Answer:
A. $7.00
Step-by-step explanation:
$82-$75=$7.00
. A small home business is set up with an investment of Birr 1,000,000 for equipment. The business manufactures a product at a cost of Birr 60 per unit. If the product sells for Birr 140, how many units must be sold before the business breaks even?
Answer:
12,500
Step-by-step explanation:
P = R-E
b.e.p : P=0
R=E
140x = 1000000 + 60 x
80x = 1000000
x=12,500
if a=(1 2 3 4) find A×A and the relation determined by (I) y=2x (II) x+y
Answer:
HOPE IT HELPS PLZ MARK ME BRAINLIEST
Step-by-step explanation:
A={1,2,3,4,5,6}
R={(x,y):y is divisible by x}
We know that any number (x) is divisible by itself.
(x,x)∈R
∴R is reflexive.
Now,(2,4)∈R [as 4 is divisible by 2]
But,(4,2)∈ /
R. [as 2 is not divisible by 4]
∴R is not symmetric.
Let (x,y),(y,z)∈R. Then, y is divisible by x and z is divisible by y.
∴z is divisible by x.
⇒(x,z)∈R
∴R is transitive.
Hence, R is reflexive and transitive but not symmetric.
Hannah would like to make an investment that will turn 8000 dollars into 33000 dollars in 7 years. What quarterly rate of interest, compounded four times per year, must she receive to reach her goal?
Answer:
20.76%
Step-by-step explanation:
[tex]33000=8000(1+\frac{i}{4})^{4*7}\\4.125=(1+\frac{i}{4})^{28}\\\sqrt[28]{4.125}=1+\frac{i}{4} \\i= .207648169[/tex]
which rounds to 20.76%
Answer:
About 0.2076 or 20.76%.
Step-by-step explanation:
Recall that compound interest is given by the formula:
[tex]\displaystyle A=P\left(1+\frac{r}{n}\right)^{nt}[/tex]
Where A is the final amount, P is the principal, r is the interest rate, n is the number of times the interest is applied per year, and t is the number of years.
Since Hannah wants to turn an $8,000 investment into $33,000 in seven years compounded quarterly, we want to solve for r given that P = 8000, A = 33000, n = 4, and t = 7. Substitute:
[tex]\displaystyle \left(33000\right)=\left(8000\right)\left(1+\frac{r}{4}\right)^{(4)(7)}[/tex]
Simplify and divide both sides by 8000:
[tex]\displaystyle \frac{33}{8}=\left(1+\frac{r}{4}\right)^{28}[/tex]
Raise both sides to the 1/28th power:
[tex]\displaystyle \left(\frac{33}{8}\right)^{{}^{1}\! / \! {}_{28}}= 1+\frac{r}{4}[/tex]
Solve for r. Hence:
[tex]\displaystyle r= 4\left(\left(\frac{33}{8}\right)^{{}^{1}\! / \! {}_{28}}-1\right)[/tex]
Use a calculator. Hence:
[tex]r=0.2076...\approx 0.2076[/tex]
So, the quarterly rate of interest must be 0.2076, or about 20.76%.
Question 4
Which term in the sequence given by n th term formula 7n - 50 has a value of 41?
th term
Answer:
13th term
Step-by-step explanation:
41 = 7n - 50
41 + 50 = 7n
91 = 7n
7n = 91
n = 91/7
n = 13
13th term has value 41
Answer:
n = 13
Step-by-step explanation:
7n - 50 = 41
Add 50 to both sides
7n = 41 + 50
7n = 91
Divide both sides by 7
n = 91/7
n = 13
Anthony had to travel 24 miles north and then 7 miles west. Find the shortest distance between the starting and the end points.
30 miles
36 miles
25 miles
39 miles
Will give brainliest.
Answer: Assuming there isnt a fourth answer, the answer is the second choice.
Step-by-step explanation: Point A is located in the first quadrant, Point B is located at 3, -1/2 and Point C is reflected off the y axis, in the second choice.
In the Cash Now lottery game there are 20 finalists who submitted entry tickets on time. From these 20 tickets, three grand prize winners will be drawn. The first prize is one million dollars, the second prize is one hundred thousand dollars, and the third prize is ten thousand dollars. Determine the total number of different ways in which the winners can be drawn. (Assume that the tickets are not replaced after they are drawn.)
If there is a 90% chance of rain tomorrow and a 70% chance of wind and rain,
what is the probability that it is windy, given that it is rainy? Round your
answer to the nearest percent.
