Gravity on Jupiter is 25 m/s/s, what is the weight of a 12 kg object on Jupiter?

The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

[tex]V_x = Vcos(\theta)[/tex]

Substituting the given parameters into the formula, we have;

[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]

Horizontal component, Vx = 15 m/s

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Answer:

hi there !

1 hour -------> 620 miles

3 1/2 ---------> ?

the number of miles the airplane travels in 3 1/2 hours

= 3 1/2 × 620 = "2170" miles

Answer:

Train A has a speed 20 miles per hour greater than that of train B. If train A travels 300 miles in the same times train B travels 220 miles, what are the speeds of the two trains?

2. A woman has a total of $13,000 to invest. She invests part of the money in an account that pays 11% per year and the rest in an account that pays 12% per year. If the interest earned in the first year is $1490 how much did she invest in each account?

Explanation:

Answer:

Homogenous Mixture

Explanation:

The composition in paint is uniform so every part of it looks the same throughout the paint.

The force might make the object move or bring the object to rest or change in direction of motion

The location of the point F that partitions a line segment from D to E ([tex]\overline{DE}[/tex]), that goes from negative 4 to positive 5, into a 5:6 ratio is fifteen halves (option 4).  

We need to calculate the segment of the line DE to find the location of point F.

Since point D is located at negative -4 and point E is at positive 5, we have:

[tex] \overline{DE} = E - D = 5 - (-4) = 9 [/tex]

Hence, the segment of the line DE ([tex]\overline{DE}[/tex]) is 9.

Knowing that point F partitions the line segment from D to E ([tex]\overline{DE}[/tex]) into a 5:6 ratio, its location would be:

[tex] F = \frac{5}{6}\overline{DE} = \frac{5}{6}9 = 5*\frac{3}{2} = \frac{15}{2} [/tex]  

Therefore, the location of point F is fifteen halves (option 4).

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I hope it helps you!

Answer:

The above answer is actually incorrect - the real answer is B. 1/11

Explanation:

I'm adding a ss below for proof

Hope this helped!

I'd really appreciate Brainliest :)

Thermal expansion is the tendency of matter to change its shape dimensions, density in response to a change in temperature.

  2. Gases

    3. Liquids

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Answer:

-4,200,000 J

Explanation:

[tex]\\ \sf\Rrightarrow F_{net}=F_1+F_2+F_3+F_4[/tex]

[tex]\\ \sf\Rrightarrow F_{net}=20N+20N+10N-10N[/tex]

[tex]\\ \sf\Rrightarrow F_{net}=40N[/tex]

Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

[tex] \tan(x) = \frac{opp}{adj} [/tex]

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]

[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]

Now we take the arctan or inverse tan of 1/2.

[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]

Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.

The western and southern component have a negative displacement as shown in the graph.

Let the southern component be -x

The western component is half of -x = -x/2

Since the angle is with the south, the trigonometric ratio to be used to find the angle is:

Tan θ = -×/2 /-x

Tan θ = 1/2

θ = tan^-1(0.5)

θ = 26.6°

Therefore, angle of the wind with the south is 26.57°.

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The change of velocity is from 18.5 to 46.1 m/s or 46.1 - 18.5 = 27.6 m/s. The time of change is 2.47 s. So the acceleration is 27.6 m/s / 2.47 s = 11.17 m/s^2. The distance traveled is average velocity times time of travel.

Answer:

Since there is no external force, there is no change (movement) in the center of mass. Internally, the center of mass might change position, but the external result is still zero net velocity.

The net recoil velocity must be zero.

Answer:

2000 J

Hope you could get an idea from here.

Doubt clarification - use comment section.

S O L U T I O N:

Here we've been provided with the information i.e

Ans we have given to find out what is work done (W) = ?

The standard formula to calculate work done is given by,

[tex]:\implies\sf{w = f \times s \times cos \theta}[/tex]

[tex]:\implies\sf{w = 20 \times 200 \times cos60}[/tex]

[tex]:\implies\sf{w = 20 \times 200 \times \frac{1}{2} }[/tex]

[tex]:\implies\sf{w = 20 \times 100 \times 1}[/tex]

[tex]:\implies\sf{w = 2000J}[/tex]

Answer:

1 N

Explanation:

1) You'll just have to sum the force vectors, and since they are opposite, you'll calculate the difference of their magnitudes, in absolute value.

Ftot = |F1 - F2| = 6N - 5N = 1N

2)The direction will be the same as the greater force's direction.

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]

[tex]\\ \sf\longmapsto s=55+121[/tex]

[tex]\\ \sf\longmapsto s=176m[/tex]

This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

[tex]v_2=\frac{34\ g.m/s}{6\ g}\\\\[/tex]

v₂ = 5.7 m/s

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The number of variations the dealership have is 40 cars.

Data given;

This is the total numbers of cars available in the dealer shop at the moment.

To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.

This is equal to

[tex]4*2*5=40[/tex]

From the above calculation, we can say that the variations the dealership offers is 40

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F = mass × Acceleration ( give Acceleration is 9.8 )

So force of 5 kg mass on A is

F = 5 × 9.8 = 49N

Force of mass 1 kg on A

F = 1 × 9.8 = 9.8 N

Force of mass 10 kg on A is

F = 10 × 9.8 = 98N

Clearly the 10 kg ball experts the most force cause it has more mass

Both carts experience the same force but Cart A has a greater speed after the recoil.

The given parameters;

Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

[tex]m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s[/tex]

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

[tex]F_A = -F_B[/tex]

Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."

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Answer:

Before collision:

momentum to right = .14 * 3.5 = .49 kg m / s

momentum to left = .62 * 4.81 = 2.98 kg m / s

Total momentum = .49 - 2.98 = - 2.49 to left

M V = -2.49    net momentum to left

V = -2.49 / (.14 + .62) = -3.28 m/s to left

Answer:

2 miles

Explanation:

Answer:

"electric or magnetic"

F = q E    force on charge q due to electric field E

F = q v x B       force on charge q due to magnetic field B

Answer:

The Agricultural Revolution of the 18th century paved the way for the Industrial Revolution in Britain. New farming techniques and improved livestock breeding led to amplified food production. This allowed a spike in population and increased health. The new farming techniques also led to an enclosure movement

Answer:

because of the gravity of the earth

Considering the ideal gas law, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P×V = n×R×T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.

In this case, you know:

Replacing in the ideal gas law:

1 atm× 2000 L = n× 0.082057 [tex]\frac{atmL}{molK}[/tex]× 210 K

Solving:

[tex]n=\frac{1 atmx 2000 L}{0.082057 \frac{atmL}{molK}x 210 K}[/tex]

n=116.06 moles

Finally, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.

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