the answer is d. y=30x+15
Complete this activity.
If the first element of the following pairs of numbers is a measure of hours and the second element is a measure of distance in miles, write an equation for D.
B = {(t, D ): (1, 50), (2, 100), (3, 150), . . .}
D =
t /2
50 t
50/ t
Answer:
D = 50t
Step-by-step explanation:
we see, with every additional hour the distance increases by 50.
that means in general that the number of hours are multiplied by 50 to get the distance.
in other words, this just calculates for a vehicle going constantly 50 miles per hour the distance it is traveling.
Identify the correct trigonometry formula to solve for x
The correct trigonometry formula to solve for x in the right angled triangle is sin(62°) = 18 / x
What is an equation?An equation is an expression that shows the relationship between two or more variables and numbers.
Trigonometric ratio is used to show the relationship between the sides and angles of a right angled triangle.
Hence:
sin(62°) = 18 / x
The correct trigonometry formula to solve for x in the right angled triangle is sin(62°) = 18 / x
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Find the value of x. (5x-40) (5x)
the first equation is inside the triangle at the bottom left but "5x" is at the bottom right on the outside of the triangle.
The value of x is 22
How to solve for x?Based on the description in the question,
The angles 5x -40 and 5x are angles on a straight line
So, we have:
5x - 40 + 5x = 180
Evaluate the like terms
10x = 220
Divide by 10
x = 22
Hence, the value of x is 22
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if x was 4, what is the value of 4x + 3
Answer:
19
Step-by-step explanation:
4(4)+3
16+3=19
Answer:
19
Step-by-step explanation:
4x+3
4(4)+3
16+3
19
hope it helps
If 2y=x³ + 2x², find dy/dx when x=2.
Answer:
10
Step-by-step explanation:
[tex]\boxed{\textsf{If }y=x^n,\: \textsf{then }\dfrac{\text{d}y}{\text{d}x}=nx^{n-1}}[/tex]
Given equation:
[tex]2y=x^3+2x^2[/tex]
Isolate y by dividing both sides by 2:
[tex]\implies y=\dfrac{1}{2}x^3+x^2[/tex]
Differentiate with respect to x:
[tex]\implies \dfrac{\text{d}y}{\text{d}x}=3 \cdot \dfrac{1}{2}x^{3-1}+2 \cdot x^{2-1}[/tex]
[tex]\implies \dfrac{\text{d}y}{\text{d}x}=\dfrac{3}{2}x^2+2x[/tex]
Finally, substitute x = 2 into the differentiated equation:
[tex]\begin{aligned} \implies \dfrac{\text{d}y}{\text{d}x} & =\dfrac{3}{2}(2)^2+2(2)\\\\ & = \dfrac{3}{2}(4)+4\\\\ & = \dfrac{12}{2}+4\\\\ & = 6+4\\\\ & = 10\end{aligned}[/tex]
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The stemplot below represents the number of bite-size snacks grabbed by 10 students in an activity for a statistics class. A stemplot titled number of snacks. The stems are 1, 2, 3, 4. The first column of leaves is 5, 0, 2, 2. Column 2 is 6, 1, blank, blank, Column 3 is 6, 3, blank, blank. Column 4 is 7, blank, blank, blank, Column 5 is 9, blank, blank, blank. Key 2 slash 4 is a student who grabbed 24 snacks. What is the correct set of data for the stemplot? 15, 16, 17, 19, 20, 21, 23, 32, 42 15, 16, 16, 17, 19, 21, 23, 32, 42 15, 16, 16, 17, 19, 20, 21, 23, 32, 42 15, 15, 16, 17, 19, 20, 21, 23, 32, 42
The correct set of data are 15, 16, 16, 17, 19, 20, 21, 23, 32, 42.
According to the question
Using the key: 2|4 = 24, the following are the set of data represented by the stem-and-leaf plot showing:
Row one, 1| 5 6 6 7 9 :
This means there are 5 data set for the first row which are:
15, 16, 16, 17, 19
Row two, 2|0 1 3 :
There are 3 data here, which are:
20, 21, 23
Row 3, 3|2: = 32
Row 4, 4|2: = 42
So, The correct set of data are 15, 16, 16, 17, 19, 20, 21, 23, 32, 42.
Correct option is C.
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what’s the equation of this line?
Answer:
Step-by-step explanation:
Hello : let A(0,-6) B(8,-8)
the slope is : (YB - YA)/(XB -XA)
(-8+6)/(8-0) = -2/8=-1/4
an equation is : y=ax+b a is a slope
y = (-1/4)x +b
the line through point A (0;-6) : -6 = (-1/4)(0)+b
b = -6 the equation is : y =(-1/)4x-6
Which of the following is the most accurate statement about Spatial Relations?
A- Children understand the spatial world watching movies about animals all over the world.
B- Children Need to know, use and be able to read spatial terms before they can demonstrate spatial awareness.
C-Spatial terms such as above, below, behind, and under are used to describe objects in space from different perspectives and are important for children to understand and express as they understand spatial relations.
Option C. The correct statement about spatial relationshipo is that Spatial terms such as above, below, behind, and under are used to describe objects in space.
What are spatial relationship?These are the types of relationships that are used to relate objects to the location of somethings else. It makes use of words like under, above etc.
It is one of the knowledge that children need in the preoperational stage to learn how to use logical operations.
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I don’t know the answer for question number 1
The area of QOR from the given diagram is 2π square centimeters
How to calculate the area of a sectorA sector is said to be a part of a circle made of the arc of the circle along with its two radii.
The formula for calculating the area of a sector is expressed as;
A = r²β/2
where
r is the radius of the circle
β is the angle subtended
Given the following parameters
<QOR = 180 - <POQ
<QOR = 180 - 135
<QOR = 45 degrees
Determine the radius
L = rβ
π = r(π/4)
1 = r/4
r = 4
Determine the area of QOR
Area = 4²(π)/8
Area = 2π
Hence the area of QOR from the given diagram is 2π square centimeters
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Why is it important for the world to have an order of operations
Answer:
Well a sovial reason is that no one would no what order yo do it in, which would cause arguments
Answer:
without the order of operations, maths literally doesn't work.
Step-by-step explanation:
like whilst some equations don't rely on a particular order for solving, if you for example, don't solve brackets first, then try to multiply them by something else basically the equation breaks and you get the wrong answer. So... kids remember your BODMAS :)
Help would really be needed asap!
Answer:
C
Step-by-step explanation:
For lines AC and EF, line FC is a transversal.
Angles ACF and EFC are same side interior angles.
Since their measures add to 180°, then the lines are parallel.
Answer: Choice C
A polynomial function g(x) has a positive leading coefficient. Certain values of g(x) are given in the following table. x –4 –1 0 1 5 8 12 g(x) 0 3 1 2 0 –3 0 If every x-intercept of g(x) is shown in the table and each has a multiplicity of one, what is the end behavior of g(x)?
Using the Factor Theorem and limits, the end behavior of g(x) is that the function decreases to the left and increases to the right.
What is the Factor Theorem?The Factor Theorem states that a polynomial function with roots [tex]x_1, x_2, \codts, x_n[/tex] is given by:
[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]
In which a is the leading coefficient.
Considering the table, the roots are given as follows:
[tex]x_1 = -4, x_2 = 5, x_3 = 12[/tex]
Hence the function is:
f(x) = a(x + 4)(x - 5)(x - 12).
f(x) = a(x² - x - 20)(x - 12)
f(x) = a(x³ - 13x² - 32x + 240).
When x = 0, y = 1, hence the leading coefficient is found as follows:
240a = 1
a = 0.004167
Then:
f(x) = 0.004167(x³ - 13x² - 32x + 240).
The end behavior is given by the limits of f(x) as x goes to infinity, hence:
[tex]\lim_{x \rightarrow -\infty} f(x) = \lim_{x \rightarrow -\infty} 0.004167 x^3 = -\infty[/tex].[tex]\lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} 0.004167 x^3 = \infty[/tex].Hence the end behavior is that the function decreases to the left and increases to the right.
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A tennis ball can in the shape of a right circular cylinder holds six tennis balls snugly. If the radius of a tennis ball is 3.4 cm, what percentage of the can is not occupied by tennis balls?
The percentage of the can that is not occupied by tennis balls is 33.33%.
PercentageGiven:
Radius of cylinder=3.4cm
First step
Height of cylinder=3.4×2×6
Height of cylinder=40.8 cm
Second step
Volume of cylinder=(3.4)^2×40.8
Volume of cylinder=471.648
Volume of tennis=6×4/3×(3.4)^3
Volume of tennis=314.432
Third step
Percentage=471.648-314.432/471.648×100
Percentage=33.33%
Therefore the percentage of the can that is not occupied by tennis balls is 33.33%.
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Find u. v.
U V=
(8, 2)
= (-6, 3)
U =
V =
Answer:
-42
Step-by-step explanation:
Assuming you want the dot product,
(8)(-6)+(2)(3)= -42
A retailer buys a table costing £95 and sells it for £114 what is the name percentage change
Answer:
20% increase
Step-by-step explanation:
To find the percent increase, use this formula
New value - original value
----------------------------------------
original value
114-95
-----------
95
19
---- = .2
95
.2 is 20%, so it is a20% increase
the ammount of time between interest payments is know as
The amount of time between interest payments is know as period.
What is period?Period is the time between when interests are paid. Period can vary depending on the terms of the investment. Periods can be yearly, quarterly, semi-annually, biweekly or weekly.
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y varies indirectly as the square of x. if y=8 when x=4, find y when x=8
Given that, y varies indirectly as the square of x, the value of y when x equal 8 is 2.
What is the value of y when x equal 8?
Indirect variation is expressed as;
y ∝ 1/x
Given that;
y ∝ 1/x²
y = k/x²
Where k is the proportionality constant.
Given that;
y₁ = 8x₁ = 4x₂ = 8y₂ = ?First, we determine the proportionality constant.
y = k/x²
8 = k/4²
8 = k/16
k = 128
Now, we find y when x = 8
y = k/x²
y = 128 / 8²
y = 128 / 64
y = 2
Given that, y varies indirectly as the square of x, the value of y when x equal 8 is 2.
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a mother is 25 years older than her son.
Write down the son's age and the mother's age
Answer:
mother age 37
sons age 12
help please I really need it
Given f (x) = x2 + 4x + 5, what is f of the quantity 2 plus h end quantity minus f of 2 all over h equal to?
h2 + 8h
2x + h + 4
8 + h
h + 4
By evaluating the quadratic function, we will see that the differential quotient is:
[tex]\frac{f(2 + h) - f(2)}{h} = 8 + h[/tex]
How to get (f(2 + h) - f(2))/h?Here we have the quadratic function:
[tex]f(x) = x^2 + 4x + 5[/tex]
Evaluating the quadratic equation we get:
[tex]\frac{f(2 + h) - f(2)}{h}[/tex]
So we need to replace the x-variable by "2 + h" and "2" respectively.
Replacing the function in the differential quotient:
[tex]\frac{(2 + h)^2 + 4*(2 + h) + 5 - (2)^2 - 4*2 - 5}{h} \\\\\frac{4 + 2*2h + h^2 + 8 + 4h - 4 - 8 }{h} \\\\\frac{ 2*2h + h^2 + 4h }{h} = \frac{8h + h^2}{h}[/tex]
If we simplify that last fraction, we get:
[tex]\frac{8h + h^2}{h} = 8 + h[/tex]
The third option is the correct one, the differential quotient is equal to 8 + 4.
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An employer provides two payment options for employees. Option A: Receive $200 the first week. Receive an additional $50 for each of the following weeks. Option B: Receive $200 the first week. Receive an additional 10% for each of the following weeks. (Score for Question 1: ___ of 2 points)
Based on the information, it can be inferred that payment option A means a payment of $450, while option B means a payment of $300.
How much money does each payment option receive?The payment options contemplated by the employer are distributed as follows:
Option A
First week: $200Second week: $200 + $50 = $250Third week: $250 + $50 = $300Fourth week: $300 + $50 = $350Fifth week: $350 + $50 = $400Sixth week: $400 + $50 = $450Option B
First week: $200Second week: $220Third week: $240Fourth week: $260Fifth week: $280Sixth week: $300Note: This question is incomplete because there is some information missing. Here is the missing information:
Complete the tables to show how much money would be received for both payment options, each week, for 6 weeks.
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I don’t have an answer but by any chance did you complete the assignment?
3. Consider the equation 2x² + 4y² + 8x - 16y + F = 0. Find all values of F such that the graph of the equation is a) an ellipse b) a point - ellipse
The equation 2•x² + 4•y² + 8•x - 16•y + F = 0, at a value of F is the graph of an ellipse when we have;
a. A value of F that results in the equation of an ellipse is; F = 23
b. A point on the ellipse is ((-2), 2.5)
Which method can be used to find the value of F that gives the graph of an ellipse?The equation of an ellipse can be presented as follows;
[tex] \frac{(x - h) ^{2} }{ {a}^{2} } + \frac{(y - k) ^{2} }{ {b}^{2} } = 1[/tex]
The given equation can be presented as follows;
2•x² + 4•y² + 8•x - 16•y + F = 0
Collecting like terms, gives;
2•(x² + 4•x) + 4•y² - 16•y + F = 0
Adding a constant value to both sides, we get;
2•(x² + 4•x + 4) + 4•y² - 16•y + 16 + F = 24
2•(x + 2)•(x + 2) + (2•y - 4)•(2•y - 4) + F = 24
2•(x + 2)² + 4•(y - 2)² + F = 24
2•(x + 2)² + 4•(y - 2)² + F - 23 = 24 - 23 = 1
When F = 23, we have;
2•(x + 2)² + 4•(y - 2)² + 23 - 23 = 1
2•(x + 2)² + 4•(y - 2)² = 1Which gives;
[tex] \mathbf{\frac{(x + 2) ^{2} }{ \left( {\frac{1}{ \sqrt{2} }} \right)^{2}} + \frac{(y - 2) ^{2} }{ \left( {\frac{1}{ 2} } \right)^{2}} } = 1[/tex]
Where;
a = 1/(√2)b = 1/2b) A point on the ellipse can be found as follows;
2•(x + 2)² + 4•(y - 2)² = 1When x = -2
2•((-2) + 2)² + 4•(y - 2)² = 1
0 + 4•(y - 2)² = 1
y - 2 = √(1/4) = 1/2
y = 2 + 1/2 = 2.5A point on the ellipse is therefore;
((-2) , 2.5)When y = 2
2•(x + 2)² + 4•(2 - 2)² = 1
2•(x + 2)² + 0 = 1
2•(x + 2)² = 1
(x + 2)² = 1/2
x + 2 = √(1/2)
x = √(1/2) - 2
Another point on the ellipse is therefore;
((√(1/2) - 2), 0)
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(SAT prep) Find the value of x in each case of the following exercises:
The value of x from the figure is 70°
How to determine the valueIt is important to note that alternate angles are equal and angles in a triangle sum up to 180°
We then have that,
x + 50 + 60 = 180 °
x + 110 = 180°
Make 'x' subject
x = 180 - 110
x = 70 °
Thus, the value of x from the figure is 70°
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Can someone answer this for me
The linear equation graphed is given by:
y - 5 = 3(x - 1).
What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.In point-slope form, considering a point [tex](x_0, y_0)[/tex], the equation is:
[tex]y - y_0 = m(x - x_0)[/tex]
The line goes through points (0,2) and (1,5), hence the slope is:
m = (5 - 2)/(1 - 0) = 3.
Since the line goes through point (1,5), the equation is:
y - 5 = 3(x - 1).
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The day you were born your Grandparents started to save money for your future education. They decided to deposit $3,000 at the end of each year, for eighteen years, in a savings account that pays 7.5% per year, compounded annually.
On your 19th birthday you get admission into university for a four-year degree course. You calculate that you require approximately $35,000, for your fees, books and living expenses for each year. Assuming you keep the money in the bank accruing the same interest, and withdraw $ 35,000, at the beginning of each year.
a) Calculate the total value of this investment at the end of the term?
b) Determine the total interest earned?
Will your inheritance last you for the full tenure of your four years at the university?
The total value of the investment is $107,032.16.
The total interest earned is $53,032.16
The inheritance would last the tenure of the university.
What is the total value of the investment?The formula that can be used to determine the future value of the 18-year annuity is: annuity factor x amount deposited yearly
Annuity factor = {[(1+r)^n] - 1} / r
Where:
r = interest rate n = number of years$3000 x [(1.075^18 - 1) / 0.075] = $107,032.16
Amount deposited in the course of 18 years = (3000 x 18) = 54,000
Interest earned = 107,032.16 - 54,000 = $53,032.16
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To calculate the area of this shape, you would identify the known figures and add their individual areas together.
However, the half circle is unlike the other known figures in this unknown shape in that it TAKES AWAY from the total area. How should you handle its area when
calculating the total area of the unknown figure?
When calculating the total area of this unknown figure, you should use (π - r²)/4 for the area of both the semicircle (half circle) and the larger square.
How to determine the total area?By critically observing this unknown figure, we can logically deduce that it comprises a semicircle, squares, a rectangle and a triangle. Thus, its total area should be calculated by adding the area of each of the geometric figures together.
Total area = A₁ + A₂ + A₃ + A₄
However, you should take note that the diameter of the semicircle (half circle) is equal to the side length of the larger square.
Area of a semicircle = πr²/4
Thus, the total area of both the semicircle (half circle) and the larger square is given by:
Area = πr²/4 - d²
Note: d = 2r
Area = πr²/4 - (2r)²
Area = πr²/4 - 4r²
Area = (π - r²)/4 sq. units.
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A rock is dropped from a height of 100 feet. Calculate the time between when the rock was dropped and when it landed. If we choose "down" as positive and ignore air friction, the function is h (t) = 36t2 - 64
t= 3.56 seconds
t= 1.78 seconds
t= 1.33 seconds
t= 8 seconds
The time it takes between when the rock was dropped and when it landed is 1.33 seconds.
What is the time it takes for the rock to land?The time it takes the rock to land on the ground from where it is dropped can be determined by using the function given.
The height of the function when it hits the ground will be zero, so the function can be written as:
[tex]\mathbf{h(t) =36t^2 -64}[/tex]
[tex]\mathbf{0 =36t^2 -64}[/tex]
64 = 36t²
[tex]\mathbf{t^2 = \dfrac{64}{36}}[/tex]
t² =1.778
[tex]t = \sqrt{1.778}[/tex]
t = 1.333 seconds
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Find the ratio of 700m to 2 km
Answer:
7 : 20
Step-by-step explanation:
2km = 2000m
Then the ratio of 700m to 2 km is :
700 / 2000
Then the ratio in simplest form is :
7 / 20
Write the expression in terms of sine and cosine, and then simplify so that no quotients appear in the final expression.
csc ß- sin ß
Choose the correct answer below.
OA. 1
B. cos ßcot B
OC. sin²B
OD. 1-sin² B
OE. sin² ßtan² ß
OF. cos B
...
Using trigonometric identities, the simplified expression, without quotients, is given as follows:
A. [tex]\cos{\beta}\cot{\beta}[/tex]
Which trigonometric identities are used to solve this question?The cosecant of an angle is given by one divided by the sine of the angle, hence:
[tex]\csc{\beta} = \frac{1}{\sin{\beta}}[/tex]
The sine and the cosine of an angle are related as follows:
[tex]\sin^2{\beta} + \cos^2{\beta} = 1[/tex]
[tex]\cos^2{\beta} = 1 - \sin^2{\beta}[/tex]
The cotangent of an angle is:
[tex]\cot{\theta} = \frac{\cos{\theta}}{\sin{\theta}}[/tex]
Which is the simplified expression?The expression given is:
[tex]\csc{\beta} - \sin{\beta}[/tex]
Simplifying the cosecant:
[tex]\csc{\beta} - \sin{\beta} = \frac{1}{\sin{\beta}} - \sin{\beta} = \frac{1 - \sin^{2}\beta}{\sin{beta}}[/tex]
Then, applying the last two identities in the subsection above to remove the quotient, the simplified expression will be found as follows:
[tex]\frac{1 - \sin^{2}\beta}{\sin{beta}} = \frac{\cos^2{\beta}}{\sin{\beta}} = \frac{\cos{\beta}}{\sin{\beta}} \times \cos{\beta} = \cos{\beta}\cot{\beta}[/tex]
Hence option A is correct.
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The sum of the roots of the quadratic equation x^2 + 1=0 is equal to
Answer:
x² + 1 = 0
a = 1
b = 0
c = 1
[tex]x1.2 = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} [/tex]
[tex]x1.2 = \frac{ - 0 ±\sqrt{ {0}^{2} - (4.1.1) } }{2.1} [/tex]
[tex]x1.2 = \frac{0± \sqrt{0 - 4} }{2} [/tex]
[tex]x1.2 = \frac{± \sqrt{ - 4} }{2} [/tex]
There is no real solution because the discriminant is negative
Note.
Formula diskriminan
√b² - 4ac.
if the diskrimanan is negatif, so the quadratic equatoin dont have solution