How can you use the properties of operations to evaluate this expression? 18+4(28)​

Answers

Answer 1

Step-by-step explanation:

open the brackets by multiplying 4 and 28 =112

18+112= 130

Answer 2

Answer:

Use the distributive property and expand 28, then distribute the 4 to 20 and the 4 to 8. Then you have 18 + 80 + 32. Use commutative property to reverse the order of 32 and 80 so that 18 and 32 are friendly numbers to add.


Related Questions

Select the correct answer.
You reflect triangle PQR with vertices P(-2,-4). Q(-3,-1), and R(-4,-4), across the y-axis to get triangle P'Q'R'. What are the coordinates of triangle
P'Q'R?

Answers

Answer:

P' (2, -4)

Q' (3, -1)

R' (4, -4)

Step-by-step explanation:

Reflection in the y axis

(x, y) → (-x, y)

P(⁻²₋₄ ) → P'(²₋₄ ) ∴ P'(2, -4)

Q(⁻³₋₁ ) → Q'(³₋₁ ) ∴ Q'(3, -1)

R(⁻⁴₋₄ ) → R'(⁴₋₄ ) ∴ R'(4, -4)

Pablo wants to build a rectangular pen for the pig he is raising in his agriculture class. Pablo only has 36 feet of fencing. What representative function can be used to model the area of the rectangular pen as a function of the side length, x?

Answers

Answer:

Area of the rectangular pen is: [tex]18 \,x-x^2[/tex]

Step-by-step explanation:

We need to specify that the perimeter of the rectangular area of side x adds to the amount of fence Pablo has (36 feet). Recall as well that the opposite sides of a rectangle are equal, so if there is a side of length x, there must be another one of this size as well (a total of 2 x in the perimeter),let's assume that the perpendicular sides to x are of length y, then:

Perimeter= 2 x + 2 y = 36

so, 2 (x+y)  = 36   then  (x+y) = 18

and therefore the side y should be:

y = 18 - x

Now we can write the formula for representing the area of the rectangle (product of both quantities: x * y

[tex]Area=x\,*\,y = x\,(18-x) =18 \,x-x^2[/tex]

What is the diameter of the circle the area of the circle is 144 square root m2

Answers

Answer: 24 m

Step-by-step explanation:

Given: area of the circle is 144 π m² .

Area of a circle = [tex]\pi r^2[/tex], where r= radius of the circle.

Then, [tex]144\pi = \pi r^2[/tex]

Cancelling π from both sides , we get

[tex]144 = r^2[/tex]

Taking square root on both sides , we get'

[tex]12= r[/tex]

i.e. radius = 12 m

Then diameter = 2 (radius ) = 2 (12)= 24 m

Hence, the diameter of the circle is 24 m.

The diameter of the circle is 13.54cm

The formula for calculating the area of the circle is expressed as:

A = πd²/4

d is the diameter of the circle

GIven the following

A = 144m²

Substitute the area into the circle

144 = πd²/4

πd² = 144 * 4

πd² = 576

d² = 576/3.14

d² =183.44

d = 13.54cm

Hence the diameter of the circle is 13.54cm

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The areas of two similar octagons are 9 m² and 25 m². What is the scale factor of their side lengths? PLZ HELP PLZ PLZ PLZ

Answers

Answer:

[tex] \frac{3}{5} [/tex]

Step-by-step explanation:

Let the side length for the octagon having 9m² as area = x

Side length for the octagon having area of 25m² = y.

Thus:

[tex] \frac{9}{25} = (\frac{x}{y})^2 [/tex] (area of similar polygons theorem)

The scale factor of their sides would be [tex] \frac{x}{y} [/tex]. Which is:

[tex] \sqrt{\frac{9}{25}} = \frac{x}{y} [/tex]

[tex] \frac{\sqrt{9}}{\sqrt{25}} = \frac{x}{y} [/tex]

[tex] \frac{3}{5} = \frac{x}{y} [/tex]

Scale factor of their sides = [tex] \frac{3}{5} [/tex]

Answer:

3:5

Step-by-step explanation:

Mr. Ferret loves fresh, juicy, organic mole meat from Mole Foods grocery store. But his ability to purchase this tasty delicacy depends upon how much Mole Foods is currently charging per pound. The more Mole Foods charges, the less mole meat Mr. Ferret will buy. Use the ‑intercept equation to plot a line representing Mr. Ferret's demand curve.y =−2x+8

Answers

Answer:

It has a negative slope = -2

Step-by-step explanation:

Let y be the price and x be the quantity purchased . Then putting the value of x in the equation we can find the price= y

where  y = −2x+8

x      0       1         2         3         4         5         6        7

y      8       6        4         2         0        -2         -4       -6

So we can plot the demand curve which has a negative slope.

We see from the values above that the slope is negative having a value equal to -2. This means that for every increase in the number of quantities there is a decrease in the price.

Which of the following can be written as a fraction of integers? CHECK ALL THAT APPLY.

2.5
square root of 14
-1.25
5.33333...
square root of 16
null
0.6

Answers

Answer:

[tex]2.5[/tex]    [tex]-1.25[/tex]      [tex]\sqrt{16}[/tex]        [tex]0.6[/tex]

Step-by-step explanation:

Required

Which of the given parameters can be represented as fraction of integers

Taking them one at a time;

1.  2.5

This can be rewritten as

[tex]2.5 = \frac{2.5}{1}[/tex]

Multiply numerator and denominator by 2

[tex]2.5 = \frac{2.5 * 2}{1 * 2}[/tex]

[tex]2.5 = \frac{5}{2}[/tex]

Hence, 2.5 can be represented as fraction of integers

2.  √14

This can be rewritten as

[tex]\sqrt{14} = 3.74165738677...[/tex]

The ... implies that the decimal continues and this cannot be represented as a fraction

3.  -1.25

This can be rewritten as

[tex]-1.25 = \frac{-1.25}{1}[/tex]

Multiply numerator and denominator by 4

[tex]-1.25 = \frac{-1.25 * 4}{1 * 4}[/tex]

[tex]-1.25 = \frac{-5}{4}[/tex]

Hence, -1.25 can be represented as fraction of integers

4.  5.33333.....

The ... implies that the decimal continues and this cannot be represented as a fraction

5.  √16

[tex]\sqrt{16} = \±4[/tex]

This can be rewritten as

[tex]\sqrt{16} = \±\frac{4}{1}[/tex]

Multiply numerator and denominator by 2

[tex]\sqrt{16} = \±\frac{4 * 2}{1 * 2}[/tex]

[tex]\sqrt{16} = \±\frac{8}{2}[/tex]

Hence, √16 can be represented as fraction of integers

6.  0.6

This can be rewritten as

[tex]0.6 = \frac{0.6}{1}[/tex]

Multiply numerator and denominator by 10

[tex]0.6 = \frac{0.6 * 10}{1 * 10}[/tex]

[tex]0.6 = \frac{6}{10}[/tex]

Hence, 0.6 can be represented as fraction of integers

What is the square root of 190,290,390,545

Answers

Answer:

Step-by-step explanation:

Answer:

190 = 13.78

290 =17.02

390 = 19.74

545 = 23.34

Step-by-step explanation:

if you need simplest ratical let me know

If m<1 is three less than twice the measure of <2, and <1 and <2 are supplementary angles, find each angle
measure.​

Answers

Step-by-step explanation:

Hey there!!

Let angle 2 be x then,

measure of angle 1 is three less than twice of angle 2 = 2x-3.

Now, we have.

Measure of supplementary angle is 180°.

Angle 1 + angle 2 = 180°

x+(2x - 3)= 180°

3x -3=180°

3x= 180°+3°

[tex]x = \frac{183}{3} [/tex]

Therefore, x = 61°.

Now, angle 2 = 61°

angle 1 = (61×2-3)= 119°.

check (119°+61°=180°).

Hope it helps...

anyone know this one

Answers

Answer:

Only B

Step-by-step explanation:

Did this in Khan Academy.

=> Also, there are 2 '-' symbols in the question.

In Option A, there is only 1 "-' symbol.

In Option B, there are 2 '-' symbols.

