If the temperature is raised while maintaining a constant pressure of 100 atm, CO2 will transition from a solid to a liquid, then from a liquid to a supercritical fluid, and lastly to a gas. This is the fourth of four targets.
What is the definition of temperature?Heat energy will logically go from a warmer (body with a high temp) to the a cooler (body with a low temp) according to temperature (one at a lower temperature). How cold or hot something is can be expressed numerically using the physiological concept of temperature. A thermometer is used to determine temperature. Thermometers were calibrated using various temperature scales that historically specified unique reference points & thermometric materials.
What is difference between heat and temperature?It is measured in joules. Heat will therefore serve as a gauge for the flow or movement of energy. You must be aware of the fact that an object will receive or lose heat but not have heat if you want to comprehend the distinction between heat and temperature. It can therefore be referred to as a measure of change. The concepts of temperature and heat are very dissimilar. a thermometer with Farenheit and Celsius scales. The average molecular kinetic energy of a substance is measured by its temperature. The temperature of something is a statement about how quickly the molecules are moving within that object.
Target 1 of 4 is the phase shifts that happen when CO2 is heated from 190 K to 350 K at a constant pressure of 1 atm. It is known as sublimation when CO2 changes its phase at 1 atm from a solid (dry ice) to a gas (carbon dioxide vapor) without going through the liquid phase.
CO2 will experience a separate set of phase shifts when subjected to pressures greater than 1 atm. CO2 will change its state from a solid to a liquid at 5.1 atm constant pressure, and then from a liquid to a gas when the temperature rises. This is the second of four targets.
When the temperature is raised, CO2 will transition from a solid to a liquid at a constant pressure of 10 atm, and then from a liquid to a supercritical fluid. This is the third of four targets.
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synthesis of dihydropyran dihydropyran is synthesized by treating tetrahydrofurfuryl alcohol with an arenesulfonic acid, arso3h. draw curved arrows to show the movement of electrons in this step of the reaction mechanism.
The creation of dihydropyran Tetrahydrofurfuryl alcohol is converted into dihydropyran by reacting it with the arenesulfonic acid arso3h.
Here's the reaction mechanism for the synthesis of dihydropyran from tetrahydrofurfuryl alcohol and arylsulfonic acid:
First, the acid protonates the alcohol to make it a better leaving group:
OH-CH2CH2CH2CH2-OH + ArSO3H → OH2+-CH2CH2CH2CH2-OH + ArSO3-
The product is then deprotonated by a base, such as sodium methoxide, to form dihydropyran:
[OC(CH2)2-Ar]+SO3- + NaOCH3 → OC(CH2)2-Ar + NaSO4CH3-
Overall, the reaction can be represented as:
OH-CH2CH2CH2CH2-OH + ArSO3H → dihydropyran + NaSO4CH3-
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which of the following is a false statement concerning amino groups?group of answer choicesthey are basic in ph.they are nonpolar.they contain nitrogen.they are found in amino acids.
The false statement concerning amino groups are nonpolar.
What is meant by amino groups?Nitrogen and hydrogen are the two components that make up an amino group. The chemical composition of an amino group is NH2. A single covalent link holds the N-H atoms in this functional group together.
Amines are substances and functional groups in chemistry that have a nitrogen atom that is basic and has a lone pair. Amines are technically ammonia derivatives in which one or more hydrogen atoms have been swapped out for a substituent, like an alkyl or aryl group.
A specific kind of functional group called an amino group is made up of one nitrogen and two hydrogens that are joined by a single covalent link. The chemical structure of the amino group is NH2.
Therefore, the correct answer is option D) They are nonpolar.
The complete question is;
Which of the following is a false statement concerning amino groups?
A) They are basic in pH.
B) They are found in amino acids.
C) They contain nitrogen.
D) They are nonpolar.
E) They are components of urea.
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Why is molecular polarity important for life?
