Answer: NOx and VOC combine chemically with oxygen to form ozone
Explanation:
assume that the collision in each scenario is elastic. a graph of the magnitude of the force exerted on cart y as a function of time for scenario 1 is shown. during which interval of time does the magnitude of the momentum of cart y change the most?
During 0.004s to 0.006s interval of time does the magnitude of the momentum of cart y change the most.
What is momentum?Momentum (more particularly linear momentum , translational momentum) is defined in Newtonian physics as the product of an object's mass and velocity. It consists of a vector quantity with magnitude and direction. If an object's mass is m and its velocity is v (also a vector quantity).
The kilogram metre per second (kgm/s) is the unit of momentum measurement in the International System of Units (SI), which really is equivalent to the newton-second. During 0.004s to 0.006s interval of time does the magnitude of the momentum of cart y change the most.
Therefore, during 0.004s to 0.006s interval of time does the magnitude of the momentum of cart y change the most.
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why was your surface pressure higher or lower than the slp of your location? if your location is falcon field, then remember that the surface pressure was measured at 245 meters above sea level.
The surface pressure is higher or lower than the SLP (Sea Level Pressure) of your location depending on the altitude at which it was measured. At Falcon Field, the surface pressure was measured at 245 meters above sea level.
This means that the pressure is lower than the SLP because the higher the altitude, the lower the atmospheric pressure. The atmospheric pressure decreases with an increase in altitude due to the decrease in the air density at higher elevations.
Surface pressure, also known as atmospheric pressure, is the pressure that the air exerts on the surface of the Earth.
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Gas particles do not respond to heat the same way people do. Do you agree with this statement? Why? Provide an example in your explanation.
Answer:
Yes, I agree with the statement that gas particles do not respond to heat the same way people do. The reason for this is that gas particles do not have the same sensory mechanisms that people have to perceive heat.
When a person is exposed to heat, their sensory nerves respond by sending signals to the brain, which then triggers a response such as sweating, increased heart rate, or a feeling of discomfort. However, gas particles do not have nerves or brains, so they cannot respond to heat in the same way.
Instead, gas particles respond to heat by increasing their kinetic energy and moving faster. This causes the gas to expand and occupy more space. For example, if a gas is heated in a container with a fixed volume, the pressure inside the container will increase as the gas particles collide more frequently with the container walls.
Additionally, unlike people, gas particles do not have a specific temperature range in which they are comfortable or safe. They will continue to gain kinetic energy and expand as long as they are exposed to heat, without any limit to their response.
In summary, gas particles and people respond to heat in fundamentally different ways due to differences in their physical and biological properties.
a motorist runs out of gas on a level road 240 m from a gas station. the driver pushes the 1,260 kg car to the gas station. if a 180 n force is required to keep the car moving, how much work (in j) does the driver do?
The work done is 43200 joules.
Work is defined as the distance traveled in the direction of the force in the product of the forces. In physics, work is energy transferred to or from an object by applying a force along a displacement. In its simplest form, work done with a constant force in the direction of motion is equal to the product of the force and the distance traveled. Work is the product of the displacement and the force component in the direction of displacement. When you do work, the kinetic energy of an object changes. In this task the force is given as 180 N to move the car he 240 m.
Work = 180 N x 240 m = 43200 J
In this case, the 1260 kg mass of the car is not needed.
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(q1) two charged spheres are 10.68 cm apart. they are moved, and the force on each of them is found to have been tripled. how far apart are they now?
The spheres are now 6.08 cm apart. The force between two charged spheres is proportional to the product of their charges and inversely proportional to the square of the distance between them.
This means that if the force is tripled, the distance between the spheres must have been reduced by a factor of the square root of 3. To find the new distance, we can use the formula:
d_new = d_old / √3
Where d_old is the original distance of 10.68 cm and d_new is the new distance. Plugging in the values, we get:
d_new = 10.68 cm / √3 = 6.08 cm
So, the spheres are now 6.08 cm apart.
In this case, F_old / F_new = 1/3, since the force has been tripled. Plugging in the original distance of 10.68 cm and the value for F_old / F_new, we can calculate the new distance. The final result shows that the spheres are now 6.08 cm apart.
