Find the value of c. Round to the nearest tenth

The value of b set to 2 is the third option, which is the correct one.

The provided equation is h(x) = -x + 5.

We obtain b=5 when comparing with the slope-intercept form y = mx+b.

Consequently, the y-intercept is at 5.

To lower the graph by three units, we must make changes.

As per the transformational laws, f(x)+c shifts c units upward, whereas f(x)-c shifts c units downward.

Therefore, we need to subtract the supplied function by 3 in order to move the graph down 3 units, and we get

y = -x+5 -3

y = -x +2.

Here, the y-intercept is 2.

The provided equation is h(x) = -x + 5.

The value of b set to 2 is the third option, which is the correct one.

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For x=2, the functions g(x)=[tex]f^{-1}(x)[/tex] are true.

Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.

The given function is f(x)=(x-1)/4 and g(x)=2x+5.

Here, y=(x-1)/4

Interchange x with y and y with x, we get

x=(y-1)/4

4x=y-1

y=4x+1

[tex]f^{-1}(x)[/tex]=4x+1

Now, g(x)=[tex]f^{-1}(x)[/tex]

2x+5=4x+1

2x=4

x=2

Therefore, for x=2, the functions g(x)=[tex]f^{-1}(x)[/tex] are true.

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The values of X1 and X2 that maximize the function Z = 30X1 + 50X2 are given as follows:

The maximum value is given as follows:

4000.

The function for this problem is defined as follows:

Z = 30X1 + 50X2.

The constraints are given as follows:

X2 has the higher multiplier, hence we should:

The maximum value of X2 is obtained when:

X2 = 100 - X1.

Replacing into the first equation, the value of X1 is given as follows:

X1 + 3(100 - X1) = 200

-2X1 = -100

2X1 = 100

X1 = 50.

Hence the value of X2 is of:

X2 = 100 - X1

X2 = 50.

The maximum value of the function is obtained as follows:

Z = 30 x 50 + 50 x 50

Z = 4000.

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Answer:

Each piece of gum is 10cents

Step-by-step explanation:

7 x 0.25 then subtract that from 2.05 then divide by the 3pieces of gum

Answer: (0.25 x 7) + 3x = 2.05 and $0.10 per piece of gum

Step-by-step explanation:

Jeff purchased 7 gumballs for $0.25 each, which is [tex](0.25*7)[/tex]

Jeff then purchased 3 pieces of gum, but we don't know for how much so the cost becomes [tex]x[/tex] and then [tex]3x[/tex]

The final cost then comes down to $2.05, therefore [tex](0.25*7)+3x=2.05[/tex] and solve for [tex]x[/tex] to find the cost of each piece of gum

[tex]1.75+3x=2.05[/tex]
[tex]3x=0.3[/tex]

[tex]x=0.1[/tex]

The zeros of the function y = -4(x-3)² + 8 are -1 and 7 and the intercept is 13

The zero of a function is any replacement for the variable that will produce an answer of zero. Graphically, the real zero of a function is where the graph of the function crosses the x‐axis; that is, the real zero of a function is the x‐intercept(s) of the graph of the function.

when y = 0

-4(x-3)² +8 = 0

expanding the equation

-4( x²-6x +9)+8 = 0

-4x² +24x -36 +8 = 0

-4x²+24x -28 = 0

divide through by 4

-x²+6x-7 = 0

-x²+7x -x -7 = 0

(-x²+7x)(-x-7) = 0

-x( x-7) 1(x-7)

1-x = 0 or (x-7 )= 0

x = -1 or 7

therefore the zeros are -1 and 7

to find the intercept:

x= 0

y = -4(0-3)²+8

y =-4+9+8

y = 13

therefore the intercept is 13

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The phrase "La sexta parte de la diferencia de dos números" in algebraic sentence can be written as [tex] \frac{x}{6} [/tex] where "x" represents the difference between two numbers.

The quantity [tex] \frac{x}{6} [/tex] is a fraction that represents one-sixth of the difference between two numbers. In other words, if you have two numbers "a" and "b", and you subtract them to find their difference "a-b", then [tex] \frac{x}{6} [/tex] would equal [tex] \frac{(a - b)}{6} [/tex].

The fraction [tex] \frac{x}{6} [/tex] gives us a portion or a ratio of the difference between the two numbers, and in this case, it's one-sixth of that difference. So, if you want to find what one-sixth of the difference between two numbers is, you can simply divide that difference by 6.

