For each name, draw the structure.
a) (E)-5-Methyl-2-hexene
b) (S)-1,1,2-Trichloro-2-fluoroethane
c) 2,5-Diethyl-1-methylcyclohexanol

Answer:

Yes, it will be enough.

Explanation:

We can calculate the heat (Q) required to heat 1.00 kg of water from 30°C to 93°C using the following expression.

Q = cp × m × ΔT

where,

Q = cp × m × ΔT

Q = 4.18 J/g°C × 1.00 × 10³ g × (93°C-30°C)

Q = 263 kJ

Since 263 kJ are necessary, 290.0 kJ will be enough to heat the water.

The energy is sufficient to raise the temperature of the water to its boiling point.

We have the following information from the question;

Boiling point of water =  93°C

Mass of water = 1.00 kg or 1000 g

Heat capacity of water = 4.18 J/g · °C

Heat absorbed by water = 290.0 kJ or 290000 J

Initial temperature of the water = 30°C

Using the formula;

ΔH = mcθ

ΔH = Heat absorbed by the water

m = mass of the water

c = heat capacity of the water

θ = temperature rise (T2 - T1)

Substituting values;

290000 J = 1000 g × 4.18 J/g · °C (T2 - 30°C)

290000  = 4180T2 - 125400

T2 = 290000 + 125400/4180

T2 = 99.3°C

The energy is sufficient to raise the temperature of the water to its boiling point.

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Answer:

The components that a cell can contain are

Answer:

e. C₃H₈(g)

Explanation:

Standard entropy is the absolute  entropy of a substance at 1 atm and 25°C.

For  different substances in the same phase, molecular complexity determines which ones have higher entropies.

Consider the gases CH₄, C₂H₂, C₂H₄, C₂H₆, C₃H₈. Propane (C₃H₈) has a more complex structure and hence more ways to execute molecular motions, which also increase its microstates. Therefore,  propane has the greatest standard entropy.

The standard entropy of propane has been highest among the given molecules. Thus, option E is correct.

The standard entropy has been the energy possessed by the 1 mole of a pure substance at standard pressure and temperature.

The entropy has been proportional to the molecular weight and structure complexity. The molecule with higher molecular weight and structure complexity tends to have higher entropy.

In the given set of molecules, the molecular mass and structure complexity of propane has been the highest. Thus, the standard entropy of propane has been highest among the given molecules. Option E is correct.

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Answer:

The correct answer would be : 33.8 g

Explanation:

Molar mass of ammonia,

Molar Mass = 1* Molar Mass(N) + 3* Molar Mass (H)

= 1*14.01 + 3*1.008  = 17.034 g/mol

mass(NH3)= 25.0 g  (given)

number of mol of NH3,

n = mass of NH3/molar mass of NH3

=(25.0 g)/(17.034 g/mol)

= 1.468 mol

Now,

Molar mass of O2

= 32 g/mol

mass(O2)= 45.0 g

similar as ammonia

n (O2)=(45.0 g)/(32 g/mol)

= 1.406 mol

Balanced chemical equation is:

4 NH3 + 5 O2 ---> 4 NO + 6 H2O

1.83456 mol of O2 is required  for 1.46765 mol of NH3

by the calculation we have only 1.40625 mol of O2

Thus, the limiting agent will be - O2

now the Molar mass of NO,

= 1*14.01 + 1*16.0

= 30.01 g/mol  (similar formula used for NH3)

Balanced equation :

mol of NO formed = (4/5)* moles of O2

= (4/5)×1.40625  (from above calculation)

= 1.125 mol

mass of NO = number of moles × molar mass

= 1.125*30.01

= 33.8 g

Thus, the correct answer would be : 33.8 g

The amount of nitrogen oxide that can be formed in the given mass is 44.12 g.

The given parameters;

The reaction of the ammonia and oxygen is written as follows;

[tex]4NH_3(g) \ + \ 5O_2 (g) \ --> \ 4NO (g) \ + \ 6H_2O(g)\\\\[/tex]

Molar mass of NH₃ = (14) + (3 x 1) = 17 g/mol

Molar mass of NO = (14) + 16 = 30 g/mol

4(17 g/mol) of NH₃ ------------------ 4(30)

25 g/mol of NH₃ --------------------- ?

[tex]= \frac{4(30) \times 25}{4(17)} \\\\= 44.12 \ g[/tex]

Thus, the amount of nitrogen oxide that can be formed in the given mass is 44.12 g.

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Answer:

A

Explanation:

Utility knife

Answer:

Utility knife

Explanation:

Answer:

Sound wave are not solid nor liquid nor gas it is invisible and goes nearly through any thing.

While waters ripples are liquid which can be easily moved by anything

Answer:

Structure in attachment.

Explanation:

The oxymercuration-demercuration of an asymmetric alkene usually produces the  Markovnikov orientation of an addition. The electrophile ⁺Hg(OAc), formed by the electrophile attack of the mercury ion, remains attached to least substituted group at the end of the double bond. This electrophile has a considerable amount of positive charge on its two  carbon atoms, but there is more positive charge on the more substituted carbon atom,  where it is more stable. The water attack occurs on this more electrophilic carbon, and the Markovnikov orientation occurs.

In hydroboration, borane adds to the double bond in one step. Boron is added to the less  hindered and less substituted carbon, and hydrogen is added to the more substituted carbon. The electrophilic boron atom adds to the less substituted end of the double bond, positioning the positive charge (and the hydrogen atom) at the more substituted end. The result is a product with the anti-Markovnikov orientation.

Answer:

Na:  1

F:    7

V:    5

Ar:   8

C:    4

Explanation:

The number of valence electrons by using periodic table are Na has 1, F has 7, V has 5, Ar has 8 and C has 4 valence electron.

The chemical elements are arranged in rows and columns in the periodic table, sometimes referred to as the periodic table of the elements. It is frequently used in physics, chemistry, and other sciences, and is frequently regarded as a symbol of chemistry.

Because of the orderly arrangement of the elements, it is known as the periodic table. They're arranged in rows and columns, as you'll see. Periods and groups are the names given to the horizontal rows and the vertical columns, respectively.

A system for arranging the chemical elements is the periodic table. The fundamental components of all matter are the chemical elements. The atomic number is a distinct characteristic of each chemical element. This figure is based on how many protons there are in each of the element's atoms.

Thus, The number of valence electrons by using periodic table are Na has 1, F has 7, V has 5, Ar has 8 and C has 4 valence electron.

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Answer:

A. [tex]Rate =k[HCl]^{m} [Na_2S_2O_3]^{n}[/tex]

Explanation:

Let's consider the reaction between hydrochloric acid and sodium thiosulfate.

2 HCl + Na₂S₂O₃ → H₂O + S + SO₂ + 2 NaCl

The rate law is:

[tex]Rate =k[HCl]^{m} [Na_2S_2O_3]^{n}[/tex]

where,

Answer:[tex]T_f=33.85\°C[/tex]

Explanation:

Hello,

In this case, we can write the following relationship, explaining that the lost by the hot water is gained by the cold water:

[tex]Q_{hot,W}=-Q_{cold,W}[/tex]

Which in terms of mass, specific heat and temperatures, we have:

[tex]m_{hot,W}Cp_{W}(T_f-T_{hot,W})=-m_{cold,W}Cp_{W}(T_f-T_{cold,W})[/tex]

Whereas the specific heat of water is cancelled out to obtain the following temperature, considering that the density of water is 1 kg/L:

[tex]T_f=\frac{m_{hot,W}T_{hot,W}+m_{cold,W}T_{cold,W}}{m_{hot,W}+m_{cold,W}}\\\\T_f=\frac{5.0kg*80\°C+60kg*30\°C}{5.0kg+60kg} \\\\T_f=33.85\°C[/tex]

Regards.

Answer:

You need 30 ml of alcohol and 70 ml of water.

Explanation:

You want to end up with 100ml of liquid, 30% of which is alcohol. 30% of 100ml is 30/100 100 = 30 ml.

Answer:

[tex]Tb=63.8\°C[/tex]

Explanation:

Hello,

In this case, for the boiling point elevation, we have:

[tex]\Delta T=i*m*Kb[/tex]

Whereas the van't Hoff factor for the given substance is 1 since is not ionizing.  Moreover, the molality is computed by:

[tex]m=\frac{mol_{solute}}{m_{solvent}}=\frac{175.3mg*\frac{1g}{1000mg}*\frac{1nol}{164g} }{1.50g*\frac{1kg}{1000g} } =0.713m[/tex]

In such a way, since the boiling point of pure chloroform is 61.2 °C, the boiling point of the solution is:

[tex]Tb=61.2\°C+1*0.713m*3.63\frac{\°C}{m} \\\\Tb=63.8\°C[/tex]

Regards.

Answer:

2p

Explanation:

Sodium has an atomic number of 11, thus, the neutral atom has 11 electrons. The electron configuration is:

Na: 1s² 2s² 2p⁶ 3s¹

To gain stability, it loses an electron from its outer shell to form the cation Na⁺. Its electron configuration is:

Na⁺: 1s² 2s² 2p⁶

If it were to lose a second electron to form a Na²⁺ cation, the electron should be lost from the 2p orbital subshell and its electron configuration would be:

Na²⁺: 1s² 2s² 2p⁵

Answer:

0.250 mol

Explanation:

The reaction between Mg and O2 is given by;

2Mg + O2 --> 2MgO

From the equation above; 2 moles of Mg reacts to form 2 moles of MgO.

0.250 mol of Mg would produce x mol of MgO.

2 = 2

0.250 = x

x = 0.250 * 2/2 = 0.250 mol

Answer:

b

Explanation:

Answer: Product

Explanation:

A substance formed in a chemical reaction is called a products ,therefore option (d) is correct .

A chemical reaction is a process that occurs when two or more molecules interact to form a new product(s).

Compounds that interact to produce new compounds are called reactants whereas the newly formed compounds are called products.

Products are substances that are created as a result of a chemical reaction. These products of reactions  may be ions or molecules.

The result of a chemical reaction might exist in the solid, liquid, or gaseous phases.

A + B → C + D

Here,

A and B are the reactants, and

C and D are the products of their reaction.

A substance formed in a chemical reaction is called a products ,hence  option (d) is correct .

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Answer:

See the answer below

Explanation:

First, it should be understood that an endothermic reaction is one that absorbs energy in the form of heat from the surrounding. The products of endothermic reactions usually have higher energy than their reactants. Hence, the ΔH° which is referred to as the enthalpy change is usually positive.

Forgetting to cover the coffee-cup calorimeter means some of the heat energy absorbed by the reactants would be exchanged back to the surroundings - a loss. It also means that the enthalpy change would be smaller compared to if the cup had been covered because some of the heat has been lost to the surrounding.

Answer:

its true

Explanation:

Answer:

true

Explanation:

you stop on ground, ground vibrates and makes sound

Answer: 0.029 V

Explanation:

For the given chemical reaction :

[tex]Zn^{2+}(0.10M)(aq)+Zn(s)\rightarrow Zn^2+{0.010M)(aq)+Zn(s)[/tex]

Using Nernst equation :

[tex]E_{cell}=E^0_{cell}-\frac{2.303RT}{nF}\log\frac{\text {anodic ion concentration}}{\text {cathodic ion concentration}}[/tex]

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature =  298 K

n = number of electrons in oxidation-reduction reaction = 2

[tex]E^0_{cell}[/tex]  = standard electrode potential of the cell = 0 (as both metals are same )

[tex]E_{cell}[/tex]  = emf of the cell = ?

[tex]E_{cell}=0-\frac{2.303\times 8.314\times 298}{2\times 96500}\log\frac{0.010}{0.10}[/tex]

[tex]E_{cell}=0.029V[/tex]

Thus the cell potential will be 0.029 V

A buffer is a solution that mitigates against changes in acidity/alkalinity.

A buffer consists of a weak acid and its conjugate base. Also, a buffer can be formed from a weak base and its conjugate acid. A buffer is a solution that helps to mitigate against changes in acidity and alkalinity.

Let us now examine the solution mixtures listed in the question:

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Answer:

D) A group 1 alkali metal bonded to chloride, such as RbCl

Explanation:

Which of the following has the greatest electronegativity difference between the bonded atoms?

A) A strong acid made of hydrogen and a halogen, such as HCl

The electronegativity difference between H and Cl is:

ΔEN = |EN(H)-EN(Cl)| = |2.1-3.0| = 0.9

B) A diatomic gas, such as nitrogen (N₂)

The electronegativity difference between N and N is:

ΔEN = |EN(N)-EN(N)| = |3.0-3.0| = 0.0

C) Carbon bonded to a Group 6A (16) nonmetal chalcogen, such as in CO

The electronegativity difference between C and O is:

ΔEN = |EN(C)-EN(O)| = |2.5-3.5| = 1.0

D) A group 1 alkali metal bonded to chloride, such as RbCl

The electronegativity difference between Rb and Cl is:

ΔEN = |EN(Rb)-EN(Cl)| = |0.8-3.0| = 2.2

Answer:

it would be 1

Explanation:

Answer:

17 atoms

Explanation:

If what we want is to calculate the number of atoms. We must take into account the subscripts of the formula. We can rewrite the formula  taking into account the "ones" implicit in the formula, therefore we will have:

[tex]Al_2(Cr_1O_4)_3 [/tex]

Now we have a "3" outside the parenthesis. Therefore, we must multiply this 3 by the number of atoms within the parentheses:

-) Oxygen atoms: 4 x 3 = 12 atoms

-) Chromium atoms: 1 x 3 = 3 atoms.

If we take into account we have 2 aluminum atoms, in total, we will have:

-) 12 oxygen atoms

-) 3 chromium atoms

-) 2 aluminum atoms

12 + 3 + 2 = 17 atoms

In total, we will have 17 atoms.

See figure 1

I hope it helps!

Answer:

where is rhe structure

Answer:

it would be 3.45lb/1 *454grams /lb

Explanation:

According to the  stoichiometry and the given balanced chemical equation 89.22 g of barium chloride are needed to make 100 grams of barium sulfate.

Stoichiometry is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given chemical equation, 208.23 g of barium chloride produces 233.38 g of barium sulfate ,so for 100 g of barium sulfate 208.23×100/233.38 =89.22 g of barium chloride is required.

Thus, 89.22 g of barium chloride are needed to make 100 grams of barium sulfate.

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Answer:

A) Balanced

B) Not Balanced

C) Not Balanced

D) Balanced

Answer:

spherical model of the universe