Answer:
78%
Step-by-step explanation:
the chance of rain
P(R) = 0.9
the chance of wind and rain
P(R∩ W) = 0.7
The probabilities of windy weather is
P(W) = [tex]\frac{P(RW)}{P(R)} =\frac{0.7}{0.9} =0.78[/tex]
The correct answer is B) 78%
What does point b represent on the graph ?
Answer:
Step-by-step B represents the $14 John earned in the 2 hours he worked.
explanation:
Find m∠GHIm∠GHI if m∠GHI=14x+6m∠GHI=14x+6, m∠QHI=130∘m∠QHI=130∘, and m∠GHQ=3x−3m∠GHQ=3x−3.
Answer:
m∠GHI = 160
Step-by-step explanation:
From the question given above, the following data were obtained:
m∠GHI = 14x + 6
m∠QHI = 130°
m∠GHQ = 3x – 3
m∠GHI =?
Next, we shall determine the value of x. This can be obtained as follow:
m∠GHI = m∠QHI + m∠GHQ
14x + 6 = 130 + (3x – 3)
14x + 6 = 130 + 3x – 3
Collect like terms
14x – 3x = 130 – 3 – 6
11x = 121
Divide both side by 11
x = 121 / 11
x = 11
Finally, we shall determine the value m∠GHI. This can be obtained as follow:
m∠GHI = 14x + 6
x = 11
m∠GHI = 14(11) + 6
m∠GHI = 154 + 6
m∠GHI = 160
25 x 2
help me
plz understand me by opening
Answer:
[tex]25 \times 2 = 50 \\ you \: are \: idiot \: [/tex]
really?! :|
Lost-time accidents occur in a company at a mean rate of 0.4 per day. What is the probability that the number of lost-time accidents occurring over a period of 9 days will be no more than 5
Answer:
0.8441
Step-by-step explanation:
This question can be solved by using the microsoft excel command.
we start off by solvingfor the mean rate for 9 days
mean rate = 0.4
for 9 days = 0.4*9 = 3.6
using the excel command,
POISSON (5, 3.6, TRUE)
p(x≤ 5) = 0.8441
so in conclusion 0.8441 is the probability that lost time accidents over 9 days would not be greater than 5.
the attachment is an excel sheet showing the input and the result.
The explicit rule for a sequence and one of the specific terms is given. Find the position of the given term.
f(n) = 3.75n − 27.5; 25
Step 1 out of 2:
You know that the value of f(n) is 25. Substitute 25 for f(n) in f(n) = 3.75n − 27.5.
25 = 3.75n − 27.5
= 3.75n
Answer:
14
Step-by-step explanation:
Given :
f(n) = 3.75n − 27.5
f(n) = 25
Put f(n) = 25 in the equation :
25 = 3.75n - 27.5
25 + 27.5 = 3.75n
52.5 = 3.75n
52.5 / 3 75 = n
14 = n
The position of the term is 14
According to the graph above, College R showed
the greatest change in enrollment between which
two decades?
Given:
The graph that shows the ennoblement for college R between 1950 and 2000.
To find:
The two decades that has the greatest change in enrollment.
Solution:
From the given graph, it is clear that the change in the enrollment is:
From 1950 to 1960 is [tex]4-3.5=0.5[/tex] thousand.
From 1960 to 1970 is [tex]5-4.5=1.5[/tex] thousand.
From 1970 to 1980 is [tex]5.5-5=0.5[/tex] thousand.
From 1980 to 1990 is [tex]6.5-5.5=1[/tex] thousand.
From 1990 to 2000 is [tex]7-6.5=0.5[/tex] thousand.
The two decades 1960-1970 and 1980-1990 have the greatest change in enrollment.
Answer:1980 to 1990
Step-by-step explanation:
I WILL GIVE BRAINLIEST FAST
TRUE OR FALSE?
The triangles shown below must be congruent
B is the answer.
The triangles doesnt creates a SSS,SAS,SAA, scenario.
This triangle isn't ASA because the triangles share the same side but it have different angles that include the side.
It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles. Find its designed life if a .97 reliability is desired.
Answer:
The designed life should be of 21,840 vehicle miles.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.
This means that [tex]\mu = 35000, \sigma = 7000[/tex]
Find its designed life if a .97 reliability is desired.
The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-1.88 = \frac{X - 35000}{7000}[/tex]
[tex]X - 35000 = -1.88*7000[/tex]
[tex]X = 21840[/tex]
The designed life should be of 21,840 vehicle miles.
