Help mee A scout troop are hiking in a forest. Starting from their base, they walk 4.2km south followed by 7.1km west. They want to walk the shortest distance back to their base. On what bearing should the scouts walk?

Answers

Answer 1

Answer:

They should walk on a bearing of 59.4 degrees

Step-by-step explanation:

Given

[tex]South = 4.2km[/tex]

[tex]West = 7.1km[/tex]

Required

The bearing back to the base

The given question is illustrated with the attached image.

To do this, we simply calculate the measure of angle a using:

[tex]\tan(a) = \frac{Opposite}{Adjacent}[/tex]

[tex]\tan(a) = \frac{7.1}{4,2}[/tex]

[tex]\tan(a) = 1.6905[/tex]

Take arctan of both sides

[tex]a = \tan^{-1}(1.6905)[/tex]

[tex]a = 59.4^o[/tex]

Help Mee A Scout Troop Are Hiking In A Forest. Starting From Their Base, They Walk 4.2km South Followed
Answer 2

The bearing that the scout should work is N59.4W for the shortest distance

Trigonometric ratio

Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.

Let  A represent the angle that the scouts walk

tan∠A = 4.2/7.1

A = 30.6°

The bearing that the scout should work is N59.4W (90 - 30.6) for the shortest distance

Find out more on Trigonometric ratio at: https://brainly.com/question/4326804


Related Questions

what is the sum of all the exterior angle of a polygon ​

Answers

Answer:

From what I learn it is 360 degrees

Darryl is finding the product of -5y(-4y^3+6y^2-5) Is he correct? If not, what changes should be made?

Answers

Answer:

A. Yes, Darryl’s work is correct.

Step-by-step explanation:

-5y(-4y^3 + 6y^2 -5)

Darryl used distributive property
Where the outside number (-5y) is being multiplied by all of the numbers in parentheses

-5y • -4y^3 = 20y^4

Two negative numbers multiplied makes a positive number and an extra y on -5y makes y^4

-5y • 6y^2 = -30y^3

Since -5y is being multiplied by a positive number, the product becomes negative. Extra y^3 comes from the y in -5

-5y • -5 = 25y

Two negatives are being multiplied causing the product to be a positive number and keeping the variable the same value.

Finally, add all of the results!

20y^4 + -30y^3 + 25y =
20y^4 - 30y^3 + 25y






Helppp and explain !!!!

Answers

Answer:

try 4

Step-by-step explanation:

basically need to find number that when multiplied 3 times equals 64 so 4*4*4=64

answer is 4

x^3 = 64

this means a number to the third power is equal to 64. in other words, a number multiplied by itself 3 times equals 64

x= cube root of 64

64 is a perfect cube, which are best to memorize. 4 x 4 x 4 = 64 so x = 4

hamood spelled backwards is hamood also let me know if u want my account by 12 AM PDT 6/2/21

Answers

Answer:

yo congratulations on finishing 10th grade (congratulate me on finishing 8th)

hamood spelled backwards is doomah so...um...

also do u mean 7/2/21..bc 6/2/21 is like in June and we're in July

3. The following are the scores you shot in five rounds of golf: 70,80,75,75,80. The variance is: A. 3.74 C. 14 B. 196 D. 70​

Answers

Answer:

Option C.

Step-by-step explanation:

For a given set of N elements:

{x₁, x₂, ..., xₙ}

The mean is given by:

[tex]M = \frac{x_1 + x_2 + ... + x_n}{N}[/tex]

And the variance is given by:

[tex]v = \frac{(x_1 - M)^2 + (x_2 - M)^2 + ... + (x_n - M)^2}{N}[/tex]

Then for our set:

{70, 80 ,75, 75, 80}

We have 5 elements, then N = 5

The first thing we need to find is the mean.

[tex]M = \frac{70 + 80 + 75 + 75 + 80}{5} = 76[/tex]

Then the variance will be:

[tex]v = \frac{(70 - 76)^2 + (80 - 76)^2 + (75 - 76)^2 + (75 - 76)^2 + (80 - 76)^2}{5} = 14[/tex]

The correct option is C, 14.

Find the value of x that will make A||B.

Please help!

Answers

Answer:

x=30

Step-by-step explanation:

Hi there!

For A to be parallel to B, 5x would be equal to 3x+60. (If they were parallel, these two angles would be alternate exterior angles, which are equal.)

[tex]5x=3x+60[/tex]

Subtract 3x from both sides

[tex]5x-3x=3x+60-3x\\2x=60[/tex]

Divide both sides by 2

[tex]x=30[/tex]

I hope this helps!

The area (A) of a circle is a function of its radius (r) and is given by the function A=f(r)=pie r^2. What is the domain of this function
A. All positive real numbers
B. All real numbers
C. All positive real numbers including 0
D. All real numbers excluding fraction

Answers

all positive real numbers. in this function, the domain is the radius. all real numbers includes negative numbers, and u cant have a negative distance. you also cant have a radius of 0 because the circle wouldnt exist. and u can have a fraction domain, so A is the answer

What is the midpoint of the segment shown below?

Answers

Step-by-step explanation:

simply take the average of the x and y coordinates

Beth wants to build a thin wire frame for a photo that is $$15 cm long and $$6 cm wide. What length of wire will she need to go around the entire photo?

Answers

Answer:

42

Step-by-step explanation:

1. Perimeter

Perimeter is [tex]2l+2w[/tex]

2. Solving[tex]2(15)+2(6)=30+12=42[/tex]

Answer: 42

Hope this helped! Please mark brainliest :)

Solve for x. Round to the nearest tenth of a degree, if necessary

Answers

Answer:

31.80°

Step-by-step explanation:

In ∆ ABC :-

sin x = BC / AC sin x = 39/74 x = sin -¹ ( 39/74) x = 31.80 °

the lines given by the equations y=6x and y=6x+2 are ____

Answers

They are parallel, as shown by the graph.

The owner of a coffee shop compared the amount of hot coffee per day, in fluid ounces, sold and the daily high temp. In degrees f per day, 5.9x+850=

Answers

The question is not complete as the scatter plot is missing.

Thus, I have attached the complete question showing the scatter plot.

Answer:

D: On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee

Step-by-step explanation:

From the attached image showing the question and scatter plot, we can see that the scatter plot is modeled by the line; y = -5.9x + 850

Where;

x is the high temperature in °F

y is the amount of fluid ounces sold

Let's try x = 0°F

Thus;

y = 0 + 850

y = 850 fluid ounces

Let's try x = 10°F

Thus;

y = -5.9(10) + 850

y = 850 - 59

y = 791

This means for every increase in temperature of 10°F, the amount sold is approximately 60 fluid ounces lesser.

Looking at the options in the attached file, the only correct one that corresponds to our answer is option D where it says;. On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee

What should the follow equations is equivalent to 6.87p+9.2=-7.056

Answers

Answer:

P=-2.3662299854

Step-by-step explanation:

6.87p = - 7.056 -9.2

So 6.87p= - 16.256

P=-2.3662299854

When two parallel lines are cut by a transversal then the interior angles on the same side of the transversal are

Answers

Answer:

Same side interior angles

Step-by-step explanation:

Same side interior angles are interior angles and on the same side. Sorry don't know how to better explain.

What is the value of p?
A)180
B)90
C) 116
D)58

Can someone help I don’t understand

Answers

Answer:

58

Step-by-step explanation:

What is the first step in solving the equation x2 - 25 = 0?
What is the second step in solving the equation?

Answers

Answer:

first step - make x² the subject of the formula

x² = 25

second step :

find the square root of both sides

√x² = √25

x = 5

Step-by-step explanation:

At maximum speed, an airplane travels
1680 miles against the wind in 5 hours.
Flying with the wind. the plane can
travel the same distance in 4 hours.
What is the speed of the plane with no wind?

Answers

Answer:

The speed of the plane with no wind is 378 miles per hour.

Step-by-step explanation:

Since at maximum speed, an airplane travels 1680 miles against the wind in 5 hours, and flying with the wind. the plane can travel the same distance in 4 hours, to determine what is the speed of the plane with no wind, the following calculation must be performed:

Against the wind = 1680/5 = 336

With the wind = 1680/4 = 420

420 - ((420 - 336) / 2) = X

420 - 42 = X

378 = X

Therefore, the speed of the plane with no wind is 378 miles per hour.

solve the problems. write the complete proof in your paper homework and for online (only) complete the probing statement (if any) that is a part of your proof or related to it

Answers

Answer:

[tex]m \angle A = m \angle C[/tex] by reason [tex]\overline{AB} \cong \overline{BC}[/tex] and [tex]m \angle B = m \angle M = m \angle P[/tex].

[tex]\triangle AMO \cong \triangle CPO[/tex] SAS Theorem

Step-by-step explanation:

We proceed to demonstrate the statement by Geometric means:

1) [tex]\overline{AB} \cong \overline{BC}[/tex], [tex]\overline {AM} \cong \overline {PC}[/tex], [tex]m\angle AMO = m\angle CPO[/tex] Given.

2) [tex]\frac{AM}{AB} = \frac{PC}{BC}[/tex] Proportionality.

3) [tex]\frac{AM}{AM + MB} = \frac{PC}{BP + PC}[/tex] Definition of line segments.

4) [tex]\frac{1}{1+\frac{MB}{AM} } = \frac{1}{\frac{BP}{PC}+1}[/tex] Algebra.

5) [tex]\frac{BP}{PC} + 1 = 1 +\frac{MB}{AM}[/tex] Algebra.

6) [tex]\frac{BP}{PC} = \frac{MB}{AM}[/tex] Algebra.

7) [tex]BP = BM[/tex] By 1)

8) [tex]m \angle B = m \angle M = m \angle P[/tex] By 1), 7)

9) [tex]\triangle AMO \sim \triangle ABC[/tex], [tex]\triangle CPO \sim \triangle ABC[/tex] By 1), 7), 8). Defintion of simmilarity.

10) [tex]\frac{AM}{MO} = \frac{AB}{BC}[/tex], [tex]\frac{PO}{PC} = \frac{AB}{BC}[/tex] Definition of proportionality.

11) [tex]\frac{AM}{MO} = \frac{PO}{PC}[/tex] Algebra.

12) [tex]AM^{2} = PO\cdot MO[/tex] Algebra.

13) [tex]PO = MO[/tex] By 12) and Algebra.

14) [tex]\overline{PO} \cong \overline{MO}[/tex] By 13).

15) [tex]\triangle AMO \cong \triangle CPO[/tex] SAS Theorem/Result.

What is the circumference of D if the length of EF is 9 cm?

Answers

Answer:

It should be B,  180 cm

Step-by-step explanation:

x = circumference of  circle D

18/360 = 9/x

9*360 = 18x

9*360/18 = x

x = 180

Arturo is building a flower bed in the shape of a right triangle. The hypotenuse of the right triangle is 13 feet. One of the legs needs to be 7 feet longer than the other leg.

Which equation can be used to find x, the length of the shorter leg?

x(x + 7) = 13
x(x + 7) = 169
x2 + (x + 7)2 = 13
x2 + (x + 7)2 = 169

Answers

Answer:

x(x + 7) = 169

Step-by-step explanation:

We are given that

Let length of shorter leg of right triangle = x ft

Length of other leg = x+7 ft

Hypotenuse of right triangle = 13 ft

We have to find the equation which can be used to find x, the length of shorter leg.

By pythagorous theorem

(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2

Substitute the values then, we get

(13)^2=x^2+(x+7)^2

x^2+(x+7)^2=169

This is required equation which can used to find x.

Answer:

d. x2 + (x + 7)2 = 169

Step-by-step explanation:

use Pythagorean theorem, substitute in the given values, and you get this

7 of 8
Write the number three million and eighty-two thousand in figures

Answers

Answer:

3,082,000

Step-by-step explanation:

THE ANSWER IS 3,082,000 HOPE IT HELPS

A circular sheet covers 425cm on the table,find the area of the sheet.



solve this question plz.​

Answers

Answer:

sorry i cannot help you

What is the standard form equation of the line shown below? Graph of a line going through negative 1, 5 and 2, 4

Answers

Answer:

y = -1/3x + 14/3

Step-by-step explanation:

We have the standard equation as;

y = mx + b

where m is the slope and b is the y-intercept

the given points are;

(-1,5) and (2,4)

So we plug x and y for each of the points

then we create two linear equations which we can solve simultaneously to get the values of m and b

From the points;

5 = -m + b•••••••(i)

4 = 2m + b

from i;

b = 5 + m

substitute this into equation ii

4 = 2m + 5 + m

4 = 3m + 5

4-5 = 3m

3m = -1

m = -1/3

Recall;

b = 5 + m

b = 5-1/3

b = 14/3

so we have the equation as;

y = -1/3x + 14/3

Multiply through by 3

3y = -x + 14

Solve for congruent triangles

Answers

Answer:

11. B.

12. C.

13. A.

14. D.

Step-by-step explanation:

for 11: we know that angles D and J are congruent from the tick marks, we also know that ∠FKD and ∠LKJ are congruent (vertical angles are congruent) therefore we need the sides between them

for 12: we know that ∠STU and ∠TUG are congruent, we also know that line TU is congruent to TU (reflexive property), therefore we need the angles adjacent to the first angles listed.

for 13: we know that ∠PQR and ∠CQR are congruent, we also know that lines RQ and RQ are congruent (reflexive property), therefore we need the other angles to which line RQ is between.

for 14: we know ∠B is congruent to ∠T and line AB is congruent to line ZY. therefore the angle cannot be connected to lines AB and ZY.

question 3 help pls in algebra

Answers

Answer:

50

Step-by-step explanation:

simplify the radical by breaking the redicand up into a product of known factors, assuming positive real numbers.

Describe the steps required to determine the equation of a quadratic function given its zeros and a point.

Answers

Answer:

Procedure:

1) Form a system of 3 linear equations based on the two zeroes and a point.

2) Solve the resulting system by analytical methods.

3) Substitute all coefficients.

Step-by-step explanation:

A quadratic function is a polynomial of the form:

[tex]y = a\cdot x^{2}+b\cdot x + c[/tex] (1)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]a[/tex], [tex]b[/tex], [tex]c[/tex] - Coefficients.

A value of [tex]x[/tex] is a zero of the quadratic function if and only if [tex]y = 0[/tex]. By Fundamental Theorem of Algebra, quadratic functions with real coefficients may have two real solutions. We know the following three points: [tex]A(x,y) = (r_{1}, 0)[/tex], [tex]B(x,y) = (r_{2},0)[/tex] and [tex]C(x,y) = (x,y)[/tex]

Based on such information, we form the following system of linear equations:

[tex]a\cdot r_{1}^{2}+b\cdot r_{1} + c = 0[/tex] (2)

[tex]a\cdot r_{2}^{2}+b\cdot r_{2} + c = 0[/tex] (3)

[tex]a\cdot x^{2} + b\cdot x + c = y[/tex] (4)

There are several forms of solving the system of equations. We decide to solve for all coefficients by determinants:

[tex]a = \frac{\left|\begin{array}{ccc}0&r_{1}&1\\0&r_{2}&1\\y&x&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]a = \frac{y\cdot r_{1}-y\cdot r_{2}}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x+x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]a = \frac{y\cdot (r_{1}-r_{2})}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]b = \frac{\left|\begin{array}{ccc}r_{1}^{2}&0&1\\r_{2}^{2}&0&1\\x^{2}&y&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]b = \frac{(r_{2}^{2}-r_{1}^{2})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]c = \frac{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&0\\r_{2}^{2}&r_{2}&0\\x^{2}&x&y\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]c = \frac{(r_{1}^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x + x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

And finally we obtain the equation of the quadratic function given two zeroes and a point.

given the figure below, what is the value of x?

Answers

Answer:

x = 6

Step-by-step explanation:

6 is x so this is the answer


Pls answer 13 b ill mark u brainlist

Answers

Answer:

7 students

Step-by-step explanation:

1+2+4=7students

Find all solutions to the equation
in the interval [0, 21). Enter the
solutions in increasing order.
sin 2x = 2 sin x
x = [?],[1]
TT
Remember: sin 20 = 2 sin 0 cos 0

Answers

Answer:

[tex]x=0, \\x=\pi[/tex]

Step-by-step explanation:

Recall the trigonometric identity [tex]\sin 2x=2\sin x\cos x[/tex].

Therefore, given [tex]\sin 2x=2\sin x[/tex], rewrite the left side of the equation:

[tex]2\sin x\cos x=2\sin x[/tex]

Subtract [tex]\sin x[/tex] from both sides:

[tex]2\sin x\cos x-2\sin x=0[/tex]

Factor out [tex]2\sin x[/tex] from both terms on the left:

[tex]2\sin x(\cos x-1)=0[/tex]

We now have two cases:

[tex]\begin{cases}2\sin x=0, x=k\pi\text{ for }k\in \mathbb{Z}\\\cos x-1=0,x=k2\pi\text{ for }k\in \mathbb{Z}\end{cases}[/tex]

Since the problem stipulates that [tex]x[/tex] is in the interval [tex][0, 2\pi)[/tex], we have:

[tex]\text{For }x\in [0, 2\pi):\\\sin x=0\rightarrow \boxed{x=0, x=\pi}\\\cos x-1=0\rightarrow \boxed{x=0}[/tex]

Recall that square brackets mean inclusive and parentheses mean exclusive. Therefore, [tex]2\pi \notin [0, 2\pi)[/tex].

Can someone please help me. If you do thanks

Answers

Answer:

(B)

Step-by-step explanation:

Can't explain lol, but that's the answer

Yes the answer is B!
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