Molecular polarity is important for life because it plays a crucial role in many biological processes.
What is molecular polarity?Molecular polarity refers to the distribution of electrical charge within a molecule. It is a property that results from differences in the electronegativity of the atoms in a molecule.
Molecular polarity is important for life because many biological molecules, including proteins, DNA, and carbohydrates, are polar, meaning they have regions of positive and negative charge.
This allows them to interact with other polar molecules, such as water, through hydrogen bonding, which helps to stabilize their structures and maintain their functionalities.
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Practice
If G = green and g = purple, how many offspring will be
purple if the parents' genotypes are gg and
In the text boxes, write the percentage of offspring that is green and
the percentage that is purple.
6GB
g g
Gg
G Gg
ggggg
Green
Purple
The percentage of purple offspring and green offspring are 25% and 25% respectively.
What is offspring?Offspring are living creatures' young creations, generated either from a single organism as well as, inside the event of sexual reproduction, by two organisms. In a broader sense, collective children may be referred to by the term brood or progeny.
This can apply to a group of children born at the same time, such as chicks hatching from a single clutch of eggs, or to the entire offspring, as in the case of the honeybee.
purple offspring = 25%
green offspring = 25%
Therefore, the percentage of purple offspring and green offspring are 25% and 25% respectively.
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Your question is incomplete but most probably your full question was,
If G = green and g = purple, how many offspring will be purple if the parents' genotypes are gg and write the percentage of offspring that is green and the percentage that is purple. 25%, 35%,45%
Which of the following is an experimental procedure used to study how attention affects the processing of competing stimuli?
A. Early selection
B. Filtering
C. Channeling
D. Dichotic listening
The experimental procedure used to study how attention affects the processing of competing stimuli would be dichotic listening.
What is dichotic listening?Dichotic listening is an experimental technique used to study selective attention in the auditory domain.
In a typical dichotic listening task, different sounds are presented simultaneously to both ears, with different stimuli presented to each ear. Participants are asked to attend to one ear (the "attended ear") and to ignore the other ear (the "unattended ear"), while listening to the sounds.
After the sounds have been presented, participants are typically asked to recall or identify the sounds presented to the attended ear. The task allows researchers to investigate the mechanisms underlying selective attention in the auditory system and to study factors that influence the selection and processing of auditory information.
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An aqueous solution of Ca(OH)2 at 25 oC has a pH of 12.4. Assume Ca(OH)2 fully dissociates. Calculate the concentration (in M) of Ca(OH)2. Report to 3 decimal places.
Answer:
the first one may be more complex so the second one will be simplified :)
Explanation:
The mass of the empty Erlenmeyer flask is 232.7 g. When filled with sodium chloride solution (density = 1.744 g/mL), the flask's mass is 428.6 g. What volume, in mL, of sodium chloride solution does the flask hold? Report the answer to one place after the decimal. Do not include the units.
The volume of the sodium chloride solution in the flask is 112.3 mL.
To find the volume of the sodium chloride solution in the Erlenmeyer flask, we first need to find the mass of the solution. We can do this by subtracting the mass of the empty flask from the mass of the filled flask:
Mass of solution = 428.6 g - 232.7 g = 195.9 g
Next, we can use the density of the solution to find the volume.
Density is defined as mass divided by volume, so we can rearrange the equation to solve for volume:
Volume = Mass / Density = 195.9 g / 1.744 g/mL = 112.3 mL
Finally, we can round our answer to one place after the decimal:
Volume = 112.3 mL ≈ 112.3 mL
So the volume of the sodium chloride solution in the flask is 112.3 mL.
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What mass of ice (in g) can be melted if 24.9 kJ of thermal energy are added at the freezing point? Use molar mass = 18.02 g/mol
The answer is approximately 1332.75 g of ice can be melted if 24.9 kJ of thermal energy are added at the freezing point.
What is thermal energy?
Thermal energy refers to the energy contained within a system that is responsible for its temperature.
