hi, if your looking for extra points (50+) and br ainiest here is ur chance, answer this question correctly plz

Answer:

No

Explanation:

No, but the total mass of reactants must equal the total mass of products to be a balanced equation.

Example: Consider the following reaction ...

3H₂ + N₂ => 2NH₃ and 'amu' is atomic mass units (formula weights from periodic table)

In terms of molecules, there are 4 molecules on the left (3 molecular hydrogens (H₂) and 1 molecular nitrogen (N₂) and 2 molecules of ammonia on the right side of equation arrow. ∑reactant molecules ≠ ∑product molecules.

In terms of mass of reactants & mass of products, the 3H₂ + N₂ => 6amu + 28amu = 34amu & mass of products (2NH₃) => 2(14amu) + 6(1amu) = 34amu for sum of product masses.

∑mass reactants = ∑mass products <=> 34amu = 34amu.

The expression '∑mass reactants = ∑mass products' as applied to chemical equations is generally known as 'The Law of Mass Balance'.

Answer:

D group

................

Answer:

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

I've checked this multiple times this should be it

Answer:

C

Explanation:

is this one ok? XD

Answer:

71.1%. , is a fertilizer.

The total mass of the compound guanidine is 59 g/mo. It contains 3 nitrogen atoms. Hence, the percent composition of nitrogen in this fertilizer is 71.18 %.

The mass percent or percent composition of an element in a compound is the measure of amount of that element in 100 g of the compound. Thus, it is the ratio of mass of that element in the compound to the total mass multiplied by 100.

mass percent = mass of the element in the sample/ total mass × 100

The given compound is guanidine with the formula, HNC(NH2)₂ .

atomic mass of N = 14 g/mol

mass of carbon = 12 g/mol

hydrogen = 1 g/mol.

Then total mass of guanidine = 14 + 12 + 1 + 2(2 + 14) = 59 g/mol.

there are 3 nitrogen.

mass of three nitrogen = 42 g.

Then mass percent of N in guanidine = 42 g/ 59 g × 100= 71.1%.

Therefore, the percent by mass of nitrogen in guanidine is 71.18%.

Find more on mass percent:

https://brainly.com/question/9904990

#SPJ6

Explanation:

The balanced equation for the reaction is given as;

2NaOH + H2SO4 → Na2SO4 + 2H2O  

a. How many moles of sodium sulfate are produced if 13 g of sulfuric acid is used in the reaction?

From the reaction;

1 mol of H2SO4 produces 1 mol of Na2SO4

Converting 13g of sulphuric acid to mol;

Number of moles = Mass /  Molar mass

Number of moles = 13g / 98.0785 g/mol

Number of moles = 0.1325 mol

Since the mol ratio is 1: 1. This means

0.1325 mol of sodium sulfate would be formed.

b. How many molecules of water are produced if 2.0 g of sodium sulfate is produced in the above reaction?

From the reaction;

1 mol of Na2SO4 is produced alongside  2 mol of H2O

Converting 2g of sodium sulfate mol;

Number of moles = Mass /  Molar mass

Number of moles = 2g / 142.04 g/mol

Number of moles = 0.01408 mol

Since the mol ratio is 1: 2. This means

0.02816 mol of water would be formed.

1 mol of water = 6.022×10^23 molecules

0.02816 mol = x

Solving for x;

x = 1.696 ×10^22 molecules

c. What mass of sulfuric acid is required to completely react with 3.4 x 1024 formula units of sodium hydroxide?

From the reaction;

1 mol of H2SO4 reacts with 2 mol of NaOH

1 mol = 6.022×10^23 units

x mol = 3.4 x 10^24 units

Solving for x;

x = 5.646 mol of NaOH

Since the mole ratio is 1:2;

5.646 mol / 2 = 2.823 mol of sulphuric acid

Converting too mass;

Mass = Number of moles * Molar mass

Mass = 2.823 mol * 98.0785 g/mol

Mass = 276.88 g

Answer:

The answer to the question is true.

Answer:

Explanation:

no becuase everything goes in the mass shouldn't change unless you put extra

Answer:

D

Explanation:

Answer:

62.02 g/mol

62.03 g/mol

Explanation:

62.03 g/mol

The molar mass of H2CO3 is 62.02 g/mol

The molar mass of the compound is the sum of molar mass of indivitual atom multiple by number of that atom.

