general solution
4sin^x+9 cosx-6=0​

Answer:

B

Step-by-step explanation:

Option B is correct, 4 and 3/10 hours  will Mrs. Nygaard need to work over the weekend to finish grading the projects.

A fraction represents a part of a whole.

To find the total amount of time Mrs. Nygaard has available during the week to grade projects, we need to add up the hours for each day:

1 and three-fourths + 1 and one-half + 1 and one-fifth + 2 + 1 and one-fourth = 7 and five-tenths hours

This means that Mrs. Nygaard has 7.5 hours during the week to grade projects.

If she needs 12 hours to grade all the projects, then she will need to work for an additional:

12 - 7.5 = 4.5 hours over the weekend to finish grading the projects.

Therefore, 4 and 3/10 hours  required to Mrs. Nygaard need to work over the weekend to finish grading the projects.

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Answer:

Symmetric Property of Equality

Step-by-step explanation:

The symmetric property of equality is a simple property that says we can interchange the sides of an equation without changing the truth-value of the equation. That is, if a = b, then b = a. Each side of the equation can be thought of as the mirror image of the other side.

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[tex] \sf Q) \: 19^{2} + 21^{2} = {?}[/tex]

[tex] \sf \to 19^{2} + 21^{2} [/tex]

[tex] \sf \to 361 + 441[/tex]

[tex] \sf \to 802[/tex] is the solution.

[tex]x = 2 \\ y = 7[/tex]

is the answer to:

[tex]y = 11 - 2x \\ 4x - 3y = - 13[/tex]

_________________________________________

[tex]x = 5 \\ y = 2[/tex]

is the answer to:

[tex]2x + y = 12 \\ x = 9 - 2y[/tex]

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[tex]x = 3 \\ y = 5[/tex]

is the answer to:

[tex]2x + y = 11 \\ x - 2y = - 7[/tex]

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[tex]x = 7 \\ y = 3[/tex]

is the answer to:

[tex]x + 3y = 16 \\ 2x - y = 11[/tex]

Answer:

[tex] \boxed{y = 2x\: – \: 5} [/tex]

Answer:

[see below]

Step-by-step explanation:

There are 100 cm in a meter.

9.56/100 = 0.0956

Hope this helps you.

(PS: You can mark the other user as Branliest)

Explanation:

The "given the customer ordered a cold drink" means we only focus on the bottom row of values. There are B = 8+12+5 = 25 people who ordered a cold drink. Of that total, A = 5 people ordered a cold large drink.

The probability we want is A/B = 5/25 = 1/5 = 0.20 = 20%

3(1/2x +4) = 2x +2

Use distributive property by multiply 3 by each term on the left side:

3/2x + 12 = 2x + 2

Subtract 12 from both sides:

3/2x = 2x -10

Subtract 2x from both sides:

-1/2x = -10

Multiply both sides by -2:

x = 20

Answer: x = 20

Answer:

1/3 fraction of whole paint is used by mark

Step-by-step explanation:

Mark used  1/2 out of 3/2 cans.

[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{3}{2} = \frac{1}{2}*\frac{2}{3}=\frac{1}{3}[/tex]

Answer:

hello!

where are you from ?

Step-by-step explanation:

option 4 is correct ...there is no constant ratio.

Answer:

2/12

Step-by-step explanation:

The answer is 2/12 because there are two dice, each with 6 sides and the probability on each dice is one sixth

Answer:

Step-by-step explanation:

-x/8=12+11=23

-x=23*8=184

x=-184

x=-184Answer:

Step-by-step explanation:

Answer: 24 square cm.

8*6=48

48/2=24

Answer:

24 cm^2

Step-by-step explanation:

(w*h)/2

Answer:

4,4,5,7,10

Step-by-step explanation:

this can be

4,4,5,7,10

5 is in the middle because 5 is median

4 appeared thrice cause it is the mode

and 10 is just there to give us our mean 6 because it is only 30/5 that gives 6 so we have to find 5 numbers whose sum gives 30

Answer:

The 5 numbers can be: 4, 4, 5, 8, 9.

Step-by-step explanation:

In 4, 4, 5, 8, 9.     5 is the median (The middle number).

The mode is 4 because 4 is the most repeated number.

(4+4+5+8+9)/5 is equal to 30/5 which equals 6. So, 6 is the mean.

Hope this helps! :)

Given:

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H,EF=4n-4,FG=3n+3, GH=2n+6[/tex]

To find:

The length of segment GH.

Solution:

Draw a figure according to the given information as shown below.

In quadrilateral EFGH, [tex]FG\parallel EH,\angleE\cong \angle H[/tex], it means the quadrilateral EFGH is an isosceles quadrilateral because base angles are equal.

Now, quadrilateral EFGH is an isosceles quadrilateral, so the sides EF and GH are equal.

[tex]EF=GH[/tex]

[tex]4n-4=2n+6[/tex]

[tex]4n-2n=4+6[/tex]

[tex]2n=10[/tex]

Divide both sides by 2.

[tex]n=\dfrac{10}{2}[/tex]

[tex]n=5[/tex]

Now,

[tex]GH=2n+6[/tex]

[tex]GH=2(5)+6[/tex]

[tex]GH=10+6[/tex]

[tex]GH=16[/tex]

Therefore, the correct option is C.

