Answer:
its b.
Explanation:
One isotope of Carbon(C) has exactly the same mass number and atomic mass since it was used as the definition of the atomic mass unit. Which isotope is it and what is it’s atomic mass?
How much energy was absorbed by the water?
Explanation:
a homogeneous is a mixture
Answer:
True
Explanation:
A homogeneous mixture is simply any mixture that is uniform in composition throughout. As long as each substance is mixed in enough to be indistinguishable from the others, it is a homogeneous mixture.
For the reaction 4 K + 2S ⇒2[tex]_{2}[/tex]S, How many atoms of sulfur will react with 52 atoms of K?
Please! Show your work!
Answer:
~26 atoms of sulfur
Explanation:
When working problems involving equations I find it helpful to works through moles because it relates to the coefficients of balanced equation by linear ratio. In other words, convert data to moles, solve by ratio and convert results to desired dimensions. In this case Atoms of Sulfur.
Given: 52 atoms K = 52 atoms/6.02 x 10²³atoms K/mole K = 9.64 x 10⁻²³ mole K atoms.
Using ratios in given equation 4K + 2S => 2K₂S
Says
4 moles K reacts with 2 moles Sulfur, then
8.64 x 10⁻²³ mole K reacts with X moles Sulfur
Set up ratio:
(4 moles K) / (8.64 x 10⁻²³ moles K) = (2 moles S) / X
Solve for X => X = (2 moles S x 8.64 x 10⁻²³ mole K) / 4 mole K = 4.32 x 10⁻²³ mole S used
Converting moles S to atoms S, multiply by Avogadro's Number ...
Atoms S used = 4.32 x 10⁻²³ mole S used x 6.02 x 10²³ Atoms S / mole S
=> 26.0064 Atoms S ≈ 26 Atoms Sulfur used.
Note: This is a reasonable answer in that the balanced equation given indicates that half the number moles S reacts with K. So, one can conclude that half the number of potassium atoms would indicate the number of sulfur atoms needed. test => ¹/₂(52) = 26 atoms S.
The elwments in group 17 of the periodic table are all halogens. All halogens have the same ______.
A. Atomic number
B. Atomic mass
C. Number of possible isotopes
D. number of valence electrons
Group 17 elements called halogens . All halogens have the same number of valence
electrons
1.8 x 1022 atoms of Rn to moles of Rn
Answer:
1.8×10²² atom of Rn contain 0.03 moles of Rn.
Explanation:
Given data:
Number of atoms of Rn = 1.8×10²² atoms
Number of moles = ?
Solution:
we will solve this problem through Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance. The number 6.022 × 10²³ is called Avogadro number.
For example,
1 mole of Rn = 6.022 × 10²³ atoms of Rn
1.8×10²² atoms of Rn × 1mol / 6.022 × 10²³ atoms of Rn
0.3×10⁻¹ moles of Rn
0.03 moles of Rn
How many oxygen atoms are there in 450.0 grams of Na2SO4?
Answer:
112.5
Explanation:
I think so because in one unit has 4 oxygen atoms.
Helpppp fasttttttttttttttt Choose the best word to complete the sentence.
The teacher asked us to determine if the triangle was
a vegetal
C. Vertex
b. equilateral
d. negative space
Please select the best answer from the choices provided
Answer:
equilateral (B)
Explanation:
it is the only word which relates to triangles and their shape - plus, its logical and makes sense.
Answer:
its b
Explanation:
The mass of a golf ball is 45.9 g . If it leaves the tee with a speed of 61.0 m/s , what is its corresponding wavelength?
Answer:
The corresponding wavelength is 2.4×10⁻³⁴ m.
Explanation:
Given data:
Mass of ball = 45.9 g (45.9/1000 = 0.0459 kg)
Speed of ball = 61.0 m/s
Wavelength = ?
Solution:
Formula:
λ = h/mv
λ = wavelength
h = Planck's constant
m = mass
v = velocity
Now we will put the values in formula.
λ = 6.63×10⁻³⁴ kg.m².s⁻¹ / 0.0459 kg ×61.0 m/s
λ = 6.63×10⁻³⁴kg.m².s⁻¹ /2.8 Kg.m/s
λ = 2.4×10⁻³⁴ m
The corresponding wavelength is 2.4×10⁻³⁴ m.
0.68 moles of calcium to calcium atoms
[tex]0.68 \: moles \: calcium \times \frac{6.02 \times {10}^{23} \: calcium \: atoms }{1 \: mole \: calcium} \\ [/tex]
The (( mole calcium ))s are simplified so the answer is based on the number of calcium atoms.
