HELP PLS




2. How would these gravity forces change if the Sun got much bigger?
Decrease. Increase. Stay the same

3. How would these gravity forces change if the Earth was much closer to the Sum?
Decrease Increase. Stay the same

4. How would these gravity forces change if the Earth got much smaller?
Decrease. Increase. Stay the same
face

Answers

Answer 1

Answer:

2. increase

3. stay the same

4. Decrease

Explanation:

(let me know if im wrong on any we learned this last year so I might be a little rusty on this subject)

Answer 2

The force of gravity increases with increase in the size of the Sun and with decrease in the distance between the earth and the Sun. However, it decreases with decrease in the size of the earth.

What is gravity?

Gravity is the force of attraction that exists between two bodies separated by a given distance.

The force of gravity increases with increase in the size of the bodies as well as with a decrease in the distance of separation.

However, the force of gravity decreases with decrease in the size of the bodies as well as with a increase in the distance of separation.

Thus, for the force of gravity between the earth and the Sun;

Force of gravity increases with increase in the size of the SunForce of gravity increases with decrease in the distance between the earth and the Sun Force of gravity decreases with decrease in the size of the earth.

Therefore, the force of gravity is affected by size of the bodies as well as the distance separating the bodies.

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Related Questions

A cart at rest accelerates to a speed of 30 meters per second over a 3.0 second time interval. What is the average velocity of the cart during these 3.0 seconds? P.4B

Answers

Answer:

15 m/s

Explanation:

Given data

Initial velocity= 0m/s----------since the cart was at rest

Final velocity = 30m/s

time= 30 seconds

Required

the average speed

We know that the sum of the initial and final velocity is divided by 2 to find the average velocity

average velocity= 0+30/2

average velocity= 30/2

average velocity= 15 m/s

Hence the average velocity is 15 m/s

its in the pic plz help

Answers

Answer:

Hand soap: basic

chocolate milk: neutral

apple juice: acidic

shampoo: acidic

mouthwash: acidic

tap water: basic

Explanation:

Check your PH scale

1-6 = acidic

7 = neutral

8-14 = basic

If you have observed something about the world and want to


investigate it further, what are you seeking to do?


a Do background research


b Construct a hypothesis


C Ask a question


d Report the results

Answers

Answer: a

Explanation: :)

A trash compactor pushes down with a force of 500 N on a 3 cm2 input piston, causing a force of 30,000 N to crush the trash. What is the area of the output piston that crushes the trash

Answers

Answer:

[tex]180 cm^2[/tex]

Explanation:

We are given that

Force [tex]F_1=500 N[/tex]

[tex]A_1=3cm^2[/tex]

[tex]F_2=30000 N[/tex]

We have to find the area of the output piston that crushes the trash

Input  piston=Output piston

We know that

[tex]Pressure=\frac{force}{Area}[/tex]

Using the formula

[tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]

Substitute the values

[tex]\frac{500}{3}=\frac{30000}{A_2}[/tex]

[tex]A_2=\frac{30000\times 3}{500}[/tex]

[tex]A_2=180 cm^2[/tex]

Hence, the area of the output piston that crushes the trash 180 square cm

A trash compactor pushes down with a force of 500 N on a 3 cm² input piston, causing a force of 30,000 N on a 180 cm² output piston.

In physics, the pressure (P) is the force (F) applied perpendicular to the surface of an object per unit area (A) over which that force is distributed.

[tex]P = \frac{F}{A}[/tex]

A trash compactor pushes down with a force of 500 N (F₁) on a 3 cm² (A₁) input piston, causing a force of 30,000 N (F₂) to crush the trash.

Since the pressure in both pistons is equal, we can use the previous expression to calculate the area of the output piston (A₂).

[tex]\frac{F_1}{A_1} = \frac{F_2}{A_2} \\\\A_2 = \frac{A_1 \times F_2}{F_1} = \frac{3cm^{2} \times 30,000N}{500N} = 180cm^{2}[/tex]

A trash compactor pushes down with a force of 500 N on a 3 cm² input piston, causing a force of 30,000 N on a 180 cm² output piston.

