Help me and I'll make u Brainliest eat and follow u

Answer:

10 m

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 14 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

Next, we shall determine the energy. This can be obtained as follow:

Velocity (v) = 14 m/s

Kinetic Energy (KE) =?

KE = ½mv²

KE = ½ × m × 14²

KE = ½ × m × 196

KE = m × 98

Finally, we shall determine the height. This can be obtained as follow:

Kinetic energy (KE) = m × 98

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

Since the object is falling from a particular height,

Potential energy (PE) = kinetic energy (KE)

PE = mgh

KE = m × 98

m × 9.8 × h = m × 98

Divide both side by m × 9.8

h = m × 98 / m × 9.8

h = 10 m

Thus, the bottle was dropped from a height of 10 m

Answer:

The correct answer is - at high pressure a huge amount of gases can be stored in less volume.

Explanation:

We already know that pressure is inversely proportional to the volume of gas which means if we increase the pressure the volume of gas becomes less.

P = 1/V

So in the scuba divers tank, the oxygen is filled at very high pressure so the high amount of the oxygen can be filled in less volume and which will last for longer than a normal pressure tank can last.

Answer:

D. Zn²⁺ + 2Ag → Zn + 2Ag⁺

Explanation:

On the reduction potential chart, we have that silver ion Ag⁺ is a stronger oxidizing agent than, zinc, Zn, which is a reducing reducing agent the compared to silver

Therefore, the redox reaction that will occur is that the zinc, Zn, will be oxidized to Zn²⁺ ion, while the silver, Ag²⁺ ion will be reduced to silver deposits Ag, therefore, the zinc will displace the silver in the solution containing silver and zinc ions because zinc is higher than silver in the reactivity series

The reduction potential Zn → Zn²⁺ + 2e⁻ = +0.76

The reduction potential for Ag⁺ + e⁻ → Ag = +0.8

Therefore, given that redox reactions are reversible, we get the following likely redux reaction;

Zn(s) + 2Ag⁺(aq) ⇄ 2Ag(s) + Zn²⁺(aq)

Therefore, from the given options;

Zn²⁺(aq) + 2Ag(s) → Zn(s) + 2Ag⁺(aq) is the reaction most likely to occur.

Answer:

ΔH = -746.6kJ

Explanation:

Using Hess's law we can find the ΔH of a reaction from the sum of similar reactions. From the reactions:

1. 2CO(g) + O2(g) → 2CO2 ΔH = -566.0kJ

2. N2(g) + O2(g) → 2NO(g) ΔH = 180.6kJ

The negative reaction of 2:

-2. 2NO(g) → N2(g) + O2(g) ΔH = -180.6kJ

The sum of 1 - 2:

2CO(g) + O2(g) + 2NO(g) → 2CO2  N2(g) + O2(g) ΔH = -566.0kJ + (-180.6kJ) =

ΔH = -746.6kJ

Subtracting the molecules that don't change:

2CO(g) + 2NO(g) → 2CO2  + N2(g) ΔH = -746.6kJ

Answer:

A standard system of measurement is very important because it helps us from making mistakes at the moment of doing calculations and correctly working...

Answer:

A standard measurement system is important because it allows scientists to compare data and communicate with each other about their results. Metric System – is a measurement system based on the number 10.

Answer: Revoke the driver's license for at least 12 months

Explanation:

Chemical tests are used in order to measure the amount of drugs or alcohol that is in the body of a person when the person was arrested. To do this, samples of the urine or blood of the person can be taken and the result will be used to know if the person was driving under the influence of alcohol or not.

If the person refuse a legal chemical test issued by a law enforcement officer, the Division of Motor Vehicles is required to revoke the the driver's license of the person for at least 12 months.

Answer:

Todas son correctas

Explanation:

I) Los compuestos del carbono son solubles en disolventes no polares como el hexano, benceno, éter, etc. VERDADERO. La mayoría de los compuestos de carbono son apolares, y basados en la regla: Similar disuelve similar, podemos presumir que la mayoría de compuestos de carbono se disuelven en solventes no polares.

II) Los compuestos del carbono generalmente presentan puntos de fusión y de ebullición bajos. VERDADERO. Al ser sustancias apolares, sus fuerzas electrostáticas son bajas. De la misma manera, como su masa atómica es pequeña, las fuerzas de Van der Waals son despreciables haciendo que sus puntos de fusión y ebullición sean bajos respecto a sustancias de estrucutra similar.

III) La gran mayoría de los compuestos del carbono son combustibles, sean estos, gaseosos, líquidos o sólidos. VERDADERO. Los gases (Como el gas natural) son combustibles usados para cocina. Los líquidos (Como la gasolina) son combustibles y bastante inflamables. Los sólidos (Como la madera) se usan como combustibles para hacer asados o son el combustible en incendios forestales.

IV) El enlace covalente es característico de los compuestos del carbono. VERDADERO. La polaridad del carbono es neutral haciendo que la mayoría de los enlaces que forma sean covalentes.

An atom is neutral as it has the same number of electrons that of protons. So, if an atom has 32 protons i.e. the atomic number of it is 32, then it will have 32 electrons revolving the nucleus.

