Heptane (C7H16) is a hydrocarbon fuel used for gas barbecues. Balance the chemical equation (given below) for the reaction that occurs when heptane burns in air. What are the coefficients in the balanced equation

Answer:

[tex]m_w=439.2g[/tex]

Explanation:

Hello!

In this case, since the by-mass percent of a solution is a measure of the mass of the solute over the mass of the solution:

[tex]\%m/m=\frac{m_{solute}}{m_{solution}} *100\%[/tex]

As we know the mass of the solution and the by-mass percent, we can compute the mass of glucose in the 480 g of solution:

[tex]m_{solute}=\frac{\%m/m*m_{solution}}{100\%}[/tex]

Thus, by plugging in the data, we obtain:

[tex]m_{solute}=\frac{8.5\%*480g}{100\%}=40.8g[/tex]

Finally, since the solution is made up of glucose and water, we compute the mass of water as follows:

[tex]m_w=m_{sol}-m_{solute}=480g-40.8g\\\\m_w=439.2g[/tex]

Best regards!

Answer: C. Heat transfers thermal energy from the student's hand to the ice.

Explanation:  It seems confusing; b and c seem to be saying the same thing, but the definition of heat is the transfer of thermal energy from a warmer object to a colder object.

Answer:

3.15 V

Explanation:

Step 1: Write the balanced cell reaction

Co(s) + F₂(g) ⟶ Co²⁺(aq) + 2 F⁻(aq)

Step 2: Identify both half-reactions:

Cathode (reduction): F₂(g) + 2 e⁻ ⟶ 2 F⁻(aq)    E°red = 2.87 V

Anode (oxidation): Co(s) ⟶ Co²⁺(aq) + 2 e⁻      E°red = -0.28 V

Step 2: Calculate the standard cell potential

We will use the following expression.

E°cell = E°red,cathode - E°red,anode

E°cell = 2.87 V - (-0.28 V) = 3.15 V

Given E°cell > 0, the reaction is spontaneous.

Taking into account the definition of standard cell potential, E°cell has a value of 3.15 V.

The balanced cell reaction is:

Co(s) + F₂(g) ⟶ Co²⁺(aq) + 2 F⁻(aq)

First of all, it must be taken into account that oxidation is a reaction where an atom, ion or molecule loses electrons while reduction corresponds to the gain of electrons from an atom, ion or molecule.

Both oxidation and reduction depend on the change in the oxidation state of the atom, that is, on the difference in the charge of the atom in a reaction.

The oxidation and reduction reactions always occur simultaneously for what are generally known as oxidation-reduction reactions or redox reactions.

So, the anode corresponds to the negative electrode which normally oxidizes in the electrolytic chemical reaction while the cathode corresponds to the positive electrode which normally reduces its oxidation state when it receives electrons.

Si, in this case, the both half-reactions will be:

The potential of an Ecel cell is a measure of the difference in electronic energy between the two electrodes. The electronic energy of each electrode is related to the force with which the reaction occurs at the electrode-solution interface. The unit in which it is measured is the volt.

In electrochemistry, because a cell reaction is made up of two half-cell reactions, each of which has a characteristic electrode potential, the potentials measure the driving force of the two half-reactions.

The cell potential is obtained by subtracting the potentials of both half cells as shown below:

E°cell= Ecatode - Eanode

So, in this case, the Ecell is calculated as:

E°cell = 2.87 V - (-0.28 V) = 3.15 V

In summary, E°cell has a value of 3.15 V.

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Answer:

115 g/mol

Explanation:

Step 1: Given data

Step 2: Calculate the mass of the unknown metal deposited

An earring is plated in an electrolytic cell. The mass of the unknown metal deposited can be calculated using the following expression.

m = mf - mi

m = 3.953 g - 1.41 g

m = 2.54 g

Step 3: Calculate the molar mass (M) of the unknown metal

0.022 moles of the metal have a mass of 2.54 g. The molar mass of the metal is:

M = m/n

M = 2.54 g / 0.022 mol

M = 115 g/mol

Answer:

pH = 2.18

Explanation:

Perchloric acid (HClO₄) is a strong acid. This means that in an aqueous solution it completely dissociates into H⁺ and ClO₄⁻ species.

First we convert 249 mg HClO₄ into moles, using its molecular weight:

Because it is a strong acid, 2.49 mmol HClO₄ = 2.49 mmol H⁺

We calculate the molar concentration of H⁺:

Finally we calculate the pH of the solution:

Answer:

The easy way to do this is to assume the number of moles. Make it a number easily divided by both 2 and 3, so say 6. Now you can have numbers to plug in to Graham's Law to find the second rate, then use the second rate to find the time. Does that make sense?

Answer:

Chemical change

Explanation:

The rusting of iron/a nail is a chemical change

Iron (Fe) and Oxygen (O) combine to create the compound Iron Oxide (Fe2O3), which is rust.

Answer:

V₂ = 0.62 L

Explanation:

Given data:

Initial volume = 2.4 L

Initial temperature = 25°C

Final temperature = -196°C

Final volume = ?

Solution:

Initial temperature = 25°C (25+273 = 298 K)

Final temperature = -196°C ( -196+273 = 77 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 2.4 L × 77 K / 298 k

V₂ = 184.8 L.K / 298 K

V₂ = 0.62 L

Answer:

D. Compressibility​

Explanation:

Answer:

Nice pic there

Explanation:

No need

Answer:

See explanation

Explanation:

The crystal field theory assumes the interaction between the central metal ion and ligands to be purely electrostatic.

The five d orbitals remain degenerate until they are surrounded by ligands which split the degeneracy of the d orbitals depending on the crystal fields formed to give either square planar, octahedral, tetrahedral or other kinds of crystal fields.

The electronic configuration of Cu II ion is 1s2 2s2 2p6 3s2 3p6 3d9. Its colour arises from an incomplete d orbital which makes d - d electron transition possible.

On the other hand, the electron configuration of copper I is  1s2 2s2 2p6 3s2 3p6 3d10. We can see that the d orbital is completely filled. Hence copper I ion has no color due to its completely filled d- orbitals

Answer:

a) an opposing force act on it

i hope its true

Answer:

dichlorine trioxide

Explanation:

di-2 tri-3 there are three oxygens and two chlorines.

Answer:

Dichlorine Trioxide

Explanation:

The molar mass and molecular weight of Cl2O3 is 118.904.

Answer:

Two.

Explanation:

Hello!

In this case, considering the attached picture wherein you can see the presence of the parent chain as aniline, we can see radicals at the nitrogen, named by N-ethyl and N-methyl which are the present alkyl substituents. In such a way, the benzene ring is not considered an alkyl radical because it belongs to the parent chain on aniline and therefore, N-ethyl-N-methylaniline has two alkyl substituents.

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There are two alkyl substituents attached to the nitrogen; one ethyl and one methyl group

Aniline consists of a benzene ring to which an -NH2 moiety is attached. Usually, it is possible for the any of the two hydrogen atoms in the -NH2 moiety to become substituted leading to N-alkylated product.

In the compound N-ethyl-N-methylaniline, there are two alkyl substituents attached to the nitrogen; one ethyl and one methyl group as shown in the image attached to this answer.

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Answer:

it becomes a negstive charge

Answer:

New molarity = M₂ = 0.167 M

Explanation:

Given data:

New molarity = M₂ = ?

Final volume = V₂ = 100mL + 20 mL = 120 mL

Initial volume =M₁ =  100 mL

Initial molarity =V₁ = 0.2 M

Solution:

M₁V₁       =    M₂V₂

0.2 M × 100 mL = M₂ × 100 mL

M₂ = 0.2 M × 100 mL/120 mL

M₂ = 20 M.mL/120 mL

M₂ = 0.167 M

Answer:

The London dispersion force is the weakest intermolecular force. The London dispersion force is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.

Answer:

An example of the thermal energy of a substance being decreased is with our food. With the thermal energy of food being decreased it is easier for foods to be eaten comfortably without any damage to the tongue or alimentary canal.

Another good example is in the handling of hot objects in the home. Thermal energy decrease in objects such as iron, pots etc helps to prevent serious burns and injuries.

Answer:

Water turning into ice

juice frozen to make popsicles

Explanation:

When something goes from liquid to a solid, that is a process called freezing. When a object loses thermal energy the particles move slower forming a solid.

The question is incomplete, the complete question is;

The heat of vaporization ΔHv of acetic acid HCH3CO2 is 41.0 /kJmol. Calculate the change in entropy ΔS when 954.g of acetic acid condenses at 118.1°C. Be sure your answer contains a unit symbol. Round your answer to 3 significant digits.

Answer:

-1.67 JK-1

Explanation:

Since Heat of vaporization of acetic acid = 41.0 kJ/mol

Therefore:

Heat of condensation of acetic acid = -41.0 kJ/mol

Mass of acetic acid = 954 g

Temperature of condensation = 118.1 °C or 391.1 K

Number of moles of acetic acid = 954 g/60g/mol = 15.9 moles

Heat evolved during condensation = 15.9 moles *  -41.0 kJ/mol = -651.9 KJ

Entropy change (ΔS) = Heat evolved/ Temperature = -651.9 KJ/391.1 K

Entropy change (ΔS) = -1.67 JK-1

Answer:

Explanation:

after solving this u can find the answer in easy way

11.12 grams of sodium chloride is required to prepare 380 mL of 0.500 M NaCl (MW = 58.5 g/mol).

HOW TO CALCULATE MASS:

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Answer:

Oxygen

Explanation:

Atomic radius trend

-decreases from left to right

-increases from top to bottom

Tungsten is in period 7, which has a larger atomic radius

Oxygen is in period 2, which is in a lower energy level and is on the right side. Therefore, has a smaller atomic radius.

Answer:

Work done W = -382,206 J (Approx)

Explanation:

We know that;

1 atm = 101.32 kPa

1 L-atm = 101.325 J

1 m³ = 1,000 L

Computation:

Work done W = -P∆V

Pressure = 196 kPa × (1 / 101.32 kPa)

Pressure = 1.9344 atm

∆V = 1.95 × (1000 L) = 1,950 L

So,

W = -(1.9344 atm) × (1,950 L)

W = -3772.0 L-atm

Work done W = -3772.0 L-atm × (101.325 J / 1 L.atm)

Work done W = -382,206 J (Approx)

The work done by the gas in Joules is equal to 3,763.5‬ Joules.

Given the following data:

Conversion:

1 atm = 101.325

X atm = 196.0 kPa

X = [tex]\frac{196.0}{101.325} = 1.93\; atm[/tex]

Conversion:

1 [tex]m^3[/tex] = 1000 Liter

1.95 [tex]m^3[/tex] = 1950 Liter

To calculate the work done by the gas in Joules:

Mathematically, the work energy by a system is given by the formula:

[tex]Work = P \delta V[/tex]

Where:

Substituting the parameters into the formula, we have

[tex]Work\;energy = 1.93 \times 1950[/tex]

Work energy = 3,763.5‬ Joules.

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Atom, smallest unit into which matter can be divided without the release of electrically charged particles. It also is the smallest unit of matter that has the characteristic properties of a chemical element. As such, the atom is the basic building block of chemistry.

Answer:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another.

Explanation:

This means that a system always has the same amount of energy unless it's added from the outside. is the total internal energy of a system.