"1. A z-score of zero always means
a.
the raw score does not exist.
b.
the raw score exists, but is negligible.
c.
the raw score almost never occurs.
d.
the raw score is equal to the mean."
Answer:
d.
Step-by-step explanation:
Here is an answer I found on the internet (kudos to investopedia.com)
If a Z-score is 0, it indicates that the data point's score is identical to the mean score.
In other words, it's saying that a z-score of zero has a standard deviation of zero.
Im asking a question because yes
+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+
ANSWER WITH A, B, C, OR D.
A fruit stand has to decide what to charge for their produce. They need $10 for 4 apples and 4 oranges. They also need $12 for 6 apples and 6 oranges. We put this information into a system of linear equations.
Can we find a unique price for an apple and an orange?
Choose 1 answer:
A
Yes; they should charge $1.00 for an apple and $1.50 for an orange.
B
Yes; they should charge $1.00 for an apple and $1.00 for an orange.
C
No; the system has many solutions.
D
No; the system has no solution.
Answer:
I believe the answer would be A!
Step-by-step explanation:
If you need $10 total, then charging $1 for 4 apples would get you $4, and charging $1.50 for 4 oranges would get you $6, totaling $10!
Find the angle between the vectors ????=????+???? and ????=−????+????. (Give an exact answer. Use symbolic notation and fractions where needed.)
Answer:
The angle between them is 60 degrees
Step-by-step explanation:
Given
[tex]a = 2i + j -3k[/tex]
[tex]b = 3i - 2j -k[/tex]
Required
The angle between them
The cosine of the angle between them is:
[tex]\cos(\theta) = \frac{a\cdot b}{|a|\cdot |b|}[/tex]
First, calculate a.b
[tex]a \cdot b =(2i + j -3k) \cdot (3i - 2j -k)[/tex]
Multiply the coefficients of like terms
[tex]a \cdot b =2 * 3 - 1 * 2 - 3 * -1[/tex]
[tex]a \cdot b =7[/tex]
Next, calculate |a| and |b|
[tex]|a| = \sqrt{2^2 + 1^2 + (-3)^2[/tex]
[tex]|a| = \sqrt{14[/tex]
[tex]|b| = \sqrt{3^2 + (-2)^2 + (-1)^2}[/tex]
[tex]|b| = \sqrt{14}[/tex]
Recall that:
[tex]\cos(\theta) = \frac{a\cdot b}{|a|\cdot |b|}[/tex]
This gives:
[tex]\cos(\theta) = \frac{7}{\sqrt{14} * \sqrt{14}}[/tex]
[tex]\cos(\theta) = \frac{7}{14}[/tex]
[tex]\cos(\theta) = 0.5[/tex]
Take arccos of both sides
[tex]\theta =\cos^{-1}(0.5)[/tex]
[tex]\theta =60^o[/tex]
Multiply 25 x 47 x 3
You are charged $9.33 total for a meal, assume the 7% sales tax, how much was the menu price of this item?
I have already tried
$8.68
$8.71
$8.67
all were wrong
Answer:
$8.71.
Step-by-step explanation:
Given that you are charged $ 9.33 total for a meal, assuming the 7% sales tax, to determine how much was the menu price of this item, the following calculation must be performed:
100 + 7 = 107
107 = 9.33
100 = X
100 x 9.33 / 107 = X
933/107 = X
8.71 = X
Therefore, the menu price of this item was $ 8.71.
rank the three fractions from smallest to largest? and why
2/7, 4/14, 8/11
Answer:
2/7 = 4/14 so from smallest to largest the fractions are:
2/7 4/14 and 8/11
Step-by-step explanation:
What is the circumference of the given circle in terms of [tex]\pi[/tex]?
a. 14[tex]\pi[/tex] in.
b. 28[tex]\pi[/tex] in.
c. 42[tex]\pi[/tex] in.
d. 196[tex]\pi[/tex] in.
Answer:
b. 28[tex]\pi[/tex] in.
Step-by-step explanation:
circumference of a circle = 2 [tex]\pi[/tex] r
whrere r is the radius of rhe circle
= 2 × [tex]\pi[/tex] × 14 in.
= 28 [tex]\pi[/tex] in.
that is option b
We have to find,
The circumference of the given circle in terms of the π.
The formula we use,
→ C = 2πr
Then we can find the circumference,
→ 2 × π × r
→ 2 × π × 14
→ 28π in.
Hence, option (b) is correct answer.
