HELP PLS ASAP PLS PLS PLS

Answer:

  Q = (-2.5, -3), quadrant 3

Step-by-step explanation:

Reflection across the x-axis changes the sign of the y-coordinate.

  Q = (-2.5, -3)

With two negative coordinates, point Q is in Quadrant III.

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Additional comment

Point P has a negative x-coordinate and a positive y-coordinate, so is located northwest of the origin in Quadrant II. The quadrant that is southwest of the origin is Quadrant III, which is where points in Quadrant II are reflected to when they are reflected across the x-axis.

Answer:

Step-by-step explanation:

Area of trapezoid:

Substitute values:

Answer:

39 cm²

Step-by-step explanation:

Area of a trapezoid: [tex]\frac{a_{1} + a_{2} }{2} h[/tex]

=> [tex](\frac{4 +9}{2}) 6[/tex]

=> [tex](\frac{13}{2} )6[/tex]

=> 13 x 3

=> 39 cm²

Hoped this helped.

Answer:

y + 4 = -5(x - 15)

Step-by-step explanation:

The given line has a slope of 1/5.  Any new line perpendicular to this given line has a slope which is the negative reciprocal of 1/5:  -5.

Use the point-slope equation of a line:  y - k = m(x - h), where (h, k) is the point through which the new line passes.  Here h = 15 and k = -4, so we have:

y + 4 = -5(x - 15)

This line is perpendicular to the given line and also passes through (15, -4).

Explanation:

Factoring to linear factors generally involves finding the roots of the polynomial.

The two rules that are taught in Algebra courses for finding real roots of polynomials are ...

In general, it is a difficult problem to find irrational real factors, and even more difficult to find complex factors. The methods for finding complex factors are not generally taught in beginning Algebra courses, but may be taught in some numerical analysis courses.

Formulas exist for finding the roots of quadratic, cubic, and quartic polynomials. Above 2nd degree, they tend to be difficult to use, and may produce results that are less than easy to use. (The real roots of a cubic may be expressed in terms of cube roots of a complex number, for example.)

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Personally, I find a graphing calculator to be exceptionally useful for finding real roots. A suitable calculator can find irrational roots to calculator precision, and can use that capability to find a pair of complex roots if there is only one such pair.

There are web apps that will find all roots of virtually any polynomial of interest.

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Additional comment

Some algebra courses teach iterative methods for finding real zeros. These can include secant methods, bisection, and Newton's method iteration. There are anomalous cases that make use of these methods somewhat difficult, but they generally can work well if an approximate root value can be found.

Answer:

B.

Step-by-step explanation:

step by step explanation

Answer:

after 70 miles, company B will charge Henry more.

Step-by-step explanation:

at 70 miles both companies will charge the same price

118 = 55 + 0.9m

m = (118 - 55) divided by 0.9 = 70  

Answer:

60

Step-by-step explanation:

9*12=108

6*8=48

108-48=60

Answer:

A physical quantity is a physical property of a material or system that can be quantified by measurement.

Step-by-step explanation:

THE ANSWER IS D BUT ME 8S NOT SURE

Answer:

128/512 or 1/4

Step-by-step explanation:

(2 x 2 x 2 x 2) x (2 x 2 x 2)= 16 x 8 = 128

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(2 x 2 x 2 x 2 x 2) x (2 x 2 x 2 x 2)= 32 x 16 = 512

Answer:

0.81

Step-by-step explanation:8x1x1x 1/10 +1x1/100=0.81

Answer:

c

i think

Step-by-step explanation:

Answer:

B and C

Step-by-step explanation:

Step-by-step explanation:

you really could not find this faster right away by a search on the internet ?

the general line equation is

y = ax + b

a is always the slope, and b is the y-intercept (the y value when x = 0).

so, the slope here is 5, and the y-intercept is 7

Answer:

5.35

Step-by-step explanation:

5.3+5.4/2

10.7/2

5.35

Answer:

ln|sec(x) + tan(x)| + c

Step-by-step explanation:

∫sec(x) dx

secx = 1/cos(x) = cos(x)/cos²(x) = cos(x)/(1-sin²(x))

let u = sinx

we get ∫secx = ∫du/(1-u²) = ln√(1+u)/(1-u)

as (1+u)/(1-u) = (1+sinx)/(1-sinx) = (sec²x + tan²x)

so ln √(1+u)/(1-u) = ln√(sec²x + tan²x) = ln|secx+tanx| +c

Answer:

Step-by-step explanation:

If a - b = c then the value of b is a - c:

Answer:

x = 56

y = 68

Step-by-step explanation:

Please mark as brain list

Answer:

So what we're going to do is now take the so drdx of negative 3x plus 1 is equal drdx of x squared

Step-by-step explanation:

Answer:

- 7

Step-by-step explanation:

Given

t < - 6

Then t = - 7 is less than - 6 and is a solution

Answer:

Step-by-step explanation:

Answer:

g=2

Step-by-step explanation:

5.3g+9=2.3g+15

5.3g-2.3g=15-9

3g=6

g=6÷3

=2

Answer:

g = 2

Step-by-step explanation:

5.3g + 9 = 2.3g + 15

Subtract 2.3g from both sides

3g + 9 = 15

Subtract 9 from both sides

3g = 6

Divide both sides by 3

g = 2

Answer:

8, 1 1/2 cup servings in 12 cups of juice.

Step-by-step explanation:

I just divided 12 by 1.5

Answer:

[tex]t=-5[/tex]

Step-by-step explanation:

[tex]\frac{2t}{5} = \frac{t^{2} -5t}{5t}[/tex], [tex]t\neq 0[/tex]

[tex]\frac{2t}{5} = \frac{t(t-5)}{5t}[/tex]

[tex]\frac{2t}{5} = \frac{t-5}{5}[/tex]

[tex]2t = t-5[/tex]

[tex]t=-5[/tex]

15:12 is the equivalent ratio of 5:4

Decimal notation is a way of expressing a number in base ten but with a decimal part. Therefore, from the given question;

Number bases is a method of expressing numbers in different notations with respect to the required base. When given numbers in base ten, it is required to divide it by the number base for conversion using long division method so as to convert it to any required base. So converting each element in the given set to base 5, we have:

{1000, 1001, 1002, 1003, 1004,......, 2000}

So that:

i. 1000 converted to base 5, we have:

5  1000

5   200  r 0

5     40   r 0

5     08   r 0

5      01   r 3

       00  r 1

⇒ [tex]13000_{5}[/tex]

ii. 1001 converted to base 5, we have:

5  1001

5   200  r 1

5     40   r 0

5     08   r 0

5      01   r 3

       00  r 1

⇒ [tex]13001_{5}[/tex]

iii. 1002 converted to base 5, we have:

5  1002

5   200  r 2

5     40   r 0

5     08   r 0

5      01   r 3

       00  r 1

⇒ [tex]13002_{5}[/tex]

So then, the set in base 5 is:

{13000, 13001, 13002, 13003, 13004,......, 31000}

To determine the number whose digits have the least sum;

a. 13000 = 1 + 3 + 0 + 0 + 0 = 4

b. 13001 = 1 + 3 + 0 + 0 + 1 = 5

c. 13002  = 1 + 3 + 0 + 0 + 2 = 6

d. 13003 = 1 + 3 + 0 + 0 + 3 = 7

e. 13004 = 1 + 3 + 0 + 0 + 4 = 8

.        .        .      .    .       .           .

.        .        .      .    .       .           .

z. 31000 = 3 + 1 + 0 + 0 + 0 = 4

Thus it would be observed that in base five, 1000, 1500 and 2000 digits gave the least sum of 4, so then:

[tex]\frac{1000+1500+2000}{3}[/tex]  = 1500

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Answer:

I think its 1500

Step-by-step explanation:

1500

Answer:

"A plane does not extend infinitely"

Step-by-step explanation:

Answer:

Step-by-step explanation:

Jagdish dj dj dj dj dj hahaha

Answer:

1,2,3,2,2

Step-by-step explanation:

because standard form is ax