Given the points (-10, -3) and (4,8) find the slope.

Answers

Answer 1

Answer: [tex]\frac{11}{14}[/tex]

Step-by-step explanation:

1) Identify Format

(x1,y1) = (−10,−3)

(x2,y2) = (4,8)

2) Use the Slope Formula

m=y2−y1x2−x1

=8−−3/4−−10

=11/14

=11/14

Bonus: Graph

Answer provided by Education Point

Given The Points (-10, -3) And (4,8) Find The Slope.

Related Questions

The polygon given below is a regular pentagon.



A. 54°
B. 108°
C. 135°
D. 540°

Answers

Answer:

Step-by-step explanation:

In a regular pentagon, all the angles and sides are equal. So, to find an angle, divide 540 by 5.

Sum of all angles of regular pentagon = 540

measurement of one angle = 540 ÷ 5

                                             = 108°

∠N = 108°

Answer:

B

Step-by-step explanation:

Find the average of this set of numbers.16, 20, 30, 30
A) 14
B) 15
C) 25
D) none of the above

Answers

Answer:

D) none of the above

Step-by-step explanation:

16+20+30+30=96

96/4 =24

I’m stuck pls help me

Answers

Answer:

B and E

Step-by-step explanation:

I think it’s E and B

Can someone please help me

Answers

Answer:

When it's negative when it goes to the other side it becomes a positive.....

Y=(x-4)(x-1)

Make y 0 when your calculating for x

Make x 0 when your calculating for y

0=(x-4)(x-1)

Therefore x=4 or x=1

Oxygen flows through one tube into a liter flask filled with air, and the mixture of oxygen and air (considered well stirred) escapes through another tube. Assuming that air contains 4% oxygen, what percentage of oxygen will the flask contain after 5 L have passed through the intake tube?

Answers

The amount of oxygen in the flask through the intake tube illustrates proportions

The flask 99.35% will contain of oxygen after 5L have passed through the intake tube

How to calculate the percentage of oxygen?

To do this, we make use of the following representations

P for the proportion of oxygenV for te volume of oxygenx for the proportion of oxygen in the flask after 5 L passed through

So. we have the following derivative

dP = dV - P * dV

Divide through by dV

dP/dV  = 1 - P

Next, we set up the integral

[tex]\int\limits^x_{0.040} \frac {1}{1 - P}dP= \int\limits^5_0 {dV}[/tex]

Integrate both sides

[tex]-\ln(|P - 1|)|\limits^x_{0.04} = 5[/tex]

Expand

-ln(|x - 1|) + ln(|0.04 - 1|) = 5

Evaluate the difference

-ln(|x - 1|) + ln(|-0.96|) = 5

Express as a fraction

ln(0.96/|x - 1|) = 5

Express both sides as exponents with a base of 2

e^ln(0.96/|x - 1|) = e^5

Solve for x

x = 1 - 0.96/e^5

Evaluate the difference

x = 0.9935

Express as percentage

x = 99.35%

Hence, the flask 99.35% will contain of oxygen after 5L have passed through the intake tube

Read more about proportions at:

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Larissa dives into a pool that is 8 feet deep. She touches the bottom of the pool with her hands 6 feet horizontally from the point at which she entered the water.

What is the approximate angle of elevation from the point on the bottom of the pool where she touched to her entry point?

36.9°
41.4°
48.6°
53.1°

Answers

Answer: 48.6°

Step-by-step explanation:

Angle of elevation = sin inverse (6/8)

= 48.6 degrees

Therefore, Option C is right answer

What is the value of the expression (–5) -3?

1. Apply the negative exponents rule:
1
(−5)3

2. Expand the power:
1
(−5)(−5)(−5)

3. Simplify:
1
x

What is the value of x?

x =

Answers

Answer:

15 :)

Step-by-step explanation:

brainliest please

Answer:

The answer is -125

Proof:

what does Y=
what does x=

Answers

Answer:

Step-by-step explanation:

The equation factors into

(x^2 + 14x + 49) =16                      Factor

(x + 7)^2 = 16                                 Take the square root of both sides

√(x + 7)^2 = √16

x + 7 = +/- 4

x + 7 = + 4                                      Subtract 7 from both sides

x  = 4 - 7

x = - 3

x + 7 = - 4                                      Subtract 7 from both sides.

x = - 4 - 7

x = - 11

x1 = -11

x2 = - 3

find the square root of 576 and do it in factorizing method and your answer is going to be in index form​

Answers

Answer:

24.

Step-by-step explanation:

Solution,

By Prime Factorisation method,

576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3

576 = (2)² × (2)² × (2)² × (3)²

Now,

By Taking square roots on both the sides,

√576 = √ (2)² × (2)² × (2)² × (3)²

√576 = 2 × 2 × 2 × 3

√576 = 24.

There are only 7 days left until the launch of our new product and we only have $668 left and Ira promotion budget we need to spend $85 on the last day can you please calculate how many dollars we can spend on the remaining days

Answers

$83.28 you can spend on seven days

Answer:

97.16

Step-by-step explanation:

in total, you have $668.00.

To reserve enough for the last day, you need to subtract the last day's budget:

This means that, for the remaining 6 days in the week, you have $583.00.

Assuming an equal amount is being spent each day, you can calculate the daily budget by dividing the remaining total by the number of days left.

To avoid going over budget, you can spend $97.16 per day for the other six days.

What is the inverse of 2x-3?

Answers

Step-by-step explanation:

the inverse of 2x-3 is

[tex] \frac{1}{2x - 3} [/tex]

if this helped pls give brainliest

Help picture below problem 3

Answers

angle ksp+61=108(being straight angle)

or,angle ksp=180-61

angle ksp=119

solve this plsssssss ​

Answers

Let's see

LHS

(-8/9×1/-5)+(-8/9×-7/11)

Keep it stay

RHS

-8/9(1/-5+-7/11)

Use distributive law

(-8/9×1/-5)+(-8/9×-7/11)

Hence proved

What is the length for X

Answers

Answer:

x = 5

Step-by-step explanation:

3^2 + 4^2 = x^2

9 + 16 = x^2

25

Now we need to find the square root of 25 :)

The answer is 5

X = 5

Have a great day!!

Please rate and mark brainliest!!

Find the exact value of sin(255∘)

Answers

Check the picture below.

[tex]\textit{Sum and Difference Identities} \\\\ sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(255^o)\implies sin(135^o+120^o) \\\\\\ sin(135^o)cos(120^o)~~ + ~~cos(135^o)sin(120^o) \\\\\\ \left( \cfrac{\sqrt{2}}{2} \right)\left( -\cfrac{1}{2} \right)~~ + ~~\left( -\cfrac{\sqrt{2}}{2} \right)\left( \cfrac{\sqrt{3}}{2} \right)\implies -\cfrac{\sqrt{2}}{4}~~ - ~~\cfrac{\sqrt{6}}{4}\implies \cfrac{-2-\sqrt{6}}{4}[/tex]

How do you graph y=3x-2

Answers

Answer:

The graph should look almost exactly like this. I used a virtual graphing chart to assist, since it is capable of showing more than paper alone.

Answer:

Here is your answer.

Step-by-step explanation:

Order the measures of mass from least to greatest.

Answers

Answer:

18 grams,160 grams,2,100 grams,2 kilograms,17 kilograms,208 kilograms.

The measure from least to greatest is 18 gm < 10 gm< 17 Kg < 2Kg < 2300 gm < 208 Kg.

What is Ascending Order?

The arrangement of numbers or other things in increasing order from least to greatest is known as ascending order. Ascending order is demonstrated by numbers on a number line, which are listed from left to right.

Given:

18gm, 17 Kg, 100 gm, 2 Kg, 2300 gm, 208 Kg

Converting all the units into gram we have

18 , 1700,  100, 2000, 2300, 208000

So, the mass from least to greatest.

18 < 100 < 1700< 2000< 2300 < 208000

Hence, 18 gm < 10 gm< 17 Kg < 2Kg < 2300 gm < 208 Kg.

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Diego's soccer team played in a tournament. The tournament started at 8:07 A.M. It ended at 3:44 P.M. How long did the soccer tournament last?

Answers

Answer:

Step-by-step explanation:

7 hours and 37 minuties

Answer:

5 hours

Step-by-step explanation:

it lasted 5 hours for the tournament

LMNO is a parallelogram, with and . Which statements are true about parallelogram LMNO? Select three options.

x = 11
m∠L = 22°
m∠M = 111°
m∠N = 59°
m∠O = 121°

Answers

Answer:

the answers 1, 4, and 5.

m∠N = 59° and m∠O = 121°.

