he solid sphere is spinning about its cm. find the moment of inertia. if the axis is shifted to one of the sides (but still perpendicular to the radius), find the new moment of inertia.

Suppose an object experiences a constant force of magnitude F. In that case, it accelerates according to Newton's second law of motion, which states that F = ma, where m is the mass of the object and a is its acceleration.

Given that the object experiences a constant force that produces an acceleration of 8 m/s^2, we can write:

F = ma = m × 8

What will the acceleration of this object be if the force is halved?

If the force is halved, the new force is F/2. Using Newton's second law, we can find the new acceleration as follows:

F/2 = ma_new

ma_new = (F/2) / m

ma_new = F/2m

ma_new = (m × 8) / 2m

ma_new = 4 m/s^2

Therefore, the object's acceleration will be 4 m/s^2 if the force is halved.

What will the acceleration of this object be if the mass is halved?

If the mass is halved, the new mass is m/2. Using Newton's second law, we can find the new acceleration as follows:

F = (m/2) × a_new

a_new = F / (m/2)

a_new = 2F/m

a_new = 2(m × 8)/m

a_new = 16 m/s^2

Therefore, the acceleration of the object will be 16 m/s^2 if the mass is halved.

If the force is halved and the mass is halved, the new force is F/2 and the new mass is m/2. Using Newton's second law, we can find the new acceleration as follows:

F/2 = (m/2) × a_new

a_new = (F/2) / (m/2)

a_new = F/m

a_new = (m × 8) / m

a_new = 8 m/s^2

Therefore, the object's acceleration will be 8 m/s^2 if the force is halved and the mass is halved.

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The gravitational force between the ball of mass 100 Kg and earth at a distance of 6.38 × 10⁶ m is 979.9 N.

The gravitational force is the force by which an object attracts other object into its center of mass. The gravitational force depends on the masses of the objects and distance between them by the equation written below:

Fg = G m1 m2/r²

where G is the universal gravitational constant equal to 6.67 × 10⁻¹¹ N/kg²m²

The gravitational force  is given 2.30 ×10⁻⁸ N.

distance  between the objects = 10 m.

then Fg = 6.67 × 10⁻¹¹ N × (100 kg × 5.98 ×10²⁴ kg)/(6.38 × 10⁶ m)² =  979.9 N

Therefore, the gravitational force between the ball and earth is 979.9 N. IN similar way, the force between any two objects can be determined using the given distance and mass.

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In order for the clown to land unharmed, the other clowns should hold the net at a point along the trajectory of the clown that is equal to the launch height of the clown.

The point can be calculated using the following equation:

Distance = velocity × time

Where velocity = 40 m/s and time = 2(velocity × sin(60o))/9.8 (where 9.8 is gravitational acceleration).

Therefore, the distance = 40 m/s × 2(40 m/s sin(60o))/9.8 = 80 m.

The other clowns should aim to place the net at a point that is 80 meters away from the cannon and at a height of 40 meters. This point should correspond to the apex of the trajectory, which is the highest point that the clown will reach when launched. The clowns should also make sure that the net is held at an angle of 30 degrees with respect to the horizontal, to ensure that the clown lands safely at the same level where it was launched.

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The force diagrams that may possibly correspond to the situation at point A on the motion diagram are 356.

A force diagram, also known as a free-body diagram, is a graphical representation that shows the forces, moments, and reactions acting on a body under a specific state. It shows a body or group of connected bodies along with all the applied forces, times, and reactions that the bodies experience.

At point A in the motion diagram, the force acting at point A are as follows:

Hence, the correct diagrams are 3, 5, and 6.

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The velocity distribution in the fluid can be found using the Navier-Stokes equation, which states that the net force on a fluid element is equal to its mass times its acceleration.

