The problem involves finding a constant c that makes each given function a valid probability mass function given are f(x) = x/c, x=1,2,3,4; f(x) = cx, x=1,2,3,...,10; f(x) = c(x+1)², x=0,1,2,3; f(x) = x/c, x=1,2,3,...,n; f(x) = (x+1)(x+2)/[x(x+3)], x=0,1,2,3,...
(a) We know that the sum of all the probabilities in a pmf must be equal to 1.
Therefore, we have:
1/c + 2/c + 3/c + 4/c = 1
Solving for c, we get:
c = 10
The pmf can be depicted as:
x f(x)
1 0.1
2 0.2
3 0.3
4 0.4
(b) Again, we know that the sum of all the probabilities in a pmf must be equal to 1. Therefore, we have:
c(1 + 2 + 3 + ... + 10) = 1
Solving for c, we get:
c = 1/55
The pmf can be depicted as:
x f(x)
1 1/55
2 2/55
3 3/55
... ...
10 10/55
(d) We can use the same approach as in part (a) to find c:
c(1 + 4 + 9) = 1
Solving for c, we get:
c = 1/14
The pmf can be depicted as:
x f(x)
0 1/14
1 1/6
2 1/3
3 4/14
(e) Similar to part (a), we have:
1/c + 2/c + 3/c + ... + n/c = 1
Solving for c, we get:
c = (n+1)n/2
The pmf can be depicted as:
x f(x)
1 1/(n+1)
2 2/(n+1)
3 3/(n+1)
n n/(n+1)
(f) We can use the hint given in the problem:
f(x) = 1/(x + 1) - 1/(x + 2)
We can see that this is a telescoping series, where all terms cancel out except for the first and the last term. Therefore, we have:
f(0) = 1/1 - 1/2 = 1/2
f(1) = 1/2 - 1/3 = 1/6
f(2) = 1/3 - 1/4 = 1/12
f(3) = 1/4 - 1/5 = 1/20
The pmf can be depicted as:
x f(x)
0 1/2
1 1/6
2 1/12
3 1/20
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Homework
Question 13, 3.3.31
HW Score: 75%, 12 of 16 points
O Points: 0 of 1
The larger number is and the smaller number is
The sum of two numbers is 1. Three times the larger number plus two times the smaller number is 18. Find the numbers.
mryn Latham
Clear all
Sa
Check answer
The larger number is 16 and the smaller number is -15.
How to obtain the numbers?The numbers are obtained by a system of equations, for which the variables are given as follows:
x and y.
The sum of two numbers is 1, hence:
x + y = 1.
y = 1 - x.
Three times the larger number plus two times the smaller number is 18, hence:
3x + 2y = 18.
Replacing the first equation into the second, the value of x is obtained as follows:
3x + 2(1 - x) = 18
3x + 2 - 2x = 18
x = 16.
Then the value of y is of:
y = 1 - x
y = 1 - 16
y = -15.
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1 a tobacco company produces blends of tobacco, with each blend containing various proportions of turkish, domestic, and other tobaccos. the proportions of turkish and domestic in a blend are random variables with joint density function (x
(a) 0.5, (b) f_Y(y) = 12y(1-y), (c) 9/128, (d) 7/36 - Probability calculations using joint density function.
(a) To find the Probability that the Turkish tobacco represents over a portion of the mix, we want to incorporate the joint thickness capability over the district where x > 0.5 and y < 1 - x. This gives:
P(X > 0.5) = ∫[0.5,1]∫[0,1-x] 24xy dy dx = 0.5
Consequently, the Probability that the Turkish tobacco represents over around 50% of the mix is 0.5.
(b) To find the negligible thickness capability for the extent of homegrown tobacco, we really want to incorporate the joint thickness capability over all potential upsides of Turkish tobacco:
f_Y(y) = ∫[0,1-y] 24xy dx = 12y(1-y) ; 0 < y < 1
Thusly, the peripheral thickness capability for the extent of homegrown tobacco is f_Y(y) = 12y(1-y).
(c) To find the Probability that the extent of Turkish tobacco is under 1/8 given that the mix contains 3/4 homegrown tobacco, we really want to utilize Bayes' standard:
P(X < 1/8 | Y = 3/4) = P(X < 1/8 ∩ Y = 3/4)/P(Y = 3/4)
We can find the numerator by coordinating the joint thickness capability over the district where x < 1/8 and y = 3/4:
∫[0,1/8] 24xy dx = 27/128
To find the denominator, we coordinate the joint thickness capability over all potential upsides of Turkish tobacco when y = 3/4:
∫[0,1/4] 24xy dx = 3
Thusly, the contingent Probability is:
P(X < 1/8 | Y = 3/4) = (27/128)/3 = 9/128
(d) To find the likelihood that the extent of homegrown tobacco is over two times the extent of the Turkish tobacco, we want to incorporate the joint thickness capability over the area where y > 2x and x + y < 1. This gives:
P(Y > 2X) = ∫[0,1/3]∫[2x,1-x] 24xy dy dx + ∫[1/3,1/2]∫[2x,1-x] 24xy dy dx
= 7/36
Accordingly, the likelihood that the extent of homegrown tobacco is over two times the extent of the Turkish tobacco is 7/36
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The complete question is:
A tobacco company produces blends of tobacco, with each blend containing various proportions of Turkish, domestic, and other tobaccos. The proportions of Turkish and domestic in a blend are random variables with joint density function (X = Turkish and Y = domestic) 24xy ;0< x, y < 1, x +y<1 fx.y(1,7) (2) ; otherwise (a) (1 point) Find the probability that in a given box the Turkish tobacco accounts for over half the blend. Page 2 (b) (1 point) Find the marginal density function for the proportion of the domestic tobacco. (c) (1 point) Find the probability that the proportion of Turkish tobacco is less than 1/8 if it is known that the blend contains 3/4 domestic tobacco. (d) (2 points) Find the probability that the proportion of domestic tobacco is more than twice the proportion of the Turkish tobacco.
7.8143
whole number what’s is it rounded up to whole number
The rounded numbers for the given decimal numbers are 4, 8 and 9.
What is rounding a number?To change a number into an approximation having fewer significant digits, is called the rounding numbers.
For example :- Round off 15.4 to 15, round off 15.51 to 15.5 or to 16, round off 0.499 to 0, and round off 970,000 to 1 million.
Given are three decimal numbers, 3.896, 7.8143 and 9.3959 we are asked to round them to whole number.
The rule for rounding the numbers is :-
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.Example: 38 rounded to the nearest ten is 40.
If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.Example: 33 rounded to the nearest ten is 30.
Therefore, in 3.896, the number after the decimal is 8 which is greater than 5 so rounding up we will get, 4
Similarly, 7.8143 = 8
And in 9.3959, the number after the decimal is 3 which is smaller than 5 so rounding down we will get, 9
Hence, the rounded numbers for the given decimal numbers are 4, 8 and 9.
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Assessment Practice
14. Write the unit fraction that represents 1 square.
Then write the fraction that represents the
whole. Select numbers from the box to write
the fractions. Numbers may be used once, more than
once, or not at all. 3.FR.1.1
12 3 4 5 6 7 8
1 square:
Whole:
The unit fraction is given by A = 2/2 and the whole number is represented by B = 4/2 = 2
What is a Fraction?An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.
Given data ,
Let the first fraction be represented as A
Now , the unit fraction is a fraction which has the value of 1
And , the numbers are represented by set S = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 }
The unit fraction A = 1/1 = 2/2 = 3/3
Let the whole fraction be represented as B
Now , the value of B is
B = 4/2 = 2
B = 6/3 = 2
Therefore , the value of A and B are 1/1 and 4/2 respectively
Hence , the fractions are solved
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Grayson loves to draw he has filled 3 times as many sketchbooks with drawings at home as he has filled at school
He had 48.75 oz of salsa.
