Answer:
Following are the solution to this question:
Explanation:
[tex]CYCLE[/tex]
[tex]Element \ \ \ \ \ \ 1\ \ \ \ \ \ 2 \ \ \ \ \ \ 3 \ \ \ \ \ \ 4 \ \ \ \ \ \ 5 \ \ \ \ \ \ 6 \ \ \ \ \ \ Average[/tex]
[tex]1 \ \ \ \ \ \ 1.2 \ \ \ \ \ \ 1.2 \ \ \ \ \ \ 1.2 \ \ \ \ \ \ 1.2 1.2 \ \ \ \ \ \ - \ \ \ \ \ \ 1.2\\\\[/tex]
[tex]2 \ \ \ \ \ \ - \ \ \ \ \ \ .7 \ \ \ \ \ \ - \ \ \ \ \ \ .7 \ \ \ \ \ \ - \ \ \ \ \ \ 0.7 \ \ \ \ \ \ 0.7 \\\\3 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 3.2 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 2.2 \ \ \ \ \ \ 2.36\\\\[/tex]
[tex]4 \ \ \ \ \ \ 3.2 \ \ \ \ \ \ - \ \ \ \ \ \ - \ \ \ \ \ \ 4.2 \ \ \ \ \ \ - \ \ \ \ \ \ - \ \ \ \ \ \ 3.7\\\\5 \ \ \ \ \ \ 0.7 \ \ \ \ \ \ .7 \ \ \ \ \ \ 1.2 \ \ \ \ \ \ 0.7 \ \ \ \ \ \ 0.7\ \ \ \ \ \ 0.7\ \ \ \ \ \ 0.78[/tex]
[tex]Element \ \ \ \ \ \ \ \ \ \ \ \ Observed \ time \\\\1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1.2\\\\2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.7\\\\3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2.36\\\\4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3.7\\\\5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.78[/tex]
In order to avoid slipping in the shop, your footwear should ___________.
A) Be brand-new
B) Have steel toes
C) Not have shoestrings
D) Have proper tread
(This is for my Automotive class by the way)
In order to avoid slipping in the shop, your footwear should have proper tread. The correct option is D.
What is slipping?Slipping is an action of falling or sliding down due to a lack of friction between the surfaces. This occurs when both surfaces coming into contact are smooth or frictionless.
During rainy seasons, due to rain everywhere the chances of slipping increase, the slippers slip on mud or water. Vehicles also slip down on roads.
To avoid slipping, wear proper shoes. The shoes that have a good grip are less to slip. The tires are given with tread, which increases the grip on the road. Tread-on shoes or slippers are also good. Wear tread full shoes. It can avoid slipping and accidents.
Thus, the correct option is D. Have proper tread.
To learn more about slipping, refer to the link:
https://brainly.com/question/6327886
#SPJ2
Ideal gas helium flows through the inlet of an isentropic nozzle with a velocity of 25 m/s, and the exit flow is at 100 kPa, 300 K, and has a velocity of 250 m/s. a. Determine the inlet temperature. b. Determine the inlet pressure. c. Determine the area ratio between inlet and exit
Answer:
a. The inlet temperature is approximately 305.232 K
b. The inlet pressure is approximately 452.0108 kPa
c. The area ratio between the inlet and exit is approximately 2.2509
Explanation:
a. From the energy equation related to the question, we have;
[tex]C_p \cdot (T_i - T_e) = \dfrac{1}{2} \cdot \left (v_e^2 - v_1^2 \right)[/tex]
Where;
[tex]C_p[/tex] = The specific heat capacity for helium = 5.913 kJ/(kg·K)
[tex]T_i[/tex] = The inlet temperature
[tex]T_e[/tex] = The exit temperature = 300 K
[tex]v_i[/tex] = The inlet velocity = 25 m/s
[tex]v_e[/tex] = The exit velocity = 250 m/s
Therefore, we have;
[tex]T_i= \dfrac{ \dfrac{1}{2} \cdot \left (v_e^2 - v_1^2 \right)}{C_p} + T_e = \dfrac{ \dfrac{1}{2} \times \left (250^2 - 25^2 \right)}{5.913 \times 1000} + 300 \approx 305.232[/tex]