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2. What is the y-component of a 95.3 N force that is exerted at 57.1

degree to the horizontal, *

Answers

Answer: 80N

Explanation:

The y-component would be the magnitude of the force multiplied by the sine of the angle.

[tex]95.3*\sin(57.1)=80N[/tex]

The y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.

What is Force?

Force is defined as an external agent which is capable of changing the state of rest or motion of a body with magnitude and direction. The direction towards which the force is applied is known as the direction of the force, and the point of application of the force is where the force is applied.

It can be expressed as:

F = m a

Where, F= Force

m= mass of the object

a= acceleration

In the given example, the force acts as vector which is broken down into the components. Given the angle θ along the horizontal axis,

so, For x component [tex]F_x[/tex] = Fcosθ

For y component [tex]F_y[/tex] = F sinθ

Given, F= 95.3 N ; θ= 57.1 °

[tex]F_y = (95.3) * (sin 57.1)\\ F_y= 80.0N[/tex]

Thus, the y-component of a 95.3 N force that is exerted at 57.1 ° to the horizontal is 80N.

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A hockey puck that has a mass of 0.170 kg travels with a speed of 42.0 m/s.

What is the momentum of the puck?

Answers

Answer:

Momentum = 7.14 Kgm/s

Explanation:

Given the following data;

Mass = 0.170 kg

Velocity = 42m/s

To find the momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

Substituting into the equation, we have;

Momentum = 0.170 * 42

Momentum = 7.14kgm/s

Therefore, the momentum of the honey puck is 7.14 Kgm/s.

walks 5 meters in 5 seconds what is the average speed

Answers

Answer:

10 is the speed

Explanation:

this is y

An object’s distance from a converging lens is 16.1 times the focal length.
How far is the image from the lens?
Answer in units of f .

Answers

Answer:Hey I just wanted to tell you that Jesus LOVES YOU SO MUCH He died on the cross for all your sins so you won’t have to suffer the consequences of your sin He paid for ALL OF IT! He loves you SO FREAKING MUCH like unconditionally... all you have to do is confess with your mouth and believe in your heart that Jesus is Lord and God raised Him from the dead 3 days later you will be saved ;)))))))) He wants an intimate relationship with you all you have to do is reach out to Him I love you AND ABOVE ALL JESUS LOVES YOU

Have a blessed day;))

Explanation:

Comparing the Motion of Two Cars
Position vs Time
for Two Cars
D
Which statements describe the motion of car A and car
B? Check all that apply.
Car A and car B are both moving toward the origin.
Car A and car B are moving in opposite directions,
Car Ais moving faster than car B.
Car A and car B started at the same location.
Car A and car B are moving toward each other until
they cross over.
B
Position (m)
Time (s)

Answers

B, C, E

Hope this helps

Which best describes how single-celled organisms are different from multi-celled organisms?
A.
A single-celled organism is more detailed and complex.
B.
A single-celled organism must perform all cellular functions.
С.
A single-celled organism must work with other cells to survive.
D.
A single-celled organism is specialized to perform one function.

Answers

A single-called organism must perform all cellular functions on its own

Answer:

A single-called organism must perform all cellular functions on its own

Explanation:

i took the test

An ice skater accelerates backward for 5.0 second to final speed of 12m/s. If the acceleration backward was at a a rate of 1.5m/s2 what was the skater's initial speed

Answers

Answer:

Initial velocity, U = 4.5m/s

Explanation:

Given the following data;

Final velocity, v = 12m/s

Time, t = 5 seconds

Acceleration, a = 1.5m/s²

To find the initial velocity, we would use the first equation of motion.

[tex] V = U + at[/tex]

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

12 = U + 1.5*5

12 = U + 7.5

U = 12 - 7.5

Initial velocity, U = 4.5m/s

Identify an example of conformity in your school or community. Tell what makes it an example of conformity.

Answers

Answer:

One example of conformity in my school is the wide obsession of designer clothes. Because famous people wear them kids think its cool and follow their actions.

Explanation:

An element has a charge of -3, has 8 protons, 11 neutrons, and electrons

Word Bank:
12 5 11 8 13
pls help

Answers

Question isn’t clear
If it’s asking the no of electrons then -
No of electrons =no of protons in an atom of a element ....therefore there are 11 electrons

How do limiting factors impact Pacific Coast organisms?