Option 3 and 4 are correct.

What is a parallelogram?

A parallelogram is a geometric object with sides that are parallel to one another in two dimensions. It is a form of polygon with four sides (sometimes known as a quadrilateral) in which each parallel pair of sides have the same length. A parallelogram has adjacent angles that add up to 180 degrees. You must have studied a variety of 2D shapes and sizes in geometry, including circles, squares, rectangles, rhombuses, etc. Each of these forms has a unique set of characteristics.

As per the given data:

LMNO is a parallelogram

The sum of adjacent angles in a parallelogram is always equal to 180°

11x + 6x - 7 = 180

17x = 187

x = 11

m∠L = m∠N {opposite angles in a parallelogram are equal}

m∠N = 6x - 7 = 6(11) - 7 m∠N

m∠L = 59°

m∠M = m∠O {opposite angles in a parallelogram are equal}

m∠M = 11x = 11(11) = 121°

m∠O = 121°

Hence, m∠N = 59° and m∠O = 121°.

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there were 63 fewer pears than apples in the supermarket. After 37 pears were sold, how many fewer pears than apples ?

Answers

Step-by-step explanation:

63/37 = 1.702 = 1.7

#Ihopethishleps

f Daria repeats the experiment 50 more times, how many of those times should she expect to pull a yellow marble?

Answers

Answer:

it matters how many colors are there

Solve the following equation for p: 6/p=x+a

Answers

[tex]\dfrac 6p = x+a\\\\\implies \dfrac 6p \times\dfrac 16 = (x+a) \times\dfrac 16 ~~~~~~;\left[\text{Multiply both sides by}~ \dfrac 16 \right]\\\\\implies \dfrac 1p = \dfrac{x+a}6\\\\\implies p= \dfrac{6}{x+a}~~~~~~~~~~~~~~~~~~~~;[\text{Cross multiply}][/tex]

The diagram shows a plan for a deck. The area of the deck is 511 ft squared what is the value of x? Show your work

Please helpp

Answers

Just have a good day

The dimension of the unknown variable x of the deck is equal to 14 feet in length.

What is a Rectangle?

A rectangle is a closed 2-D shape, having 4 sides, 4 corners, and 4 right angles (90°).The opposite sides of a rectangle are equal and parallel.

Given in the question is a diagram showing a plan for deck. From the data given, we can write -

Area of Deck = 511 ft.

The value of x can be found out by subtracting the area of the deck from the  area of rectangle having dimensions of length 29 ft and width (16 + 4) = 20 ft. The remaining area will be equated to the sum of the area of rectangle at top right corner having dimensions of length 9 ft and width 4 ft and the area of triangle at lower right corner.

Firstly, we will find the dimensions of the triangle at the lower right. The height of the triangle will be = (20 - 9) ft = 11 ft. The base of the triangle will be = 29 - ( x + 9) ft = (20 - x) ft. Now -

[Area of Rectangle (29 x 20)] - [Area of Deck] = [Area of Rectangle (9 x 4) + Area of triangle (lower right)].

Mathematically -

580 - 511 = 9 x 4 + 1/2 × (20 - x) × 11 = 69

36 + 5.5(20 - x) = 69

36 + 110 - 5.5x = 69

146 - 69 = 5.5x

5.5x = 77

x = 14 ft

Therefore, the dimension of the unknown variable x of the deck is equal to 14 feet.

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A study was designed to investigate the effects of two variables​(1) a​ student's level of mathematical anxiety and​ (2) teaching methodon a​ student's achievement in a mathematics course. Students who had a low level of mathematical anxiety were taught using the traditional expository method. These students obtained a mean score of 440 with a standard deviation of on a standardized test. Assuming no information concerning the shape of the distribution is​ known, what percentage of the students scored between 360 and 520 ​?

Answers

Using Chebyshev's Theorem, considering a standard deviation of 40, we have that at least 75% of the students scored between 360 and 520.

What does Chebyshev’s Theorem state?

When we have no information about the population distribution, Chebyshev's Theorem is used. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.At least 89% of the measures are within 3 standard deviations of the mean.An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].

In this problem, considering a standard deviation of 40, we have that:

440 - 2 x 40 = 360.

440 + 2 x 30 = 520.

Within 2 standard deviations of the mean, no information about the distribution, hence, at least 75% of the students scored between 360 and 520.

More can be learned about Chebyshev's Theorem at https://brainly.com/question/25303620

PLEASE HELP!!! I JUST NEED A STEP-BY-STEP!!!!!!

HINT: integrate with respect to y first (it is an easier approach)
∫∫5x sec^2(xy) dA; R={(x,y): 0 ≤ x ≤ π/6 , 0 ≤ y ≤ 2

[Answer] -5/2 ln(1/2)

Answers

Answer:

Step-by-step explanation:

[tex]=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}x\sec^2(xy)dy\\=5\displaystyle\int_{0}^{\pi/6}dx\displaystyle\int_{0}^{2}\sec^2(xy)d(xy)\\=5\displaystyle\int_{0}^{\pi/6}dx\tan(xy)|_{y=0}^{y=2}[/tex]

[tex]=5\displaystyle\int_{0}^{\pi/6}\tan(2x)dx\\=-\frac{5}{2}\ln\cos(2x)|_{0}^{\pi/6}\\=-\frac{5}{2}[\ln\cos(\pi/3) - \ln\cos(0)]\\[/tex]

[tex]=-\frac{5}{2}\ln{\frac{1}{2}[/tex]

8. Anita recorded the amount of rainfall in
her area each day for 14 days. What was
the total amount of rainfall in the 14 days?
A 40 cm
B 36 cm
C 13.5 cm
D 12.5 cm

Answers

How to determine the total amount of rainfall

From the dot plot, we have the following frequency table

Rainfall    Frequency

0                  4

1/8               5

1/4               1

3/8              2

1/2               1

1 1/4             1

= 3/8 inches

General solution of: (1-xy)^-2 dx + [y^2 + x^2 (1-xy)^-2]dy = 0


show two solution on your answer

nonsense answer deleted​

Answers

✒️MATHEMATICS

[tex] \Large \bold{SOLUTION\ 1:} [/tex]

[tex] \small \begin{array}{l} \text{First, we need to check if the given differential} \\ \text{equation is exact.} \\ \\ (1-xy)^{-2} dx + \big[y^2 + x^2 (1-xy)^{-2}\big]dy = 0 \\ \\ \dfrac{dx}{(1-xy)^2} + \left[y^2 + \dfrac{x^2}{(1-xy)^2}\right]dy = 0 \\ \\ \quad M(x, y) dx + N(x, y) dy = 0 \end{array} [/tex]

[tex] \small \begin{array}{l l}\tt\: M(x,y) = \dfrac{1}{(1 - xy)^2}, & N(x,y) = y^2 + \dfrac{x^2}{(1-xy)^2}\\ \\\tt \dfrac{\partial M}{\partial y} = \dfrac{-2(-x)}{(1 - xy)^3}, & \dfrac{\partial N}{\partial x} = \dfrac{2x}{(1 - xy)^2} + \dfrac{-2(-y)x^2}{(1 - xy)^3} \\ \\\tt \dfrac{\partial M}{\partial y} = \dfrac{2x}{(1 - xy)^3}, & \dfrac{\partial N}{\partial x} = \dfrac{2x(1 - xy)+2x^2y}{(1 - xy)^3} \\ \\\tt \: & \dfrac{\partial N}{\partial x} = \dfrac{2x}{(1 - xy)^3} \end{array} [/tex]

[tex] \small \begin{array}{l} \tt\dfrac{\partial M}{\partial y} = \dfrac{\partial N}{\partial x} \implies \text{Differential equation is exact.} \\ \\\tt \dfrac{\partial F}{\partial x} = M(x, y) = \dfrac{1}{(1 - xy)^2} \\ \tt\displaystyle F(x, y) = \int \dfrac{1}{(1 - xy)^2} \partial x = -\dfrac{1}{y} \int \dfrac{1}{(1 - xy)^2}(-y)\partial x \\ \\ \tt\:F(x, y) = \dfrac{1}{y(1 - xy)} + h(y) \\ \\ \tt\dfrac{\partial F}{\partial y} = N(x, y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\\tt \dfrac{\partial}{\partial y}\left[\dfrac{1}{y(1 - xy)} + h(y)\right] = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ \tt-\dfrac{1 - xy + y(-x)}{y^2(1 - xy)^2} + h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ \tt-\dfrac{1 - 2xy}{y^2(1 - xy)^2} + h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} + \dfrac{1 - 2xy}{y^2(1 - xy)^2} \\ \\ \tt\:h'(y) = y^2 + \dfrac{x^2y^2 - 2xy + 1}{y^2(1-xy)^2} = y^2 + \dfrac{1}{y^2} \\ \\ h(y) = \dfrac{y^3}{3} - \dfrac{1}{y} + C \\ \\ \tt\text{Substituting to }F(x,y),\text{we get} \\ \\ \dfrac{1}{y(1 - xy)} + \dfrac{y^3}{3} - \dfrac{1}{y} = C \\ \\ \quad \quad \text{or} \\ \\ \tt\red{\boxed{\dfrac{x}{1 - xy} + \dfrac{y^3}{3} = C} \Longleftarrow \textit{Answer}} \end{array} [/tex]

[tex] \Large \bold{SOLUTION\ 2:} [/tex]

[tex] \small \begin{array}{l} \tt\text{Since we already know that the equation is exact,} \\ \text{we can then continue solving for the solution by} \\ \text{inspection method or by algebraic manipulation.} \\ \\ \tt(1-xy)^{-2} dx + \big[y^2 + x^2 (1-xy)^{-2}\big]dy = 0 \\ \\ \tt\dfrac{dx}{(1-xy)^2} + \left[y^2 + \dfrac{x^2}{(1-xy)^2}\right]dy = 0 \\ \\ \tt\dfrac{dx}{(1-xy)^2} + y^2 dy + \dfrac{x^2}{(1-xy)^2} dy = 0 \\ \\ \tt\dfrac{dx + x^2dy}{(1-xy)^2} + y^2 dy = 0 \\ \\ \tt\text{Divide both numerator and denominator of the} \\ \tt\text{fraction by }x^2. \end{array} [/tex]

[tex] \small \begin{array}{c}\tt \dfrac{\dfrac{1}{x^2}dx + dy}{\dfrac{(1-xy)^2}{x^2}} + y^2 dy = 0 \\ \tt\\ \tt\dfrac{\dfrac{1}{x^2}dx + dy}{\left(\dfrac{1}{x}-y\right)^2} + y^2 dy = 0 \\ \\ \tt-\dfrac{\left(-\dfrac{1}{x^2}dx - dy\right)}{\left(\dfrac{1}{x}-y\right)^2} + y^2 dy = 0 \\ \\ \tt\displaystyle {\large{\int}} -\frac{d\left(\dfrac{1}{x}-y\right)}{\left(\dfrac{1}{x}-y\right)^2} + \int y^2 dy = \int 0 \\ \\ \tt\implies\tt \dfrac{1}{\dfrac{1}{x}-y} + \dfrac{y^3}{3} = C \\ \\\text{or} \\ \\ \tt\red{\boxed{\dfrac{x}{1 - xy} + \dfrac{y^3}{3} = C} \Longleftarrow \textit{Answer}} \end{array} [/tex]

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Please help me. I really need help. and I'm not smart

A researcher weighed watermelons grown across a certain region. The data are rounded to the nearest pound and displayed in this histogram.

What does the fourth bin represent?

Select from the drop-down menu to correctly complete the statement.
Four watermelons weigh:



at least 12 pounds but less than 16 pounds


at least 12 pounds but no more than 16 pounds

more than 12 pounds but less than 16 pounds
.
more than 12 pounds but no more than 16 pounds
.

Answers

In the given histogram, the correct option regarding the representation of the fourth bin is:

at least 12 pounds but less than 16 pounds.

What is an histogram?

An histogram is a graph that shows the number of times each element of x was observed. The lower bound is inclusive, while the upper bound is exclusive.

Hence, considering the inclusiveness and exclusiveness of the bounds, the correct option regarding the fourth bin, given by [12, 16) is:

at least 12 pounds but less than 16 pounds.

More can be learned about histograms at https://brainly.com/question/25836450

Answer:

The answer is "at least 12 pounds but less than 16 pounds"

Explanation:

I took the quiz! Hope this helps! :)

Please help, has t toy cars. Zachary has 3 times as many toy cars as Oliver. Write an expression
that shows how many toy cars Zachary has.

Answers

Answer:

z=3t

Step-by-step explanation:

multiply it by 3

Which of the following is NOT a characteristic of a plane?

A. thickness
B. width
C. flat surface
D. length

Answers

Answer:

A). thickness are correct

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