Let's say that the two numbers you want to find the difference between are 15 and 6. To find their difference, we would subtract the smaller number from the larger one:

15 - 6 = 9

So, the difference between these two numbers is 9. To find one-sixth of this difference, we would divide the difference by 6:

[tex] \frac{9}{6} = 1.5[/tex]

So, one-sixth of the difference between 15 and 6 is 1.5.

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x = 2

y = 2 [tex]\sqrt{2}[/tex]

Special right triangles are triangles with specific angle measurements whose side lengths have patterns.

45-45-90 Triangle

The triangle above is a 45-45-90 triangle since it has two 45-degree angles. For this explanation, let a and b represent the legs of a right triangle and c be the hypotenuse. In this type of triangle, the legs are equal, so a=b. The hypotenuse is [tex]\sqrt{2}[/tex] times the leg length. So, c = a√2.

Finding x and y

In this problem, x is one of the legs. This means that x = 2 since 2 is the length of the leg. The y-value represents the hypotenuse, so we can multiply the leg by √2. Thus, y = 2√2.

32 thousands 6 hundreds 8 ones can be rewritten as 32608

According to the BODMAS rule, the brackets have to be solved first followed by powers or roots (i.e. of), then Division, Multiplication, Addition, and at the end Subtraction. Solving any expression is considered correct only if the BODMAS rule or the PEMDAS rule is followed to solve it.

Given here: 32 thousands 6 hundreds 8 ones

Thus we can rewrite as 32×1000+6×100+8×1=32608

Numbers in words are written using the English alphabet. Numbers can be expressed both in words and figures. For example, 100,000 in words is written as One Lakh or One hundred thousand. Numbers in words can be written for all the natural numbers, based on the place value of digits, such as ones, tens, hundreds, thousands, and so on.

Hence, 32 thousands 6 hundreds 8 ones can be rewritten as 32608

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Answer:

Rational number

Step-by-step explanation:

because all rational number multiple by0 is 0

Answer:

see explanation

Step-by-step explanation:

using the rules of exponents/ radicals

• [tex]a^{m}[/tex] × [tex]a^{n}[/tex] = [tex]a^{(m+n)}[/tex]

• [tex]a^{\frac{m}{n} }[/tex] = [tex](\sqrt[n]{a} )^m[/tex]

then

(fg)(x)

= f(x) × g(x)

= [tex]x^{\frac{1}{2} }[/tex] × 2x²

= 2 × [tex]x^{(\frac{1}{2}+2) }[/tex]

= 2[tex]x^{\frac{5}{2} }[/tex]

when x = 9 , then

= 2 × [tex]9^{\frac{5}{2} }[/tex]

= 2 × [tex](\sqrt{9})^5[/tex]

= 2 × [tex]3^{5}[/tex]

= 2 × 243

= 486

Answer:

Square root

Step-by-step explanation:

Something to the 1/2 power means the square root of that number.

Answer: It is 84 degrees

The solution is given below.

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. A triangle with vertices A, B, and C is denoted \triangle ABC. In Euclidean geometry, any three points, when non-collinear, determine a unique triangle and simultaneously, a unique plane.

here, we have,

Remember that the Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.

According to this, the correct answer is: given below.

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The system of equations is

15x + 10y = 800

x + y = 60

and the solution to these equations is

x = 40

y = 20

Given is that an office manager requests a calculator or calendar for each of the 60 office employees. Each calculator is $15 and each calendar is $10. The total order amounted to $800.

We can write the system of equations as -

15x + 10y = 800

x + y = 60

We can write -

y = 60 - x

So, we can write -

15x + 10(60 - x) = 800

15x - 10x + 600 = 800

5x = 200

x = 40

Then -

y = 20

Therefore, the system of equations is

15x + 10y = 800

x + y = 60

and the solution to these equations is

x = 40

y = 20

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{Question in english is -

An office manager requests a calculator or calendar for each of the 60 office employees. Each calculator is $15 and each calendar is $10. The total order amounted to $800. Part A: Write the system of equations that models this scenario. (5 points) Part B: Use the substitution method or the elimination method to determine the number of calculators and calendars ordered. Show all the necessary steps. (5 points)

}

Answer:

Tan u = sin u/cos u, csc u = 1/sin u, sec u = 1/cos u, and cot u = cos u/sin u. The denominators of the fractions can be rationalized by multiplying the numerator and denominator by the conjugate of the denominator.

Step-by-step explanation:

The graph is the graph of straight lines

The point (2, 3) is not included in the solution area

From the question, we have the following parameters that can be used in our computation:

4x+2y = 16

x+y=4

The equations are linear equations

We have

(x, y) = (2, 3)

This gives

4(2) + 2(3) = 16 -- false

2 + 3 = 4 -- false

Hence, it is not in the solution

We have

4x+2y = 16

x+y=4

This gives

4x+2y = 16

4x + 4y=16

So, we have

2y = 0

And:

y = 0

This means that

4x + 2(0) = 16

x = 4

So, the solution set is (4, 0)

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Note that it is correct to state that LN ≅ MN and Nk ⊥ LM, so NK is the perpendicular bisector of LM and P is on NK. See attached image.

A perpendicular bisector is a line that cuts another line segment across the junction point at a straight angle. As a result, a perpendicular bisector always cuts a line segment through its midway. The phrase bisect implies dividing evenly or uniformly.

A simple technique to determine a perpendicular bisector is to measure the line segment you need to bisect. Then, divide the measured length by two to determine the midway. Draw a line at a 90-degree angle out from this middle.

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Full Question:

Tell whether the information in the diagram allows you to conclude that point P lies on the perpendicular bisector of LM. Explain your reasoning. See attached image.

A) No. You would need to know that LK ⊥ MK

B) No. You would need to know that KP ⊥ LM
C) Yes, t LN ≅ MN and Nk ⊥ LM, so NK is the perpendicular bisector of LM and P is on NK
D) Yes, NK ⊥ LM, so NK is the perpendicular bisector of LM and P is on NK

Answer:

1/2 i think this is it

Step-by-step explanation:

Answer:

Equation is

[tex]\mbox {\large \boxed{g(m) = 4.411 (0.94988)^m}}[/tex]

Step-by-step explanation:

We have to translate the information in the table as an equation of the form

[tex]g(m) = P(1 + r)^m\cdots \cdots(1)[/tex]

Let's take the date from the table

For m = 1, g(m) = 4.19

Substituting these values in equation (1) we get:
[tex]g(1) = P(1 + r)^1[/tex]

[tex]4.19 = P(1 + r)^1[/tex]

[tex]P(1 + r)^1 = 4.19 \; \textrm{ (by switching sides)}[/tex]

[tex]P(1+r) = 4.19\; \cdots \cdots (2)\\\textrm{ (an expression raised to the power 1 is the expression itself)}[/tex]

For the next entry in the table, m = 2, g(m) = 3.98

Plugging into (1)

[tex]3.98 = P(1 + r)^2 \cdots\cdots(3)[/tex]
or

[tex]P(1 + r)^2 = 3.98[/tex]

Divide equation (3) by equation (2)

[tex]\dfrac{P(1+r)^2}{P(1+r} = \dfrac{3.98}{4.19}[/tex]

[tex]\textrm{The P terms cancel and } \dfrac{(1 + r)^2}{(1+r)} = 1 + r[/tex]

==> [tex]1 + r = \dfrac{3.98}{4.19}\\\\1 + r = 0.94988\\\\[/tex]

Plugging this value of 1 + r into equation (2):

[tex]P( 0.94988) = 4.19\\\\P = \dfrac{4.19}{0.94988}\\\\P = 4.411\\\\[/tex]

So the equation is

[tex]g(m) = 4.411 (0.94988)^m[/tex]

We can verify this is correct for m = 2, 3 and 4

[tex]m\quad\quad g(m) = 4.411(0.94988)^m\\\------------------\\2\quad\quad 4.411(0.94988)^2 = 3.97992 \approx 3.98\\\\3\quad\quad 4.411(0.94988)^3 = 3.78044 \approx 3.78\\\\3\quad\quad 4.411(0.94988)^4 = 3.59097 \approx 3.59\\\\[/tex]

Answer:

Y=4cm

Step-by-step explanation:

We can use the relationship between the side length and area of a square to solve for Y. Let's call the area of the small square "A" and the area of the large square "B". From the problem statement, we know:

A = 1/9 * B

Since the area of a square is equal to the side length squared, we can substitute this relationship into the equation above:

Y^2 = 1/9 * 12^2

Solving for Y:

Y^2 = 1/9 * 144

Y^2 = 16

Y = sqrt(16)

Y = 4

So, the side length of the small square is 4 cm.

Answer: It is not possible to convert 3 c to mL without a conversion factor. There are several different units of measurement for volume, including cubic centimeters (cc), milliliters (mL), and cubic meters (m^3). To convert from one unit to another, you need to know the conversion factor.

The conversion factor between cubic centimeters (cc) and milliliters (mL) is 1:1, meaning they are equivalent units of measurement. So, 3 cc is equal to 3 mL.

Step-by-step explanation:

Answer: 8xw=a

Step-by-step explanation:

w=width

a=area

The expression (3a⁸)⁹ * (3b⁵)² is solved to get 3¹¹a⁷²b¹⁰

power or exponents as used in mathematics are number written on top of a base number. The power says how many times the base number multiplies itself.

The problem is solved as follows

= (3a⁸)⁹ * (3b⁵)²

raising the terms by power of 9 and 2 accordingly

= (3^9 * a^(8 * 9)) * (3^2 * b^(5 * 2) )

= (3^9 * a^(72)) * (3^2 * b^(10) )

collecting base 3

= (3^9 * 3^2 * a^(72) * b^(10))

= (3^(9 + 2) * a^(72) * b^(10))

= (3^(11) * a^(72) * b^(10))

rewriting the expressions

= 3¹¹a⁷²b¹⁰

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The graph that best represents the situation, given the person cycling from home to the library, is Graph C.

The graph that would best represent the situation would show that the person cycling, stopped moving after 8 kilometers because they were at the library.

The graph should also show that after 30 minutes, the person left the library which is shown in Graph C as:

= 50 - 20 minutes

= 30 minutes

The best graph is therefore Graph C.

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The length of LN for the triangle is 18.

A triangle is a three-sided polygon because it has three edges and three vertices. The most important attribute of a triangle is the sum of its internal angles to 180 degrees

Given triangle JKL,

and MN is parallel to JK,

taking ΔJKL and ΔLMN

∠L = ∠L  (common angle)

because MN is parallel to JK, so corresponding angles are equal,

so ∠K = ∠N

and ∠J = ∠M

ΔJKL ≈ ΔLMN(triangles are similar)

since both triangles are similar the ratio of their corresponding sides is equal,

JL/LM = JK/MN = LK/LN

and JK = 55 and LK = 33

and MN = 12 + LN

JK/MN = LK/LN

substitute the values

55/(12 + LN) = 33/LN

55LN = 33(12 + LN)

55LN - 33LN = 396

22LN = 396

LN = 396/22

LN = 18

Hence the length of LN is 18.

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Answer:

162/5 hours.

Step-by-step explanation:

Let's call the normal depth of the river "D". Since 2/3 of the way to go back to normal is still flooded, the current depth of the water is D + 2/3D = 5/3D.

The flood waters recede at a rate of 1/9 the flood level per hour, so the change in water level each hour is -1/9 * 5/3D = -5/27D.

To find the number of hours it takes to go from the current depth (5/3D) to the normal depth (D), we need to divide the change in depth (-5/27D) by the change in depth per hour (-5/27D): (5/3D - D) / (-5/27D) = (5/3D - D) / (-5/27D) = -(5/3D - D) / (5/27D) = (2/3D) / (5/27D).

This can be simplified to 2/3 * 27/5 = 162/5 hours. The answer is 162/5 hours.

Answer: Since the flood waters still have 2/3 of the way to go back down to reach the normal level, it means that 1/3 of the flood level has already receded.

If the flood level recedes at a rate of 1/9 the flood level per hour, then it will take 1/9 * 1 hour = 1 hour to recede 1/9 of the flood level.

Therefore, to recede 2/3 of the flood level, it will take 2/3 * 1/9 hours = 2/27 hours.

Since there are 60 minutes in 1 hour, the time it takes for the flood waters to reach the normal level in minutes is: 2/27 hours * 60 minutes/hour = 20 minutes.

Therefore, it will take 20 more minutes for the water to reach its normal depth.

Step-by-step explanation:

The coordinates of point A'  and B' are A'(-12,8) and B'(20, 0)

A dilation is a transformation that changes the size of a figure but not its shape.

In a dilation with respect to the origin, a point (x, y) is transformed to a point (kx, ky) where k is a scale factor.

In this case, the point A (-3, 2) and B (5, 0) are transformed under a dilation of 4 with respect to the origin.

So the images are

A' = (kx, ky) = (-3*4, 2*4) = (-12, 8)

B' = (kx, ky) = (5*4, 0*4) = (20, 0)

So the image point of A(-3,2) under a dilation of 4 with respect to the origin is A'(-12,8)

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Complete question

The triangle ABC is dilated by a scale factor of 4 with the center of dilation at the origin.

a) What are the coordinates of A?

b) What are the coordinates of B?

if A (-3, 2) and B (5, 0)