Answer:
The price of 1 adult ticket is 12 dollars, and the price of a ticket for one student is 7 dollars
Step-by-step explanation:
Make a system of equations for the two days that the play was shown.
Let x = the price of an adult ticket
Let y = the price of a student ticket
For the first day:
9x+8y=164For the second day:
2x+7y=73Now, we can solve using the elimination method. Multiply the first equation by 2 and the second equation by 9. Then swap the order of the equations.
18x+63y= 657-18x+16y= 3280x+ 47y= 329divide both sides by 47y = 7Plug in 7 for y for the 2nd equation2x+7(7)=732x+49=73subtract 49 from both sides2x= 24divide both sides by 2x = 12 Check:2(12)+7(7)=7324+49= 73!Answer: And I don’t know math
Step-by-step explanation:
Jackson bought 6 basketballs for 72 dollars what was the price per basket ball
Answer:
the answer would be 12 I say this because 72 divied by 6 would equal 12
Answer:
12 dollars
Set up a proportion.
6/72=1/x
Solve by cross-multiplying (my preferred method) and then you will end up with the final answer of x=12.
12 is the answer :)
PLEASE MARK BRAINLIEST!
THANK YOU & HAVE A WONDERFUL DAY :))
The area of a square is s2, where s is the side length of the square. Jack has a square-shaped flower garden in his yard. Each side of the garden is 8 feet. What is the area of the flower garden?
Answer:
64 square feet
Step-by-step explanation:
A = s² = 8² = 8*8 = 64
Express the following surds in the simplest form
a)
[tex] \sqrt{128} [/tex]
b)
[tex] \sqrt{48} [/tex]
c)
[tex] \sqrt{300} [/tex]
[tex] \sqrt{128} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2} \\ = \sqrt{ {2}^{2} \times {2}^{2} \times {2}^{2} } \\ = 2 \times 2 \times 2 \\ = 8[/tex]
[tex] \sqrt{48} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 3} \\ = \sqrt{ {2}^{2} \times {2}^{2} \times 3 } \\ = 2 \times 2 \sqrt{3} \\ = 4 \sqrt{3} [/tex]
[tex] \sqrt{300} \\ = \sqrt{2 \times 2 \times3 \times 5 \times 5} \\ = \sqrt{ {2}^{2} \times 3 \times {5}^{2} } \\ = 2 \times 5 \sqrt{3} \\ = 10 \sqrt{3} [/tex]
Hope you could get an idea from here.
Doubt clarification - use comment section.
The area of a square pond is 1000m2.A path of uniform width is surrounded outside the pond and its area is 369m2.find the outer length of the path
Answer:
631 m²
Step-by-step explanation:
Outer length of park = Total area - Area of pond
Outer length of park = 1000 - 369
Outer length of park = 631 m²
Answer:
Hope it will help you a lot.
Which expression is undefined?
Answer:
D: [tex]\frac{3}{(6-6)}[/tex]
Step-by-step explanation:
Option A equates to [tex]-\frac{0}{2}=0[/tex]
Option B equates to [tex]\frac{(-4+0)}{8}=\frac{-4}{8}=-\frac{1}{2}[/tex]
Option C equates to [tex]0\div11 =0[/tex]
Option D equates to [tex]\frac{3}{(6-6)}=\frac{3}{0}[/tex] which cannot be defined as division by 0 is impossible
Which numbered choice shows a set of numbers whose product is -20 and whose sum is +1?
Help, im incredibly confused
[tex]f[/tex](x) = 0.20x + 35 : 29.5
Find an equation of the plane.
The plane that contains the line
x = 3 + 2t,
y = t,
z = 6 − t
and is parallel to the plane
2x + 4y + 8z = 16
Answer:
x +2y +4z = 27
Step-by-step explanation:
The parallel plane will have the same coefficients of x, y, z as the given plane. We notice those have a common factor of 2, so the equation can be reduced to ...
x +2y +4z = constant
This equation is satisfied for every point on the line, so we have ...
