HELP

explain what the answer is

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here's the solution ~

To write a quadrilatic function, we have to use its roots, like we have to subtract the roots from x and multiply them ~ then we will get our required function !

Since our only root is 11 here, we have to do t double

[tex]\qquad \sf  \dashrightarrow \:(x - 11)(x - 11)[/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} - 11x - 11x + 121 [/tex]

[tex]\qquad \sf  \dashrightarrow \: {x}^{2} - 22x + 121[/tex]

That's our required function ~ I hope you understood the whole thing !

Answer:

-> See attached

115.893 meters²

Step-by-step explanation:

   See attached for my sketch.

    Area for a rectangle is A = L * W:

9.78 meters * 11.85 meters = 115.893 meters²

Answer:

448 ft ^2

Step-by-step explanation:

[tex]A = \frac{b_{1} + b_{2}}{2} * h\\A = \frac{17 + 39}{2} * 16\\A = \frac{56}{2} * 16\\\\A = 28 * 16\\\\A = 448 ft^{2}[/tex]

Hope this helps,

If best, mark brainliest, if not, hope it helps anyway.

Answer:

g= 81

Step-by-step explanation:

Replace X with 15

g = 6x -9

g = 6(15) - 9

g = 90 - 9

g = 81

Step-by-step explanation:

g=6x-9

putting the value of x

g=6×15-9

g=81

Answer:

180-52=128

Do mark BRAINLIEST

Answer:

Step-by-step explanation:

The given function is quadratic.

The maximum of the quadratic function is its vertex.

The x-coordinate is determined by x = - b/(2a)

Apply the x-value and find the value of f:

Answer:

18.25

Step-by-step explanation:

we are given a quadratic function

[tex] f(x) = - 16 {x}^{2} + 20x + 12[/tex]

where:

To find the maximum value of f(x) in other words, the maximum height, in feet, reached by the arrow.

Differentiate both sides:

[tex] f'(x) = \dfrac{d}{dx}( - 16 {x}^{2} + 20x + 12)[/tex]

with sum differentiation rule, we acquire:

[tex] \displaystyle f'(x) = \frac{d}{dx}( - 16 {x}^{2} )+ \frac{d}{dx} 20x + \frac{d}{dx} 12[/tex]

recall that,

utilizing the rules we acquire:

[tex] \displaystyle f'(x) = - 32 {x}^{} + 20 [/tex]

now equate f'(x) to 0:

[tex] \displaystyle - 32 {x}^{} + 20 = 0[/tex]

solving the equation for x yields:

[tex]x _{max}= \dfrac{5}{8} [/tex]

plug in the maximum value of x into the quadratic function:

[tex]f(x )_{max}= - 16 {( \frac{5}{8} )}^{2} + 20( \frac{5}{8} ) + 12[/tex]

simplify:

[tex]f(x )_{max} = 18.25[/tex]

hence,

The maximum height reached by the arrow is 18.25 feet

Answer:

96 in³

Step-by-step explanation:

Volume = 2(BHD) / 2

The 2s cancel out

Volume = 3(8)4

Volume = 96

Answer:

1 and 40

2 and 20

4 and 10

5 and 8

Step-by-step explanation:

need to know the factors of 40

factors of are 1, 2, 4, 5, 8, 10, 20 and 40

possible lengths and widths would be

1 and 40

2 and 20

4 and 10

5 and 8

Answer:

x-73

Step-by-step explanation:

Let x=Jose's height.  If it says "less than," then that is subtraction.  Since Jose's height is not defined, there is no specific number that can be used to describe "73 less than twice Jose's height," so I use the variable x, and then subtract 73.

Answer:

1/6 < 1/3 < 1/2 < 2/3

Step-by-step explanation:

We can turn the following to decimal;

1/6 = 0.16666666666        

2/3 = 0.66666666666

1/2 = 0.5

1/3 = 0.33333333333

0.16666666666   < 0.33333333333 < 0.5 < 0.66666666666

Thus, from least to greatest is 1/6 < 1/3 < 1/2 < 2/3

~Learn with Lenvy~

Check the picture below, so the green line is really the radius of the circle, and we know its center.