Answer:

because they are high reactive to the air thats why we keep them in paroffin oil

1. Sodium triphosphate ·

2. Sodium hydroxide ·

3. potassium hydroxide

4. Sodium Lauryl Sulfate · 5.Hydroxyethylcellulose ·

6. Sodium carbonate

Answer:

[tex]V=795.26L[/tex]

Explanation:

From the question we are told that:

Volume [tex]V=1dm^3=>1L[/tex]

Density [tex]\rho=70.8g/L[/tex]

Generally the equation for Density is mathematically given by

[tex]\rho =\frac{Mass}{Volume}[/tex]

Therefore

[tex]M=\rho*V[/tex]

[tex]M=70.8*1[/tex]

[tex]M=70.8g[/tex]

Since at STP

[tex]T=273K[/tex]

[tex]P=1atm[/tex]

[tex]Mass =70.8g[/tex]

Therefore

[tex]Moles\ of\ Hydrogen=\frac{Mass}{2g}[/tex]

[tex]Moles\ of\ Hydrogen=\frac{70.8}{2g}[/tex]

[tex]Moles\ of\ Hydrogen=35.4moles[/tex]

Generally the equation for Ideal gas is mathematically given by

[tex]PV=nRT[/tex]

Therefore

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{35.4*0.0826*273}{1}[/tex]

[tex]V=795.3L[/tex]

Answer: The statement conjugate base of hydrofluoric acid is weaker than that of acetic acid is most likely true.

Explanation:

A strong acid upon dissociation gives a weak conjugate base. This can also be said as stronger is the acid, weaker will be its conjugate base or vice-versa.

Hydrofluoric acid is a strong base as it dissociates completely when dissolved in water.

For example, [tex]HF \rightleftharpoons H^{+} + F^{-}[/tex]

The conjugate base is [tex]F^{-}[/tex] which is a weak base.

Acetic acid is a weak acid as it dissociates partially when dissolved in water. So, the conjugate base of acetic acid is a strong base.

[tex]CH_{3}COOH \rightarrow CH_{3}COO^{-} + H^{+}[/tex]

Thus, we can conclude that the statement conjugate base of hydrofluoric acid is weaker than that of acetic acid is most likely true.

Answer:

Explanation:The equation for this is F = -GmM/R^2 where the minus sign says the force is attractive m is 10 kg, M is 20 kg and R is 5 meters. If you crunch the numbers you get an answer of:

Answer:

C) K

Explanation:

K has an electron configuration of 2.8.8.1

Answer:

hanigin ng mga pule natin

Answer:

-0.75 , 1.25

Explanation:

Number of electrons present in valence shell,

P-O = 5 + 8 = 13

Number of electrons involved in bond formation,

13 - 3 = 10

Number of bonds in PO3 - 4ion = 102

Average P-O bond = 1.25

Average formal charge on Oxygen atom is -0.75

Answer:

0.302M

Explanation:

Molarity, which is the molar concentration of a solution can be calculated as follows:

Molarity = number of moles (n) ÷ volume (V)

According to this question, 19.5 grams of Be(OH)2 is dissolved in enough water to make a 1.5 L solution.

Using mole = mass/molar mass to calculate the number of moles in 19.5g of Be(OH)2

Molar mass of Be(OH)2 = 9 + (16 + 1)2

= 9 + (17)2

= 9 + 34

= 43g/mol

mole = 19.5/43

mole = 0.453moles

Molarity = n/V

Molarity = 0.453/1.5

Molarity = 0.302M

Answer:

exactly 0.10071444308 mols or just 0.1 mols

Explanation:

converting 6.4 g of copper to moles is done by using it's Molar Mass we can find the Molar Mass by lookin at the periodic table or just googling it. In this case, copper's molar mass is 63.546g per Mole. so thats 6.4/63.546 = 0.015736631731344 moles of copper

Answer:

1) The percentage of oxygen in dry air is _______

C. 21

2) The composition of the Earth’s earliest atmosphere was different to that of the present atmosphere. Which of these gases was present in large amounts in the Earth’s earliest atmosphere?

B. CARBON DIOXIDE

Hope it helps

have a nice day

Answer: The percentage of oxygen in dry air is .  21

Explanation:  Ammonia gases was present in large amounts  in the easth7s earliest atmosphere

Hope it will help you

Answer:

51.6058

Explanation:

The percentage of abundance is changed to decimal by dividing 100

Answer:

130 mL

Explanation:

2FeCl3(aq) + 3K2S(aq) -----> Fe2S3(s) + 6KCl(aq)

Percent yield = actual yield/theoretical yield × 100

actual yield = 2.75 g

Theoretical yield = x

65= 2.75/x × 100

x= 2.75 × 100/65

x= 4.2 g

Number of moles of FeCl3 = mass/molar mass = 4.2 g/ 162.2 g/mol = 0.026 moles

Then;

n= CV

n= number of moles

C= concentration

V= volume

V= n/C

V= 0.026 moles/ 0.200 M

V= 0.13 L or 130 mL

Answer:

Explanation:

Indira point is the southern most point of India and is situated on great nicobar island in the nicobar island.

Answer:

Your Ans Is

(A) Indra point.

Answer:

Then, at some point, these higher energy electrons give up their "extra" energy in the form of a photon of light, and fall back down to their original energy level.

Explanation:

When properly stimulated, electrons in these materials move from a lower level of energy up to a higher level of energy and occupy a different orbital.

A magnesium ribbon is cleaned to remove the protective layer of basic magnesium carbonate from its surface, so that it may readily combine with the oxygen in air (on heating).

Answer:

Magnesium gets covered with a layer of magnesium oxide when kept in air for a long time. This layer hinders the burning of magnesium. Hence, it is to be cleaned before burning.

8g + 65g = 73g

24g + 38g = 62g

Answer:

1)Na + O2 = > 2NaO

8 g + 65 g = > 73g

2) 2H2 + O2 → 2H2O

24 g + 38g→ 62 g