Help me plz i can't figure this out

Answer:

(a) $83 for 6 snacks

(b) [tex]y = 65 + 3x[/tex] --- for x snacks

Step-by-step explanation:

Given

Let:

[tex]n \to people[/tex]

[tex]ticket =\$13[/tex] --- per individual

[tex]snacks = \$3[/tex] --- per individual

Solving (a): Amount for 6 snacks

The amount paid (y) is:

[tex]y = ticket * n + snacks * 6[/tex] ---- because she bought 6 snacks

[tex]y = 13 * n + 3 * 6[/tex]

[tex]y = 13n + 18[/tex]

[tex]n = 5[/tex] ---- Annabelle and the 4 kids.

So:

[tex]y =13*5+18[/tex]

[tex]y =65+18[/tex]

[tex]y =83[/tex]

Solving (b): For x snacks

The amount paid (y) is:

[tex]y = ticket * n + snacks * x[/tex] ---- because she bought x snacks

[tex]y = 13* 5 + 3* x[/tex]

[tex]y = 65 + 3x[/tex]

Answer:

Step-by-step explanation:

Since all the grids have 100 squares, which grid has all squares shaded? And which grid has 40 (4 columns) shaded? This add up to 100+40=140. The answer, of course, is C+D (last answer). None of the others have enough shaded squares

Answer:

Step-by-step explanation:

for circle

diameter = 26 cm

radius = diamtere/2

=26/2

=13 cm

area of circle  = πr^2

=3.14^13^2

=3.14*169

=530.66 cm^2

=531 cm^2   (after round off )

area of square= l^2

=5.1^2

=26.01 mi^2

are of rectangle = l *b

=6*5.1

=30.6 m^2

area of triangle = base*height / 2

=9*6.4 / 2

=57.6 / 2

=28.8 yd^2

Answer:

551.8

Step-by-step explanation:

5.2\times 104 is 540.8

1.3\times 10-2 is 11

540.8 + 11 =551.8

Answer:

The answer is 676.

Step-by-step explanation:

I think you mean 5.2 multiplied by [tex]10^{4}[/tex], and 1.3 multiplied by [tex]10^{-2}[/tex].

Or do you mean 5.2 multiplied by 104 and 1.3 multiplied by 10 then subtract 2? Not really clear, but I'm going to go with the first option.

5.2 * [tex]10^{4}[/tex] = 52,000

1.3 * [tex]10^{-2}[/tex] = 0.013

52,000 * 0.013 = 676

The answer is 676.

Answer:

D. The coefficient of determination is the ratio of the explained variation to the total variation.

C. The coefficient of determination is the percent of variation of y that is explained by the relationship between x and y

Step-by-step explanation:

The Coefficient of determination is the ratio of the explained variation in y to the total variation in y.

Coefficient of determination, r² ;

r² = explained variation / total variation

The coefficient of determination is the proportion of variation in y (predicted value) which is due to the regression line ; Hence, it is the percent of variation of y that is explained by the relationship between x and y.

Answer:

x2+y2−12x+4y−60=0

The center of the circle is point: C=(6,−2).

The radius of the circle is r=10.

Answer:

4

Step-by-step explanation:

T = 9

T = 4F - 7

9 = 4F - 7

16 = 4F

F = 4

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: {b}^{2} + 2b - 24}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {Step-by-step\:explanation:}}}[/tex]

[tex] \: (b + 6)(b - 4)[/tex]

➼[tex] \: b \: (b - 4) + 6 \: (b - 4)[/tex]

➼[tex] \: {b}^{2} - 4b + 6b - 24[/tex]

Combining like terms, we have

➼[tex] \: {b}^{2} + 2b - 24[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

9514 1404 393

Answer:

Step-by-step explanation:

Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...

  x + y = 85 . . . . . combined weight of a large and small box

  70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes

We can subtract 50 times the first equation from the second to find the weight of a large box.

  (70x +50y) -50(x +y) = (5350) -50(85)

  20x = 1100 . . . . simplify

  x = 55 . . . . . . . divide by 20

Using this in the first equation, we can find the weight of a small box.

  55 +y = 85

  y = 30 . . . . . . . subtract 55

A large box weighs 55 pounds; a small box weighs 30 pounds.

Answer:

57

Step-by-step explanation:

31-3=28

31-2=29

28+29=57

Answer:

V≈718.38 cm cubed

Answer:

A i think

Step-by-step explanation:

edge 2021

The simplified expression is - f(x) = [tex]log_{2} (\frac{x^{3} (x+4)}{3}})[/tex]

We have the following statement -

3 log Subscript 2 Baseline x minus (log Subscript 2 Baseline 3 minus log Subscript 2 Baseline (x + 4))

We have to convert it into Single logarithm.

Logarithm is a quantity representing the power to which a fixed number (the base) must be raised to produce a given number.

[tex]log_{b} (b^{x} ) = x[/tex]

According to the question, We can write the given statement in the mathematical form as follows -

f(x) = [tex]3\;log_{2} (x )-[log_{2} (3) -log_{2} (x+4)][/tex]

Using the property of logarithm -

log (A) - log(B) = log ([tex]\frac{A}{B}[/tex]), we get -

f(x) = [tex]3\;log_{2} (x )-log_{2} (\frac{3}{x+4} )[/tex]

Using the property of logarithm -

[tex]a\;log (b) = log(b^{a})[/tex]

f(x) = [tex]log_{2} (x^{3} )-log_{2} (\frac{3}{x+4} )[/tex]

f(x) = [tex]log_{2} (\frac{x^{3}}{\frac{3}{x+4}} )[/tex]

f(x) = [tex]log_{2} (\frac{x^{3} (x+4)}{3}})[/tex]

Hence, the simplified expression is - f(x) = [tex]log_{2} (\frac{x^{3} (x+4)}{3}})[/tex]

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Answer:

tom sleep 14hour my ans lt might help you

Answer:

242 m³ of space is there in the fort.

Step-by-step explanation:

Given that,

The dimensions of first box is 4 meters long, 8 meters wide, and 8 meters high.

The dimensions of the second box is 2 meters long, 7 meters wide, and 1 meter high.

Space left = Volume of first box - volume of second box

= (4)(8)(8) - 2(7)(1)

= 242 m³

So, 242 m³ of space is there in the fort.

Answer:

The Third one

Step-by-step explanation:

Your Welcome :)

Graph of the function is attached below.

Correct option is D.

As the name suggests, the exponential function contains an exponent. Note, however, that the exponential function has a constant as its base and a variable as its exponent, not vice versa (if a function has a variable as its base and a constant as its exponent, it is a power function). The exponential function can be in one of the following forms:

Definition of exponential function

In mathematics, an exponential function is a function of the form f(x) = aˣ. where "x" is a variable and "a" is a constant  called the base of the function, which must be greater than 0.

Given, exponential function

f(x) = (1/4)4ˣ

exponential function is defined for x∈R

Putting x = 0

f(0) = (1/4)4⁰

f(0) = 1/4

Point on curve is (0,1/4)

Putting x = 1

f(1) = (1/4)4¹

f(1) = (1/4)4

f(1) = 1

Point on curve is (1,1)

Putting x = 2

f(2) = (1/4)4²

f(2) = (1/4)16

f(2) = 4

Point on curve is (2,4)

Putting x = 3

f(3) = (1/4)4³

f(3) = (1/4)64

f(3) = 16

Point on curve is (3,16)

Point (0, 1/4), (1, 1), (2, 4), (3, 16) can be used to draw graph of the function.

Hence, graph of the function is drawn as follows.

Learn more about exponential function here:

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Answer:

download gauthmath it will help you answer this

Answer:

Step-by-step explanation:x=2y-8

4y=3.(2y-8)+6

4y=6y-24+6

4y-6y=-24+6

-2y=-18

Y=9

X=2Y-8

x=2.9-8=10

Step-by-step explanation:

of what ? there is nothing here to work with.

be a little bit more careful to at least understand the meaning of the problem, Ame what is given to you written with to solve the problem. because we here also need that information. we would need to read in a Crystal ball what your teacher wants from you, if you don't give us that information.

and I am good but not that good ...

Answer:

I think B

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

The lengths of the sides can be found using the distance formula.

  d = √((x2 -x1)^2 +(y2 -y1)^2)

  AC = √((0 -(-2))^2 +(8 -2)^2) = √(4+36) = 2√10

  BC = √((0 -6)^2 +(8 -2)^2) = √(36+36) = 6√2

The distance AB is the difference of the x-coordinates of the points: 6-(-2) = 8.

Then the perimeter is ...

  P = a + b + c = 6√2 +2√10 +8 = 8.49 +6.32 +8 = 22.81 . . . units

__

The height of the triangle is the difference in y-values between vertex C and line AB: 8 -2 = 6. The area is given by the formula ...

  A = 1/2bh

  A = 1/2(8)(6) = 24 . . . square units

The solution is given below.

A number line is a pictorial representation of numbers on a straight line. In elementary mathematics, a number line is a picture of a graduated straight line that serves as visual representation of the real numbers. Every point of a number line is assumed to correspond to a real number, and every real number to a point.

here, we have,

Refer to the fraction strip to show 3/4 & 6/8 are same.

Also if you reduce 6/8 by dividing 2 to numerator & denominator…

it’s 3/4.

The solution is attached below.

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Answer:

12/1=60/5

1/12=60/5

Answer:

B and C

Step-by-step explanation:

Answer:

the perdom

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Answer:

8xy+12y/5

Step-by-step explanation:

write the division as a fraction

4(2x+3)/5 y

Calaucte the product

4y(2x+3)/5

Distbtute 4y through the parentheis  

8xy+12y/5

which gives you 8xy+12y/5

Answer:

|-2| + |5|

Step-by-step explanation:

Dennis walks from (–5, –2) to (–5, 5) on the map.

Point on the format (x,y). On the x-coordinate, he stayed at the same position, x = -5, so it does not enter the distance calculation.

On the y-coordinate, he went from -2 to 5, so the distance is of:

[tex]d = 5 - (-2) = 5 + 2 = |5| + |2| = |5| + |-2| = 7[/tex]

So the correct option is |-2| + |5|

Answer:

y = 0.9

Step-by-step explanation:

1.05 + 0.7y = 3.5y - 1.47

-3.5y + 0.7y = -1.47 - 1.05

-2.8y = -2.52

y = 9/10 = 0.9

Answer:

[tex]\textbf{HELLO!!}[/tex]

[tex]0.7\left(1.5+y\right)=3.5y-1.47[/tex]

[tex]1.05+0.7y=3.5y-1.47 \gets \textsl{Expand}[/tex]

[tex]1.05+0.7y-1.05=3.5y-1.47-1.05 \gets Subtract\; 1.05 \from\:both\:sides[/tex]

[tex]0.7y=3.5y-2.52[/tex]

[tex]0.7y-3.5y=3.5y-2.52-3.5y[/tex]

[tex]\mathrm{Subtract\:}3.5y\mathrm{\:from\:both\:sides} \nwarrow[/tex]

[tex]-2.8y=-2.52[/tex]

[tex]\frac{-2.8y}{-2.8}=\frac{-2.52}{-2.8} \hookleftarrow \mathrm{Divide\:both\:sides\:by\:}-2.8[/tex]

[tex]\boxed{\boxed{\underline{\textsf{\textbf{y=0.9}}}}}[/tex]

[tex]\bullet \bullet \bullet \bullet \bullet \bullet \bullet \bullet \bullet \bullet \bullet \bullet \bullet[/tex]

[tex]\textbf{HOPE IT HELPS}[/tex]

[tex]\textbf{HAVE A GREAT DAY!!}[/tex]