HELP ASAP ROCKY!!! will get branliest.​

Answer:What if you were asking this question? How would you explain it to yourself?

Step-by-step explanation:

Answer:oufonsrgonsrgnrsosgnsogwo0on93rhskgv oaoef

Step-by-step explanation:

iaeiuaefiaef ebf efa fcade emma jog 123e oefofoinsfnfsaefosefnhsfnalnfaogh

Answer:

Yes, the table represents quadratic function.

[tex]Y = 3X^2+10[/tex]

Step-by-step explanation:

Given that table of values:

[tex]\begin{center}\begin{tabular}{ c c}X & Y \\ 1 & 13 \\ 2 & 22 \\ 3 & 37 \\ 4 & 58 \\ 5 & 85 \\\end{tabular}\end{center}[/tex]

To find:

Whether the given table represents a quadratic?

Solution:

First of all, let us plot the given values on the coordinate xy plane.

Kindly refer to the attached image for the graph of given values.

The graph seems parabolic in nature which is the graph of a quadratic equation.

Now, let us try to find the equation from the given set of values from hit and trial.

Let Quadratic equation be:

[tex]y=ax^{2} +b[/tex]

If the coefficient a = 1

[tex]f(1) = 13 = 1^2+12[/tex]

[tex]f(2) = 22 = 2^2+18[/tex]

[tex]f(3) = 37= 3^2+28[/tex]

[tex]f(4) = 58 = 4^2+42[/tex]

[tex]f(5) = 85 = 5^2+60[/tex]

value of b is not same in each case.

Now, let us try coefficient a = 3

[tex]f(1) = 13 = 3 \times 1^2+10[/tex]

[tex]f(2) = 22 = 3\times 2^2+10[/tex]

[tex]f(3) = 37= 3\times 3^2+10[/tex]

[tex]f(4) = 58 = 3\times 4^2+10[/tex]

[tex]f(5) = 85 =3\times 5^2+10[/tex]

Value of b = 10

So, we can clearly say that the given table represents a quadratic equation.

and the quadratic equation is:

[tex]Y = 3X^2+10[/tex]

Answer:

soln,

y=37/100×x

or, 100y=37x.....is the answer

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

The equation of y is 37% of x is

y = 0.37x

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example:

2 + 3x + 4y = 7 is an expression.

2 + 3 - 4 is an expression.

2x4 + 4x = 4 is an expression.

We have,

y is 37% of x.

This can be written as,

y = 37/100 of x

y = 0.37x

Thus,

The equation of y is 37% of x is

y = 0.37x

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Answer: the real solution: x = - 2

Find the attached file for the remaining solution

Step-by-step explanation:

The equation given is:

x3 - 5x2 + 28 = 0 

Let assume that -2 is one of the root of the equation. Substitute -2 for x

(-2)^3 - 5(-2)^2 + 28

-8 - 20 + 28 = 0

Therefore, -2 is one of the root of the equation since the equation tend to zero.

If x = -2, then x+2 is one of the factors of the equation. Therefore, the real solution is x = -2

Please find the attached file for the remaining solution.

Answer:

0.412

Step-by-step explanation:

Given the stem plot figure out which ones are below 17g.

So: 7g / 17g = 0.412 which is the proportion

Answer:

-2°F

Step-by-step explanation:

So on Sunday night, the temperature was -10°F.

And by Monday morning, the temperature has increased by 8°F.

In other words, to find the temperature on Monday morning, we just have to add 8 to -10. Therefore:

[tex](-10)+(8)=-2[/tex]

The temperature on Monday morning is -2°F

Answer:

-2 degrees F.

If you have -10, you have to add positive 10 just to get to 0.

Answer:

  1 : 50,000,000

Step-by-step explanation:

The given scale (with units) is ...

  1 mm : 50 km

If we convert both units to meters, so we can give the scale as a pure number, then we have ...

  10^-3 m : 5×10^4 m = 1 : 5×10^7 = 1 : 50,000,000

201 bars

Let the number of bars bought be x.

Cost of three bars is 20 cents.

Therefore, 1 bar will cost [tex]\frac{20}{3}[/tex] cents.

He ate one of the bars...

Therefore, remaining bars will be x - 1

... He sold the remainder at 10 cents each i.e

1 bar = 10 cents

(x - 1) bars = 10( x - 1) cents

...He made $200.00 from selling the remaining bars.