[tex]~~~~~~~~~~~~\textit{distance between 2 points}\\\\(\stackrel{x_1}{0}~,~\stackrel{y_1}{-3})\qquad(\stackrel{x_2}{\frac{15}{2}}~,~\stackrel{y_2}{1})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\\stackrel{radius}{r}=\sqrt{[\frac{15}{2} - 0]^2 + [1 - (-3)]^2}\implies r=\sqrt{\left( \frac{15}{2} \right)^2 + (1+3)^2}\\\\\\r=\sqrt{\left( \frac{15}{2} \right)^2 +4^2}\implies r=\sqrt{\frac{225}{4} + 16}\implies r=\sqrt{\cfrac{289}{4}}\implies r=\cfrac{17}{2}\\\\[-0.35em]\rule{34em}{0.25pt}[/tex]

[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{0}{ h},\stackrel{-3}{ k})\qquad \qquad radius=\stackrel{\frac{17}{2}}{ r} \\\\\\\ [x-0]^2~~ + ~~[y-(-3)]^2~~ = ~~\left( \cfrac{17}{2} \right)^2\implies x^2+(y+3)^2 = \cfrac{289}{4}[/tex]

Answer:

441

Step-by-step explanation:

The value of x from the figure is 17.82 units

1) From the first figure.

Opposite side = x

Adjacent = 12

Using the SOH CAH TOA identity

tan53 = opp/adj

tan53 = x/12

x = 12tan53

x = 15.92 units

2) Using the SOH CAH TOA identity

cos27 = adj/hyp

cos27 = x/20

x = 20cos27

x =  17.82units

Hence the value of x from the figure is 17.82 units

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Answer:

  (iv)  b

  (v)  c

  (vi)  d

Step-by-step explanation:

The first two questions have to with understanding the meaning of the English words. (It's reading comprehension.)

__

(iv) "no larger than 10" means "less than or equal to 10"

  (b) x ≤ 10

__

(v) "at most 1600" means "less than or equal to 1600"

  (c)  c ≤ 1600

__

(vi) A value of x will be a solution to the inequality if substituting it into the inequality results in a true statement. Here, using x=0 effectively eliminates the x-term from the inequality.

  (a) 0 > 0 . . . false

  (b) 5 < 0 . . . false

  (c) 2 < 0 . . . false

  (d) -2 < 0 . . . true

Answer:

The cylinder can hold 508.68 in³

Explanation:

The volume of a cylinder can be calculated using the following rule:

Volume of cylinder = πr²h cubic units

where r is the radius of the cylinder and h is its height

Now, we are given that:

height of cylinder = 18 in

diameter of cylinder = 6 in which means that the radius of the cylinder is 3 in

π is 3.14

Substitute with the givens in the above equation to get the volume of the cylinder as follows:

Volume of cylinder = πr²h

Volume of cylinder = 3.14 * (3)² * 18

Volume of cylinder = 508.68 in³

To find area of square one :-

Given :

To find :

We know :

Area of square = side²

Therefore:-

→Area of square = 9²

→Area of square = 9 × 9

→Area of square = 81 (unit)²

To find area of square two :-

Given :

To find :

We know :

Area of square = side²

Therefore:-

→Area of square = 11²

→Area of square = 11 × 11

→Area of square = 121 (unit)²

Now it's clearly visible that the whole figure is also. a square .

Therefore AE = CP

Which means area of square three = 81 (unit)²

Now area of shaded figure :-

Answer:

69%

Step-by-step explanation:

10×10 table, 69 cells are orange. Therefore the fraction 69/100 as a percentage is 69%.

The length of the rectangle is 48 yards.

Let's denote the width of the rectangle as "w" yards.

According to the information given, the length of the rectangle is 32 yards less than 10 times its width. So, the length can be represented as: 10w - 32 yards.

The formula for the area of a rectangle is length times width: Area = length × width.

