for ever action forces there is (n) _ forces

Answer:

The new temperature is 200 K.

Explanation:

Charles law gives the relationship between temperature and volume of a gas. It states that volume is directly proportional to temperature such that,

[tex]V\propto T\\\\\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}[/tex]

We have,

[tex]T_1=100\ K\\\\V_1=500\ mL\\\\V_2=1000\ mL\\\\T_2=?[/tex]

Plugging all the values,

[tex]T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{1000\times 100}{500}\\\\T_2=200\ K[/tex]

So, the new temperature is 200 K.

Answer:

500

Explanation:

Answer:

(CH3)3N(aq)

Explanation:

We have to think of the definition of acid and base in the sense of Brownstead-Lowry. The Brønsted–Lowry theory is an acid–base reaction theory which was proposed independently by Johannes Nicolaus Brønsted and Thomas Martin Lowry in 1923.

A Bronsted-Lowry acid is a chemical species that donates one or more hydrogen ions in a reaction. In contrast, a Bronsted-Lowry base accepts hydrogen ions. When it donates its proton, the acid becomes its conjugate base. A more general approach to the theory is viewing an acid as a proton donor and a base as a proton acceptor.

If we look at the reaction closely, we can see that (CH3)3N(aq) accepted a proton. According to the definition above, we will have to classify (CH3)3N(aq) as a base. Hence the answer.

Answer:

THE NEW VOLUME OF THE GAS SAMPLE IS 40 L AT 1 atm AND 400 K

Explanation:

Using general gas equation which combines Boyle's and Charles' law, the volume of the gas sample at the new pressure and temperature can be obtained.

P1V1/T1 = P2V2/T2

P1 = Initial pressure = 2 atm

V1 = Initial volume = 15 L

T1 = Initial temperature = 300 K

P2 = Final pressure = 1 atm

T2 = Final temperature = 400 K

V2 = Final volume = unknown

Substituting the values into the equation, we have;

V2 = P1V1T2 / P2 T1

V2 = 2 * 15 * 400 / 1 * 300

V2 = 12 000/ 300

V2 = 40 L

The new volume after the pressure was reduced to 1 atm and the temperature increased to 400 K is 40 L.

a mushroom

Explanation:

it don't make sense because the tree is not food chain

Answer:

they are both primary producers so i would say they are at the same level, hope this helps

Answer:

Silver (Ag)

Explanation:

The electronic configuration of copper is shown below;

[Kr]4d10 5s1

We can see that there is only one 5s1 electron. Hence Ag^+ tends to display a pseudo noble gas configuration. This pseudo noble gas configuration explains why silver is prevalent in the +1 oxidation state.

The other transition metals have many stable oxidation states found in nature. Chromium is observed both in +3 and +6 oxidation states. Iron is found in +2 and +3 oxidation states and copper is mostly stable in the +2 oxidation state since the +1 oxidation state readily disproportionate.

Hence silver tends to have only a single ionic charge for reasons aptly stated above.

Answer:

Heating the CuSO4. 5H2O crystals causes then to loose the water of crystallisation that is the 5H2O part. It becomes anhydrous copper sulphate. Its colour changes to white from blue.

Answer:

10.28 mol

Explanation:

S + 2O = SO2

(atm x L) ÷ (0.0821 x K)

(3.45 x 45.6) ÷ (0.0821 x 373)

=5.13726

Then round it to significant figures

=5.14

5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)

=10.28 mol O

The number of moles of oxygen atoms in 5.14 moles of SO₂ gas is equal to 10.28 mol.

The ideal gas law is used to describe an equation of the state of an ideal gas. The ideal gas equation can be defined as the product of the volume (V) and the pressure (P) of 1-mole ideal gas is equal to the product of the universal gas constant (R) and absolute temperature.

The ideal gas equation can be expressed in the mathematical form as follows:

PV = nRT

Where n is the moles of a gas, P is the pressure,  V is the volume of the gas,  and R is the universal gas constant.

Given, the volume of sulfur dioxide, V = 45.6 L

The temperature of SO₂ gas, T = 373 K

The universal gas constant, R =0.082 atmL /K mol

The pressure of the SO₂ gas, P = 3.45 atm

Substituting the values R, V, P, and T in the gas law equation, we get:

The number of moles of sulphur dioxide, n = PV/RT

n = 3.45 ×45.6/(0.082 × 373)

n = 5.14 mol

The number of moles SO₂ gas = 5.14

Moles of oxygen atoms in 5.14 moles of SO₂ = 2 × 5.14 = 10.28 mol

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Answer:7

Explanation:

H+ concentration of solutions is related to pH as -

[H+] = antilog(-pH)

For pH = 4,

[H+] = antilog(-4)

[H+] = 10^-4 M

For pH = 10,

[H+] = antilog(-10)

[H+] = 10^-10 M

When these 2 solutions are added, concentration of the mixture will be -

[H+] = √(10^-10 × 10^-4)

[H+] = √(10^-14)

[H+] = 10^-7 M

So now, pH of the mixture will be

pH = -log(10^-7)

pH = 7

Answer:

The increase in mass is not due to the heating but due to the reaction of the metal with oxygen in air to form an oxide

Explanation:

When a metal is heated in the presence of air, oxygen present in air reacts with the metal to form the oxide of the metal. The mass of this oxide is greater than the original metal by the amount of oxygen added to the metal during the reaction.

The above reaction is known as an oxidation reaction. Generally,

metal M + O2 ---> MO2

Answer:

I has 5 valance electrons it wants 10 and 3 bonds

Explanation:

Answer:

Chemical change

Explanation:

Rust cannot be done without using chemicals.

Answer:

Option B.) Chemical Change

Answer:

A meteor shower happens when Earth passes through the path of a comet. When this happens, the bits of comet debris, most no larger than a grain of sand, create streaks of light in the night sky as they burn up in Earth's atmosphere. Bits of debris which enter Earth's atmosphere are called meteors.

Answer:

D.  18,800 J/mol

Explanation:

We need to use the Arrhenius equation to solve for this problem:

[tex]k=Ae^{\frac{-E_a}{RT}[/tex], where k is the rate constant, A is the frequency factor, [tex]E_a[/tex] is the activation energy, R is the gas constant, and T is the temperature in Kelvins.

We want to find the value of [tex]E_a[/tex], so let's plug some of the information we have into the equation. The gas constant we can use here is 8.31 J/mol-K.

At 0°C, which is 0 + 273 = 273 Kelvins, the rate constant k is [tex]4.6*10^{-2}[/tex]. So:

[tex]k=Ae^{\frac{-E_a}{RT}[/tex]

[tex]4.6*10^{-2}=Ae^{\frac{-E_a}{8.31*273}[/tex]

At 20°C, which is 20 + 273 = 293 Kelvins, the rate constant k is [tex]8.1*10^{-2}[/tex]. So:

[tex]k=Ae^{\frac{-E_a}{RT}[/tex]

[tex]8.1*10^{-2}=Ae^{\frac{-E_a}{8.31*293}[/tex]

We now have two equations and two variables to solve for. We just want to find Ea, so let's write the first equation for A in terms of Ea:

[tex]4.6*10^{-2}=Ae^{\frac{-E_a}{8.31*273}[/tex]

[tex]A=\frac{4.6*10^{-2}}{e^{\frac{-E_a}{8.31*273}} }[/tex]

Plug this in for A in the second equation:

[tex]8.1*10^{-2}=Ae^{\frac{-E_a}{8.31*293}[/tex]

[tex]8.1*10^{-2}=\frac{4.6*10^{-2}}{e^{\frac{-E_a}{8.31*273}} }e^{\frac{-E_a}{8.31*293}[/tex]

After some troublesome manipulation, the answer should come down to be approximately:

Ea = 18,800 J/mol

The answer is thus D.

Answer:

N2+O2-> 2NO

Explanation:

An endothermic reaction refers to a reaction in which heat taken in. This implies that heat is usually absorbed by the reaction system. The enthalpy of reaction for an endothermic reaction is always positive.

The triple bond between two Nitrogen atoms in N2 gas is very strong due to its small size and the triple bond thus the nitrogen molecule has a high dissociation energy. This accounts for the large amount of energy required to break the triple bond between nitrogen atoms in the nitrogen molecule. This causes the oxidation of Nitrogen molecule to NO to be largely endothermic.

Answer: 1. [tex]NH_3[/tex] increases.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

[tex]N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)+energy[/tex]

If the concentration of [tex]N_2[/tex] is increased , according to the Le-Chatlier's principle, the reaction has to shift to right or forward direction. In order to do that  the concentration of products has to increase.

Thus the concentration of [tex]NH_3[/tex] increases.

Answer:

0,1 mol

Explanation:

We know that the formula of concentration is C= moles of solute/ volume  

0,4 M= moles of solute/ 250 mL

Convert mL to L      250 mL =0,25 L

0,4 M x 0,25 L= moles of solute

0,1 moles= moles of solute

Answer:

B

Explanation:

I’m not really great at chemistry but I truly tried my best

Answer:

136.36 mL

Explanation:

Here we have to use the dilution formula

From C1V1= C2V2

Where;

C1= initial concentration of the solution= 12.0 M

C2= final concentration of the solution= 2.20 M

V1 = initial volume of the solution= 25.0 ml

V2= final volume of the solution= ?????

Then recall;

C1V1=C2V2

V2 = C1V1/C2

Substituting values from the parameters given;

V2= 12.0 × 25.0 / 2.20

V2= 136.36 mL

Answer:

0 being the lowist 14 being the hieist 0 is the most acidic 14 is the hieist base 7 is nutrol

Explanation:

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14

Answer:

false

Explanation:

Answer:Vinegar Is 5% Acetic Acid And Its Molarity Is 0.833M.

Explanation:

yes

Answer:  3597 kJ of heat

Explanation:

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure of gas = 5.00 atm

V = Volume of gas = 8.00 L

n = number of moles = ?

R = gas constant =[tex]0.0821Latm/Kmol[/tex]

T =temperature =[tex]25.0^0C=(25.0+273)K=298K[/tex]

[tex]n=\frac{PV}{RT}[/tex]

[tex]n=\frac{5.00atm\times 8.00L}{0.0821 L atm/K mol\times 298K}=1.63moles[/tex]

As it is given :

1 mole of propane produces = 2220 kJ of heat

Thus 1.63 moles of propane produces = [tex]\frac{2200}{1}\times 1.63=3597kJ[/tex]

Thus 3597 kJ of heat is produced

Answer:

Option a. = 0.01 M

Explanation:

To do this, we need to gather the data:

E = 2.21 V

[Cl⁻] = 0.1 M

And the Redox reaction taking place is the following:

Zn(s) + Cl₂(g) <-------> Zn²⁺(aq) + 2Cl⁻(aq)       Q = [Zn] [Cl]²

E° Cl⁻/Cl₂ = 1.36 V

E° Zn/Zn²⁺ = -0.76 V

According to this, the expression to use will be the Nernst equation, and we can assume we are working at 25 °C, therefore, the Nernst equation will be:

E = E° - (0.059/n) logQ

E = E° - (0.059/n) ln([Cl⁻]² * [Zn²⁺])   (1)

From there, we can solve for Zn later.

First, we need to write the semi equation of oxidation and reduction, and get the standard potential of the cell:

Zn(s) --------> Zn²⁺(aq) + 2e⁻       E₁° = 0.76 V

Cl₂(g) + 2e⁻ -----------> 2Cl⁻(aq)   E₂° = 1.36 V

---------------------------------------------------------------

Zn(s) + Cl₂(g) -------> Zn²⁺(aq) + 2Cl⁻(aq)    E° = 0.76 + 1.36 = 2.12 V

Now, let's replace in (1) and then, solve for [Zn]:

2.21 = 2.12 - (0.059/2) log ([0.1]² * [Zn])

2.21 - 2.12 = -0.0295 log (0.01[Zn])

- 0.09 / 0.0295 = log (0.01[Zn])

-3.0508 = log (0.01[Zn])

10^(-3.0508) = 0.01[Zn]

8.8961x10⁻⁴ = 0.01[Zn]

[Zn²⁺] = 0.08896 M

This value can be rounded to 0.1 M. so the correct option will be option A.

Answer:

1.

2.

Explanation:

Protons and neutrons are located at the center of an atom which is nucleus .

Electrons will orbit around the nucleus .

Answer:

Explanation:

SO; If we assume that:

P should be the diffusion of oxygen towards the surface ; &

Q should be the  diffusion of carbondioxide away from the surface.

Then  the total molar flux of oxygen is illustrated by :

[tex]Na,x = - cD_{PQ}\frac{dy_P}{dr} +y_P(NP,x + N_Q,x)[/tex]

where;

r is the radial distance from the center of the carbon particle.

Since ;

[tex]N_P,x = - N_Q, x[/tex] ; we have:

[tex]Na,x = - cD_{PQ}\frac{dy_P}{dr}[/tex]

The system is not steady state and the molar flux is not independent of r because the area of mass transfer [tex]4\pi r^{2}[/tex] is not a constant term.

Therefore,  using quasi steady state assumption, the mass transfer rate   [tex]4\pi r^{2}N_{P,x}[/tex] is assumed to be independent of r at any instant of time.

[tex]W_{P}=4\pi r^{2}N_{P,x}[/tex]

[tex]W_{P}=-4\pi r^{2}cD_{PQ}\frac{dy_{P}}{dr}[/tex]        

       = constant

The oxygen concentration at the surface of the coal particle [tex]yP,R[/tex] will be calculated from the reaction at the surface.

The mole fraction of oxygen at a location far from pellet is 1.

Thus, separating the variables and integrating result into  the following:

[tex]W_{P}\int_{R}^{\infty} \frac{dr}{r^{2}}=-4\pi[/tex]

[tex]r^{2}cD_{PQ}\int_{y_{P,R}}^{y_{P,\infty }}dy_{P}[/tex]

[tex]-W_{P}\frac{1}{r}\mid ^{\infty }_{R}= -4\pi cD_{PQ}(y_{P,\infty }-y_{P,R})[/tex]

[tex]=> W_{P}= - 4\pi cD_{PQ}(1-y_{P,R})R[/tex]

The mole of oxygen arrived at the carbon surface is equal to the mole of oxygen consumed by the chemical reaction.

[tex]W_{P} = 4 \pi R^2R"[/tex]

[tex]W_{P}= 4\pi R^{2}k_{1}"C_{O_{2}}\mid _{R}[/tex]

[tex]W_{P}= 4\pi R^{2}k_{1}"c y _{P,R}[/tex]

[tex]-4\pi cD_{PQ}(1-y_{P,R})R= - 4\pi R^{2}k_{1}"c y _{P,R}[/tex]

[tex]y_{P,R}=\frac{D_{PQ}}{D_{PQ}+Rk_{1}}[/tex]

[tex]y_{P,R}=\frac{1.7 \times 10^{-4}}{1.7\times 10^{-4}+10^{-3}\times 0.1}[/tex]

[tex]\mathbf{= 0.631}[/tex]

Obtaining the total gas concentration from the ideal gas law; we have the following:

where;

R= [tex]0.082m^3atm/kmolK[/tex]

[tex]c=\frac{P}{RT} \\ \\ c=\frac{1}{0.082\times 1450} \\ \\ = 0.008405kmol/m^3[/tex]

The steady state [tex]O_2[/tex] molar consumption rate is:

[tex]W_{P}= -4\pi cD_{PQ}(1-y_{P,R})R[/tex]

[tex]W_{P}= -4\pi (0.008405)(1.7\times 10^{-4})(1-0.631)(10^{-3})[/tex]

[tex]W_{P}= - 6.66\times 10^{-9}kmol/s[/tex]

Answer: the line Spectra of hydrogen lies between the ultra-violet, visible light and infra-red of the electro magnetic spectrum

Explanation:

Electromagnetic radiation spans an wide range of wavelengths and frequencies. This range is called the electromagnetic spectrum. The electromagnetic spectrum is generally divided into seven regions, in order of decreasing wavelength and increasing energy and frequency. The 7 regions includes; radio waves, microwaves, infrared (IR), visible light, ultraviolet (UV), X-rays and gamma rays.

lower-energy radiation, such as radio waves, is expressed as frequency while microwaves, infrared, visible and UV light are usually expressed as wavelength and finally, higher-energy radiation such as X-rays and gamma rays, is expressed in terms of energy per photon.

Therefore, hydrogen lies between the ultra-violet, visible light and infra-red region of the electro magnetic spectrum.

Answer energy,mass,speed of light

Explanation:

Edge

Answer

energy, mass, speed of light

Explanation:

Edge2020

Answer: The time for activity to fell from 800 counts per second to 200 counts per second is 20 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for finding the rate constant:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]

[tex]k=\frac{0.693}{10min}=0.0693min^{-1}[/tex]

b) for activity to fell from 800 counts per second to 200 counts per second.

[tex]t=\frac{2.303}{0.0693}\log\frac{800}{200}[/tex]

[tex]t=20minutes[/tex]

The time for activity to fell from 800 counts per second to 200 counts per second is 20 minutes

Answer:

Because you don't want 2 different things mixing together unless their supposed to be mixed together

Explanation:

The hand cream used as a separating agent when the flubber was handled because it is not about 2 different things mixing together unless their supposed to be mixed together.

What is separating agent ?

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