(a) Velocity distribution and torques on two coaxial cylinders:

The fluid is incompressible, so the continuity equation can be used to relate the fluid velocities at different radii. For the coaxial cylinders, the velocity distribution can be found by assuming a linear velocity profile between the two surfaces, where the velocity at the inner surface is ai * kr and the velocity at the outer surface is a * r. Therefore, the velocity profile is given by:

v(r) = (a - ai) / (r - kr) * (r - kr) + ai * kr

The torque required to maintain the motion of the cylinders can be found using the formula:

T = I * α

where T is the torque, I is the moment of inertia, and α is the angular acceleration. For each cylinder, the moment of inertia is given by:

I = (1/2) * m * R²

where m is the mass of the cylinder and R is its radius. The angular acceleration is related to the angular velocity by:

alpha = (a - ai) / (r - kr)

Therefore, the torque on the inner cylinder is:

Ti = (1/2) * m * kr² * (a - ai) / (r - kr)

and the torque on the outer cylinder is:

To = (1/2) * m * r² * (a - ai) / (r - kr)

(b) Velocity distribution and torques on two concentric spheres:

The velocity distribution and torques on two concentric spheres can be found in a similar way to the coaxial cylinders. Assuming a linear velocity profile between the two spheres, where the velocity at the inner sphere is ai * kr and the velocity at the outer sphere is a * r, the velocity profile is given by:

v(r) = (a - ai) / (r - kr) * (r - kr) + ai * kr

The torque required to maintain the motion of the spheres can be found using the same formula as for the cylinders, with the moment of inertia for each sphere given by:

I = (2/5) * m * R²

where m is the mass of the sphere and R is its radius. Therefore, the torque on the inner sphere is:

Ti = (2/5) * m * kr² * (a - ai) / (r - kr)

and the torque on the outer sphere is:

To = (2/5) * m * r² * (a - ai) / (r - kr)

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Escherichia coli use long, whip-like structures called flagella to propel themselves.

Escherichia coli, also known as E. coli, is a Gram-negative, facultative anaerobic, rod-shaped, coliform bacterium of the genus Escherichia that is commonly found in the lower intestine of warm-blooded organisms

Given is to find what two structures help E.coli move.

Escherichia coli use long, whip-like structures called flagella to propel themselves. Motors in the cell's wall spin the flagella into bundles that rotate counter-clockwise, creating a twist that causes the bacterium to rotate clockwise, or towards the right when viewed from above.

Therefore, Escherichia coli use long, whip-like structures called flagella to propel themselves.

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In the sentences for the telescope in the right-hand column from the first-hand column, the relevant blank has been filled.

Describe the telescope.

A telescope is the device used to show an enlarged view of a far-off object.

There are different types of telescopes, and each is used for a particular purpose.

The blank that should be filled in correctly from the first column is as follows:

1. Shorter (bluer) wavelengths of light have better angular resolution than longer (redder) wavelengths of light for the Hubble Space Telescope.

2. Huge reflecting telescopes are employed by the numerous research observatories on Mauna Kea.

3. The spectrograph, which divides light into its various colors, enables astronomers to ascertain the stellar composition as well as a number of other stellar characteristics.

4. The identical 10-m Keck

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A wire's resistance is inversely correlated with its cross-sectional area and inversely proportional to its length. Wire A will therefore have four times the area of Wire B if it is twice as long and twice as thick.

The distance between charged particles will increase as the conductor's cross-sectional area does. As a result, there will be less chance of electron collisions. As a result, resistance will decrease as the conductor's cross-sectional area increases.

It is inversely related to the wire's cross-sectional area. The resistance decreases with increasing wire cross-section area and increases with decreasing cross-section area.

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The temperature axis is the horizontal axis on a graph where the temperature values are plotted. In other words, it is the x-axis of a graph where the values on the x-axis represent different temperatures. The temperature axis is usually labeled with the units in which temperature is measured, such as degrees Celsius (°C), degrees Fahrenheit (°F), or Kelvin (K). The temperature axis is an important component of many scientific and engineering graphs, particularly those that involve the study of thermal properties and changes in temperature over time.

The plot should have the temperature on the x-axis and the pressure on the y-axis. The temperature axis should be labeled in degrees Celsius (°C) and the pressure axis should be labeled in units of pressure such as Pascals (Pa) or atmospheres (atm).

The data points should be plotted between 20°C and 60°C, with several points at different temperatures and corresponding pressures. These points should be labeled with their respective temperature and pressure values.

A line showing the ideal gas law should be plotted on the same graph. This line should be a smooth curve that passes through or near the data points. The equation of the ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature. When plotted on a pressure-temperature graph, the ideal gas law forms a straight line.

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a.) The acceleration of the cart can be calculated using the formula g = 9.8 m/s², where g is the acceleration due to gravity. a = F/m = m × g = 4.40 kg × 9.8 m/s² = 43.12 m/s²

b.) The time it takes the cart to travel from the starting point to the ending point can be calculated using the kinematic equation:

d = v_0t + 1/2at²,

366 m - 53 m = 313 m

313 = 0t + 1/2(43.12)t² = 1/2(43.12)t²

313 = 21.56t²,  t² = 313 / 21.56

t² = 14.52, t = √14.52 = 3.8 sec.

c.) The acceleration of the cylinder can be calculated using the formula a = g - (v²)/Rg

d.) The time it takes the cylinder to travel from the top of the ramp to the bottom can be calculated using the kinematic equation:

d = v_0t + 1/2at²,

What is acceleration?

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The diver's highest point above the board is 0.60 meter, her feet are in the air for 0.684 second, and her velocity when her feet hit the water is 3.43 m/s downward.

To find the diver's highest point, we can use the fact that at the highest point, her velocity will be zero. We can use the equation:

v² = u² + 2as

where u is the initial velocity, v is the final velocity (which is zero at the highest point), a is the acceleration due to gravity (g = 9.81 m/s²), and s is the distance traveled. Solving for s, we get:

s = (v² - u²) / 2a

s = (0 - (3.35 m/s)²) / (2 × -9.81 m/s²)

s = 0.60 m

So the diver's highest point is 0.60 m above the diving board.

To find how long the diver's feet are in the air, we can use the fact that the time of flight (i.e. the time spent in the air) is twice the time it takes to reach the highest point. We can use the equation:

v = u + at

where t is the time, and v and u are the final and initial velocities, respectively. Solving for t, we get:

t = (v - u) / a

At the highest point, the velocity is zero, we can use u = 3.35 m/s and v = 0:

t = (0 - 3.35 m/s) / -9.81 m/s² = 0.342 second

So the time of flight is twice this value, or 0.342 × 2 = 0.684 second.

To find the diver's velocity when her feet hit the water, we can use the same equation as in part (b), but with u = 0 and v as the velocity we want to find. We can also use the fact that the distance traveled from the highest point to the water is the same as the distance traveled from the takeoff point to the highest point (0.60 m). So we have:

s = (v² - u²) / 2a

0.60 m = (v² - 0) / (2 × -9.81 m/s²)

v = -√(2 × -9.81 m/s² × 0.60 m) = -3.43 m/s

The negative sign indicates that the velocity is downward, which makes sense since the diver is falling feet first into the water. So the diver's velocity when her feet hit the water is 3.43 m/s downward.

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A sine wave is a periodic signal that can be measured in terms of it's amplitude, frequency and phase.

Sine waves have equal phase, frequency, and amplitude. The phase of a sine wave determines its position relative to a reference point in time, and a sine wave always starts at zero phase. The frequency of a sine wave is the number of cycles it completes in one second, and the amplitude of a sine wave is the maximum value it reaches. In a pure sine wave, these three properties are constant and equal.

Sine waves are analog signals and are commonly used in communication systems, audio and video processing, and electronic signal processing. They are also used in scientific and engineering applications, such as vibration analysis, acoustics, and control systems.

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--The complete question is, a sine wave is a periodic signal that, 1) can be measured in terms of it's amplitude, frequency and phase 2) has equal phase, frequency and amplitude 3) is digital or analog 4) has a maximum peak amplitude equal to it's frequency--

The only force operating on the ball once it has left its racquet is gravity, which the earth exerts on everything in its immediate vicinity. The ball is accelerated vertically by gravity at a velocity of around 9.8 m/s. ^2,

Hit into their deuce back for the opening point while standing on the right side of the center line; for the second part, serve from of the left side toward what is identified as the advantages service box. Until the game is won, the same player serves; after that, the other player takes over as the server.

In the middle ages, tennis score were shown on two watch faces that ranged from 0 to 60. The pointer changed position on each score, going from Zero to 15, 30, 45, and 60 for a victory.

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To lessen electrostatic attraction between them, the extra charges will be dispersed equally on the enormous conducting plates as widely as feasible.

a. When the battery is connected to the wires, the negatively charged electrons on the wire attached to the negative terminal of the battery will reject one another, driving them to spread as much as possible down the wire.

Positively charged holes (holes left over when electrons are missing) behave similarly to negatively charged holes in that they repel one another and spread out as much as possible down a wire connected to a positive terminal of a battery.

b. In order to prevent the battery from pushing more charge onto the plates, the extra charges on the plates will generate an electric field between them.

The back EMF, sometimes referred to as the counter EMF, grows as the charge on the plates rises. The back EMF will eventually equal the battery's EMF, at which time the battery will be unable to push any more charge onto the plates.

c. Yes, as the battery charges the plates, there will be a current going through the cables. The current is the passage of electrons from the battery's negative terminal onto the negative plate through the wire.

d. Because it shows how well the two plates can hold an electrical charge, much like a capacitor does, the amount C is known as capacitance.

Therefore, For a given voltage differential between the plates, the capacitance increases the amount of charge that may be stored.

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If a particle is moving along a straight line, the net change and the net displacement are always equal.

If a particle is moving along a straight line, then the net change and the net displacement are always the same. Net change is the total change in position of the particle, which is the final position minus the initial position. Net displacement, on the other hand, is the change in position of the particle in a particular direction, which is the final displacement minus the initial displacement.

When a particle moves along a straight line, the direction of its displacement is always the same as the direction of its motion. Therefore, the net displacement is simply the distance traveled by the particle in the direction of motion. And since the net change in position is also the distance traveled by the particle, the net change is always equal to the net displacement in this case.

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This assertion is true: There is no electric field inside a hollow charged conductor.

Any sort of charge causes an electric field to be associated to a location in space. The strength and direction of the electric field are expressed by the value of E, also referred to as the electric field strength, electric field intensity, or simply the electric field.

The electric field is the region of space around an electrically charged particle or object where the charge body feels force. Examples: -Electric fields are created by charges and their configurations, such as capacitors and battery cells.

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A force that is inversely proportional to the distance of the object from equilibrium is consistent with simple harmonic motion.

Mathematically, the restoring force can be expressed as [tex]F = -kx,[/tex]

where F is the restoring force, x is the displacement from equilibrium, and k is the spring constant, which determines the strength of the restoring force. Negative sign indicates that the restoring force is opposite in direction to the displacement. If we rearrange this equation, we get x = -(1/k) * F, which shows that the displacement is inversely proportional to the force. Therefore, a force that is inversely proportional to the distance of the object from equilibrium is consistent with simple harmonic motion.

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The required electric potential energy when charge and diameter of the copper plate are given is calculated to be -432 J/c.

The diameter of the copper plate is given as 15 cm = 0.15 m.

Radius r = diameter d/2 = 0.15/2 = 0.075 c

The charge over the copper plate is given as -3.6 nc = -3.6 × 10⁻⁹ c.