The half life of carbon 14 is 5,730 year suppose a fossil found with 20 percent as much of its carbon 14 as compared to a living sample how old is the fossil
3,235 years
32,346 years
1331 years
13,307 years
13,305 years
Step-by-step explanation:
[tex]A = A_02^{-\frac{t}{5730}}[/tex]
Since only 20% of the original C-14 is left, then [tex]A=0.2A_0[/tex]. We can then write
[tex]0.2A_0=A_02^{-\frac{t}{5730}}[/tex]
Taking the log of both sides,
[tex]\log 0.2 = \left(-\dfrac{t}{5730}\right)\log 2[/tex]
Solving for t,
[tex]t = \dfrac{-(5730\:\text{years})\log 0.2}{\log 2}[/tex]
[tex]\:\:\:\:\:\:\:= 13,305\:\text{years}[/tex]
What type of line is PQ⎯⎯⎯⎯⎯⎯⎯⎯?
Answer:
median
Step-by-step explanation:
Q is at the midpoint of RS and so PQ is a median
A median is a segment from a vertex to the midpoint of the opposite side.
We want to define what type of line is PQ (the line that passes through points P and Q) by looking at the given image, one can easily see that the line PQ is a median, now let's explain why.
First, let's analyze the image:
In the image, we can see that P is one vertex of the triangle, and Q is the midpoint of the segment RS (you can see that RQ = 4 and QS = 4) , where R and S are the other two vertexes of the triangle.
Particularly, we can define a median of a triangle as the line that passes through the midpoint of one side of the triangle and by the vertex that does not belong to that side.
With that definition, we can see that PQ is a median because Q is the midpoint of one side of the triangle and P is the vertex that does not belong to that side.
If you want to learn more, you can read:
https://brainly.com/question/2272632
What is the HCF of 1280 and 630
Given:
The two numbers are 1280 and 630.
To find:
The HCF of the given numbers.
Solution:
First write the given numbers in prime factorization form.
[tex]1280=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 5[/tex]
[tex]630=2\cdot 3\cdot 3\cdot 5\cdot 7[/tex]
Now the product of all the common prime factors is known as the HCF of 1280 and 630.
[tex]HCF=2\cdot 5[/tex]
[tex]HCF=10[/tex]
Therefore, the HCF of 1280 and 630 is 10.
Need the answers from a - e
Answer:
10
Step-by-step explanation:
Sorry. I needed to answer this question to get access.
Suppose the figure KLMN is dilated using a scale factor of 1/3 with the center of dilation at the origin. Which are the ordered pairs for the image?
1. K’(-1,3), L’(-3,0), M’(⅔, -8/3), N’(2, 4/3)
2. K’(-9,27), L’(-27,0), M’(6, -24), N’(18, 12)
3. K’(0,6), L’(-6,-3), M’(-1, -5), N’(3, 1)
4. K’(3,-1), L’(0,-3), M’(-8/3, ⅔), N’(4/3,2)
Answer:
K’(-1,3), L’(-3,0), M’(⅔, -8/3), N’(2, 4/3)
Step-by-step explanation:
In the diagram, DG ∥ EF.
On a coordinate plane, quadrilateral D E F G is shown. Point D is at (negative 2, 2), point G is at (1, 2), point F is at (3, negative 3), and point E is at (negative 4, negative 3).
What additional information would prove that DEFG is an isosceles trapezoid?
DE ≅ GF
DE ≅ DG
EF ≅ DG
EF ≅ GF
Answer:
[tex]DE \cong GF[/tex]
Step-by-step explanation:
Given
See attachment for quadrilateral
Required
What proves DEFG as isosceles trapezoid
The non-parallel sides of an isosceles trapezoid are similar and equal.
From the attached quadrilateral, the non-parallel sides are: DE and GF
Hence, for DEFG to be an isosceles trapezoid;
[tex]DE \cong GF[/tex]
Answer:DE ≅ GF
Step-by-step explanation:
cause i said so
A researcher designs an experiment by manipulating the following variables: temperature (low or high), illumination level (low or high), and time of testing (day or night). For a repeated measures design, how many participants would the researcher require in order to have 10 participants per condition?
Answer:
10
Step-by-step explanation:
As it could be inferred from the name, repeated measure design may be explained as experimental measures involving multiple (more than one) measures of a variable on the same observation, subject or participants which are taken at either various times or periodic intervals, different levels, different conditions. Hence, a repeated measurement taken with the same sample but under different treatment conditions. Therefore, since the measurement will be performed on a the same subjects(paired) , then the number of subjects needed will be 10. As it is this same samples that will be used for the other levels or conditions.