How are deltas formed?

erosion of softer rock
connection of channels
deposition from flow into a lake or an ocean
creation of large, flat areas by flooding deposits

Answers

Answer 1

Answer:

It is created from deposition from flow into a lake or an ocean like the Missisippi delta

Explanation:

Answer 2

Answer:

C: deposition from flow into a lake or an ocean

Explanation:

deposition from rivers creates a variety of features, delta deposits created by flow into lake or ocean, is one of them.


Related Questions

Assuming an n-type transistor with Vds of 1.8V and Vt of 0.7V, find the ranges of Vgs to put the transistor in cutoff, linear, and saturation regions.

Answers

Answer:

1. Vgs<0.7

2. Vgs>2.5

3. 0.7<vgs<2.5

Explanation:

The information below was used to answer to answer this question.

Vds = 1.8V

Vt = 0.7V

1.

The cutoff region

Vgs < Vt

= Vgs < 0.7 volts

This the cut off region

2.

Linear region

Vds < Vgs - Vt

When we put in the values

1.8V < Vgs - 0.7V

1.8V+0.7V < Vgs

2.5Volts < Vgs

This is the linear region when Vgs > 2.5 volts

3.

The saturation region

Vds > Vgs - Vt

When we put in the values we have:

1.8V > Vgs - 0.7V

2.5V > Vgs

And 0.7 < Vgs

Then the saturation region is:

0.7V < Vgs < 2.5 V

6 A square silicon chip (k 150 W/m K) is of width w 5 mm on a side and of thickness t 1 mm. The chip is mounted in a substrate such that its side and back surfaces are insulated, while the front surface is exposed to a coolant. If 4 W are being dissipated in circuits mounted to the back surface of the chip, what is the steady-state temperature difference between back and front surfaces

Answers

Answer:

1.1⁰C

Explanation:

Width W = 5mm = 0.005

Thickness t = 1 mm = 0.001

K = thermal conductivity = 150W/m.K

P = q = heat transfer rate = 4W

We are to find the steady state temperature between the back and the front surface

We have to make these assumptions:

1. There is steady state conduction

2. The heat flow is of one dimension

3. The thermal conductivity is constant

4. The heat dissipation is uniform

We have:

∆t = t*P/k*W²

= (0.001m x 4W)/150x(0.005)²

= 0.004/0.00375

= 1.06667

This is approximately,

1.1⁰C

Thank you!

List 3 specific things you can do with a Tape measure (not just measure things)

Answers

see the inches on things.
how wide things could be and how long

Answer:

See how many inches are in a foot

measure width and hight of places

Nail grabbing

Explanation:

Alex loves to build things and wants to study robotics. He needs to get a job over the summer but the only one he can find is at a fast food restaurant. Does taking the job mean that Alex cannot pursue a career in robotics? Explain your answer.

Answers

Answer:

He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.

the fixed scale specifies 10.5 millimeters and the thimble specifies 30 hundredths of a mm. what is the total value shown by the micrometer when you add these readings together

Answers

Answer:

10.80 mm

Explanation:

Given that the reading of the fixed scale is : 10.5 mm

The thimble scale specifies : 0.30 mm

The micrometer reading will be : 10.5 + 0.30 =10.80 mm

List 3 specific things you can do with a screw gun (not just screw in screws)

Answers

Answer:

1: Attaching a fork and wip eggs/batter/ ect.

2: You can entertain a cat by putting yarn on the gun/drill

3: If you get yarn everywere, you can spin the yarn up on the drill/gun

Explanation:

I hope this helps you out somehow

Visual interpretations when driving are two things: first, what the driver sees around him or her passively, so it is what the eyes receive, and the second is:
Choose one
A. How the driver understands and processes the things his or her eyes receive.
B. How the driver disregards these things.
C. How the driver violates these things whenever he can.
D. How the driver appreciates all the colors he sees.

Answers

Answer:

A. How the driver understands and processes the things his or her eyes receive.

Explanation:

When driving, visual interpretation occurs in two things;

What the driver sees around him or her passively, mainly what is received by the eyeHow the driver understands and processes the things his or her eyes receive

Proper vision is vital while driving. There is the central vison and the peripheral vision. The central vision is what the driver sees in front through the windshield straight ahead. The Peripheral vision is what is seen at the corners of the eyes.

