Helpppppp pleaseeeee with 16

Answer:

Air masses are also identified based on whether they form over land or over water. Maritime air masses form over water and are humid. Continental air masses form over land and are dry. ... One that forms over the Indian Ocean is called a maritime tropical air mass and is warm and humid

The type of air mass that forms in an area is determined by the location and nature of the water and land.

Air mass may be characterized as a huge volume of air that is present in the atmosphere which possesses a uniform temperature and moisture. This attribute is generally classified on the basis of latitude and continental or maritime source regions.

For example, Maritime air masses construct over water and are significantly humid. While continental air masses construct over land and are significantly dry. That is why air masses are characterized by the temperature and humidity of the given region.

Therefore, the type of air mass that forms in an area is determined by the location and nature of the water and land along with the temperature and humidity of the given region.

To learn more about Air masses, refer to the link:

https://brainly.com/question/18201898

#SPJ6

Answer:

b

Explanation:

I did this quiz and i think a got it right i also looked up my answer to make sure it was right good luck on quiz :)

1.83 × 10⁻⁷ mol Au

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

3.60 × 10⁻⁵ g Au (Gold)

Step 2: Identify Conversions

Molar Mass of Au - 196.97 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

Answer:

14 days.

Explanation:

If today were October 7 and we observed a waxing gibbous moon, that is, a moon with an illumination greater than a first quarter but less than a full moon, we would have to wait 14 days to see a waning crescent moon, which would be a moon with a visibility less than the last quarter but greater than a new moon.

Answer:

[tex]\boxed {\boxed {\sf 856.8648 \ grams \ of \ K_2CO_3}}[/tex]

Explanation:

To convert from moles to grams, we must find the molar mass.

1. Molar Mass

First, identify the elements in the compound. K₂CO₃ It has potassium, carbon, and oxygen. Find these elements and their masses on the Periodic Table.

Note the subscript of 2 after K and 3 after O. We must multiply oxygen's molar mass by 2, then oxygen's by 3, and add carbon.

2. Convert Moles to Grams

Use the molar mass as a fraction.

[tex]\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}[/tex]

Multiply by the given number of moles: 6.2

[tex]6.2 \ mol \ K_2CO_3 *\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}[/tex]

[tex]6.2 *\frac {138.204 \ g \ K_2CO_3}{1 }[/tex]

[tex]6.2 * {138.204 \ g \ K_2CO_3}[/tex]

[tex]856.8648 \ g \ K_2CO_3[/tex]

There are 856.8648 grams of potassium carbonate in 6.2 moles.

Answer:

dominant and recessive

Explanation:

Answer:

gains 2 electrons. In order for the new ionic compound to form a a neutral compound, the oxygens must gain 6 electrons

Answer:

C

Explanation:

because you got to share

Answer:

1=a 2=d i think

Explanation:

Answer:

Yes, because it follows the octet rule.

Explanation:

The Lewis is correct

because it follows the octet rule.

And

The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas.

Answer: The enantiomeric excess ee is 50%

Explanation:

Given that;

compound A = 75%, B = 25%

ee = ?

so

ee = [( A - B) / ( A + B)] × 100

= [( 75 - 25) / ( 75 + 25)] × 100

= [50 / 100] × 100

= 0.5 × 100

= 50%

Therefore enantiomeric excess ee is 50%

Answer:

5.61 * 10²¹ molecules

Explanation:

You have 1.25 g of malic acid, C4H.Os, an acid found in apples and other fruits. How many molecules of the acid do you have?

Solution:

A molecule is the group of two or more atoms held together by chemical bonds.

The number of molecules is calculated using the formula:

number of molecules in a substance = number of moles of substance * Avogadro constant

Avogadro constant = 6.02 * 10²³ mol⁻¹

number of moles = mass / molar mass

Given that mass = 1.25 g

molar mass of malic acid (C₄H₆O₅) = (12 * 4) + (1 * 6) + (16 * 5) = 48 + 6 + 80 = 134 g/mol

number of moles = mass / molar mass = 1.25 g / 134 g/mol = 0.0093 mol

Recall that: number of molecules in a substance = number of moles of substance * Avogadro constant

number of molecules in a substance = 0.0093 mol * 6.02 * 10²³ mol⁻¹ = 5.61 * 10²¹ molecules