(3 +2t) +2(t) +4(6 -t) = constant . . . . . substituting for x, y, z
3 +2t +2t +24 -4t = constant
27 = constant
The equation of the desired plane is ...
x +2y +4z = 27
The normal to the given plane is (2, 4, 8), and the plane we want is parallel to this one so it has the same normal vector.
When t = 0, the given line, and thus the plane we want, passes through the point (3, 0, 6).
Then the equation of the plane is given by
(2, 4, 8) • (x - 3, y - 0, z - 6) = 0
2 (x - 3) + 4y + 8 (z - 6) = 0
2x + 4y + 8z = 54
or
x + 2y + 4z = 27
f(x)=x^2. what is g(x)?
A spherical solid, centered at the origin, has radius 4 and mass density(x,y,z)=6-(x^2+y^2+z^2). Set up the triple integral and find its mass.
I've attached a photo of the question.
There's something very off about this question.
In spherical coordinates,
x² + y² + z² = ρ²
so that
f(x, y, z) = 6 - (x² + y² + z²)
transforms to
g(ρ, θ, φ) = 6 - ρ²
When transforming to spherical coordinates, we also introduce the Jacobian determinant, so that
dV = dx dy dz = ρ² sin(φ) dρ dθ dφ
Since we integrate over a sphere with radius 4, the domain of integration is the set
E = {(ρ, θ, φ) : 0 ≤ ρ ≤ 4 and 0 ≤ θ ≤ 2π and 0 ≤ φ ≤ π}
so that the integral is
[tex]\displaystyle \int_{\phi=0}^{\phi=\pi} \int_{\theta=0}^{\theta=2\pi} \int_{\rho=0}^{\rho=4} (6 - \rho^2) \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi[/tex]
Computing the integral is simple enough.
[tex]\displaystyle = \int_{\phi=0}^{\phi=\pi} \int_{\theta=0}^{\theta=2\pi} \int_{\rho=0}^{\rho=4} (6 \rho^2 - \rho^4) \sin(\phi) \, d\rho \, d\theta \, d\phi[/tex]
[tex]\displaystyle = 2\pi \int_{\phi=0}^{\phi=\pi} \int_{\rho=0}^{\rho=4} (6 \rho^2 - \rho^4) \sin(\phi) \, d\rho \, d\phi[/tex]
[tex]\displaystyle = 2\pi \left(\int_{\phi=0}^{\phi=\pi} \sin(\phi) \, d\phi\right) \left(\int_{\rho=0}^{\rho=4} (6 \rho^2 - \rho^4) \, d\rho\right)[/tex]
[tex]\displaystyle = 2\pi \cdot 2 \cdot \left(-\frac{384}5\right) = \boxed{-\frac{1536\pi}5}[/tex]
but the mass can't be negative...
Chances are good that this question was recycled without carefully changing all the parameters. Going through the same steps as above, the mass of a spherical body with radius R and mass density given by
[tex]\delta(x, y, z) = k - (x^2 + y^2 + z^2)[/tex]
for some positive number k is
[tex]\dfrac{4\pi r^3}{15} \left(5k - 3r^2\right)[/tex]
so in order for the mass to be positive, we must have
5k - 3r² ≥ 0 ⇒ k ≥ 3r²/5
In this case, k = 6 and r = 4, but 3•4²/5 = 9.6.
find the angle of rotation that maps point D onto point A
Answer:
A - 144
Step-by-step explanation:
everything else would be too far. thx
Round 9296 to the nearest hundred?
The answer it 9300 so 9296 round to is 9300
Hello, would be very nice if someone could help me ! :)
A finite geometric series is the sum of a sequence of numbers. Take the sequence
1, 2, 4, 8, ..., for example. Notice that each number is twice the value of the
previous number. So, a number in the sequence can be represented by the
function f(n) = 2^n-1. One way to write the sum of the sequence through the 5th
number in the sequence is ∑^5 n-1 2^n-1.