This result shows how the force between charged spheres is directly influenced by the distance between them. Understanding this relationship is important in many fields, including physics, electrical engineering, and materials science.
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Calculate the time it takes a 200 W appliance to transfer 40,000 J of energ
Answer:
the answer is 200seconds(s)
what is the orbital period, to the nearest hundredth of a year, of an asteroid has a major axis length of 5.07 a.u.
The orbital period of the asteroid to the nearest hundredth of a year is 34.43 years.
The orbital period of an asteroid is given by the formula T = 2 × pi × (a³ / G × M)^(1/2). To find the orbital period, we need to calculate T using the given values for a, G, and M.
a = 5.07 a.u.
G = 6.67 x 10⁻¹¹ N × m² / kg²
M = 1.989 x 10^30 kg
T = 2 × pi × (a³ / G × M)^(1/2)
T = 2 × pi × (5.07³ / 6.67 x 10⁻¹¹ × 1.989 x 10³⁰)^(1/2)
T = 2 × pi × (156.9837 / 6.67 x 10⁻¹¹ × 1.989 x 10³⁰)^(1/2)
T = 2 × pi × (1.8048 x 10¹² / 6.67 x 10⁻¹¹ × 1.989 x 10³⁰)^(1/2)
T = 2 × pi × (1.8048 x 10¹² / 1.38 x 10⁻²³)^(1/2)
T = 2 × pi × (1.30 x 10³⁵)^(1/2)
T = 2 × pi × (3.66 x 10¹⁷)^(1/2)
T = 2 × pi × 1.91 x 10⁹
T = 12.57 x 10⁹
T = 12.57 / 365.25
T = 34.43 years
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if a car moving at 90 mi/h takes 300 ft to stop with uniform acceleration after its brakes are applied, how far will it take to stop under the same conditions if its initial velocity is 45 mi/h ?
If the car is initially moving at a speed of 45 mi/h and it takes 300 ft to stop with uniform acceleration after its brakes are applied, it will take 600 ft to stop under the same conditions.
This is because the deceleration is the same, but the initial velocity is halved.
Acceleration is the rate of change of velocity of an object with respect to time. It is a vector quantity which is defined as the rate of change of an object's velocity and is usually represented by the symbol a. Acceleration can be caused by a variety of factors, including external forces, changes in direction, or changes in speed. In physics, acceleration can be described as the rate of change of an object's velocity over a period of time.
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at 20!c, a brass cube has edge length 30 cm. what is the in- crease in the surface area when it is heated from 20!c to 75!c?
The increase in surface area when the temperature rises from 20 to 75 degrees Celsius. = 11cm².
What transpires as the temperature rises?Heat waves will probably occur more frequently and persist longer as a result of the higher temperatures. Heat waves can be deadly, leading to conditions like heat cramps and heat stroke as well as actual mortality. Additionally, warmer temperatures have the potential to trigger a variety of other changes all around the world.
What is the name for rising temperatures?A fever is defined as a rise in body temperature above what is regarded as normal. It's also known as a high temperature, hyperthermia, or pyrexia, and it typically indicates that your body is attempting to protect you from an infection.
According to the given information:The increase in the surface area of the brass cube (which has six faces), which had side length L at 20 o, is
Δ A - 6(L - ΔL)² - 6L²
12LΔL = 12abL²ΔT
= 12(19 x 10⁻⁶/c)(30cm)²
=(75c - 20c)
= 11cm²
The increase in surface area when the temperature rises from 20 to 75 degrees Celsius. = 11cm².
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c) A thin plano-convex lens is made of glass of refractive index 1.5 when an object is set
up 10 cm from the lens, a virtual image ten times its size is formed. What is: i) focal
length of lens? ii) the radius of curvature of the lens surface? (Ans: f=11.1 cm, R= 55.6
cm)
Answer:
i) The focal length of the lens is 11.1 cm. ii) The radius of curvature of the lens surface is 55.6 cm.
Explanation:
Given: refractive index of glass = 1.5, object distance u = -10 cm, image distance v = 100 cm (since the image is virtual and ten times the size of the object), and the thickness of the lens t is small.
i) To find the focal length f, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values, we get:
1/f = 1/100 - 1/-101/f = 0.01 + 0.11/f = 0.11f = 1/0.11f = 9.09 cm
However, this is the focal length of the lens surface. Since the lens is thin, we can assume that the thickness is negligible compared to the focal length.