[tex]0.68 \times 6.02 \times {10}^{23} = 68 \times {10}^{ - 2} \times 602 \times {10}^{ - 2} \times {10}^{23} \\ [/tex]
[tex] = 68 \times 602 \times {10}^{ - 4} \times {10}^{23} = 40936 \times {10}^{19} \\ [/tex]
[tex] calcium \: atoms = 40936 \times {10}^{19} \\ [/tex]
_________________________________
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
The is the
variable that
gets measured
Answer:
what? what's the full question?
Describe electrons.
Location:
Charge:
mass
Answer:
Describe electrons.
Location: electron cloud
Charge: negative
Mass: one-two thousands amu
Explanation:
Which characteristic of life is described as the transfer of DNA from parent to offspring, and is important for keeping a species alive
A. Homeostasis
B. Cell Organization
C. Heredity
Answer:
C. Heredity
Explanation:
Homeostasis means that an organism can control its own body temperature. This is important because if we couldn't control our temperature, then our cells would have trouble working properly from being to hot or cold.
Cell organization means that our body and cells can organize themselves into groups that work together. For example, cells form groups and tissue for different organs while other cells form nerves.
Heredity is the passing of genes from parent to offspring
what is the next step if a scientist's hypothesis is supported
Which of the following are properties of substances with matter? (2 points)
a
Mass and volume
b
Length and width
c
Shape and color
d
Size and texture
Which is the correct name for the compound CoCO 3?
A
Cobalt Carbonoxide
B
Cobalt (II) Carbonate
C
Carbon Oxygen Carbonate
D
Cobalt Carbonate
QUICK PLEASE!!!
Answer:
Cobalt (II) Carbonate
Explanation:
Answer:B
Explanation:
I NEED HELPPP THIS DUE TODAY!!!! IT IS URGENT!!
Cyclohexanecarboxylic acid, C6H11COOH (pKa 4.90), is only slightly soluble in water, but its sodium salt, C6H11COO-Na , is quite soluble in water. Describe the solubility of cyclohexanecarboxylic acid in solutions of sodium hydroxide, sodium bicarbonate (NaHCO3), and sodium carbonate (Na2CO3). The pKa values for the conjugate acids of sodium hydroxide, sodium bicarbonate (NaHCO3), and sodium carbonate (Na2CO3) are 15.7, 6.36, and 10.33, respectively.
Answer:
See explanation
Explanation:
Carboxylic acids are all soluble in solutions of NaOH, Na2CO3 and NaHCO3 due to the formation of a sodium salt of the acid.
In all these cases, the sodium salt of cyclohexanecarboxylicacid formed is more soluble in water than the parent acid.
When the acid is dissolved in sodium bicarbonate or sodium carbonate, carbon dioxide gas is also evolved.
A 10.0-g sheet of gold with a temperature of 18.0°C is laid flat on a sheet of iron that weighs 20.0 g and has a temperature of 55.6°C. Given that the specific heats of Au and Fe are 0.129 J g-1 0 c-1 and 0.444 J g-1 0 c-1, respectively, what is the final temperature of the combined metals? Assume that no heat is lost to the surroundings. (Hint: The heat gained by the gold must be equal to the heat lost by the iron.)
Answer:
T = 50.83°C
Explanation:
Let the final temperature be T .
heat lost = mass x specific heat x fall in temperature
heat lost by iron = 20 x .444 x ( 55.6 - T )
heat gained by gold = 10 x .129 x ( T- 18 )
heat lost = heat gained
20 x .444 x ( 55.6 - T ) = 10 x .129 x ( T- 18 )
493.73 - 8.88 T = 1.29 T - 23.22
10.17 T = 516.95
T = 50.83°C
The final temperature of the combined metals (gold and iron) is 50.83°C.
Given the following data:
Initial temperature of gold = 18.0°CFinal temperature of iron = 55.6°CMass of gold = 10.0 gMass of iron = 20.0 gSpecific heat capacity of iron = 0.444 J/g°C.Specific heat capacity of gold = 0.129 J/g°C.To find the final temperature of the combined metals (gold and iron):
Heat lost by the iron = Heat gained by the gold.