This equation can also be written as S5 = 2^0+2^1+ 2^2+ 2^3+ 2^4. If we multiply this equation by 2. the equation becomes 2(S5) = 2^1+ 2^2+ 2^3+ 2^4+ 2^5
What happens if you subtract the two equations and solve for S5? Can you use this information to come up with a way to find any geometric series Sn in the
form ∑^a n-1 b^n-1 ?
Answer:
Step-by-step explanation:
2S₅ - S₅ = 2⁵ - 2⁰
S₅ = 2⁵ - 1
Sₙ = (bᵃ - 1) / (b - 1)
50, 60, 72, ...
Find the 8th term.
You flip a coin 8 times and get tails 6 times. Based on this experiment, what is the probability of flipping a coin and getting heads?
Answer:
1/4
Step-by-step explanation:
If you get 6 tails, then that means you got 2 heads. 8-6=2.
probability= 2/8=1/4 based on this experiment.
[tex]\sqrt[3]{y} (7\sqrt[3]{8y^2}-\sqrt[3]{y^5} -4y\sqrt[3]{27y^2}[/tex] simplify
Answer:
[tex]\huge\boxed{-y^2+2y}[/tex]
Step-by-step explanation:
[tex]\sqrt[3]y\cdot\left(7\sqrt[3]{8y^2}-\sqrt[3]{y^5}-4y\sqrt[3]{27y^2}\right)\\\\=(\sqrt[3]y)(7\sqrt[3]{8y^2})-(\sqrt[3]y)(\sqrt[3]{y^5})-(\sqrt[3]y)(4y\sqrt[3]{27y^2})\\\\=7\sqrt[3]{(y)(8y^2)}}-\sqrt[3]{(y)(y^5)}-4y\sqrt[3]{(y)(27y^2)}\\\\=7\sqrt{8y^3}-\sqrt{y^6}-4\sqrt{27y^3}\\\\=7\sqrt[3]{2^3y^3}-\sqrt{y^{2\cdot3}}-4\sqrt{3^3y^3}\\\\=7\sqrt[3]{(2y)^3}-\sqrt{(y^2)^3}-4\sqrt{(3y)^3}\\\\=7\cdot2y-y^2-4\cdot3y\\\\=14y-y^2-12y\\\\=-y^2+2y[/tex]
Used:
[tex]a(a+b)=ab+ac\\\\\sqrt[3]{a\cdot b}=\sqrt[3]a\cdot\sqrt[3]b\\\\\sqrt[3]{a^3}=a\\\\(a^n)^m=a^{n\cdot m}[/tex]
Omar needs at least $8 to buy lunch. Which number line represents this scenario?
Answer:
I'd say none, as we're missing something in this problem. Make sure you've included everything to solve this problem. Thanks.
A waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of 5 mugs from a full pot of coffee. If her coffee pot holds 8 cups, how many fluid ounces does she have left?
Answer:
4 fluid ounces
Step-by-step explanation:
A waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of 5 mugs from a full pot of coffee. If her coffee pot holds 8 cups, how many fluid ounces does she have left?
Remember
8 fluid ounces = 1 cup.
First you need to do find out how many fluid ounces she poured in total.
So do,
5 mugs × 12 fluid ounces.
which is 60 fluid ounces.
Now that you now that you need to convert 8 cups into fluid ounces.
Like I said at the top 8 fluid ounces = 1 cup.
So you need to do,
8 cups × 8 fluid ounces.
Which is 64 fluid ounces she can hold in her coffee pot.
Now you subtract,
64 fluid ounces - 60 fluid ounces.
Which is 4 fluid ounces left in her coffee pot.
The number of fluid ounces she has left is 4 fluid ounces if the waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of the 5 mugs from a full pot of coffee.
What is unit conversion?It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.
It is given that:
A waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of 5 mugs from a full pot of coffee.
Let x be the number of fluid ounces she has left.