Given that the area of the rectangle is 384 square yards, we can set up an equation:

Area = length × width

384 = (10w - 32) × w

Now, let's solve for the width (w):

384 = 10w² - 32w

0 = 10w² - 32w - 384

Dividing the equation by 2 to simplify:

0 = 5w² - 16w - 192

Now we have a quadratic equation. We can either factor it or use the quadratic formula to solve for "w." Let's use the quadratic formula:

w = (-b ± √(b² - 4ac)) / 2a

For our equation, a = 5, b = -16, and c = -192. Plugging these values into the formula:

w = (16 ± √((-16)² - 4 × 5 × (-192))) / (2 × 5)

w = (16 ± √(256 + 3840)) / 10

w = (16 ± √4096) / 10

w = (16 ± 64) / 10

This gives us two possible solutions for the width:

w = (16 + 64) / 10 = 8 yards

w = (16 - 64) / 10 = -4.8 yards

Since width can't be negative, we'll ignore the second solution.

So, the width of the rectangle is 8 yards. Now, let's find the length using the earlier expression:

Length = 10w - 32

Length = 10 × 8 - 32

Length = 80 - 32

Length = 48 yards

Therefore, the length of the rectangle is 48 yards.

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Answer:

3/5

Step-by-step explanation:

6 white cars out of 10 cars would be written as 6/10.

You then would simplify this fraction to 3/5.

So your answer is 6/10 or 3/5.

Answer:

1456

Step-by-step explanation:

56x2x13

56x26

1456

The graph of the weight function w = 20n is an illustration of linear equations

The expected weight of honey per hive is 20 pounds

The equation of the model is given as:

w = 20n

To plot the graph, we use the following representations

See attachment for the graph of w = 20n

The graph shows that:

Read more about linear equations at:

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In order to find the missing angles, we can see that vertically opposite angles and corresponding angles are equal.

46° + 82° + No. 4 = 180°

No. 4 = 180° - 128° = 52°

Therefore: No. 4 = No. 1 = 52° (vertically opposite angles)

In geometry, an angle is actually known to be the figure that is created by two rays that actually meet at an end point that is common to the both rays. It is represented by the symbol: ∠.

So, we can see that:

Line a || Line b and Line c || Line d

46° = 7 (corresponding angles)

So, 46° + 82° + No. 4 = 180°

Thus, No. 4 = 180° - 128° = 52°

Therefore:

No. 4 = No. 1 = 52° (vertically opposite angles)

No. 2 = 180° - 52° = 128° (angles on a straight line)

No. 2 = No. 3 = 128° (vertically opposite angles)

No. 7 = No. 6 = 46° (vertically opposite angles)

No. 8 = 180° - 46° = 134° (angles on a straight line)

No. 8 = No. 5 = 134° (vertically opposite angles).

82° = No. 11 (vertically opposite angles)

No. 9 = 180° - 82° = 98° (angles on a straight line)

No. 9 = No. 10 = 98° (vertically opposite angles)

No. 9 = No. 15 = 98° (alternate angles)

No. 13 = No. 15 = 98° (vertically opposite angles)

No. 12 = No. 14 = 82° (vertically opposite angles)

46°= No. 17 (vertically opposite angles)

No. 18 = 180° - 46° = 134° (angles at a point)

No. 18 = No. 16 = 134° (vertically opposite angles)

No. 19 = 180° - (46° + 82°) = 52° (sum of angles in a triangle)

No. 19 = No. 22 = 52° (vertically opposite angles)

No. 20 = 180° - 52° = 128° (angles on a straight line).

No. 20 = No. 21 = 128° (vertically opposite angles)

No. 25 = No. 2 = 128° (corresponding angles)

No. 25 = No. 24 = 128° (vertically opposite angles)

No. 23 = No. 26° (vertically opposite angles).

So, all the angles are:

1= 52°

2= 128°

3= 128°

4= 52°

5= 134°

6= 46°

7= 46°

8=134°

9= 98°

10= 98°

11= 82°

12= 82°

13= 98°

14= 82°

15= 98°

16= 134°

17= 46°

18= 134°

19= 52°

20= 128°

21= 128°

22= 52°

23= 52°

24= 128°

25= 128°

26= 52°

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Answer:

[tex]1,\!848[/tex].

Step-by-step explanation:

There are two disjoint sets of ways to choose a lineup as required:

Assume that none of Alicia, Amanda, or Anna is to be selected. This lineup of [tex]6[/tex] would then need to be selected from a set of [tex]14 - 3 = 11[/tex] players (which excludes Alicia, Amanda, and Anna.)

The number of ways of selecting (without order) [tex]6[/tex] items out of a set of [tex]11[/tex] (distinct) items is equal to the combination:

[tex]\begin{aligned}\begin{pmatrix}11 \\ 6\end{pmatrix} &= \frac{11!}{(6!)\, (11 - 6)!} \\ &= \frac{11!}{6! \times 5!}\end{aligned}[/tex].

Assume that Alicia is selected, but neither Amanda nor Anna is selected. The other [tex]6 - 1 = 5[/tex] players in this lineup would then need to be selected from a set of [tex]14 - 1 - 2 = 11[/tex] players. (This set of [tex]11[/tex] excludes Alicia, Amanda, and Anna.)

The number of ways to select [tex]5[/tex] items from a set of [tex]11[/tex] items is:

[tex]\begin{aligned}\begin{pmatrix}11 \\ 5\end{pmatrix} &= \frac{11!}{(5!)\, (11 - 5)!} \\ &= \frac{11!}{5! \times 6!} \\ &= \frac{11!}{6! \times 5!}\end{aligned}[/tex].

Similarly, there would be another set of [tex](11!) / (6! \times 5!)[/tex] distinct ways to select the lineup if Amanda is selected, but neither Alicia nor Anna is.

Likewise, the number of ways to select the lineup with Anna but neither Amanda nor Alicia would also be [tex](11!) / (6! \times 5!)[/tex].

These sets of configurations for the lineup are pairwise disjoint from one another. Thus, the total number of ways to select this lineup would be:

[tex]\begin{aligned}& \begin{pmatrix}11 \\ 6 \end{pmatrix} + 3 \times \begin{pmatrix}11 \\ 5 \end{pmatrix} \\ =\; & \frac{11!}{6! \times 5!} + 3 \times \frac{11!}{6! \times 5!} \\ =\; & \frac{4 \times 11!}{6! \times 5!} \\ =\; & \frac{4 \times 11 \times 10 \times 9 \times 8 \times 7}{5 \times 4 \times 3 \times 2} \\ =\; & \frac{11 \times 10 \times 9 \times 8 \times 7}{5 \times 3 \times 2} \\ =\; & 1,\!848\end{aligned}[/tex].

The unit price of canned corn is $0.14

14 ounces = $1.96

1 ounce = 1.96 / 14

= 0.14

Answer:

893

Step-by-step explanation:

893 is too far away to round to 880. It would actually round to 890.

The last digits of 883 and 882 are small enough to round to 880.

The last digit of 878 is large enough to round to 880.

Answer:

893

Step-by-step explanation:

We round down if the digit is less than 5

We round up if the digit is 5 or more

Rounding to the nearest 10:

893 → 890 (round down as 3 is less than 5)

883 → 880 (round down as 3 is less than 5)

882 → 880 (round down as 2 is less than 5)

878 → 880 (round up as 8 is more than 5)

So the only number that does NOT round to 880 is 893.

The time I would need to leave the hotel if the flight lands at 3:23 p.m is 7 : 09 am

The first step is to add the total hours of the flight to the time of the tax ride and the time you need to get to the airport.

7h + 12 min + 45 + 17 = 8 hours 14 minutes

Now subtact  8 hours 14 minutes  form 3: 23

(12 + 3:23) -  8 hours 14 minutes =7 : 09 am

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Answer:

down syndrome

Step-by-step explanation:

Answer:

A

First prove Triangle ABC is congruent to Triangle CDA, and then state AD and BC are corresponding sides of the triangles.

Hope this helps!

Please Mark Brainleast!!!

The sequence to prove that AD = BC is; First prove ABC is similar to CDA, and then state AD and BC are opposite sides of the parallelograms.

From the question, we see that the parallelogram ABCD has a diagonal AC. Thus; AB║ CD and AD║BC.

Now, the parallelogram is divided into two triangles ΔABC and ΔADC by its diagonal AC.

Thus;

∠ACB = ∠DAC  and ∠CAB = ∠ACD  because they are alternate interior angles.

Also, AC = AC  (Reflexive property)

Thus; by ASA congruence postulate, we can say that; ΔABC ≅  ΔADC

Also, by corresponding sides of the congruent triangles are congruent we can say that AD = BC.

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