Answer:
A. To find the magnitude of R, we first need to find the vector R by adding the vectors r1, r2, and r3.
R = r1 + r2 + r3 = (3i + 2j + k) + (2i - 4j - 3k) + (-1i + 2j + 2k) = (4i - 2j + 2k)
The magnitude of R is given by the formula ∣R∣ = √(R⋅R), where R⋅R is the dot product of R with itself.
∣R∣ = √(R⋅R) = √(4i^2 + (-2j)^2 + (2k)^2) = √(16 + 4 + 4) = √(24) = 2√(6)
B. To find the magnitude of A, we first need to find the vector A by applying the scalar multiplication 2 to r1 and subtracting scalar multiplications of r2 and r3.
A = 2r1 - 3r2 - 5r3 = (6i + 4j + 2k) - (6i - 12j + 15k) - (-5i + 10j + 10k)
A = (6i + 4j + 2k) - (6i - 12j + 15k) - (-5i + 10j + 10k) = (11i + 2j - 13k)
The magnitude of A is given by the formula ∣A∣ = √(A⋅A), where A⋅A is the dot product of A with itself.
∣A∣ = √(A⋅A) = √(11i^2 + 2j^2 + (-13k)^2) = √(121 + 4 + 169) = √(294) = 2√(73)
help me with the following
(a) The power required by the car climbing the inclined plane at steady speed is 15.554 kW.
(b) The power required by the car when the speed changes is 19.45 kW.
What is the power required for the car?
The power required by a car climbing the inclined plane is calculated as follows;
P = Fv
where;
v is the average velocity of the carF is the force of frictionSince the speed is steady, v = 80 km/h = 22.22 m/s
P = 700 N x 22.22
P = 15,554 W
P = 15.554 kW
When the speed of the car changes from 90 km/h to 110 km/h, the power required is calculated as;
vf = 110 km/h = 30.56 m/s
vi = 90 km/h = 25 m/s
V = ( 30.56 + 25 ) / 2 = 27.78 m/s
P = FV
P = 700 x 27.78
P = 19,446 W
P = 19.45 kW
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3. A football player runs at 8 m/s and plows into a 80 kg referee standing on the field causing
the referee to fly forward at 5.0 m/s. If this were a perfectly elastic collision, what would the
mass of football player be?
Answer:
Explanation:
To solve for the mass of the football player, we can use the conservation of momentum principle, which states that the total momentum before a collision is equal to the total momentum after the collision. Assuming the collision is perfectly elastic, we have:
m1 * v1 + m2 * v2 = m1 * v1' + m2 * v2'
where m1 is the mass of the football player, v1 is the initial velocity of the football player, m2 is the mass of the referee, v2 is the initial velocity of the referee, v1' is the final velocity of the football player, and v2' is the final velocity of the referee.
Since the referee is at rest before the collision, we can set v2 = 0. Plugging in the given values, we get:
m1 * 8 + m2 * 0 = m1 * (-8) + m2 * 5
Expanding and solving for m1:
8m1 = -8m1 + 80
16m1 = 80
m1 = 5 kg
So, the mass of the football player is 5 kg.
Air bags are put into cars and other vehicles to reduce injury to passengers. How do these devices reduce injury?
Answer:
it's there to reduce movement of the passenger if hit.
Explanation:
it's quite simple really, its there because if it wasn't the person would've gone flying through the front window screen.
Particles q₁ = +18.1 µC, q2 = -11.2 μC, and
93 +5.67 μC are in a line. Particles q₁ and q2 are
separated by, 0.280 m and particles q2 and q3 are
separated by 0.350 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-27.7 x 10⁶ N is the net force on particle q₂..
Define a charged particle
A particle with an electric charge is said to be charged particle. It might be an ion, such as a molecule or atom having an excess or shortage of electrons in comparison to protons. It could also be an elementary particle like as an electron, proton, or another one that is thought to have the same charge (except antimatter).
F₁₂ = kq₁q₂/r²
k is Coulomb's constant
r is the distance between q₁ and q₂
q represent charges
F₁₂ = (9x 10⁹ x 18.1 x 10⁻³ x 11.2 x 10⁻³)/(0.28)²
F₁₂ = -23* 10⁶ N
F₂₃ = kq₂q₃/r²
F₂₃ = -(9 x 10⁹ x 11.3 x 10⁻³ x 5.67 x 10⁻³)/(0.35)²
F₂₃ = 4.7 x 10⁶ N
F(net) = F₁₂ + F₂₃
= -23* 10⁶ N + -4.7 x 10⁶ N
= -27.7 x 10⁶ N
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The tension T2 has a magnitude of 60.0 N and the masses m₁ = 10.0 kg, m2 = 8.00 kg, and m3 = 12.0 kg. Determine the acceleration of the masses and the tension T1.
Answer: We can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by acceleration.
Let's call the acceleration of the system "a". Then the net force acting on m1 is T1 - T2 + m1 * a = 0.
The net force acting on m2 is T2 - m2 * a = 0.
And the net force acting on m3 is T2 + m3 * a = 0.
Solving these three equations, we get:
T1 = T2 + m2 * a = 60.0 N + 8.00 kg * a
m1 * a = -T2 + 60.0 N + m1 * a
m3 * a = T2 - 60.0 N + m3 * a
Substituting T2 = 60.0 N, we get:
T1 = 60.0 N + 8.00 kg * a
m1 * a = -60.0 N + 10.0 kg * a
m3 * a = 60.0 N + 12.0 kg * a
Solving for the acceleration, we get:
a = (60.0 N + 8.00 kg * a) / (10.0 kg - 8.00 kg) = (60.0 N + 8.00 kg * a) / 2.0 kg
a = (60.0 N + 8.00 kg * a) / 2.0 kg = (60.0 N) / 2.0 kg + (8.00 kg * a) / 2.0 kg
a * 2.0 kg = 60.0 N + 8.00 kg * a
a = 60.0 N / 2.0 kg + 8.00 kg * a / 2.0 kg
a * 2.0 kg - 8.00 kg * a = 60.0 N
a * 10.0 kg = 60.0 N + 8.00 kg * a
a = 60.0 N / 10.0 kg = 6.0 m/s²
Finally, we can use T1 = 60.0 N + 8.00 kg * a to find T1:
T1 = 60.0 N + 8.00 kg * 6.0 m/s² = 60.0 N + 48.0 N = 108.0 N
So the acceleration of the masses is 6.0 m/s², and the tension T1 is 108.0 N.
Explanation:
A bottle of wine known as a magnum contains a volume of 1.5 liters. A bottle known as a jeroboam contains 0.792 U.S. gallons. How many magnums are there in 8 jeroboams?
Answer:
Explanation: =− And ..=. −=. = =. ( .. . ) ( . ..) =. Therefore = .=
A car traveling at 3500 m/s is to stop on a 35-meter long shoulder of the road. What minimum deceleration is required?
The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.
What is deceleration?Deceleration is defined as the decrease in speed as the body moves away from the starting point.
The minimum deceleration required can be calculated using the equation of motion:
d = v^2 / (2 * a)
where d is the distance, v is the initial velocity, and a is the acceleration.
Rearranging the equation to solve for a:
a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2
In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.
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Which of the following are electric insulators?
The examples of electric insulators are -
glass jar, rubber ball, tree, puddle.
What are electric insulators?Electric insulators are the materials that does not conduct electricity through them.
Given are the examples of electric insulators.
The examples of electric insulators are -
glass jar, rubber ball, tree, puddle
Therefore, the examples of electric insulators are -
glass jar, rubber ball, tree, puddle.
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Your friend shoots an 80-g arrow through a 100-g apple balanced on william tells head. the arrow has a speed of 50 m/s before passing through the apple and 40 m/s after. determine the final speed of the apple
The final speed of the apple would be 26.9 m/s.
What is collision in physics?A collision happens when two bodies come in direct contact with each other.In this case, the two bodies exert forces on each other in a short period of time.The energy and momentum of bodies interacting undergo a change as a result of the collision.An elastic collision is an encounter (collision) between two bodies in which the total kinetic energy of the two bodies remains the same.In an ideal, perfectly elastic collision, there is no net conversion of kinetic energy into other forms such as heat, noise, or potential energy.Given is that your friend shoots an 80g arrow through a 100g apple balanced on William tells head. The arrow has a speed of 50m/s before passing through the apple and 40m/s after.
In a elastic collision, the total kinetic energy of the system remains the same. So, we can write -
[tex]$E_{1i} +E_{2i} = E_{1f} +E_{2f}[/tex] .... Eq{ 1 }
We can write as -
{1/2 x 80 x 2500} + 0 = {1/2 x 80 x 1600} + {1/2 x 100 x v²}
{1/2 x 100 x v²} = {40 x 2500} - {40 x 1600}
50v² = 40 x 900
v² = 720
v = √720
v = 26.9 m/s
Therefore, the final speed of the apple would be 26.9 m/s.
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What is the Power (Watts) dissipated in a 25 Ohm circuit if it has 3.0 Amps of current?
The amount that the valve is open is reflected by the resistance in the faucet. The diameter of the opening* in the wire determines its resistance.
What is Power?
Work is the result of a force creating a displacement. The length of time that this force exerts to generate the displacement has nothing to do with work.
The pace of the process can vary from being completed quickly to taking a while. A rock climber, for instance, takes an unusually lengthy time to raise her body a few meters up the cliff's edge.
Power= I2R, 225 is the power. The amount that the valve is open is reflected by the resistance in the faucet. The diameter of the opening* in the wire determines its resistance.
Therefore, The amount that the valve is open is reflected by the resistance in the faucet. The diameter of the opening* in the wire determines its resistance.
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Circuits
Calculate the total Resistance, Current, and Power in the circuits
The total resistance of the circuit is 3 ohms.
The total current in the circuit is 4 A.
The power of the circuit is 48 W.
What is the total resistance of the circuit?
The total resistance of the circuit is calculated as follows;
1 / Rt = 1/R1 + 1/R2 + 1 / R3
1/Rt = 1/6 + 1/12 + 1/12
1/Rt = 0.3333
Rt = 3 ohms
The total current in the circuit is calculated as follows;
I = V / Rt
I = ( 12 ) / ( 3 )
I = 4 A
The power of the circuit is calculated as follows;
P = IV
P = ( 4 x 12 )
P = 48 W
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Gas in a container is at a pressure of 1.6 x 10^5 Pa and a volume of 4.0 m^3. What is the work done by the gas if it expands at a constant pressure to twice its initial volume?
Answer: W = 6.4 x 10^5
Explanation: W = P x AV +(1.6x10^5 PA)(4M)
W = 6.4 x 10^5
A 100 kg person pushes a box up a ramp at constant speed. The mass of the box is 30 kg, the coefficient of kinetic friction between the box and the ramp is 0.2, and the ramp is inclined 25 degrees above the horizontal. The person (new at pushing boxes up ramps) pushes purely in the horizontal direction. HINT: you must draw complete FBDs to receive full credit. a) Find an expression for the magnitude of the normal force on the box due to the ramp. This answer should be left in variables, not numbers. b) Find the magnitude of the force on the box due to the person. c) Each step the person takes requires a force of static friction so that she does not slip. Find the magnitude of the force of static friction on the person due to the ramp. d) Find the minimum coefficient of static friction between the person's shoes and the ramp, so that this feat is possible.
Since cos(25) is approximately 0.906, the minimum coefficient of static friction is μs >= 0.906
How find the normal force?a) Substituting this into the previous equation, we get:
N - mg * sin(25) = μk * N
Solving for N, we get:
N = mg * sin(25) / (1 - μk)
b) Since the force applied by the person is horizontal, the horizontal component of the normal force must balance it. Therefore,
F = N * cos(25)
Solving for N, we get:
N = F / cos(25) = 0 / cos(25) = 0 N
c) Since the person is not slipping, the friction force must balance the horizontal component of the gravitational force. Therefore,
fs = μs * N
where μs is the coefficient of static friction.
Since N = mg * cos(25),
fs = μs * mg * cos(25)
d)Since cos(25) is approximately 0.906, the minimum coefficient of static friction is
μs >= 0.906
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What is the volume, in m3, of 10,000 kg of CO2 at 20 ∘C and 1.0atm pressure?
Answer:
pv=nrt
Explanation:
pv=nrt
A student runs an experiment in which a block of known mass is moving across a horizontal table in an xy-coordinate plane. As the block reaches the origin of the coordinate system, the block explodes into two pieces of masses m1 and m2. During the experiment, the velocity of the block 1.0 second before the explosion and the velocity of the two pieces 1.0 second after the explosion are measured using a motion sensor. Conservation of momentum is applied using the masses of the two pieces. However, when the velocity of the piece of mass m2 is calculated, the measured value is 10% less than the calculated value. Which of the following statements best explains the difference in the calculated and measured velocity?
Responses
Answer:
The difference in the calculated and measured velocity could be due to the fact that the motion sensor may not have been able to accurately detect the velocity of the block 1.0 second before the explosion due to the sudden change in momentum caused by the explosion. Additionally, the motion sensor may not have been able to accurately detect the velocity of the two pieces 1.0 second after the explosion due to the sudden change in momentum caused by the explosion. This could explain the 10% discrepancy between the calculated and measured velocity.
Explanation:
Energy is transmitted from the sun to Earth primarily through radiation, which, like gravitational force, obeys an inverse-square law. Show that the energy input at aphelion is 92% the intensity at perihelion. Does that difference explain the difference in surface temperature from winter to summer? Make a claim and argue from evidence.
The energy input at aphelion (farthest from the sun) is 92% of the intensity at perihelion (closest to the sun) because of the inverse-square law, which states that the intensity of radiation decreases with the square of the distance from the source.
How is the difference in surface temperature explained?However, the difference in energy input does not solely explain the difference in surface temperature from winter to summer.
Other factors, such as the Earth's axial tilt, atmospheric composition, and cloud cover also play a role in determining the surface temperature.
Evidence from climate models and observations indicate that changes in these factors, especially changes in the number of greenhouse gases in the atmosphere, can have a significant impact on global temperature patterns.
In conclusion, while the inverse-square law affects the intensity of solar radiation, it is not the sole factor in determining surface temperature, and the role of other factors must be considered to fully understand seasonal and climatic variations.
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4. The Orion Nebula is shown in the Figure below. How long has the light been
traveling from this object before it arrives on Earth? The distance to Orion nebula is
1344ly.
Light has been traveling from this object before it arrives on earth for 1,500 light-years.
Why is Orion Nebula so bright?
The Orion Nebula, a colourful cloud of gas and cosmic dust, is a star-forming region. The nebula has "a rather brilliant apparent brightness because it is the nearest massive star-forming zone to Earth.
Why was Orion given that name?
The ancient Egyptians believed that the stars in the belt represented the spot where the spirit of the god Osiris would ultimately dwell. To the Arabs, the constellation appeared to be enormous. The mythological Greek hunter Orion is the subject of the constellation's name.
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A 20×10⁹charge is moved between two points A andB that are 30mm apart and have an electric potential difference of 600v between them. calculate a) the electric field strength between A and B b)the work done on the charge.
The electric field strength between A and B 90x20=1800.
What is Electric field?The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also known as an E-field. It can also refer to a system of charged particles' physical field.
Electric charges and time-varying electric currents are the building blocks of electric fields. The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields.
Electrical technology makes use of electric fields, which are significant in many branches of physics. For instance, in atomic physics and chemistry, the electric field acts as an attractive force to hold atoms' atomic nuclei and electrons together.
Therefore, The electric field strength between A and B 90x20=1800.
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In your circuit toolbox, you have only three resistors ( 1=60 Ω
, 2=30 Ω
, 3=20 Ω
) and some switches that can be open or closed. Construct a circuit, filling in all four boxes, such that the equivalent resistance between A and B is 80 Ω
.
The required circuit can be constructed by arranging resistor 1 (60 Ω), resistor 3 (20Ω) in one arm and resistor 2 (30 Ω) and open switch in other arm.
What is resistor?A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.
When the circuit be constructed by arranging resistor 1 (60 Ω), resistor 3 (20Ω) in one arm and resistor 2 (30 Ω) and open switch in other arm, the equivalent resistor is = (60 + 20) Ω = 80 Ω.
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[tex]\huge\bold{Question}[/tex]
An orange of mass 125 g falls from a branch to the ground 3.50 m below. (a) Relative to the ground, what is the gravitational potential energy of the orange on the branch? On the ground? (b) Relative to the branch, what is the gravitational potential energy of the orange on the branch? On the ground? J (c) During the orange's fall, what is its change in gravitational potential energy relative to the ground? Relative to the branch?
(a) Relative to the ground, the gravitational potential energy of the orange on the branch is 4.29 J and on ground is 0 J.
(b) ) Relative to the branch, the gravitational potential energy of the orange on the branch is 0 J and on ground is 4.29 J.
(c) The change in potential energy relative to the ground is -4.29 J and relative to the branch is 0 J.
What is the gravitational potential energy?
Relative to the ground, the gravitational potential energy of the orange on the branch is calculated as follows;
P.E = mgh
where;
m is the mass of the orangeh is the height of the branch above the groundg is acceleration due to gravityP.E = 0.125 kg x 9.8 m/s² x 3.5
P.E = 4.29 J
The gravitational potential energy of the orange on the ground is calculated as follows;
P.E = mgh
P.E = m x g x 0 m
P.E = 0 J
The change in potential energy = final potential energy - initial potential energy
change in potential energy = 0 J - 4.29 J = - 4.29 J
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In a physics lab, 0.500-kg cart (Cart A) moving rightward with a speed of 92.8 cm/s collides with a 1.50-kg cart (Cart B) moving leftward with a speed of 21.6 cm/s. The two carts stick together and move as a single object after the collision. Determine the post-collision speed of the two carts.
The speed of the two carts after the collision is 10 m/s.
What is momentum?
Momentum is a measure of an object's motion and is defined as the product of an object's mass and velocity. The SI unit of momentum is kilogram-meters per second (kg m/s).
In physics, momentum is an important concept in the study of motion and is related to the forces acting on an object. According to Newton's second law of motion, the momentum of an object changes when a force is applied to the object. The magnitude of the change in momentum is proportional to the size of the force and the time over which it is applied.
In collisions and other interactions between objects, the total momentum of the system is conserved, meaning that the total momentum before the interaction is equal to the total momentum after the interaction.
initial momentum = mA · vA1 + mB · vB1
final momentum = (mA + mB) · vAB2
Where:
mA = mass of cart A = 0.500 kg
vA1 = velocity of cart A before the collision = 100 m/s
mB = mass of cart B = 1.50 kg.
vB1 = velocity of cart B before the collision = - 20 m/s
vAB2 = velocity of the carts that move as a single object = unknown.
(notice that we have considered leftward as negative direction)
Since the momentum of system remains constant:
initial momentum = final momentum
mA · vA1 + mB · vB1 = (mA + mB) · vAB2
Solving for vAB2:
(mA · vA1 + mB · vB1) / (mA + mB) = vAB2
(0.500 kg · 100 m/s - 1.50 kg · 20 m/s) / (0.500 kg + 1.50 kg) = vAB2
vAB2 = 10 m/s
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The symbols for speed, distance, and elapsed time are, respectively. * Ax and At. The MKS units of speed, distance, and elapsed time are, respectively, meters per second, meters and seconds. Which of the following equations is incorrect by unit analysis?
The incorrect equation among them is: Δt = v/Δx.
What is physical quantity?A physical quantity is a property of a substance or system that can be measured and quantified. The algebraic multiplication of a "Numerical value" and a "Unit" can be used to express a physical quantity as a value.
Unit of distance Δx is meter.
Unit of elapsed time Δt is second.
Unit of speed v is meter per second.
Hence, the possible equations among them are:
Δx = vΔt
v = Δx/Δt
Δt = Δx/v
1/Δt = v/Δx
But the incorrect equation among them is:
Δt = v/Δx.
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Your question is incomplete, but most probably the options of the question are:
Δx = vΔt
v = Δx/Δt
Δt = Δx/v
1/Δt = v/Δx
Δt = v/Δx.
A Martian is on Mars, where the acceleration
gravitational is gMars=0.38gEarth, the ball oscillates with a period of 1.5s when it swings like a pendulum. On a trip, the Martian finds himself on a planet where the ball oscillates with a period of 0.92s.
What planet is it on?
First we must find the length of the pendulum:
The planet that a Martian is on is Earth.
The formula to calculate the period from a simple pendulum
T = 2π × √(L ÷ g)
T ÷ 2π = √(L ÷ g)
(T ÷ 2π)² = L ÷ g
T² ÷ 4π² = L ÷ g
L = (T² × g) ÷ 4π²
the length of the pendulum (m)π = 3.14g = the acceleration due to gravity (m/s²)T = period (s)Compare from pendulum on Mars and another planet
g Earth = gg Mars = g₁ = 0.38 gT on Mars = T₁ = 1.5 sT on another planet = 0.92 sAssume the same pendulum on Mars is the same as the pendulum on another planet. Then the length of the two pendulums is the same.L₁ = L₂
(T₁² × g₁) ÷ 4π² = (T₂² × g₂) ÷ 4π²
T₁² × g₁ = T₂² × g₂
1.5² × 0.38g = 0.92² × g₂
2.25 × 0.38g = 0.8464 × g₂
0.855g = 0.8464 × g₂
g₂ = 0.855g ÷ 0.8464
g₂ = 1.0101g
g₂ = 1.0101 × 9.8
g₂ = 9.89
The other planet is Earth.
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to what temp must 0.588 moles of ammonia gas have to be heated in a 15.0 L container in order for it to exert a pressure of 3,50 kPa?
According to the ideal gas law, 0.588 moles of NH3 gas in a 15.0 L container must be heated to a temperature of 1088.85 K or 815.85°C in order for it to impose a pressure of 3.50 atm.
What is Ideal gas law?Real gases are simplified into ideal gases to make them easier to understand. It is believed to be made up of point particles that move randomly and independently.
Additionally, it is believed that perfect gas molecules by themselves have no volume.
Three state variables—absolute pressure (P), volume (V), and absolute temperature—define an ideal gas (T). The ideal gas law, an equation that relates them, is based on their relationship.
Therefore, According to the ideal gas law, 0.588 moles of NH3 gas in a 15.0 L container must be heated to a temperature of 1088.85 K or 815.85°C in order for it to impose a pressure of 3.50 atm.
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A 25-kg chandelier hangs from a ceiling on a vertical 4.0-m-long wire.
Part A: What horizontal force would be necessary to displace its position 0.16 m to one side?
Express your answer to two significant figures and include the appropriate units.
Part B: What will be the tension in the wire?
Express your answer to two significant figures and include the appropriate units.
The horizontal force required to displace the chandelier 0.16 m is equal to the restoring force divided by the displacement is 1500N
What is the horizontal force?A. To displace the position of the chandelier 0.16 m to one side, a horizontal force is necessary to balance the restoring force due to the tension in the wire. This restoring force can be calculated as the weight of the chandelier times the acceleration due to gravity:
Frest = W * g = 25 kg * 9.8 m/s^2 = 245 N
The horizontal force required to displace the chandelier 0.16 m is equal to the restoring force divided by the displacement:
Fhorizontal = Frest / (0.16 m) = 245 N / 0.16 m = 1531 N
Rounding to two significant figures, the answer is:
Fhorizontal = 1500 N
B. The tension in the wire can be calculated as the sum of the forces in the vertical direction, which is equal to the weight of the chandelier:
Tension = W = 25 kg * 9.8 m/s^2 = 245 N
Rounding to two significant figures, the answer is:
Tension = 250 N
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need help please thanks
1. The percentage of incoming solar radiation which reflected and scattered back into space is 30%
2. Yes, solar radiation that is reflected and scattered heat the objects it strikes does.
3. The percentage of incoming solar radiation is 19% absorbed by clouds and gasses in the atmosphere.
4. 51% percentage of incoming solar radiation passes through the atmosphere and is absorbed by the Earth's surface.
5. No. The most transmit or absorb is Earth's surface.
About solar radiationIn a climate system, all processes start from radiant energy coming from the sun onto the surface of the atmosphere (air). Furthermore, this energy is forwarded to the earth's surface where along the way some of it is reflected back into space. Part of it is absorbed by the air and the rest is transmitted to the earth's surface.
Radiation that can reach the earth's surface can eventually heat the earth's surface, evaporate water, melt snow and heat the ground. The changed energy is also sent back into space in the form of radiation.
Variations in the amount of radiation received by the earth's surface and variations in the interaction between the earth and the atmosphere can cause spatial and time variations of energy changes which ultimately determine the climate of a place.
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15 6. Acar moves with a velocity of 30m/s is accelerated in 6sec find final velocity and the distance during that time
Explanation:
To find the final velocity and distance traveled during the acceleration, we can use the equations of motion:
v = u + at, where v is the final velocity, u is the initial velocity (30 m/s), a is the acceleration, and t is the time (6 s)
v = 30 m/s + a x 6 s
d = ut + 0.5at^2, where d is the distance traveled
d = 30 m/s x 6 s + 0.5 x a x (6 s)^2
Since acceleration (a) is not given, we can use one equation to solve for it and substitute into the other:
v = 30 m/s + a x 6 s
a = (v - 30 m/s) / 6 s
Substitute this into the second equation to find the distance:
d = 30 m/s x 6 s + 0.5 x (v - 30 m/s) / 6 s x (6 s)^2
So, we can find the final velocity and distance traveled once the acceleration (a) is known.
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V.
Answer:
E+V= Weird
Explanation:
If you subtract "e" repeating from E and V you'll get the equation above.
The table to the right shows the time it takes three trucks to go from 0 to 60 km/h
The quantities that can be compared from four cars is the average acceleration. Answer A.
The question isn't complete. A similar question is in the attachment. When a truck or a car increases its velocity over time, it means it experiences acceleration. The vehicle moves in a non-uniform motion. The formula in non-uniform motion
v = u + atv² = u² + 2add = ut + 0.5at²where
t = time (s)d = distance (m)u = initial velocity (m/s)v = final velocity (m/s)a = acceleration (m/s²)The information in the question that four cars have a different time to travel but have the same
u = 0 km/h = 0 m/sv = 60 km/hLearn more about non-uniform motion here: brainly.com/question/30392559
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Joe went 4.2 km/h south and then went 4.1 kw/h west. From start to finish, joe went 5.9 kw/h southwest. 1. What are the instantaneous velocities? 2.what is the average velocity?
(1) The instantaneous velocities are 4.2 km/h south and 4.1 km/h west
(2) The average velocity of Joe is 5.9 km/h southwest.
What are the instantaneous velocities?
The instantaneous velocities are the velocities of Joe at any given time period and it is calculated as follows;
v (1 ) = 4.2 km/h south
v ( 2 ) = 4.1 km/h west
The average velocity of Joe is calculated from the ratio of the total displacement to total time of motion.
v (avg) = ( total displacement ) / ( total time of motion )
v (avg) = 5.9 km/h southwest
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