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.
here, we have,
I guess that Clay is filling 6.5 oz bottles of salsa.
And we know that he was able to fill 7.5 of these bottles,
then if each bottle has 6.5 oz, 7.5 of them have a total mass of salsa will be equal to 7.5 times 6.5 ounces,
this is:
M = 7.5*6.5 oz = 48.75 oz
This means that Clay had 48.75 ounces of Salsa
A drawn model to show this is seen below.
Each big square represents 0.5 oz,
and the area black delimited area represents a total amount of 6.5 oz, we have 7 of them, then you can draw that 7 times,
and count the squares,
and then you will find the total ounces of salsa that Clay had, which is equivalent to the multiplication we did above.
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- 360 = (-9(6x - 8)
Color blindness is a gender-linked inherited condition that s much more common among men than women. Suppose that 5% of all men and 0.4% of all women are color-blind. A person is chosen at random and found to be color-blind. What is the probability that the person is male. (You may assume that 50% of the population are men and 50% are women).
Given that the person is colorblind, the likelihood that they are male is around 0.926, or 92.6%.
As per the question given,
Let's use Bayes' theorem to solve this problem.
Let M be the event that the person is male, and C be the event that the person is color-blind. We want to find the probability P(M|C), which is the probability that the person is male given that they are color-blind.
Using Bayes' theorem, we have:
P(M|C) = P(C|M) * P(M) / P(C)
We know that P(M) = 0.5, since 50% of the population are men. We also know that P(C|M) = 0.05, since 5% of men are color-blind. To find P(C), we can use the law of total probability:
P(C) = P(C|M) * P(M) + P(C|F) * P(F)
where F is the event that the person is female. We know that P(F) = 0.5, since 50% of the population are women, and we also know that P(C|F) = 0.004, since 0.4% of women are color-blind.
Substituting the values into Bayes' theorem, we have:
P(M|C) = 0.05 * 0.5 / (0.05 * 0.5 + 0.004 * 0.5)
= 0.926
Therefore, the probability that the person is male given that they are color-blind is approximately 0.926, or 92.6%.
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consider a manufacturing process that is producing hypodermic needles that will be used for blood donations. these needles need to have a diameter of 1.65 mm. needles that are too large hurt the donor and needles that are too small will rupture the red blood cells, making the sample unusable. this means that the manufacturing process needs to be closely monitored to detect any significant changes from the desired diameter of 1.65 mm. during every shift, a random sample is taken of several needles and diameters are measured. if a problem is discovered, the manufacturing is stopped until it is corrected. suppose the most recent random sample of 35 needles have an average diameter of 1.64 mm and a standard deviation of 0.07 mm. also suppose the diameters of needles produced by this manufacturing process have a bell-shaped distribution.
Type 1 error is rejecting the null hypothesis, even when we know it is true. Here the average diameter is 1.65mm, but we decide that it is not 1.65mm.
The data which given says that the average diameter should be 1.65mm. Bigger and smaller diameters may result in problems like pain and rupture of RBCs.
So the null and alternate hypothesis are
Null hypothesis , H₀ : μ= 1.65 mm
Alternate hypothesis, H₁ : μ≠ 1.65 mm
Here the sample size, n= 35, σ = 0.07, mean = 1.64
Type 1 error means rejecting null hypothesis, when it is true. It is also known as false positive error. A false positive can occur if something other than the stimuli applied during the test is resulting the outcome. This cannot be avoided because of the degree of uncertainty involved.
In type 1 error, we assume that the null hypothesis, H₀ : μ=1.65 is false, that means the average diameter is not 1.65 mm, even if the actual diameter is 1.65 mm.
Se decide average diameter is not 1.65 mm.
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if v ~w if defiened by the equation v~w=(2vw)^2 - (v+w)^3, what is 5~3
Answer:
Step-by-step explanation:
To find 53 using the equation vw=(2vw)^2 - (v+w)^3, we need to substitute v=5 and w=3 into the equation:
5~3 = (2(5)(3))^2 - (5+3)^3
Simplifying:
5~3 = (30)^2 - (8)^3
5~3 = 900 - 512
5~3 = 388
Therefore, 5~3 is equal to 388.
16 Answer:
For what values of the variable x is the rational
expression undefined: 3/(x - 5)
17 Answer:
For what values of the variable x is the rational
expression undefined: 8/(x + 2)
Answer:
16. The rational expression 3/(x-5) is undefined when x equals 5.
17. The rational expression 8/(x+2) is undefined when x equals -2.
Step-by-step explanation:
16.
The rational expression 3/(x-5) is undefined when the denominator (x-5) is equal to zero, because division by zero is undefined. Therefore, we need to find the values of x that make the denominator zero.
To find those values, we can set the denominator equal to zero and solve for x:
x - 5 = 0
x = 5
Therefore, the rational expression 3/(x-5) is undefined when x equals 5.
17.
The rational expression 8/(x+2) is undefined when the denominator (x+2) is equal to zero, because division by zero is undefined. Therefore, we need to find the values of x that make the denominator zero.
To find those values, we can set the denominator equal to zero and solve for x:
x + 2 = 0
x = -2
Therefore, the rational expression 8/(x+2) is undefined when x equals -2.
Each unit on the map represents 1 mile. To the nearest tenth of a mile, what is the distance from the library to the park?
Answer:
Step-by-step explanation:
If you are using both y & x they are easy to find
distance from 9 and 2 is seven units and the distance from each other
3 & 2 are one unit hoped it helped you so you can find the miles
URGENT HELP
WRITE A SIMILARITY STATEMENT
RELATING THE THREE RIGHT TRIANGLES.
Complete each proportion
The similarity statement is ΔRSP ≈ ΔRSQ ≈ ΔPRQ.
The proportions are:
QS/QR = QR/PQ
SP/SR = RS/QS
What is triangle congruency?There are ways to prove that two triangles are congruent.
- Side-Side-Side (SSS) Congruence.
The three sides of one triangle are equal to the corresponding three sides of another triangle.
- Side-Angle-Side (SAS) Congruence.
The two sides and the included angle of one triangle are equal to the corresponding two sides and included angle of another triangle.
- Angle-Side-Angle (ASA) Congruence.
The two angles and the included side of one triangle are equal to the corresponding two angles and included side of another triangle.
- Angle-Angle-Side (AAS) Congruence.
The two angles and a non-included side of one triangle are equal to the corresponding two angles and a non-included side of another triangle.
We have,
From the figure,
We have,
Three right triangles:
ΔRSP, ΔRSQ, and ΔPRQ
So,
ΔRSP ≈ ΔRSQ ≈ ΔPRQ
Now,
From ΔRSP and ΔPRQ.
Corresponding sides are considered.
QS/QR = QR/PQ
And,
From ΔRSP and ΔRSQ.
Corresponding sides are considered.
SP/SR = RS/QS
Thus,
The similarity statement is ΔRSP ≈ ΔRSQ ≈ ΔPRQ.
The proportions are:
QS/QR = QR/PQ
SP/SR = RS/QS
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A binomial experiment consists of 12 trials. The probability of success on trial 5 is 0.85. What is the probability of failure on trial 9?
0.17
0.72
0.64
0.9
0.15
0.44
The probability of failure on the trial 9 for the given binomial experiment is 0.15.
What is binomial experiment?An experiment with a set number of independent trials and just two results is referred to as a binomial experiment. The results of these experiments can be classified as either successes or failures. Due to the nature of the experiment's subject, results may only be categorised as successes or failures.
Due to the set number of outcomes that might occur in each experiment's trial, binomial experiments are unique from other types of studies. Binomial experiments, in particular, can only ever produce one of two outcomes.
The probability of success and failure of a trial is same for every number of trials.
Given that,
n = 12 trials
Success = 0.85
The failure is given as:
failure = 1 - success of trial
failure = 1 - 0.85
failure = 0.15
Hence, the probability of failure on the trial 9 for the given binomial experiment is 0.15.
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Allins test scores are shown below
88,90,35,92,82,90
PART A (what is the mean, median,mode,and range of his scores.what is the outlier in the data set?
Answer:
The only score that falls outside of this range is 35, so that is the outlier.
Step-by-step explanation:
To find the mean of Allins test scores, we add up all the scores and divide by the number of scores:
Mean = (88+90+35+92+82+90)/6 = 77.83 (rounded to two decimal places)
To find the median, we need to arrange the scores in order from least to greatest:
35, 82, 88, 90, 90, 92
The median is the middle value, which in this case is 89.
To find the mode, we look for the value that appears most frequently. In this case, the mode is 90, since it appears twice.
To find the range, we subtract the lowest score from the highest score:
Range = 92 - 35 = 57
To identify the outlier in the data set, we can use the interquartile range (IQR) and the rule that any data point more than 1.5 times the IQR below the first quartile or above the third quartile is considered an outlier.
First, we need to find the quartiles:
Q1 (first quartile) = 80 (the median of the lower half of the data set)
Q3 (third quartile) = 91 (the median of the upper half of the data set)
IQR = Q3 - Q1 = 11
Any data point more than 1.5 times the IQR below Q1 or above Q3 is considered an outlier.
Lower outlier threshold = Q1 - 1.5(IQR) = 63.5
Upper outlier threshold = Q3 + 1.5(IQR) = 107.5
The only score that falls outside of this range is 35, so that is the outlier.
how does null hypothesis statistical testing works
When a research is conducted on a randomly chosen representative sample, hypothesis testing involves gathering data and calculating how likely a specific set of data is. No connection exists between the factors.
What three categories of hypothesis testing are there?The t test is the most used null test for this statistical connection. Only one t test, the reliant t test, as well as the individual t test are three different t test types that are examined in this section and are used to a variety of study methods.
In hypothesis testing, what does p-value mean?The probability that you would have discovered a certain collection of data if the null hypothesis had been correct is expressed as a number called the p value, which is determined from a statistical test. In order to determine either to reject a null hypothesis, P values are utilized in hypothesis testing.
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Question 2 of 10
Which value of x is in the domain of f(x)=√x-11?
O A. x= 13
OB. x= 10
OC. x= -4
OD. X=0
The value of x in the domain of function f(x) = √(x - 11) will be 13. Then the correct option is A.
What is a function?A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.
The domain means all the possible values of x and the range means all the possible values of y.
The function is given below.
f(x) = √(x - 11)
The value inside the square root should be greater than or equal to zero. Then we have
x - 11 ≥ 0
x ≥ 11
The value of x in the domain of function f(x) = √(x - 11) will be 13. Then the correct option is A.
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Given the following historical data and weights of 0.5, 0.3, and 0.2, what is the three-period weighted moving average forecast for period 5? reriodValue 1 142 146 144 148 4 A. 145.80 B. 146.40 C. 145.00 D. 146.00 E. 148.00
The three-period weighted moving average forecast for period 5 is option (B) 146.4.
In forecasting, the weighted moving average method is commonly used to estimate future values by giving more weight to the recent observations than the older ones.
To calculate the three-period weighted moving average, we need to apply the given weights of 0.5, 0.3, and 0.2 to the last three periods' data. The formula for calculating the weighted moving average is:
Weighted Moving Average = (w₁Y₁) + (w₂Y₂) + (w₃*Y₃)
where w₁, w₂, and w₃ are the weights assigned to the most recent period, second most recent period, and third most recent period, respectively. Y₁, Y₂, and Y₃ are the corresponding values of the periods.
Applying this formula to the given data, we get:
Weighted Moving Average = (0.5148) + (0.3144) + (0.2*146)
= 74 + 43.2 + 29.2
= 146.4
Therefore, the correct option is (B).
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Kristen gets home from work at 5:34p.m. Kristen's dinner is ready at 5:15 p.m
How many seconds after Kristen gets home is her dinner ready?
After 1020 sec Kristen get her Dinner ready.
What is Unit Conversion?The same attribute is expressed using a unit conversion, but in a different unit of measurement.
For instance, time can be expressed in minutes rather than hours, and distance can be expressed in kilometres, feet, or any other measurement unit instead of miles.
Subtract Kristen's arrival time from the time her food is ready to get the number of seconds she needs to wait before eating.
So,
5 :51 pm - 5: 34 pm = 17 min
As, 1 minute = 60 minute
So, 17 minutes
= 17(60)
= 1020 sec
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what is the range for the following set of scores? 6,12,9,17,11,4,14. The range value is ___ works particularly well for Another valid range value is___ commonly used with (a. variables with precisely defined upper and lower bounds. b. measurements of continuous variable)
Another valid range value for this set of scores is 8, which is the interquartile range.
The range is a measure of the spread or variability of a dataset, and it is calculated as the difference between the largest and smallest values in the set. To find the range for the given set of scores, we first need to order the numbers from smallest to largest:
4, 6, 9, 11, 12, 14, 17
The smallest value in the set is 4, and the largest value is 17, so the range is:
17 - 4 = 13
Therefore, the range for the given set of scores is 13.
The range is a useful measure of variability that is simple to calculate and easy to interpret. However, it has a limitation in that it is sensitive to extreme values or outliers in the dataset. As a result, it may not always provide an accurate representation of the spread of the data.
Another measure of range that works particularly well for variables with precisely defined upper and lower bounds is the interquartile range (IQR). The IQR is calculated as the difference between the 75th percentile (Q3) and the 25th percentile (Q1) of the dataset. It is commonly used with measurements of continuous variables and is less sensitive to extreme values than the range.
To calculate the IQR, we first need to find the median of the dataset. The median is the middle value when the numbers are arranged in order:
4, 6, 9, 11, 12, 14, 17
The median is 11.
Next, we need to find the first and third quartiles. The first quartile (Q1) is the median of the lower half of the dataset, and the third quartile (Q3) is the median of the upper half of the dataset. To find Q1 and Q3, we split the dataset into two halves:
Lower half: 4, 6, 9, 11
Upper half: 12, 14, 17
The median of the lower half is:
(6 + 9) / 2 = 7.5
The median of the upper half is:
(14 + 17) / 2 = 15.5
Therefore, the first quartile (Q1) is 7.5 and the third quartile (Q3) is 15.5.
The interquartile range (IQR) is the difference between Q3 and Q1:
IQR = Q3 - Q1 = 15.5 - 7.5 = 8
Therefore, another valid range value for this set of scores is 8, which is the interquartile range.
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Sulin had a sum of money. She spent 1/5 of it in January,1/4 of it in February and $220 in March. After spending these amounts of money, she still had $110 left. How much money did she have at first?
Please help select all orders pairs that are a solution for the function y=-8x+6?
Answer:
Step-by-step explanation:
since y = -8x + 6
if x=-10, y=-8x10+6=-74, so A is not the solution
if x =-8, y=-8x(-8)+6=70, so B is not the solution
if x =5, y=-8x5+6=-34, so C is the solution
if x =3, y=-8x3+6=-18, so D is not the solution
A committee must be formed with 5 teachers and 4 students. If there are 11 teachers to choose from, and 14 students, how many different ways could the committee be made?
Answer:
there are 462,462 different ways the committee can be formed.
Step-by-step explanation:
To form the committee, we need to choose 5 teachers out of 11 and 4 students out of 14. We can use the combination formula to find the number of ways:
Number of ways to choose 5 teachers out of 11:
C(11, 5) = 11! / (5! * 6!) = 462
Number of ways to choose 4 students out of 14:
C(14, 4) = 14! / (4! * 10!) = 1001
The total number of ways to form the committee is the product of these two combinations:
462 * 1001 = 462462
Therefore, there are 462,462 different ways the committee can be formed.
The average amount of time, in minutes, for students to complete a standardized test is normally distributed. A data analyst takes a sample of n =49 student times and finds a 90% confidence interval to be[116.8,149.2] What is the population parameter? What is the interpretation of the confidence interval?
The Population parameter is population mean i.e μ. The Interpretation of 90% confidence that population mean i.e μ lies between 116.8 and 149.2.
We have, a Normalised average amount of time, in minutes, data for students to complete a standardized test.
Sample size, n = 49
Significance level, = 90% = 0.90
Confidence interval is range of values. It is calculated by below formula, confidence interval,
CI = Mean ± Z( standard deviations/sample size)
but we have, the 90% confidence interval is equals to [116.8,149.2]. The population is a large set and it is deficult to work on population, so sample subsets of it are considered for observation. Population parameter is population mean. The interpretation from provide informations about 90% of confidence interval is that population mean lie between 116.8 and 149.2, i.e., 116.8 ≤ μ ≤149.2.
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Adam tried to write 4 + 5x² +4 as a product of linear factors. This is his work:
2*+5 +4
= (x² + 4)(x² + 1)
= (x² + 4)(x + i)(x − i)
= (x+i√2)(x − i√2)(x+i)(x-i) Step 3
In what step did Adam make his first mistake?
Adam makes his first mistake in the first step. And the product of linear factors will be (√5x - 2i √2) and (√5x + 2i√2).
What is factorization?It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.
The expression is given below.
⇒ 4 + 5x² + 4
Simplify the expression, then we have
⇒ 5x² + 8
Factorize the expression, then we have
⇒ 5x² + 8
⇒ (x√5)² - (2i √2)²
⇒ (√5x - 2i √2) (√5x + 2i√2)
Adam makes his first mistake in the first step. And the product of linear factors will be (√5x - 2i √2) and (√5x + 2i√2).
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suppose that f(x), g(x), and h(x) are functions such that f(x) is o(g(x)) and g(x) is o(h(x)). show that f(x) is o(h(x)).
If f(x), g(x), and h(x) are functions such that f(x) is θ(g(x)) and g(x) is θ(h(x)), it is shown that f(x) is θ(h(x)).
Since f(x) is θ(g(x)), there exist constants A, B > 0 such that
A × g(x) < f(x) < B × g(x) for sufficiently large x.
Similarly, since g(x) is θ(h(x)), there exist constants C, D > 0 such that
C × h(x) < g(x) < D × h(x) for sufficiently large x.
Hence, for a sufficiently large x, we have
f(x) < B g(x) < B × (D × h(x)) = (BD) h(x), and
f(x) > A g(x) > A × (C × h(x)) = (AC) h(x).
Hence, we have constants E, F > 0 (where E = AC and F = BD) such that
E × h(x) < f(x) < F × h(x) for sufficiently large x.
Therefore, f(x) is θ(h(x)).
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Find the value of the constant that makes the following function continuous on (−∞,∞).
The piecewise function is continuous only if a = 2.
Which must be the value of the constant a?The function will be continuous if both parts of the function have the same value on the "jump" between the two parts.
The first part evaluated in x = 1 is:
f(x) = (4x^3 - 4x)/(x - 1)
We can rewrite the numerator as:
(4x^3 - 4x) = 4x*(x^2 - 1) = 4x*(x + 1)*(x - 1)
Then we can rewrite the function as:
f(x) = 4x*(x + 1)
Evaluating in x = 1 we will get:
f(1) = 4*1*(1 + 1) = 8
Then the other piece evaluated in x = 1 also must be equal to 8, we will get:
f(x) = 4x^2 + 2x + a
f(1) = 4*1^2 + 2*1 + a = 8
= 4 + 2 + a = 8
a = 8 - 4 - 2 = 2
The value of a must be 2.
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Which figure repeats in the tessellation shown below?
• A. Figure B
• B. Figure C
• C. Figure A
• D. Figure D
The figure repeats in the tessellation is Figure B, the correct option is A
What is a regular tessellation?
A regular tessellation is a pattern made by repeating a regular polygon. In simpler words regular tessellations are made up entirely of congruent regular polygons all meeting vertex to vertex.
How many regular tessellation are possible?
There are only 3 regular tessellation.
1. Triangle
2. Square
3. Hexagon
Given;
The figure
Not more than 3 regular tessellations are possible because the sums of the interior angles are either greater than or less than 360 degrees;
Therefore, repeated tessellation will be B.
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the following data has been recorded regarding the rental history of a high pressure cleaner. find the expected demand for the high pressure cleaner. demand frequency 0 20 1 23 2 27 3 14 4 16
The expected demand for the high-pressure cleaner is 1.86.
Frequency distribution is a statistical tool that organizes data into different categories and shows how often each category occurs. In this case, the demand for a high-pressure cleaner is the category, and the number of times it occurs is the frequency.
To calculate the expected demand, we need to first find the relative frequency of each demand level. The relative frequency is the percentage of the total number of demands accounted for by each demand level. We can calculate the relative frequency by dividing the frequency of each demand level by the total number of demands.
Total number of demands = 20 + 23 + 27 + 14 + 16 = 100
Relative frequency of demand level 0 = 20/100 = 0.20
Relative frequency of demand level 1 = 23/100 = 0.23
Relative frequency of demand level 2 = 27/100 = 0.27
Relative frequency of demand level 3 = 14/100 = 0.14
Relative frequency of demand level 4 = 16/100 = 0.16
Next, we multiply each demand level by its relative frequency and add the products to get the expected demand.
Expected demand = (0 × 0.20) + (1 × 0.23) + (2 × 0.27) + (3 × 0.14) + (4 × 0.16)
=> 1.86
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Complete Question:
The following data has been recorded regarding the rental history of a high pressure cleaner. Find the expected demand for the high pressure cleaner.
Demand Frequency
0 20
1 23
2 27
3 14
4 16
Help me with the square roots please, meaning by simplify the equation
The simplification of the given expression
[tex]5 \sqrt[3]{250} - 3 \sqrt[3]{686} [/tex]
is
[tex] = 4 \sqrt{2} [/tex]
How to simplify expressions?[tex]5 \sqrt[3]{250} - 3 \sqrt[3]{686} [/tex]
[tex] = 5 \sqrt[3]{125 \times 2} - 3 \sqrt[3]{343 \times 2} [/tex]
[tex] = 5 \times 5 \sqrt{2} - 3 \times 7 \sqrt{2} [/tex]
[tex] = 25 \sqrt{2} - 21 \sqrt{2} [/tex]
[tex] = 4 \sqrt{2} [/tex]
Consequently,
[tex]4 \sqrt{2} [/tex]
is the answer to the given expression.
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The length of a rectangular poster is 4 more inches than three times its width. The area of the poster is 340 square inches. Solve for the dimensions (length and width) of the poster.
31 in by 31/4 in is the required dimension of the poster
Determining the area of a rectangleThe formula for calculating the area of a rectangle is expressed as:
A = lw
If the length of a rectangular poster is 4 more inches than three times its width, then;
l = 3w - 4
Substitute
340 = w(3w - 4)
340 = 3w^2 - 4w
3w^2 - 4w - 340 =0
On factorizing, the measure of the width of the poster is 34/3 in
l = 3w - 4
l = 3(34/3) - 4
l = 31in
Hence the dimension of the given poster is 31 in by 31/4 in
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