Given:
The quadratic equation is
[tex]-2x^2-y+10x-7=0[/tex]
To find:
The vertex of the given quadratic equation.
Solution:
If a quadratic function is [tex]f(x)=ax^2+bx+c[/tex], then
[tex]Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)[/tex]
We have,
[tex]-2x^2-y+10x-7=0[/tex]
It can be written as
[tex]-2x^2+10x-7=y[/tex]
[tex]y=-2x^2+10x-7[/tex] ...(i)
Here, [tex]a=-2,b=10,c=-7[/tex].
[tex]\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}[/tex]
[tex]\dfrac{-b}{2a}=\dfrac{-10}{-4}[/tex]
[tex]\dfrac{-b}{2a}=\dfrac{5}{2}[/tex]
Putting [tex]x=\dfrac{5}{2}[/tex] in (i), we get
[tex]y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7[/tex]
[tex]y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7[/tex]
[tex]y=\dfrac{-50}{4}+25-7[/tex]
[tex]y=\dfrac{-25}{2}+18[/tex]
On further simplification, we get
[tex]y=\dfrac{-25+36}{2}[/tex]
[tex]y=\dfrac{11}{2}[/tex]
So, the vertex of the given quadratic equation is [tex]\left(\dfrac{5}{2},\dfrac{11}{2}\right)[/tex].
Therefore, the correct option is A.
A population has a mean of 125 and a standard deviation of 16. A sample of 64 observations will be taken. The probability that the sample mean will be between 122.4 and 126.1 is
Answer:
0.61204
Step-by-step explanation:
μ = 125 ; σ = 16 ; n = 64
Probability that mean will be between 122.4 and 126.1
Z = (x - μ) / σ/sqrt(n)
x = 122.4
Z = (122.4 - 125) ÷ 16/sqrt(64)
Z = - 2.6 ÷ 2 = - 1.3
P(Z < - 1.3) = 0.0968
x = 126.1
Z = (126.1 - 125) ÷ 16/sqrt(64)
Z = 1.1 ÷ 2 = 0.55
P(Z < 0.55) = 0.70884
P(Z < 0.55) - P(Z < - 1.3)
0.70884 - 0.0968
= 0.61204
3.5 liters into kiloliters
Answer:
.0035 kiloliters
Step-by-step explanation:
1 liter = 0.001 kiloliters
3.5 liters x .001 = .0035 kiloliters
or just use calculator bro
Solve the following question:
Q1: A family has booked a long holiday in Skragness, where the probability of rain on any particular day is 0.3.
a) Find the probability that the first day to rain will be on the third day of their holiday.
b) Find the probability chance that it will not rain for the first 2 weeks of their holiday.
[hint: X~Geo(0.3) a) P(X=__), b) P(X<__)]
Q2: If G~B(42, 7/12)
a) Find E(G) and Var(G) giving your answer as a fraction or mixed number
b*) Find P(G=20) correct to 3 significant figures.
Answer is in the photo. I can only upload it to a file hosting service. link below!
tinyurl.com/wpazsebu
$200 in a savings account. The interest rate is 3%. Determine the exact amount of money that will be in the
account after the following amounts of time.
a) 2 months: b) 6 months:
c) 11 months: d) 1 year:
e) 2.5 years: f) 5 years:
Answer:
what
Step-by-step explanation:
Find y to the nearest hundredths place
Answer:
I cant see the picture
Step-by-step explanation:
Please solve the following. Solve for X. PLEASE HELP
Answer:
8
Step-by-step explanation:
(x+4)/x=24/16
24x=16x+64
8x=64
x=8
The manager of an online shop wants to determine whether the mean length of calling time of its customers is significantly less than 9 minutes. A random sample of 28 customers was taken. The average length of calling time in the sample was 8.1 minutes with a standard deviation of 2.9 minutes. At a 0.05 level of significance, it can be concluded that the mean of the population is:
Answer:
Step-by-step explanation:
Other Academics
4: Assessment Form A
Henry sells rings for $8 each. His expenses are $1.50 per ring, plus $91 for supplies. How many rings does he need to sell for his revenue to equal his
expenses?
A 140
B. 9
C. 10
D. 14
Which graph best represents f(x)=6(3)x. PLEASE
Answer:
Hi! You have not shown any options, but your graph should look like this
Step-by-step explanation:
I need help please.
Answer:
B
Step-by-step explanation:
What is the slope of a line perpendicular to a line that contains the points (-8,-4) and (0,-8)
Answer:
I hope some of these help (examples)
Step-by-step explanation:
Line AB contains points A (1, 2) and B (−2, 6) The slope of line AB is
a)zero
b)undefined
c)positive
d)negative
The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?
Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is
Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (−2, 2). Lines QR and ST are
The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).
The equation of line CD is y = −2x − 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).
Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (−2, 2). Lines QR and ST are
parallel because the product of the slopes is −1
perpendicular because the product of the slopes is −1
parallel because the slopes are the same
perpendicular because the slopes are the same
Question 2
(06.02 LC)
The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD?
1 over 2
2
negative 1 over 2
−2
Question 3
(06.02 LC)
Line CD contains points A (4, 6) and B (−2, 6). The slope of line CD is
zero
undefined
positive
negative
Question 4
(06.02 MC)
The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).
y = 2x + 16
y = negative 1 over 2x + 17 over 2
y = − 1 over 2x + 7 over 2
y = 2x − 4
Question 5
(06.02 MC)
The equation of line CD is y = −2x − 2. Write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5).
y = −2x + 13
y = negative 1 over 2x + 7
y = 1 over 2x + 3
y = − 2x − 3
On the first question, the formula would be m=\frac{y2-y1}{x2-x1} and the value we got is -4/3, so D.
On the second quesiton, the slope in the given equation of the line is -2, its negative reciprocal is 1/2, so A.
On the third question, use the slope formula above and the value you would get is zero, so A.
On the fourth question, the equation of the line perpendicular to line QR is y=2x+b, to find b, just substitute the point (5,6) to the equation. That would make b = -4. the final equation of the line would be: y=2x-4, so D.
On the fifth question, the equation of the line parallel to line QR is y = -2x + b. substitute the point (4,5) to the equation, and you'll get b = 13. the final equation of the line would be y=-2x+13, so A.
D,A,A,D,A
1) Determine the slope of the line that is perpendicular to the equation below.
y = -3x + 4
Type your answer as a reduced fraction, if necessary, like this: 3/4
2) Which line is parallel to the line with this equation?
3x – 4y = 24
A) 8y-6x=32
B) 3x-5y=25
C) y=-3/4x -6
D) y+3 = 3(x-4)
3) Determine which equation is in slope-intercept form for the line that passes through (5, 0) and is perpendicular to the line below.
y = -5/2x + 6
A) y=-2/5x - 2
B) y=5/2x+2
C) y=5/2x-2
D) y=2/5x-2
4) Line 1 contains the points (6, -5) and (2, 7). Which of the given pairs of coordinates could be contained by Line 2 if Line 1 is parallel to Line 2?
HINT: Remember that two parallel lines share NO points.
A) (2,7) and (11,10)
B) (6,-5) and (-1, 3)
C) (9,8) and (6, 9)
D) (5,6) and (9, -6)
5) What value should replace the "?" to make the equations parallel?
Type your answer as a reduced fraction, using the "/" symbol to separate the numerator and denominator, like this: 2/5
y=5/3 x - 8
y=? x + 9
6)Determine whether the pair of lines is parallel, perpendicular, or neither.
y = 7x and y – 28 = 7(x – 4)
A) parallel
B) perpendicular
C) Neither
1) m=-2
2) C) y=-3/4x -6
3) D) y=2/5x-2
I hope this helps:)
4. Determine the volume of the eraser below. 3 in 1.5 in eraser 1 in
Answer:
volume = 4.5 in³
Step-by-step explanation:
V = L x W x H
V = 3 x 1.5 x 1 = 4.5
Sale 10 % off During the sale, Susan pays $603 for a wedding cake. What was the original price?
Answer:
$670
Step-by-step explanation:
1/10x + 603 = x
x -10x = -6030
-9x = -6030
x = 670
please help ill give brainliest
A catering company needs 8.75 Ib of shrimp for a small party. They buy 3 2/3 Ib of jumbo shrimp, 2 5/8 Ib of medium-sized shrimp, and some mini-shrimp. How many pounds of mini -shrimp do they buy?
Need help ASAP!!!!!!!!!!
Answer:
the last two
Step-by-step explanation:
there are 65 cookies in a jar. the probability of randomly choosing an oatmeal cookie from the jar is 40% how many of the cookies are oatmeal cookies pls help
Answer:
25
Step-by-step explanation:
Yolanda created a scatter plot of the relationship between the number of times she visited different friends each month, y, and the distance in miles of the friends from her home, x. She calculated the equation of the trend line to be y = −3.5x + 20. Use this information to predict the number of times in one month Yolanda would visit a friend who is 4 miles from her home.
Answer:
6 times
Step-by-step explanation:
y = −3.5x + 20 ; x = 4
y = -3.5(4) + 20
y = -14 + 20
y = 6
find the area of the figure use 3.14 for pie
Dominick and Janelle are working to simplify the expression 2c + 4 + c + 6. Janelle simplifies her expression to 2c + 10, while Dominick simplifies his to 3c + 10.
Answer:
3c + 10
Step-by-step explanation:
1c = c
2c + 4 + c + 6
(combine like terms)
3c + 10
Answer:
Dominic is right
Step-by-step explanation:
equation:
2c + 4 + c + 6
combine like terms:
2c + c = 3c
4 + 6 = 10
new equation:
3c + 10
PLSSS HELP ASAPPPPPP
it will be A.25
Step-by-step explanation:
hope its right
evaluate the following definite integral
Answer:
[tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}[/tex]
General Formulas and Concepts:
Symbols
e (Euler's number) ≈ 2.71828Algebra I
Exponential Rule [Multiplying]: [tex]\displaystyle b^m \cdot b^n = b^{m + n}[/tex]Calculus
Differentiation
DerivativesDerivative NotationBasic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Integration
IntegralsDefinite IntegralsIntegration Constant CIntegration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
U-Substitution
U-SolveIntegration by Parts: [tex]\displaystyle \int {u} \, dv = uv - \int {v} \, du[/tex]
[IBP] LIPET: Logs, inverses, Polynomials, Exponentials, TrigStep-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx[/tex]
Step 2: Integrate Pt. 1
[Integrand] Rewrite [Exponential Rule - Multiplying]: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \int\limits^1_0 {x^5e^{x^3}e} \, dx[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = e\int\limits^1_0 {x^5e^{x^3}} \, dx[/tex]Step 3: Integrate Pt. 2
Identify variables for u-solve.
Set u: [tex]\displaystyle u = x^3[/tex][u] Differentiate [Basic Power Rule]: [tex]\displaystyle du = 3x^2 \ dx[/tex][u] Rewrite: [tex]\displaystyle x = \sqrt[3]{u}[/tex][du] Rewrite: [tex]\displaystyle dx = \frac{1}{3x^2} \ du[/tex]Step 4: Integrate Pt. 3
[Integral] U-Solve: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = e\int\limits^1_0 {x^5e^{(\sqrt[3]{u})^3}\frac{1}{3x^2}} \, du[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}\int\limits^1_0 {x^5e^{(\sqrt[3]{u})^3}\frac{1}{x^2}} \, du[/tex][Integral] Simplify: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}\int\limits^1_0 {x^3e^u} \, du[/tex][Integrand] U-Solve: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}\int\limits^1_0 {ue^u} \, du[/tex]Step 5: integrate Pt. 4
Identify variables for integration by parts using LIPET.
Set u: [tex]\displaystyle u = u[/tex][u] Differentiate [Basic Power Rule]: [tex]\displaystyle du = du[/tex]Set dv: [tex]\displaystyle dv = e^u \ du[/tex][dv] Exponential Integration: [tex]\displaystyle v = e^u[/tex]Step 6: Integrate Pt. 5
[Integral] Integration by Parts: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3} \bigg[ ue^u \bigg| \limits^1_0 - \int\limits^1_0 {e^u} \, du \bigg][/tex][Integral] Exponential Integration: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3} \bigg[ ue^u \bigg| \limits^1_0 - e^u \bigg| \limits^1_0 \bigg][/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}[ e - e ][/tex]Simplify: [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
what is x in 5x - ((2x-1)÷2) = 5
Answer:
5x - ((2x-1)÷2) = 5-----(1)
(1) multiply by 2;
2 *(5x - ((2x-1)÷2) = 5)
10x - (2x-1) = 10
10x - 2x + 1 = 10
8x + 1 =10
8x = 10-1
x=9 /8
Step-by-step explanation:
Answer:
x = 9/8
Step-by-step explanation:
5x - ((2x - 1) ÷ 2) = 5
2 × (5x - ((2x - 1) ÷ 2) = 5
10x - (2x-1) = 10
10x - 2x + 1 = 10
8x + 1 = 10
8x + 1 - 1 = 10 - 1
8x = 10 - 1
8x = 9
8x ÷ 8 = 9 ÷ 8
x = 9 ÷ 8
x = 9/8 or 1 and 1/8
Expand the following expression −7(5x−8)
Select one:
5x+56
35x−8
56−35x
21x
What is the range of the data set? *
2 points
53, 39, 123, 59, 25, 79, 88
84
53
123
98
25
Answer:
25
Step-by-step explanation:
range = largest value - smallest value (123-25)
there 2 parts to the question
Answer:
a) ∠PNQ=40°
b) ∠POQ=80°
Explanation:
The Inscribed Angle Theorem proves that an inscribed angle is half of the intercepted arc length. From that information, we can determine the angle of PNQ with ∠PNQ=[tex]\frac{1}{2}[/tex]QP or ∠PNQ=[tex]\frac{1}{2}[/tex](80). Multiply those two to get 40. Because the central angle is equal to the measure of its intercepted arc length. So, we know that ∠POQ is 80°.
Use the distributive property to write an equivalent expression. 4(2x+3)
Answer:
20x
Step-by-step explanation:
4(2x+3)
4(5x)
4x5x
20x
I need help please.
Answer:
its b
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Because it is invert.
The parent function is given by f(x) = x^2
Choose the BEST description for f(x - 3)+2.
Maximize −4x + 5y + 70 subject to the constraints:
2x + y ≤ 8
x + 3y ≥ 5
x + y ≤ 6
x ≥ 0,
y ≥ 0
a. Fix any constraints, as needed, and then convert the linear programming problem into a system of linear equations.
b. Give a fully labeled initial tableau, and circle the pivot element.
Answer:
Step-by-step explanation:
[tex]\text{To maximize -4x + 5y + 70 subject to } \\ \\ 2x + y \le 8 --- (1) \\ \\ x + 3y \ge 5 --- (2) \\ \\ x + y \le 6----(3) \\ \\ x \ge 0, y \ge 0[/tex]
[tex]\text{From above equationn (1)} : 2x + y = 8 \\ \\ \text{Divide boths sides by 8} \\ \\ \dfrac{2x}{8} + \dfrac{y}{8} = \dfrac{8}{8}[/tex]
[tex]\dfrac{x}{4} + \dfrac{y}{8} = 1 \\ \\ x = 4; y = 8[/tex]
[tex]\text{From above equationn (2)} : x + 3y = 5 \\ \\ \text{Divide boths sides by 5} \\ \\ \dfrac{x}{5} + \dfrac{3y}{5} = \dfrac{5}{5} \\ \\ x = 5; \ y = 1.66[/tex]
[tex]\text{From above equation (3)} : x + y = 6 \\ \\ \text{Divide boths sides by 5} \\ \\ \dfrac{x}{6} + \dfrac{y}{6} = \dfrac{6}{6} \\ \\ x = 6; \ y = 6[/tex]
[tex]\text{From the image attached below, we can see the representation in the graph}[/tex]
- [tex]\text{Now from equation (1) ad (III)} \\ \\ 2x + y = 8 \\ \\ x+y = 6[/tex]
[tex]x[/tex] [tex]= 2[/tex]
[tex]From : x + y = 6 \\ \\ 2 + y = 6 \\ \\ y = 6-2 \\ \\ y =4[/tex]
[tex]\text{From equation (1) and (II) } \\ \\ \ \ 2x + y = 8 \\ - \\ \ \ x + 3y = 5 \\ \\[/tex]
[tex]-5y = -2 \\ \\ y = \dfrac{2}{5} \ o r\ 0.4 \\ \\ From : 2x+ y = 8 \\ \\ 2x = 8 - \dfrac{2}{5} \\ \\ x = \dfrac{ 8 - \dfrac{2}{5} }{2} \\ \\ x = 3.8[/tex]