Therefore, the focal length of the lens is approximately equal to the focal length of the lens surface, which is 9.09 cm.
The focal length of the thin plano-convex lens is -11.1 cm and the radius of curvature of the lens surface is 55.6 cm. These values are obtained by applying the lens-maker formula and considering the given conditions.
Explanation:In this question, a thin plano-convex lens made of glass with a refractive index of 1.5 is described. An object is placed 10 cm from this lens and a virtual image ten times the size of the object is formed. We are required to find the focal length of the lens and the radius of curvature of the lens surface.
Using the lens-maker formula, 1/f = (n-1)(1/R1 - 1/R2 ), and considering the object distance (u) as -10 cm (the negative sign is due to the convention for virtual images), and the image distance (v) as -100 cm (ten times the object size), we find that the focal length (f) of the lens is -11.1 cm.
Next, applying the lens-maker formula again, but this time for the radius of curvature (R) of the lens surface. Since one surface of the lens is plane (R1 = ∞), the radius of curvature is that of the convex side (R2), we obtain R = 55.6 cm.
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what happens to the average kinetic energy when the average velocity of the molecules is increased by a factor of 2.
The average kinetic energy is increased by 4 times when the average velocity of the molecules is increased by a factor of 2.
It is given that the average velocity that is average velocity is increased by a factor of 2, so it is increased by 2 x times.
Another formula to calculate kinetic energy,
[tex]\dfrac{1}{2} \times m \times v^2[/tex]
Kinetic energy will also increase by, 4 times as it is proportional to the square of velocity.
Average kinetic energy is a function of gas molecule speed, increasing temperature causes the gas molecules to move more quickly, which raises the average kinetic energy of the gas molecule.
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examining your graph, how would you describe the relationship between vapor pressure and temperature? is it linear? explain this relationship in terms of the kinetic energy of the molecules.
The pressure that a gas, at a constant temperature, exerts over a liquid surface is known as vapour pressure. Since the kinetic energy of molecules increases with temperature, vapour pressure likewise rises.
As a result, more molecules possess the necessary energy to transform from a liquid to a gas.
The pressure that a gas, at a constant temperature, exerts over a liquid surface is known as vapour pressure. Due to the fact that more molecules have adequate kinetic energy to transition from a liquid to a gas as the temperature rises, the vapour pressure likewise rises.
A liquid or solid's vapour pressure increases along with its temperature. On the other hand, when the temperature drops, the vapour pressure drops.
There are several techniques to calculate a liquid's vapour pressure. A little amount of the liquid is injected into a closed flask that is attached to a manometer for a straightforward measurement.
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The desorption of a single molecular layer of n-butane from a single crystal of aluminum oxide was found to be first order with a rate constant of 0. 128/s at 150 K. The half life of the reaction is 5. 41sPart BIf the surface is initially completely covered with n-butane at 150 K, how long will it take for 25% of the molecules to desorb?Part CFor 50% to desorb?Part DIf the surface is initially completely covered, what fraction will remain covered after 14s ?Part EAfter 20s ?