Option C says none of the above.

Since, Option B has 2 '-' symbols, it is the correct.

X + 7
2x - 3
Perimeter:
Area:

Answers

Answer:

P=6x+8

A=2x^2+11x-21

Step-by-step explanation:

Perimeter:

P=2(x+7)+2(2x-3)

P=6x+8

Area:

A=(x+7)(2x-3)

A=2x^2+11x-21

What is the measure of Angle X, in degrees?

Answers

Answer:

sinx = perpendicular/hypotenuse

sinx = 12/16

sinx = 3/4

x = arcsin 3/4

x = 48.6 degrees (using calculator)

Use Lagrange multipliers to find three positive numbers whose sum is 210 and whose product is maximum. (Enter your answers as a comma-separated list.)

Answers

Answer: the three positive numbers are; 70, 70, 70

Step-by-step explanation:

Given that sum is equal = 210

Lets ( x, y, z ) be the three positive numbers

such that

x + y + z = 210

what is the maximum of xyz

take f(x,y,z) = xyz

Q(x,y,z) = 0

x + y + z -210 = 0

consider the function

F(x,y,z) = f(x,y,z) + λQ(x,y,z)

F = xyz + λ(x+y+z-210)

dF/dx = 0 ⇒ yz + λ(1) = 0 ⇒ λ = -yz   ..............equ(1)

dF/dy = 0 ⇒ xz + λ(1) = 0 ⇒ λ = -xz.................equ(2)

dF/dz = 0 ⇒ xy + λ(1) = 0 ⇒ λ = -xy...............equ(3)

Now

equ(1)/equ(2) ⇒ λ/λ = -yz/-xz ⇒ x = +y

equ(1)/equ(3) ⇒ λ/λ = - yz/-xy ⇒ x = +z

⇒ y = z = x

by substitution

x + y + z = 210

x + x + x = 210

3x = 210

x = 210/3 = 70

∴ x, y, z = 70, 70 ,70

MAXIMUM

∛xyz = 70  { when x = y = z = 70}

Solve it! Hurry
Will mark as brainliest
IF U TRY TO get the points free i would report u

Answers

Answer:

A. 3x^2+7x^2+2×3x ×7-84x = 3x^2+7x^2-2×3x×7

9x^2+49x^2+42x-84 x= 9x^2+49x^2-42x

9x^2+49x^2-42 = 9x^2+49 x^2-42x

verified

B.

Answer:

Give him or her brainlist

Step-by-step explanation:

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A rectangle has opposite sides that are parallel and congruent. What is the measure of each interior angle in a rectangle?

Answers

Each angle interior angle in a rectangle is 90

Each interior angle of a rectangle measures 90°

What is a rectangle?

A rectangle is a closed 2-D shape, having 4 sides, 4 corners, and 4 right angles (90°). The opposite sides of a rectangle are equal and parallel.

According to the property of a rectangle, we have,

Opposite side equal and paralleleach interior angle right angleDiagonal are equal and bisects each other.

Hence, Each interior angle of a rectangle measures 90°

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if you bought a stock last year for $59 and it risen 13% how much is the stock worth now

Answers

the corresponding amount in a 13% increase is: (59 * 13): 100 = $ 7.67

so the current stock price is: 59 + 7.67 = $ 66.67

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
6-x+1=x+5
O 2
O 3
O 6
O 12

Answers

we can multiply 12 to eliminate the fractions

Using traditional methods it takes 98 hours to receive an advanced flying license. A new training technique using Computer Aided Instruction (CAI) has been proposed. A researcher believes the new technique may reduce training time and decides to perform a hypothesis test. After performing the test on 200 students, the researcher decides to reject the null hypothesis at a 0.01 level of significance. What is the conclusion?

Answers

Answer:

We conclude that the new technique reduces the training time that it takes less than 98 hours to receive an advanced flying license.

Step-by-step explanation:

We are given that using traditional methods it takes 98 hours to receive an advanced flying license. A researcher believes the new technique may reduce training time and decides to perform a hypothesis test.

After performing the test on 200 students, the researcher decides to reject the null hypothesis at a 0.01 level of significance.

