Firecrackers A and B are 600 m apart. You are standing exactly halfway between them. Your lab partner is 300 m on the other side of firecracker A. You see two flashes of light, from the two explosions, at exactly the same instant of time.
Define event 1 to be "firecracker 1 explodes" and event 2 to be "firecracker 2 explodes." According to your lab partner, based on measurements he or she makes, does event 1 occur before, after, or at the same time as event 2? Explain.

Answers

Answer 1

Answer:

See the explanation

Explanation:

Given:

Distance of Firecrackers A and B = 600 m

Event 1 = firecracker 1 explodes

Event 2 = firecracker 2 explodes

Distance of lab partner from cracker A = 300 m

You observe the explosions at the same time

to find:

does event 1 occur before, after, or at the same time as event 2?

Solution:

Since the lab partner is at 300 m distance from the firecracker A and Firecrackers A and B are 600 m apart

So the distance of fire cracker B from the lab partner is:

600 m  + 300 m = 900 m

It takes longer for the light from the more distant firecracker to reach so

Let T1 represents the time taken for light from firecracker A to reach lab partner

T1 = 300/c

It is 300 because lab partner is 300 m on other side of firecracker A

Let T2 represents the time taken for light from firecracker B to reach lab partner

T2 = 900/c

It is 900 because lab partner is 900 m on other side of firecracker B

T2 = T1

900 = 300

900 = 3(300)

T2 = 3(T1)

Hence lab partner observes the explosion of the firecracker A before the explosion of firecracker B.

Since event 1 = firecracker 1 explodes and event 2 = firecracker 2 explodes

So this concludes that lab partner sees event 1 occur first and lab partner is smart enough to correct for the travel time of light and conclude that the events occur at the same time.


Related Questions

Which of the following best describes the position of the Sun in the geocentric model? A. It is at the center of the Universe. B. It orbits Earth. C. It is at the center of the Milky Way Galaxy. D. It orbits another star.

Answers

Answer:

option B is correct

Explanation:

in geocentric model earth is at the center of the universe and sun,moon star etc orbited the earth  thats why option B is correct

What factors affect the strength of forces

Answers

Speed, weight, and time between impact and stopping all are the factors that affect force.

What is force?

A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate.

Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.

The magnitude of a force expresses its strength. The magnitude of a force is expressed in Newtons, the SI unit of force.

One Newton is the force that can cause an object weighing one kilogram to move one meter per second.

The mass of the objects and the coefficient of friction between them are the two factors. The angle between them is also important.

Thus, these are some factors affecting strength of force.

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Which of the following correctly describes the relative air pressure at the center of a hurricane, with respect to the horizontal direction? Group of answer choices low at the surface, high aloft low at the surface and aloft high at the surface and aloft high at the surface, low aloft

Answers

Explanation:

The pressure of hurricane which is high decreases gradually as we move higher . The pressure is maximum at the surface . Hence the relative air pressure is higher at the surface and low at the top . Like wise the pressure is low at the center and keeps on increasing when we move outside . Hence the answer is pressure is high at surface and low aloft.

Firecracker A is 300 m from you. Firecracker B is 600 m from you in the same direction. You see both explode at the same time. Define event 1 to be "firecracker A explodes" and event 2 to be "firecracker B explodes." Does.event 1 occur before, after, or at the same time as event 2? Explain.

Answers

Answer:

e see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

Explanation:

This is an ejercise in special relativity, where the speed of light is constant.

Let's carefully analyze the approach, we see the two events at the same time.

The closest event time is

       c = (x₁-300) / t

       t = (x₁-300) / c

The time for the other event is

       t = (x₂- 600) / c

since they tell us that we see the events simultaneously, we can equalize

        (x₁ -300) / c = (x₂ -600) / c

         x₁ = x₂ - 300

We see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

Complete the following statement: (In Boyle's law), the volume of a gas ________ when the ________ decreases.

Answers

Answer:

In Boyle's law the volume of a gas increases when the pressure decreases.

Explanation:

Boyle's law states that at fixed mass of gas, the volume of a gas is inversely proportional to the gas pressure, provided temperature remain constant.

Mathematically it be expressed as;

P₁V₁ = P₂V₂

As the  volume of a gas increases,  the pressure decreases, or as the volume of the gas decreases, the pressure of the gas increases.

Therefore, in Boyle's law the volume of a gas increases when the pressure decreases.

In empty space, which quantity is always larger for X-ray radiation than for a radio wave?
a) amplitude
b) wavelength
c) frequency
d) speed.

Answers

Answer:

C

Explanation:

Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. Measuring from the center of the pattern, we find that the fifth dark spot is 4.00cm away. What is the spacing between the slits

Answers

Answer:

The  value is  [tex]d = 0.000125 \ m[/tex]

Explanation:

From the question we are told that

   The  wavelength is  [tex]\lambda = 500 \ nm = 500 *10^{-9 } \ m[/tex]

    The  distance is of  the screen is  [tex]D = 2.0 \ m[/tex]

    The  width of the fifth dark spot is [tex]y = 4.00 \ cm = 0.04 \ m[/tex]

Generally the width of a fringe is mathematically represented as

           [tex]y = \frac{ n * \lambda * D }{d }[/tex]

=>        [tex]0.04 = \frac{ 5 * 500 *10^{-9} * 2 }{d}[/tex]

=>        [tex]d = \frac{ 5 * 500 *10^{-9} * 2 }{0.04}[/tex]

=>        [tex]d = 0.000125 \ m[/tex]

Suppose you attempt to pour out 100 g of salt, using a pan balance for measurements, while an elevator that is accelerating upward. Will the quantity (weight) of salt be too much, too little, or the correct amount? Explain

Answers

Answer:

the correct amount

Explanation:

The pan balance has two pans . When the elevator is accelerating upward , the apparent weight of both objects placed on either pan increase . The net effect is that they cancel out the effect of accelerating elevator . Hence the apparent weight of salt remains same as and equal to its real weight.

In case of spring balance,  its apparent weight would have increased . Its apparent weight would have measured more than its true weight.

i have been wondering this for a long time, does higher density mean higher solidity?

Answers

Explanation:

Solidity means the quality or state of being firm or strong in structure. Density means the degree of compactness in a structure.

Which of these changes will decrease the acceleration of an object? Select the two correct answers

increasing the applied net force

decreasing its mass

increasing its mass

decreasing the applied net force​

Answers

Answer:

✔️From Newton's second law of motion we know that

✔️acceleration is inversely proportional to the mass of the body

✔️Here in this question increasing the mass of body will decrease its acceleration.

Explanation:

Hope it will help you :)

The critical period is a special time of development in humans. True False

Answers

Answer:

True

Explanation:

Without proper development during the critical period, the growth of some life skills may be severely delayed or stunted.

Suppose that the clay balls model the growth of a planetesimal at various stages during its accretion. Choose the planetesimal that is most likely
to pull in debris particle A.

Answers

Answer:2

Explanation:

Suppose that the clay balls model the growth of a planetesimal at various stages during its accretion, the planetesimal that is most likely to pull in debris particle A would be option B.

What is science?

Science is the methodical, empirically-based pursuit and application of knowledge and understanding of the natural and social worlds.

                                                   

Science is a way of learning about the world.

People may contribute to the development of new knowledge through science and utilize it to promote their objectives.

                                                               

It is a method, a thing, and an organization all at once.

If the clay balls represent the formation of a planetesimal at different phases of its accretion, then option B represents the planetesimal that is most likely to draw in debris particle A.

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Which step of the scientific method do you perform after you state the
problem?
O A. Collect data and observations.
B. Conduct an experiment.
C. Form a hypothesis.
D. Draw conclusions.

Answers

Answer:

form a hypothosis

Explanation:

Which of the following is not a way that astronomers can find how much dark matter there is in cluster of galaxies?

a. Using gravitational lensing effects to make a map of how much mass a cluster of galaxies contains.
b. Observe the radio waves coming from all dark matter; from the strength of the radio waves from each cluster, estimate the amount of dark matter needed to produce them.
c. Observing X-rays from the hot gas in the cluster, and using the amount of x-ray radiation to estimate the mass of the cluster.
d. Measuring how much slower galaxies in a rich cluster or supercluster are moving than the Hubble Law would predict.
e. Measuring the speeds with which the galaxies are moving around, to estimate the mass of the cluster needed to keep them from moving away.

Answers

Answer:

b. Observe the radio waves coming from all dark matter; from the strength of the radio waves from each cluster, estimate the amount of dark matter needed to produce them.

Explanation:

The universe is thought to be made up of 85% dark matters. Dark matter is called dark because it does not appear to interact with the electromagnetic field, which means it doesn't absorb, reflect or emit electromagnetic radiation, and is therefore difficult to detect. This means that option b is wrong since radio wave is an electromagnetic wave. Dark matter is a form of matter that makes up  about a quarter of the total mass–energy density of the universe. Dark matter was theorized due a variety of astrophysical observations and gravitational effects that cannot be explained by accepted theories of gravity unless there were more matter in the universe than can be seen.

Find the lowest two frequencies that produce a maximum sound intensity at the positions of Moe and Curly.

Answers

Answer:

hello your question has some missing parts below is the complete question

and the missing diagram

The two speakers emit sound that is 180° out of phase and of a single frequency,ƒ, Find the lowest two frequencies that produce a maximum sound intensity at the positions of Moe and Curly.

answer : 1316.2 hertz

Explanation:

The frequency that produce the maximum sound intensity can be calculated using the relation below

dsin ∅ = n A

where A = dsin ∅ / n  when n = 1 . d = 0.800

A = 0.800 * ( 1 / 3.162 )

A = 0.253 m

speed of sound = 333 m/s

frequency = speed / A

=   333 / 0.253 =  1316.2 hertz

By calculating its wavelength (in nm), show that the second line in the Lyman series is UV radiation.

Answers

Answer:

 λ = 102.78  nm

This radiation is in the UV range,

Explanation:

Bohr's atomic model for the hydrogen atom states that the energy is

           E = - 13.606 / n²

where 13.606 eV   is the ground state energy and n is an integer

an atom transition is the jump of an electron from an initial state to a final state of lesser emergy

            ΔE = 13.606 (1 / [tex]n_{f}^{2}[/tex] - 1 / n_{i}^{2})

the so-called Lyman series occurs when the final state nf = 1, so the second line occurs when ni = 3, let's calculate the energy of the emitted photon

            DE = 13.606 (1/1 - 1/3²)

            DE = 12.094 eV

let's reduce the energy to the SI system

            DE = 12.094 eV (1.6 10⁻¹⁹ J / 1 ev) = 10.35 10⁻¹⁹ J

let's find the wavelength is this energy, let's use Planck's equation to find the frequency

            E = h f

             f = E / h

            f = 19.35 10⁻¹⁹ / 6.63 10⁻³⁴

            f = 2.9186 10¹⁵ Hz

now we can look up the wavelength

           c = λ f

           λ = c / f

           λ = 3 10⁸ / 2.9186 10¹⁵

           λ = 1.0278  10⁻⁷ m

let's reduce to nm

            λ = 102.78  nm

This radiation is in the UV range, which occurs for wavelengths less than 400 nm.

Imagine that you are seeking treatment from a provider who offers complementary, alternative, or integrative treatment. Write at least one (1) question you would want to ask the provider about their education or credentials.