The inlet temperature = [tex]T_i[/tex] ≈ 305.232 K
b. From the following equation for the critical pressure, for helium, we have;
[tex]\dfrac{P_c}{P_i} = \left (\dfrac{2}{n + 1} \right ) ^{\dfrac{n}{n - 1} } = 0.487[/tex]
Where;
[tex]P_c[/tex] = The critical pressure = 2.26 atm for helim
[tex]P_i[/tex] = The inlet pressure
n = The polytropic constant
We have;
[tex]\dfrac{2.26 \ atm}{P_i} = 0.487[/tex]
[tex]\therefore P_i = \dfrac{2.26 \ atm}{0.487} \approx 4.641 \ atm[/tex]
The inlet pressure, [tex]P_i[/tex] ≈ 4.641 atm ≈ 452.0108 kPa
c. The inlet to exit pressure ratio is given as follows;
[tex]P_e = \dfrac{A_i \times T_e \times v_i}{A_e \times T_i \times v_e} \times P_i[/tex]
Therefore, we have;
[tex]\dfrac{A_i}{A_e} = \dfrac{P_e \times T_i \times v_e}{ T_e \times v_i \times P_i} = \dfrac{100 \times 305.232 \times 250}{ 300 \times 25 \times 452.0108} = 2.2509[/tex]
The area ratio between the inlet and exit, [tex]A_i/A_e[/tex] ≈ 2.2509.
A gas stream (A) of 15.0 mol% H2, and the balance N2, is to be mixed with another gas stream
(B) containing 40.0 mol% H2, and the balance N2, to produce 100 kg/h of a 25 mol% H2, and the
balance N2 gas stream (C).
(a) Draw and fully label a flowchart of the mixing process.
(b) Calculate the average molecular weight of the product stream (C).
(c) Calculate the molar flow rates of the product stream (C) in kmol/h.
(d) Calculate the required flow rates of the feed mixtures A and B in kmol/h.
Answer:
A gas stream and other points are discussed below in details.
Explanation:
The method flow chart is displayed above.
B)Mole fraction of H2 in stream C=25%=0.25
Mole fraction of N2 in steams C=1-Mole fraction of H2=1-0.25=0.75
Average molecular weight of stream C=Mole fraction of H2*Molecular weight of H2+ Mole fraction of N2*Molecular weight of N2=0.25*2 kg/kmol+0.75*28 kg/kmol=21.5 kg/kmol
C) Mass flow rate of product C=100 kg/h
Molar flow rate of product C=Mass flow rate /Molecular weight=100 kg/h/21.5 kg/kmol=4.6512 kmol/h
D) Apply overall mole balance
Mole in=Mole out
Mole in=Mole of A+Mole of B=A+B
Let mole of A=A kmol/h
Mole of B=B kmol/h
Mole out=Mole of C stream=4.6512 kmol/h
A+B=4.6512 eq.1
Apply hydrogen mole balance
Mole of H2 in=Mole of H2 in A stream+ Mole of H2 in B stream=0.15 A+0.4 B
Mole of H2 out=Mole of H2 in C stream=0.25*4.6512=1.1628 kmol/h
1.1628 =0.15 A+0.4 B eq.2
Multiply eq.1 by 0.15
0.69768=0.15 A+0.15 B eq.3
Subtract eq.3 from eq.2
0.25 B=0.46512
B=1.86048 kmol/h
Substitute in eq1.
A=4.6512-1.86048=2.79042 kmol/h
Molar flow rate of A=2.79042 kmol/h
A molar flow rate of B=1.86048 kmol/h
A journeyman electrician with 16 years experience on-the-job was removing metal fish
tape from a hole at the base of a metal light pole. It was raining during the course of the
work. The fish tape became energized, electrocuting him. What could have been done to
prevent this accident? Select all that apply.
Explanation:
1. Ensure all circuits are de-energized before beginning work (29 CFR 1926.416(a)(3)).
2. Controls to be deactivated during the course of work on energized or de-energized
equipment or circuits must be tagged (29 CFR 1926.417(a)).
3. Employees must be instructed to recognize and avoid unsafe conditions associated with
their work (29 CFR 1926.21(b)(2)).
What is a shop air compressor
Answer:
need more information about the question