The expression of electric charged plate distributed over the surface is given by,

V = k (q/r)  

where,

V is the electric potential energy

q is the charge over the plate

r is the radius of the plate

k is coulomb's constant (9 × 10⁹ N)

Putting the values into the equation above gives us,

V = k (q/r) = [9 × 10⁹× (-3.6 × 10⁻⁹)]/0.075 = -432 J/c

Thus, the electric potential energy is calculated to be -432 J/c.

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The transition from n=2 to n=1 emits the longest wavelength.

The energy of a photon is directly proportional to its frequency and inversely proportional to its wavelength. A transition of an electron from an excited state to the ground state (n=1) results in the emission of a photon with the longest wavelength in the Lyman series.

The Lyman series corresponds to electron transitions to the n=1 level and includes ultraviolet wavelengths. The transition with the longest wavelength in the Lyman series is from n=2 to n=1, and it corresponds to the emission of a photon with a wavelength of 121.6 nm.

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--The complete question is, When an electron in excited energy level drops to a lower energy level a photon is emitted, if the electron is dropping to n=1 which transition will emit the longest wavelength?--

The required frequency of the sound when distance between the two speakers is given is calculated to be 21.25 kHz.

Sound waves are travelling waves and they can be modelled as

A(r, t) = A₀(r)sin(kr - ωt + Ф₀)

Where,

A₀ is the initial amplitude of the wave

r is the distance

ωt is the frequency

Ф₀ is the initial phase shift

First we need to find out the phase difference (ΔФ) between two waves at different distances.

ΔФ = 2πΔr/λ + ΔФ₀

When you stand centred between the two waves you hear maximum intensity of sound so the the two waves must be in phase

ΔФ = 2πΔr/λ + 0

λ = 2πΔr/ΔФ

The distance when listening in front of the speakers is given by

Δr = r₂ - r₁

r₁ = 6.0 mm = 0.006 m

r₂ = √(0.013²+0.006²) = √(0.000169 + 0.000036) = 0.014 m

Δr = r₂ - r₁ = 0.014 - 0.006 = 0.008 m

λ = 2π × 0.008/ΔФ

The phase difference ΔФ = π

λ = 2π × 0.008/π

λ = 0.016 m

As we know the relation between frequency and wavelength is given by

f = c/λ

Where,

c = 340 m/s is the speed of light

f = 340/0.016

f = 21250 Hz

f = 21.25 kHz

Thus, the frequency of the sound is calculated to be 21.25 kHz.

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Based on the graphs in the figure, the motion of a car and a truck that initially alongside each other at time t = 0. And at time T, the distances traveled by the vehicles since time t = 0 is the car will have travelled further than the truck (option C)

Looking at the graph, the distance traveled by the truck and the car at time T = t is equal.

When T = t, the journey's duration and the speeds of the automobile and truck exactly match each other, as shown by the graph.

Consequently, if we take the equation into account;

V = Δs/Δt

Where;

v = velocity

s = the distance change

t = time change.

Given that the coordinates of velocity and time for the automobile and the truck match, the two objects have gone the same distance.

The area under the curve is used to calculate the mit. The truck would have traveled nearly half as far as the car, which will have traveled the greatest distance.

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The change in velocity in y direction, if the runner accelerates at 0.350 m/s² at 52° angle is 2.83 m/s.

Acceleration of an object is the rate of change in velocity. It is a vector quantity having both direction and magnitude.

a = Δv/t

The initial velocity u = 2.88 m/s

a = 0.350 m/s²

the time t = u/a = 2.88 /0.350 = 8.2 s.

vy = uy + ay t

uy = u sin θ = 2.88 sin 52 =2.84 m/s

ay = 0.350 sin 52 = 0.345 m/s²

then vy = 2.84 m/s + (0.345 m/s²) 8.22 s = 5.67 m/s

then change in velocity in the y-direction is calculated as:

Δy = vy - uy

    = 5.67 m/s  - 2.84 m/s = 2.83 m/s

Therefore, the change in velocity in y-direction Δy for the runner is 2.83 m/s.