It was discovered that the rate of desorption of a single molecular layer of n-butane from a single crystal of aluminum oxide was first order. constant of 0. 128/s at 150 K , Half life=[tex]\frac {ln(2)}{k}[/tex]=5.415 s
For first order desorption:
In([tex]\frac {N}{N_o}[/tex]) =-kt and [tex]\frac {N}{N_o}[/tex] = [tex]e^{(-kt)[/tex] where N is the number of molecules remaining at time t, No is initial number and k is rate constant
(A) Half life=[tex]\frac {ln(2)}{k}[/tex]=5.415 s
(B) 25% desorbs [tex]\rightarrow[/tex] 75% remains
⇒ [tex]\frac {N}{N_o}[/tex] x 100% = 75% => [tex]\frac {N}{N_o}[/tex]=0.75
In(0.75)=-0.128 x t
Time t = 2.25 s
(C) 50% desorbs ⇒ 50% remains
=> [tex]\frac {N}{N_o}[/tex] x 100% = 50% => [tex]\frac {N}{N_o}[/tex]= 0.50
In(0.50) = -0.128 x t
Time t = 5.42 S
(D) For t = 14 s
Fraction remaining= [tex]\frac {N}{N_o}[/tex] =[tex]e^{(-0.128 \times 14)[/tex]
Fraction remaining= -0.167 (approximately 0.17)
(E) For t = 20 s
Fraction remaining= [tex]\frac {N}{N_o}[/tex] = [tex]e^{(-0.128 \times 20)[/tex]
Fraction remaining= -0.0773 (approximately 0.077)
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how many different wavelengths of emitted light are emitted by those atoms as the electrons fall into
6 possible falls producing 6 wavelengths so the Correct option is C)
no. of radiation = [tex]^{4} C_2=\frac{4\times3}{2}[/tex] =6
a wave's wavelength is the separation between two adjacent waves' corresponding points. Two points or particles that are in the same phase—i.e., points that have completed identical fractions of their periodic motion—are referred to as "corresponding points." Wavelength is typically measured from crest to crest or from trough to trough in transverse waves (waves with points vibrating at right angles to the direction of their advance); from compression to compression or from rarefaction to rarefaction in longitudinal waves (waves with points vibrating in the same direction as their advance).
6 possible falls producing 6 wavelengths
4 → 3, 4→2 , 4→1
3→2,3→1
2→1
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which of the following describes a hypothesis? multiple choice question. any information we collect about the physical universe using our senses an explanation that has been proven correct a general principle that is derived from hundreds of observations and experiments a tentative explanation for a natural phenomenon
A tentative explanation for a natural phenomenon describes hypothesis .
A straightforward hypothesis can indicate that there is a causal relationship—that is, that one variable affects the other—between two variables. Here's an illustration: Higher grades are the result of more time spent preparing for a test. The number of hours spent studying is the independent variable in this statement, and the result is the dependent variable. The independent variable is altered while the dependent variable is evaluated to ascertain how the dependent variable is impacted by the independent variable. Similar to a simple hypothesis, a complex hypothesis has two or more independent variables and/or two or more dependent variables.
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the radius of the sun is 696,000km. if its period is 587.28 hours, what is its tangential velocity at the equator? (
The tangential velocity of the sun at the equator is, 2370.25π km/hr.
Tangential velocity is the linear component of the speed of any object which is moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center.
The equation for velocity is v = ΔxΔt. Using the circumference of the circle as the distance and the time as the period, we can rewrite the equation for velocity: v = 2πr/T.
Plug in the given values and solve for the velocity.
v = 2π (696,000km)/587.28 hr
v = π × 1392000km/587.28 hr
v = 2370.25π km/hr
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calculate the magnitude (in m/s2) of the centripetal acceleration at the tip of a 3.20 m long helicopter blade that rotates at 205 rev/min. m/s2
The magnitude of the centripetal acceleration at the tip of a 3.20 m long helicopter blade that rotates at 205 rev/min is 1,474.7 m/s2
The acceleration that a body experiences when moving around in a circle is known as centripetal acceleration. Since velocity is a vector quantity (that is, it possesses both a magnitude, which is the speed, and a direction), when a body travels on a circular path, its direction is constantly changing, and as a result, its velocity is changing as well, which results in an acceleration. The acceleration is exerted in a radial direction that is directed toward the center of the circle. To calculate the centripetal acceleration, we can use this following formula:
Ac = v² ÷ r
V = ωr
Ac = (ωr)² ÷ r
Ac = ω²r
ω = 205 rev/min = 21.47 rad/s
r = 3.20 m
Next, we can substitute the required values to find the centripetal acceleration:
Ac = (21.47 rad/s)² × 3.20 m
Ac = 1,474.7 m/s²
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a baseball is released with an initial velocity of 29.4 m/s at an angle of 30.0 degrees above the horizontal. what is the maximum height that the ball reaches during its trajectory?
The ball's maximum height during its trajectory is 22.05 meters.
