g Two long parallel wires are a center-to-center distance of 2.50 cm apart and carry equal anti-parallel currents of 2.70 A. Find the magnitude of the magnetic field at the point P which is equidistant from the wires. (R

Answers

Answer 1

Answer:

864 mT

Explanation:

The magnetic field due to a long straight wire B = μ₀i/2πR where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, i = current in wire, and R = distance from center of wire to point of magnetic field.

The magnitude of magnetic field due to the first wire carrying current i = 2.70 A at distance R which is mid-point between the wires is B = μ₀i/2πR.

Since the other wire also carries the same current at distance R, the magnitude of the magnetic field is B = μ₀i/2πR.

The resultant magnetic field at B is B' = B + B = 2B = 2(μ₀i/2πR) = μ₀i/πR

Now R = 2.50 cm/2 = 1.25 cm = 1.25 × 10⁻² m and i = 2.70 A.

Substituting these into B' = μ₀i/πR, we have

B' = 4π × 10⁻⁷ H/m × 2.70 A/π(1.25 × 10⁻² m)

B = 10.8/1.25 × 10⁻⁵ T

B = 8.64 × 10⁻⁵ T

B = 864 × 10⁻³ T

B = 864 mT

Answer 2

This question involves the concept of the magnetic field due to two current-carrying wires in the same direction, parallel to each other.

The magnitude of the magnetic field at the point P, which is equidistant from the wires is "8.64 x 10⁻⁵ T".

The following formula is used to find the magnetic field at the center distance between two parallel current-carrying wires in the same direction:

[tex]B = \frac{\mu_oI_1}{2\pi r}+\frac{\mu_oI_2}{2\pi r}\\\\But,\ I_1=I_2=I\\\\B = \frac{\mu_oI}{\pi r}[/tex]

where,

B = magnetic field at required point = ?

μ₀ = permeability of free space = 4π x 10⁻⁷ H/m

I = current = 2.7 A

r = distance from wires to the point = 2.5 cm/2 = 1.25 cm = 0.0125 m

Therefore,

[tex]B=\frac{(4\pi\ x\ 10^{-7}\ H/m)(2.7\ A)}{\pi (0.0125\ m)}[/tex]

B = 8.64 x 10⁻⁵ T

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G Two Long Parallel Wires Are A Center-to-center Distance Of 2.50 Cm Apart And Carry Equal Anti-parallel

Related Questions

if mass of an object is decreased to half and acting force is reduced by quarter the acceleration of its motion​

Answers

Answer:

See explanations below

Explanation:

According to Newtons second law of motion

F = mass * acceleration

F = ma

If mass of an object is decreased to half, then m₂ = 1/2 m

If acting force is reduced by quarter, then F₂ = 3/4 F

F₂ = m₂a₂

3/4F = 1/2m a₂

Divide both expressions

(3/4F)/F = (1/2m)a₂/ma

3/4 = 1/2a₂/a

3/4 = a₂/2a

4a₂ = 6a

2a₂ = 3a

a₂ = 3/2 a

Hence the acceleration of its motion will be one and a half of its original acceleration.

A group of particles of total mass 48 kg has a total kinetic energy of 320 J. The kinetic energy relative to the center of mass is 80 J. What is the speed of the center of mass?

Answers

K=.5mv^2 + relative Ke
320=.5(48)v^2+80
V=3.16

A train with proper length L has clocks at the front and back. A photon is fired from the front to the back. Working in the train frame, we can easily say that if the photon leaves the front of the train when a clock there reads zero, then it arrives at the back when a clock there reads L/c. Now consider this setup in the ground frame, where the train travels by at speed v. Rederive the above frame-independent result (namely, if the photon leaves the front of the train when a clock there reads zero, then it arrives at the back when a clock there reads L/c) by working only in the ground frame.

Answers

Explanation:

In train's rest frame, the speed of photon is [tex]c[/tex] and the proper length of the train is [tex]L[/tex]. The time taken by the photon to cross the train is [tex]t=\frac{L}{c}[/tex]

In ground frame, the speed of the photon is given as follows:

[tex]v_{x}=\frac{v_{x}+v}{1+\frac{v_{x} \cdot v}{c^{2}}}[/tex]

[tex]=\frac{c+v}{1+\frac{c v}{c^{2}}} \\=c[/tex]

The speed of light or photon remains same in every frame of reference.

Now, the speed of train is very less as compared to the speed of photon so that [tex]v<c[/tex] So that, [tex]\frac{v}{c} \ll 1[/tex]

The length contraction in the ground frame is given as follows:

[tex]L^{\prime}=L \sqrt{1-\frac{v^{2}}{c^{2}}}[/tex]

[tex]=L[/tex]

Time taken by the photon to travel the length of the train in ground frame is .

When we add or remove energy from a substance, what kind of changes can we observe? Can they happen at the same time ?

Answers

Answer:

When you add energy to a substance?

One change of state happens when you add energy to the substance. This change of state is called melting. By adding energy to the molecules in a solid the molecules begin to move quicker and can break away from the other molecules. The temperature at which a substance goes from a solid to a liquid is it melting point.

When you remove energy from a substance?

When a substance is heated, it gains thermal energy. Therefore, its particles move faster and its temperature rises. When a substance is cooled, it loses thermal energy, which causes its particles to move more slowly and its temperature to drop.

Explanation:

The addition of energy increases the kinetic energy of the particles, which reduces the intermolecular forces between the particles. Freezing occurs when a liquid becomes a solid and energy is released.

Atoms lose energy when they change from solid to liquid or gas and quid to gas.

Calculate the momentum of a 10 kg bowling ball rolling at 2m/s towards north.

Answers

Answer:

momentum=mass x velocity= 10 x 2 = 20kgm/s

an object is spun around in a circle of radius 2.0m with a period of 10.0s. what’s it’s velocity ?

Answers

Answer:

1.26 m/s

Explanation:

v=(2*pi*r)/T

v=(2*pi*2)/10

The  object is spun around in a circle of radius 2.0m with a period of 10.0s. Its velocity be 1.25 m/s.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Radius of the circle = 2.0 m.

Period of spinning of the object = 10.0 s.

So, angular velocity of the object be = 2π/10 radian/second.

So, magnitude of velocity be = radius × angular velocity

= 2.0 × 2π/10 m/s

= 1.25 m/s.

Hence, the magnitude of velocity of the object be 1.25 m/s.

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Write an equation to help Stacy find the gravitational force on an object if she knows the mass. In the equation, let W represent gravitational force, m represent mass, and g represent the ratio you found in part D. Test your equation using a set of values from the table to be sure it works.

Answers

Answer:

The last column of the table gives this relationship:

w/m = g

Rewrite the equation to solve for W: W = m × g.

For one washer, the table shows a mass of 0.6 kilograms, a force of 5.9 newtons, and an acceleration due to gravity of 9.8 N/kg. The equation works correctly for these values and for the other values in the table:

W = m × g = 0.6 kg × 9.8 N/kg    5.9 N.

Explanation:

This is the answer on Edmentum. :)

A students walks at a rate of 4 miles per hour to school. If she leaves her
house at 7:40am how long will it take her to travel 2 miles?

Answers

Answer:

30 minutes or 1/2 hour

she'll get there at 8:10am but that's not important

Explanation:

u can divide 4mph by two to find how long it would take her to travel 2 miles

she travels at 2 miles per 1/2 hour

hope this helps chu <3

Which of the following is true for the entropy of the universe?
A It is always decreasing.
B It is always increasing.
C It is always negative.
D It is always a constant.

Answers

Answer:

B It is always increasing.

Explanation:

In Physics, entropy can be defined as the tendency or ability of a substance to reach maximum disorder i.e to be randomly distributed.

This ultimately implies that, entropy is a thermodynamic quantity that measures the degree of maximum disorder or randomness of a system.

The S.I unit used for the measurement of the degree of maximum order or randomness of a system is Joules per Kelvin (JK¯¹). An example of entropy is the mixing of ideal gases.

Generally, the entropy in an irreversible process always increases and as such the change in entropy has a positive value.

Hence, the entropy of the universe is always increasing because its energy flow is considered to be in a downward direction rather than upward i.e from a hot region to a cold region; making the energy to be evenly distributed.

3
How does the electrical conductivity of metals
and metalloids change with an increase in
temperature?​

Answers

Answer:

In metals there are free electrons at normal temperature so when we increase temperature it resistivity gets increases,so conductivity decreases,while in semiconductor the electrons are not free so when we increase the temperature the covalent bonds begin to break and the electron becomes free so conductivity get.

Explanation:

A 50kg crate is being push on a horizontal floor at constant velocity. Given that the coefficient of kenitic friction between crate and floor is hk=0.1 . What is the push force?​

Answers

Answer:

  F = 49 N

Explanation:

For this exercise we must use Newton's second law. Let's set a reference frame with the x axis parallel to the floor.

As they indicate that the box is going at constant speed, its acceleration is zero

Y axis y

       N-W = 0

       N = mg

X axis

        F-fr = 0

        F = fr

the friction force has the formula

      fr = μ N

      fr = μ mg

we substitute

            F = μ m g

let's calculate

            F = 0.1 50 9.8

            F = 49 N

SIMPLE HARMONIC MOTION 1.0 Objective To study simple harmonic motion by observing the motion of a simple pendulum. 2.0 Simple harmonic motion Oscillatory motion is extremely common in nature. Examples include waves (water, sound, earthquake, etc.) and vibrations produced by musical instruments. If the oscillation is characterized by a constant frequency and amplitude (if the motion reproduces itself in a fixed time period T), then the motion is said to be "harmonic." If the oscillation can be described as a sinusoidal function of time and position, the motion is said to be "simple harmonic." Simple harmonic motion (SHM) occurs when for every applied force or torque, there is a restoring force or torque which is proportional to the displacement of the system from its equilibrium position. 2.0.1 Name two real-world examples of harmonic motion. (Hint: Southern California is known for what sort of natural disasters?)

Answers

Answer:

the waves in the sea,  leaves of the trees, cables in the bridges, pendulum clock

Explanation:

In nature there are many examples of simple harmonic motion, for example.

* The movement of the waves in the sea is an oscillation movement up and down

* The movement of the leaves of the trees when a wind blows and then stops, but the leaf and branches are oscillating

* The movement of the cables in the bridges, especially in the suspension bridges

* The movement of a pendulum clock

A strong electromagnet produces a uniform magnetic field of 1.60 T and a cross-sectional area of 0.200 m2. If we place a coil having 240 turns and a total resistance of 21.0 around the electromagnet and then we then smoothly reduced the current in the electromagnet until it reaches zero in 20.0 ms, what is the current induced in the coil

Answers

Answer:

the magnitude of the induced current is 182.86 A.

Explanation:

Given;

number of turns, N = 240 turns

cross sectional area of the loop, A = 0.2 m²

uniform magnetic field strength, B = 1.6 T

resistance of the loop, R = 21 ohms

time, Δt = 20.0 ms

The magnitude of the induced emf is calculated as;

[tex]emf = \frac{NA B}{t} \\\\emf = \frac{240 \times 0.2 \times 1.6}{20 \times 10^{-3}} \\\\emf = 3,840\ V[/tex]

The induced current in the loop is calculated as;

[tex]I = \frac{emf}{R} \\\\I = \frac{3840}{21} \\\\I= 182.86 \ A[/tex]

Therefore, the magnitude of the induced current is 182.86 A.

A light year is the amount of time it takes for light from the Sun to reach the Earth.
True
False

Answers

true! a light year is the amount of time it takes for light from the sun to reach Earth!

Match each term with the best description.
1. Compass
2. Magnetic dipoles
3. Magnetic fields
4. Magnetic field lines
5. Magnetic field vectors
6. Magnetometer
A. Configurations of north and south pole pairs
B. They never cross one another and have densities proportional to field strength
C. Their length is proportional to the strength of the field at their location
D. Trace out the direction and strength of the magnetic force
E. A very small bar magnet that can pivot freely in response to a magnetic force
F. A device used to measure the strength and direction of a magnetic field

Answers

Answer:

Explanation:

Compass: Configurations of north and south pole pairs.

Magnetic dipoles: A very small bar magnet that can pivot freely in response to a magnetic force.

Magnetic Field: Their length is proportional to the strength of the field at their location.

Magnetic Field Lines: They never cross one another and have densities proportional to field strength.

Magnetic Field Vectors: Trace out the direction and strength of the magnetic force.

Magnetometer: A device used to measure the strength and direction of a magnetic field.

When measuring espresso for a drink, which instrument would give the
greatest precision?

Answers

How many mL is an espresso?

One shot of espresso is generally about 30–50 ml (1–1.75 oz), and contains about 63 mg of caffeine (3). Important point: The “golden ratio” for espresso is this: a single shot is 30 to 44 mL (1 to 1.5 ounces) of water and 7 grams of coffee

3. Two bullets have masses of 0.003 kg and 0.006 kg, respectively. Both are fired with a speed of 40.0 m/s.
A. Which bullet has more kinetic energy?
B. When you double the mass, what happens to the kinetic energy?

Answers

Answer:

A. The bullet with 0.006kg has more energy

B. When the mass is doubled the kinetic energy increases

Explanation:

Kinetic energy increases when mass increases

kinetic energy increases when velocity increases

Fig 1 shows a pendulum of length L = 1.0 m. Its ball has speed of vo=2.0
m/s when the cord makes an angle of 30 degrees with the vertical. What
is the speed (V) of the ball when it passes the lowest position?

Answers

Answer:

v = 2.57 m / s

Explanation:

For this exercise let's use conservation of energy

starting point. When it is at an angle of 30º

          Em₀ = K + U = ½ m v₁² + m g y₁

final point. Lowest position

          Em_f = K = ½ m v²

as there is no friction, the energy is conserved

          Em₀ = Em_f

          ½ m v₁² + m g y₁ = ½ m v²

Let's find the height(y₁), which is the length of the thread minus the projection (L ') of the 30º angle

         cos 30 = L ’/ L

         L ’= L cos 30

         y₁ = L -L '

          y₁ = L- L cos 30

we substitute

          ½ m v₁² + m g L (1- cos 30) = ½ m v²

           v = [tex]\sqrt{ v_1^2 +2gL(1-cos30 )}[/tex]

let's calculate

           v = [tex]\sqrt{ 2^2 + 2 \ 9.8 \ 1.0 (1- cos 30)}[/tex]

           v = 2.57 m / s

A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at the elbow. During this punch, the horizontal flexor muscles of the shoulder contract and shorten at an average speed of 75 cm/s. They move through an arc length of 5 cm during the hook, while the fist moves through an arc length of 100 cm. What is the average speed of the fist during the hook

Answers

Answer:

average speed of the fist during the hook = 15 m/s or 1500 cm/s

Explanation:

We are given;

Speed of shoulder contraction, v_s = 75 cm/s = 0.75 m/s

Distance moved through the arc length by shoulder, d_s = 5 cm = 0.05 m

Distance moved by the fist, d_f = 100 cm = 1 m

Now, we are to find the average speed of the fist during the hook; v_f

Thus can be gotten from proportion;.

d_f/d_s = v_f/ v_s

Making V_f the subject, we have;

v_f = (d_f × v_s)/d_s

Thus;

v_f = (1 × 0.75)/0.05

v_f = 0.75/0.05

v_f = 15 m/s

In an elastic collision, ________. A. an individual molecule in the collision never loses energy B. the molecules involved in the collision move in a circular motion C. the total energy of all molecules in the collision remains constant D. the molecules involved in the collision are held to each other by strong intermolecular interactions

Answers

Answer:

Im pretty sure its B im very sorry if its wrong.

16–2. Just after the fan is turned on, the motor gives the
blade an angular acceleration a = (202-0.6) rad/s'. where :
is in seconds. Determine the speed of the tip P of one of the
blades when i 3 s. How many revolutions has the blade
turned in 3 s? When / O the blade is at rest.​

Answers

Answer:

P.S My answer may not render so let me know if it doesn't

Explanation:

if the water measures -5 feet at low tide and 3ft at high tide what is the tidal range ​

Answers

Answer:

8 feet

................

In a test of an energy-absorbing bumper, a 2800-lb car is driven into a barrier at 5 mi/h. The duration of the impact is 0.4 seconds. When the car rebounds from the barrier [in the opposite direction], the magnitude of its velocity is 1.5 mi/h. Use the principle of impulse and momentum to determine the magnitude of the average horizontal force (lb) exerted on the car during the impact.

Answers

Answer:

F = 2074.13 lb

Explanation:

Given that,

Mass of car, m = 2800 lb = 1270.059 kg

Initial speed, u = 5 mi/h = 2.2352 m/s

Final speed, v = - 1.5 mi/h = -0.67056 m/s  (in opposite direction)

Time, t = 0.4 s

We need to find the magnitude of the average horizontal force (lb) exerted on the car during the impact. It can be calculated as :

[tex]F=m\times \dfrac{v-u}{t}\\\\F=1270.059\times \dfrac{-0.67056 -2.2352 }{0.4}\\\\F=9226.21\ N[/tex]

or

F = -2074.13 lb

So, the required force is 2074.13 lb.

Which of these statements best explains why the atmosphere of today was partly due to the interactions of spheres in the past?

Bacteria used nutrients in the soil for volcanic eruptions.
Chemicals released from water formed the atmosphere.
The molten Earth released hydrogen and helium into the atmosphere.
The increase in fertility of soil around the volcano helped produce rain.

Answers

Answer:

The answer is: Plants and animals exchange carbon dioxide and oxygen with the atmosphere.

Explanation:

Got the answer right.

An 5 kg object moving at 10 m/s will have a momentum equaling ____________.

15 kg m/s/s

15 kg m/s

Answers

Answer:

50Kgm/s

Explanation:

Momentum=Mass*Velocity

P=mv

Given Mass=5Kg. Given Velocity=10m/s

Momentum=5*10=50Kgm/s

5.
2075 Set A Q.No. 20 2070 Supp. Set B Q.No. 2 B What
happens to the kinetic energy of photo electrons when
intensity of light is doubled?
[2]​

Answers

Answer:

The energy of each photon can be transformed into kinetic energy and as this energy does not change, the energy of both photoelectrons remains constant,

Explanation:

The photoelectric effect was explained by Einstein, who assumed that the lz is made up of particles called photons each of a given energy, therefore the photoelectric effect can be explained as a collision of particles.

From this explanation we see that the intensity is proportional to the number of existing particles, when we double the intensity we double the number of particles, but the energy of each particle does not change, therefore if we use the conservation of energy.

The energy of each photon can be transformed into kinetic energy and as this energy does not change, the energy of both photoelectrons remains constant, only the number of electrons expelled changes.

Two Carnot heat engines are operating in series such that the heat sink of the first engine serves as the heat source of the second on. If the source temperature of the first engine is 1300 K and the sink temperature of the second engine is 300 K and the thermal efficiencies of both engines are the same, the temperature of the intermediate reservoir is

Answers

Answer:

the temperature of the intermediate reservoir is 624.5 K

Explanation:

Given the data in the question  

The two Carnot heat engines are operating in series;

[ T[tex]_H[/tex] ]

  ↓

((1)) ⇒ W[tex]_{out[/tex]

  ↓

[ T[tex]_M[/tex] ]

   ↓

 ((2)) ⇒ W[tex]_{out[/tex]

[ T[tex]_L[/tex] ]

The maximum possible efficiency for any heat engine is the Carnot efficiency;

η[tex]_{rev[/tex] = 1 - [tex]\frac{T_L}{T_H}[/tex]

the thermal efficiencies if both engines are the same will be;

η[tex]_A[/tex] = η[tex]_B[/tex]

1 -  [tex]\frac{T_M}{T_H}[/tex] = 1 - [tex]\frac{T_L}{T_M}[/tex]

1 - 1 -  [tex]\frac{T_M}{T_H}[/tex] = - [tex]\frac{T_L}{T_M}[/tex]

-  [tex]\frac{T_M}{T_H}[/tex] = - [tex]\frac{T_L}{T_M}[/tex]

[tex]\frac{T_M}{T_H}[/tex] =  [tex]\frac{T_L}{T_M}[/tex]

T[tex]_M[/tex]² = T[tex]_L[/tex] × T[tex]_H[/tex]

T[tex]_M[/tex] = √(T[tex]_L[/tex] × T[tex]_H[/tex])

source temperature of the first engine T[tex]_H[/tex] = 1300 K

sink temperature of the second engine T[tex]_L[/tex] = 300 K

we substitute

T[tex]_M[/tex] = √(300 × 1300)

T[tex]_M[/tex] = √390000

T[tex]_M[/tex] = 624.4998 K ≈ 624.5 K

Therefore, the temperature of the intermediate reservoir is 624.5 K

An object, accelerating from rest at a constant rate, travels over 28 m in 11 s. What is its final velocity?

1.81 m/s

3.20 m/s

5.09 m/s

0.00 m/s

none of the above

Answers

Answer:

answer is 3

Explanation:

by using s= [(v+ u)/2] x t

28= (v+ 0)/2 x 11

v= 5.09 ms^-1

1. When an unbalanced force acts on an object,
O the object remains at rest
the weight of the object decreases.
O the object's motion changes.
the inertia of the object increases.

Answers

The object’s motion changes :)

Why are Big cinema hall are carpeted and their walls are made of some rough matenals.​

Answers

Okay jsmsksmsms s. I amaks. Sis ammoammapaa
Max
Aka
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