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Answer:

Below

Explanation:

Eforce =  C q1 q2 / r^2     C = coulomb's constant

            = (9 x 10^9)  (2.6x 10^-6)(3.8x 10^-6) / (.075)^2 = 15808 x 10^-3

            = 15.8 N     (attractive force because the forces are opposite charge)

i) The period of oscillation of the vertical spring-mass system is 0.643 seconds.

ii) There are two quiet spots along the line segment connecting the speakers.

Over time, oscillation is a form of repeating motion. It describes how an object or system moves back and forth around a fixed point, usually an equilibrium center. Depending on the characteristics of the system, the oscillation may be periodic or non-periodic, and its frequency and amplitude may change. A pendulum's motion, the sound waves produced by a guitar string, and the alternating current in electrical circuits are all examples of oscillation. Oscillation is the repeating or periodic change of a quantity around a central value or between two or more states, often in time. An alternating current and a swinging pendulum are two common examples of oscillation. Numerous physical and biological systems depend on oscillations in one way or another.

(i) The period of oscillation of a horizontal spring-mass system is given by:

T = 2π√(m/k)

where m is the mass of the object attached to the spring, and k is the spring constant.

Using the values given in the problem, we can calculate the period T:

T = 2π√(m/k) = 2π√(1.0 kg / 78 N/m) = 0.571 s

Now, when the same spring-mass system oscillates vertically, the period of oscillation is given by:

T = 2π√(m/k_eff)

where k_eff is the effective spring constant, which takes into account the weight of the mass and the spring.

k_eff = k - mg

where g is the acceleration due to gravity. Substituting the values given in the problem, we get:

k_eff = 78 N/m - (1.0 kg) × (10.0 m/s^2) = 68 N/m

Using the above value of k_eff, we can calculate the period of oscillation T:

T = 2π√(m/k_eff) = 2π√(1.0 kg / 68 N/m) = 0.643 s

(ii) The distance between the two speakers is 7.0 m, which means that the halfway point (where the sound waves from the two speakers would be perfectly out of phase) is located at a distance of 3.5 m from each speaker.

Let's start by considering the point directly in front of one of the speakers. At this point, the distance traveled by the sound wave from the first speaker is simply the distance from that speaker to the point or 3.5 m. The distance traveled by the wave from the second speaker is the distance from that speaker to the point, plus the extra distance of 1.2 m due to the phase difference. Using the Pythagorean theorem, we can calculate this distance as:

sqrt((7.0/2)^2 + (1.2)^2) ≈ 3.65 m

This means that the first quiet spot is located 3.65 m in front of the second speaker.

Similarly, we can find the second quiet spot by considering the point directly in front of the second speaker. At this point, the distance traveled by the wave from the second speaker is simply 3.5 m, while the distance traveled by the wave from the first speaker is 7.0 m - the distance from the point to the second speaker, minus the extra distance of 1.2 m. Using the Pythagorean theorem again, we get:

sqrt((7.0/2)^2 + (1.2)^2) ≈ 3.65 m

This means that the second quiet spot is also located 3.65 m in front of the second speaker, but on the opposite side of the line connecting the speakers.

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Answer:

Explanation:

The work done (W) by a force (F) over a distance (d) can be calculated using the equation:

W = F * d

In this case, the work done by the tractor is 11,100 N-m and the force applied is 257.9 N. To find the distance the tractor pulled the plow, we need to rearrange this equation to solve for d:

d = W / F

Plugging in the values:

d = 11,100 N-m / 257.9 N = 43.01 meters

So, the tractor pulled the plow a distance of 43.01 meters.

The combined mass of the six blocks of steel on the Moon would be 10.0kg. This is because the gravitational force on the Moon is only one sixth of the gravitational force on Earth, meaning that the mass of the blocks would be correspondingly reduced. On the Moon, the blocks of steel would weigh only 1.67 kg each, for a total mass of 10.0kg.