Which launch angle causes the ball to travel the furthest horizontally above level ground?Maximum range (dx) is obtained at an angle of 45°. The most horizontal distance is covered at an angle of 45 degrees or nearly there. The greatest possible height will be attained and the longest duration spent in the air when the angle is 90 degrees or higher.
What is the maximum height formula?The formula for determining the greatest height, ymax, is: vy 2 = vy(0)2 + 2 ay (y - y(0)). To get ymax = vy(0)2/ 2g, substitute into y(t) = vy(0) t - 12 g t2. The beginning velocity in the y-direction and the maximum height are used to calculate the maximum height.
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an object is 30 cm in front of a converging lens with a focal length of 5 cm. use ray tracing to determine the location of the image. is the image upright or inverted?
A 5 cm focal length converging lens is 30 cm away from the item being observed. The image is real but it is inverted.
Converging lens: what is it?Light is directed to a location at the focal spot or axis of a convergent lens. a lens that creates a true image by converting parallel light beams to convergent light rays. The image is actual and inverted as longer as the thing is not within the focal point.
What shape is a convergent lens?Since the rays concentrate after passing through the convex lens, convex lenses are indeed known as converging lenses. Since the rays disperse after striking the concave lens, curvy lenses are also known as converging lenses.
u = Object distance
= 30 cm
v = Image distance
f = Focal length
= 5 cm
Lens Equation,
1/f = 1/u + 1/v
1/f - 1/u = 1/v
1/v = 1/5 - 1/30
1/v = 1/6
v = 6cm
m = -v/u
m = -6/30
m = -0.2
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Make A CER about this Question --> as an asteroid collided with Earth in the ancient past and what were the effects of this collision? PLEASE HELP PLEASE PLEASE PLEASE PLEASE PLEASE !
It is widely believed that an asteroid impact was responsible for the extinction of the dinosaurs and many other species, which took place approximately 65 million years ago.
What are the effects of collision of the asteroids?The exact effects of this collision would have been massive, including:
A massive shockwave that would have caused widespread destruction and firesA tsunamis that would have flooded coastlinesA massive release of dust and debris into the atmosphere, blocking out the sun and causing a cooling of the planetA release of massive amounts of heat and energy, which would have caused massive fires and further atmospheric disruption.These events likely had a significant and long-lasting impact on the Earth's environment and ecology, and led to one of the largest mass extinctions in Earth's history.
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A 2.0 kg object moving east at 4.0 m/s collides
with a 5.0 kg object moving west at 6.0 m/s.
The two objects stick together after the
collision. Determine the speed of the two
objects after the collision.
The speed of the objects after collision, given that they stocked together is 5.4 m/s
How do I determine the speed of the objects after collision?We'll beging by listing out the given parameters from the question. This is given below:
Mass of object moving east (m₁) = 2.0 KgSpeed of object moving east (u₁) = 4.0 m/sMass of object moving west (m₂) = 5.0 KgSpeed of object moving west (u₂) = 6.0 m/sSpeed after collision (v) =?The speed after the collision can be obtained as shown below:
Momentum before = momentum after
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(2 × 4) + (5 × 6) = v(2 + 5)
8 + 30 = v × 7
38 = v × 7
Divide both sides by 7
v = 38 / 7
v = 5.4 m/s
Thus, the speed after collision is 5.4 m/s
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joe and bob needed to move a trunk with a mass of 75kg the trunk is too heavy to life so the boys slide it 12 meters to the waiting truck. the coefficient of sliding friction between the trunk and the floor is 0.20 the entire task is accomplished in 13 seconds
weight of truck:
how much force is excerted on the truck:
how much work is done to move the trunk:
what is the power exerted:
The weight of the trunk is 735 N
The force of friction is 147 N
The force exerted on the trunk is 882 N
The work done to move the trunk is 10,584 J
The power exerted is 814 W
How to calculate?The weight of the trunk can be calculated as :
Weight = 75 kg * 9.8 m/s^2 = 735 N
The force of friction can be calculated as:
Friction = μ * N = 0.20 * 735 N = 147 N
The force exerted on the trunk can be calculated as :
Force = Weight + Friction = 735 N + 147 N = 882 N
The work done to move the trunk can be calculated as
Work = Force * Distance = 882 N * 12 m = 10,584 J
The power exerted can be calculated as :
Power = Work / Time = 10,584 J / 13 s = 814 W.
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Help me please I am struggling
A wave is a disturbance in a medium. The speed of a wave can be calculated by the formula: V = λf.
What is a Wave?A wave is a propagating dynamic disturbance of one or more quantities such as sound and light. Waves can be periodic, in which case those quantities oscillate repeatedly about an equilibrium value at some frequency.
V = λf
where, V is the velocity of wave,
λ is the wavelength,
f is the frequency.
1. Time period = 0.25 second
Frequency of a wave = 1/T
F = 1/ 0.25
F = 4 sec⁻¹
2. Speed of the wave with frequency 5.0 Hz and wavelength 10cm
v = λf
v = 10 × 5.0
v = 50 cm/s
3. Frequency of a wave with speed 20cm/s and wavelength 10cm
v = λf
f = λ/v
f = 10/20
f = 1/2 or 0.5 Hz
4. Wavelength of a wave when frequency is 5.0 Hz and speed 30 cm/s
v = λf
λ = v/f
λ = 30/5
λ = 6cm
5. Speed of a wave when the period is 3 sec and wavelength is 20m
Period = 1/f
3 = 1/f
f = 1/3
v = λf
v = 20 × 1/3
v = 6.66m/s
6. Wavelength of the wave when frequency is 75 Hz and speed is 300m/s
v = λf
λ = v/f
λ = 300/ 75
λ = 4m
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a car traveling with an initial velocity of 20 m/s accelerates at a constant rate of 3.2 m/s2 for 6 seconds. what distance does the car travel during this process?
The vehicle accelerates steadily around 3 m/s2 for 15 sec while moving at 20 m/s. This indicates that when the car accelerates, it will cover a total length of 75 metres.
What is acceleration, exactly?An item that follows a circular course while maintaining a constant speed is still moving forward because the source of its motion is shifting.
Additionally, it is either the first variant of velocity in relation to time or the second derivative for position in relation to time.
What time is it?The time frame that can be measured or quantified.
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through a piece of copper wire 20 cm long and with a cross-sectional area of \u200b\u200b0.6 mm ^ 2 a charge of 4 cells is passed in 0.1 s. determine the voltage at the ends of the wire
The voltage across the wire is 1332 V.
What is voltage ?Voltage is a measure of electrical potential difference between two points in a circuit. It is a measure of the amount of electrical energy available to do work. Voltage is measured in volts (V). The voltage between two points is the difference in electrical potential between those two points. Voltage is the force pushing electrons through a circuit and is responsible for the current that flows in a circuit. The higher the voltage, the greater the current. Voltage is created when charge is stored in a capacitor or a battery.
The voltage across the wire is determined by Ohm's law, In this case, the resistance of the wire is given by R = L/A, where L is the length of the wire (20 cm) and A is the cross-sectional area of the wire (0.6 mm^2). Therefore, the resistance of the wire is 33.3 Ω.
The current is given by I = Q/t, where Q is the charge (4 cells) and t is the time (0.1 s). Therefore, the current is 40 A.
Using Ohm's law, we can calculate the voltage across the wire: V = IR = (40 A)(33.3 Ω) = 1332 V.
Therefore, the voltage across the wire is 1332 V.
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2.4 Displacement of 27m north,31 m east,63m south and 58m west. Take east as the positive x-direction and north as the positive y-direction. 3. Check 2.4 with an accurate tail to head vector diagram
The resultant displacement of the object is 45 m.
What is the displacement of the object?
The resultant displacement of the object is calculated as follows;
Sum of the vertical displacement of the object is calculated as;
y = 27 m - 63 m = -36 m
Sum of the horizontal displacement of the object is calculated as;
x = 31 m - 58 m = -27 m
The resultant displacement of the object is calculated as follows;
d = √ [ ( -36² ) + ( - 27² ) ]
d = 45 m
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The complete question is below;
2.4 Displacement of 27m north,31 m east,63m south and 58m west. Take east as the positive x-direction and north as the positive y-direction. 3. Check 2.4 with an accurate tail to head vector diagram. Calculate the resultant displacement of the vector
5) what is the gravitational potential energy (relative to infinite) of a 5.00x103 kg satellite that is in orbit with a radius of 9.90x106 m around the earth?
P.E -1.57 × 10¹¹J is the gravitational potential energy.
Give the definition of gravitational potential energy
The energy that an object acquires as a result of its height or vertical position is known as gravitational potential energy. When we elevate items against Earth's gravity, the energy is held back by the gravitational force.
The energy that an item has or acquires when its location changes as a result of being in a gravitational field is known as gravitational potential energy. Gravitational potential energy can be defined as an energy that has a connection to gravitational force or gravity.
P.E = -GMm/r
m = 5000kg
r = 9.9 × 10⁶ m
G = 6.67 × 10⁻¹¹
M = 5.18 × 10²⁴
P.E = -(6.67 × 10⁻¹¹ *5.18 × 10²⁴ × 5000) / ( 9.9 × 10⁶ + 6.38 × 10⁶)
P.E = -1.57 × 10¹¹J
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suppose electric current is going through a 960 ohm resistor and you use a voltmeter to measure a potential difference of 4.98 volts across the two terminals of the resistor. what must be the current in amperes going through this resistor?
The current in amperes going through this resistor is 0.005208 Amperes or 5.208 mA.
Ohm's law is one of the most fundamental laws of electrical engineering. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. Mathematically, the relationship is given by the equation: I = V / R, where I is the current in amperes, V is the voltage in volts, and R is the resistance in ohms.
In our example, we are given a resistor with a resistance of 960 ohms and a potential difference (voltage) of 4.98 volts across its two terminals. We need to divide the voltage by the resistance to find the current flowing through the resistor. Using the equation I = V / R, we have: I = 4.98 volts / 960 ohms = 0.005208 Amperes or 5.208 milliamperes.
So, the current flowing through the 960-ohm resistor is 5.208 milliamperes.
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oppositely charged parallel plates are separated by 5.96 mm. a potential difference of 600 v exists between the plates. (a) what is the magnitude of the electric field between the plates?
The magnitude of the electric field between the oppositely charged parallel plates is 100,336 N/C.
The electric field (E) between the parallel plates can be calculated using the following formula:
E = V / d
where V is the potential difference between the plates and d is the separation distance between the plates.
In this case, the potential difference is 600 V and the separation distance is 5.96 mm = 0.00596 m.
So, the magnitude of the electric field between the plates can be calculated as:
E = 600 V / 0.00596 m = 100,336 N/C
Therefore, the magnitude of the electric field between the oppositely charged parallel plates is 100,336 N/C.
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a 12kg koala is swinging in a circular path perpendicular to the ground. the koala moves in a clockwise direction with a constant speed of 2m/s . what is the velocity of the koala at the bottom of the circle?
The velocity of the koala at the bottom of the circle is 2.23 m/s.
The velocity of the koala at the bottom of the circle can be determined by considering the concepts of centripetal force and centripetal acceleration. Centripetal force is the force that acts towards the center of the circle and is responsible for keeping the object moving in a circular path. Centripetal acceleration is defined as the acceleration of an object moving in a circular path, and it can be calculated as follows: a = [tex]v^{2}[/tex] / r, where v is the velocity of the object and r is the radius of the circle.
v = [tex]\sqrt{g\times r}[/tex], where v is the velocity, g is the acceleration due to gravity (9.8 m/[tex]s^{2}[/tex]), and r is the radius of the circular path.
Since the speed of the koala is constant at 2 m/s, we can use this value to find the radius of the circular path:
r = [tex]v^{2}[/tex] / g
r = [tex](2 m/s)^2[/tex] / (9.8 m/[tex]s^{2}[/tex])
r = 0.408 m
Now that we have the radius, we can use the equation for centripetal velocity to find the velocity of the koala at the bottom of the circle:
v = [tex]\sqrt{g\times r}[/tex]
v = √(9.8 m/[tex]s^{2}[/tex] × 0.408 m)
v = 2.23 m/s
Since the speed of the koala is constant, its velocity at the bottom of the circle will be equal to its speed, which is 2.23 m/s.. Hence, the velocity of the koala at the bottom of the circle is 2.23 m/s.
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