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Answer:

382.74 kJ.

Explanation:

The work that must be done to stop an 1100 kg car travelling at 59  km/h is  - 382.74 kJ.

The work needed to stop an 1100 kilograms car moving with a velocity of  59.0 km/hr would be  147.72 kilojoules.

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

Work Done = Force * Displacement

As given in the problem we have to find out how much work is needed to stop a 1,110-kilogram car that is moving straight down the highway at 59.0 kilometers/hour

the mass of the car = 1100 kilograms

the velocity of the car = 59 kilometers/hour

KE = 0.5mv²

     =0.5×1100×(59×1000/3600)²

     = 147.72 kilojoules

Thus, the work needed to stop an 1100 kilograms car would be  147.72 kilojoules

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Answer:

Explanation:

The common observable evidence are:

The big bang is the theory which explains that how the universe began. It says that the universe began with just a single point. It went on expanding and stretched to grow as large as possible. It is still now expanding.

The big bang consist of fully dark matter, interstellar gases or dust. The big bang is increasing just because in universe there is abundant of hydrogen and helium.

The radiations come from the big bang. These rays are also called as cosmic wave. This big bang is still on it way of expanding more.

Thus, the observational evidence are the measured abundances of element, the expansion of space and the cosmic wave background.

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Hi there!

We can begin by calculating the acceleration using the kinematic equation:

d = vit + 1/2at²

Since the rocket starts from rest, we can rewrite this as:

d = 1/2at²

Plug in given values:

4.2 = 1/2a(0.137²) ⇒ a = 447.55 m/s²

Now, we can use Newton's Second Law to find the appropriate force:

∑F = m · a

∑F = 50,000 · 447.55 = 22,377,500 N

Answer:

A + B = B - A

The above equation must hold for the sum and difference to be zero.

How can one of the vectors not be zero?????

Answer:

The orbital speeds of stars far from the galactic center are surprisingly high, suggesting that these stars are feeling gravitational effects from unseen matter in the halo.

Answer: molecular solid

Explanation:

The velocity and acceleration of the particle moving round the circle is;

Velocity = 162.12 m/s

Velocity = 162.12 m/sAcceleration = 6.873 × 10^(-5) m/s²

We are given;

Radius of circle; 382400 km = 382400000 m

Time; t = 27.3 days = 27.3 × 86400 s = 2358720 s

Now, formula for velocity is;

Velocity = distance/time

Thus;

I) velocity = 382400000/2358720

Velocity = 162.12 m/s

II) Acceleration is centripetal acceleration and is given by the formula;

a = v²/r

a = 162.12²/382400000

a = 6.873 × 10^(-5) m/s²

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Answer:

ill go with B

Explanation:

inertia is the ability of a body to remain at rest or in a constant speed in a constant direction when no force is acting on it

Answer:its 3 and 5

Explanation:

j

Answer:

112 [kJ]

Explanation:

1) related formula is: A=F*S, where A - required work [J], F - force [N], S - distance [m].

2) according to the formula above: A=140*800=112000[J]=112 [kJ]

Answer:

112000 J

Explanation:

800N x 140m

Answer:

Wavelength and speed both depend on the material of the medium.

Explanation:

Let [tex]f[/tex] denote the frequency of a wave. Let [tex]v[/tex] denote the speed of that wave in a given medium. Let [tex]\lambda[/tex] denote the wavelength of that wave in this medium.

The frequency [tex]f[/tex] of a wave stays the same regardless of the material of the media. However, the speed [tex]v[/tex] of a wave indeed depends on the material of the medium (density of the medium, etc.)

[tex]\lambda = v / f[/tex] and [tex]f[/tex] stays the same regardless of the medium. Thus, the wavelength [tex]\lambda[/tex] of this wave in a given medium would be proportional to the speed [tex]v[/tex] in that medium.

For example, the speed of sound in materials with a larger density (e.g., water) is generally larger than that in materials with lower density (e.g., air.)

When a sound wave travels from air into water, the frequency [tex]f[/tex] of this wave would stay the same. However, since the speed [tex]v[/tex] of the wave would increase, the wavelength [tex]\lambda[/tex] of this wave would also increase.

Answer:

High water level during a tide is called High tide.

Low water level during a tide is called Low tide.

Answer:

It is unique among planets in our solar system for having water in its liquid form at the surface, in an amount conducive to life evolving. ... No one knows why Earth has the exact amount of water it does, which is relatively small considering that water molecules outnumber silicate molecules in the galaxy, he said. so no one actually found out who actually put water on the earth and why

Explanation:

Answer:

It is the only planet in our solar system that has water in its liquid state at the surface in sufficient quantities to support the evolution of life. Despite the fact that water molecules outnumber silicate molecules in the galaxy, no one understands why Earth has the precise quantity of water it has, which is a minuscule amount when compared to the rest of the galaxy.

Explanation:

Hope it helps:)

Answer:

radiation

Explanation:

Answer:

B is most likely forgive me if im wrong

Explanation:

Answer:

the acceleration of the rocket is: a=vemΔmΔt−g a = v e m Δ m Δ t − g .

Explanation:

I answered this before.

hope this helps! :)

Answer:

refers to the bending of light

the fact or phenomenon of light, radio waves, etc. being deflected in passing obliquely through the interface between one medium and another or through a medium of varying density.

unlock your third eye and youll be able to see it

Answer:

C

Explanation:

Tama Po yan don't worry

Answer: 4.44302176697 m/s^2

Explanation:

formula for acceleration is (final velocity - initial velocity)/time.   So in your case:

(34.7m/s - 0m/s)/ 7.81s  = 4.44302176697 m/s^2

Answer:The 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.

As we move away from the nucleus, the values of the principal quantum number (n) continues to increase.

As the principal quantum number (n) increases, the orbital becomes farther away from the nucleus.

The higher energy orbital are always larger than the orbitals closer to the nucleus.

Hence, the 2s orbital different than the 1s orbital because the 2s orbital extends farther from the nucleus than the 1s.

Explanation:

Answer: if you double the pressure, you will halve the volume. If you increase the pressure 10 times, the volume will decrease 10 times.

Explanation:

The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

The impulse experienced by the ball is calculated as follows;

[tex]Ft = \Delta P[/tex]

where;

[tex]Ft[/tex] is impulse

[tex]\Delta P[/tex] is change in momentum

The time of motion of the ball is calculated as follows;

[tex]t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s[/tex]

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

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Answer:

d/t = (230 km)/(3.25 h) = 70.8 km/h.

Explanation:

The linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s

We find the linear speed of a point on the 32nd parallel from v = rω where r = radius of 32nd parallel north = Rcos32° (since it is the radius of the small circle at the 32nd parallel) where R = radius of earth = 6,371,000 m and ω = angular speed of the earth = 2π/T where T = period of earth = 24h = 24 × 60 × 60 s = 86400 s.

So, v = rω

v = Rcos32° × 2π/T

v = 2πRcos32°/T

substituting the values of the variables into the equation, we have

v = 2πRcos32°/T

v = 2π × 6,371,000 m × cos32°/86400 s.

v = 2π × 6,371,000 m × 0.8480/86400 s.

v = 33947512.5035 m/86400 s

v = 392.91 m/s

So, the linear speed of a point located on the 32nd parallel, as a result of Earth’s rotation is 392.91 m/s

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The density of the object is 5911.94 kg/m³

An object's buoyancy is the upward force produced by a fluid in opposition to the weight of a partly or totally submerged object.

The buoyancy = weight of the object - weight in water

= 15 N - 13N

= 2 N

The buoyancy force can also be determined by using the expressed:

[tex]\mathbf{F_B = Volume (V) \times density ( \rho) \times g}[/tex]

[tex]\mathbf{2 = Volume (V) \times788 \ kg/m^3 \times9.8 }[/tex]

[tex]\mathbf{ Volume (V) = \dfrac{2}{ 788 \ kg/m^3 \times9.8 }}[/tex]

volume (v) = 2.589 × 10⁻⁴m³

Recall that:

The mass of an object can be estimated by using the formula:

Weight = mass × gravity

mass = Weight / gravity

mass = 15/9.8

mass = 1.5306 kg

The density of the object can now be calculated using the relation

Density = mass/volume

Density = 1.5306 kg / 2.589 × 10⁻⁴m³

Density = 5911.94 kg/m³

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Answer:

C.) decreases, stronger

Explanation:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases; however, as the two objects are closer to each other, the force of the gravitational attraction between them also increases (stronger).