Answers

Answer:

Limiting factors include a low food supply and lack of space. Limiting factors can lower birth rates, increase death rates, or lead to emigration. When organisms face limiting factors, they show logistic growth (S-shaped curve, curve B: Figure below). ... Limiting factors determine the carrying capacity of a population.

Explanation:

7. A ball is dropped from a height of 4.0 m. Just before it hits the ground it's momentum is
8.85 kg-m/s. What is the mass of the ball?

Answers

Answer:

Approximately [tex]1\; \rm kg[/tex]. (Assumption: [tex]g = 9.8\; \rm m \cdot s^{-2}[/tex].)

Explanation:

Let the mass of this ball be [tex]x\; \rm kg[/tex].

Initial gravitational potential energy of this ball: [tex]m \cdot g \cdot h \approx (39.2\, x) \; \rm J[/tex].

Just before the ball hits the ground, all [tex](39.2\, x)\; \rm J[/tex] of gravitational potential energy would have been converted to kinetic energy. Calculate the velocity of the ball at that moment:

[tex]\begin{aligned} \text{kinetic energy} = \frac{1}{2}\, m \cdot v^{2} \end{aligned}[/tex].

Therefore, right before hitting the ground, the velocity of the ball would be:

[tex]\begin{aligned} v&= \sqrt{\frac{2\, (\text{kinetic energy})}{m}} \\ &= \sqrt{\frac{2 \times (39.2\, x)}{x}}\\ & \approx \sqrt{2 \times 39.2} \approx 8.85\; \rm m \cdot s^{-1}\end{aligned}[/tex].

The momentum [tex]p[/tex] of an object of mass [tex]m[/tex] and velocity [tex]v[/tex] would be [tex]p = m \cdot v[/tex]. Rewrite this equation to find an expression for mass [tex]m\![/tex] given velocity [tex]v\![/tex] and momentum [tex]p\![/tex]:

[tex]\displaystyle m = \frac{p}{v}[/tex].

Right before collision, the momentum of this ball is [tex]p = 8.85\; \rm kg \cdot m \cdot s^{-1}[/tex] while its velocity is [tex]v \approx 8.85\; \rm m \cdot s^{-1}[/tex]. Therefore, the mass of this ball would be:

[tex]\begin{aligned}m &= \frac{p(\text{right before landing})}{v(\text{right before landing})} \\ &\approx \frac{8.85\; \rm kg \cdot m \cdot s^{-1}}{8.85\; \rm m \cdot s^{-1}} \approx 1\; \rm kg\end{aligned}[/tex].

A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is 5.40 m and friction is ignored, what is the kinetic energy of the fish when it hits the water?

Answers

Here we go.
My abbreviations; KE = Kinetic Energy; GPE = Gravitational Potential Energy.

So first off, we know the fish has KE right when the bird releases it. Why? Because it has horizontal velocity after released! So let’s calculate it:
KE = 1/2(m)(V)^2
KE = 1/2(2)(18)^2
KE = 324 J

Nice!
We also know that the fish has GPE at its maximum height before release:
GPE = mgh
GPE = (2)(9.81)(5.40)
GPE = 105.95 J

Now, based on the *queue dramatic voice* LAW OF CONSERVATION OF ENERGY, we know all of the initial energy of the fish will be equal to the amount of final energy. And since the only form of energy when it hits the water is KE, we can write:
KEi + GPEi = KEf
(Remember - we found the initial energies before!)
(324) + (105.95) = KEf
KEf = 429.95J
And that’s you’re final answer! Notice how this value is MORE than the initial KE from before (324 J) - this is because all of the initial GPE from before was transformed into more KE as the fish fell (h decreased) and sped up (V increased).

If this helped please like it and comment!

Which process causes the transfer of energy by air currents within the Earth's atmosphere?

Answers

Answer:

Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface



What is the net force of a scooter acting on the road with an impulse of 550 Ns for 10s.