Calculation of molar mass of H2CO3 ,

Molar mass of H2CO3 =  Molar mass of H*2 +  Molar mass of C + Molar mass of O*3

Molar mass of H2CO3 = 1.0079*2 + 12.010 + 15.999*3

Molar mass of H2CO3 = 2.0158 + 12.010 + 47.997

Molar mass of H2CO3 = 62.02 g/mol

To learn more about  Molar mass here.

https://brainly.com/question/12127540

#SPJ3

Answer:

It can be verified since the information came from a government article. Or you could trust the magzine/general article if its from a well known article. Explanation:

you get the point, you can add on to this. I can't make it the best since im not in your class learning. Good luck

Answer:

A. 0.027 M

B. 0.0054 M

C. 31 cm³

Explanation:

A. Determination of the final concentration (Molarity)

Initial Volume (V₁) = 27 cm³

Initial concentration (C₁) = 0.150 M

Final volume (V₂) = 150 cm³

Final congratulation (C₂) =?

C₁V₁ = C₂V₂

0.150 × 27 = C₂ × 150

4.05 = C₂ × 150

Divide both side by 150

C₂ = 4.05 / 150

C₂ = 0.027 M

Thus, the final concentration of the solution is 0.027 M

B. Determination of the final concentration (Molarity)

Initial Volume (V₁) = 35.71 cm³

Initial concentration (C₁) = 0.0756 M

Final volume (V₂) = 500 cm³

Final congratulation (C₂) =?

C₁V₁ = C₂V₂

0.0756 × 35.71 = C₂ × 500

Divide both side by 500

C₂ = (0.0756 × 35.71) / 500

C₂ = 0.0054 M

Thus, the final concentration of the solution is 0.0054 M

C. Determination of the final volume.

Initial Volume (V₁) = 10 cm³

Initial concentration (C₁) = 0.155 M

Final congratulation (C₂) = 0.05 M

Final volume (V₂) =?

C₁V₁ = C₂V₂

0.155 × 10 = 0.05 × V₂

1.55 = 0.05 × V₂

Divide both side by 0.05

V₂ = 1.55 / 0.05

V₂ = 31 cm³

Thus, the final volume of the solution is 31 cm³

Answer:

It is possible not all of the water was evaporated from the sand, causing the recovered mass to be higher.

Explanation:

If not all the water is evaporated from the sand so the recovered mass to be higher than the sand from which more water is evaporated because evaporation of little amount of water causes less decrease in the recovered mass as compared to that sand from which more water is evaporated so more decrease occur in the recovered mass.

Answer:

It would be exactly 5.3586262014272155. But if you were to round it up it would be 5.35.

Answer:

its the last one

Explanation:

296 g BaBr₂

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 8.56 × 10²³ formula units BaBr₂

[Solve] grams BaBr₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Ba - 137.33 g/mol

[PT] Molar Mass of Br - 35.45 g/mol

Molar Mass of BaBr₂ - 137.33 + 2(35.45) = 208.23 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

295.99 g BaBr₂ ≈ 296 g BaBr₂

Thank you agenthammerx for helping me with this question!

Answer:

296 g BaBr₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets

Parenthesis

Exponents

Multiplication

Division

Addition

Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Moles

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 8.56 × 10²³ formula units BaBr₂

[Solve] grams BaBr₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Ba - 137.33 g/mol

[PT] Molar Mass of Br - 35.45 g/mol

Molar Mass of BaBr₂ - 137.33 + 2(35.45) = 208.23 g/mol

Step 3: Convert

[DA} Set up:                                                                                                      

[DA] Multiply/Divide [Cancel out units]:                                                          

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

295.99 g BaBr₂ ≈ 296 g BaBr₂

Answer:

N2O.

Explanation:

Hello there!

In this case, according to the Avogadro's number, we can compute the number of atoms, taking into account that CO2 has three moles of atoms, N2O has three moles of atoms, He one mole of atoms and CO two moles of atoms:

[tex]atoms_{CO_2}=1molCO_2*\frac{3*6.022x10^{23}atoms}{1molCO_2}=1.81x10^{24}atoms\\\\atoms_{N_2O}=3molN_2O*\frac{3*6.022x10^{23}atoms}{1molN_2O}=5.4x10^{24}atoms\\\\atoms_{He}=2molHe*\frac{1*6.022x10^{23}atoms}{1molHe}=1.2x10^{24}atoms\\\\atoms_{CO}=4molCO*\frac{2*6.022x10^{23}atoms}{1molCO}=4.82x10^{24}atoms[/tex]

Thus, we infer that 3 moles of N2O have the greatest number of atoms.