[tex]Q_{lost} = Q_{gained}\\\\mc\theta = mc\theta\\\\20(0.444)(55.6 - T_f) = 10(0.129)(T_f - 18)\\\\8.88(55.6 - T_f) = 1.29(T_f - 18)\\\\493.728 - 8.88T_f = 1.29T_f - 23.22\\\\8.88T_f + 1.29T_f = 493.728 + 23.22\\\\10.17T_f = 516.948\\\\T_f = \frac{516.948}{10.17}[/tex]
Final temperature = 50.83°C
Read more: https://brainly.com/question/188778
2) 3,160 tons of water flows over Niagra Falls every second. Assuming the water has a density of 1.00 g/ml,
how much time would it take the water to fill up a cylinder with the diameter of a school garbage can (53 cm)
that stretched to the moon, which is on average 236,000 miles from the earth? Answer in a time unit that is
most meaningful (for example 1.40 days is more meaningful than 121,000 seconds). 1 ton = 2000 pounds
Answer:
Time = 8.12 h = 0.34 day
Explanation:
First we find speed of water flow:
Speed = u = (3160 tons/s)(907.185 kg/1 ton)
u = 2866704.6 kg/s
also,
Density = (1 g/mL)(1 mL/1 x 10⁻⁶ m³)(1 x 10⁻³ kg/1 g)
Density = 1000 kg/m³
Now,
Volume Flow Rate = Speed/Density
Volume Flow Rate = (2866704.6 kg/s)/(1000 kg/m³)
Volume Flow Rate = 2866.7 m³/s
Now, we find volume of cylinder:
Volume = (Area)(Length)
Volume = (πd²/4)(L)
Volume = [(π)(0.53 m)²/4][236000 mi][1609.36 m/1 mi]
Volume = 83,792,823.82 m³
Now,
Time = Volume/Volume Flow Rate
Time = (83,792,823.82 m³)/(2866.7 m³/s)
Time = (29299.71 s)(1 h/3600 s)
Time = 8.12 h = 0.34 day
elasric energy is a type of kenetic energy true or false
Answer:
False
Explanation:
Explain the purpose of the Parados and summarize the text. In addition, infer how the Parados reveals tone and evokes mood. Finally, analyze how the text reveals the beliefs of the ancient Greek people.
Answer:
The purpose of the Parados is to add an explanation of events that happened before the play begins. In the first section the mood is triumphant because of the recent battle win. Then it jumps back to the beginning of the battle and the mood is scared. Before the army lead by the brother of the king could attack they are forced to retreat and the army counterattacks. Unfortunately, the brothers kill each other during the battle. The people of Ancient Greece believed that Zeus and Ares were on their side and used the gods as the excuse for winning a battle. The story ends victorious but sad tone because the two brothers have slain each other.
Explanation: Gets you 100%
Whose measurements are more precise?20.3 cm and 21.0cm
Answer:
will i think the 21.0cm
what is the formula for titanium (IV) sulfate
How can sediment be a bad thing??
Answer:
Sediment increases the cost of treating drinking water and can result in odor and taste problems. Sediment can clog fish gills, reducing resistence to disease, lowering growth rates, and affecting fish egg and larvae development.
Explanation:
Answer:
"Sediment increases the cost of treating drinking water and can result in odor and taste problems. Sediment can clog fish gills, reducing resistance to disease, lowering growth rates, and affecting fish egg and larvae development".
Explanation:
Question 4 (1 point)
Neon gas is often used to make signs for restaurants and businesses. However, neon only accounts
for 0.0018% of Earth's atmosphere. Scientists are looking for other elements that have similar
properties as neon that could be used as a substitute. Which of the following elements would most
likely be a good substitute?
Oь
Argon
Flourine
Chlorine
Oxygen
d
Submit
Submit
Answer:
Argon
Explanation:
The element that would most likely be a good substitute for neon is "argon".
These two elements belong to the noble gases in Group 18(8A) of the Periodic Table. They are inert gases - they do not react chemically with other substances.
Argon, as an inert gas is often used whenever an inert atmosphere is needed. Argon is used in incandescent light bulbs. It is used to stop oxygen from corroding the filament. It is also used by welders to protect weld area.
Argon is a good substitute for neon in this context because they possess some physical properties which are similar.
The gas cyclobutane, C4H8(g), can be used in welding. When cyclobutane is burned in oxygen, the reaction is: C4H8(g) + 6 O2(g)4 CO2(g) + 4 H2O(g) (a) Using the following data, calculate ΔH° for this reaction. ΔH°f kJ mol-1: C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ (b) Calculate the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 (c) When this reaction is carried out in an open flame, almost all the heat produced in part (a) goes to raise the temperature of the products. Assuming that the reactants are at 25°C, calculate the maximum flame temperature that is attainable in an open flame burning cyclobutane in oxygen. The actual flame temperature would be lower than this because heat is lost to the surroundings. Maximum temperature = °C
Answer:
a
[tex]\Delta H^o _{rxn} = -2568.9 \ kJ [/tex]
b
[tex]H = 350 JK^{-1}[/tex]
c
[tex]T_{max} = 32.4 ^o C[/tex]
Explanation:
From the question we are told that
The reaction of cyclobutane and oxygen is
[tex]C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}[/tex]
ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ
Generally ΔH° for this reaction is mathematically represented as
[tex]\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ][/tex]
=> [tex]\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0][/tex]
=> [tex]\Delta H^o _{rxn} = -2568.9 \ kJ [/tex]
Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is mathematically represented as
[tex]H = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}][/tex]
=> [tex]H = [ 4 * 37.1 + 6* 33.6 ][/tex]
=> [tex]H = 350 JK^{-1}[/tex]
From the question the initial temperature of reactant is [tex]T_i = 25^oC[/tex]
Generally the enthalpy change([tex]\Delta H^o _{rxn}[/tex]) of the reaction is mathematically represented as
[tex]|\Delta H^o _{rxn} |= H * (T_{max} -T_i)[/tex]
[tex] 2568.9 = 350 * (T_{max} -25)[/tex]
=> [tex]\frac{2568.9 }{350} = T_{max} - 25[/tex]
=> [tex]T_{max} = 32.4 ^o C[/tex]
BRAINLIEST!!!!!!!!!!