Answers

Answer:

55N

Explanation:

Impulse is the product of Force and Time

Impulse = Force * Time

Given

Impulse = 550Ns

Time = 10s

Force = Impulse/Time

Force = 550/10

Force = 55N

Hence the net force on the scooter is 55N

An excited 92 kg football player celebrates a touchdown by carelessly running straight into the goalpost at 9.4 m/s. He bounces straight backward at 6.2 m/s. What was the change in velocity? What was the impulse of the player?

Answers

Answer:

i. 15.6 m/s

ii. I = 1.44 KNs

Explanation:

The impulse, I, on a body is the product of force applied on it and the time it acts.

i.e I = F x t

Impulse is sometimes expressed as the change in momentum of a body. It is measured in Ns.

i. mass, m, of the player = 92 kg

initial velocity of the player, u = 9.4 m/s

final velocity of the player, v = 6.2 m/s

Since he bounces back on hitting the pole, then the sign of initial and final velocities are of opposite sign.

So that,

change in velocity of the player = final velocity - initial velocity

                                          = 6.2 - (-9.4)

                                         = 6.2 + 9.4

                                         = 15.6 m/s

change in velocity of the player is 15.6 m/s

ii. Impulse, I = m(v - u)

                    = 92 x 15.6

                    = 1435.2

Impulse on the player is 1.44 KNs.

scientific notation

1. 0,000034
2. 0,0054
3. 346574
4. 0,00125
5. 348954

Answers

Answer:

1. 3.4 x10^-5

2. 5.4 x10^-3

3. 346574

4. 12.5x10^-4

5. 348954

Hope this helps, please mark me brainliest if it does! :)

You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a building that is 20.0 m above the ground.


a)How long after it is launched does the walnut reach the ground?

b)How far does the walnut travel horizontally from launch point to landing point?

c) What are the horizontal and vertical components of the walnut’s velocity just before it reaches the ground? Suppose that the +y-axis is directed upward and the +x-axis is directed horizontally from the launch point toward the landing point.

Answers

Answer:

a.3.51s

b.33.8m

c. 9.64,-22.9

Explanation:

(a) The time taken be "3.5083 sec".

(b) The distance will be "33.82 m".

(c) The horizontal and vertical components be "9.64 m/s and -22.89 m/s".

Velocity and Direction

According to the question,

Speed, V₀x = 15 Cos (50.0°)

                   = 9.64 m/s

            V₀y = 15 Sin (50.0°)

                   = 11.49 m/s

Vertical displacement = -20.0 m

(a) We know the relation between displacement, time and acceleration

→  y = vt + [tex]\frac{1}{2}[/tex]at²

By substituting the values,

→ -20.0 = 11.49 t - 4.9 t²

  4.9 t² - 11.49 t - 20.0 = 0

                                   t = [tex]\frac{11.49 + \sqrt{132.02+392} }{9.8}[/tex]

                                     = [tex]\frac{11.49 + 22.89}{9.8}[/tex]

                                     = 3.5083 sec

(b) We know the formula,

Distance = Speed × Time

or,

→ X = 9.64 t

      = 9.64 × 3.5083

      = 33.82 m

(c) Again by using the above relation, we get

    Vx = V₀x

          = 9.64 m/s

    Vy = V₀y - gt

By substituting the values,

          = 11.49 - 9.8 × 3.5083

          = 11.49 - 34.38

          = -22.89 m/s

Thus the response above is correct.

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How quickly will a 4 kg ball be accelerated if it is struck by a 12 N force?

Answers

Explanation:

Hey there!

Given that 4kg ball struck by 12 N force.

So, we need acceleration.

Force = Mass × Acceleration

And, so

Acceleration = Force / Mass.

Acceleration = 12/4

Acceleration is equal to 3m/s² in SI units.

Hope it helps :)

28.5 g of iron shot is added to a graduated cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL mark. From this information, calculate the density of iron.

Answers

Answer:

Density=mass/volume.

1) we have to calculate the iron volume in liters.

iron volume=second level - first level=49.10 ml-45.50 ml=3.6 ml

3.6 ml=3.6 ml(1 liter / 1000 ml)=0.0036 liters  

2) we calculate the mass iron in kg.

