Help me please thank you

Answer:

Step-by-step explanation:

12x - 2 + 20x - 10 = 180

32x - 12 = 180

32x = 192

x = 6

12*6 - 2

72 - 2 = 70

the solution is b

Answer: It will be 4 or -5.

Step-by-step explanation:

Answer:

x = 4, -5

Step-by-step explanation:

Step 1: Write out expression

0 = (x - 4)(x + 5)

Step 2: Find roots

x - 4 = 0

x = 4

x + 5 = 0

x = -5

Answer:

3/8, 5/8, 3/4, 7/8, 4/3

Step-by-step explanation:

Divide distance walked by time:

2 1/4 miles / 2/3 hours = 3 3/8 miles per hour

Answer:  82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB [tex]=\sqrt{(9+1)^2+(-1-7)^2}[/tex] units  [By distance formula : [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]]

[tex]=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41}[/tex] units

Width = BC = [tex]\sqrt{(-1+5)^2+(7-2)^2}[/tex] units

[tex]=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}[/tex]

Area = length x width

= [tex]2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}[/tex]

Hence, the  area of the rectangle is 82 sq. units .

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Hi my lil bunny!

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[tex]y= [-7-6][/tex]

[tex]y = -13[/tex]

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Have a great day/night!

❀*May*❀

Answer:

45

Step-by-step explanation:

Answer: 45

Step-by-step explanation: Parentheses first.

10-1=9. Next is multiplication. 5(9)=45.

Answer:

Step-by-step explanation:

Circumference of a circle = πd

where

d is the diameter of the circle

From the question

Circumference = 56.52 inches

π = 3.14

To find the diameter substitute the value of the circumstance into the above formula and solve for the diameter

That's

56.52 = πd

[tex]d = \frac{56.52}{\pi} \\ d = \frac{56.52}{3.14} [/tex]

We have the final answer as

Hope this helps you

The diameter of Dion's bicycle tire is 18 inches.

The length of the perimeter of the circle is known as the Circumference. Mathematically, [tex]C=2\pi r[/tex]

The circumference of the bicycle tire is 56.52 inches.

So,

[tex]2\pi r=56.52\\r=\dfrac{56.52}{2\times 3.14}\\r=9 inches[/tex]

So, the diameter of the bicycle tire is [tex]9\times 2= 18[/tex] inches.

Thus, the diameter of the bicycle tire is 18 inches.

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Answer:

Step-by-step explanation:

-7y = -10x - 8

y = 10/7x + 8/7

Answer:

x = -1

Step-by-step explanation:

[tex]Midpoint =(1,2)= (x,y)\\J(3,-3)=(x_1,y_1) \:and\:K(x,7)= (x_2,y_2)\\\\x = \frac{x_1+x_2}{2} \\\\1 = \frac{3+x}{2}\\ \\Cross\:Multiply \\2\times 1 = 3+x\\2 =3+x\\2-3=x\\-1=x\\\\x =-1[/tex]

Answer:

(a) the probability that an individual distance is greater than 214.80 cm is 0.1401.

(b) The probability that the mean for 15 randomly selected distances is greater than 204.00 cm is 0.2482.

(c) The normal distribution can be used because the original population has a normal distribution.

Step-by-step explanation:

We are given that the overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 8.6 cm.

(a) Let X = the overhead reach distances of adult females.

The z-score probability distribution for the normal distribution is given by;

                         Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)  

where, [tex]\mu[/tex] = population mean reach distance = 205.5 cm  

           [tex]\sigma[/tex] = standard deviation = 8.6 cm

So, X ~ Normal([tex]\mu=205.5,\sigma^{2} =8.6^{2}[/tex])

Now, the probability that an individual distance is greater than 214.80 cm is given by = P(X > 214.80 cm)

    P(X > 214.80 cm) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{214.80-205.5}{8.6}[/tex] ) = P(Z > 1.08) = 1 - P(Z [tex]\leq[/tex] 1.08)

                                                                    = 1 - 0.8599 = 0.1401

The above probability is calculated by looking at the value of x = 1.08 in the z table which has an area of 0.8599.

(b) Let [tex]\bar X[/tex] = the sample mean selected distances.