The heat required to melt a substance is equal to the enthalpy of fusion of that substance times its mass. The molar enthalpy of fusion of ice is 333.55 J/mol, so the amount of heat required to melt 1 mol of ice is 333.55 J.
To find the mass of ice that can be melted with 24.9 kJ of thermal energy, we first need to convert the energy from kJ to J:
24.9 kJ = 24.9 x 10^3 J = 24900 J
Next, we divide the amount of thermal energy by the molar enthalpy of fusion of ice to find the number of moles of ice that can be melted:
24900 J / 333.55 J/mol = 74.22 mol
Finally, we multiply the number of moles of ice by its molar mass to find the mass of ice in grams:
74.22 mol x 18.02 g/mol = 1332.75 g
Therefore, The answer is approximately 1332.75 g of ice can be melted if 24.9 kJ of thermal energy are added at the freezing point.
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I need to mark the steepest areas.
The hilltops and the steepest point of a slope are found in the highest and most closely-spaced contour lines on the map.
What are contour lines?Contour lines are lines on a map that connect points of equal elevation. Each contour line represents a specific elevation, and the spacing between contour lines represents the slope of the terrain.
The closer the contour lines are to each other, the steeper the slope. The hilltops are found where the contour lines form a closed circle or oval shape. The steepest point of a slope is found where the contour lines are closest together, indicating the highest rate of change in elevation.
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if you take 5ml of this solution and dilute it too 150ml what is the concentration of the glucose in the resulting solution in micromoles
The concentration of the glucose in the resulting solution will contain[tex]33micromoles/L[/tex]
Glucose is a simple sugar molecule composed of 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms. The chemical formula for glucose is C6H12O6. Glucose is a monosaccharide, meaning it is a single-molecule sugar. It is the most important source of energy for living organisms and is found in many foods. Assuming that the initial solution contains 5 millimoles of glucose (5 mmol/L), the resulting solution will contain
[tex]{5 mmol}{150mL} \\= 0.033 mol/L \\= 33 micromoles/L.[/tex]
This can be expressed using the equation:
C1 V1 = C2 V2
Where C1 is the concentration of the original solution (5 mmol/L), V1 is the volume of the original solution (5 mL), C2 is the concentration of the resulting solution (33 micromoles/L) and V2 is the volume of the resulting solution (150 mL).
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An open manometer is filled with mercury and
connected to a container of hydrogen. The
mercury level is 78.0 mm higher in the arm of the
tube connected to the air. Air pressure is
100.7 kPa. What is the pressure of the hydrogen in kilopascals?
Does anyone know what the container pressure would be? and how do I solve this?
Answer:
The pressure of the hydrogen in the container can be determined by using the equation:
P_H2 + ρgh = P_air
where P_H2 is the pressure of the hydrogen, ρ is the density of mercury (13,600 kg/m^3), g is the acceleration due to gravity (9.8 m/s^2), and h is the height difference between the mercury levels in the two arms of the manometer.
First, we need to convert the height difference from millimeters to meters:
h = 78.0 mm = 0.078 m
Next, we can substitute the given values into the equation:
P_H2 + (13,600 kg/m^3)(9.8 m/s^2)(0.078 m) = 100.7 kPa
Solving for P_H2, we get:
P_H2 = 100.7 kPa - (13,600 kg/m^3)(9.8 m/s^2)(0.078 m)
P_H2 = 99.0 kPa
Therefore, the pressure of the hydrogen in the container is 99.0 kPa
Calculate the percent by mass of the solute in the following solution: 4.10 g of toluene in 29.0 g of benzene.
The percent by mass of the solute (toluene) in the solution is 12.4%.
To calculate the percent by mass of the solute in a solution, you need to divide the mass of the solute by the mass of the entire solution and multiply by 100%.