Lard, Lye, and Salt are combined to make Glycerin (a sweet-tasting substance found in lotion) and Soap. This process makes some left-over material as a waste product. If 30.0 kg of lard, 20.0 kg of lye, and 5.0 kg of salt are combined and 25.0 kg of glycerin and 5.0 kg of waste are produced, what mass of soap is made? Show all work.
Explain how question demonstrates the Law of Conservation of Mass.
Answer:
30
Explanation:
25.0 + 5.0 = 30
Answer:
30
Explanation:
Consider a cylinder of a gasoline engine at the beginning of the compression cycle, during which a fuel/air mixture (for our purposes mostly composed of nitrogen and oxygen, i.e. an ideal gas of diatomic molecules) at 300 K and 1 bar is compressed down to one-tenth volume (compression ratio of 10:1). Assume that the compression is rapid so no heat exchange occurs with the environment. Calculate the pressure and the temperature of the compressed gas. In a diesel engine the compression ratios are typically much higher; redo the same calculation with the compression ratio of 20:1.
Answer:
(i) Final pressure and temperature are 25.119 bar and 753.566 K, (ii) Final pressure and temperature are 66.289 bar and 994.336 K.
Explanation:
This system experiments an adiabatic compression, as such compression happens with no heat interaction between the piston-cylinder device and surroundings. This is a particular case of polytropic process, in which there is no entropy generation according to the Second Law of Thermodynamics.
The compression process is represented by the following formulas:
[tex]\frac{p_{2}}{p_{1}} = \left(\frac{V_{1}}{V_{2}} \right) ^{\gamma}[/tex] (Eq. 1)
[tex]\frac{T_{2}}{T_{1}} = \left(\frac{V_{1}}{V_{2}} \right)^{\gamma - 1}[/tex] (Eq. 2)
Where:
[tex]p_{1}[/tex], [tex]p_{2}[/tex] - Initial and final pressures, measured in bar.
[tex]T_{1}[/tex], [tex]T_{2}[/tex] - Initial and final temperatures, measured in Kelvins.
[tex]V_{1}[/tex], [tex]V_{2}[/tex] - Initial and final volumes, measured in cubic meters.
[tex]\gamma[/tex] - Specific heat ratio of air, dimensionless.
From Theory of Diesel and Otto Cycles we know that compression ratio is defined as:
[tex]r_{c} = \frac{V_{1}}{V_{2}}[/tex] (Eq. 3)
And (Eqs. 1, 2) can be rewritten as follows:
[tex]\frac{p_{2}}{p_{1}} = r_{c}^{\gamma}[/tex] (Eq. 1b)
[tex]\frac{T_{2}}{T_{1}} = r_{c}^{\gamma - 1}[/tex] (Eq. 2b)
Then, we clear final pressure and pressure in each expression and calculate them for each case:
[tex]p_{2} = p_{1}\cdot r_{c}^{\gamma}[/tex]
[tex]T_{2} = T_{1}\cdot r_{c}^{\gamma-1}[/tex]
(i) [tex]r_{c} = 10[/tex], [tex]p_{1} = 1\,bar[/tex], [tex]T_{1} = 300\,K[/tex], [tex]\gamma = 1.4[/tex]
[tex]p_{2} = (1\,bar)\cdot 10^{1.4}[/tex]
[tex]p_{2} = 25.119\,bar[/tex]
[tex]T_{2} = (300\,K)\cdot 10^{0.4}[/tex]
[tex]T_{2} = 753.566\,K[/tex]
Final pressure and temperature are 25.119 bar and 753.566 K.
(ii) [tex]r_{c} = 20[/tex], [tex]p_{1} = 1\,bar[/tex], [tex]T_{1} = 300\,K[/tex], [tex]\gamma = 1.4[/tex]
[tex]p_{2} = (1\,bar)\cdot 20^{1.4}[/tex]
[tex]p_{2} = 66.289\,bar[/tex]
[tex]T_{2} = (300\,K)\cdot 20^{0.4}[/tex]
[tex]T_{2} = 994.336\,K[/tex]
Final pressure and temperature are 66.289 bar and 994.336 K.
Which of the following is least like the others on the list?
a. Amino acid
b. Ribonucleic acid
c. Nucleic acid
d. Nucleotides
Explanation:
C option i think but I didn't know