28.5 g=28.5 g(1 kg /1000 g)=0.0285 kg.

2) we calculate the density of iron.

density=0.0285 kg / 0.0036 liters=7.92 kg/L

7.92 kg/l=7.92 kg/L(1000 g/1Kg)(1000 cm³/1 L)=7.92 g/cm³.

From this information the Iron density is 7.92 Kg/L or  7.92 g/cm³.

Explanation:

I hope this helps u! :D

Answer:

7.92 g/cm^3

Explanation:

1 mL = 1 cm^3

density = mass/volume

volume: 49.10 mL - 45.50 mL = 3.60 mL = 3.60 cm^3

mass: 28.5 g

density = (28.5 g)/(3.60 cm^3) = 7.91666... g/cm^3

Answer: 7.92 g/cm^3

If a 5.5 kg object experiences 15 N of force for .15 seconds what is the speed change

Answers

The speed change : Δv = 0.41 m/s

Further explanation

Given

mass = 5.5 kg

Force = 15 N

time = 0.15 s

Required

the speed change

Solution

Newton 2nd's law

Impulse and momentum

F = m.a

F = m . Δv/t

F.t = m.Δv

Input the value :

15 N x 0.15 s = 5.5 kg x Δv

Δv = 0.41 m/s

PLS ANSWER FAST WILL GIVE BRAINLYEST TIMED TEST!!!!


use the equation solving a= F divided by M

Also use metres per second squared [m/s2]


A Spring balance is used to launch a 0.05 kg foam ball with a force of 5N. What acceleration is produced?

Answers

using a=f/m u get 100 bc 5/.05 =100m/s

When you push an object, it pushes back with an equal and opposite force

Answers

Answer:

I would say false

Explanation:

Because friction slows it down which means when the object bounces back it will not have the same energy or force that was applied before.

need help someone please

Answers

Answer:

C would be the correct answer.

Explain why the following statement is either true or false: The idea that all matter consists of the elements was first introduced a few hundred years ago

Answers

So i say false because 500 years is more than a few years but i could be wrong. Because of Aristotle’s idea that al matter is made up of only four elements it was accepted for over 2000 years but only around 500 years ago did scientists start discovering all of the elements known today.

It is a true statement that the idea that all matter consists of elements was first introduced a few hundred years ago.

What is the matter?

Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.

These different states of matter have different characteristics according to which they vary their volume and shape.

Individuals have believed that earth, air, water, and fire are the only four elements that make up matter for roughly two thousand years.

For more than two thousand years, Aristotle's theory that all matter is composed of just four elements was accepted, but only around 500 years ago did scientists begin to find all of the elements that are currently recognized.

Beginning around five hundred years ago, scientists started learning about all of the elements that are currently recognized.

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Formula for angular acceleration

Answers

Answer:

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]

Explanation:

The angular acceleration is given by the relation as follows :

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]

Where

[tex]\omega_i\ and\ \omega_f[/tex] are the initial and final angular velocities

t is time

The SI unit of angular acceleration is rad/s². Hence, this is the required solution.

A 9 V battery produces a current of 18 amps. What is the resistance?

Answers

[tex]\bf{ \underline{Given:- }}[/tex]

[tex] \sf• \: Battery \: Voltage \: (V) = 9 \: v[/tex]

[tex] \sf• \: Current \: (I) = 18 \: Amps.[/tex]

[tex] \\ [/tex]

[tex]\bf{ \underline{To \:  Find :- }}[/tex]

[tex] \sf• \: The \: Resistance. [/tex]

[tex] \\ [/tex]

[tex] \huge\bf{ \underline{Solution :- }}[/tex]

[tex] \bf \red{ \bigstar{ \: Formula \: of \: Resistance \: (R) = \frac{V}{I}}}[/tex]

[tex] \rightarrow \sf R = \frac{9}{18} [/tex]

[tex] \rightarrow \sf R = \frac{1}{2}[/tex]

[tex] \rightarrow \sf R = 0.5[/tex]

[tex] \\ [/tex]

[tex] \bf \purple{Therefore, \: the \: \: resistance \: \: is \: \: 0.5 \: Ω \: .}[/tex]
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