Answers

Explanation:

It is important to reach a decision only after noting the quality of responses received about the following pertinent questions;

1. What training program(s) have they gone through?

2. Do they have any licences?

3. Have they received any certifications from a recognized body?

4. Do they have any ongoing or past scientific research work?

5. Awards they've received, if any?

As this is a key decision of someone's life, making the decision on the basis of the provider's experience with similar cases and quality of service is the most important.

We should ask the following questions to the provider,

1.  Does the practitioner have licenses for such practice?

2. Where did the practitioner receive their educational qualifications from and do they still learn to be up to date with the advanced treatments available in the market?

3. Was the practitioner awarded for any similar cases or handled similar cases?

4. For how long they have been practicing?

5. Does the practitioner have a membership of any organizations or professional societies?

6. Can the treatment be covered by the insurance?

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A person travels 1.5 km in 6 minutes, how fast were they traveling in meters per second?

Answers

Answer:

4.167m/sec

Explanation:

1km=1000m

1.5km=1500m

1min=60sec

6min=360sec

In 360sec they travel 1500m

In 1 sec they travel=1500m/360

1sec=4.167m

What is the magnitude of the total acceleration of point A after 2 seconds? The bar starts from rest and has a constant angular acceleration of 1.0 rad/s2 clockwise.

Answers

Answer:

a_total = 2 √ (α² + w⁴) ,   a_total = 2,236 m

Explanation:

The total acceleration of a body, if we use the Pythagorean theorem is

          a_total² = a_T²2 + [tex]a_{c}[/tex]²

where

the centripetal acceleration is

  a_{c} = v² / r = w r²

tangential acceleration

   a_T = dv / dt

angular and linear acceleration are related

         a_T = α  r

we substitute in the first equation

       a_total = √ [(α r)² + (w r² )²]

       a_total = 2 √ (α² + w⁴)

Let's find the angular velocity for t = 2 s if we start from rest wo = 0

        w = w₀ + α t

        w = 0 + 1.0 2

        w = 2.0rad / s

       

we substitute

        a_total = r √(1² + 2²) = r √5

        a_total = r 2,236

In order to finish the calculation we need the radius to point A, suppose that this point is at a distance of r = 1 m

         a_total = 2,236 m

A long, straight wire of radius R carries a steady current I that is uniformly distributed through the cross section of the wire. Calculate the magnetic field a distance r from the center of the wire in regions r ≥ R and r < R.

Answers

Answer:

a

  When [tex]r \ge R[/tex]

      [tex]B = \frac{ \mu_o * I}{ 2 \pi r }[/tex]

b

 When [tex]r< R[/tex]

   [tex]B = [\frac{\mu_o * I }{ 2 \pi R^2} ]* r[/tex]

Explanation:

From the question we are told that

   The  radius is  R  

   The  current is  I

    The  distance from the center

Ampere's law is mathematically represented as

       [tex]B[2 \pi r] = \mu_o * \frac{I r^2 }{R^2 }[/tex]

      [tex]B = \frac{ \mu_o}{2 \pi } * \frac{r}{R^2}[/tex]

When [tex]r \ge R[/tex]

=>     [tex]B = \frac{ \mu_o * I}{ 2 \pi r }[/tex]

But when [tex]r< R[/tex]

   [tex]B = [\frac{\mu_o * I }{ 2 \pi R^2} ]* r[/tex]

     

If the period of a simple pendulum is T and you increase its length so that it is 4 times longer, what will the new period be?

Answers

Answer:

T' = 2T

Explanation:

The time period of a simple pendulum is given by the relation as follows :

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

l is length of the pendulum

g is acceleration due to gravity

If the length is increased four time, new length is l' = 4l

So,

New time period is :

[tex]T'=2\pi \sqrt{\dfrac{l'}{g}}\\\\T'=2\pi \sqrt{\dfrac{4l}{g}}\\\\T'=2\times 2\pi \sqrt{\dfrac{l}{g}}\\\\T'=2\times T[/tex]

So, the new time period is 2 times of the initial time period.

From what height must an oxygen molecule fall in a vacuum so that its kinetic energy at the bottom equals the average energy of an oxygen molecule at 300 K ?

Answers

Answer:

The  value is  [tex]h = 11930 \ m[/tex]

Explanation:

From the question we are told that

    The  temperature is  [tex]T = 300 \ K[/tex]

     

Generally the root mean square speed of the  oxygen molecules is mathematically represented as

        [tex]v = \sqrt{\frac{3 * R * T }{M} } = \sqrt{ 2 * g * h }[/tex]

Here  R is the gas constant with a value  [tex]R = 8.314 \ J\cdot K^{-1} \cdot \ mol^{-1}[/tex]

    M  is the molar mass of oxygen molecule with value [tex]M = 0.032 \ kg /mol[/tex]

So  

     [tex]\frac{3 * 8.314 * 300 }{0.032} = 2 * 9.8 * h[/tex]

=>    [tex]h = 11930 \ m[/tex]

   

If you cook a marshmallow a few feet above a camp fire, it will cook mostly
by
A) radiation
OB) conduction
C) convection

Answers

Answer:

A) radiation.

Explanation:

Hello,

In this case, heat transfer from a body with a high temperature to a body with a lower temperature may occur when the bodies are not in direct physical contact with each other or when they are separated in space and it is is called heat radiation. Solids, liquids, or gaseous substances are able to emit energy via a process of electromagnetic radiation because of vibrational and rotational movement of their molecules and atoms.

Hence, since the camp fire is not in contact with the marshmallow and it still cooks it, we can infer that the mechanism of heat transfer is A) radiation. Moreover, both conduction and convection occur when the bodies are in contact.

Regards.

A scientist is observing a figure under the microscope that appears to be alive, however she is not sure. The scientist observes a membrane, but after closer observation notices that the image is not clear. What additional observation could she make to support that the object that she is observing under the microscope is alive? A. Bright, vibrant colors. B. Hair that surrounds the object. C. Communicating with another organism. D. The object splitting into two parts to form two organisms. BTW it is either C or D just couldn't figure it out.

Answers

Answer:

D. The object splitting into two parts to form two organisms.

Explanation:

The splitting of cell of an organism actually shoes if it's Alive or not .

The splitting can be either mitosis or meosis for either plant or animal.

But for the fact that it's has cell membrane shoes it's either a plant or an animal.

So the splitting will confirm it's alive.

Answer:

D the correct answer is D

Explanation:

I took the test and was going to pick c but changed my mind

Activity
In this activity, you will solve the following problems using the rules for adding and subtracting and multiplying and dividing with significant
figures
Part A
28.97 + 45.876

Answers

Explanation:

We need to add 28.97 and 45.876.

Here, the first no is 28.97 and other no is 45.876

Here, 28.97 is the least precise value and 45.876 is most precise.

28.97 + 45.876 = 74.846

We need to write the final answer such that there is two digit after the decimal. So, 28.97 + 45.876 = 74.85 because 6 is more than 5 i.e. we add 1 to 4.

Answer:

 28.97

+ 45.876

 74.846

Explanation:

Because 28.97 has only two decimal places, round off the answer to two decimal places: 74.85.

A cylindrical can of radius R is rolling across a horizontal surface without slipping.
A. After one complete revolution of the can, what is the distance that its center of mass has moved.
B. Would this distance be greater or smaller if slipping occurred?

Answers

Answer:

a) 2πR

b) greater

Explanation:

Radius of the cylinder = R

a) after one complete revolution, the center of mass would have moved a distance equal to the circumference of the radius formed by the cylinder.

distance moved = 2πR

b) If slipping occurred, there will be some distance lost during rotation, which will increase the distance that the center of mass will have to move.

a box with a weight of 555 N is sitting on the ground and the bottom of the box measures 0.55 m by 0.45. What is the pressure exerted by the box on the ground?

Answers

Explanation:

Pressure = force / area

P = 55 N / (0.55 m × 0.45 m)

P = 220 Pa

LED light bulbs are more energy efficient, last longer, cost more, and have a smaller environmental impact from manufacture to recycling or disposal. The question is which costs less: incandescent, compact fluorescent (CFL), or LED lights?
(a) Ignore the time value of money. What is the average cost per hour for 25,000 hours of light-mg in a community with exist0.15/kWh electricity: for each choice?
(b) If the light is on 5%, 30%, or 60% of the time, how long until does it take for the 25,000 hours?
(c) Which type of light should a homeowner buy?

Answers

Answer:

a) Cost_incandescent  = $ 375 , Cost _CFL = $ 75 , Cost_LED = $ 45

b)  total = 20833 days ,  total_day = 3472 days ,  Total_days = 1736 d

c) LED

Explanation:

This problem is interesting to solve it, we must have a very important factor, such as the equivalence of the light emitted by the three systems, let's perform the calculation for a light intensity of 1000 lumen in the three bulbs.

consumed potence

         incandescent 100W = fluorescent (CFL) 20W = Led 12 W

Now if we can solve your exercise

a) Let's find the power consumed by each type of bulb in the 25000 h

          E = P t

incandescent

             E_incandescent = 100 25000

             E_incandescent = 2.5 105 Wh

             E_incandescent = 2.5 103 kWh

Fluorescent (Low Power) CFL

               E_CFL = 20 25000

               E _DFL = 5 102 kWh

LED

               E_LED = 12 25000

               E_LED = 3 102 kwh

               

Let's use a direct rule of proportions (rule of three) for the cost of energy, if 1 kWh costs $ 0.15, the energy calculates how much it costs

incandescent

                 Cost_Incandescent = 2.5 103 kW / h ($ 0.15 / 1kWh)

                 Cost_incandescent = $ 3.75 102 = $ 375

CFL

                  Cost_CFL = 5 102 0.15

                  Cost _CFL = $ 75

LED

                  Cost_LED = 3 102 0.15

                   Cost_LED = $ 45

Here we do not take into account the possibility of burning incandescent bulbs and there is an extra replacement cost

b) for this part we use direct proportion rules

If the day has 24 hours and the light is on for 5%, how many days are 25000 hours?

     for 5% = 0.05

hours on in a day

         #_hoursdays = 24 hrs 0.05 = 1.2 hrs

total days

          total = 25000 / 1.2

          total = 20833 days

for 30% = 0.30

       # _hoursday = 24 0.30 = 7.2 h

       Total_days = 25000 h (1 day / 7.2 h)

        total_day = 3472 days

for 60% = 0.602

         #_hours = 24 0.60 = 14.4 h

         Total _days = 25000h (1day / 14.4 h)

          Total_days = 1736 d

c) you should decide between the CFL and the Led are much lower.

Between these two should take into account the cost of the bulbs, if we only take into account the cost of the energy consumed, the selection should be LED

The average speed of a snail is 0.020 miles/hour and that of a Leopard is 70 miles/hour. Convert these speeds in SI units. ​

Answers

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What is the gauge pressure in Pascals inside a honey droplet of a 0.1 cm diameter? Assume that air is surrounding this droplet and the surface tension of honey is 0.052 N/m.
Give your answer to the nearest integer (do NOT use scientific notation).

Answers

Answer:

The gauge pressure in Pascals inside a honey droplet is 416 Pa

Explanation:

Given;

diameter of the honey droplet, D = 0.1 cm

radius of the honey droplet, R = 0.05 cm = 0.0005 m

surface tension of honey, γ = 0.052 N/m

Apply Laplace's law for a spherical membrane with two surfaces

Gauge pressure =  P₁ - P₀ = 2 (2γ / r)

Where;

P₀ is the atmospheric pressure

Gauge pressure = 4γ / r

Gauge pressure = 4 (0.052) / (0.0005)

Gauge pressure = 416 Pa

Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa

Other Questions
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