Given the circle below with secants \overline{UVW} UVW and \overline{YXW} YXW . If YW=40, YX=16YW=40,YX=16 and VW=22VW=22, find the length of \overline{UV} UV . Round to the nearest tenth if necessary.

Answer:

P = 59/5

Step-by-step explanation:

Answer: 16.10

Step-by-step explanation:

$14 + 15% increase rate = 16.10

15% = 2.10

The equation is x² + y² = 277 and the value of x and y is 9 and 14 respectively

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the two number be x and y

One integer is 5 less than another

So , x = y - 5  

x - y = -5   be equation (1)

And , sum of their squares is 277

So , x² + y² = 277   be equation (2)

On simplifying the equation , we get

( x - y )² = x² + y² - 2xy

Substituting the values in the equation , we get

( -5 )² = 277 - 2xy

2xy = 277 - 25

2xy = 252

And , ( x + y )² = x² + y² + 2xy

Substituting the values in the equation , we get

( x + y )² = 277 + 252

( x + y )² = 529

( x + y ) = 23   be equation (3)

Adding equation (1) and equation (3) , we get

2x = 18

x = 9

So , y = 14

Therefore , the value of x and y is 9 and 14 respectively

Hence , the equations are solved

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It's possible that the lines do not appear to be perpendicular, even though the slopes are negative reciprocals, because the lines may not be intersecting at 90 degrees angle,

What are the slopes of the two lines?

The slope of a straight line between two points says (x1,y1) and (x2,y2) can be easily determined by finding the difference between the coordinates of the points. The slope is usually represented by the letter m.

The slopes of the two lines that Laurie graphed, -2 and 1/2, are negative reciprocals of each other, which means that their product is -1.

In a Cartesian coordinate system, lines that are perpendicular to each other will have slopes that are negative reciprocals of each other, and the product of their slopes will be -1.

However, it's possible that the lines do not appear to be perpendicular, even though the slopes are negative reciprocals, because the lines may not be intersecting at 90 degrees angle.

The two lines could be skew lines that never intersect and thus cannot be perpendicular.

Another reason could be that the lines may not be in the same coordinate system or not graphed on the same set of axes.

When working with slope, we always assume that the lines are defined on a 2D Cartesian coordinate system, if that is not the case, it could cause the lines to not appear as perpendicular.

Hence, it's possible that the lines do not appear to be perpendicular, even though the slopes are negative reciprocals, because the lines may not be intersecting at 90 degrees angle, another reason could be that the lines may not be in the same coordinate system or not graphed on the same set of axes.

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Answer: 27 boys

Step-by-step explanation:

There is a rule in math, what you do to one side, you do to the other.

So in this case the ration is 3:5

                                             ?:45

As you can see, they multiplied 5 by 9 to get 45, remember the rule, so we do the same.

3 times 9 is 27, so 27 boys

The coordinate of the point C is (0, a)

From the question, we have the following parameters that can be used in our computation:

A = (0, a)

B = (b, 0)

As a general rule, the orthocenter of a triangle is a point located at the intersection of the lines containing the altitudes of the triangle.

This means that we start by calculating the equation of the altitude from B to line AC.

A linear equation is represented as

y = mx + c

Where

slope = m

y-intercept = c

Using the above as a guide, we have the following:

slope = (y₂ - y₁)/(x₂ - x₁)

This gives

m(BC) = (0 - 0)/(b - 0) = 0

y-intercept (c) = a

So the equation of the line BC is

y = 0 * x + a

y = a

For line AC, we have

m(AC) = (a - 0)/(0 - 0) = a/0 = undefined.

This means that the equation of the line AC is

x = 0

The equation x = 0 implies that the x-coordinate is always 0, irrespective of the y-coordinate e.g. (0, a)

At this stage, we have the coordinates of the points from lines AC and BC to be

(0, a) and (0, a)

Next, we calculate the C as follows

C = Midpoints of (0, a) and (0, a)

This gives

C = 1/2 * (0 + 0, a + a)

Evaluate

C = (0, a)

Hence, the coordinate of C is (0, a)

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Education order reads: 24 hours after bone marrow transfusion give Neupogen 10 mcg/kg/d IV. Supply on hand. Neupogan 300 mcg/ml. Patient’s weight 115 lbs. Give 1.74 mL

To calculate the appropriate dosage of Neupogen to give to the patient, we need to convert the patient's weight from pounds to kilograms and then use the dosage provided in the order (10 mcg/kg/d IV).

First, we have to convert the patient's weight from pounds to kilograms:

115 pounds = 52.16 kg

Now we can use the dosage provided in the order (10 mcg/kg/d IV) to calculate the appropriate dosage for the patient:

10 mcg/kg/d IV

= 10 mcg/kg/day * 52.16 kg

= 521.6 mcg/day

Then, since the Neupogen is available in a solution of 300 mcg/ml, we can use the following formula to calculate the required volume of solution to give to the patient:

Volume = Dosage / Concentration

= 521.6 mcg / 300 mcg/ml

= 1.74 ml

So, the education order reads 24 hours after bone marrow transfusion, give 1.74 mL of Neupogen at a concentration of 300 mcg/mL IV.

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Need to find the x and y: The Graph asking in question is attached below:

A graph is a type of data structure used to represent relationships between different objects. It consists of nodes, which are connected by edges. The nodes represent the objects, while the edges represent the relationships between them. Graphs can be used to represent many different types of information, such as road networks, social networks, and even computer networks. Graphs can be used to solve a variety of problems, such as finding the shortest path between two nodes, or finding the most efficient way to route data throughout a network. Graphs can be represented in a variety of ways, such as in the form of a table, a map, or a diagram. In addition, graphs can be used to represent abstract concepts such as relationships between individuals.

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The center of the circle is (-10,4) and the radius is 10.

The circle is defined as the locus of the point traces around a fixed point called as the center and is equidistant from the outer trace.

All points in a plane that are at a specific distance from a specific point, the center, form a circle. In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant.

The equation of the circle is,

( x - h )² + ( y - k )² = r²

(x+10)² + (y−4)² = 100

(x+10)² + (y−4)² = 10²

Compare the equations and find the center and radius,

Center = ( h,k) = ( -10,4)

Radius = r = 10

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Answer:yesb

Step-by-step explanation:

because u

Answer:

[tex]a^{12} b^{4}[/tex]

Step-by-step explanation:

To simplify we will have to use the negative exponent rule and the power rule along with some algebra.

Negative Exponent Rule

[tex]a^{-b} =\frac{1}{a^b}[/tex]

Power Rule

[tex](a^b)^{c} =a^{bc}[/tex]

Given

[tex](a^{-4}b^{-1}c )^{2} (a^2bc)^{2}[/tex]

Rewrite [tex]a^{-4}[/tex] using negative exponent rule.

[tex](\frac{1}{a^{4}}* b^{-1}c )^{2} (a^2bc)^{2}[/tex]

Rewrite [tex]b^{-1}[/tex] using negative exponent rule.

[tex](\frac{1}{a^{4}}* \frac{1}{b}*c )^{2} (a^2bc)^{2}[/tex]

Simplify

[tex](\frac{c}{a^4b} )^{2} (a^2bc)^{2}[/tex]

Rewrite the base as its reciprocal.

[tex](\frac{a^4b}{c} )^{2} (a^2bc)^{2}[/tex]

Apply the power rule.

[tex]\frac{a^8b^2}{c^2} *(a^2bc)^{2}[/tex]

Apply the power rule.

[tex]\frac{a^8b^2}{c^2} *a^4b^2c^2[/tex]

Cancel the common factor of [tex]c^2[/tex].

[tex]a^8b^2 a^4b^2[/tex]

Apply the power rule.

[tex]a^{12} b^{4}[/tex]

Answer:

[tex]a^{12}\:b^{4}[/tex]

Step-by-step explanation:

Given expression:

[tex]\left(a^{-4}\:b^{-1}\:c\right)^{-2}\left(a^2\:b\:c\right)^2[/tex]

[tex]\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:[/tex]

[tex]\implies a^{(-4 \times -2)}\:b^{(-1 \times -2)}\:c^{-2}\:a^{(2 \times 2)}\:b^2\:c^2[/tex]

Simplify:

[tex]\implies a^{8}\:b^{2}\:c^{-2}\:a^{4}\:b^2\:c^2[/tex]

Collect like terms:

[tex]\implies a^{8}a^{4}\:b^{2}b^2\:c^{-2}c^2[/tex]

[tex]\textsf{Apply exponent rule} \quad a^b \cdot a^c=a^{b+c}:[/tex]

[tex]\implies a^{(8+4)}\:b^{(2+2)}\:c^{(-2+2)}[/tex]

Simplify:

[tex]\implies a^{12}\:b^{4}\:c^{0}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^0=1:[/tex]

[tex]\implies a^{12}\:b^{4}(1)[/tex]

[tex]\implies a^{12}\:b^{4}[/tex]

The graphs as per the transformations are given below.

What are transformation of graphs?

There are four transformations that happens in a graph -

When a figure is translated, it is moved in any direction.

Flipping a figure over a line is called reflection.

Rotation is the process of turning a figure a specific amount around a point.

When we dilate a figure, we increase or decrease its size.

The triangle CHV have points C(-4,5), H(-3,3) and V(-3,5). When it is reflected across x=-3. The image gets mirrored in the negative y-axis with the points C(-4,-2), H(-3,0) and V(-3,-2).

The parallelogram CJWY have points C(-3,-1), J(-2,-1), W(-2,-4), Y(-1,-4). It needs to be translated by (x,y)->(x+2,y+0)

C=(-3+2,-1+0)=(-1,-1)

J=(-2+2,-1+0)=(0,-1)

W=(-2+2,-4+0)=(0,-4)

Y=(-1+2,-4+0)=(1,-4)

The parallelogram TSCH have points T(-1,3), S(1,4), C(1,-1), H(3,0). It needs to be translated by (x,y)->(x+0,y-1)

T=(-1+0,3-1)=(-1,2)

S=(1+0,4-1)=(1,3)

C=(1+0,-1-1)=(1,0)

H=(3+0,0-1)=(3,-1)

The triangle RDP have points R(0,0), D(-2,-2) and P(3,-3). On rotation of 180 degrees graph (x,y) becomes (-x,-y).

R=(0,0)

D=[-(-2),-(-2)]=(2,2)

P=[-(3).-(-3)]=(-3,3)

Therefore, the transformations are made.

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Answer:

The scale of the model is (21 ft / 3 in) = 7 ft / 1 in. So an 84 foot building would be (84 ft / 7 ft) * 1 in = 12 inches tall in the model.

Step-by-step explanation:

hope it helps

Answer:

588 inches

Step-by-step explanation:

First, find the scale factor of the model by dividing the height of the real building by the height of the model: 21 ft / 3 inches = 21/3 = 7

7 inches/ft

Then, multiply the scale factor by the height of the 84 foot building to find the height of the model: 7 inches/ft * 84 ft = 7*84 = 588

588 inches

Answer: To compare the level of support for the new after-school club between teachers and students, we can calculate the percentage of individuals in each group that responded "yes" to the proposal.

For teachers: 13 out of 20 is equivalent to 13/20 = 0.65 or 65%

For students: 37 out of 50 is equivalent to 37/50 = 0.74 or 74%

Based on the percentage of individuals in each group that responded "yes," we can see that students are more in favor of the new after-school club than teachers. 74% of students responded "yes" to the proposal, while only 65% of teachers responded "yes."

It's worth mentioning that it's important to keep in mind that this comparison is based on the sample size of teachers and students that responded to the survey and not the whole population, also if the sample size isn't representative of the population and not randomly selected it can't be generalized.

Step-by-step explanation:

Answer:

Step-by-step explanation:

a.we konw DC=2b and DO=OC, so the coordinate of D(-b, 0), C(b, 0)

b.we konw the height of rectangle is h, so the coordinate of A(-b, h), B(b, h).

Answer: 13/15

Step-by-step explanation: Hope this helps, please mark brainliest and give thanks!

2/3+1/5

15÷3*2+15÷5*1

10+3/15

13/15

Answer:

Step-by-step explanation:

Answer: Here, let X,Y,ZX,Y,Z indicate the amount in dollars to be invested

Step-by-step explanation: Here, let X,Y,ZX,Y,Z indicate the amount in dollars to be invested

Therefore , the solution to the given problem of arithmetic mean comes out to be 1. 105, 2. 234 and 3. 42.5

The combination of the amount of all of the values in a list and the number of items in the that list, split by both, is the arithmetic average or mean of the group. The mathematical progression is same to this. This mean of the digits 5, 7, and 9 is 4,

For example, as expression 5 + 7 + 9 is 21, and 21 divided by 3 [there are actually three numbers] equals 7.

Given:

1) There are six terms in AP, with terms a and d each being worth five points.

2) There are 6 terms in AP, with terms 9 and 12 respectively.

3) In AP, there are five terms, where an is 5.7 and d is 1.4.

4) In AP, = 20, t21 = 400

5) In AP, t100 = 99 and a = 0

Find the sum of the terms in the arithmetic series.

As is common knowledge, Sn in the AP equals n/2[2a+(n-1)d]

To determine: the total terms in the arithmetic series

The AP sum of n words is well known. Sn = (n-1)/2[2a+(n-1)d]

1) There are 6 terms in the case where a = 5 and d = 5, as shown by S6 = [2(5)+(61)5] = 3[10+5(5)] = 3[10 + 25] = 3(35) = 105

2) There are 6 terms in the case where a = 9 and d = 12, where S6 = [2(9)+(61)12] = 3[18+5(12)] = 3[18+60] = 3(78) = 234

3) There are 5 terms total, with terms a = 5.7 and d = 1.4.

S5= [2(5.7)+(5—1)1.4] = 2.5[11.4+4(1.4)] = 2.5[11.4+5.6] = 2.5(17) = 42.5

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Answer:

1.05

Step-by-step explanation:

it is 105 divided by 1000

Answer:

0.105 metres

Step-by-step explanation:

105 divided by 1000

This is a separable differential equation, which means we can separate the variables y and x on either side of the equation. To do this, we'll move all the terms involving y to one side and all the terms involving x to the other side.

dy/dx = (1+y²)e^x

We'll divide both sides by (1+y²)e^x:

dy/(1+y²)e^x = dx

Now we'll integrate both sides with respect to their respective variables. The integral of dy/(1+y²) with respect to y is the inverse tangent (tan^-1) function, so we'll use that on the left side:

∫ dy/(1+y²) = ∫dx + C

tan^-1(y) = x + C

On the right side, we'll integrate e^x with respect to x, which gives us e^x. So we have:

tan^-1(y) = e^x + C

We can solve for y by reversing the tan^-1 function:

y = tan(e^x + C)

Where C is an arbitrary constant of integration.

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The time that it will take for the spaceships to meet is given as follows:

3 hours.

Each of the spaceships is traveling at a constant rate, hence linear functions are used to model the situation.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which the parameters are given as follows:

The positive direction is considered from the first spaceship towards the second spaceship.

The first spaceship started an hour before the second spaceship and is traveling at 110,000 km/hr, hence the difference when the second spaceship starts traveling is given as follows:

710,000 - 110,000 = 600,000 km.

Then the functions are given as follows:

They will meet when:

x1(t) = x2(t).

Hence:

110t = 600 - 90t

200t = 600

t = 600/200

t = 3 hours.

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The time that it will take for the spaceships to meet is given as follows:

3 hours.

How to model the situation?

Each of the spaceships is traveling at a constant rate, hence linear functions are used to model the situation.

The slope-intercept definition of a linear function is given as follows:

y = mx + b.

In which the parameters are given as follows:

The slope m represents the velocity.

The intercept b represents the initial position.

The positive direction is considered from the first spaceship towards the second spaceship.

The first spaceship started an hour before the second spaceship and is traveling at 110,000 km/hr, hence the difference when the second spaceship starts traveling is given as follows:

710,000 - 110,000 = 600,000 km.

Then the functions are given as follows:

x1(t) = 110t.

x2(t) = 600 - 90t. (negative as they travel in opposite direction).

They will meet when:

x1(t) = x2(t).

Hence:

110t = 600 - 90t

200t = 600

t = 600/200

t = 3 hours.

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In order to find the length of v in ΔUVW, we can use the Law of Sines.

The Law of Sines states that the ratio of the length of a side of a triangle to the sine of the opposite angle is the same for all sides and angles in the triangle. This can be expressed as:

a/sin A = b/sin B = c/sin C

Where a, b, and c are the lengths of the sides of the triangle and A, B, and C are the angles opposite those sides.

In ΔUVW, we are given the lengths of two sides (w and v) and the measure of the angles opposite those sides (m∠W and m∠U). We can use the Law of Sines to find the length of v:

v/sin U = w/sin W

v = (w/sin W) * sin U

Substituting the given values, we get:

v = (1.4 cm / sin 63°) * sin 29°

Using a calculator, we find that v = 2.72 cm to the nearest hundredth of a centimeter. Rounding to the nearest 10th of a centimeter, we get v = 2.7 cm.

Therefore, the length of v in ΔUVW is approximately 2.7 cm to the nearest 10th of a centimeter.

Answer:

-10

Step-by-step explanation:

-5b + 35 = 85

-5b = 50

-5b/-5 = 50/-5

b = -10

Answer:

B = -10

Step-by-step explanation:

-5b + 35 = 85

work is shown in picture

The line that passes through these two points is y=x-2

Linear equations help in representing the relationship between variables such as x, y, and z, and are expressed in exponents of one degree. In these linear equations, we use algebra, starting from the basics such as the addition and subtraction of algebraic expressions.

Given here function whose graph contains the points (9, 7) and (4, −8)

Thus using the two point formula for a line we get the equation as

y-7=(x-9)

y=x-2

Hence, The line that passes through these two points is y=x-2

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Answer:

3.5 miles per hours

Step-by-step explanation:

7/2 =3.5

Therefore , the solution to the given problem of order comes out to be

-6< -3< -2.2 < -1/2 < 1/4 < 2[tex]\frac{1}{3}[/tex] < 2.5 < 4.

Numerical order can be used to organise a set of numbers. It is possible to use both increasing and decreasing ordering. Consider how a set of numbers would seem if they were organized in ascending order like 2, 55, 103, 256, and 802, for example. This can make sorting through a huge collection of numbers much easier.

Here,

Given : 2.5, -6, -3, 4, -2.2, 1/4, -1/2, 2 1/3

To put them according to ascending order :

So ,

negative terms are the smallest compare to positive terms as their values are lower than 0.

thus,

-6< -3< -2.2 < -1/2 < 1/4 < 2[tex]\frac{1}{3}[/tex] < 2.5 < 4

Therefore , the solution to the given problem of order comes out to be

-6< -3< -2.2 < -1/2 < 1/4 < 2[tex]\frac{1}{3}[/tex] < 2.5 < 4.

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ax + by = 6000 and a + 5 = b are two equations that might be used to calculate how many soup cans and frozen dinners were purchased.

There are several methods to define a formula. A mathematical statement that establishes the equivalence of two mathematical expressions is the definition of an equation in algebra. This is best shown by the formula 3x + 5 = 14. In this instance, the word equal comes between the phrases 3x + 5 and 14. Even the most basic algebraic equations include the usage of mathematical variables.

X now has 300 mg of sodium in it.

[tex]x = 300[/tex]

Y also has 450 mg of sodium in it.

[tex]y = 450[/tex]

Samuel reportedly buys five more frozen dinners than soup cans, and they all have a combined salt content of 6000 mg.

Let the number of frozen dinners be "b," and the number of soup cans be "a."

ax + by = 6000

a(300) + b(450) = 6000 .

Samuel bought 5 more frozen dinners than soup cans, according to the inquiry, which results in equation

[tex]a + 5 = b \\a(300) + (a + 5)(450) = 6000\\300a + 450a = 6000 - 2250\\ 750a = 3750\\ a = 3750/750\\ a = 5\\5 + 5 = b\\ b = 10[/tex]

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Step-by-step explanation:

please refer to the sketch

Answer:

  C

Step-by-step explanation:

You want the equations of the circle and ellipse in the given figure.

The standard form equation for an ellipse is ...

  [tex]\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1[/tex]

where 'a' and 'b' are the semi-axes in the x-direction and y-direction, respectively.

You will notice that when a=b=r, the ellipse becomes a circle and the equation can be rewritten as ...

  [tex]\dfrac{x^2}{r^2}+\dfrac{y^2}{r^2}=1\ \Longleftrightarrow\ x^2+y^2=r^2[/tex]

Here, the radius is 3, the same as the semi-major axis in the x-direction (a=3). The ellipse axis in the y-direction appears to be about 1/3 that value, so b=1, and the equations of the circle and ellipse are ...

  [tex]x^2+y^2=9\qquad\text{circle}\\\\\dfrac{x^2}{9}+\dfrac{y^2}{1}=1\qquad\text{ellipse}[/tex]