Freezer a has interior dimensions of 1‘ x 1‘ x 5‘ and sells for $499.99 freezer B has interior dimensions of 1.5‘ x 1.5‘ x 4‘ and sells for $149.99 which freezer is a better buy in terms of dollars per cubic foot.

Answer:

(a) 15 students

(b) 3 minutes (by 4 students)

(c) 2 students

(d) 7 students

(e) Ordering this data from least to greatest:

0, 1, 2, 2, 3, 3, 3, 3, 5, 5, 7, 7, 9, 9, 11

The median number is 3.

The length of the side of the square is given as follows:

20 cm.

In the figure, there are two expressions used to give the side length to each square, as follows:

In a square, all the four side lengths have the same length, hence the value of x is obtained as follows:

6x - 1 = 4x + 6

2x = 7

x = 3.5 cm.

Then the side length of the square is obtained as follows:

6(3.5) - 1 = 20 cm.

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The value of the identities are;

sin X= 3/√34

tan Y = 3/5

Option A

To determine the value, we need to take note of the different trigonometric identities. These identities are;

From the information given, we have that;

the hypotenuse side = √34

The opposite of X is 3

the opposite of Y is 5

Using the sine identity;

Substitute the opposite and the hypotenuse in the fraction order

sin X = 3/√34

Using the tangent identity, we have;

tan Y = 3/5

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The probability of at least covering the transportation costs and additional fee is 0.9888.

To estimate the probability of at least covering the transportation costs and additional fee, we can use the binomial distribution.

The binomial distribution models the probability of success or failure in a fixed number of independent trials.

The probability of success is 0.28 (choosing a brand on premium shelf space), and we want to calculate the probability of at least 40 successes out of 200 trials (customers).

We can use the binomial probability formula to calculate this probability:

P(X ≥ 40) = 1 - P(X < 40)

Where:

P(X≥ 40) is the probability of at least 40 successes

P(X < 40) is the probability of less than 40 successes

P(X < 40) = sum of binomial probabilities for x = 0 to 39

P(X < 40) = sum [from x = 0 to 39] (200 C x) × (0.28ˣ)×(0.72²⁰⁰⁻ˣ)

P(X < 40) = 0.0112

Therefore,

P(X ≥ 40) = 1 - P(X < 40)

P(X ≥ 40) = 1 - 0.0112

P(X≥ 40) = 0.9888

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Answer:

Step-by-step explanation:

23/40 = 0.575

The box and whisker plot that has the greatest interquartile range is option 3..

The interquartile range of a data set can be found by finding the difference of the data at the beginning and end of the edges of the rectangular box in a box and whisker plot.

It is also the difference between the third and first quartile.

The box and whisker plot in option 3 has the greatest interquartile range because the difference of the Q3 and Q1 is close to 9, which is the highest compared to the other data.

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The situation that could represent the probability distribution table is

Considering the given probability distribution table:

X : P(X)

A = 1/10

B = 3/5

C = 3/10

Let there be 40 cards each labeled A, B, and C.

The probabilities are aclculated as follows:

Four of the cards are labeled A;

Hence, P(A) = 4/40 or 1/10

24 of the cards are labeled B;

Hence, P(B) = 24/40 or 3/5

12 of the cards are labeled C;

Hence, P(C) = 12/40 or 3/10

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The equivalent logarithmic value of the given expression log 3  + log 6 is equal to logarithm of 18.

The expression is equal to,

log 3  + log 6

By using the law of multiplication we have,

Log A + Log B = Log ( A × B )

Using the properties of logarithms, we can simplify the expression and get the equivalent logarithm number ,

Substitute the value of A = 3 and value of B = 6 in the formula we have,

log 3 + log 6

= log (3 × 6)

= log 18

Therefore, the expression log 3 + log 6 is equivalent to the logarithm of 18.

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The value of the product is  -6i² + 37ij - 6j²

Algebraic expressions are simply described as expressions that are composed of coefficients, their variables, constants, terms, and factors.

Also note that algebraic expressions are expressions that consists of mathematical or arithmetic operations.

These operations are listed thus;

From the information given, we have;

Then, the product is;

vw = (6i - j)(-i + 6j)

expand the bracket

= -6i² + 36ij + ij - 6j²

add the like terms

= -6i² + 37ij - 6j²

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The two numbers whose geometric mean is 5√3 is 3 and 25

Given data ,

Let the geometric mean of the numbers be A = 5√3

Now , the first number is a = 3

Let the second number be b

And , the equation for the geometric mean as:

√(b x 3) = 5√3

To solve for "b", we can square both sides of the equation

(√(b * 3))² = (5√3)²

b x 3 = 75 (since (√a)² = a)

Now, we can divide both sides of the equation by 3

b = 75 / 3

b = 25

Hence , the other number is 25

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Answer: x=14 y=10

Step-by-step explanation:

To calculate the number of different meals available when selecting an appetizer, an entrée, and a dessert, we need to multiply the number of choices for each course.

Using the multiplication principle of counting, we can find the total number of meal options as follows:

Total number of meal options = number of appetizer choices x number of entrée choices x number of dessert choices

Total number of meal options = 5 x 13 x 4

Total number of meal options = 260

Therefore, there are 260 different meals available when you select an appetizer, an entrée, and a dessert from the given choices.

Answer:

Step-byHow do I calculate the mean?

The mean can be calculated only for numeric variables, no matter if they are discrete or continuous. It's obtained by simply dividing the sum of all values in a data set by the number of value

-step explanation:

46+57+66+63+49+52+61+68= 462/8 the total number of observation

the answer 57

The tangent at any point of a circle is perpendicular to the radius through the point of contact by showing that line PQ coincides with the radius OP.

Let us assume that we have a circle with center O and radius r.

Let P be any point on the circle .

And let Q be the point of intersection of the tangent to the circle at P and the radius OP,

To prove that PQ is perpendicular to OP.

First, we observe that OP is a radius of the circle and therefore its length is r.

Since PQ is tangent to the circle at point P,

It is perpendicular to the radius drawn from the center of the circle to point P.

As the tangent to a circle is perpendicular to the radius drawn to the point of contact.

This implies, angle QOP is a right angle.

Next, triangle OPQ is a right triangle with right angle at Q.

By the Pythagorean Theorem, we have,

OP²= OQ² + PQ²

Substituting r for OP and noting that OQ = r since Q is on the radius. we have,

⇒ r² = r²+ PQ²

Subtracting r² from both sides, we get,

⇒ PQ² = 0

This implies that PQ = 0,

In other words, that point Q coincides with point P.

PQ is a line that coincides with the radius OP.

And since angle QOP is a right angle, we can conclude that PQ is perpendicular to OP.

Therefore, it is proved that the tangent at any point of a circle is perpendicular to the radius through the point of contact.

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The above question is incomplete, the complete question is:

Prove that the tangent at any point of a circle is perpendicular to the radius through the point of contact.

The initial sum of the number of students in College P and College Q is 5040.

We have,

Let's assume that the number of students in college Q is represented by Q, and the number of students in college P is represented by P:

P = Q - 0.32Q = 0.68Q

We also know that if 960 more students enroll in college P, the two colleges will have the same number of students.

So, we can set up another equation:

P + 960 = Q

We can substitute the first equation into the second equation to eliminate P:

0.68Q + 960 = Q

Solving for Q, we get:

0.32Q = 960

Q = 3000

The initial number of students in college Q was 3000.

We can use this value to find the initial number of students in college P:

P = 0.68Q = 0.68(3000) = 2040

So, the initial sum of the number of students in College P and College Q is:

P + Q = 2040 + 3000 = 5040

Therefore,

The initial sum of the number of students in College P and College Q is 5040.

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The complete question.

College P has 32% less students then college Q if 960 more students college P , the two college will have the same number of student what is the sum of the number of student in college p and college Q initially?

1) 5880

2)5040

3)8400

4)6720​

75% of students of a class answered Question No. 1 correct and 55% answered Question No. 1 correct and 20% answered neither question correctly . 50 is the percentage of students who only answered one question

A percentage is a quantity or ratio that is expressed as a fraction of 100. It is symbolised by the '%' percentage sign. 'pct' or 'pc' are the acronyms used to indicate the percentage. In sense, the percentage is measured in terms of 100 and is defined as the amount of one quantity that is made up of another.

Students answer Q.1 or Q.2 or both correctly = ( 100 - 20) = 80%

x% students answered both correctly

( 75 - x) + ( 55 - x) + x = 80

130 - x = 80

x = 50

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Your question is incomplete but most probably your full question was,

75% of students of a class answered Question No. 1 correct and 55% answered Question No. 1 correct and 20% answered neither question correctly . What percent of students answered both question correctly ?

The combinations of side lengths that would not form a triangle with vertices X, Y, and Z is A. XY = 15 mm, YZ = 10 mm, and XZ = 28 mm.

We shall us the triangle inequality theory for this problem.

According to this theory, the addition of the lengths of any two sides of a triangle must be greater than the length of the third side.

Therefore, for the sides XY, YZ, and XZ to form a triangle, we must have:

XY + YZ > XZ

YZ + XZ > XY

XZ + XY > YZ

We can check each option to see if it satisfies these conditions:

A. XY = 15 mm, YZ = 10 mm, XZ = 28 mm

15 + 10 > 28 (not satisfied)

10 + 28 > 15 (satisfied)

28 + 15 > 10 (satisfied)

Option A does not satisfy the condition XY + YZ > XZ, so it would not form a triangle.

B. XY = 18 mm, YZ = 10 mm, XZ = 25 mm

18 + 10 > 25 (satisfied)

10 + 25 > 18 (satisfied)

25 + 18 > 10 (satisfied)

Option B satisfies all the conditions, so it would form a triangle.

C. XY = 18 mm, YZ = 13 mm, XZ = 22 mm

18 + 13 > 22 (satisfied)

13 + 22 > 18 (satisfied)

22 + 18 > 13 (satisfied)

Option C satisfies all the conditions, so it would form a triangle.

D. XY = 15 mm, YZ = 10 mm, XZ = 22 mm

15 + 10 > 22 (satisfied)

10 + 22 > 15 (satisfied)

22 + 15 > 10 (satisfied)

Option D satisfies all the conditions, so it can form a triangle.

Therefore, the combinations that would not form a triangle is A, where XY = 15 mm, YZ = 10 mm, and XZ = 28 mm.

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5√2 is the value of x in the given triangle. Therefore, the correct option is option A among all the given options.

A polygon having three edges & three vertices is called a triangle. It can be considered one of the fundamental geometric shapes. A unique triangle and plane (i.e., the two-dimensional Euclidean space) are determined by any three non-collinear points in Euclidean geometry. In other words, every triangle has a location in a plane, and there is just one level that contains that triangle.

√2×√50 = √100 = 10.

1×√50 = √50 = 5√2

5√2 since √50 = √25×√2 = 5√2

Therefore, the correct option is option A among all the given options.

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Your question is incomplete but most probably your full question was,

Answer:

y = 1/2x + 5

Step-by-step explanation:

hope this helps :)

Answer:

y= 1/2x +5

Step-by-step explanation:

3x-6y=-30

-3x -3x

-6y = -3x -30

/-6 /-6 /-6

y = 1/2 +5

The length of the hypotenuse of the given right angled triangle is √113.

Three given side lengths of a triangle a, b and c are said to be the sides of the right angled triangle if -

a² = b² + c²

The above theorem is known as the Pythagoras theorem.

Now, we can write that -

(hypotenuse)² = (base)² + (perpendicular)²

(hypotenuse)² = (7 x 7) + (8 x 8)

(hypotenuse)² = 49 + 64

(hypotenuse)² = 113

(hypotenuse) = √113

So, the length of the hypotenuse of the given right angled triangle is √113.

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The equivalent expression to the given expression [tex]2^{3x}[/tex] - 4  is equal to 8ˣ - 4.

The expression is equal to,

[tex]2^{3x}[/tex] - 4

Simplify the expression using the law of exponent we get,

yᵃᵇ = (yᵃ)ᵇ

Here  in the expression the value of y = 2,

Value of a = 3

and the value of b = x

Substitute the value in the formula we get,

= ( 2³ )ˣ - 4

value of the exponent 2³ = 2 × 2 × 2

                                          = 8

This implies the equivalent expression is,

= 8ˣ - 4

Therefore, the value of the given expression is equivalent to 8ˣ - 4.

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The solution of the differential equation is y + e²ˣ = Ceˣ, if Ceˣ > 0

or -y - e²ˣ = Ceˣ, if Ceˣ < 0.

The solution of the differential equation is calculated as follows;

dy/dx = e²ˣ + y

Apply the method of separating viables;

dy/dx = e²ˣ + y

dy/(y + e²ˣ) = dx

Integrate both sides;

∫ dy/(y + e²ˣ) = ∫ dx

ln|y + e²ˣ| = x + C

To solve for y, we need to exponentiate both sides;

|y + e²ˣ| = e^(x+C) = Ceˣ

The final solution becomes;

y + e²ˣ = Ceˣ, if Ceˣ > 0

or

-y - e²ˣ = Ceˣ, if Ceˣ < 0

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Answer:

45

Step-by-step explanation:

10!/(10-2)!*2!

10!=1*2*3*4*5*6*7*8*9*10=3628800

8!=1*2*3*4*5*6*7*8=40320

2!=1*2=2

3628800/40320*2

3628800/80640=45

The area of each of the bottom fret markers using given dimensions is equal to 364 square millimeters.

Base of the fret marker = 45.5mm

Height of the fret marker = 8mm

Attached image.

The area of a parallelogram can be found by multiplying the base by the height.

Here, the base of each of the 3 bottom fret markers is 45.5mm and the height is 8mm.

So, the area of each fret marker is,

Area = base x height

Substitute the value of base and height we have,

⇒ Area = 45.5mm x 8mm

⇒ Area = 364 mm²

Therefore, the area of each of the 3 bottom fret markers is 364 square millimeters.

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The above question is incomplete, the complete question is:

Raymond applies the pearl guitar fret markers to his fret board as shown. Each fret marker is in the shape of a parallelogram. Each of the 3 bottom fret markers has a base that measures 45.5mm and a height of 8mm. What is the area of each of the bottom fret​ markers?

Attached image.

If 30% children travelling by bus is represented by 360 children, then total number of students who attended the school are 1200.

The "Percent" is a way of expressing a fraction or proportion as a number out of 100. It is a unit of measurement used to represent the relative size or amount of something compared to the whole.

If 30% of the children at a particular school travel by bus and this represents 360 children, we use this data to find total number of children who attend the school.

Let "X" be = total number of children at the school.

We know that 30% of X represents 360 children, so we can write an equation:

⇒ 30% of X = 360,

⇒ 30% × X = 360,

⇒ 0.3 × X = 360,            ...because 30% = 0.3,

⇒ X = 360/0.3 = 1200,

Therefore, there are 1200 students who attend the school.

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Expressing as single logarithm 3/2㏑4x⁶ - 2/5㏑2y²⁵ = ㏑(2x⁹/y¹⁰)

Since we have the logarithm expression

3/2㏑4x⁶ - 2/5㏑2y²⁵

To simplify, we proceed as follows

First, we use the power law of logarithm which states that

n㏑x = ㏑xⁿ

So, using this, we have that

3/2㏑4x⁶ - 2/5㏑2y²⁵ = ㏑4x⁶ - 2/5㏑2y²⁵

[tex]= ln4x^{6\times\frac{3}{2} } - ln2y^{25\times\frac{2}{5} } = ln4x^{3\times3} } - ln2y^{5\times2 }[/tex]

= ㏑4x⁹ - ln2y¹⁰

Using the subtraction law of logarithm, which states that

㏑a - ㏑b = ㏑(a/b), we have that

㏑4x⁹ - ln2y¹⁰ =  ㏑(4x⁹/2y¹⁰)

= ㏑(2x⁹/y¹⁰)

So, 3/2㏑4x⁶ - 2/5㏑2y²⁵ = ㏑(2x⁹/y¹⁰)

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Answer:

The measure of an inscribed angle in a circle equals half the measure of its intercepted arc.

3) 56 + 2x = (1/2)(112 + x)

x = 0, so the measure of arc BCD is

360° - 112° = 248°.

5) 3 + 20x = (1/2)(43x - 3)

6 + 40x = 43x - 3

3x = 9, so x = 3

The measure of arc MLK is

360° - (43(3) - 3)° = 360° - 126° = 234°.

JL = 4x = 12 units.

Step-by-step explanation:

Since JKLM is an isosceles trapezoid, we know that parallel sides JK and LM are congruent. Additionally, since the diagonals intersect at point R, we know that angles JRM and KRL are congruent.

To find m∠JKL, we can use the fact that the sum of the angles in a quadrilateral is 360 degrees. We know that angle LMK is 78 degrees, angle KJM is 27 degrees, and JRM and KRL are congruent. So, m∠JKL = 360 - 78 - 27 - 2x, where x is the measure of angle KRL.

To find angle KRL, we can use the fact that JRL and KRM are congruent (since they are opposite angles formed by intersecting lines). We also know that JRL + KRL = 180 degrees (since they form a linear pair). Therefore, JRL = KRL = (180 - 27 - 78) / 2 = 37.5 degrees.

Plugging this into our equation for m∠JKL, we get:

m∠JKL = 360 - 78 - 27 - 2(37.5) = 197 degrees

To find m∠KJM, we can simply use the given measure:

m∠KJM = 27 degrees

To find JL, we can use the Pythagorean theorem on right triangles JRL and KRL. We know that JRL is a 3-4-5 right triangle (since 3, 4, 5 is a Pythagorean triple), so JR = 3x and RL = 4x for some value of x. Similarly, we know that KRL is a 7-24-25 right triangle (since 7, 24, 25 is another Pythagorean triple), so KR = 7y and RL = 24y for some value of y.

Since JR = 39 and KR = 42, we can set up two equations:

3x + 24y = 39

4x + 7y = 42

Solving for x and y using any method (substitution, elimination, etc.), we get:

x = 3, y = 2

Therefore, JL = 4x = 12 units.