Answers
Answer:
1332 i think is how it will be writen
Step-by-step explanation:
Answer:
121,212
Step-by-step explanation:
im not 100% sure
Related Questions
Brenya Estate produces a high quality tea branded Super by blending three types of tea coded A, B and C in the ration 1: 5:1. Originally Type A tea costs GHS 1,600 type B costs GHS 800 and type C costs GHS 1,700 per kg to produce. Brenya Tea Estate packs Super tea in packets of 825g each. Blending and packing costs are 40 per kg. Determine the production cost for a packet of Super tea,
Answers
Solution :
Cost of 1 kg super tea mixture
[tex]$=\frac{1(1600)+5(800)+1(1700)}{1+5+1}$[/tex]
[tex]$=\frac{1600+4000+1700}{7}$[/tex]
[tex]$=\frac{7300}{7}$[/tex]
= 1042.8
≈ 1043
Include of cost blending and packaging.
So, cost of 1 kg is 1043 + 40 = 1083
Cost of packaging of 825 gram super tea = [tex]$\frac{825}{1000} \times 1083$[/tex]
= 893.47
In triangle ABC, if ∠A = 120°, a = 8, and b = 3, then ∠B =
Answers
Answer:
Step-by-step explanation:
Use the Law of Sines here:
[tex]\frac{sin120}{8} =\frac{sinB}{3}[/tex] and cross multiply to get
8sinB = 3sin120 and solve for B:
[tex]sinB=\frac{3sin120}{8}[/tex] and
sinB = .3247595264
Now hit the 2nd button and then sin to get
[tex]sin^{-1}([/tex]
on your display. After that open parenthesis, enter that decimal and hit enter to get that angle B = 18.95 which you can round to howeve many places you need.
Given the figure below as marked, which term best describes EF?
A. angle bisector
B. median
C. perpendicular bisector
D. altitude
Answers
Answer:
B
median
hope its help you
Answer: B. Median
Step-by-step explanation:
its the middle line.
Matthew grows wheat on his farm. One of his fields produced 66.8 bushels of wheat this year. If wheat is currently selling for $5.40 per bushel, how much will Matthew earn from this field?
Answers
Answer:
Mathew will earn $360.72 from his food
Step-by-step explanation:
We know that:
1 bushel of wheat = $5.40
And Matthew produced 66.8 bushels of heat this year
To find how much Matthew will earn from his field, multiply:
5.40 x 66.8 = 360.72
Therefore he will earn $360.72 from his field.
Hope thjs helps!
a little bit of help here??
Answers
Answer:
balanced
Step-by-step explanation:
The upward force is 75+ 160 =235
The downward force is 235
The force is balanced since the upward force equals the downward force
Help please !!!!!!!!!!!!
Answers
=============================================================
Explanation:
Ignore the rows that are labeled "stock ABC" and "stock MNO".
We only focus on the top row (gains and losses) and the "stock JKL" row.
Multiply each gain or loss with its corresponding probability in decimal form. Use negative values to represent a loss
-25*0.15 = -3.755*0.65 = 3.2545*0.20 = 9Add up those results to get the final answer: -3.75+3.25+9 = 8.50
-----------------------
Here's another way to get the answer.
Let's say you had a 10 by 10 grid of graph paper.
Shade exactly 15 tiny squares in red to represent a loss of $25 (note that 15/100 = 15%)Shade exactly 65 squares in blue to represent a gain of $5 (65/100 = 65%)Shade the remaining 20 squares in green to represent a gain of $45This can be thought of as like a dart board. Imagine throwing 1000 darts at this grid (maybe do so blindfolded to give each square an equal chance; if you land outside the grid then re-throw the dart). Theoretically, the probability of landing in the red area is 15/100 = 0.15, so we expect about 1000*0.15 = 150 darts will land there out of the 1000 thrown total. Each of those 150 darts in the red area represents a loss of $25. So we have a loss of 150*25 = 3750 dollars. We'll write this as -3750.
We also expect 0.65*1000 = 650 darts to have a gain of $5. That means 650*5 = 3250 is earned here. Furthermore, 0.20*1000 = 200 darts land in the green squares to get us $45 per attempt. So that's another 45*200 = 9000 dollars.
Overall, we would get -3750+3250+9000 = 8500 in profit.
Divide this over the 1000 dart throws and we end up with an expected value of 8500/1000 = 8.50
Keep in mind that this dart game or thought experiment is depending on theoretical probabilities. If you actually do this game, then your empirical probabilities will likely differ slightly from the theoretical values. However, the more trials you conduct, the closer your empirical probabilities should get to the theoretical ones.
To find the quotient of multiply 3 by
Answers
Answer:
the other number to get the quotient
what is the place value of the 3 in the numeral : 247.3
Answers
the place value of 3 in the following is (0.3)
Find the measure of "theta". Round all answers to the nearest tenth.
Answers
Answer:
58.6 degrees
Step-by-step explanation:
This is the last for tonight
Answers
Answer:
m ∠ ZLK = 75°
Step-by-step explanation:
Evaluate expressions- if A=4 and B=9 what is the value of the following expression
20/a+7•b
A.28
B.33
C.68
D.108
Answers
Answer:
68
Step-by-step explanation:
just put the value of a and b in the expression and you will get the answer
20/a+7.b is
20/4+7×9
5+63
68
Answer:
C. 68
Step-by-step explanation:
Fill in your values.
20/ 4 + 7 x 9
Solve using PEMDAS.
5 + 7 x 9
5 + 63
68
35/48*100 fraction into percentage.
Answers
Answer:
729167
Step-by-step explanation:
Now we can see that our fraction is 72.916666666667/100, which means that 35/48 as a percentage is 72.9167%.
Calculus 2. Please help
Answers
Answer:
[tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}}} \, dx = \infty[/tex]
General Formulas and Concepts:
Algebra I
Exponential Rule [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Calculus
Limits
Right-Side Limit: [tex]\displaystyle \lim_{x \to c^+} f(x)[/tex]Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
Derivatives
Derivative Notation
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Integrals
Definite IntegralsIntegration Constant C
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
U-Substitution
U-Solve
Improper Integrals
Exponential Integral Function: [tex]\displaystyle \int {\frac{e^x}{x}} \, dx = Ei(x) + C[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx[/tex]
Step 2: Integrate Pt. 1
[Integral] Rewrite [Exponential Rule - Rewrite]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \int\limits^1_0 {\frac{e^{-x^2}}{x} \, dx[/tex][Integral] Rewrite [Improper Integral]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \int\limits^1_a {\frac{e^{-x^2}}{x} \, dx[/tex]Step 3: Integrate Pt. 2
Identify variables for u-substitution.
Set: [tex]\displaystyle u = -x^2[/tex]Differentiate [Basic Power Rule]: [tex]\displaystyle \frac{du}{dx} = -2x[/tex][Derivative] Rewrite: [tex]\displaystyle du = -2x \ dx[/tex]Rewrite u-substitution to format u-solve.
Rewrite du: [tex]\displaystyle dx = \frac{-1}{2x} \ dx[/tex]Step 4: Integrate Pt. 3
[Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {-\frac{e^{-x^2}}{x} \, dx[/tex][Integral] Substitute in variables: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {\frac{e^{u}}{-2u} \, du[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}\int\limits^1_a {\frac{e^{u}}{u} \, du[/tex][Integral] Substitute [Exponential Integral Function]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(u)] \bigg| \limits^1_a[/tex]Back-Substitute: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-x^2)] \bigg| \limits^1_a[/tex]Evaluate [Integration Rule - FTC 1]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-1) - Ei(a)][/tex]Simplify: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{Ei(-1) - Ei(a)}{2}[/tex]Evaluate limit [Limit Rule - Variable Direct Substitution]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \infty[/tex]∴ [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx[/tex] diverges.
Topic: Multivariable Calculus
7x+2y=39 in slope intercept form
Answers
Y=-7/2x+39/2
Which ratio is equivalent to 30%?
A. 6:20
B. 3:9
C. 2:6
D. 5:18
Answers
Answer:
2+2= -5
Step-by-step explanation:
i dont come up with the rules i just state the facts.
Simplify exponents. A, B, or C and explain.
Answers
Answer:
[tex]8^{-3}[/tex]
Step-by-step explanation:
[tex]\frac{8^3}{8^6}[/tex]
in division f the base are same u can subtract their exponents
8^3-6
8^-3
x3+y3+z3=k, with k being all the numbers from one to 100
Answers
✦ ✦ ✦ Beep Boop - Blu Bot! At Your Service! Scanning Question . . .
Code: Green! Letters, Numbers, and Variables Received! ✦ ✦ ✦
--------------------------------------------------------------------------------------------------------------Question: x3+y3+z3=k, with k being all the numbers from one to 100
--------------------------------------------------------------------------------------------------------------Answer: X = -80538738812075974, Y = 80435758145817515, and Z = 12602123297335631.
-------------------------------------------------------------------------------------------------------------
X = -80538738812075974, Y = 80435758145817515, and Z = 12602123297335631.
PLEASE HELP
what is the amount of an investment $10,000 compounded quarterly for 3 years at a rate of 4 percent?
Answers
Answer:
10000 times 3 times 0.04 = 1200
Answer:
11268.25
Step-by-step explanation:
[tex]P(1+\frac{i}{n})^{n*t}=10000(1+\frac{.04}{4})^{4*3}=11268.2503[/tex]
The angle of elevation to a nearby tree from a point on the ground is measured to be 61 ∘ ∘ . How tall is the tree if the point on the ground is 59 feet from the tree? Round your answer to the nearest hundredth of a foot if necessary.
Answers
Answer:
106.44 ft
Step-by-step explanation:
tan = opp/adj
tan61 = opp/59
59*tan61 = opp
opp = 106.438817561014012
Rounded
106.44 ft
I NEED HELP ASAP PLESSEEE
What is the relation between the variables in the equation
Y/x^2= 10?
a. x varies directly with the square of y
b. y squared varies inversely with x
C. y varies directly with x squared
y varies inversely with x squared
d.
Answers
Answer:
I think C is the relation between the variables.
x ÷ 8.2 = 10. What is the value of x?
Answers
Answer:
82
Step-by-step explanation:
Answer:
82
Step-by-step explanation:
10 times 8.2 would be 82 so you just divide 82 by 10
Is this question biased or unbiased?
"Why is drinking fruit juice good for you?"
Answers
Your not showing your against it or anything. Just a general factual question.
how can I solve this question ?
wick method should I use ?
Answers
15/3=5
The 3rd fraction is 2/5.
You use a similar method for the 4th fraction, b/120.
Now, we find out what was done to 15 (the denominator) to make it a 120.
The 15 was multiplied by 8. So we do the same for 6.
6*8=48
The 4th fraction is 48/120.
For the last fraction 16/c, we use 2/5 as one numerator (16) is a multiple of the other (2).
2 was multiplied by 8 to get to 16, so we do the same for 5.
5*8=40
The last fraction is 16/40.
Answer:
24/60=6/15=2/5=48/120=16/40
Step-by-step explanation:
Now we see that,
6/15=2/__
Let us say '__' in 2/__ is 'x'
6/15=2/x
6x=15x2
6x=30
x=5
=>2/5
Similarly,
2/5=x/120
2x120=5x
240=5x
5x=240
x=240/5
x=48
=>48/120
48/120=16/x
48/16=120/x
3=120/x
x=120/3
x=40
=>16/40
If David walks 1/2 mile in 1/4 hour, then how fast does David walk in one hour? (In other words, what is David's "unit rate"?)
Answers
El volumen de un prisma de base rectangular es 24 m3. Si el largo de la base es 2,5 m y su ancho es 4 m, ¿cuál es la altura del prisma?
Answers
Answer:
La altura del prisma es 2,4 m.
Step-by-step explanation:
Para calcular el volumen de un prisma rectangular, es necesario multiplicar sus tres dimensiones, esto es, longitud*ancho*altura. El volumen se expresa en unidades cúbicas.
Entonces:
volumen= longitud*ancho*altura
En este caso, los datos conocidos son:
volumen= 24 m³longitud= largo de la base= 2,5 mancho= 4 maltura= ?Reemplazando:
24 m³= 2,5 m* 4 m* altura
Resolviendo:
[tex]altura=\frac{24 m^{3} }{2,5 m*4m}[/tex]
[tex]altura=\frac{24 m^{3} }{10 m^{2} }[/tex]
altura= 2,4 m
La altura del prisma es 2,4 m.
Which point is located at -8.95?
Answers
Answer:
pt A
Step-by-step explanation:
Answer:
Point A
Step-by-step explanation:
Hope this helps
Last week, a family ordered dinner through a local food delivery service. The food was $45. They had a coupon for 15% off the total bill.
The bill was $
when the coupon was applied.
Answers
Louise begins factoring the polynomial, which has four terms. 8x3+24x2+10x+30 2(4x3+12x2+5x+15) 2[4x2(x+3)+5(x+3)] Which is the completely factored form of her polynomial? 8x2(x + 3)2 2x(4x2 + 5) 2(4x2 + 5) (x + 3) 2(4x2 + 5) (x + 3)2
Answers
Answer:
[tex]8x3+24x2+10x+30= 2[(4x^2+5)(x+3)][/tex]
Step-by-step explanation:
Given
[tex]8x3+24x2+10x+30= 2(4x^3+12x^2+5x+15)[/tex]
[tex]8x3+24x2+10x+30= 2[4x^2(x+3)+5(x+3)][/tex]
Required
The complete factored form
We have:
[tex]8x3+24x2+10x+30= 2[4x^2(x+3)+5(x+3)][/tex]
Factor out x + 3
[tex]8x3+24x2+10x+30= 2[(4x^2+5)(x+3)][/tex]
The above represents the completely factored form
Answer:
C on edge
Step-by-step explanation:
I took the test
PLS I beg someone to finish ALL of this :(. I’ve stayed up all night to do this but I couldn’t figure all of them out. Pls pls pls!!! ill mark you brainliest n I can give you a thank you such as 5 Stars in return. Please take your time and I hope you all have a amazing day!
Answers
Answer:
5. 2 hours 45 minutes 6. 7:23 7. 10:05 8. 1 hour 34 minutes
Step-by-step explanation:
I mean u gotta be lying about staying up all night to do these 4 problems but heres the answers
Answer:
5. 2 hours 45 mins
6. 7:23 start
7. 10:05
8. 1 hour 34 mins
log2 1 is defined
True
False
Answers
Answer: True
Through the change of base formula, we can say,
[tex]\log_{2}(1) = \frac{\log(1)}{\log(2)} = \frac{0}{\log(2)} = 0[/tex]
So in short,
[tex]\log_{2}(1)=0[/tex]
It turns out that
[tex]\log_{b}(1) = 0[/tex]
for real numbers b such that b > 0 and [tex]b \ne 1[/tex]