In this case, the solute is 4.10 g of toluene, and the solvent is 29.0 g of benzene. Therefore, the mass of the entire solution is:
4.10 g (toluene) + 29.0 g (benzene) = 33.1 g
Now we can calculate the percent by mass of the solute:
(4.10 g / 33.1 g) x 100% = 12.4%
Therefore, the percent by mass of the solute (toluene) in the solution is 12.4%.
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what is the multiplicity of the methylene hydrogens indicatedi nthe proton nmr of the following compound
Calculate the percent ionization of propionic acid (C2H5COOH) in solutions of each of the following concentrations (Ka is given in Appendix D in the textbooka) 0.250M .b 7.74×10−2M .c 2.03×10−2M .
The percent ionization for propionic acid in each of cases are given below:
Part A. 0.704%
Part B. 1.31%
Part C. 2.61 %
Percent ionization is defined as the quantity of a weak acid that ionizes in a solution expressed as a percentage.
Percent ionization can be calculated using the following expression.
α% = √(Ka/Ca) × 100%
where,
α% is the percent ionization.
Ka is the acid dissociation constant (1.34 × 10⁻⁵ for propionic acid).
Ca is the concentration of the acid.
For Part A. 0.250 M
α% = √(1.34 × 10⁻⁵/0.250) × 100% = 0.704%
Part B. 7.84 × 10⁻² M
α% = √(1.34 × 10⁻⁵/7.74 × 10⁻²) × 100% = 1.31 %
Part C. 1.97 × 10⁻² M
α% = √(1.34 × 10⁻⁵/2.03 × 10⁻²) × 100% = 2.61 %
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Select factors that will change when additional A is added...Select the factors that will change when additional A is added to a system at equilibrium. Select the factors that will change when additional A(g) is added to the following system at equilibrium. Overall Reaction: A(g) + B(g) 2C(g)
When additional A(g) is added to the following system at equilibrium, the actors that will change are pressure, temperature, reaction rate and concentration.
Concentrations of A, B, and C: The concentration of A will increase, while the concentrations of B and C will decrease. The extent of the changes will depend on the stoichiometry of the reaction and the equilibrium constant.
Pressure: The addition of A(g) will increase the pressure of the system, assuming the volume is constant. This may cause a shift in the equilibrium position to favor the side with fewer moles of gas, which in this case is the reactant side.
Temperature: The addition of A(g) may cause a temperature change in the system. If the reaction is exothermic, the addition of A(g) will increase the temperature of the system and may cause a shift in the equilibrium position to favor the reactants. If the reaction is endothermic, the addition of A(g) will decrease the temperature of the system and may cause a shift in the equilibrium position to favor the products.
Reaction rate: The addition of A(g) may temporarily increase the rate of the forward reaction, but the system will eventually reach a new equilibrium position with the same equilibrium constant.
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A 400 mL sample of a 0.100 M formate buffer, pH 3.75, is treated with 6 mL of 1.00 M KOH. What is the pH following this addition? (pKa for formic acid is 3.75)
Express your answer to two decimal places.
The pH of A 400 mL sample of a 0.100 M formate buffer, pH 3.75, is treated with 6 mL of 1.00 M KOH is 4.88
pH buffer = 3.75
pKa for formic acid is 3.75
Using Henderson-Hasselbalch equation for formate buffer:
pH = pKa + log [ HCOO⁻]
[HCOOH]
Input values in above equation
3.75 = 3.75 + log [ HCOO⁻]
[HCOOH]
log [ HCOO⁻] = 0
[HCOOH]
[ HCOO⁻] = 1
[HCOOH]
[ HCOO⁻] = [HCOOH]
Concentration of formate buffer = 0.100 M
[ HCOO⁻] - [HCOOH] = 0.100 M
[ HCOO⁻] = [HCOOH] = 0.05 M
As a result, the buffer's volume is the same. As a result, the concentration is calculated as the number of moles of both formate ions and formic acid.
Then we should calculate the number of moles for given molarity
Molarity of solution = moles of solute x 1000
volume of solution in mL
1M KOH = moles of KOH x 1000 = 0.006 moles
6 mL
The chemical reaction for formic acid and KOH follows the equation:
HCOOH +KOH ⇒ HCOO⁻ +H₂O
initial 0.05 0.006 0.05
final 0.041 - 0.056
Volume of solution = 400 + 6 = 406 mL = 0.406 L
We use the Henderson Hasselbalch equation to determine an acidic buffer's pH:
pH = pKa + log [ HCOO⁻]
[HCOOH]
[ HCOO⁻] = 0.056 =
0.406
[ HCOOH] = 0.041
0.406
pH = 3.75 + log [ HCOO⁻]
[HCOOH]
pH = 3.75+ log [0.056/ 0.406]
[ 0.041/ 0.406]
pH = 4.88
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a solution is prepared by mixing 10.5 g of nacl (molar mass 58.44 g/mol) with 147 g of h2o (molar mass 18.02 g/mol). the final volume of the solution is 150 ml. which of the following options are the correct values for molarity (m) and molality (m) of the solution? select all that apply.
m = 0.180 mol/0.147 kg = 1.22 m m 0.180 mol/ 0.150 L = 1.20 m
m = 0.180 mol/ 0.158 kg = 1.14 m
moles NaCl = 0.180 mol
The appropriate values for the solution's molality and molarity are:
M is 1.20 M, while m is 1.22 M.
We must first determine how many moles of NaCl are present in the solution:
Moles of NaCl are equal to the mass of NaCl divided by its molar mass, which is 10.5 g/58.44 g/mol, or 0.180 mol.
We must divide the number of moles of NaCl by the litres of the solution's volume to determine its molarity:
Molarity (M) is equal to moles of NaCl per litre of solution.
1.20 M = 0.180 mol/0.150 L molarity (M)
We must divide the number of moles of NaCl by the kilogramme mass of the solvent (water) in order to determine the molality of the solution:
moles of NaCl/mass of solvent in kg molality (m) = 0.180 mol/0.147 kg 1.22 m mass of H2O = 147 g = 0.147 kg
Hence, the appropriate values for the solution's molality and molarity are:
M is 1.20 M, while m is 1.22 M.
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Give, and identify, the 1,2 and 1,4 products of the following reactions. for each circle the thermodynamic product.(3pts) O H-BrO CI2_CH2CI2O CH2 H-Br
Kinetic Versus Thermodynamic Control Furthermore of HBr to Dienes: 1,2-and 1,4-Addition
In the present post we'll talk about 1,2-and 1,4-Addition to dienes - specifically, the expansion of solid corrosive like HBr.
When a diene goes through response with a solid corrosive like HBr, protonation brings about a reverberation settled carbocation
The reverberation settled carbocation can go through assault at two potential positions.
At the point when the response is led at low temperatures, the response is irreversible and the significant item will be the one with the least energy change state, which is the carbon best ready to balance out certain charge.
This is alluded to as running the response under kinetic control.
At the point when the response is directed at higher temperatures, the response is reversible and the significant item will be the one which is generally thermodynamically steady, which is by and large the most-subbed alkene.
This is alluded to as running the response under thermodynamic control.
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Which part of the economy is represented by box C on the circular flow model?
Box C in the circular flow model represents households, or consumers.
What does the circular flow model depict?In the circular flow model, households are shown as the source of spending and demand for goods and services in the economy.
The model depicts a continuous flow of money from households to firms, in exchange for goods and services, and then from firms back to households as wages and profits. Box C is typically depicted as one of two boxes on either side of the model, representing either households or firms. The other box, Box F, typically represents firms, or producers.
Therefore, the correct answer is as given above. It could then be concluded that the correct answer is that Box C in the circular flow model represents households, or consumers.
