From the reaction: B2H6 + O2 HBO2 + H2O a. What mass of O2 will be needed to burn 36.1 g of B2H6? b. How many moles of water are produced from 19.2 g of B2H6?

Answers

Answer 1

A. The mass of O₂ needed to burn 36.1 g of B₂H₆ is 123.77 g

B. The number of mole of water, H₂O produced from 19.2 g of B₂H₆ is 1.372 mole

Balanced equation

B₂H₆ + 3O₂ —> 2HBO₂ + 2H₂O

Molar mass of B₂H₆ = (2×11) + (1×6) = 28 g/mol

Mass of B₂H₆ from the balanced equation = 1 × 28 = 28 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 3 × 32 = 96 g

SUMMARY

From the balanced equation above,

28 g of B₂H₆ required 96 g of O₂

A. How to determine the mass of O₂ needed

From the balanced equation above,

28 g of B₂H₆ required 96 g of O₂

Therefore

36.1 g of B₂H₆ will require = (36.1 × 96) / 28 = 123.77 g of O₂

Thus, 123.77 g of O₂ is required for the reaction

B. How to determine the mole of water produced

We'll begin by calculating the number of mole of in 19.2 g of B₂H₆. This can be obtained as follow:

Mass of B₂H₆ = 19.2 g Molar mass of B₂H₆ = 28 g/mol Mole of B₂H₆ =?

Mole = mass / molar mass

Mole of B₂H₆ = 19.2 / 28

Mole of B₂H₆ = 0.686 mole

Finally, we shall determine the number of mole of water produced. This is illustrated below:

Balanced equation

B₂H₆ + 3O₂ —> 2HBO₂ + 2H₂O

From the balanced equation above

1 mole of B₂H₆ reacted to produce 2 moles of H₂O

Therefore, H₂O

0.686 mole of B₂H₆ will react to produce = 0.686 × 2 = 1.372 mole of H₂O

Thus, 1.372 mole of H₂O was obtained from the reaction

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Chemical equilibrium refers to a situation in which the forward reactions and the backward reactions in a reversible reaction are occurring at the same same same rate.

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How many moles of sodium hydrogen carbonate are present in 2.61 grams of this compound?

Answers

Molar mass of NaHCO_3

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Now

[tex]\\ \sf\longrightarrow No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}[/tex]

[tex]\\ \sf\longrightarrow No\:of\; moles=\dfrac{2.61}{84}[/tex]

[tex]\\ \sf\longrightarrow No\:of\:moles=0.0312mol[/tex]


potassium hydroxide → potassium oxide + water
-
how do i balance this equation?

Answers

2KOH --> K²O + H²O

Explanation:

Potassium Hydroxide = KOH

Potassium oxide = K²O

Water = H²O

KOH --> K²O + H²O

K = 1. K = 2.

2KOH --> K²O + H²O

O = 2. O = 2.

H = 2. H = 2.

Balanced symbol = 2KOH --> K²O + H²O

Balanced word = 2Potassium Hydroxide --> Potassium oxide + Water.

What is represented in the image?

A: a space-filling model
B: a ball-and-stick model
C: a chemical formula
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Answers

Answer:

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This particle, an/a ___ has a negative charge

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Answer:

Explanation:

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This particle, an/a ___ has a negative charge

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How many grams of hydrogen will be produced from 4.0 moles of Magnesium?

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Answer:

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Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.



Note: the answer should have 3 significant digits. Do not include the unit mL in the answer.

Answers

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

Balanced equation

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From the balanced equation above,

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Answers

Answer:

Explanation:

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i got it ccorerct

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The milk of goats and sheep is similar in composition to that of cows.

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In one to two sentences, describe the characteristics of a high-pressure system.

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A high pressure system has higher pressure at its center than the areas around it

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Answer:

Its phosphorus (P)

Explanation:

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Answer:

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SO2 + H2O +_ H2SO3
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Answers

Hi so first of all count the number of atoms on both sides.
S = 1
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Answers

Answer:

A

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Is not my personal answer, but here is what I found.

"This entity has been manually annotated by the ChEBI Team. Potassium chromate is the inorganic compound with the formula (K2CrO4). This yellow solid is the potassium salt of the chromate anion"

100 points! Chemistry! Please help if you can with the following two questions

Answers

H_2S+O_2--->SO_2+H_2O

Balance it

2H_2S+3O_2--->2SO_2+2H_2O

So

Molar mass of oxygen=2(16)=32g/mol

Molar mass of SO_2=2(16)+32=32+32=64g/mol

Moles of oxygen:-

Given mass/Molar mass44.7/321.399mol

Here

3 mol of Oxygen produces 2 mol SO_21 mol of oxygen produces 2/3=0.6mol SO_2

Moles of so_2

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Answers

Answer:

Metals tend to lose electrons in chemical reactions, as indicated by their low ionization energies. Within a compound, metal atoms have relatively low attraction for electrons, as indicated by their low electronegativities.

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