Answer:

x=2.

Explanation:

Hello there!

In this case, since we have a mole ratio of moles of Cl to moles of Cu as 2.39, it is possible to write the following:

[tex]\frac{2.39molCl}{1molCu}[/tex]

Thus, since the two possible copper chlorides are CuCl and CuCl₂, we can therefore infer that x=2 since it is close but not as close as it should to the whole number 2.

Best regards!

Answer:

its B

Explanation:

The earthquakes are occurring more in the land region of earth surface. Hence, the waves would arrive at point B before they arrived at point.

When two layers of the ground abruptly slide past one another, an earthquake results. The fault or fault plane is the area where they slide. The epicenter is the point on the earth's surface that is directly above the hypocenter, which is where the earthquake begins under the surface.

The energy that would typically force the blocks to move past one another is being saved up while the fault edges are glued together and the rest of the block is moving.

All that accumulated energy is released when the force of the sliding blocks ultimately displaces the resistance of the sharp edges of the fault and causes it to unstick. Like ripples on a pond, the energy radiates from the fracture in all directions as seismic waves. Therefore, point B in the land surface will first experience the seismic waves.

To find more on earthquakes, refer here:

https://brainly.com/question/29500066

#SPJ2

Answer:

1.239 * 10^8 Kg

Explanation:

Since all the electricity consumed comes from natural gas;

amount of electricity consumed = 700 * 300,000 = 2.1 * 10^8 kWh

So, amount of CO2 consumed is given by;

amount of electricity consumed * amount of CO2 per kWh

Hence,

Amount of CO2 = 2.1 * 10^8 kWh * 0.59 = 1.239 * 10^8 Kg

Answer:

A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms.

Explanation:

Answer:

A molecule is the smallest part of an element, sorry if im incorrect

Answer:

Explanation:

Lithium is in group 1 so there's 1 outermost shell electron.

Oxygen is in group 6 so there's 6 outermost shell electron.

To react lithium with oxygen, we need 2 lithium and 1 oxygen

Each lithium transfer 1 electron to the oxygen and oxygen gain 2 electrons.

[tex]Li_{2}O\\[/tex] formed.

If there's 4 lithium oxide, 4 molecules will be there.

If you mean how many ATOMS are there, there will be 3×4=12 atoms.

Answer:

1.  H₂SO₄  +  Na₂CO₃  ⇒  Na₂SO₄  +  H₂O  +  CO₂

sulfuric acid + sodium carbonate ⇒ sodium sulfate + water + carbon dioxide

2.  2 HCl  +  Mg(HCO₃)₂  ⇒  MgCl₂  +  2 H₂O  +  2 CO₂

hydrochloric acid + magnesium hydrogencarbonate ⇒ magnesium chloride + water + carbon dioxide

Explanation:

1.  Sulfuric acid is H₂SO₄.  Sodium carbonate is Na₂CO₃.

H₂SO₄  +  Na₂CO₃  ⇒  Na₂SO₄  +  H₂O  +  CO₂

sulfuric acid + sodium carbonate ⇒ sodium sulfate + water + carbon dioxide

2.  Hydrochloric acid is HCl.  Magnesium hydrogencarbonate is Mg(HCO₃)₂.

2 HCl  +  Mg(HCO₃)₂  ⇒  MgCl₂  +  2 H₂O  +  2 CO₂

hydrochloric acid + magnesium hydrogencarbonate ⇒ magnesium chloride + water + carbon dioxide

Answer:

an object is a rest upon a table

Answer:

Yes.

Explanation:

Yes, the change in cuvette lead to a determinate error in the analysis if the different cuvette is used for the analysis because the amount of liquid sample that is used has different volume. If both cuvette are of the same type and has no difference in their structure and size then there is error occurs in the analysis but if both cuvette are different from one another then the error will occur in the analysis. because the amount of liquid that is used has different volume.