Answer:

the answer is C

Step-by-step explanation:

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Answer:

See below

Step-by-step explanation:

Let side AB equal x. Since triangle ABC is equilateral, sides AB, BC, and Ac are all the same length, x. In any isosceles triangle(equilateral is a type of isosceles triangle) the median is the same as the altitude and angle bisector. This means we can say that AD is also a median. A median splits a side into two equal sections, so we can say BD = DC = x / 2. We are given that DC = CE, so we can also say CE = DC = x / 2. Now, we can use the pythagorean theorem to find the length of AD. So we get the equation:

AB^2 - BD^2 = AD^2

We have the values of AB and BD, so we can substitute them and solve for AD:

x^2 - (x/2)^2 = AD^2

x^2 - x^2 / 4 = AD^2

AD^2 = 3x^2 / 4

AD = x√3 / 2

DE is equal to the sum of DC and CE because of segment addition postulate, so we can say DE = DC + CE = x / 2 + x/ 2 = x. We can again use the pythagorean theorem to find the length of AE:

AD^2 + DE^2 = AE^2

(x√3 / 2)^2 + x^2 = AE^2

3x^2 / 4 + x^2 = AE^2

AE^2 = 7x^2 / 4

AE = x√7 / 2

Now, we know(from before) that AE squared is 7x^2 / 4. We can say EC squared is x^2 / 4 because EC is x / 2 and x / 2 squared is x^2 / 4. We can also notice that AE squared is 7 times EC squared because 7x^2 / 4 = 7 * x^2 / 4

Therefore, we can come to the conclusion AE^2 = 7 EC^2

Answer:

[tex]4x-8+4y[/tex]

Step-by-step explanation:

We are given that an expression

[tex]4(x-2+y)[/tex]

We have to find an equivalent expression using distributive property .

Distributive property:

[tex]a\cdot (b+c)=a\cdot b+a\cdot c[/tex]

Using the property

[tex]4(x-2+y)=4(x-2)+4\cdot y[/tex]

[tex]4(x-2+y)=4x+4(-2)+4y[/tex]

[tex]4(x-2+y)=4x-8+4y[/tex]

Hence, the equivalent expression  of the given expression is given  by

[tex]4x-8+4y[/tex]

Answer:

Get all the values of the histogram and put them in order:

For example 2,5,7,1,7,3  becomes 1,2,3,5,7,7 and then you get the middle number, which is in this case (3+5)/2=3.5

Then see which of the readings lie on 3.5.

Step-by-step explanation:

9514 1404 393

Explanation:

The histogram will have a count associated with each class. You may have to read the count from the vertical scale of the graph. If it is a histogram of relative frequencies, each class will have a fraction or percentage instead of a count.

Find the total of all counts. Determine what half that number is. If the total is odd, then round up to the nearest integer. This is the index number of the median value.

Add up the counts in the classes starting at one side of the graph, working toward the other side. (Left-to-right is the usual direction for doing this.) When you find the class that increases the total to a value equal or greater than the index number, this is the class that contains the median.

__

If the histogram is a relative frequency histogram, the class that brings the total to 50% is the one containing the median.

__

There may be cases where the total count is even, and the total of all of the classes up to a point is exactly equal to the index number you're looking for. In that case, the median is between that class and the next. Here's an example:

  class 1: count 3

  class 2: count 5

  class 3: count 4

  class 4: count 4

Total count: 3+5+4+4 = 16. Median index = 16/2 = 8

Total of classes 1 and 2 = 3+5 = 8. This means exactly half of the represented values are in class 2 or below, and half are in class 3 or above. If you had access to the actual data values, you would find the median as the average of the 8th and 9th data values (when they are sorted into increasing order). Here, the median might be estimated as the value halfway between the upper bound of class 2 and the lower bound of class 3.

__

2nd example

Consider the same histogram as above, but with a count of 3 in class 4. This brings the total count to 15, and the index of the median is 15/2 = 7.5, rounds to 8. Again, the 8th data value (median) is in class 2. There is no ambiguity in this case.

Answer:

no solution

Step-by-step explanation:

7x-12<7x-7

-13<-7

no solution

Answer:

There is an infinite amount, but let say that x is 10, then:

5*10

y=50

A point(10, 50)

Answer:

A) [tex]3x^{2} - x - 4[/tex]

B) [tex]-3x^{2} -4x -5[/tex]

Step-by-step explanation:

Answer:

I think it's c

Step-by-step explanation:

Well I believe that would mean that one coordinate would shift by five, c looks the most likely in this case.

I was actually surprised to see that statement A is correct

graphed around with desmos until I reconstructed f(x), then graphed f(x+4)

see screenshot

Answer:

14 units

Step-by-step explanation:

A = - 2, B = 12

Therefore,

d(A, B) = 12 - (-2) = 12 + 2 = 14 units

Answer:

Step-by-step explanation:

each die has numbers 1-6 thus there are 36 (6*6) possible outcomes

a) 18 of the 36 are even = 1/2 = .5 = 50%

b) (1,2) and (2,1) are the only 3's 2/36 = 1/18 = .055

c) there are 10 combos that are LESS THAN 6 (2,3,4,5)

   10/36 = .277 = 27.7%

2 3 4 5 6 7

3 4 5 6 7 8

4 5 6 7 8 9

5 6 7 8 9 10

6 7 8 9 10 11

7 8 9 10 11 12

[tex]\displaystyle\ a(n)=-3(2)^ {n-1}\Longrightarrow a(10)=-3(2)^{10-1}=2^9\cdot -3=\boxed{-1536}[/tex]

Answer:

8

Step-by-step explanation:

[tex] \frac{23}{2} = 11.5[/tex]

[tex]92 \div 11.5 = 8[/tex]

Answer:

A.

Step-by-step explanation:

A.-6r+6

Answer:

tan(9pi/12) = 0.041146549

Step-by-step explanation: