he school that Tony goes to is selling tickets to a play. On the first day of ticket sales the school
sold 9 adult tickets and 8 student tickets for a total of $164. The school took in $73 on the second
day by selling 2 adult tickets and 7 student tickets.

What is the price each of one adult ticket?

What is the price each of one student ticket?

Plz explain how to do this

Answer:

The answer is A.

Step-by-step explanation:

It is A because both sides match up except for the last pair, where they are the same. Hope this helped!

Answer:

x = 84 y = 59°

Step-by-step explanation:

x = (40/30)×63

x = 84

∆ABC = ∆PQR

so y = 59°

Answer:

1.) 47

2.) 28

Step-by-step explanation:

you just had to use the sin equation for both

Answer:

Step-by-step explanation:

2S₅ - S₅ = 2⁵ - 2⁰

        S₅ = 2⁵ - 1

Sₙ = (bᵃ - 1) / (b - 1)

Answer:

Cosine Formula

Thus, the cosine of angle α in a right triangle is equal to the adjacent side's length divided by the hypotenuse. To solve cos, simply enter the length of the adjacent and hypotenuse and solve.

Answer:

the answer would be 12 I say this because 72 divied by 6 would equal 12

Answer:

12 dollars

Set up a proportion.

6/72=1/x

Solve by cross-multiplying (my preferred method) and then you will end up with the final answer of x=12.

12 is the answer :)

PLEASE MARK BRAINLIEST!

THANK YOU & HAVE A WONDERFUL DAY :))

Answer:

[tex]\huge\boxed{-y^2+2y}[/tex]

Step-by-step explanation:

[tex]\sqrt[3]y\cdot\left(7\sqrt[3]{8y^2}-\sqrt[3]{y^5}-4y\sqrt[3]{27y^2}\right)\\\\=(\sqrt[3]y)(7\sqrt[3]{8y^2})-(\sqrt[3]y)(\sqrt[3]{y^5})-(\sqrt[3]y)(4y\sqrt[3]{27y^2})\\\\=7\sqrt[3]{(y)(8y^2)}}-\sqrt[3]{(y)(y^5)}-4y\sqrt[3]{(y)(27y^2)}\\\\=7\sqrt{8y^3}-\sqrt{y^6}-4\sqrt{27y^3}\\\\=7\sqrt[3]{2^3y^3}-\sqrt{y^{2\cdot3}}-4\sqrt{3^3y^3}\\\\=7\sqrt[3]{(2y)^3}-\sqrt{(y^2)^3}-4\sqrt{(3y)^3}\\\\=7\cdot2y-y^2-4\cdot3y\\\\=14y-y^2-12y\\\\=-y^2+2y[/tex]

Used:

[tex]a(a+b)=ab+ac\\\\\sqrt[3]{a\cdot b}=\sqrt[3]a\cdot\sqrt[3]b\\\\\sqrt[3]{a^3}=a\\\\(a^n)^m=a^{n\cdot m}[/tex]

Answer:

1/4

Step-by-step explanation:

If you get 6 tails, then that means you got 2 heads. 8-6=2.

probability= 2/8=1/4 based on this experiment.

Answer:

Segment ED has the same length as EA

The line segment which is equal to EA is ED. Therefore, option B is the correct answer.

In the given diagram, a line perpendicular to line AB passes through point C.

A tangent to a circle is a line which intersects the circle at only one point. The common point between the tangent and the circle is called the point of contact.

The length of two tangents drawn from an external point to a circle is equal.

From the given figure we can see there are three circles, two large circles and one small circle.

Line segment EA is tangent to a small circle.

The line segment which is equal to EA is ED because ED is another tangent to a small circle from the same external point.

The line segment which is equal to EA is ED. Therefore, option B is the correct answer.

To learn more about the tangent to a circle visit:

https://brainly.com/question/16592747.

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[tex]slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= 2x^3+4\qquad \begin{cases} x_1=4\\ x_2=6 \end{cases}\implies \cfrac{f(6)-f(4)}{6-4} \\\\\\ \cfrac{[2(6)^3+4]~~ -~~[2(4)^3+4]}{2}\implies \cfrac{436~~ -~~132}{2}\implies \cfrac{304}{2}\implies 152[/tex]

Answer:

D: [tex]\frac{3}{(6-6)}[/tex]

Step-by-step explanation:

Option A equates to [tex]-\frac{0}{2}=0[/tex]

Option B equates to [tex]\frac{(-4+0)}{8}=\frac{-4}{8}=-\frac{1}{2}[/tex]

Option C equates to [tex]0\div11 =0[/tex]

Option D equates to [tex]\frac{3}{(6-6)}=\frac{3}{0}[/tex] which cannot be defined as division by 0 is impossible

Answer:

1

Step-by-step explanation:

(3,3) has a positive x value and a positive y value which means it is in the first quadrant

Answer:

  x +2y +4z = 27

Step-by-step explanation:

The parallel plane will have the same coefficients of x, y, z as the given plane. We notice those have a common factor of 2, so the equation can be reduced to ...

  x +2y +4z = constant

This equation is satisfied for every point on the line, so we have ...

  (3 +2t) +2(t) +4(6 -t) = constant . . . . . substituting for x, y, z

  3 +2t +2t +24 -4t = constant

  27 = constant

The equation of the desired plane is ...

  x +2y +4z = 27

The normal to the given plane is (2, 4, 8), and the plane we want is parallel to this one so it has the same normal vector.

When t = 0, the given line, and thus the plane we want, passes through the point (3, 0, 6).

Then the equation of the plane is given by

(2, 4, 8) • (x - 3, y - 0, z - 6) = 0

2 (x - 3) + 4y + 8 (z - 6) = 0

2x + 4y + 8z = 54

or

x + 2y + 4z = 27

The answer it 9300 so 9296 round to is 9300

[tex]f[/tex](x) = 0.20x + 35 : 29.5

Answer:

Yes

Step-by-step explanation:

Answer:

631 m²

Step-by-step explanation:

Outer length of park = Total area - Area of pond

Outer length of park = 1000 - 369

Outer length of park = 631 m²

Answer:

Hope it will help you a lot.

Answer:

64 square feet

Step-by-step explanation:

A = s² = 8² = 8*8 = 64

Answer:

4 fluid ounces

Step-by-step explanation:

A waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of 5 mugs from a full pot of coffee. If her coffee pot holds 8 cups, how many fluid ounces does she have left?

Remember

8 fluid ounces = 1 cup.

First you need to do find out how many fluid ounces she poured in total.

So do,

5 mugs × 12 fluid ounces.

which is 60 fluid ounces.

Now that you now that you need to convert 8 cups into fluid ounces.

Like I said at the top 8 fluid ounces = 1 cup.

So you need to do,

8 cups × 8 fluid ounces.

Which is 64 fluid ounces she can hold in her coffee pot.

Now you subtract,

64 fluid ounces - 60 fluid ounces.

Which is 4 fluid ounces left in her coffee pot.

The number of fluid ounces she has left is 4 fluid ounces if the waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of the 5 mugs from a full pot of coffee.

It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.

It is given that:

A waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of 5 mugs from a full pot of coffee.

Let x be the number of fluid ounces she has left.

4 fluid ounces

As we know,

8 fluid ounces = 1 cup

The total amount of coffee = 5×12

The total amount of coffee = 60

Total amount = 8 cups × 8 fluid ounces.

x = 64 fluid ounces - 60 fluid ounces.

x = 4 fluid ounces

Thus, the number of fluid ounces she has left is 4 fluid ounces if the waitress is filling coffee mugs at a diner. She pours 12 fluid ounces into each of the 5 mugs from a full pot of coffee.