The effect of the reduced gravity on the blocks of steel is due to the inverse square law of gravitation. This law states that the force of gravity between two objects is inversely proportional to the square of the distance between them. Since the Moon is much farther away from the Earth than the blocks of steel were on Earth, the gravitational force on the blocks is much weaker. The reduced gravitational force on the Moon means that the six blocks of steel have a collective mass of 10.0kg. This mass is significantly lower than their combined mass of 60 kg on Earth, which is due to the inverse square law of gravitation.

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The six steel blocks on the Moon would weigh a total of 10.0kg. This is due to the fact that the gravitational force on the Moon is only one sixth that on Earth, which implies that the mass of the blocks would be lowered accordingly.

The steel blocks would only weigh 1.67 kg each, for a total mass of 10.0 kg, on the Moon.

The inverse square law of gravitation is what causes the steel blocks to be affected by the decreasing gravity. According to this rule, the force of gravity is inversely proportional to the square of the distance between two objects. The gravitational pull on the steel blocks is much weaker on the Moon since it is much further away from the Earth than the steel blocks were on Earth. The six steel blocks weigh a total of 10.0 kg due to the Moon's lower gravitational pull. The inverse square law of gravitation explains why this mass is far smaller than their total mass of 60 kg on Earth.

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Answer:

Explanation:

To determine the acceleration of the sled, we need to balance the net force acting on it with its weight.

The weight of the sled and person is given by:

Weight (W) = mass (m) x acceleration due to gravity (g) = 48 kg x 9.8 m/s^2 = 470.4 N

The weight acts vertically downward, perpendicular to the slope of the hill. The net force acting on the sled can be found by subtracting the force of friction from the thrust:

Net force (F) = thrust (T) - weight (W) x sin(θ)

where θ is the angle between the horizontal and the slope of the hill, given as 16.2°.

The force of friction is zero in this case, as the sled is moving up a frictionless icy hill.

So, the net force is simply equal to the thrust:

Net force (F) = thrust (T) = 431 N

The acceleration of the sled is given by:

acceleration (a) = net force (F) / mass (m) = 431 N / 48 kg = 9 m/s^2

Therefore, the magnitude of the acceleration of the sled while it travels up the hill is 9 m/s^2.

The formulated sentences for each will be:

A: If length is 5cm, width 2cm, height 4cm, volume:  40 cubic centimeters.

B: If the length is 3cm, width 4cm, height 2cm, then Volume is: 24 cubic centimeters.

C:  If the length is 6cm, width 2cm, height 3cm, the  volume is 36 cubic centimeters.

D:  If the length is 3cm, width 2cm, height 4cm, the  volume 24 cubic centimeters.

To calculate the volume of a rectangular prism using multiplication, you need to multiply the length, width, and height of the prism. The multiplication sentence for this is:

Volume = length (m) x width (m) x height (m)

For a. The multiplication sentence for calculating the volume of rectangular prism C is:

b. The multiplication sentence for calculating the volume of rectangular prism B is:

c. The multiplication sentence for calculating the volume of rectangular prism C is:

Lastly, for d. The multiplication sentence for calculating the volume of rectangular prism D is:

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Displacement is expressed magnitude and a direction in m, km, ft etc. Among the given options, the one indicting a displacement is 40 km southwest.

Displacement is a physical quantity measuring how far an object is travelling and in which direction from the initial position. The displacement is a vector quantity having both magnitude and direction.

Displacement can be expressed in different units such as m, km, ft etc. Here, 32 ft/s²  and 9.8 m/s² are acceleration. 120 m/s is velocity. Then, 186000 ml is expressing volume of a substance.

Therefore, among the given options, 40 km southwest is indicating the displacement of an object with its magnitude and direction. 40 Km is magnitude and southwest is the direction.

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Answer:

KE = 3456 J

Explanation: