From the reaction: B2H6 + O2 HBO2 + H2O a. What mass of O2 will be needed to burn 36.1 g of B2H6? b. How many moles of water are produced from 19.2 g of B2H6?

Answers

Answer 1

A. The mass of O₂ needed to burn 36.1 g of B₂H₆ is 123.77 g

B. The number of mole of water, H₂O produced from 19.2 g of B₂H₆ is 1.372 mole

Balanced equation

B₂H₆ + 3O₂ —> 2HBO₂ + 2H₂O

Molar mass of B₂H₆ = (2×11) + (1×6) = 28 g/mol

Mass of B₂H₆ from the balanced equation = 1 × 28 = 28 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ from the balanced equation = 3 × 32 = 96 g

SUMMARY

From the balanced equation above,

28 g of B₂H₆ required 96 g of O₂

A. How to determine the mass of O₂ needed

From the balanced equation above,

28 g of B₂H₆ required 96 g of O₂

Therefore

36.1 g of B₂H₆ will require = (36.1 × 96) / 28 = 123.77 g of O₂

Thus, 123.77 g of O₂ is required for the reaction

B. How to determine the mole of water produced

We'll begin by calculating the number of mole of in 19.2 g of B₂H₆. This can be obtained as follow:

Mass of B₂H₆ = 19.2 g Molar mass of B₂H₆ = 28 g/mol Mole of B₂H₆ =?

Mole = mass / molar mass

Mole of B₂H₆ = 19.2 / 28

Mole of B₂H₆ = 0.686 mole

Finally, we shall determine the number of mole of water produced. This is illustrated below:

Balanced equation

B₂H₆ + 3O₂ —> 2HBO₂ + 2H₂O

From the balanced equation above

1 mole of B₂H₆ reacted to produce 2 moles of H₂O

Therefore, H₂O

0.686 mole of B₂H₆ will react to produce = 0.686 × 2 = 1.372 mole of H₂O

Thus, 1.372 mole of H₂O was obtained from the reaction

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This particle, an/a ___ has a negative charge

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This particle, an/a ___ has a negative charge

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Answer:In general, the gross composition of cow's milk in the U.S. is 87.7% water, 4.9% lactose (carbohydrate), 3.4% fat, 3.3% protein, and 0.7% minerals (referred to as ash).

Explanation:

i got it ccorerct

Answer:

The milk of goats and sheep is similar in composition to that of cows.

Milk protein consists mainly of casein, and it exists in several classes: α, β, etc. If milk pH falls below 4.6, the casein precipitates. Although casein represents 80–85% of total milk protein, when precipitation occurs, the liquid portion is referred to as whey.

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The ash content of around 0.7% consists of a relatively high level of Ca2+ and a lower level of Fe2+.

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Answers

Hi so first of all count the number of atoms on both sides.
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In one to two sentences, describe the characteristics of a high-pressure system.

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Answers

H_2S+O_2--->SO_2+H_2O

Balance it

2H_2S+3O_2--->2SO_2+2H_2O

So

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Moles of oxygen:-

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Here

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Answers

Answer:

Explanation:

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Answers

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Balanced equation

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From the balanced equation above,

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Chemical equilibrium is a dynamic equilibrium whereby the forward and backward reactions are occurring at the same rate.

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Sodium nitride is exothermic reaction and hydrochloric acid is endothermic reaction.

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Answer:

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Answers

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bacteria

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Answer:

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I took the test and got it right

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Answers

Answer:

A

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Is not my personal answer, but here is what I found.

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Answers

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Fe2O3

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Answers

2KOH --> K²O + H²O

Explanation:

Potassium Hydroxide = KOH

Potassium oxide = K²O

Water = H²O

KOH --> K²O + H²O

K = 1. K = 2.

2KOH --> K²O + H²O

O = 2. O = 2.

H = 2. H = 2.

Balanced symbol = 2KOH --> K²O + H²O

Balanced word = 2Potassium Hydroxide --> Potassium oxide + Water.

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What's the question so I can help?

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Answer:

B Nematoda

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Answers

Molar mass of NaHCO_3

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Now

[tex]\\ \sf\longrightarrow No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}[/tex]

[tex]\\ \sf\longrightarrow No\:of\; moles=\dfrac{2.61}{84}[/tex]

[tex]\\ \sf\longrightarrow No\:of\:moles=0.0312mol[/tex]

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Answers

mol = M(molar concentration) times V (volume)

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Answers

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chemical composition and physical properties of packaging materials determine their ability to fulfill the various functions expected from the package. 

Use the chart below to answer the question.

Answer correctly.

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Answers

Answer:

Species M. furo and F. catus

Explanation:

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Answers

Answer:

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Hope this helps ya have a nice day

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Answers

Volume=25LTemperature=5°CPressure=89.9kPa

Now

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[tex]\\ \rm\rightarrowtail n=\dfrac{PV}{RT}[/tex]

[tex]\\ \rm\rightarrowtail n=\dfrac{89.9(25)}{5R}[/tex]

[tex]\\ \rm\rightarrowtail n=89.9(5)/R[/tex]

[tex]\\ \rm\rightarrowtail n=449.5/R mol[/tex]

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Answers

Answer:

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