Let [tex]\mu[/tex] = mean time to receive an advanced flying license.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 98 hours

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] < 98 hours

Here, the null hypothesis states that it takes 98 hours to receive an advanced flying license.

On the other hand, the alternate hypothesis states the new technique may reduce training time that it takes less than 98 hours to receive an advanced flying license.

Now, it is stated that after performing the test on 200 students, the researcher decides to reject the null hypothesis at a 0.01 level of significance. This means we don't have sufficient evidence to support the null hypothesis as our test statistics will fall in the rejection region.

Therefore, we conclude that the new technique reduces the training time that it takes less than 98 hours to receive an advanced flying license.

exploring the graph of y equals cosine Theta​

Answers

Answer:  see below

Step-by-step explanation:

The coordinates on the Unit Circle are (cos, sin). Since we are focused on cosine, we only need to focus on the left side of the coordinate. The cosine value (left side) will be the y-value of the function y = cos x

Use the quadrangles (angles on the axes) to represent the x-values of the function y = cos x.

Quadrangles are: 0°, 90°, 180°, 270°, 360°  (360° = 0°)

Together, the coordinates will be as follow:

[tex]\boxed{\begin{array}{c||c|c||c}\underline{(cos,sin)}&\underline{x=angle}&\underline{y=cosx}&\underline{\quad (x,y)\quad}\\(1,0)&0^o&1&(0^o,1)\\(0,1)&90^o&0&(90^o,0)\\(-1,0)&180^o&-1&(180^o,-1)\\(0,-1)&270^o&0&(270^o,0)\\(1,0)&360^o&1&(360^o,1)\end{array}}[/tex]

A toxin increase from 12ppm to 16ppm. What percent increase is this?​

Answers

For percentage increase there is a formula
New value - old value
Divided by old value
Multiplied by 100
16-12=4
(4/12)*100
=33.3%
For percentage decrease
The formula is a bit different
It is old value - new value
Divided by old value
Multiplied by 100

Which expression is equivalent to the one below?

Answers

Answer:

D . 9 .1/13

Step-by-step explanation:

[tex]9\div 13 = \frac{9}{13} \\\\9\cdot \frac{1}{13}\\\\=\frac{9}{1}\cdot \frac{1}{13}\\\\=\frac{9\cdot \:1}{1\cdot \:13}\\\\=\frac{9}{13}[/tex]

when bisecting an angle, why must The Arc be drawn in the interior of the angle?​

Answers

Answer:

It depends on the measure of the angle you are talking about

Given f(x)=10-2x, find f(7)

Answers

Answer:

f(7)=10-14=-4

Answer=-4

Step-by-step explanation:

Answer:

-4

Step-by-step explanation:

f(x)=10-2x

Let x = 7

f(7) = 10 -2(7)

     = 10 -14

     = -4

Will mark brainiest for simplest and most coherent answer. What does it mean if an x (input) or y (output) value doesn't make sense? What does it look like on a graph? What happens in the equation?

Answers

Answer:

I tried to answer but I still would like to know what doesn't make sense.

Considering the identity:

[tex]\sec^2\theta-\tan^2\theta=1 \implies |\sec\theta|\geq1[/tex]

[tex]$\forall\;\theta\in\mathbb{R}-\{(2n+1)\frac{\pi}{2}, n\in\mathbb{Z} \}$[/tex]

The identity is true whenever both sides are defined. It is not supposed to hold the values when we have division by zero, because it is undefined.

If the value doesn't make sense, it is probably not a function, or it is undefined by the given value of [tex]x[/tex].

Let's go back to the definition of function again:

A function relates a set of inputs and a set of allowable outputs where each input is related to only one output. It basically defines the relation of ordered pairs.

Hope it helped you a bit.

Find the output, y, when the input, x, is 30. y = 14 - 0.5x y = _________

Answers

Answer:

[tex]\Huge \boxed{y=-1}[/tex]

[tex]\rule[250]{250}{3}[/tex]

Step-by-step explanation:

[tex]y=14-0.5x[/tex]

The input x is 30. Switching x with 30.

[tex]y=14-0.5(30)[/tex]

Solving for y.

[tex]y=14-15[/tex]

[tex]y=-1[/tex]

[tex]\rule[250]{250}{3}[/tex]

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{y = - 1}}}}}[/tex]

Step-by-step explanation:

Given, Value of x is 30

To find : Value of y

[tex] \sf{y = 14 - 0.5x}[/tex]

Plug the value of x

⇒[tex] \sf{y = 14 - 0.5 \times 30}[/tex]

Multiply the numbers : 0.5 and 30

⇒[tex] \sf{y = 14 - 15}[/tex]

Subtract 15 from 14

⇒[tex] \sf{y = - 1}[/tex]

Hope I helped!

Best regards!!

A lamina occupies the disk x squared space plus space y squared space less or equal than 4. Find the mass, if the density at any point is proportional to its distance from the origin, where the proportionality constant is 3.

Answers

Answer: Mass of Lamina is (K/3)

Centre of mass is (3/8, 3pi/16)

Step-by-step explanation:

Find explanation in the attachments

New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.4, they are hidden by Han Solo. When Leia hides the codes, she hides them with BB-8 70% of the time and with C-3PO 30% of the time. Han Solo is equally likely to hide them with BB-8 and C-3PO a. What is the probability that the codes are with BB-8? b. Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

Answers

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

joseph wants to find the side length of a square that has an area of 150 feet. Should his answer be rational or irrational ? why ?

Answers

Answer:

i dont what it is can u tell me

Step-by-step explanation:

The length side is not a integer. Therefore, The answer is irrational.

What is the area of a square?

The area of a square is given by the formula

A = side x side

In this problem we have

A = 150 square feet.

Now, substitute in the formula

150 = side^2

Now, take the square root both sides

side = √150

Then simplify

side = 5√6 feet

Remember that; A Rational Number is a number that can be made by dividing two integers. soThe length side is not a integer

Therefore, The answer is irrational.

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Here is a sample distribution of hourly earnings in Paul's Cookie Factory: Hourly Earning $6 up to $9 $9 up to $12 $12 up to $15 Frequency 16 42 10 The limits of the class with the smallest frequency are: ______.

Answers

Answer:

$12 up to $15

Step-by-step explanation:

Given

Hourly Earning: $6 - $9 || $9 - $12 || $12 - $15

Frequency:          16        ||         4      ||   10

Required

Determine the limits of the least frequency;

First, we have to determine the lowest frequency;

From the table. the lowest frequency is:

[tex]Lowest = 10[/tex]

Next is to determine the corresponding class limits

The corresponding class limit is $12 up to $15

The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1 (All units are 1000 cells/μ L.)
Using the empirical rule, find each approximate percentage below.
What is the approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 ?
What is the approximate percentage of women with platelet counts between 71.3 and 443.9 ?
a. Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.
(Type an integer or a decimal. Do not round.)
b. Approximately ____ % of women in this group have platelet counts between 71.3 and 443.9.
(Type an integer or a decimal. Do not round.)

Answers

Answer:

(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.

(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1

Let X = the blood platelet counts of a group of women

So, X ~ Normal([tex]\mu=257.62, \sigma^{2} =62.1^{2}[/tex])

Now, the empirical rule states that;

68% of the data values lie within the 1 standard deviation of the mean.95% of the data values lie within the 2 standard deviations of the mean.99.7% of the data values lie within the 3 standard deviations of the mean.

(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.

(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;

       z-score of 443.9 =  [tex]\frac{X-\mu}{\sigma}[/tex]

                                   =  [tex]\frac{443.9-257.62}{62.1}[/tex]  = 3

       z-score of 71.3 =  [tex]\frac{X-\mu}{\sigma}[/tex]

                                =  [tex]\frac{71.3-257.62}{62.1}[/tex]  = -3

So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

which of these limits evaluate to 0?

Answers

Answer: C) I and II only

===============================================

Work Shown:

Part I

[tex]\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\[/tex]

----------

Part II

[tex]\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\[/tex]

----------

Part III

[tex]\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\[/tex]

Other Questions
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