Answer:
Chemical Bonding
Explanation:
The atmosphere of Venus is mostly carbon dioxide, and the atmosphere of the Earth has water vapor. Why are these two gases absent in the atmosphere of the satellite around Saturn called Titan
Answer:
if these gases existed in Titan, this n in solid form, by which its absence in the atmosphere is understood.
Explanation:
Each gas and chemical compound has a defined temperature for changes of state, specifically for the change from gaseous to liquid and from liquid to solid state we have
gas gas → liquid liquid → solid
(ºC) (ºC)
H₂0 (Water) 100 0
CO₂ -56.6 (P> = 5.2 bar) <-56.6
The temperature of the Titan satellite is - 180ºC
From the above, if these gases existed in Titan, this n in solid form, by which its absence in the atmosphere is understood.
please help with a step by step method
Answer:
Explanation:
This is a First Law of thermodynamics problem. We have to remember that the total energy available to a system is constant throughout the whole problem and that energy cannot be created or destroyed. So we need to find the total energy available right at the start. Well it just so happens that we are told that the total energy is 1000J and that it is all potential energy when the sphere is at rest and is 25 m off the ground. If the object isn't moving, all the energy is potential until it starts moving and the energy begins to convert from potential to kinetic a little bit at a time. The thing that we don't know is the mass of the shpere. Begin with the fact that the PE = 1000 (I'm going to se 2 sig fig's since there's only 1 in 1000). If
PE = 1000 and PE = mgh, then
1000 = m(9.8)(25) so
m = 4.1 kg
We also need the height at which this sphere has a PE of 600. Again, if
PE = 600 and PE = mgh, then
600 = (4.1)(9.8)h so
h = 15 Filling in the total energy equation now, using the fact that the total energy available to the system is 1000J:
TE = PE + KE and
1000 = (4.1)(9.8)(15) + [tex]\frac{1}{2}(4.1)v^2[/tex] and we are looking for v.
1000 = 6.0 × 10² + 2.1v² so
[tex]v=\sqrt{\frac{1000-6.0*10^2}{2.1} }[/tex] and
[tex]v=\sqrt{\frac{4.0*10^2}{2.1} }[/tex] gives us
v = 14 m/s
URGENT A student runs at 4.5 m/s [27° S of W] for 3.0 minutes and then he turns and runs at 3.5 m/s [35° S of E] for 4.1 minutes. a. What was his average speed? b. What was his displacement? PLEASE SHOW ALL WORK
Answer:
Explanation:
As far as the displacement goes, we have 2 displacement vectors. If we didn't have the angles to deal with, this would be a much simpler process, but then that wouldn't be any fun at all, would it? I'll deal with the average speed first, then the displacement, which is a vector addition problem.
The average speed is found by adding together the distances the student traveled and then dividing this sum by the total time he spent traveling. If we are told that the student runs at 4.5 m/s for 3.0 minutes, we can use this to find out the distance he ran during that time interval. However, the units are not the same. We will find the distance the student traveled by convering the time to seconds.
3.0 minutes = 180 seconds, and
4.1 minutes = 246 seconds.
That means that the distance he ran in 180 seconds is found by multiplying this time be the speed at which he ran:
4.5 m/s(180 s) = 810 m and
3.5 m/s(246 s) = 860 m (rounded to follow the rules of sig dig).
This makes the speed equation look like this:
[tex]s=\frac{810+861}{180+246}=\frac{1671}{426}=3.9\frac{m}{s}[/tex] That's the average speed, which is NOT at all the same as the displacement. Displacement is where he ended up in reference to where he started. The angles play a huge part in this math (that is very involved, to say the least). We begin by restating the displacement of each "leg" of this journey.
The first leg took him 810 m at 207 degrees and
the second leg took him 860 m at 325 degrees
To find the x and y components of these 2 legs, or parts, we have to use the cos and sin formulas. We will call the first leg A and the second leg B. First the x components of both A and B:
[tex]A_x=810cos207[/tex] and
[tex]A_x=-720[/tex]
[tex]B_x=860cos325[/tex] and
[tex]B_x=704[/tex] and we add these to get the x-component of the resultant vector, C:
-720
+ 704
-10 (rounded, as needed, to the tens place).
Now for the y-components of the resultant vector:
[tex]A_y=810sin207[/tex] and
[tex]A_y=-370[/tex]
[tex]B_y=860sin325[/tex] and
[tex]B_y=-490[/tex] and we add these to get the y-component of the resultant vector, C:
-370
+ -490
-860
Since the x component is negative and so is the y, we are in QIII, so when we finally find our angle, we will have to add 180 to it.
For the magnitude of the displacement vector, in m:
[tex]C_{mag}=\sqrt{(-10)^2+(-860)^2}[/tex] which gives us
[tex]C_{mag}=860m[/tex]
Now, because displacement is vector, we also need the angle. We find that is the formula
[tex]\theta=tan^{-1}(\frac{C_y}{C_x})[/tex] and filling in:
[tex]\theta=tan^{-1}(\frac{-860}{-10})=90[/tex] (rounded correctly), and then we add 180 to give us a final direction of 270 degrees.
So the final displacement of the student is 860 m at 270 degrees
What is the relation between acceleration due to gravity and radius of the earth?
Answer:
As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.
Formula: g = GM/r2
Dimensional Formula: M0L1T-2
Values of g in SI: 9.806 ms-2
Explanation:
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Answer:
♡
Explanation:
As the earth is an oblate spheroid, its radius near the equator is more than its radius near poles. Since for a source mass, the acceleration due to gravity is inversely proportional to the square of the radius of the earth, it varies with latitude due to the shape of the earth.
Calculate the electric field acting on the electron in a hydrogen atom due to the proton in the nucleus the radius of the orbit of the electron is 5.3×10^-11
Answer:
[tex]F=-8.2*10^{-8}N[/tex]
Explanation:
From the question we are told that:
Radius [tex]r=5.3*10^{-11}[/tex]
Where
Proton Charge [tex]q_1=1.6*10^{-19}C[/tex]
Charge of Electron [tex]q_2=-1.6*10^{-19}C[/tex]
Generally the equation for Coulomb's Law is mathematically given by
[tex]F=\frac{9*10^9(q_1)(q_2)}{r^2}[/tex]
[tex]F=\frac{9*10^9(1.6*10^{-19}C)(-1.6*10^{-19}C)}{5.3*10^{-11}}[/tex]
[tex]F=-8.2*10^{-8}N[/tex]
A hot-air balloon is rising upward with a constant speed of 2.85 m/s. When the balloon is 2.50 m above the ground, the balloonist accidentally drops a compass over the side of the balloon. How much time elapses before the compass hits the ground
Answer:
Explanation:
You have to declare which way is plus -- up or down. I will use down.
vi = - 2.85 The balloon is going up. That is the minus direction.
a = 9.81
d = 2.50 meters distance in this case is from the object to the ground.
d = vi*t + 1/2 a t^2
-2.50 = -2.85*t + 1/2 * 9.81 * t^2
-2.50 = -2.85*t + 4.905 * t^2 transfer the left to the right.
-4.905 t^2 + 2.85*t + 2.50 = 0
Use the quadratic formula to solve for t.
It turns out that t = 1.06
three condensers are connected in series across a 150 volt supply, the voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10^-8 c.calculate (a) the capacitance of each condenser (b)the effective capacitance of the combination
Answer:
(a) 1.5 nF, 1.2 nF, 1 nF
(b) 0.4 nF
Explanation:
V = 150 V
V' = 40 V, V'' = 50 V, V''' = 60 V, q = 6 x 10^-8 C
(a) C' = q/V' = 6 x 10^-8 / 40 = 1.5 x 10^-9 F
C'' = q/V'' = 6 x 10^-8 / 50 = 1.2 x 10^-9 F
C''' = q/V''' = 6 x 10^-8 / 60 = 1 x 10^-9 F
(b) The effective capacitance is
[tex]\frac{1}{C}=\frac{1}{C'}+\frac{1}{C''}+\frac{1}{C'''}\\\\\frac{1}{C}=\frac{10^9}{1.5}+\frac{10^9}{1.2}+\frac{10^9}{1}\\\\C = 0.4\times 10^{-9} F[/tex]
The difference between starting and ending
positions is
distance
displacement
Answer:
displacement
Explanation:
Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.
This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.
A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.
Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, position, displacement, etc.
Displacement can be defined as the change in the position of a body or an object. It is a vector quantity because it has both magnitude and direction.
This ultimately implies that, the difference between the starting and ending positions of a physical object is generally referred to as displacement
IA body starts to move from rest and travels with uniform acceleration of 7mls2. How far will the body move in 4 second .
Astronomers observe the Small Magellanic Cloud (SMC), a not very dense, rather small galaxy near us. They notice that even those stars that formed recently have relatively few heavier elements (when compared to such recent stars in our Milky Way.) What is the likely explanation for this deficiency
Answer:
The reason it has few heavier elements is due to the fact that it's stars are widely spaced and this implies that it's stars have very low rate of formation and termination.
Explanation:
The Small Magellanic Cloud, is basically a very tiny galaxy located near the Milky Way. Although it's tiny, it's diameter is approximately 7,000 light-years while it also contains over hundred million stars which are widely spaced.
Now, the reason it has few heavier elements is due to the fact that it's stars are widely spaced and this implies that it's stars have very low rate of formation and termination.
how to Calculate the pressure on its base.
Answer:
p is =force x 10 whch is constant
From class, weight is a measurement of the force of
acting on an object.
Friction
Normal
Gravity
Tension
Applied
Answer:
the answer is well known as gravity
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26. D. crushing the sugar cube and dissolving it in water.
27. A. atom
28. B. molecule
29. B. plum pudding model of Joseph John Thomson
30. B. He used cathode ray tubes which showed that all atoms contain tiny negatively charged subatomic particles or electrons.
31. D. protons and neutrons are relatively heavier than electrons.
A hamster in it's ball starts at rest and accelerates to 3ms1 in 6 seconds.
What was the distance the hamster travelled
Answer:9m
Explanation:
Ball starts from rest . Time taken = 6 seconds. Distance travelled by ball. ∴Distance travelled = 9 m
Hope it helps you
Good luck
An ice skater pushes harder with her legs and begins to move faster. Which two laws best describes this
Answer:
Newton' second law and third law describes the situation.
Explanation:
According to the Newton's second law, the force applied on a body is proportional to the rate of change of momentum of the body.
According to the Newton's third law, for every action there is an equal and opposite reaction.
When ice skater pushes harder means more force is applied so he moves fast and more be the action force more be the reaction force.
Thus, Newton' second law and third law describes the situation.
A scientist wants to use a model to help present results of his detailed scientific investigation
If a wire lies withina magnetic field what must be true for the magnetic field to produce an electric current in the wire
Answer:
The magnetic field through the wire must be changing
Explanation:
According to Faraday's law, the induced emf, ε in a metallic conductor is directly proportional to the rate of change of magnetic flux,Φ through it. This is stated mathematically as ε = dΦ/dt.
Now for the wire, the magnetic flux through it is given by Φ = ABcosθ where A = cross-sectional area of wire, B = magnetic field and θ = angle between A and B.
So, dΦ/dt = dABcosθ/dt
Since A and B are constant,
dΦ/dt = ABdcosθ/dt = -(dθ/dt)ABsinθ
Since dθ/dt implies a change in the angle between A and B, since A is constant, it implies that B must be rotating.
So, for an electric current (or voltage) to be produced in the wire, the magnetic field must be rotating or changing.
A screw Jack whose pitch is 2mm is used to raise a bus of mass 900kg through height of 20cm. The length of the Tommy of the Tommy of the jack is 40cm. Calculate the velocity ratio of the machine
R= 40cm —> R= 0.4 m
P= 2mm —> P= 0.002 m
[tex]V.R = \frac{2πR}{p} = \frac{2 \times 3.14 \times 0.4}{0.002} = 1256[/tex]
I think this is the answer
I hope I helped you
Good luck ^_^
A ball of mass 0.3 kg is released from rest at a height of 8 m. How fast is it going when it hits the ground? (Gravity being equal to 9.8)
Answer:
Explanation:
Mass doesn't matter here because when something is falling, gravity plays fairly; an elephant falls at the same rate of acceleration as does a feather. What DOES matter is everything pertinent to the y-dimension of free-fall:
a = -9.8 m/s/s
v₀ = 0 (since the ball was held before it was dropped)
v = ??
Δx = -8 m (negative because the ball drops this far below the point from which it was released).
Putting all this together in one equation:
v² = v₀² + 2aΔx and filling in this equation:
v² = (0)² + 2(-9.8)(-8) and
v² = 156.8 so
v = 12.5 which rounds to 13 if you're using 2 sig figs, and rounds to 10 if you're only using 1 (which you should be, according to the way the numbers have been given in this problem)
Two planets are separated by a distance of 4.5x108 m. One of the planets has a mass of 2.1x1021 kg. The force of attraction between the planets is 5x1024 N. What is the mass of the other planet? (Be careful with your algebra!)
Answer:
The mass of the other planet is 7.23*10^(30) kg
Explanation:
For two objects of masses m₁ and m₂ respectively, separated by a distance r, the gravitational force between them is given by:
F = G*(m₁*m₂)/r^2
Where G = 6.67*10^(-11) m^3/(kg*s^2)
Here, we know that:
r = 4.5*10^8m
m₁ = 2.1*10^21 kg
F = 5*10^24 N
And we want to find the mass of the other planet, first, let's isolate m₂ in the force equation:
(F*r^2)/(G*m₁) = m₂
Now we can replace all the values that we know in the left side, and solve it:
m₂ =[(5*10^24 N)*( 4.5*10^8m)^2]/[6.67*10^(-11) m^3/(kg*s^2)*2.1*10^21 kg]
m₂ = 7.23*10^(30) kg
The mass of the other planet is 7.23*10^(30) kg
The moon's mass is____
a 1.18 x 1011 kg
b 7.35 x 1022 kg
С 5.32 x 10kg
d 3.20 x 1018 kg
Answer:
7.35kg
Explanation:
Hope this is helpful :)
please help me with my question due tomorrow morning,
Answer:
D)7 1/2 or 15/2
Explanation:
Let's calculate Combined resistance of the parallel first
1/Rt= 1/2+1/6=4/6
Rt=6/4 which is also equal with 3/2
Now let's add it with the series one
Rt= 6+3/2
=15/2 And when we put that un a mixed fraction 7 1/2
a current of 6.0A runs through a circuit for 2.5 minutes how much change was delivered to this circuit
Answer:
900C
Explanation:
Change 2.5 mins to secs by multiplying by 60 which is 150secs
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1. Priya is responsible for collecting canned food along three different streets for her school's
annual Thanksgiving Food
Drive. She walks 300 m [N] along Oak Road, 500 m [E] along
Second Street, and then 150 m (S45°W) along Cross Ave. She completes the journey in 10
minutes
a. Draw a scale diagram of her trip.
b. Calculate her total distance, displacement, speed, and velocity.
Answer:
distance = 950 m
displacement = 439.2 m
speed= 1.58 m/s
velocity = 0.732 m/s
Explanation:
A = 300 m North
B = 500 m East
C = 150 m South west
Time, t = 10 minutes = 600 s
(A) The diagram is given below.
(B) Total distance = 300+ 500 + 150 = 950 m
[tex]A = 300 \widehat{j} \\\\B = 500\widehat{i}\\\\C = - 150 (cos 45 i+ sin 45 j) = - 106 \widehat{i} - 106 \widehat{j}\\\\D = A + B + C \\\\D = 394 \widehat{i} + 194 \widehat{j}\\\\D=\sqrt{394^2 +194^2} = 439.2 m[/tex]
Speed = distance / time = 950/600 = 1.58 m/s
velocity = 439.2 / 600 = 0.732 m/s
Calculate the gravitational force between two bodies of masses 10kg and 55kg, if they are placed at a distance of 2m apart.
Answer:
F = 9.177*10^-9N
Explanation:
Gravitational force between the two bodies is expressed as;
F = GMm/r²
Given tha
M = 55kg
m = 10kg
r = 2m
G = 6.67408 × 10-11 m³ kg-1 s-2
Substitute;
F = GMm/r²
F = 6.67408 × 10-11*55*10/2²
F = 3,670.744× 10-11/4
F = 9.177*10^-9N
The brakes in car A and car B stop working and they need to stop. Car A and car B have the same mass. Car A is traveling at 30 miles per hour, smashes into a big wall, and is brought to rest in a collision that lasts for a fraction of a second. Car B was also traveling at 30 mph but it drives out into a field of grasses and sand and finally comes to rest after a bumpy 20 second ride. Which car gets the larger impulse?
Answer:
Both have equal impulse.
Explanation:
Let the mass of cars be m.
Then the Force acting on each of them for taking them to state of rest:
(Using Newton's second law of motion)
[tex]F_A=\frac{m\times (0-30)}{\Delta t_A}[/tex]
[tex]F_A=-30\frac{m}{\Delta t_A}[/tex] ...................................(1) (negative sign is associated with direction, here we are concerned about the magnitude only)
[tex]F_B=\frac{m\times (0-30)}{\Delta t_B}[/tex]
[tex]F_B=-30\frac{m}{\Delta t_B}[/tex] ...................................(2)
[tex]\because \Delta t_A<\Delta t_B[/tex]
[tex]\therefore F_A>F_B[/tex]
We know that impulse is given as:
[tex]J=F\times \Delta t[/tex] ........................................(3)
So, from eq. (1), (2) & (3)
[tex]J_A=F_A\times \Delta t_A[/tex]
[tex]J_A=-30m[/tex]
&
[tex]J_B=F_B\times\Delta t_A[/tex]
[tex]J_B=-30m[/tex]
Hence both have equal impulse.
A car moves with the speed of 40 km/hr for the first half and 60 km/hr
for Second half distance "What is the average distance of cars.
Answer:
50 km/h
Explanation:
[tex](40 + 60) / 2[/tex]
-> [tex]50[/tex] (km/h)
Which of the following quantity is unit-less? 1 Specific gravity 2 Mass density 3 Acceleration due to gravity 4 All of the above
Answer:
1
Explanation:
Specific gravity is a ratio (of 2 densities) so it has no unit.
A train is travelling at 50 m s−1 when the driver applies the brakes and gives the train a constant deceleration of magnitude 0.50 m s−2 for 100 s. Describe what happens to the train. Calculate the distance travelled
Answer:
The strain will come to rest after traveling some distance.
distance traveled = 2500 m
Explanation:
The strain will come to rest after traveling some distance.
Applying,
s = ut+at²/2................... Equation 1
Given: u = initial velocity, a = deceleration, t = time, s = distance
From the question,
Given: u = 50 m/s, t = 100s, a = -0.5 m/s²(deceleration)
Substitute these values into equation 1
s = 50(100)+(-0.5)(100²)/2
s = 5000-2500
s = 2500 m
Hence the distance traveled is 2500 m
A toy rabbit of mass 0.15 kg is accelerated at 8 m/s2 by an angry toddler. Calculate the force exerted on the toy rabbit.
Answer:
1.2 N
Explanation:
Given that,
Mass (m) = 0.15 kgAcceleration (a) = 8 m/s²We are asked to calculate force exerted (F).
[tex]\longrightarrow[/tex] F = ma
[tex]\longrightarrow[/tex] F = (0.15 × 8) N
[tex]\longrightarrow[/tex] F = 1.2 N