The z-score probability distribution for the sample mean is given by;

                                   Z  =  [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]  ~ N(0,1)  

where, [tex]\mu[/tex] = population mean reach distance = 205.5 cm  

           [tex]\sigma[/tex] = standard deviation = 8.6 cm

           n = sample size = 15

Now, the probability that the mean for 15 randomly selected distances is greater than 204.00 cm is given by = P([tex]\bar X[/tex] > 204.00 cm)

    P([tex]\bar X[/tex] > 204 cm) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{204-205.5}{\frac{8.6}{\sqrt{15} } }[/tex] ) = P(Z > -0.68) = 1 - P(Z [tex]\leq[/tex] 0.68)

                                                                    = 1 - 0.7518 = 0.2482

The above probability is calculated by looking at the value of x = 0.68 in the z table which has an area of 0.7518.

(c) The normal distribution can be used in part​ (b), even though the sample size does not exceed​ 30 because the original population has a normal distribution and the sample of 15 randomly selected distances has been taken from the population itself.

Answer:

[tex]\Huge \boxed{x=-1}[/tex]

Step-by-step explanation:

[tex]x^2+2x=-1[/tex]

Adding 1 to both sides of the equation.

[tex]x^2+2x+1=-1+1[/tex]

[tex]x^2 +2x+1=0[/tex]

Factoring the left side of the equation.

[tex]x^2 +1x+1x+1=0[/tex]

[tex]x(x+1)+1(x+1)=0[/tex]

[tex](x+1)(x+1) = 0[/tex]

[tex](x+1)^2 =0[/tex]

Taking the square root of both sides of the equation.

[tex]\sqrt{(x+1)^2} =\sqrt{0}[/tex]

[tex]x+1=0[/tex]

Subtracting 1 from both sides of the equation.

[tex]x+1-1=0-1[/tex]

[tex]x=-1[/tex]

Answer:

x = -1

Step-by-step explanation:

[tex]x^2+2x = -1\\=0\\=x^2+2x+1 \\= (x+1)(x+1)\\=(x+1)^2\\\\0 = \sqrt{(x+1)^2} \\= x+1\\\\x+1=0\\x=-1[/tex]

Answer:

[tex]x_n=7(-3)^{n-1}[/tex]

Step-by-step explanation:

First, write some equations so we can figure out the common ratio and the initial term. The standard explicit formula for a geometric sequence is:

[tex]x_n=ar^{n-1}[/tex]

Where xₙ is the nth term, a is the initial value, and r is the common ratio.

We know that the second and fifth terms are -21 and 567, respectively. Thus:

[tex]a_2=-21\\a_5=567[/tex]

Substitute them into the equations:

[tex]x_2=ar^{(2)-1}\\-21=ar[/tex]

And:

[tex]a^5=ar^{(5)-1}\\567=ar^4[/tex]

To find a and r, divide both sides by a in the first equation:

[tex]r=-\frac{21}{a}[/tex]

And substitute this into the second equation:

[tex]567=a(\frac{-21}{a} )^4[/tex]

Simplify:

[tex]567=a(\frac{(-21)^4}{a^4})[/tex]

The as cancel out. (-21)^4 is 194481:

[tex]\frac{567}{1}=\frac{194481}{a^3}[/tex]

Cross multiply:

[tex]194481=567a^3\\a^3=194481/567=343[/tex]

Take the cube root of both sides:

[tex]a=\sqrt[3]{343} =7[/tex]

Therefore, the initial value is 7.

And the common ratio is (going back to the equation previously):

[tex]r=-21/a\\r=-21/(7)\\r=-3[/tex]

Thus, the common ratio is -3.

Therefore, the equation is:

[tex]x_n=7(-3)^{n-1}[/tex]

Answer:

The length and width of the parking lot are [tex]\frac{46}{3}[/tex] meters and [tex]\frac{23}{2}[/tex] meters, respectively.

Step-by-step explanation:

The surface formula ([tex]A[/tex]) for the rectangular parking lot is represented by:

[tex]A = w\cdot l[/tex]

Where:

[tex]w[/tex] - Width of the rectangle, measured in meters.

[tex]l[/tex] - Length of the rectangle, measured in meters.

Since, surface formula is a second-order polynomial, in which each binomial is associated with width and length. If [tex]A = 6\cdot x^{2}-19\cdot x -7[/tex], the factorized form is:

[tex]A = \left(x-\frac{7}{2}\,m \right)\cdot \left(x+\frac{1}{3}\,m \right)[/tex]

Now, let consider that [tex]w = \left(x-\frac{7}{2}\,m \right)[/tex] and [tex]l = \left(x+\frac{1}{3}\,m \right)[/tex], if [tex]x = 15\,m[/tex], the length and width of the parking lot are, respectively:

[tex]w =\left(15\,m-\frac{7}{2}\,m \right)[/tex]

[tex]w = \frac{23}{2}\,m[/tex]

[tex]l =\left(15\,m+\frac{1}{3}\,m \right)[/tex]

[tex]l = \frac{46}{3}\,m[/tex]

The length and width of the parking lot are [tex]\frac{46}{3}[/tex] meters and [tex]\frac{23}{2}[/tex] meters, respectively.