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A 2.540 g sample of an oxide of tin was heated in the air until the mass of the sample no longer
changed, and 2.842 g of tin (IV) oxide (SnO₂) was obtained as a result of the heating.
Work through the following questions. You only will be asked to submit your answers to some of
them, but you may need to calculate all of the answers a) - f) to determine the final answer g).
a) What is the mass percent of tin in SnO₂?
b) What is the mass of tin in the final sample?
c) What was the mass of tin in the original sample?
d) What was the mass of oxygen in the original sample?
e) What was the number of moles of tin in the original sample?
f) What was the number of moles of oxygen in the original sample?
g) What is the formula (SnxOy) of the original oxide of tin?
Answer:
A) The molar mass of SnO₂ is 150.71 g/mol (118.71 g/mol for Sn and 32 g/mol for O). The mass percent of tin in SnO₂ is (118.71 g/mol / 150.71 g/mol) × 100% = 78.76%.
B) The mass of tin in the final sample is 2.842 g.
C) Let x be the mass of tin in the original sample. The mass of oxygen in the original sample is (2.540 g - x). Since tin is oxidized to SnO₂, we can write the equation: Sn + O₂ → SnO₂. The molar ratio of Sn to SnO₂ is 1:1, so the number of moles of Sn in the original sample is the same as the number of moles of SnO₂ in the final sample. Using this, we can set up the following equation:
x / 118.71 g/mol = 2.842 g / 150.71 g/mol
Solving for x, we get x = 1.727 g.
Therefore, the mass of tin in the original sample is 1.727 g, and the mass of oxygen in the original sample is (2.540 g - 1.727 g) = 0.813 g.
D) The mass of oxygen in the original sample is 0.813 g.
E) The number of moles of tin in the original sample is 1.727 g / 118.71 g/mol = 0.0146 mol.
F) The number of moles of oxygen in the original sample is 0.813 g / 32 g/mol = 0.0254 mol.
G) The ratio of tin to oxygen in the original sample can be calculated by dividing the number of moles of tin and oxygen by the smallest of the two:
tin: 0.0146 mol / 0.0146 mol = 1
oxygen: 0.0254 mol / 0.0146 mol ≈ 1.74
We can round this to the nearest whole number, giving a ratio of 1:2. Therefore, the empirical formula of the original oxide of tin is SnO₂.
on a t-v diagram, the region under the dome area between the saturated liquid and saturated vapor lines is known as the ____ region.
saturated liquid vapor aka liquid-vapor mixture. A mixture of saturated vapor and liquid is present in this condition. The dryness fraction, a parameter that describes the characteristics of water in this phase, must be calculated is combined with the saturation characteristics.
What is vapor pressure?Vapor pressure is the pressure exerted by a vapor when it is in equilibrium with its liquid or solid phase at a given temperature. It is a measure of the tendency of a substance to evaporate and is a function of the temperature and the strength of the intermolecular forces between the molecules of the substance. At any given temperature, a substance will have a specific vapor pressure. When the vapor pressure of the substance is equal to the external pressure, the substance will begin to boil or evaporate. The vapor pressure of a substance increases with increasing temperature, as the average kinetic energy of the molecules increases and more molecules can escape from the liquid or solid phase and enter the gas phase.
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importance of PH in Pharmactical Practices
pH affects the solubility of the molecule, which determines the stability of pharmaceuticals, the biological tolerability of the formulation, and the activity of the molecule, pH is a crucial element for all drugs manufactured in aqueous liquid forms.
Why pH is important ?A solution's pH is a significant indicator of its chemical composition. The pH may impact how readily available nutrients are, how biological processes work, how bacteria behave, and how chemicals behave.
The negative base-10 log of the hydronium ion concentration in a solution is the usual definition of pH value.
In the pharmaceutical sector, we're accustomed to concentrations of little more than 1M under typical circumstances. That being stated, the pH value in that situation may be between two extremes.
Thus, pH is important in Pharmaceutical Practices.
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The mass of Cu (63.55 g/mol) used to create Cu2S was 36.25 grams. what theoretical mass of Cu2S (159.16 g/mol) can be produced? Report your answer with three significant figures.
On a T-v diagram, the saturated liquid states can be connected by a line called the _________ liquid line, and the saturated vapor states can be connected by the _________ vapor line.
A line known as the Saturated Liquid Line can be used to connect the saturated liquid states on a T-V diagram, while the Saturated Vapor Line can be used to connect the saturated vapor states.
What is Saturated Vapor Line?In the T-s diagram, the curve separating the two-phase state from the superheated vapor state is known as the saturation vapor curve. The T-s diagram's saturated liquid curve is the line dividing the subcooled liquid state from the two-phase state. The term "saturated liquid line" refers to a line that connects all saturated liquid states. The saturated vapor line connects all of the saturated vapor states. Both the saturated liquid state and the saturated vapor state combine into a single point on the T-v diagram when pressure reaches Pcr (critical pressure).The saturation line is the area beyond which a substance or component in a system either changes from liquid to vapor or vapor to liquid according to the Temperature Pressure Equilibrium Diagram.To learn more about Saturated Vapor Line, refer to:
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which of the following macromolecules are characteristically water-insoluble?group of answer choicesproteinslipidscarbohydrates
The macromolecules that are characteristically water insoluble is the correct option is lipids.
The macromolecule are the molecule that are extraordinarily large. They may be organic materials such as the sugars and the natural fibers or the synthetic materials such as the plastics, the synthetic fibers, Lipids, the proteins, the nucleic, and carbohydrates . The lipids are water hating. They are water insoluble.
The lipids are the non polar compound and the water is the polar compound. The polar will dissolve the polar compounds and the non polar will dissolves the non polar compound. Therefore the lipids are insoluble in the water.
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FILL IN THE BLANK. A stove that circulates heated air to uniformly cook food is an example of ________ heat transfer.
Answer: A stove that circulates heated air to uniformly cook food is an example of convection heat transfer.
FILL IN THE BLANK. The cations found in seawater originally came from ____, whereas the anions originated from ____.
The ions such as the cations found in seawater originally came from Earth's crust whereas the anions originated from Earth's mantle.
What are ions?An ion is defined as an atom or a molecule which has a net electrical charge. There are 2 types of ions :1) cation 2) anion . The cation is the positively charged ion and anion is the negatively charged ion . As they are oppositely charged they attract each resulting in the formation of ionic bond.
Ions consisting of single atom are mono-atomic ions while which consists of two or more ions are called as poly-atomic ions . They are created by chemical interactions .
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How many grams of HCI are needed to prepare .40 L of 1.5 M solution?
Answer: 21.90 grams HCl ; 22 g HCl if need correct sig figs
Explanation:
moles = M X L = 1.5 x .40 =0.60 moles HCl
convert to grams
0.60 X 36.5 = 21.90
HELP ASAP PLEASE ANSWER BOTH OF THESE QUESTIONS! I WILL GIVE YOU BRAINELIST IF YOU ANSWER IT!
Answer:
because it absorbs all colours expect for red,
Explanation: making the red light bounce into your eyes, therefore seeing the colour red
Question 2: The wave transfers its energy to the mineral, I think, thats my best guess
If a compound is being consumed in a reaction, the rate constant for that compound is _______.
The rate of a reaction depends upon the concentration of the reactants. If a compound is being consumed in a reaction, the rate constant for that compound decreases.
What is rate constant?The rate constant or specific reaction rate of the reaction at a given temperature is defined as the rate of the reaction when the molar concentration of each of the reactants is unity.
The reaction rate is directly related to rate constant. The rate of a reaction decreases as the concentration of the reactants decreases with time. Here since the reactants are consumed, then the rate constant decreases.
Thus If a compound is being consumed, rate constant decreases.
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