The moles would be 12 moles, 4 moles and 11.34 moles
How to solve for the molesWhen hydrogen gas (H2) reacts with oxygen gas (O2) to produce water (H2O), the balanced chemical equation is:
2H2 + O2 -> 2H2O
So,
For every 6 moles of H2, 12 moles of H2O will be produced
For every 2 moles of H2, 4 moles of H2O will be produced
For every 5.67 moles of H2, 11.34 moles of H2O will be produced.
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openstax college physics what would this frequency become if the person's breathing passage were filled with carbon dioxide instead of air? assume the same temperature dependence for carbon dioxide as for air.
The speed of sound in a given medium, which depends on the medium's temperature, pressure, and density, determines the frequency of a sound wave inside.
The frequency of a wave is the number of times its cycles occur in a unit of time. It is typically expressed in Hertz (Hz), which stands for one cycle per second, in physics. A wave's apparent pitch depends on its frequency; higher frequency waves produce higher pitches, and lower frequency waves produce lower pitches. Frequency is a key idea in several branches of physics, such as electromagnetism and optics, where it relates to the energy of waves and the colour of light, respectively. The periodic motion of objects and the behaviour of oscillating systems are both connected to frequency in mechanics. Additionally, it is employed in the research of sound waves and the creation of music.
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a pot contains 9 l of brine at a concentration of 110 g/l. how much of the water should be boiled off to increase the concentration to 220 g/l?
4.95 liters of water need to be boiled off to increase the concentration of the brine to 220 g/l.
When the solution will boil, only the solvent will be converted to gas. The solute remains in the solution, so its amount does not change but the concentration does.
The total amount of the solute = 110 g/l * 9 l = 990 g
Inorder concentration = 220 g/l
The amount of the water that should be boiled off = 990 g / (220 / 110)
= 990 g / 2
= 4.95 liters
So, 4.95 liters of water need to be boiled off to increase the concentration of the brine to 220 g/l.
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you are conducting the acetophenetidin reaction and just finished your hot gravity filtration. you notice that you have some activated carbon in your filtrate solution. what is the best way to address this problem?
Use a fresh funnel and fresh filter paper to repeat the hot gravity filtration.
The best way to address this problem is to perform a cold gravity filtration. This will allow the activated carbon to settle at the bottom of the container, making it easier to filter out. After the cold gravity filtration, you may also want to consider running the solution through a filter paper to remove any remaining activated carbon particles. Recrystallization is accomplished using hot gravity filtration. It is specifically used to clean the sample of any insoluble contaminants. The stemless funnel is ideal for this method because it prevents crystallization on the stem of the funnel (since stemless).
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an acidic water sample initially contains 2 mg/l of iron(iii). how much iron precipitates out if the ph is raised to 3? assume the temperature is 25oc
The amount of iron that precipitates out if the ph is raised to 3 assuming the temperature is 25 will be depending on the solubility product constant of iron(III) hydroxide.
The amount of iron(III) that precipitates out when the pH of an acidic water sample is raised to 3 depends on the solubility product constant (Ksp) of iron(III) hydroxide. At 25°C, the Ksp of Fe(OH)3 is 1.26 x 10^-39. When the pH of the water sample is raised to 3, the concentration of hydroxide ions increases, which can lead to the precipitation of iron(III) hydroxide if the concentration exceeds the solubility limit defined by the Ksp. The exact amount of iron(III) that precipitates out can be calculated using an equilibrium expression and the Ksp, but without more information about the initial conditions and changes in concentration, it is not possible to determine the exact amount of iron that precipitates.
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simple bread recipe calls for
g of flour, 8 g of salt, 1 g of yeast, 400
and 0.3 L of water. The recipe
produces 1 loaf of bread. The data
table shows the amounts of
each ingredient you have. Identify the
limiting reagent. What is the
theoretical yield, assuming you could
make partial loaves? How many
whole loaves of bread can you actually
make? What is the percent
yield? How much of each ingredient do
you have left over?
We would produce a loaf of bread, the limiting reagent is water and the percent yield is 30%
What is the limiting reagent?The limiting reagent, also known as the limiting reactant, is the reactant that determines the maximum amount of product that can be formed in a chemical reaction. It is the reactant that is completely consumed first and therefore determines the amount of product that can be formed.
Since we have 0.3 g of the water, the theoretical yield would now be;
0.3 g/1 g * 100/1
= 30 %
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how many ml of 1.5 m naoh are required to neutralize 220 ml 0.8 m hcl? select one: a. 94.6 ml b. 144.8 ml c. 117.3 ml d. 180.1 ml
It takes 117.3 ml NaOH to neutralize 220 ml and 0.8 M HCl.
The dilution process is a process carried out by mixing a solvent that is larger than the substance it is dissolving. In principle, dilution only adds solvent, so that the number of moles of solute before dilution is the same as the number of moles of solute after dilution.
Formula:
V₁ × M₁ = V₂ × M₂
Information:
M₁ = Molarity of the solution before dissolution/dilution
V₁ = Volume of solution before dissolution/dilution
M₂ = Molarity of the solution after dissolution/dilution
V₂ = Volume molarity of the solution after dissolution/dilution
In the given question
M₁ = 1.5 M
V₂ = 220 ml
M₂ = 0.8 M
So, the required volume of NaOH is
V₁ × M₁ = V₂ × M₂
V₁ × 1.5 = 220 × 0.8
V₁ × 1.5 = 176
V₁ = 176/1.5
V₁ = 117.3 ml NaOH
So, the correct answer is C.
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in non-ionized hydrogen, for instance, what does a higher orbital state have more of than a lower orbital state?
In non-ionized hydrogen, a higher orbital state refers to an electron in a higher energy level or shell.
What are orbital states?
Orbital states in physics and chemistry define the energy and position of an electron in an atom. An electron in an atom is typically described by its orbital state, which includes the energy level, the angular momentum, and the magnetic moment of the electron.
In a hydrogen atom, for example, an electron can occupy different energy levels or shells, which correspond to different orbital states. Each orbital state is characterized by a unique set of quantum numbers that describe the energy, angular momentum, and magnetic moment of the electron in that state.
In comparison to a lower orbital state, a higher orbital state has a higher energy and is farther away from the nucleus of the hydrogen atom.
The main difference between a higher and lower orbital state is their energy and the distance between the electron and the nucleus. Electrons in higher orbital states have more energy and are farther away from the nucleus than those in lower orbital states. This means that electrons in higher orbital states are less likely to be held by the positively charged nucleus and are therefore more likely to participate in chemical reactions or interactions with other atoms.
So, In non-ionized hydrogen, a higher orbital state refers to an electron in a higher energy level or shell.
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what is the freezing point of a solution formed by dissolving 0.75 moles naphthalene in 2.0 kg benzene g
The freezing point of a solution is dependent on the concentration of solute particles in the solvent. The presence of solute particles in a solvent decreases its ability to freeze, and as a result, the freezing point of the solution is lowered.So, the freezing point of the solution would be lower than that of pure benzene by 1.91 °C.
The freezing point depression of a solution can be calculated using the equation:
ΔTf = Kf x molality
where ΔTf is the change in freezing point, Kf is the freezing point depression constant for the solvent, and molality is the concentration of solute particles in the solution expressed in moles per kilogram of solvent.
In this case, the solvent is benzene and its freezing point depression constant, Kf, is 5.12 °C/m. The molality of the solution can be calculated as follows:
molality = moles of solute / kilograms of solvent
= 0.75 moles / 2.0 kg
= 0.375 moles/kg
Substituting these values into the equation, we get:
ΔTf = 5.12 °C/m x 0.375 moles/kg
= 1.91 °C
So,the freezing point of the solution is 1.91 °C.
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a compound has the empirical formula c2h4s. its molecular weight is 120 g/mol. identify the molecular
The molecular formula of the compound with empirical formula C2H4S and molecular weight of 120 g/mol is C6H12S2.
The empirical formula represents the simplest ratio of atoms in a compound. It is determined from the elemental analysis of the compound. The molecular weight of the compound is the sum of the atomic weights of all the atoms in the molecular formula. To find the molecular formula, the molecular weight is used to determine the number of atoms in the empirical formula.
In this case, the molecular weight of 120 g/mol can be used to find the molecular formula by dividing the molecular weight by the empirical formula weight. The empirical formula weight of C2H4S is 40 g/mol, which means that the molecular formula must have a weight of three times the empirical formula weight, or 120 g/mol.
This leads to the molecular formula of C6H12S2, which has a molecular weight of 120 g/mol.
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In the following acid-base reaction,
OH- is the
CH3NH2(g) + H2O(1)
→
CH3NH3(aq) + OH¯(aq)
Conjugate base
Acid
Conjugate acid
The base in the following chemical interaction is CH3NH2, which is methyl amine. It creates its conjugate acid, the methyl ammonium ion, when it receives a proton.
How is the conjugate base discovered?The conjugate base's formula is the acid's formula less one hydrogen. The base that reacts changes into its conjugate acid. The conjugate acid's formula is the base's formula adds one hydrogen ion.
Is ch3oh a base for Bronsted-Lowry?Because it is categorized as both a Lewis acid and a Bronsted-Lowry acid, methanol. It will become a Bronsted-Lowry acid as a result of the proton donation, and the methanol will also take electrons as a result.
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An element X after reacting with
Answer:
Magnesium + Hydrochloric Acid → Magnesium Chloride + Hydrogen
What do we do with the extra 0.24 days each year upon the completion of Earth's revolution?
A. Every year on New Year's Day we get an extra 4 hours added to our day.
B. Nothing is done with them and our yearly calendar always has 365 days.
C. Every 4 years they are put together and we add one day to our yearly calendar.
D. We move our clocks back an hour in the fall and ahead an hour in the spring.
Answer:
C. Every 4 years they are put together and we add one day to our yearly calendar.
Answer:C. Every 4 years they are put together and we add one day to our yearly calendar (leap year).
Explanation:
if 5 half-lives have gone by and you have .03125 grams of an unstable parent substance, how many grams of stable daughter product should you have?
Answer:
Explanation:
The amount of daughter product that should be present after 5 half-lives depends on the specific radioactive decay process involved and the initial amount of the parent substance. In general, after each half-life, the amount of the parent substance decreases by half, and the corresponding amount of the daughter product increases by half.
In this case, with 5 half-lives gone by, the amount of the parent substance should have decreased by a factor of 2^5 = 32. Hence, the amount of the parent substance should be .03125/32 = 0.0009765625 grams.
Since the amount of daughter product is proportional to the amount of the parent substance that decays, the amount of daughter product should be 0.0009765625 * 32 = 0.03125 grams.
2 C8H18 + 25 O2 > 16 CO2 + 18 H2O how many moles of O2 are needed to react fully with 4 moles of octane
Answer:
100 moles of O2 are needed to react fully with 4 moles of octane.
Explanation:
Answer:
50
Explanation:
To find the number of moles of O2 needed to react fully with 4 moles of octane (C8H18), we need to balance the equation first:
2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O
So, the balanced equation tells us that for every 2 moles of C8H18, 25 moles of O2 are needed. Thus, to react with 4 moles of C8H18, we need 25 * (4/2) = 50 moles of O2.
how many grams of NaCl would dissolve in water to make a 50 M solution with 500 mL final volume
Mass of NaCl that would dissolve in water to make a 50 M solution with 500 mL final volume is 1460 grams
To make a 50 M solution of sodium chloride (NaCl), the number of moles of NaCl required can be calculated using the formula:
moles of solute = concentration (M) x volume (L)
where volume is in liters. In this case, the concentration is 50 M and the volume is 0.5 L (500 mL).
moles of NaCl = 50 M x 0.5 L = 25 moles
Since the molecular weight of NaCl is 58.44 grams/mole, the mass of NaCl required can be calculated by multiplying the number of moles by its molecular weight:
mass = moles x molecular weight
mass of NaCl = 25 moles x 58.44 grams/mole = 1460 grams
So, 1460 grams of NaCl would dissolve in water to make a 50 M solution with a final volume of 500 mL.
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GIVING BRAINLIEST TO WHOEVER GETS IT RIGHT
Identify the choice that best completes the statement or answers the question. The following paragraph contains an error. Read the entire passage. Then select the option that corrects the error. Most people know that bats can find their way in the dark using echolocation. Bats make a series of high-pitched squeaks. Based on the way these sound waves diffract off objects around it, a bat can form a mental picture of its surroundings. Fewer people realize that humans can also learn to echolocate. A man named Daniel Kish can ride his bike even though he lost his vision at the age of one! Mr. Kish makes a sharp clicking sound with his tongue. By listening to the echoes of the click, he can easily navigate his surroundings.
A. Mr kishs use of echolocation would be limited due to absorption of sound waves
B. Mr kish actually navigates through the use of radar waves, not echolocation
C. in echolocation, bats listen to the way sound waves refract, not diffract
D. In echolocation, bats listen to the way sound waves reflect, not diffract
Answer:C
Explanation: Done by reading and is best answer option.
the child is receiving d10ns with 20 meq kcl infusing at 100 ml/hr. a new 1,000- ml fluid bag was hung at 0700. at 0800 the iv infiltrated and was restarted at 1000. at 1100 the iv rate was decreased to 50 ml/hr until 1900. calculate the total iv intake from 0700 to 1900.
The following formula can be used to determine the total IV intake between 7:00 and 9:00. Thus, 600 cc of IV fluid total were administered between 7:00 and 1:00.
Total IV intake is the total volume of fluid injected into a person's circulation via an intravenous (IV) line. Typically, the IV line is put into a vein in the arm or hand, and the fluid, which may contain nutrients, electrolytes, and drugs, is then given directly into the bloodstream. Tracking the overall IV intake is crucial, particularly in healthcare settings, since it ensures that patients are receiving the right amount of fluid and minerals to preserve their health. A range of medical disorders, such as dehydration, malnutrition, and some medical procedures, may require the insertion of an IV line. It is crucial to carefully monitor the total IV intake to prevent consequences like fluid overload.
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n the formation of ammonia from the reaction of hydrogen and nitrogen . 1. a. hydrogen gains electrons and is reduced. 2. b. hydrogen loses electrons and is reduced. 3. c. hydrogen gains electrons and is oxidized. 4. hydrogen loses an electron and is oxidized. 5. none of the above
In the formation of ammonia from the reaction of hydrogen and nitrogen, hydrogen gains electrons and is reduced.
Reduction is a chemical process in which a substance gains electrons and its oxidation state decreases. This can be contrasted with oxidation, in which a substance loses electrons and its oxidation state increases. In the formation of ammonia from the reaction of hydrogen and nitrogen, hydrogen gains electrons and is reduced, while nitrogen is oxidized. During the reaction, hydrogen atoms donate electrons to nitrogen atoms, forming a covalent bond and producing ammonia. The electrons that are donated by the hydrogen atoms result in an increase in the number of electrons in the hydrogen atoms, which is what makes them reduced. This reaction provides a clear example of how the concepts of reduction and oxidation are related and how they can occur simultaneously in a single chemical reaction.
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what is the poh of 2.95 m ba(oh)2 solution? is the solution neutral, acidic, or basic? the poh of the solution is: g
Three often used definitions of bases in chemistry are Arrhenius bases, Bronsted bases, and Lewis bases. pOH is equal to -log (OH-)/-log (3.67 x 10-5)/-log (4, 44).
Bases are substances that interact with acids, as stated by all definitions, and as G.-F. Rouelle initially proposed in the middle of the 18th century. In 1884, Svante Arrhenius stated that a base is a substance that, in an aqueous solution, separates into Hydroxide ions (OH). These ions can mix with hydrogen ions (H+), which are formed during the dissociation of acids, to form water in an acid-base process. Therefore, a base was a metal hydroxide, such NaOH or Ca (OH)2. Additionally, these aqueous hydroxide solutions have a few distinctive qualities. The answer is rather straightforward. The solution is basic with a pOH of 4, 44. The amount of OH (hydroxyl) ions in the solution is determined by the pOH value.
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a flask contains four gases: ch4, o2, c2h5, and n2. when the stopper is removed, which gas will diffuse the fastest? responses c2h5 uppercase c subscript 2 end subscript uppercase h subscript 5 end subscript o2 uppercase o subscript 2 end subscript ch4 uppercase c h subscript 4 end subscript n2
The gas that will diffuse the fastest is O2 (oxygen). Gases diffuse from areas of high concentration to areas of low concentration. Oxygen has a relatively small molecular size compared to the other gases.
So, it is more likely to move quickly through the container and escape through the opening. Methane (CH4) and Ethane (C2H5) are larger, and thus will diffuse slower than oxygen.
Nitrogen (N2) is an even larger gas, and it will diffuse the slowest of all the gases in the flask.
Methane is a chemical composite with the chemical formula CH₄. It is a group-14 hydride, the simplest alkane, and the main basic of natural gas.
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9.9 kg of r-134a at 300 kpa fills a rigid container whose volume is 14 l. determine the temperature and total enthalpy in the container. the container is now heated until the pressure is 600 kpa. determine the temperature and total enthalpy when the heating is completed. use data from the refrigerant tables.
the temperature and total enthalpy after the heating is can be found by using the conservation of energy principle and the first law of thermodynamics.
To determine the temperature and total enthalpy in a container filled with 9.9 kg of R-134a at 300 kPa and a volume of 14 L, and then to find the temperature and total enthalpy after the pressure has been increased to 600 kPa, we need to use the refrigerant tables to look up the thermodynamic properties of R-134a.
The first step is to find the specific volume, internal energy, and enthalpy of R-134a at the initial state (300 kPa and a temperature to be determined).
Next, we can use the ideal gas law to find the temperature of R-134a at the initial state:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of refrigerant, R is the gas constant, and T is the temperature.
The number of moles can be found using the mass and molecular weight of R-134a:
n = m/M
where m is the mass of R-134a and M is its molecular weight.
Using the refrigerant tables, we can find the specific volume, internal energy, and enthalpy of R-134a at the final state (600 kPa and a temperature to be determined).
With this information, we can calculate the change in internal energy and enthalpy during the process of heating the container.
Finally, the final temperature and total enthalpy can be found by using the conservation of energy principle and the first law of thermodynamics.
This is a complex calculation that requires a good understanding of thermodynamics and the use of refrigerant tables. If you need more detailed information or have specific data, please provide it and I will do my best to assist you.
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what occurs when ice melts? responses a physical change a physical change an atomic compound is newly formed. an atomic compound is newly formed. a nuclear change a nuclear change a chemical change
When ice melts a physical change occur. The correct answer is A.
The capacity to flow gives an ice cube the ability to alter shape as it melts. Its makeup stays the same, though. One instance of a physical change is melting. A physical change is when a sample of matter experiences a change in some of its qualities but not in its identity.
A reversible change in the substance's or object's physical characteristics can be referred to as the physical change. It is a physical change when ice melts. Water (H₂O) appears to alter when it turns from a liquid state to a solid state (ice). However, this shift is just physical, as the constituent molecules still consist of 11.19% hydrogen and 88.81% oxygen by mass.
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what percent of the global atmosphere is carbon dioxide (co2)? lab 5 and other subsequent labs have an emphasis on co2.
The percentage of the global atmosphere is the carbon dioxide that CO₂ is 0.04 %.
The CO₂ that is carbon dioxide makes up the only about 0.04% of the atmosphere, and the water vapor can vary the range from the 0 to 4%. The water vapor is the concentrated lower in atmosphere. The higher will be the greenhouse gas, the more effective will be the trapping heat from the Earth’s surface.
The burning of fossil fuels will affects the concentration of the CO₂ in the earth atmosphere. Before the industrial revolution, the amount of the carbon dioxide in the earth atmosphere was about the 288 ppm.
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if 17.3 g of ammonia is produced by the reaction of 20.2 g of nitrogen with an excess of hydrogen, what is the percent yield of the reaction?
The theoretical yield of the reaction is 17.3 g of ammonia. The percent yield of the reaction is 85.6%.
This means that 85.6% of the theoretical yield of ammonia (17.3 g) was actually produced in the reaction.
The percent yield of a reaction can be calculated by dividing the actual yield of the reaction (in grams) by the theoretical yield (in grams) and multiplying by 100%. This number is a useful metric for determining the efficiency of a reaction, as it tells us how much of the theoretical yield was actually produced in the reaction. Additionally, it can be used to compare the efficiency of different reactions, as it allows us to compare the actual yields of different reactions.
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Comparing the grams of each reactant needed to the number of grams actually used in the lab, the limiting reaction is _______ and the excess reaction is _________.
Answer:
The limiting reactant is the reactant that is completely consumed first in a chemical reaction and the excess reactant is the reactant that remains after the limiting reactant is used up.
how many moles and how many grams of kmno4 are needed to carry out this reaction on 11.4 grams of kno2
0.0451 moles of KMnO4 and 7.18 grams of KMnO4 are required to produce 11.4 grams of KNO3.
The chemical equation for the reaction is
5 KNO₂ + 2KMnO₄ + 3 H₂SO₄ →5 KNO₃ + K₂SO₄ + MnSO₄ + 3 H₂O
From the equation, we see that for every 5 moles of KMnO2, 5 moles of KNO3 are produced, and for every 2 moles of KMnO4, 5 moles of KNO3 are produced.
Determine the number of moles of KNO3 produced, which can be calculated from the mass of KNO3 (11.4 g) and its molar mass (101.1 g/mol):
11.4 g KNO3 / 101.1 g/mol = 0.1129 moles KNO3
Since 5 moles of KMnO2 produce 5 moles of KNO3, 2 moles of KMnO4 produce 5 moles of KNO3.
This means that for every 0.1129 moles of KNO3, 0.1129 moles / (5/2) = 0.0451 moles of KMnO4 are required.
Convert the number of moles of KMnO4 to mass by multiplying by its molar mass (158.0 g/mol):
0.0451 moles KMnO4 * 158.0 g/mol = 7.18 g KMnO4
How do you convert moles to mass?
Multiply the molecular weight by the number of moles for the substance. The molecular weight is the number of grams per mole for the substance and gives the conversion factor for moles to grams for that particular substance.
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7. From the following enthalpy changes,
Xe (g) + F2 (g) → XeF2 (s)
Xe (g) + 2F2 (g) → XeF4 (s)
calculate the value of AH° for the reaction XeF2 (s) + F2 (g) →→→ XeF4 (s).
AH° = -123 kJ
ΔΗ° = -262 kJ
In the standard enthalpy of formation, all the substances are represented in their standard states. The enthalpy of formation for the reaction is -139 kJ.
What is enthalpy of formation?The standard enthalpy of formation of a compound is defined as the enthalpy change accompanying the formation of one mole of the compound from its constituent elements.
In order to calculate the enthalpy of formation of XeF₄, we want XeF₂ on the reactant side. For this reverse the equation (1).
XeF₂ → Xe (g) + F₂ (g) ΔH = 123 J
By reversing, the sign of ΔH change as well.
Xe (g) and F₂ (g) of equation (1) cancels out with Xe and one of the F₂ of equation (2).
Now left is XeF₂ (s) + F₂ (g) → XeF₄ (s)
ΔH = 123 - 262 = -139 kJ
Thus the value of ΔH⁰ is -139 kJ.
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given that a sample of air is made up of nitrogen, oxygen, and argon in the mole fractions , , and , what is the density of air at standard temperature and pressure?
The density of air is1.293 kg/m³
What is density?
this can be defined as the ratio of the mass of a body and its volume.
The S.I unit of density is kg/m³
D = m/v.......(1)
D = density, m = mass, v = volume
(i) Mass of one mole of N₂ = 28 g
Therefore, mass of 0.78 mole of N₂ = 28×0.78 = 21.84 g.
(ii) Mass of one mole of O₂ = 32 g
Therefore, mass of 0.21 mole of O₂ = 32×0.21 = 6.72 g
(iii) Mass of one mole of Ar = 40 g
Therefore mass of 0.01 mole of Ar = 0.01×40 = 0.4 g
m = 21.84 + 6.72 + 0.4 = 28.96 g
One mole of every gas at standard temperature and pressure = 22.4 dm³
Therefore,
(i) volume of 0.78 mole of N₂ = 22.4×0.78 = 17.47 dm³
(ii) volume of 0.21 mole of O₂ = 0.21×22.4 = 4.704 dm³
(iii) volume of 0.01 mole of Ar = 0.01×22.4 = 0.224 dm³
Therefore,
v = 17.47+4.704+0.224
v = 22.398 dm³
Substituting the value of v and m into equation (1)
D = 28.96/22.398
D = 1.293 g/dm³
D = 1.293 kg/m³
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When 16.68 grams of methane (CH4) are burned (see equation below), how many moles of oxygen gas (O2) will be used? Please round your answer to two digits after the decimal point and don't forget units and substance!
CH4 + 2 O2 --> CO2 + 2 H2O
Please help me with this! thank you a bunch in advance!!
When 16.68 grams of methane (CH4) are burned. Therefore, 2.06moles of oxygen gas will be used.
What is mole?A mole is merely a measuring unit. In reality, it is one of the International System of Units' seven foundation units (SI). When basically determines are insufficient, new units are created.
Chemical reactions frequently occur at levels that use grams would be inappropriate, but using actual figures of atoms/molecules/ions could also be misleading. As a result, scientists devised the moles to bridge the divide between extremely small and extremely huge numbers.
CH[tex]_4[/tex] + 2 O[tex]_2[/tex] [tex]\rightarrow[/tex]CO[tex]_2[/tex]+ 2 H[tex]_2[/tex]O
moles of methane = 16.68 /16.04=1.03moles
the mole ratio between methane and oxygen is 1:2
mole of oxygen = 2×1.03=2.06moles
Therefore, 2.06moles of oxygen gas will be used.
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what is the concentration of every ion present in solution made by mixing 25ml of 3m solution of aluminum
The concentration of aluminum ions in the solution made by mixing 25ml of 3M Al solution is determined by the amount of solute present in a given amount of the solvent.
What are aluminum ions?Aluminum ions are positively charged atoms of aluminum that have lost one or more electrons. These ions are important components in many chemical reactions, and they are also used in a variety of industries, such as in the production of aluminum products.
The aluminum ion concentration in the solution formed by combining 25ml of 3M Al solution will be 3M. This is because the amount of solute (in this example, Al) present in a given amount of solvent determines the concentration of the solution (in this case, 25ml of the solution). Because the concentration of the solution is 3M, the concentration of aluminum ions in the solution is also 3M.
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