In driving, visual interpretations are important as it entails what the driver sees and A. How the driver understands and processes the things his or her eyes receive.

It's important for drivers to have proper vision when driving. A driver should be able to interpret what the driver sees around him or her passively.

Also, it's important for the drive to be able to understand and processes the things his or her eyes receive. This is vital in order to prevent accidents.

Learn more about driving on:

https://brainly.com/question/24606937

Technician A says that the refractometer reading is determined at the point of the scale where the dark and light areas meet. Technician B says that the reading is determined by where a dial points on a scale. Who is correct

Answers

Answer:

Technician B says that the reading is determined by where a dial points on a scale.

Explanation:

A refractometer is a devise used by scientists to gauge a liquids index of refraction.

The refractive index of a liquid is the ratio of light velocity of a specific wavelength in air to its velocity in the substance in evaluation.

The steps of reading a measurement are;

point the front of the refractometer towards the light source and view into the eyepieceYou will see the line outlined at a different point on the refractometer's internal indexRead the point on the index at which the line falls

Select four components of the drivetrain used in a large tractor. shaft drive O belt transmission O engine O clutch O final drive blade O chain​

Answers

Answer:

1

Explanation:

if citrus overlord is 200 (I'm offering for a lucid leaf) and shiny eternal contrast is 250, 450 so far and I'm also last thing offering for lucid (which is 100 secret value and I'm offering in shiny value and Lucid's shiny value is 500 but gets op's because it's a secret pet) is a shiny dark omen which is 100, I'm offering 550 for 500 but gets op's, w or l, I think w.

Answers

Answer: I'm pretty sure your taking a W.

your getting a W, lucid isn't that bad to trade, you can probably flip lucid for more shiny's and getting a better offer because omen has bad demand and you can tell someone to switch it for something better you can flip lucid and get better pets ok so accept and trade lucid unless you wanna keep it.

Explanation:

Answer:

gg's if you did it cause w

Explanation:

Need help tryna get a good grade

Answers

Answer:

C - Prototype model

Explanation:

I believe it's C but Hope this Helps!

C- Prototype Model should be the answer

this is it dont anwser this is for my other account

Answers

Answer:

thanks for the poiunts

Explanation:

What does abbreviation vom stand for

Answers

it’s Volt Ohm Meter!

Answer:

vom = Volt Ohm Meter

Explanation:

A plane stress state (2D) of material is defined by: [σ] = [800300300−400] (MPa). Define the principal stresses σ1, σ2 using:

• Determinant Method
• Mohr’s Circle (determine also ????max)

Answers

Answer:

Explanation:

Given that:

[tex][\sigma] = \left[\begin{array}{cc}800&300\\ \\300&-400\end{array}\right] (MPa)[/tex]

[tex][\sigma] = \left[\begin{array}{cc}\sigma_{xx}&\sigma_{xy}\\ \\\sigma_{yx}&\sigma_{yy}\end{array}\right][/tex]

Using Determinant method

The principal stress is the maximum or minimum normal stress acting on any plane. For the 2D stress system, the 2-principle plane always carries zero shear stress.

For principal stress [tex]( \sigma_1, \sigma_2)[/tex]

[tex]\sigma_{1,2} = \dfrac{\sigma_x+ \sigma_y}{2} \pm \sqrt{( \dfrac{\sigma_x - \sigma_y}{2} )^2 + \sigma^2_{xy}}[/tex]

[tex]\sigma_{1} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]

[tex]\sigma_{1} = \dfrac{400}{2} \pm \sqrt{ (600)^2 + (300)^2}[/tex]

[tex]\sigma_{1} = 200+ 670.82 \\ \\ \sigma_{1} = 870.82 \ MPa[/tex]

[tex]\sigma_{2} = \dfrac{800+(-400)}{2} \pm \sqrt{( \dfrac{800 -(-400)}{2} )^2 + (300)^2}[/tex]

[tex]\sigma_{2} = 200- 670.82 \\ \\ \sigma_{1} = - 470.82 \ MPa[/tex]

According to Mohr's circle;

Mohr's circle is the locus provided that the position of the normal stress and the shear stress is acting on any plane.

Center = (a,0)

[tex]a = \dfrac{\sigma_{x}+\sigma_{y}}{2}[/tex]

[tex]a = \dfrac{800+(-400)}{2}[/tex]

a = 200 MPa

radius (r) = [tex]\sqrt{ (\dfrac{\sigma_{x}-\sigma_{y}}{2})^2 + \sigma^2 _{xy}}[/tex]

[tex]=\sqrt{ (\dfrac{800-(-400)}{2})^2 + (300)^2}[/tex]

[tex]=\sqrt{ (600)^2 + (300)^2}[/tex]

r = 670.82 MPa

[tex]\sigma_1 = a +r \\ \\ \sigma_1 = 200 + 670.82 \\ \\ \sigma_1 = 870.82 \ MPa[/tex]

[tex]\sigma_2 =-(r-a)[/tex]      (it is negative because of the negative x-axis)

[tex]\sigma_2 =670.82 - 200 \\ \\ \sigma_1 = 470.82 \ MPa[/tex]    

[tex]\tau_{max} = radius \ of \ Mohr's \ circle[/tex]

[tex]\tau_{max} = 670.82 \ MPa[/tex]

Prepare 250 cm3 2M NAOH: molar mass M = 40g/mol. calculate substance mass​

Answers

Answer: The mass of the substance is 20 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml  = 250 ml   [tex](1cm^3=1ml)[/tex]

moles of [tex]NaOH[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{40g/mol}[/tex]

Now put all the given values in the formula of molality, we get

[tex]2=\frac{x\times 1000}{40\times 250}[/tex]

[tex]x=20g[/tex]

Therefore, the mass of the substance is 20 g

The gross weight of a two-place Piper Cherokee is 2000lb and its wing area is 160 ft^2. What is its wing loading

Answers

Answer:

[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]

[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]

Explanation:

Given

[tex]Weight=2000lb[/tex]

[tex]Area = 160ft^2[/tex]

Required

Determine the wing loading (W)

Wing loading is calculated using:

[tex]W = \frac{Weight}{Area}[/tex]

Substitute values for Weight and Area

[tex]W = \frac{2000lb}{160ft^2}[/tex]

[tex]W = 12.5\ lb/ft^2[/tex]

The answer can also be converted to N/m^2

[tex]1\ lb = 4.4482216153N[/tex]

[tex]1ft^2 = 0.092903m^2[/tex]

So, we have:

[tex]W = \frac{12.5 * 4.4482216153N}{0.092903m^2}[/tex]

[tex]W = \frac{55.6027701912N}{0.092903m^2}[/tex]

[tex]W = 598.503N/m^2[/tex]

Hence, the wing loading is:

[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]

[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]

Vacancy diffusion statement refer to that a mechanism that
atom at lattice traveled to a vacant latblèe
• True
• False

Answers

Answer:

true

Explanation:

What percentage is 122 out of 222?

Answers

Answer:

Divide the first number by the second.

Explanation:

~55%

Answer:

About 54-55% It depends on if you need to round.

Explanation:

A business owned by one people is a

Answers

Answer:

A sole proprietorship, also known as the sole trader, individual entrepreneurship or proprietorship, is a type of enterprise that is owned and run by one person and in which there is no legal distinction between the owner and the business entity.

Explanation:

Answer:

A business owned by one people is a-Sole proprietorship

Explanation:

This is correct i did it for my electives class which was career reaserch and decision making.

brainliest?

What are the environmental factors that cause the formation of rust?
Air
A Friction
B )Water
C )Iron Alloys
D )A, B and C
E )A, B, C and D
SP2
Copyright 2021 S/P2. All Rights Reserved.

Answers

Answer:

AirWaterIron Alloys

Explanation:

Rust is quite simply hydrated Iron oxide because it is as a result of iron allows coming into contact with oxygen(air) and water.

The resulting reaction gives off rust as a product. The chemical reaction is:

                                  4Fe + 3O₂ + 6H₂O → 4Fe(OH)₃.

You can see from above how rust is formed from Iron alloys, Oxygen and water.

As iron is a widely used components in the production of many things such as cars, rust presents a problem because in dissolving away iron, the object produced is compromised and this can lead to serious consequences if left unchecked.

(Giving Brainliest to 1st!)Which organelle acts as a temporary storage center, containing water, waste, and other products?
A. cell membrane
B. cytoplasm
C. vacuole
D. nucleus

Answers

I think it’s C but u could be wrong !

If a shear stress acts in one plane of an element, there must be an equal and opposite shear stress acting on a plane that is

Answers

Answer:

90 degrees

Explanation:

In the case when the sheer stress acts in the one plane of an element so it should be equal and opposite also the shear stress acted on a plan i.e. 90 degrees from the plane

Therefore as per the given situation it should be 90 degrees from the plane

hence, the same is to be considered and relevant too

90 becaus I’m the goat

A train starts from rest at station A and accelerates at 0.6 m/s^2 for 60 s. Afterwards it travels with a constant velocity for 25 min. It then decelerates at 1.2 m/s^2 until it is brought to rest at station B. Determine the distance between the stations.

Answers

Answer:

The distance between the station A and B will be:

[tex]x_{A-B}=55.620\: km[/tex]  

Explanation:

Let's find the distance that the train traveled during 60 seconds.

[tex]x_{1}=x_{0}+v_{0}t+0.5at^{2}[/tex]

We know that starts from rest (v(0)=0) and the acceleration is 0.6 m/s², so the distance will be:

[tex]x_{1}=\frac{1}{2}(0.6)(60)^{2}[/tex]

[tex]x_{1}=1080\: m[/tex]

Now, we need to find the distance after 25 min at a constant speed. To get it, we need to find the speed at the end of the first distance.

[tex]v_{1}=v_{0}+at[/tex]

[tex]v_{1}=(0.6)(60)=36\: m/s[/tex]

Then the second distance will be:

[tex]x_{2}=v_{1}*1500[/tex]

[tex]x_{2}=(36)(1500)=54000\: m[/tex]        

The final distance is calculated whit the decelerate value:

[tex]v_{f}^{2}=v_{1}^{2}-2ax_{3}[/tex]

The final velocity is zero because it rests at station B. The initial velocity will be v(1).

[tex]0=36^{2}-2(1.2)x_{3}[/tex]

[tex]x_{3}=\frac{36^{2}}{2(1.2)}[/tex]  

[tex]x_{3}=540\: m[/tex]

Therefore, the distance between the station A and B will be:

[tex]x_{A-B}=x_{1}+x_{2}+x_{3}[/tex]  

[tex]x_{A-B}=1080+54000+540=55.620\: km[/tex]  

I hope it helps you!

 

The displacement of a certain object is described by y(t) = 23 sin 5t, where t is measured in seconds. Compute its period and its oscillation frequency in rad/sec and in hertz

Answers

Answer:

5 rad/sec

0.796 Hz

1.256 seconds

Explanation:

Y(t) = 23sin5t ----1

Y(t) = aSin(w)t----2

w = 5 rad/sec

Then we get the Oscillation frequency from the formula below

w = 2πf

We make f to be the subject of this formula

f = w/2π

f = 5/2*3.24

f = 5/6.28

f = 0.796Hz

From the calculated frequency, we get the period = 1/f

= 1/0.796

= 1.256 seconds

The Jones family paid
$
253
in August for electricity. The September bill was
21
%
lower.

How much was the September bill?

Answers

Answer:

$199.87

Explanation:

Just take $253 times 0.21 to get $53.13. This is how much lower the bill was. Next take 253 - 53.13 to get 199.87, which is the total bill amount for September.

. Assuming an n-type transistor with Vds of 1.8V and Vt of 0.7V, find the ranges of Vgs to put the transistor in cutoff, linear, and saturation regions.

Answers

Answer:

1. Cut off region: Vgs < 0.7 volts

2. Linear region: Vgs > 2.5

3. Saturation region: 0.7 < Vgs < 2.5

Explanation:

This question has provided us with these details

Vds = 1.8V

Vt = 0.7V

1. To get The cutoff region

Vgs < Vt

Such that when we put in the value, we have:

Vgs < 0.7 volts

This gives us the cut off region

2. The we get the Linear region using this formula:

Vds < Vgs - Vt

After we put in the values;

1.8V < Vgs - 0.7V

Such that

1.8V + 0.7V < Vgs

2.5V < Vgs

This is therefore the linear region of the transistor when Vgs > 2.5 volts

3. We get The saturation region using

Vgs < Vt and

Vds > Vgs - Vt

When we put in the values we have:

Vgs < 0.7V and

1.8V > Vgs - 0.7V

1.8V+0.7V > Vgs

2.5V > Vgs

Then our saturation region would be

0.7V < Vgs < 2.5 V

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