Learn more about the unit conversion here:

brainly.com/question/14350438

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Area = length x width

Area of square = 8 x 8 = 64 square inches

Area of rectangle = 24 x 20 = 480 square inches

Area of rectangle surrounding the square = 480 - 64 = 416 square inches

Answer: 416 square inches

There's something very off about this question.

In spherical coordinates,

x² + y² + z² = ρ²

so that

f(x, y, z) = 6 - (x² + y² + z²)

transforms to

g(ρ, θ, φ) = 6 - ρ²

When transforming to spherical coordinates, we also introduce the Jacobian determinant, so that

dV = dx dy dz = ρ² sin(φ) dρ dθ dφ

Since we integrate over a sphere with radius 4, the domain of integration is the set

E = {(ρ, θ, φ) : 0 ≤ ρ ≤ 4 and 0 ≤ θ ≤ 2π and 0 ≤ φ ≤ π}

so that the integral is

[tex]\displaystyle \int_{\phi=0}^{\phi=\pi} \int_{\theta=0}^{\theta=2\pi} \int_{\rho=0}^{\rho=4} (6 - \rho^2) \rho^2 \sin(\phi) \, d\rho \, d\theta \, d\phi[/tex]

Computing the integral is simple enough.

[tex]\displaystyle = \int_{\phi=0}^{\phi=\pi} \int_{\theta=0}^{\theta=2\pi} \int_{\rho=0}^{\rho=4} (6 \rho^2 - \rho^4) \sin(\phi) \, d\rho \, d\theta \, d\phi[/tex]

[tex]\displaystyle = 2\pi \int_{\phi=0}^{\phi=\pi} \int_{\rho=0}^{\rho=4} (6 \rho^2 - \rho^4) \sin(\phi) \, d\rho \, d\phi[/tex]

[tex]\displaystyle = 2\pi \left(\int_{\phi=0}^{\phi=\pi} \sin(\phi) \, d\phi\right) \left(\int_{\rho=0}^{\rho=4} (6 \rho^2 - \rho^4) \, d\rho\right)[/tex]

[tex]\displaystyle = 2\pi \cdot 2 \cdot \left(-\frac{384}5\right) = \boxed{-\frac{1536\pi}5}[/tex]

but the mass can't be negative...

Chances are good that this question was recycled without carefully changing all the parameters. Going through the same steps as above, the mass of a spherical body with radius R and mass density given by

[tex]\delta(x, y, z) = k - (x^2 + y^2 + z^2)[/tex]

for some positive number k is

[tex]\dfrac{4\pi r^3}{15} \left(5k - 3r^2\right)[/tex]

so in order for the mass to be positive, we must have

5k - 3r² ≥ 0   ⇒   k ≥ 3r²/5

In this case, k = 6 and r = 4, but 3•4²/5 = 9.6.

Answer:

A - 144

Step-by-step explanation:

everything else would be too far. thx

150−28w

i think i dont know

Answer:

I'd say none, as we're missing something in this problem. Make sure you've included everything to solve this problem. Thanks.

The expression which is equivalent to 1/4 (5x + 6) is; Choice A: {5(1/4)x} + {6(1/4)x}.

According to the question:

In a bid to expand the expression; we must multiply each term in the parenthesis by (1/4);

In essence; we have;

Read more on multiplication;

https://brainly.com/question/847421

Answer: Pretty sure it's 80

Step-by-step explanation:

[tex] \sqrt{128} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2} \\ = \sqrt{ {2}^{2} \times {2}^{2} \times {2}^{2} } \\ = 2 \times 2 \times 2 \\ = 8[/tex]

[tex] \sqrt{48} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 3} \\ = \sqrt{ {2}^{2} \times {2}^{2} \times 3 } \\ = 2 \times 2 \sqrt{3} \\ = 4 \sqrt{3} [/tex]

[tex] \sqrt{300} \\ = \sqrt{2 \times 2 \times3 \times 5 \times 5} \\ = \sqrt{ {2}^{2} \times 3 \times {5}^{2} } \\ = 2 \times 5 \sqrt{3} \\ = 10 \sqrt{3} [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.