Answer:

last option ie all of the above are true

Lines s and t are intersect at P. Therefor, option D is the correct answer.

In a plane, intersecting lines are any two or more lines that cross one another. The point of intersection, which can be found on all intersecting lines, is where the intersecting lines share a common point.

Straight lines s and t are intersect at P.

P is called point of intersection.

Therefor, option D is the correct answer.

Learn more about intersection of lines here:

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Answer:

It would be 81

Step-by-step explanation:

[tex]9^{2}[/tex] is the same as 9 times 9. And 9 times 9 is 81.

Answer:

2⁹ = 512

Step-by-step explanation:

2⁹ = 2*2*2*2*2*2*2*2*2 = 512

Answer:

Step-by-step explanation:

[tex]4 - 2(3 + 2) ^{2} \\ 4 - 2( {5}^{2} ) \\ 4 - 2(25) \\ 4 - 50 = - 46[/tex]

Answer:

  see attached

Step-by-step explanation:

This is asking you to recognize the symbols used to designate a point, line segment, ray, angle, line, and plane.

The point is designated by its letter.

A line segment is designated by the letters of its endpoints, with an overline.

A ray is designated by the endpoint and a point on the ray. The endpoint is listed first. The letters have an arrow over them pointing in the direction from the endpoint.

An angle is designated using the symbol ∠. If three letters are used to identify the angle, the middle one is the vertex.

A line is designated using its name, or by the letters of two points on the line. If the letters are used, there may be a double-ended arrow over them.

A plane is designated by 3 non-collinear points, for example, "plane ABC". It may also be designated by the name of the plane.

Answer:

24 ft.

Step-by-step explanation:

10x2=20. 20+4=24

Answer:

24 FT.

Step-by-step explanation:

10x2=20. 20+4=24

Answer:

[tex]\frac{3}{4}[/tex], [tex]\frac{30}{40}[/tex], [tex]\frac{45}{60}[/tex], [tex]\frac{60}{80}[/tex]....e.t.c are all equivalent fractions

Step-by-step explanation:

For the answer you need to know bout equivalent fractions

TO find equivalent fractions you have to multiply the numerator and denominator by the same amount

E.x.[tex]\frac{15}{20}=\frac{(15)(2)}{(20)(2)} =\frac{30}{40}[/tex]

Therefore [tex]\frac{30}{40}[/tex] is an equivalent fraction

Answer:

Hello! Answer below.

Step-by-step explanation:

The answer to your question is:

18 9/10 or 18.9

Steps below...

You have to do this first.

1. Convert the mixed number to fraction.

2. [tex]7/2[/tex]

Multiplied by

[tex]27/5[/tex]

This will equal, 189/10

If you divide this the answer will be 18 9/10

So the answer is 18 9/10 or 18.9

Hope this helps!

By, BrainlyMagic

Answer:

19.375 m.

Step-by-step explanation:

Before the first bounce it has travelled 10 meters.

Then after just hitting the ground the second time it has travelled 10 +1/2(10) = 15 m.

The common ratio is 0.5 and we want the sum of  5 terms

= a1  (1 - r^n) / (1 - r)

= 10 * (1 - 0.5^5) / (1 - 0.5)

= 19.375 m.

Answer:

2/15

Step-by-step explanation:

given that the triple integral = ∫∫∫ 8x^2 dv

and T is the solid tetrahedron with vertices :  (0, 0, 0), (1, 0, 0), (0, 1, 0), and (0, 0, 1)

hence the equation of the plane: x + y + z = 1

T [ (X,Y,Z) : 0≤x≤1, 0≤y≤1-x, 0≤z≤1-x-y ]

attached below is the detailed solution ( we multiply our answer after evaluation with the coefficient of  8 as attached to the initial expresssion)

By evaluating the triple integral where T is the solid tetrahedron with verticies (0, 0, 0), (1, 0, 0), (0, 1, 0), and (0, 0, 1) the value calculated is 2/15.

Given :

The triple integral ∭ 8x^2 dV, where T is the solid tetrahedron with verticies (0, 0, 0), (1, 0, 0), (0, 1, 0), and (0, 0, 1).

The following calculation can be used to evaluate the triple integral:

[tex]\rm I = \int\int\int 8x^2dV[/tex]

T[(x,y,z) : [tex]0 \leq x \leq 1[/tex] ; [tex]0 \leq y \leq 1-x[/tex] ; [tex]0 \leq z \leq 1-x-y[/tex] ]

Now put the limits in the above integral.

[tex]\rm I = \int\limits^1_0\int\limits^{1-x}_0\int\limits^{1-x-y}_0 {8x^2} \, dz \, dy \, dx[/tex]

[tex]\rm I = \int\limits^1_0\int\limits^{1-x}_0 {8x^2} (1-x-y) \, dy \, dx[/tex]

[tex]\rm I = 8 \int\limits^1_0\int\limits^{1-x}_0 {x^2-x^3-x^2y} \, dy \, dx[/tex]

[tex]\rm I = 8 \int\limits^1_0 {x^2(1-x)-x^3(1-x)-x^2\dfrac{(1-x)^2}{2}} \, dx[/tex]

[tex]\rm I = 8 \int\limits^1_0 {x^2-x^3-x^3+x^4-x^2\dfrac{(1+x^2-2x)}{2}} \, dx[/tex]

[tex]\rm I = 4\left( \int\limits^1_0 {2x^2-4x^3+2x^4-x^2-x^4+2x^3} \, dx\right)[/tex]

[tex]\rm I = 4\left( \int\limits^1_0 {x^2+x^4-2x^3} \, dx\right)[/tex]

[tex]\rm I = 4\left( {\dfrac{x^3}{3}+\dfrac{x^5}{5}-\dfrac{x^4}{2}} \right)^1_0[/tex]

[tex]\rm I = 4\left( {\dfrac{1}{3}+\dfrac{1}{5}-\dfrac{1}{2}} \right)[/tex]

[tex]\rm I = \dfrac{2}{15}[/tex]

By evaluating the triple integral where T is the solid tetrahedron with verticies (0, 0, 0), (1, 0, 0), (0, 1, 0), and (0, 0, 1) the value calculated is 2/15.

For more information, refer to the link given below:

https://brainly.com/question/24308099

Look it up then u get the answer

Answer:

hey mate!

kindly see attached picture

hope it helped you:)

Answer:

.= 157

Step-by-step explanation:

There are three clock summing up to 21

One clock=21/3

One clock= 7

There are three calculator summing up to 30

One calculator= 30/3

One calculator= 10

There are three light bulb summing up to 15

One light bulb =15/3

One light bulb= 5

So the problem expression is

Clock +calculator *3bulb

= Clock +(calculator*3bulb)

= 7+(10*3(5))

= 7 +(10*15)

= 7 + 150

.= 157

Answer:

apples:bananas: strawberries

3     :             6       :         7

Step-by-step explanation:

apples:bananas: strawberries

6              12                  14

Divide each by 2

6/2           12/2               14/2

3                 6                      7

The ratio is

3     :             6       :         7

Answer:

3:6:7  

Step-by-step explanation

The answer is 3:6:7 because if you divide the numbers by 2, you will get a answer of 3, 6, and 7, the simplest form of the ratio.

Hope this helped!

~Emilie Greene

Answer:

Step-by-step explanation:

(b-(a-a)) ÷ 3

a = 6 , b = 3

Substitute the values into the above formula

That's

[tex](3 - (6 - 6)) \div 3[/tex]

Using PEDMAS solve the terms in the bracket first

That's

[tex](3 - 0) \div 3[/tex]

We have

3 ÷ 3

Hope this helps you

Answer:

f(-3)= -3

Step-by-step explanation:

We are given the function:

f(x) = 2x+3

and asked to find f(-3). Essentially, we want to find f(x) when x is equal to -3.

Therefore, we can substitute -3 for each x in the function.

f(x)= 2x+3 at x= -3

f(-3)= 2(-3) +3

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition and Subtraction

Multiply 2 and -3.

f(-3) = (2*-3) +3

f(-3)= (-6)+3

Add -6 and 3.

f(-3)= (-6+3)

f(-3)= -3

If f(x)= 2x+3, then f(-3)= -3

Answer:

[tex] \boxed{ \sf{ \bold{ \huge{ \boxed{71}}}}}[/tex]

Step-by-step explanation:

Using PEMDAS rule :

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Let's solve:

[tex] \sf{8 + 7 \times 9}[/tex]

Multiply the numbers

⇒[tex] \sf{8 + 63}[/tex]

Add the numbers

⇒[tex] \sf{71}[/tex]

Hope I helped!

Best regards!