4 fluid ounces
As we know,
8 fluid ounces = 1 cup
The total amount of coffee = 5×12
The total amount of coffee = 60
Total amount = 8 cups × 8 fluid ounces.
x = 64 fluid ounces - 60 fluid ounces.
x = 4 fluid ounces
Thus, the number of fluid ounces she has left is 4 fluid ounces if the waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of the 5 mugs from a full pot of coffee.
Learn more about the unit conversion here:
brainly.com/question/14350438
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The two triangles are similar. Find the values of the unknown variables
Answer:
x = 84 y = 59°
Step-by-step explanation:
x = (40/30)×63
x = 84
∆ABC = ∆PQR
so y = 59°
Answer:
1.) 47
2.) 28
Step-by-step explanation:
you just had to use the sin equation for both
The point (3, 3) is in what quadrant? 2,1,3,4
Answer:
1
Step-by-step explanation:
(3,3) has a positive x value and a positive y value which means it is in the first quadrant
c. A square that is 8 inches on a side is placed inside a rectangle that has a length of 24 inches and a width of 20 inches. What is the area of the region inside the rectangle that surrounds the square?
Area = length x width
Area of square = 8 x 8 = 64 square inches
Area of rectangle = 24 x 20 = 480 square inches
Area of rectangle surrounding the square = 480 - 64 = 416 square inches
Answer: 416 square inches
Use the fundamental identities to
Find tan s if sin s=3/4 and s is in quadrant 2
Answer:
Cosine Formula
Thus, the cosine of angle α in a right triangle is equal to the adjacent side's length divided by the hypotenuse. To solve cos, simply enter the length of the adjacent and hypotenuse and solve.
desceibe how to determine the average rate of change between x=4 and x=6 for the function f(x)=2x^3 +4
[tex]slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2x^3+4\qquad \begin{cases} x_1=4\\ x_2=6 \end{cases}\implies \cfrac{f(6)-f(4)}{6-4} \\\\\\ \cfrac{[2(6)^3+4]~~ -~~[2(4)^3+4]}{2}\implies \cfrac{436~~ -~~132}{2}\implies \cfrac{304}{2}\implies 152[/tex]
Which expression is equivalent to 1/4 (5x + 6)?
The expression which is equivalent to 1/4 (5x + 6) is; Choice A: {5(1/4)x} + {6(1/4)x}.
According to the question:
We are required to determine an expression which is equivalent to 1/4 (5x + 6).In a bid to expand the expression; we must multiply each term in the parenthesis by (1/4);
In essence; we have;
{5(1/4)x} + {6(1/4)x}Read more on multiplication;
https://brainly.com/question/847421
6(25-8w)+20w for w=2
150−28w
i think i dont know
4. This diagram is a straightedge and compass construction of a line perpendicular to line AB passing through point C. Which segment has the same length as segment EA.
a. EC
b. ED
C. BE
d. BD
Answer:
Segment ED has the same length as EA
The line segment which is equal to EA is ED. Therefore, option B is the correct answer.
In the given diagram, a line perpendicular to line AB passes through point C.
What is the tangent to the circle?A tangent to a circle is a line which intersects the circle at only one point. The common point between the tangent and the circle is called the point of contact.
The length of two tangents drawn from an external point to a circle is equal.
From the given figure we can see there are three circles, two large circles and one small circle.
Line segment EA is tangent to a small circle.
The line segment which is equal to EA is ED because ED is another tangent to a small circle from the same external point.
The line segment which is equal to EA is ED. Therefore, option B is the correct answer.
To learn more about the tangent to a circle visit:
https://brainly.com/question/16592747.
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Help help help help hep
Answer:
Yes
Step-by-step explanation:
let f(x)=3x^2-6x+5 what is the leading coefficient
PLEASE HELP ME WITH GEOMETRY
Answer:
The answer is A.
Step-by-step explanation:
It is A because both sides match up except for the last pair, where they are the same. Hope this helped!
What is 40÷1/2 please help me
Answer: Pretty sure it's 80
Step-by-step explanation: