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Answer: Because these low summer temperatures limit the growth of plants in the summer

Explanation: Took the test!

In an ecosystem, like  Arctic's tundra,  though very cold for much of year, is said to be more strongly defined by its cool summer temperatures, instead of its winter lows because these low summer temperatures limit growth of plants in  summer.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other.As a result of this transfer of matter and energy takes place through the system .Living organisms also influence the quantity of biomass present.By decomposition of dead plants and animals by microbes nutrients are released back in to the soil.

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Answer:

5,000,000 joules

Explanation:

Formula for Potential Energy =mgh

mass*gravity*height

mass=weight ÷ by gravity

10000÷10= 1000

1000×10×500m=5,000,000 joules

The mass, in grams, of lead that will be produced from the illustrated reaction would be 71.47 grams

From the balanced equation of the reaction:

Pb(NO3)2 + 2NaCl ---> PbCl2 + 2NaNo3

Mole ratio of Pb(NO3)2 and NaCl = 1:2

Mole of 15.3 g NaCl = 15.3/58.4

 = 0.257 moles

Mole of 60.8 g PbCl(NO3)2 = 60.8/331.2

  = 0.184 moles

Thus, NaCl is limiting.

Mole ratio of NaCl to PbCl2 = 1:1

Mas of 0.257 moles PbCl2 = 0.257 x 278.1

 = 71.47 grams

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Answer:

I will find the answer for you

Explanation:

Just a minute

Hydrocarbons are composed of hydrogen and carbon only and the hydrocarbon produced will differ according to their mole ratio.

Hydrocarbons are compounds composed only of carbon and hydrogen.

Hydrocarbons are very large families of compounds which have a common property of being combustible.

Hydrocarbons include:

The mole ratio of the carbon to hydrogen in each type of hydrocarbon differs.

Therefore, starting with 10 carbon and 3 Hydrogen, the hydrocarbon produced will differ according to their mole ratio.

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Answer:

otherwise you will be bord and have nothing to do

Explanation:

The amount of heat absorbed in kilojoules when 3.5 moles of water react is 1635.08 KJ

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂  ΔH = 2803 KJ

From the balanced equation for above,

6 moles of water reacted to absorb 2803 KJ of heat

From the balanced equation for above,

6 moles of water reacted to absorb 2803 KJ of heat

Therefore,

3.5 moles of water will react to absorb = (3.5 × 2803) / 6 = 1635.08 KJ of heat

Thus, 1635.08 KJ of heat were absorbed by the reaction.

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Copper will turn green and calcium will turn orange.  this is as a result of the atomic transitions visible in line spectra

Transition elements are substances with partially filled d orbitals, sometimes referred to as transition metals. According to IUPAC, a transition element is an element with a partially filled d subshell or one with the capacity to create stable cations that has an unfilled d orbital.

As a result of their transitional behavior between s-block or p-block elements, the d-block elements are referred to as transition elements. Their characteristics are intermediate between those of the covalently-bonded, highly reactive s-block metallic elements and those of the p-block elements.

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Answer:

answer in the picture above

That is correct! It is a positive ion!

A. The number of molecules in 0.750 mole of KNO₃ is 4.515×10²³ molecules

B. The mass (in milligrams) of 2.39×10²⁰ molecules of Ag₂SO₄ is 124 mg

C. The number of molecules in 3.429 g of NaHCO₂ is 3.04×10²² molecules

1 mole of substance = 6.02×10²³ molecules

1 mole of KNO₃ = 6.02×10²³ molecules

Therefore,

0.750 mole of KNO₃ = 0.75 × 6.02×10²³

0.750 mole of KNO₃ = 4.515×10²³ molecules

6.02×10²³ molecules = 312 g of Ag₂SO₄

Therefore,

2.39×10²⁰ molecules = (2.39×10²⁰ × 312) / 6.02×10²³

2.39×10²⁰ molecules = 0.124 g

Multiply by 1000 to express in mg

2.39×10²⁰ molecules = 0.124 g × 1000

2.39×10²⁰ molecules = 124 mg of Ag₂SO₄

68 g of NaHCO₂ = 6.02×10²³ molecules

Therefore,

3.429 g of NaHCO₂ = (3.429 × 6.02×10²³) / 68

3.429 g of NaHCO₂ = 3.04×10²² molecules

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Answer:

Single-replacement reaction

Explanation:

Single-replacement reactions, aka. single-displacement reactions, involve one element/ion in a compound being replaced by another element/ion. In this case, aluminum is replacing the iron in the compound.

If you need help visualizing, the equation looks like this:

Fe₂O₃ + Al³⁺ --> Al₂O₃ + Fe³⁺

Since 220 mL of oxygen gas was collected over water, the pressure exerted by only the oxygen gas is 720.8 mmHg

The total pressure of a gas collected over water is given by P = P' + p where

Making P' subject of the formula, we have

P' = P - p

Since the total pressure of oxygen plus water vapor is P = 745.8 mmHg, substituting the values of the variables into the equation, we have

P' = P - p

P' = 745.8 mmHg - 25 mmHg

P' = 720.8 mmHg

So, Since 220 mL of oxygen gas was collected over water, the pressure exerted by only the oxygen gas is 720.8 mmHg

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Explanation:

Their force of attraction is strongest in the middle of the magnet.

Answer:

Distillation can be used to separate and collect a liquid from a solution. Distillation can also be used to soften water as the water evaporates as it is heated and the ions are left behind. Hard water can be softened by adding sodium carbonate (washing soda) or by passing the water through an ion-exchange column.

Explanation:

Sinve CH3NH2 is weak base and its salt is CH3NH3Cl, mixing 125.0 mL of CH3NH2 and 120.0 mL of CH3NH3Cl so produce a buffer.

A buffer is a solution which resists changes to its pH when a small quantity of strong acid or base is added to it..

A buffer is made from a weak acid and its salt or a weak base and its salt.

From the given options, CH3NH2 is weak base and its salt is CH3NH3Cl.

Therefore, mixing 125.0 mL of CH3NH2 and 120.0 mL of CH3NH3Cl so produce a buffer.

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Answer:

Combination reactions

Explanation:

Hope this helps:)

Now

[tex]\\ \rm\rightarrowtail Q=mc\delta T[/tex]

[tex]\\ \rm\rightarrowtail Q=20(40)(0.13)[/tex]

[tex]\\ \rm\rightarrowtail Q=800(0.13)[/tex]

[tex]\\ \rm\rightarrowtail Q=104J[/tex]

Answer:

• Information and media literacy

Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

Activity

Part A

Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil

War started? Base your

Explanation:

• Information and media literacy

Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

Activity

Part A

Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil

War started? Base your

Answer: =378.94000053g

Explanation:

I think that explains it

The pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

The pH of a buffer solution can be calculated by initially calculating the millimoles of both the conjugate base and acid.

From, Henderson Hasselbalch equation,

pH = pKa + log conjugate base/acid

pka of HCl = -6.3

-6.3 + log 262.5/185.9

6.3 + 0.15

pH = 6.45

Therefore, the pH of the buffer prepared by adding 275 mL of .676M of HCl to 500 mL of .525M sodium acetate is 6.45.

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Hi!

[tex]\\ \sf\rightarrow pH=-log[H^+][/tex]

[tex]\\ \sf\rightarrow -log[H^+]=6.1[/tex]

[tex]\\ \sf\rightarrow log[H^+]=-6.1[/tex]

[tex]\\ \sf\rightarrow [H^+]=10^{-6.1}[/tex]

[tex]\\ \sf\rightarrow [H^+]=7.94M[/tex]

Answer:

Explanation:

alculate the (H3O+) for a solution whose pH is 6.79

Note: blank 1 should have three significant figures

The answer is: Blank 1 X 10^Blank 2

The pH of a solution is the negative logarithm of H₃O⁺ ion concentration.The concentration of H₃O⁺ ions in a solution with a pH of 6.79 is 1.6 × 10⁻⁷M.

pH of a solution is the measure of its acidity or basicity. Mathematically it is the negative logarithm of its  H₃O⁺ ion concentration. A solution with a pH of 7 is neutral.

The solution with a pH below 7 is acidic and above 7 is basic. Thus, the higher H+ ion concentration, then the pH will be lower and more acidic the solution.

It is given that the pH of the solution is 6.79. The concentration of  H₃O⁺ ions in the solution is calculated is calculated as follows:

pH   = -log ( H₃O⁺)

6.79 = -log( H₃O⁺

[ H₃O⁺] = antilog (-6.79)

             =  1.6 × 10⁻⁷M

Hence, the  hydronium ion H₃O⁺ ion concentration of the solution of pH 6.79 is  1.6 × 10⁻⁷M.

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Answer:

Sulfur (S) has 3 shells.

Explanation:

The first shell can have up to 2 electrons. The second and third shells have up to 8 electrons as well. This makes the maximum of each shell to be 2, 10, and 18. Sulfur has 16 electrons so it has more than the second shell but less than the third shell. So, it will have 3 shells with a valence of 2 since it is missing 2 electrons to create a full shell.

The interaction which will occur when the non sticky tape pieces are turned towards each other is attraction.

This involves the coming together of objects as a result of a force. When non-sticky sides of the tape are brought towards each other attraction takes place due to the sticky content.

This however wears off after some time thereby making it the most appropriate choice.

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I agree with idea of Kevin because bakong soda dissociates faster in hot water than cold water.

Baking soda is a chemical that can undergo a decomposition reaction when heated. At 80 degrees Celsius, sodium bicarbonate starts to break down into sodium carbonate (Na2CO3), water (H2O) and carbon dioxide (CO2) which is ready for reaction with other chemical.

So we can conclude that Kevin idea is correct because bakong soda dissociates faster in hot water than cold water.

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