tex]

⇒                        [tex]\frac{M_{A} }{M_{B} }[/tex] = [tex]\frac{4}{1}[/tex]

Therefore, [tex]M_{A}[/tex] : [tex]M_{B}[/tex]  = 4 : 1

Answer:

4.

Explanation:

Hello,

In this case, since we are talking about the same material, their densities are the same:

[tex]\rho _A=\rho _B[/tex]

And each density is defined by:

[tex]\rho _A=\frac{m_A}{V_A} \\\\\rho _B=\frac{m_B}{V_B}[/tex]

Thus, we also define the volume of a cylinder:

[tex]V_{cylinder}=\pi r^2h[/tex]

Therefore, we obtain:

[tex]\rho _A=\frac{m_A}{\pi r_A^2h_A}[/tex]

[tex]\rho _B=\frac{m_B}{ \pi r_B^2h_B}[/tex]

Now, the given information regarding the the length and the radius is written mathematically:

[tex]h_A=\frac{1}{4} h_B\\\\r_A=4 r_B[/tex]

So we introduce such additional equations in:

[tex]\frac{m_A}{\pi r_A^2h_A}=\frac{m_B}{\pi r_B^2h_B}\\\\\frac{m_A}{\pi (4r_B)^2(\frac{1}{4}h_B)}=\frac{m_B}{\pi r_B^2h_B}\\\\\frac{m_A}{m_B} =\frac{\pi (4r_B)^2(\frac{1}{4}h_B)}{\pi r_B^2h_B}[/tex]

So we simplify for the radius and lengths:

[tex]\frac{m_A}{m_B} =\frac{\pi (4r_B)^2(\frac{1}{4}h_B)}{\pi r_B^2h_B}\\\\\frac{m_A}{m_B} =16 *\frac{1}{4}\\ \\\frac{m_A}{m_B} =4[/tex]

So the ratio of the mass of cylinder A to the mass of cylinder B is 4.

Best regards.

Answer:

No. it,s not possible.

Explanation:

Because you know that ionic compound is having large inter-molecular forces. -77C* is for a compound having v.very small inter-molecular forces.you must know that M.B is directly varing with inter-molecular forces.

Answer:

17.2mL

Explanation:

Step 1:

Determination of the molarity of potassium phosphate K3PO4 solution.

This is illustrated below:

Mass of K3PO4 = 46.3g

Molar Mass of K3PO4 = (39x3) + 31 + (16x4) = 212g/mol

Mole of K3PO4 =..?

Mole = Mass /Molar Mass

Mole of K3PO4 = 46.3/212 = 0.218 mole

Volume of water = 250mL = 250/1000 = 0.25L

Molarity = mole /Volume

Molarity of K3PO4 = 0.218/0.25

Molarity of K3PO4 = 0.872M

Step 2:

Determination of the volume of the stock solution of K3PO4 needed.

Molarity of stock solution (M1) = 0.872M

Volume of stock solution needed (V1) =..?

Molarity of diluted solution (M2) = 0.1M

Volume of diluted solution (V2) = 150mL

The volume of the stock solution needed can be obtained as follow:

M1V1 = M2V2

0.872 x V1 = 0.1 x 150

Divide both side by 0.872

V1 = (0.1 x 150)/0.872

V1 = 17.2mL

Therefore, the volume of the stock solution needed is 17.2mL

answer :

b because 24 <3

Explanation:

hdjsna surveyed I need points lol sorry for wasting time

Answer:

The reduction potential of   [tex]Cu^2+/Cu[/tex] is  [tex]E_c^o = 0.34 \ V[/tex]

Explanation:

From the question we are told that

      The potential of the cell is  [tex]M_{cell} = E^o _{cell} = 1.100 \ V[/tex]

       The range is  [tex]R = 0.005 \ V[/tex]

        The temperature is  [tex]T = 25 ^oC[/tex]

Note the reason why Zn is oxized and  Cu is reduced is because Zn is higher than Cu on the electrochemical series

    The reaction at the anode is  

              [tex]Zn ^{2-} _{(aq)} + 2e \to Zn_{(s)} \ \ \ \ \ E^o_a = -0.76 \ V[/tex]    

The [tex]E^o\ is \ the \ standard\ oxidation \ potential\ value\ for\ Zn\ oxidation[/tex]

    The reaction at the anode is  

             [tex]Cu^{2+} _{(aq)} + 2e^{-} \to Cu_{(s)} \ \ \ \ \ \ \ \ E^o_c = c \ V[/tex]  

Now

          [tex]E^o _{cell} = E_c^o - E_a^o[/tex]  

substituting values

           [tex]1.100 = E_c^o -(- 0.76)[/tex]

           [tex]E_c^o = 1.100 - 0.76[/tex]

           [tex]E_c^o = 0.34 \ V[/tex]

Hence the reduction potential of   [tex]Cu^2+/Cu[/tex] is  [tex]E_c^o = 0.34 \ V[/tex]

Answer:

a. 1.23 V

b. No maximum

Explanation:

Required:

a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?

b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

If E°cell must be at least 1.10 V (E°cell > 1.10 V),

E°red, cat - E°red, an > 1.10 V

E°red, cat - 0.13V > 1.10 V

E°red, cat > 1.23 V

The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.