10( x - 1) cents = $200.00             ---------------(i)

Convert from dollars to cents

$1 = 10 cents

$200 = 200 x 10 cents = 2000 cents

From equation (i)

10(x - 1)cents = 2000 cents

=> 10( x - 1) = 2000            [divide both sides by 10]

=> x - 1 = 200

=> x = 200 + 1

=> x = 201

Therefore, he bought 201 bars of ice cream.

Answer:

D.  The line is dashed with a y-intercept at (0,-3) and slope of -.

Step-by-step explanation:

If you rearrange the inequality -3x-2y<6 to y=mx+b form you should get y>-3/2x-3

The slope would be mx or -3/2

The Y intercept would be b or -3

I hope this helps :)

The line with an inequality equation -3x - 2y < 6 when plotted on the graph, occupies a region with a dashed boundary line with the attributes, the slope m = -3/2, and the y-intercept c = -3.

An inequality equation for a line is the equation that is true for certain values of its variables. The inequality symbols are ' <, >, ≤, ≥ '.

When inequality is graphed,

The inequality equation is re-arranged in the slope-intercept form to know the attributes of the line such as the slope of the line and the y-intercept of the line.

The given inequality is -3x - 2y < 6

Step 1: Rewriting the equation into the slope-intercept form:

-3x - 2y < 6

To change the sign,  change the inequality symbol also.

⇒ 3x + 2y > 6

⇒ 2y > 6 - 3x

⇒ y > -3/2x - 3

Therefore, the obtained equation is in the slope-intercept form.

So, m = -3/2 and c = -3

Step 2: Graphing the inequality:

To graph the line, we need coordinates.

So, consider x = 0  inorder to get y-coordinate

On substituting,

-3(0) -2y = 6

y = -3

∴ (0, -3) is one of the coordinates of the line

Then, consider y = 0 inorder to get x-coordinate

On substituting,

-3x - 2(0) = 6

x = -2

∴ (-2, 0) is one of the coordinates of the line

These points are plotted in the graph and a line is drawn from these points.

Step 3: Observations from the graph:

Therefore, the attributes of the boundary line (dashed line) are slope -3/2 and y-intercept -3.

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Answer:

true

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

So we have the expression:

[tex](6m+3)(m-2)[/tex]

Use the distributive property and distribute:

[tex]=(6m+3)(m)+(6m+3)(-2)[/tex]

Distribute:

[tex]=(6m^2+3m)+(-12m-6)[/tex]

Combine like terms:

[tex]=6m^2+3m-12m-6\\=6m^2-9m-6[/tex]

The correct answer is D

Edit: Typo

Answer:

11 years old

Step-by-step explanation:

Because the dog is 4 years older, add 7+4

Looks like your function is

[tex]f(x)=\dfrac x{6x^2+1}[/tex]

Rewrite it as

[tex]f(x)=\dfrac x{1-(-6x^2)}[/tex]

Recall that for [tex]|x|<1[/tex], we have

[tex]\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n[/tex]

If we replace [tex]x[/tex] with [tex]-6x^2[/tex], we get

[tex]f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}[/tex]

By the ratio test, the series converges if

[tex]\displaystyle\lim_{n\to\infty}\left|\frac{(-6)^{n+1} x^{2(n+1)+1}}{(-6)^n x^{2n+1}}\right|=6|x^2|\lim_{n\to\infty}1=6|x|^2<1[/tex]

Solving for [tex]x[/tex] gives the interval of convergence,

[tex]|x|^2<\dfrac16\implies|x|<\dfrac1{\sqrt6}\implies -\dfrac1{\sqrt 6}<x<\dfrac1{\sqrt 6}[/tex]

We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.

The interval of the convergence is (-1/√6 < x < 1/√6). We can confirm that the interval is open by checking for convergence at the endpoints.

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

The given function is

[tex]\rm f(x) = \dfrac{x}{6x^2 + 1} \\\\or \\\\f(x) = \dfrac{x}{1 - (-6x^2)}[/tex]

For |x| < 1, we have

[tex]\rm \dfrac{1}{1-x} = \Sigma_{n=0}^{\infty} \ x^n[/tex]

If x is replaced with -6x², then we have

[tex]\rm f(x)= \Sigma_{n=0}^{\infty} (-6x^2 )^n = \Sigma_{n=0}^{\infty} (-6)^n x^{2n+1}[/tex]

Then by the ratio test, the series converges if

[tex]\displaystyle \lim_{n \to \infty} \left| \dfrac{(-6)^{n+1}x^{2(n+1)+1}}{(-6)^{n}x^{2n+1}} \right|=6|x^{2}| \displaystyle \lim_{n \to \infty }1=6|x^{2}| < 1[/tex]

Solving for x, the interval of convergence will be

[tex]|x^2| < \dfrac{1}{6} \\\\|x| < \dfrac{1}{\sqrt6} \\\\-\dfrac{1}{\sqrt6} < x < \dfrac{1}{\sqrt6}[/tex]

We can confirm that the interval is open by checking for convergence at the endpoints.

More about the function link is given below.

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Answer:

20

Step-by-step explanation:

Given:

As per the picture:

Comparing the two equations above:

x = 20 is the correct answer for this question

Otherwise something is wrong with the question.

Answer:

found this on the web. hopefully it helps

Answer: True.

Step-by-step explanation:

The one-way analysis of variance usually (abbreviated as one-way ANOVA). is a method that is used to compare the means of two or more samples ( by make use of the F distribution). This method only applies to numerical response data, the "Y", usually one variable, and numerical or (usually) categorical input data, the "X", always one variable, hence the reason it’s know as "one-way" beca it takes it account one variae at a time.

Answer:

x = 16

Step-by-step explanation:

Step 1: We know DF - DE = EF

9x - 39 - 47 = EF

Step 2: Simplify

9x - 86 = EF

Step 3: Set the equation equal to 3x + 10

9x - 86 = 3x + 10

6x = 96

x = 16

Therefore x is equal to 16

Answer:

58

Step-by-step explanation:

DE + EF = DF

47+ 3x+10 = 9x-39

Combine like terms

57 +3x = 9x-39

Subtract 3x from each side

57+3x-3x = 9x-3x-39

57 = 6x-39

Add 39 to each side

57+39 = 6x-39+39

96 = 6x

Divide by 6

96/6 = 6x/6

16 =x

We want the length of EF

EF = 3x+10

     = 3*16 +10

    = 48+10

   = 58

Hello, please consider the following.

x is obviously different from 0 and then, dividing by x is legit.

For the first 105 miles the speed is x, so the time spent is

[tex]\dfrac{105}{x}[/tex]

For the second part, the speed is 1.4 x, so the time spent is

[tex]\dfrac{105}{1.4x}=\dfrac{75}{x}[/tex]

In total, the time she spent driving is

[tex]\dfrac{105}{x}+\dfrac{75}{x}\large \boxed{=\dfrac{180}{x}}[/tex]

Thank you.

Answer:

58.33

Step-by-step explanation:

35 isn't exactly 60% of an number but by rounding you will get 58.33

Answer:

3.2 units

Step-by-step explanation:

Given that:

WY bisects UV at Y.

[tex]UV=x-7[/tex] and

[tex]YV = 3x-29[/tex],

To find: UV = ?

Solution:

First of all, let us draw the diagram of the given dimensions and bisector line WY of UV.

As UV is bisected i.e. divided in two equal parts at Y by the line WY

Therefore, UY = YV

UV = UY+YV

OR

UV = 2 YV

Now, let us put the given values to solve for [tex]x[/tex]:

[tex]x-7=2 \times (3x-29)\\\Rightarrow x-7=2 \times 3x-2 \times 29\\\Rightarrow x-7=6x-58\\\Rightarrow 6x-x=58-7\\\Rightarrow 5x=51\\\Rightarrow \bold{x =10.2 }[/tex]

Now, we are given that:

[tex]UV=x-7[/tex]

Putting value of [tex]x[/tex] as solved in above step to get the value of UV:

[tex]UV=10.2-7\\\Rightarrow \bold{UV=3.2}[/tex]

So, answer is UV = 3.2 units

Answer:

0.1875

Step-by-step explanation:

The well formatted expression for the series has been attached to this response.

Each term in the series is govern by the rule, Tₙ

Where

n = term position

Tₙ = [tex]\frac{(-1)^{n+1}n}{2^n}[/tex]

To get the first six terms, we substitute n = 1 through 6 into Tₙ as follows:

When n = 1, we have;

T₁ = [tex]\frac{(-1)^{1+1}(1)}{2^1} = \frac{1}{2}[/tex] = 0.50000

When n = 2, we have;

T₂ = [tex]\frac{(-1)^{2+1}(2)}{2^2} = \frac{-2}{4} = \frac{-1}{2}[/tex] = -0.50000

When n = 3, we have;

T₃ = [tex]\frac{(-1)^{3+1}(3)}{2^3} = \frac{3}{8}[/tex] = 0.37500

When n = 4, we have;

T₄ = [tex]\frac{(-1)^{4+1}(4)}{2^4} = \frac{-1}{4}[/tex] = -0.25000

When n = 5, we have;

T₅ = [tex]\frac{(-1)^{5+1}(5)}{2^5} = \frac{5}{32}[/tex] = 0.15625

When n = 6, we have;

T₆ = [tex]\frac{(-1)^{6+1}(6)}{2^6} = \frac{-6}{64} = \frac{-3}{32}[/tex] = -0.09375

Therefore, the approximate sum of the series using the sum of the first six terms is

=> T₁ + T₂ + T₃ + T₄ + T₅ + T₆

=> 0.50000 + -0.50000 + 0.37500 + -0.25000 + 0.15625 + -0.09375

=> 0.1875

Answer:

  [tex]1-\dfrac{2}{3}\sqrt{3}[/tex]

Step-by-step explanation:

Maybe you want to simplify ...

  [tex](1-\sqrt{3})\dfrac{1}{3+\sqrt{3}}[/tex]

Multiply numerator and denominator by the 'conjugate' of the denominator:

  [tex](1-\sqrt{3})\dfrac{1}{3+\sqrt{3}}\cdot\dfrac{3-\sqrt{3}}{3-\sqrt{3}}=\dfrac{(1-\sqrt{3})(3-\sqrt{3})}{9-3}=\dfrac{3-4\sqrt{3}+3}{6}\\\\\boxed{1-\dfrac{2}{3}\sqrt{3}}[/tex]

Answer:

y = -7x + 2

Step-by-step explanation:

Use the slope-intercept form y = mx + b.

Substitute -7 for m, 0 for x and 2 for y.  Then

2 = (-7)(0) + b, so b must be 2.

The desired equation is y = -7x + 2.

Answer:

False

Step-by-step explanation:

In an essay, you have to cite every source you use because

a) the teacher needs to KNOW you didn't copy

b) the teacher needs to know if you got your info from a reliable source

c) the teacher needs to see your ability to use info from a source to put into your essay

This may be different for books, but citation is always a rule of thumb for essays in school, so don't forget unless you want points to be taken off of your score.

Answer: 3

Step-by-step explanation: you add 7+3 which is 10 - 7 =3

Answer:

Once we got

[tex]x=-1[/tex]

[tex]y=3[/tex]

[tex]z=2[/tex]

[tex]\boxed{\text{The sum is 4}}[/tex]

Step-by-step explanation:

Given the linear system:

[tex]\begin{cases} 2x + 3y-z = 5 \\ x- 3y + 2z = -6 \\ 3x + y - 4z = -8 \end{cases}[/tex]

Let's solve it using matrices. I will use Cramer's rule

[tex]M=\left[\begin{array}{ccc}2&3&-1\\1&-3&2\\3&1&-4\end{array}\right][/tex]

Considering determinant as D.

[tex]D=\begin{vmatrix}2&3&-1\\1&-3&2\\3&1&-4\\\end{vmatrix}=40[/tex]

[tex]M_x = \left[\begin{array}{ccc}5&3&-1\\-6&-3&2\\-8&1&-4\end{array}\right] \implies D_x = \begin{vmatrix}5&3&-1\\-6&-3&2\\-8&1&-4\\\end{vmatrix}=-40[/tex]

[tex]M_y = \left[\begin{array}{ccc}2&5&-1\\1&-6&2\\3&-8&-4\end{array}\right] \implies D_y = \begin{vmatrix}2&5&-1\\1&-6&2\\3&-8&-4\\\end{vmatrix}=120[/tex]

[tex]M_z = \left[\begin{array}{ccc}2&3&5\\1&-3&-6\\3&1&-8\end{array}\right] \implies D_z= \begin{vmatrix}2&3&5\\1&-3&-6\\3&1&-8\\\end{vmatrix}=80[/tex]

So, we have

[tex]$x=\frac{D_x}{D} =\frac{-40}{40}=-1 $[/tex]

[tex]$y=\frac{D_y}{D} =\frac{120}{40}=3$[/tex]

[tex]$z=\frac{D_z}{D} =\frac{80}{40}=2 $[/tex]

Answer:

3x + 5

Step-by-step explanation:

We are doing variables and simplifying.

You have two types of numbers here, you have a coefficient, and you have regular numbers. Now do keep in mind that you can never add a regular number to a coefficient. So the only thing in this problem you will add is 3 and 2. Because 3x is different

3x + (3 + 2)

3x + 5

The simplified form of the expression is 3x + 5.

Option A is the correct answer.

We have,

Expression:

3x + 3 + 2

Add like terms.

3x + (3 + 2)

3x + 5

This is the simplest simplified form of the expression.

Thus,

The simplified form of the expression is 3x + 5.

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