five factors predisposing a person to stroke​

Given:-

To be calculated:-

Calculate its volume.

Formula used:-

Density = Mass/volume

=> 25 = 125/Volume

=> Volume = 125/25

=> Volume = 5 cm³

Answer:

Hope it will help you :)

Explanation:

Answer:

Explanation:

  The capacitance of a capacitor is defined as the charge stored per unit potential change.

using the expression for the capacitance

[tex]C= \frac{eA}{d}[/tex]

where e=  electrostatic constant

A = the area of the plate

d = separation distance.

Given the problem statement

1.  If the place separation is doubled

2. plate area is halved.

 effecting the conditions in our expression for the capacitance we have

[tex]C= \frac{e\frac{A}{2} }{2d}\\\\2dC=e\frac{A}{2}[/tex]

cross multiplying we have

[tex]4dC=eA[/tex]

dividing both sides by 4d we have

[tex]C=\frac{eA}{4d}[/tex]

The capacitance is 1/4 the initial value

The capacitance should become C)one forth

It could be defined by the charge stored per unit with respect to the potential change.

Here the following expression should be used.

[tex]C = eA \div d[/tex]

Here e=  electrostatic constant

A = the area of the plate

d = separation distance.

So in the case when place separation is doubled and plate area is halved

So,

[tex]C = \frac{e\frac{A}{2} }{2d}\\\\2Dc = e\frac{A}{2}\\\\ 4Dc = eA[/tex]

Now if we divide both the sides by 4d so

[tex]C = \frac{eA}{4D}[/tex]

Learn more about plate here: https://brainly.com/question/15612606

Answer:

6.37*10^6 m

Explanation:

We know that,

g = GM/R²

values given to us

acceleration due to gravity = g = 9.8 m/s²

Mass of the earth is= 6.4*10^24

G = 6.67*[tex]10^{-11}[/tex]

implementing

9.8 = 6.67*10^-11 * 6*10^24/R^2

9.8 = 40.02 * 10^13/ R^2

R^2 = 4002/98 * 10^12

R^2 = 40.83* 10^12

R= 6.37*10^6 m   (approximately)

Explanation:

a. Average speed = distance / time

= 100 m / 70 s

= 1.43 m/s

b. Average displacement = displacement / time

= 0 m / 70 s

= 0 m/s

Distance is the length of the path traveled.  Displacement is the difference between the final position and initial position.

Answer:

Explanation:

[tex] \sf{Potential Energy ( P.E ) \: = \: 20.8 \: joule}[/tex]

[tex] \sf{distance \: = 27.6 \: metre}[/tex]

[tex] \sf{mass = }[/tex] ?

[tex] \sf{acceleration \: due \: to \: gravity = 9.68 \: {metre \: per \: second}^{2} }[/tex]

Now, let's find the mass:

[tex] \sf{PE \: = mass \times gravity \: \times \: distance}[/tex]

plug the values

⇒[tex] \sf{20.8 = m \times 9.8 \times 27.6}[/tex]

Multiply the numbers

⇒[tex] \sf{20.8 = 270.48 \: m}[/tex]

Swap the sides of the equation

⇒[tex] \sf{270.48m = 20.8}[/tex]

Divide both sides of the equation by 270.48

⇒[tex] \sf{ \frac{270.48m}{270.48} = \frac{20.8}{270.48} }[/tex]

Calculate

⇒[tex] \sf{0.0769}[/tex] kg

Hope I helped!

Best regards!!

Answer:

[tex]\huge \boxed{\mathrm{0.0769 \ kg}}[/tex]

Explanation:

[tex]\displaystyle \sf Mass=\frac{Potential \ energy}{Acceleration \ of \ gravity \times Height}[/tex]

[tex]\displaystyle m=\frac{PE}{gh}[/tex]

[tex]\mathrm{We \ need \ to \ find \ the \ mass.}[/tex]

[tex]\displaystyle m=\frac{20.8}{9.8 \times 27.6}[/tex]

[tex]m= 0.0769[/tex]

Answer: D

Explanation:

First, we know that the acceleration is defined as the ratio of change of the velocity.

This means that, if we have a change in the velocity, then we also have acceleration.

And by Newton's second law we know that:

F = m*a

Force equals mass times acceleration.

So if we have acceleration different than zero, then we should also have force different than zero.

So we must have a nonzero net force acting on it.

The correct option is D

Hello!

----------

The statement in which correctly applies to a car that changes its velocity over a period of time would be "a nonzero new force is acting on it."

Hope this helps! Also, if you need help with the rest of this assignment, I make a study set on Quizlet that may help you out with the other question. Thanks and good luck!

Quizlet - Unit 6: Lesson 3 Newton's Second Law

h t t p s : / / q u i z l e t . c o m / 7 3 7 7 7 5 3 2 0 / u n i t - 6 - l e s s o n - 3 - n e w t o n s - s e c o n d - l a w - f l a s h - c a r d s / ? n e w

Explanation:

One parsec is the distance to an object whose parallax angle is one arcsecond. The radius of the Earth's orbit equals one astronomical unit (AU), so an object that is one parsec distant is 206,265 AU (or 3.26 light-years) away

Answer:

Parsec is a unit of distance used in astronomy, equal to about 3.26 light years (3.086 × 10^13 kilometres). One parsec corresponds to the distance at which the mean radius of the earth's orbit subtends an angle of one second of arc.

Hope this helps!

Answer:

3.7 m/s

Explanation:

Given:

Δx = 10.0 m

v₀ = 2.0 m/s

a = 0.50 m/s²

Find: v

v² = v₀² + 2aΔx

v² = (2.0 m/s)² + 2 (0.50 m/s²) (10.0 m)

v = 3.7 m/s

Answer:

--->

Explanation:

1. Air Resistance- this is a type of frictional force that acts upon objects as they travel through air. It usually opposes the motion of an object and it is mathematically difficult to predict its value.

2. Gravity- the force of gravity is the force that the earth, and moon use to attract an object towards itself. The moon has far less gravity than earth. All objects on earth experience a force of gravity that pulls them downward, towards the center of the earth.

3. Tension- the tension force is the force that is transmitted through a string, rope, cable or wire when it is pulled from opposite ends. The tension force is directed along the length of the wire and pulls equally on the objects on the opposite ends of the wire

4. Friction- this is the force exerted by a surface when an object moves across it. Friction results from the two surfaces being pressed together closely.

5. Electromagnetic force- although they don't seem similar, electricity and magnetism are related. Flowing electrons produce magnetism, and a moving magnet produces electricity.

6. Upthrust- this is the upward force that a liquid or gas exerts on a body floating in it.

7. Spring force- The spring force is the force exerted by a compressed  spring upon any object that is attached to it. This object is always acted upon by a force that restores the object to its rest or equilibrium position.

8. Applied force- An applied force is a force that is applied to an object by a person or another object.

9. Electrostatic force- The types of forces exerted by all electrically charged bodies on another charged bodies in the universe are ‘electrostatic forces’. They can be either positively or negatively charged.

10. Nuclear force- these are the forces that act between two or more nucleons. They bind protons and neutrons into atomic nuclei. The nuclear force is about 10 millions times stronger than the chemical binding that holds atoms together in molecules.

Answer:

[tex] \boxed{\sf Time \ taken = 10 \ seconds} [/tex]

Given:

Initial velocity (u) = 10 m/s

Final velocity (v) = 30 m/s

Acceleration (a) = 2 m/s²

To Find:

Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s²

Explanation:

[tex]\sf From \ equation \ of \ motion:[/tex]

[tex] \boxed{ \bold{v = u + at}}[/tex]

Substituting values of v, u & a in the equation:

[tex] \sf \implies 30 = 10 + 2t[/tex]

Substract 10 from both sides:

[tex] \sf \implies 30 - 10 = (10 - 10) + 2t[/tex]

[tex] \sf \implies 20 = 2t[/tex]

20 = 2t is equivalent to 2t = 20:

[tex] \sf \implies 2t = 20[/tex]

Dividing both sides by 2:

[tex] \sf \implies \frac{ \cancel{2}t}{ \cancel{2}} = \frac{20}{2} [/tex]

[tex] \sf \implies t = \frac{10 \times \cancel{2}}{ \cancel{2}} [/tex]

[tex] \sf \implies t = 10 \: s[/tex]

So,

Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s² = 10 seconds

Answer:

245.1° and 13 knots

Explanation:

The given parameters are;

The true heading = 135°

The resultant ground track = 130°

The true airspeed = 135 knots

The ground speed = 140 knots

Given that the true airspeed the ground speed and the wind direction and magnitude form a triangle, we have;

From cosine rule, we have;

a² = b² + c² - 2×b×c×cos(A)

Where

a = The magnitude of the wind speed in knot

b = The true airspeed = 135 knots

c = The ground speed = 140 knots

A = The angle in between the true heading and the resultant ground track heading = 5°

Which gives;

a² = 135² + 140² - 2×135×140×cos(5 degrees) = 168.84 knots²

a = √168.84 = 12.9934 ≈ 13 knots

We have;

135 × sin(135 degrees) - 140× sin(130 degrees) = -11.7868

135 × cos(135 degrees) - 140× cos(130 degrees) = -5.469

Tan(θ) = -11.8/-5.5 = 2.155

θ = tan⁻¹(2.155) = 65.108°

Given that the wind is moving in opposite direction (slowing down the airplane, we add 180°, to get

Therefore, the angle direction = 180 + 65.108 = 245.1

Therefore, we have;

245.1° and 13 knots

Answer:

Fashion and interior design.

I hope it will help you.

Answer:

Calcium sulphide

Explanation:

If we look at the compound, we will discover that it is an ionic compound. The compound is comprised of Ca^2+ and S^2-.

The cation Ca^2+ is the calcium ion while the anion S^2- is the sulphide ion hence the compound is rightly named calcium sulphide.

Answer:

Neither A nor B

Explanation:

The charge rate of a battery is the rate at which charge is added to the battery in a given time unit. The unit of charge rate is Coulombs/second or amps

The time to charge a battery, is given by  the battery charging formula which is given as follows;

Battery charging time, t = Battery Ah(Ampere hour)/(Charging current, A)

T = Ah/A

Where;

T = Time (Hours)

Ah = The rating of the battery in Ampere Hour

A = The Current applied given in Amperes

The charging current should 10% of the Ah battery rating, such that a 120 Ah battery requires about 12 Amperes charging current

However, due to losses in the system, the current can be set at 13A

the time for charging will then be t = 120/13 = 9.23 hours

Answer:

The clip is denser than the three liquids, and water is denser than oil.

Explanation:

In this exercise, the Archimedes principle must be used, on the thrust that is equal to the weight of the dislodged liquid

          B = ρ_liquid g V_body

when a body is placed on a liquid, the equilibrium equation must be fulfilled

          W - B = 0  

          W = B

            ρ_body g V_body =  ρ _liquid  g V’

from this expression we see that we have three possibilities

* the density of the body is less than the density of the liquid, therefore the body floats

* The density of the body is equal to the density of the liquid, the body is in equilibrium with the liquid, neither floats nor sinks

* the density of the body greater than that of the liquid, the body sinks.

Based on this, the liquids are arranged in the cylinder according to their density.

           ρ_oil ​​ <  ρ_water  <  ρ_starch

as the clip sinks

the density of the clip is higher than that of liquids

We review the final statements and the correct one is: Clip is denser than liquids and water is denser than oil

Answer:   D

Explanation:

Answer:

A main sequence star that lacks the mass necessary to explode in a supernova so it goes KAbooM and then will become a white dwarf, a 'dead' star that has burned through all of its hydrogen and helium

eventually stop emitting light and heat and become black dwarfs.

Answer: the answer key is in the pdf files below

Explanation:

Answer: 0.079mm

Explanation:

Hope this helps^^

Answer:

Explanation:

Bones?

Bones are primarily made of calcium. Also, they protect the body, which is pretty much obvious. They also act as camouflage.

The only but I have is, can they be found as a filler in most household?

Asides that, bones pretty much fits in to the answer.

Given:-

To be calculated:-

Calculate the pressure exerted on a level ground.

Formula used:-

Pressure = Force/Area

Solution:-

First of all,

We have to find out Force ;

Force = m × g

Force = 75 kg × 9.8 m/s²

Force = 735 kg.m/s² [ 1 N = kg.m/s² ]

Force = 735 N

Now,

Pressure = Force/Area

Pressure = 735 / 28/1000

Pressure = 735 × 1000 / 28

Pressure = 735000 / 28

Pressure = 26,250 Pascal

Answer:

Explanation:

idk

Answer:

The velocity after 6 m while moving at 10 m/s² ≈ 10.95 m/s

Explanation:

The given parameters are;

The given distance of the sack movement = 6 m

The acceleration, a of the sack = 10 m/s²

The velocity of the is given from the relation;

v² = u² + 2×a×s

Where;

u =The initial velocity = 0

Which gives;

v² = 2×a×s

v² = 2×10×6 - 120

v = √120 = 2·√30 m/s

The velocity after 6 m while moving at 10 m/s² is 2·√30 m/s or approximately equal to 10.95 m/s.

Answer:

607.6g

Explanation:

Assume each mark on the scale represented 1 g. That is 1 cm = 1g

To estimate how much a sheet of paper would mass a sheet of paper is 28 cm by 21.7 cm, first calculate the area.

Area = 28 × 21.7 = 607.6 cm^2

Mass = 607.6 × 1g = 607.6 g

Therefore, the estimation will be 607.6g

Answer:

Explanation:

59 ) Graph has been given in the file attached .

60)  Since the  v- t graph is a straight line so the acceleration is constant . This acceleration does not change with time . It is also called acceleration due to gravity . Its value is 10 m /s²

61 ) If there is no resistance , both the objects will fall together and reach the earth simultaneously if fallen from same height . it is so because each and every object falls under gravity without any obstruction with equal acceleration which is equal to 10 m /s ² .

Answer:

16

Explanation:

10+6=16

Explanation:

When a constant force acts upon an object the acceleration of the object varies inversely with its mass.

[tex]a\propto \dfrac{1}{m}[/tex]

or

[tex]\dfrac{a_1}{a_2}=\dfrac{m_2}{m_1}[/tex]

If m₁ = 21 kg, a₁ = 3 m/s², m₂ = 9 kg

We need to find a₂

So,

[tex]a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{21\times 3}{9}\\\\a_2=7\ m/s^2[/tex]

So, if mass is 9 kg, its acceleration is 7 m/s².

Answer:

A AND B

Explanation:

Answer: Yes. Please find the answer in the explanation.

Explanation:

Yes. Since velocity is a vector quantity, that is, it has both magnitude and direction.

If the displacements covered are not of the same direction, the velocity will not also of the same direction.

Take for instance, if the velocity in a positive is 40 m/s and velocity in the opposite direction is - 20 m/s . Then, the resultant velocity will be 40 - 20 = 20 m/s

Therefore,  it is possible that at any time during their trip their velocity was -20 m/s.